Two uniform solid spheres have the same mass, 1.75 kg, but one has a radius of 0.206 m while the other has a radius of 0.834 m. for each of the spheres, find the torque required to bring the sphere from rest to an angular velocity of 327 rad/s in 15.5 s. each sphere rotates about an axis through its center. torque on sphere with the smaller radius.
Answers
The torque required for the sphere with the smaller radius is approximately 0.622 N*m.
To find the torque required for each sphere, we need to first calculate the moment of inertia (I) for each sphere, and then use the formula for torque (τ) which is τ = I * α, where α is the angular acceleration.
The moment of inertia for a solid sphere is given by I = (2/5) * M * R^2, where M is the mass and R is the radius.
For the smaller sphere (radius = 0.206 m):
I₁ = (2/5) * 1.75 kg * (0.206 m)^2 ≈ 0.0295 kg*m^2
For the larger sphere (radius = 0.834 m):
I₂ = (2/5) * 1.75 kg * (0.834 m)^2 ≈ 0.5093 kg*m^2
Next, we need to find the angular acceleration (α) using the formula α = Δω/Δt, where Δω is the change in angular velocity and Δt is the time interval.
Δω = 327 rad/s (final angular velocity) - 0 rad/s (initial angular velocity) = 327 rad/s
Δt = 15.5 s
α = 327 rad/s / 15.5 s ≈ 21.1 rad/s^2
Now, we can find the torque (τ) for each sphere using τ = I * α.
Torque for smaller sphere:
τ₁ = 0.0295 kg*m^2 * 21.1 rad/s^2 ≈ 0.622 N*m
Torque for larger sphere:
τ₂ = 0.5093 kg*m^2 * 21.1 rad/s^2 ≈ 10.76 N*m
So, the torque required for the sphere with the smaller radius is approximately 0.622 N*m.
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Related Questions
An Elephant is pulled by a group of clowns across a circus. The elephant has a mass of 1000kg and the clowns are pulling with a force of 200N. What is the acceleration of the elephant?
Answers
Answer:
The acceleration of the elephant is 5m/s^2 (squared).
Explanation:
Given: Force=200N, Mass=1000kg
Required: acceleration=?
Equation: a=F/m
Solution: a=200N/1000kg
Answer: a=5m/s^2
An aircraft jet engine has a thrust of I80N. What impulse is produced
in 30 S?
Answers
Answer:
5400N.s
Explanation:
lmpuls=force ×time
force =180N
time=30s
impulse =180×30=5400N.s
does the battery appear to be a source of constant current, constant voltage, or neither when different elements are added to a circuit?
Answers
Adding additional components to a circuit gives the impression that the battery is a source of consistent voltage.
A battery is typically considered to be a source of constant voltage, meaning that it maintains a fixed potential difference between its terminals, regardless of the elements that are added to the circuit. However, the current supplied by the battery may vary depending on the resistance of the circuit and the characteristics of the elements that are added. Ohm's Law states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance. Therefore, adding elements with higher resistance to the circuit will result in a decrease in the current supplied by the battery.
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1. Find the acceleration of an object when the force is 5.2 N and the mass is 2.6 x 10kg.
Answers
Answer:
F=ma
5.2N=26a
a=5.2÷26=0.2
Answer:
0.2 metre square
Explanation:
acceleration=force/mass
You use 35 joules of energy to move a 7 newton box. How far did you move it?
Answers
If you picked it straight up, you lifted it 5 meters.
If you moved it horizontally, it could be ANY distance.
Answer:
5
Explanation:
distance = work / force
d = 35 J / 7 N
d = 5 m
20. A cavern 165 m long, 22 m wide and 15 m high is to be excavated in chalk beneath the sea. The crown of the cavern will be 35 m below the seabed. What is the main geological information you would like to have before proceeding with the excavation? 2. A mine is planned to use a decline with a dip of 30
∘
to access the orebody at the depth of 500 meters. Estimate the vertical and horizontal insitu stresses at 500 m depth, assuming the average unit weight of rock 27kN/m3, horizontal Young's modulus 75 GPa and Poisson's ratio 0.3.
Answers
At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.
Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:
a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.
b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.
c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.
To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.
Vertical Stress:
The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.
Vertical Stress = Unit Weight of Rock × Depth
Vertical Stress = 27 kN/m³ × 500 m
Vertical Stress = 13,500 kN/m² or 13.5 MPa
Horizontal Stress:
The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:
Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)
Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)
Horizontal Stress = 13.5 MPa × 0.6 / 0.7
Horizontal Stress = 11.57 MPa
Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.
