Tendremos lo siguiente:
Primero, recordamos que en el caso de un elevador
\(T=mg+ma\)Aquí "T" es la tensión, "m" es la masa, "g" es la aceleración de la gravedad y "a" es la aceleración del elevador. Con esto, remplazamos la información y solucionamos para "a":
\(8950N=\left(752kg\right)\left(9.8m/s^2\right)+\left(752kg\right)*a\Rightarrow\left(752kg\right)a=8950N-7369.6N\)\(\Rightarrow a=\frac{1580.4N}{752kg}\Rightarrow a=\frac{3951}{1880}m/s^2\)\(\Rightarrow a=2.101595745...m/s^2\Rightarrow a\approx2.1m/s^2\)Entonces, la aceleración del elevador es aproximadamente 2.1 m/s^2.
A 10,000 kg freight car moving at 2 m/s collided with a stationary 30,000 kg freight car. The two cars couple together and move off at what speed?
Answer:
Explanation:
Momentum conservation:
10,000 x 2 = (10,000 + 30,000) x v
so
v = 0.5 m/s
The speed after collision will be = 0.5m/s
What is conservation of momentum ?The conservation of momentum states that the amount of momentum remains constant , momentum is neither be created nor be destroyed but only changes through the actin of forces as described by newton's law of motion
since , momentum should be conserved before and after the collision
so , from momentum conservation we can write ,
m1 = mass of moving freight car = 10000kg
v1 = speed of moving freight car = 2m/s
m2 = mass of stationary freight car = 30000 kg
v2 = speed of stationary freight car = 0 (since , at rest )
M = mass of coupled cars after collision
V = velocity coupled cars after collision
momentum before collision = momentum after collision
m1*v1 + m2*v2 = MV
10000 * (2) + 30,000 * 0 = (10000 + 30000) V
20000 = 40000V
V = 0.5 m/s
The speed after collision will be = 0.5m/s
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At 20 ◦C a copper wire has a resistance of 4×10−3 Ω and a temperature coefficient of resistivity of 3.9×10−3 (C◦)−1, its resistance at 100 ◦C is
A.
52.5 × 10-3 Ω
B.
5.25 × 10-3 Ω
C.
5.25 × 10-4 Ω
D.
5.25 × 10-2 Ω
E.
25.5 × 10-3 Ω
Answer:
\(R _{t} = R _{0}( \alpha t + 1) \\ = 4 \times {10}^{ - 3} (3.9 \times {10}^{ - 3} \times 20 + 1) \\ = 4 \times {10}^{ - 3} (1.078) \\ = 4.312 \times {10}^{ - 3} \: Ω\)
How many centimeters are in a kilometer? Step by step explanation
100,000 centimeters or 10⁵ centimeters are in a kilometer.
What is unit of length?Any arbitrarily selected and widely used reference standard for length measurement is referred to as a unit of length. The metric system, which is adopted by every nation on earth, is the most widely utilized in modern times.
We know that:
1 kilometer = 1000 meters.
And 1 meter = 100 centimeters.
So, 1 kilometer = 1000 meters
1 kilometer = 1000 × 100 centimeters
1 kilometer = 100,000 centimeters
1 kilometer = 10⁵ centimeters.
Hence, 100,000 centimeters or 10⁵ centimeters are in a kilometer.
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How much energy is needed to change the temperature of 50g of water 15°c
Explanation:
This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature
why is a magnetic field used to deflect electron beam but not an electric field in a tv picture tube
Answer:
Here's ur answer
Explanation:
It is deflected by both electric and magnetic field because it carries negative charge
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A pulse of sound takes 1 second to travel about 25 feet to the seafloor
100
and back. A ship stops in an area where the seafloor extends to the bottom
of the Sunlight Zone. At this spot an echosounder gives a pulse of sound
that takes 26 second to travel to the seafloor and back. How deep is the
100
ocean at the bottom of the Sunlight Zone?
HELP!!! I’m stumped!! Get max points ( if it lets me! )
Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.
The distance travelled by echo sound is given by the formula -
Speed = 2×distance/time
So, calculating the speed of sound from the formula using distance and time
Speed = 2×25/(1/100)
Speed = 50×1000
Speed of sound = 5000 feet/second
Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -
Distance = (speed×time)/2
Distance = (5000×26/100)/2
Distance = 1300/2
Distance = 650 feets
Hence, the depth of ocean is 650 feets.
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Answer:
We can start by using the formula:
distance = speed x time
where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.
The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).
Converting the round-trip time to seconds, we have:
26 seconds - 1 second = 25 seconds
Substituting the values into the formula:
2 x depth = 4,921 feet/second x 25 seconds
2 x depth = 123,025 feet
depth = 61,512.5 feet
Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.
A 1700 kg is traveling along a highway at 100 km/hr and skids to a halt. a) How far will the car travel (while skidding) if the coefficient of kinetic friction between the tires and the road is 0.7? b) How many kilojoules of energy is dissipated during this braking? c) What happens to this energy? Where does it go?
why is measurment necessary in our daily life?
