Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del suelo con un ángulo de θi = 33.0° arriba de la horizontal como se muestra en la figura siguiente. Si la rapidez del chorro cuando sale de la manguera es vi = 40.0 m/s, ¿a qué altura (en m) golpeará el edificio? m
Answers
Answer:
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
Explanation:
El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:
Distancia horizontal (en metros)
\(x = x_{o} + v_{o}\cdot t \cdot \cos \theta\)
Donde:
\(x_{o}\) - Posición horizontal inicial, medida en metros.
\(t\) - Tiempo, medido en segundos.
\(v_{o}\) - Velocidad inicial, medida en metros por segundo.
\(\theta\) - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.
Distancia vertical (en metros)
\(y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}\)
Donde:
\(y_{o}\) - Posición vertical inicial, medida en metros.
\(g\) - Constante gravitacional, medida en metros por segundo al cuadrado.
Partiendo de la primera ecuación, se despeja el tiempo:
\(t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}\)
Si \(x = 31\,m\), \(x_{o} = 0\,m\), \(v_{o} = 40\,\frac{m}{s}\) and \(\theta = 33^{\circ}\), entonces:
\(t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}\)
\(t = 0.924\,s\)
La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si \(y_{o} = 0\,m\), \(v_{o} = 40\,\frac{m}{s}\), \(t = 0.924\,s\) y \(g = -9.807\,\frac{m}{s^{2}}\), entonces:
\(y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}\)
\(y = 15.943\,m\)
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
Related Questions
PLS PLS HURRY!!!! 50 points!!
Fred and Ted are racing cars down a frictionless track with a jump at the bottom
when suddenly an argument breaks out. Fred says, “If we release the cars from a
point twice as high as we are currently doing so, the cars will have twice the
gravitational potential energy, and therefore be travelling twice fast when they hit
the jump." Ted says, “In order to double the speed of the cars when they hit the
ramp, I think we will have to more than double the height!" Who is right? Prove it!
Answers
Answer: I think Fred is right.
Explanation:
Calculate the angular separation θ1 at which two point sources of wavelength 600 nanometers are just resolved when viewed through a circular aperture of diameter 1.5 centimeters. Express your answer in radians to three significant figures.
Answers
4.88×10⁻⁵rad is the angular separation θ1 at which two point sources of wavelength 600 nanometers are just resolved when viewed through a circular aperture of diameter 1.5 centimeters.
What is angular separation?The angle between two sightlines or between two point objects as seen by an observer is known as angular distance (also called as angular separation, apparent distance, and apparent separation).
All of the natural sciences and mathematics make use of angular distance, particularly geometry and trigonometry. It appears with angular velocity, angular acceleration and torque in the classical mechanics of spinning objects.
The angular separation is calculated as given below.
θ =1.220 ×λ/d
= 1.220 ×600×10⁻⁹/1.5×10⁻²
=4.88×10⁻⁵rad
Therefore, the angular separation is 4.88×10⁻⁵rad.
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A 6000 kg truck full of Girl Scout cookies traveling north at 5 m/s collides with a
4000 kg tanker truck full of milk traveling west at 15 m/s. The two remain locked
together after the collision. What is their velocity after the collision?
Answers
Answer:
Approximately \(6.7\; {\rm m\cdot s^{-1}}\) at approximately \(63^{\circ}\) west from north (\({\rm N63^{\circ}W}\).)
Explanation:
The velocity of both vehicles can be described with a two-dimensional vector:
\(\begin{aligned}\begin{bmatrix}(\text{north-south velocity}) \\ (\text{west-east velocity})\end{bmatrix}\end{aligned}\).
(Note that the two directions are perpendicular to one another.)
For example, since the cookie vehicle is travelling north at \(5\; {\rm m\cdot s^{-1}}\), its velocity vector will be:
\(\begin{aligned}v_{a} &= \begin{bmatrix}5 \\ 0\end{bmatrix}\; {\rm m\cdot s^{-1}}\end{aligned}\).
Likewise, the velocity vector of the milk vehicle travelling west at \(15\; {\rm m\cdot s^{-1}}\) will be:
\(\begin{aligned}v_{a} &= \begin{bmatrix}0 \\ 15\end{bmatrix}\; {\rm m\cdot s^{-1}}\end{aligned}\).