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If a ball is given a push so that it has an initial velocity of 6 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation s(t) = 6t + 5t2 (a) Find the velocity after 2 seconds. m/s (b) How long does it take for the velocity to reach 40 m/s? (Round your answer to two decimal places.)
Answers
The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.
Given the equation s(t) = 6t + 5t²
Let's find the velocity after 2 seconds.
(a) Velocity = (ds)/(dt)
Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t
At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s
Therefore, the velocity after 2 seconds is 26 m/s.
(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at
We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s
Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.
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construct a turing machine that will accept the following language on {a, b}: l = {w : |w| is odd}
Answers
Turing Machine Description:
The Turing machine will have two states, q0 and q1, with q0 being the initial state and q1 being the accepting state. The tape alphabet consists of the symbols {a, b, blank}. The machine will traverse the input string, moving right on each step. The transition rules are as follows:
In state q0:
If the current symbol is 'a', replace it with 'x' and move right.
If the current symbol is 'b', replace it with 'y' and move right.
If the current symbol is blank, move to state q1 (accepting state).
In state q1:
If the current symbol is 'x' or 'y', move right.
If the current symbol is blank, move to state q0.
The Turing machine is designed to accept the language L = {w : |w| is odd}, which consists of strings with an odd number of symbols from the alphabet {a, b}. The machine starts in state q0 and scans the input string from left to right. For each symbol encountered, it replaces 'a' with 'x' and 'b' with 'y', effectively marking them. It then moves to the next symbol.
If the machine reaches the end of the input string and encounters a blank symbol in state q0, it transitions to state q1, indicating that the length of the input string is odd. In state q1, it continues moving right until it encounters a blank symbol, at which point it transitions back to state q0 to scan the input again.
If the machine encounters a blank symbol in state q0 before reaching the end of the input string, it means the length of the string is even, and the machine rejects the input.
In summary, the Turing machine accepts the language L by transitioning to the accepting state q1 when it reaches the end of an odd-length input string.
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QUESTION 1
A conveyor belt delivers 120 ton of crushed stone per hour into a storage bin. The distance between the main pulley centres, is 100m. The speed of the 650 mm troughed belt is 90 m/min, the coefficient of friction between the pulley and the belt is 0,25. The discharge is 12 m higher than the loading point. The snubber pulley provides a contact angle between the belt and the main pulley of 225°. The power required to overcome friction is 35% of the power required to lift the load against gravity. The drive is 80% efficient.
Calculate the following:
1.1 The power against gravity. (3)
1.2 The power to overcome friction. (3)
1.3 The power of the motor. (2)
1.4 The belt tensions (7, and 7, ). (6)
1.5 The number of plies in the belt if the allowable tension is 2,3 kN per meter width per ply. (3)
[17]
Answers
The distance between the main pulley centres, is 100m. The power of gravity, the mass flow rate of crushed stone per hour is 120 ton. As the conveyor belt is lifting the material to a height of 12 m.
1.1 Power against gravity:
\(P = mgh\)
\(P = 33.33 * 9.81 * 12\)
\(P = 3898.3 Watt\)
Answer:\(3898.3 Watt or 3.9 kW\)
1.2 Power to overcome friction:
\(P = 0.35 * 3898.3\)
\(P = 1364.4 Watt\)
Answer:\(1364.4 Watt or 1.4 kW\)
1.3 Power of the motor:
\(P = Total power / efficiency\)
\(P = (3898.3 + 1364.4) / 0.80\)
\(P = 6055.9 Watt\)
Answer: \(6055.9 Watt or 6.06 kW\)
1.4 Belt tensions:
Tension at the tight side:
\(T₁ = (P₁ + P₂) / (2v)\)
\(P₁ - P₂ = (2 * F * Sin θ) / (cos(α) + cos(β))\)
\(F = 33.33 * 9.81 = 327.2 N\)
\(Sin θ = Sin 112° = 0.967\)
\(Cos(α) = (cos(45)) / 0.25 = 1.414\)
\(Cos(β) = (cos(225)) / 0.25 = -1.414\)
\(P₁ - P₂ = (2 * 327.2 * 0.967) / (1.414 - (-1.414))\)
\(T₁ = (P₁ + P₂) / (2v)\)
\(T₁ = (886.9 + 0) / (2 * 1.5)\)
\(T₁ = 295.6 N/m\)
Tension at the slack side:
\(T₂ = T₁ * e^(μθ)\)
\(μ = 0.25\)
θ = 225°
\(T₂ = 295.6 * e^(0.25 * 225 * π/180)\)
\(T₂ = 744.2 N/m\)
Answer: \(T₁ = 295.6 N/m, T₂ = 744.2 N/m\)
1.5 Number of plies:
Allowable tension per
meter width = 2.3 kN/m
Tension per meter width \((T) = (T₁ + T₂) / 2\)
\(T = (295.6 + 744.2) / 2\)
\(T = 519.9 N/m\)
\(No. of plies = T / Allowable tension per ply widthNo. of plies = 519.9 / 2300\)
\(No. of plies = 0.23 plies = 1 ply\)
Answer: \(Number of plies = 1 ply\).
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The gravitational field strength on the moon is 1.63 N/kg. If a rock on the moon weighs 2000N, how
much does the same rock weigh on the earth?
Answers
Answer:
12000N
Explanation:
gravity on earth is six times one on the moon
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles
traveled in a straight line and some were deflected at different angles.
Which statement best describes what Rutherford concluded from the motion of the particles?
Answers
Answer:
C
Explanation:
I just took the quiz
A 55 kg boy is riding a skateboard at a speed of 1.0 m/s. What is his
kinetic energy?
Answers
Answer:
27.5
Explanation:
KE=1/2m(v)^2
Calculate the frequency of an x-ray having a wavelength of 2.5 x 10-7 cm.
Answers
The frequency of an x-ray having a wavelength of 2.5×10⁻⁷ cm is 1.2×10¹⁷ Hz
How do I determine the frequency of the x-ray of wavelength 2.5×10⁻⁷ cm?We'll begin by converting the value of the wavelength from cm to m. Details below:
Wavelength (in cm) = 2.5×10⁻⁷ cmWavelength (in m) =?100 cm = 1 m
Therefore
2.5×10⁻⁷ cm = (2.5×10⁻⁷ cm × 1 m) / 100
2.5×10⁻⁷ cm = 2.5×10⁻⁹ m
Finally, we shall determine the frequency of the x-ray. This is shown below:
Wavelength (λ) = 2.5×10⁻⁹ mSpeed of x-ray (v) = 3×10⁸ m/sFrequency of x-ray (f) =?Velocity (v) = wavelength (λ) × frequency (f)
3×10⁸ = 2.5×10⁻⁹ × frequency
Divide both sides by 2.5×10⁻⁹
Frequency = 3×10⁸ / 2.5×10⁻⁹ m
Frequency = 1.2×10¹⁷ Hz
Thus, from the above calculation, we can conclude, the frequency is1.2×10¹⁷ Hz
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1. If some unimaginable calamity destroyed the Sun, using the astronomical unit for the Earth-Sun distance and the value for the speed of light above, how long would we still have light after the Sun ceased to exist? (5)
Answers
Answer:
8 minutes and 20 seconds
Explanation:
Average Distance between Earth and Sun: 150 million km = \(1.5 * 10^{8}\) km
Velocity of light: \(3 * 10^{8} \ m/s = 3 * 10^{5} \ km/s\)
Time = Distance/Speed
or Time = \(1.5 * 10^{8} \ km\) / \(3 * 10^{5} \ km/s\)
= 5 * 100
= 500 seconds
⇒ Time = 8 minutes and 20 seconds
speed1=20 m/s. time1=5sec
speed2=30 m/s. time2=5sec
speed3=15 m/s. time3=5sec
find average speed?
Answers
Answer:
21.25 m/sExplanation:
AVERAGE SPEED=\( = \frac{s1 t1+ s2t2 + s3t3}{t1 + t2 + t3} \)
\( = \frac{20 \times 10 + 30 \times 5 + 15 \times 5}{10 + 5 + 5} \)
\( = \frac{200 + 150 + 75}{20} \)
\( = \frac{425}{20} \)
\( = 21.25 ms\)
Where do you find the atoms with the strongest metallic properties on the periodic table?
A. the upper left
B. the lower right
C. the lower left
D. the lower right
Answers
Answer:
Key Takeaways: Metallic Character These properties include metallic luster, formation of cations, high electrical and thermal conductivity, and ...
Explanation:
The atoms with the strongest metallic properties on the periodic table are found in upper left corner of periodic table. The correct option is A.
The upper left corner of the periodic table is typically where one can find the atoms with the strongest metallic properties. Alkali metals and alkaline earth metals which are renowned for their high electrical conductivity, luster and malleability are found in this region. These elements are easy to lose and easily form positive ions because they have few valence electrons in their outermost energy levels.
Due to growing atomic size and declining electronegativity, metallic properties tend to become more noticeable as you move down and to the left in this region. On the other hand nonmetals and metalloids with stronger nonmetallic properties such as high electronegativity and poor electrical conductivity make up the lower right region.