When an object of mass \(m\) travels at a velocity of \(v\), the momentum \(p\) of that object will be \(p = m\, v\).
The momentum vector of the \(m_{a} = 6000\; {\rm kg}\) cookie vehicle will be:
\(\begin{aligned}p_{a} &= m_{a} \, v_{a} \\ &= (6000\; {\rm kg})\, \begin{bmatrix}5 \\ 0\end{bmatrix}\; {\rm m\cdot s^{-1}} \\ &= \begin{bmatrix}30000 \\ 0\end{bmatrix}\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}\).
The momentum vector of the \(m_{a} = 4000\; {\rm kg}\) milk vehicle will be:
\(\begin{aligned}p_{a} &= m_{a}\, v_{a} \\ &= (4000\; {\rm kg})\, \begin{bmatrix}0\\ 15\end{bmatrix}\; {\rm m\cdot s^{-1}} \\ &= \begin{bmatrix}0\\ 60000\end{bmatrix}\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}\).
Hence, the total momentum of the two vehicles before the collision will be:
\(\begin{aligned}p_{a} + p_{b} &= \begin{bmatrix}30000\\ 0\end{bmatrix}\; {\rm kg\cdot m\cdot s^{-1}} + \begin{bmatrix}0\\ 60000\end{bmatrix}\; {\rm kg\cdot m\cdot s^{-1}} \\ &= \begin{bmatrix}30000\\ 60000\end{bmatrix}\; {\rm kg\cdot m\cdot s^{-1}} \end{aligned}\).
Let \(v\) denote the velocity vector of the two vehicles right after they collide. With a total mass of \((m_{a} + m_{b}) = (6000\; {\rm kg} + 4000\; {\rm kg}) = 10000\; {\rm kg}\), the total momentum of the two vehicles right after the collision will be: \(p = (m_{a} + m_{b})\, v\).
Momentum is conserved. Hence, right after collision, the total momentum of the two vehicles will stay the same. Thus,
\(\begin{aligned}(m_{a} + m_{b})\, v = p = p_{a} + p_{b}\end{aligned}\).
\(\begin{aligned}v &= \frac{p}{m_{a} + m_{b}} \\ &= \frac{p_{a} + p_{b}}{m_{a} + m_{b}} \\ &= \frac{\begin{bmatrix}30000 \\ 60000\end{bmatrix}\; {\rm kg \cdot m\cdot s^{-1}}}{10000\; {\rm kg}} \\ &= \begin{bmatrix}3 \\ 6\end{bmatrix}\; {\rm m\cdot s^{-1}}\end{aligned}\).
Since the two directions (north-south and west-east) are perpendicular to each other, the Pythagorean Theorem can be applied to find the magnitude of this velocity:
\(\begin{aligned}\| v \| &= \left(\sqrt{3^{2} + 6^{2}}\right)\; {\rm m\cdot s^{-1}} \\ &\approx 6.7\; {\rm m\cdot s^{-1}}\end{aligned}\).
The angle between this velocity and the direction of north can be found as:
\(\begin{aligned}\arctan\left(\frac{\text{opposite}}{\text{adjacent}}\right) &= \arctan \left(\frac{6}{3}\right) \approx 63^{\circ}\end{aligned}\).
A person rides a bike with a constant velocity of 2 m/s. If his total displacement is 10 meters, for how long was he riding?
Answers
Answer:
5s
Explanation:
i just know
A person rides a bike with a constant velocity of 2 m/s. If his total displacement is 10 meters, he was riding for 5 sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Given in question a person rides a bike with a constant velocity of 2 m/s. If his total displacement is 10 meters,
Velocity = Displacement / time
2 = 10/time
time = 5 sec
A person rides a bike with a constant velocity of 2 m/s. If his total displacement is 10 meters, he was riding for 5 sec.
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Riley is doing an experiment working with friction. he wants to find two ways to modify an object that could increase or decrease the same type of friction. which methods could he use to perform his experiment? increasing roughness and speed increasing surface area and aerodynamic design using nonstick materials and ball bearings using lubricants and increasing surface area
Answers
Riley is doing an experiment working with friction. Increasing surface area and aerodynamic design is used to perform the task.
Describe the significance of friction.Friction can cause things to slow down and cease moving if they are stationary. More objects would slide around in a frictionless world, clothes and shoes would be difficult to keep on, and it would be extremely difficult for people or cars to move or change direction. Friction is considered a necessary evil because it is both useful and destructive. Friction enables us to move, write, hold objects, and raise them. As a result, it is required for our survival. Many vital processes cannot take place without friction. The frictional force is described as the force created when two surfaces slide against each other.
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Penetration capabilities in...
- Radio Waves
- Microwaves
- Infrared
- Visible light
- Ultraviolet
- X-rays
- Gamma rays
Answers
Ultra = X-ray
Explanation:
how are things going to paint the roof for beginners painting and decorating the whole house so I'm going away with a few sports mates for a couple nights for beginners but will have a look painting at a time and see what is going to be Strong enough
You wish to date a hip bone fragment you found at a cave site.
You find a ratio of 1 14C atoms for every 31 14N atoms. How many
half- lives have elapsed?
Answers
To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.
The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.
In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.
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a
student is pushing a 55 kg box of textbooks with a horizontal force
of 320 N into their turn room across a rich sidewalk.
a. calculate the weight of the box of books.
b. calculate the coefficient of
than, answer. 6. A student is pushing a 55 kg box of textbooks with a horizontal force of 320 N into their dorm room across a rough sidewalk a Calculate the weight of the box of books? b. Calculate th
Answers
a) The weight of the box of textbooks can be calculated as follows;
Weight of
box= mass × acceleration due to gravity
Where mass= 55 kg
Acceleration due to
gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;
Weight of
box= 55 kg× 9.8 m/s²= 539 N
the weight of the box of textbooks is 539 N.
b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.
The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;
F_x= 320 N (this is the horizontal component of the force)F_y=
(This is the vertical component of the force)Thus, the normal force on the box is given by;
F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.
F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.
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the speed of sound increases by about 0.4 m/s for each degree celsius when the air temperature rises. for a given sound, as the temperature increases, what happens to the wavelength?
Answers
As the temperature of the air increases, the speed of sound also increases.
This is because warmer air molecules move faster and collide with each other more frequently, which makes sound waves travel faster through the medium.
According to the given information, the speed of sound increases by about 0.4 m/s for each degree Celsius of temperature rise.
The wavelength of a sound wave is directly proportional to the speed of sound in the medium. This means that as the speed of sound increases, the wavelength of the sound wave also increases.
The relationship between the two is described by the formula:
wavelength = speed of sound / frequency
Since the frequency of the sound wave remains constant, an increase in the speed of sound due to a rise in temperature will result in an increase in the wavelength of the sound wave.
Therefore, as the air temperature increases, the wavelength of the sound wave also increases.
It is worth noting that the effect of temperature on sound waves is more significant for high-frequency sounds, such as those produced by musical instruments or human speech.
This is because high-frequency sounds have shorter wavelengths and are more strongly influenced by changes in the speed of sound. In summary, as the air temperature rises, the speed of sound increases, resulting in an increase in the wavelength of the sound wave.
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The wavelength of a particular sound decreases as air temperature increases.
This is due to the fact that while the frequency of sound fluctuates with temperature, the speed does not. Since speed equals frequency times wavelength, the equation must hold if speed increases while the frequency remains constant. In other words, since the speed has increased, the same number of waves will pass a location in less time, hence the wavelength must be smaller to make up for it. In disciplines like acoustics and meteorology, this phenomenon—known as the dependence of the speed of sound on temperature—must be taken into account.
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A conducting bar moves along a circuit with a
constant velocity. A constant magnetic field is
perpendicular to the bar and circuit. The bar
covers 1.50 m2 of area in 1.00 second. An
EMF of 3.57 V is induced in the circuit. What
is the strength of the magnetic field in Tesla?
[?] T
Answers
Answer:
2.38 T
Explanation:
Since the number of coils and the change in time are both 1, I set it up as 3.57=1.50(x) and then solved for x to be 2.38 T.
Plz I need help on my last question
Answers
Answer:
Dispalcement(s)=v*t
=8.1*6
=48.6m
the propulsion force on a car is due to group of answer choices static friction. kinetic friction. elastic energy. the car engine.
Answers
Static fiction, A force that holds an object at rest is called static friction.
What is static fiction?
When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. The frictional force opposes an object's motion in kinetic friction.