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Conduction is greater in solids .explain in your own words Why?
Answers
Explanation:
because conduction takes place in objects whose particles are close/touching each other therefore conduction happens in solid as liquid and gas paricles are not close to each other
What are the three components of the equation for the second law of motion?
Answers
force= mass × acceleration
HAAS Machine Tool Company offers you an SL-20 Machine for $50,000 at an annual interest rate of 2% for 7 Years. If you accept this deal and your company makes (7) end of year payments in the amount of the Annual Cost of the Machine (A) to HAAS, what is the total amount of interest paid to HAAS over the 7 years of making the payments
Answers
PLEASE HELP! NO FAKE ANSWERS
1. Imagine a person flying straight up from Earth's surface. She would experience different conditions as she goes through the layers of the atmosphere. Some layers are cooler, some are hotter, some have oxygen, and some have almost no molecules. Answer the questions below to describe the conditions in each layer. (10 points)
A. What are the conditions in the troposphere? (2 points)
B. What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere? (3 points)
C. What sort of temperatures would she experience in the mesosphere? (2 points)
D. What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere? (3 points)
Answers
Troposphere, stratosphere, mesosphere, thermosphere and exosphere.
What are five layers of earth?Earth's atmosphere has five major layers.
From lowest to highest, layers are the troposphere, stratosphere, mesosphere, thermosphere and exosphere.
a) What are the conditions in the troposphere?
The atmospheric temperature descends upward with a slope of ~10 K km−1 for dry air and ~7 K km−1 for wet air in troposphere.
The temperature of troposphere decreases with an increase in height.
B) What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere?
The temperature in the stratosphere ranges from- 60° F at the troposphere boundary to -5°F at the top.
The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.
C)What sort of temperatures would she experience in the mesosphere?
The temperature in the mesosphere ranges from -2.5°C to -90°C
The temperature decreases because of a decrease in the absorption of penetrating solar radiation.
The atmosphere gets cooler with an increase in altitude because an increase in distance from the Earth's surface.
D)What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere?
4,500°F is the temperature of thermosphere.
Temperatures climb sharply in the lower thermosphere , then level off and hold fairly steady with increasing altitude above that height.
Temperatures in the upper thermosphere can range from about 500° C (932° F) to 2,000° C (3,632° F) or higher.
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You observe a star system for many weeks. The light curve does not show significant changes in brightness, but a series of spectra show a spectral feature that cyclically appears as one absorption line, then two, then one again, and so on. Is this a binary system
Answers
Based on the changes in the light curve and the behavior of the series of spectra, this is a binary system.
How is this is binary system?The characteristics described are those of a binary system with the specific type of system being the spectroscopic binary system.
This is because in a spectroscopic binary system, there won't be significant changes in brightness but as a result of stars orbiting towards and then away from us, spectral features will appear as alternative absorption lines.
In conclusion, this is a binary system.
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what is the necessary condition on the path length difference between two waves that interfere as follows
Answers
The necessary condition on the path length difference between two waves that interfere is that the path length difference must be an integer multiple of the wavelength.
This condition leads to constructive interference, where the two waves add up and result in an increased amplitude.
Step-by-step explanation:
Consider two waves with the same frequency and wavelength traveling towards each other.The path length difference between the two waves is the difference in the distance each wave travels before they meet.If the path length difference is an integer multiple of the wavelength (e.g. 0, λ, 2λ, 3λ...), the waves will meet at points where their phases match, causing constructive interference.On the other hand, if the path length difference is an odd-integer multiple of half the wavelength (e.g. λ/2, 3λ/2, 5λ/2...), the waves will meet at points where their phases are opposite, causing destructive interference.In summary, the necessary condition on the path length difference between two waves that interfere is that it must be an integer multiple of the wavelength for constructive interference to occur.Learn more about conditions are necessary: brainly.com/question/3406634
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i really need help !!
Answers
Answer:
The generator will work only if the magnetic field associated with the turns of coil change.
here both magnet and coil are stationary with respect to each other so no electromagnetic induction would take place. so no indiced current will be produced.
the student has to introduce some mechanism either to rotate the coil or the magnet
a rocket moves through outer space at 12,800 m/s. at this rate how much time would be required to travel the distance from earth to the moon, which is 380,000 km?
Answers
The time required to travel the distance from earth to the moon, which is 380,000 km is 34545.45sec.
To find timeThe formula of speed is speed = distance/time. To check out what the checks are for speed, you must to understand the units for distance and time.