Static friction is a force that maintains an object at rest. Static friction is defined as the resistance one encounters when attempting to move a stationary object across a surface without actually moving their body or the surface they are moving the object across.
Static friction is a type of friction force that acts on the body when there is no relative motion between the object and the surface.
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Calculate force a father will push a 20.0 kg baby carriage with
if he goes 4.5 m while he does 2920 J of work.
Answers
Answer:
649 N
Explanation:
W = force X distance
2920 = force * 4.5
2920/4.5 = force = 649 N
Sorry if it’s a bit blurry. But thanks for answering if you do!
Answers
I don’t know too much about the earths core but I’m pretty sure it’s energy
111. When a meteorite strikes Earth, the meteorite or its pieces remain on or near Earth's surface. Suppose a giant object from space enters the solar system and collides head-on with Earth as Earth travels in its path around the Sun.
If the object's speed is twice Earth's speed, how massive must it be to reduce Earth's orbital velocity by even a hundredth of a percent? Annotate your calculation with a description of your approach.
Answers
Answer:
Explanation:
To calculate the mass of an object that would reduce Earth's orbital velocity by even a hundredth of a percent, we need to use the conservation of momentum principle. According to this principle, the total momentum of a system remains constant if no external forces act on it.
In this scenario, we can consider the Earth and the object as a closed system. The initial momentum of the system is Earth's momentum, and the final momentum is Earth's momentum after the collision.
Let's assume the mass of the Earth is M_E and the initial velocity of Earth is V_E. After the collision with the object, the final velocity of Earth is V_E' . The mass of the object is M_O, and its velocity is V_O (twice Earth's velocity)
The conservation of momentum principle states that:
M_E * V_E = M_E * V_E' + M_O * V_O
To reduce Earth's orbital velocity by even a hundredth of a percent, we can assume that V_E' = V_E - (0.0001 * V_E)
Therefore,
M_E * V_E = M_E * (V_E - (0.0001 * V_E)) + M_O * (2 * V_E)
Rearranging this equation we can find the mass of the object M_O
M_O = M_E * (V_E / (2 * V_E - 0.0001 * V_E))
To get the exact mass of the object, we need to know the mass of the Earth and the velocity of Earth, which are not provided in the question. However, this calculation will give an approximate mass that the object would need to have in order to reduce Earth's orbital velocity by even a hundredth of a percent.
A ball is falling from the sky down to the left. What two forces are being used?
Answers
Answer:
push and pull
Explanation:
i beleve good luck❤️❤️
Answer: Gravity for sure and...air resistance.
Explanation: I hope this is correct.
can someone please answer this, ill give you brainliest and your getting 100 points.
Answers
Answer:
Pacific and Australia
Explanation:
Convergent boundary is the area where two plates collide.
Means the direction of arrows should be opposite and towards each other .
Answer:
Pacific and Australian
Explanation:
Convergent boundaries are where two plates come together. Either tall mountains are formed on land or deep trenches in the ocean. There are deep ocean trenches where the Pacific and Australian plate converge.
A man supports himself and the uniform horizontal beam pulling the rope with a force T.The weights of men and the beam are 883 N and 245 N respectively.Calculate the tension T in the rope and the forces exerted by the pin at A.
Answers
Answer:
T=502.5N
Ax=171.8N
Explanation:
The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:
vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0
Now
horizontal forces sum = Ax - Tcos70
Now Moment about B
-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0
Ay=453.6N
Now substitute in sum of vertical forces T=502.5N
Ax=171.8N
a. The tension (T) in the rope is equal to 502.51 Newton.
b. The forces exerted by the pin at A is equal to 171.86 Newton.
Given the following data:
Weight of men = 883 N Weight of beam = 245 NTo calculate the tension (T) in the rope and the forces exerted by the pin at A:
First of all, we would determine the vertical force by taking moment about point B as shown in the diagram.
\(-A_y \times 4.8 + 883 \times 1.8 + 245 \times 2.4 =0\\\\-4.8A_y + 1589.4 + 588 =0\\\\4.8A_y= 3237\\\\A_y=\frac{2177.4}{4.8} \\\\A_y= 453.63 \;Netwon\)
The tension (T) in the rope would be calculated by the sum of the vertical component of forces, which is given by:
\(\sum F_x = A_y + Tsin20 + T - 245 - 883 = 0\\\\453.63 + 0.3420T + T -1128=0\\\\1.3420T = 1128-453.63\\\\1.3420T =674.37\\\\T =\frac{674.37}{1.3420}\)
Tension, T = 502.51 Newton.
To find the forces exerted by the pin at A, we sum the vertical component of forces, which is given by:
\(\sum F_y = A_x - Tcos70 =0\\\\A_x =Tcos70\\\\A_x = 502.51 \times cos70\\\\A_x = 502.51 \times 0.3420\\\\A_x = 171.86\;Newton\)
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Calculate the initial oil-in-place (N) of a volumetric oil reservoir if:
A=1,600 acres, h=32 ft, Ø = 22%, Si = 20%, B= 1.23 bbISTB
Calculate the initial gas-in-place of a volumetric gas reservoir if:
A=1,320 acres, h=45 ft, Ø = 17.5%, Sw = 23%, By = 0.004276 cuft/SCF
Answers
The initial oil-in-place (N) of a volumetric oil reservoir is a critical parameter used to estimate the total amount of oil that can be recovered from the reservoir. It represents the total volume of oil contained within the reservoir at the beginning of its production life.
The initial gas-in-place (G) of a volumetric gas reservoir is a critical parameter used to estimate the total amount of gas that can be recovered from the reservoir. It represents the total volume of gas contained within the reservoir at the beginning of its production life.To calculate the initial oil-in-place and gas-in-place, we need to use certain parameters such as the area of the reservoir, the thickness of the reservoir, the porosity of the reservoir, the initial oil or water saturation, and the formation volume factor. The formulas used to calculate the initial oil-in-place and gas-in-place are different, and the parameters used in each formula are specific to either an oil or gas reservoir.
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Now, let's look at a situation with changing flux. Starting from the far left of the screen, move the magnet to the right so it goes through the middle of the two loops coil at a constant speed and out to the right of the coil. Roughly where is the magnet when the light bulb is the brightest? (The brightness of the light bulb correlates with how much the needle of the voltmeter gets deflected away from the middle.) a) The light bulb is brightest when the middle of the magnet is in the middle of the coil. b) The brightness of the light bulb is the same, regardless of the location of the magnet (as long as it is moving). c) The light bulb is brightest when either end of the magnet is in the middle of the coil. d) The light bulb does not shine since the magnet is moving at a constant speed.
Answers
The correct answer is: a) The light bulb is brightest when the middle of the magnet is in the middle of the coil.
This phenomenon is known as Faraday's law of electromagnetic induction, which states that a changing magnetic field induces an electromotive force (EMF) in a nearby conductor. When the magnet is moved through the coil, the magnetic flux through the coil changes, which induces an EMF in the coil according to the law. The magnitude of the EMF is proportional to the rate of change of the magnetic flux.
When the magnet is in the middle of the coil, the magnetic flux through the coil is changing at its maximum rate. Therefore, the induced EMF and the current through the bulb are at their maximum, making the bulb the brightest. As the magnet moves away from the middle of the coil, the rate of change of the magnetic flux decreases, and so does the brightness of the bulb.
So, the correct answer is a) The light bulb is brightest when the middle of the magnet is in the middle of the coil.
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the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answers
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
The driver of a car slams on the brakes, causing the car to slow down at a rate of 24.0ft/s? as the car skids 253ft to a stop.
How long does the car take to stop?
What was the car's initial speed?
Answers
It takes approximately 4.59 seconds for the car to come to a stop. the car's initial speed was approximately 110.2 ft/s,
To determine the time it takes for the car to stop and the car's initial speed, we can use the kinematic equation:
v² = u² + 2as
where:
v is the final velocity (0 ft/s, since the car comes to a stop),
u is the initial velocity (unknown),
a is the acceleration (-24.0 ft/s², as the car slows down),
and s is the distance traveled (253 ft).
Plugging in the known values into the equation, we can solve for u:
0² = u² + 2(-24.0 ft/s²)(253 ft)
0 = u² - 48.0 ft/s² * 253 ft
48.0 ft/s² * 253 ft = u²
u² = 12144 ft²/s²
Taking the square root of both sides:
u = √12144 ft/s
u ≈ 110.2 ft/s
So, the car's initial speed was approximately 110.2 ft/s.