As we know that
Speed = distance/ time
first, convert km into m of distance
then 380,000 km distance will be 380000000m.
putting the given values in the formula
12800 = 380000000 / time
The time required would be
34545.45 seconds.
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how far away is lightning if thunder sounds 10 seconds after the lightning flashes?
Answers
Sound travels at approximately 343 meters (or 1,125 feet) per second in dry air at room temperature.
To determine how far away lightning is when thunder sounds 10 seconds after the lightning flash, we can use the speed of sound.
Distance = Speed × Time
Distance = 343 m/s × 10 s
Distance = 3,430 meters
Therefore, if thunder sounds 10 seconds after the lightning flash, the lightning is approximately 3,430 meters (or 3.43 kilometers) away.
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Match the material with its property. Metals
Ceramics
Composites
Polymers Semiconductors - Good electrical and thermal insulators
- Conductivity and weight can be tailored
- Poor electrical and thermal conductivity - The level of conductivity or resistivity can be controlled - low compressive strength
Answers
Metals - Conductivity and weight can be tailored, Ceramics - Good electrical and thermal insulators, Composites - The level of conductivity or resistivity can be controlled, Polymers - Poor electrical and thermal conductivity, Semiconductors - low compressive strength.
Metals: Metals are known for their good electrical and thermal conductivity. They are excellent conductors of electricity and heat, allowing for efficient transfer of these forms of energy.
Ceramics: Ceramics, on the other hand, are good electrical and thermal insulators. They possess high resistivity to the flow of electricity and heat, making them suitable for applications where insulation is required.
Composites: Composites are materials that consist of two or more different constituents, typically combining the properties of both. The conductivity and weight of composites can be tailored based on the specific composition.
Polymers: Polymers are characterized by their low conductivity, both electrical and thermal. They are poor electrical and thermal conductors.
Semiconductors: Semiconductors possess unique properties where their electrical conductivity can be controlled. They have an intermediate level of conductivity between conductors (metals) and insulators (ceramics).
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The picture below shows Earth:
A. rotating
B. revolving
C. orbiting
D. stopping
Answers
The figure shows about the rotating earth.
To find the correct option among all the options, we need to know about the rotation state of earth.
What is rotation of earth?Motion of earth about its own axis is known about its rotation motion.
How does rotation motion different from orbital or revolving motion?In revolving and orbital motion, an object moves around an axis out side of that bulk of object in a certain orbit, while in rotational motion, the object moves around its own axis.
How is rotation motion represented?Rotation motion is represented by drawing an axis in the bulk of object and to indicate the rotation a circular arrow is drawn.
Thus, we can conclude that the figure shows about the rotating earth.
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1: The ball is on the 50 yard line. The ball travels west 5 yards before it's
handed off and ran forward (EAST) 15 yards where they're tackled.
What is the distance the ball traveled?
Your answer
This is a required question
* 1 point
Answers
The ball is on the 50-yard line. The ball travels west 5 yards. The distance ball traveled was 60 yards.
WHAT IS DIFFERENCE BETWEEN DISTANCE AND DISPLACEMENT ?Distance can be defined as the length of any path between any two locations. Displacement is the direct distance between any two points when calculated via the shortest path between them. When computing distance, the direction is disregarded. The displacement computation takes the direction into consideration.
CALCULATIONThe 5 yard gain would bring the ball to the 45 yard line (ball was tackled at the 50 yard line, so 50 - 5 = 45), but the 15 yards lost due to the tackle and push back would bring ball to the 60 yard line (45 + 15 = 60).
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When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet.
Answers
When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet exhibits retrograde motion.
What do you mean by retrograde motion?
Retrograde motion, in astronomy, the actual or apparent motion of a body in the opposite direction to the direction of the (direct) motions of most members of the solar system or other astronomical systems with a preferred direction of motion. Viewed from a position in space north of the Solar System (from some great distance above Earth's north pole), all the major planets revolve around the Sun in a counterclockwise direction, and all but Venus and Uranus rotate counterclockwise about their own axes; these two, therefore, have retrograde rotation. Of the known satellites of the planets, a minority show retrograde revolution. These include the four outermost moons of Jupiter; Phoebe, Saturn's outermost moon; and Triton, the largest of Neptune's moons. The orbital planes of the satellites of Uranus are so strongly inclined that describing the motion of these bodies as retrograde or direct has little meaning. The rotations around the Sun of all known asteroids are direct; of the known periodic comets, only a few, one of which is Halley's Comet, move in a retrograde orbit.To learn more about retrograde motion, refer to:
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What useful thing can happen to a wave when it encounters a concave reflecting surface?
Answers
Answer:
Explanation:
if u just look at it yk u can see it