Now, to find the time it takes for the car to stop, we can use the equation:
v = u + at
0 = 110.2 ft/s + (-24.0 ft/s²) * t
24.0 ft/s² * t = 110.2 ft/s
t = 110.2 ft/s / 24.0 ft/s²
t ≈ 4.59 s
Therefore, it takes approximately 4.59 seconds for the car to come to a stop.
In summary, the car's initial speed was approximately 110.2 ft/s, and it took approximately 4.59 seconds for the car to come to a stop while skidding a distance of 253 ft.
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Work done on a point mass A point mass m = 7 kg is moving in 2D under the influence of a constant force F = 2i-8j N. At time t = 0 s the mass has position vector ro = 7i - 8j m, while by time t =6 s it has moved to rf = 4i+3j m. How much work W does the force F do on the point mass between these two times? W = _____ J
Answers
-94 J is the work done (W) on the point mass between these two times.
To find the work done (W) on a point mass (m = 7 kg) between two times (t = 0 s and t = 6 s) under the influence of a constant force F = 2i - 8j N, we can use the formula:
W = F • Δr
where W is the work done, F is the force, and Δr is the change in position vector.
First, we need to find the change in position vector:
Δr = rf - ro = (4i + 3j) - (7i - 8j) = -3i + 11j
Now, we can find the dot product of F and Δr:
F • Δr = (2i - 8j) • (-3i + 11j) = 2(-3) + (-8)(11) = -6 - 88 = -94
Therefore, the work done (W) on the point mass between these two times is:
W = -94 J
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Xplain to someone who knows nothing about fossils the study of paleobotany and how it helps scientists understand the history of the earth. Be sure your explanation contains a minimum of two complete sentences.
Answers
Answer:
They're impressions of organisms preserved in rock. Paleontologists use fossil remains to understand different aspects of extinct and living organisms. They do this by analyzing invertebrate fossils. All of this, all this studying helps to know our past.
Explanation:
Maria drove 100 miles in 2 hrs. what was marias speed?
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A cycler rides 27.0 km in 13 minutes, then 33.0 km in 17 minutes. What is the jogger's average speed in km per minute?
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Answer: 9
Explanation: because you would add 13+4=17, then you would add 27+5=33, so then 4+5=9 so there's your answe
Which diagram has a greater gravitational force
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Answer:
2
Explanation:
Due to the fact that the gravitational force is inversely proportional to the mass of the two interacting objects, heavier objects will be drawn together by a stronger gravitational attraction. As a result, the gravitational pull between two objects grows as their respective masses rise.
What mass has a greater gravitational force?Since the gravitational force is exactly proportional to the mass of both interacting objects, heavier items will be attracted by stronger gravitational forces. Therefore, the gravitational attraction between two objects grows as their respective masses do as well.
The attraction created by gravity is between masses. The gravitational force, commonly known as the gravity force, increases with the size of the masses. With an increase in the distance between masses, the gravitational pull rapidly lessens.
Therefore, second have greater gravitational force.
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During a recent upset victory against New Greer Academy, South's #2 singles player, Dimitri, stepped in some mud and left the following tracks along the baseline. The point-to-point distances are:
A to B: 18.1 feet
B to C: 13.3 feet
What is Dimitri's total distance?
Distance
feet
Attempts: 0
What is the magnitude of Dimitri's displacement?
Displacement
feet
Attempts: 0
Answers
Distance can be defined as the amount of ground covered (traveled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.
Mathematically, the distance traveled by a physical object can be calculated by using this formula:
Distance = speed × time
What is Dimitri's total distance?Dimitri's total distance is the sum of the distance he covered by moving from point A to B and then from B to C. Thus, his total distance is given by:
Total distance = AB + BC
Total distance = 18.1 + 13.3
Total distance = 31.4 feet.
What is the magnitude of Dimitri's displacement?The magnitude of Dimitri's displacement would be calculated by finding the difference in the position of the two point-to-point distances as follows:
Displacement = AB - BC
Displacement = 18.1 - 13.3
Displacement = 4.8 feet.
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why aeroplanes and boat having bird like structure
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People have looked up at birds for years and they have inspired us to fly. Airplanes have wings, just like birds. They also have a light skeleton (or framework) to decrease their weight, and they have a streamlined shape to decrease drag.
manita carries a box of mass 40kg. What is the wieght of the box?
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Answer:
40kg
Explanation:
that the answer