Answer:
Measurements play an important role in daily life because they are useful to do basic tasks, such as take a child's temperature with a thermometer, make time estimations, measure out medicine and find weights, areas and volumes of different materials or substance. Measurement is widely used applications of mathematics.
can someone help me pleaseenkwnsn
If a third resistor is added in SERIES, what changes happens to the....
a. Total Voltage - stay the same b. Total Current - decrease c. Total Resistance - increase d. Voltage through resistor 1 - decrease e. Current through resistor 1 - decreaseWhat happens in a circuit?When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.
The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.
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The photograph below shows a girl pushing on a large stone sphere. The sphere has a mass of 8200 kg and a radius of 90 cm and floats with nearly zero friction on a thin layer of pressurized water. Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 25 N and that the pressured water provides a frictionless support. How long will it take her to rotate the sphere one time, starting from rest?
The time required for a girl to rotate the sphere one time, starting from rest, is 19.256 s.
A measure of an object's resistance to changes in its rotating motion, the moment of inertia, is used in physics. It measures the amount of mass disposed about a rotational axis. The equivalent of mass in linear motion is the moment of inertia in rotational motion.
The inertia is given by:
I = (2/5)m×r²
I = (2/5) × 8200 kg × (0.9m)²
I = 2657 kg·m²
The torque is given by:
τ = I×α
25 × 0.9 = 2657 × α
α = 0.00846 rad/s²
The angular displacement is:
Θ = ½α×t²
2π rads = ½ × 0.00846 × t²
t =√(4π rads/0.0106rad/s²)
t = 19.256 s
Hence, the time required for a girl to rotate the sphere one time, starting from rest, is 19.256 s.
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a box of mass 8.0 kg rests on a horizontal rough surface. a string attached to the box passes over a smooth pulley and supports a 2.0 kg mass at its other end, when the box is released, a frictional force of 6.0 n acts on it. (a) draw free-body diagrams of the 8.0 kg box and the 2.0 kg mass. (b) determine the (i) acceleration of the system, (in) tension in the string.
a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.
bi) the acceleration of the system is 0.4 m/s^2
bii) the tension in the string is 0.8 N.
How do we calculate?Net force = ma
Net force = T - F_friction
where T is the tension force and F_friction is the frictional force.
Substituting the given values, we have:
T - F_friction = ma
T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)
T - 6.0 N = 10.0 kg a
(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:
Net force = ma
where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:
Net force = T
Substituting the given values, we get:
T = ma
T = 2.0 kg x a
To solve for T, we need to find the acceleration of the system.
To find both a and T, we can use the equations we derived above and solve them simultaneously:
T - 6.0 N = 10.0 kg a (equation 1)
T = 2.0 kg x a (equation 2)
Substituting equation 2 into equation 1, we get:
2.0 kg x a - 6.0 N = 10.0 kg a
Solving for a, we get:
a = 0.4 m/s^2
Substituting a into equation 2, we get:
T = 2.0 kg x 0.4 m/s^2 = 0.8 N
Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.
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What is the speed at 5.0 seconds? (Use the graph to draw on and help you)
The graph of the given values in the table is shown below:
In the previous graph, speed is represented by the vertical values (each unit represents 10.0 m/s) and time is represented by horizontal values (each unit represents 1.0s).
As you can notice on the graph, for a time of 5.0s the speed is 25.0m/s (by considering the red lines with show the values on vertical and horizontal axis)
a What is meant by zero error?
b Give an example of when you would have to allow
for it.
a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.
b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.
a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.
Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.
b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.
In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.
To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.
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A watermelon seed has the following coordinates: x = -7.1 m, y = 5.6 m, and z = 0 m. Find its position vector as (a) a magnitude and (b)
an angle relative to the positive direction of the x axis. If the seed is moved to the xyz coordinates (4.7 m, Om, O m), what is its
displacement as (c) a magnitude and (d) an angle relative to the positive direction of the x axis? Put the angles in the range (-180°, 180°]
Who has so much time to measure the fμcking seeds?
How long does it take an airplane to fly 5000m if it maintains a speed of 240 meters per second
Explanation:
s/u =t
5000m/240ms-1
20.8 s
An object is dropped on earth (g=10m/s/s (meters per second per second or m/s^2)) and it falls for five seconds draw a speed vs time graph
Answer:
v = 10t
Explanation:
The velocity of an object after time t is given by the equation
v(t) = u + at
Here u, the initial velocity is 0
a = acceleration = g = 10 m/s²
Therefore at any time,
v(t) = 0 + 10t
v = 10t
After 5 seconds, v = 10 m/s² x 5s = 50 m/s
The graph of this equation is given
A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above her head, and the string angles down slightly (11.9° below the horizontal.). The string is massless and 0.75m long.
A coordinate system lies with its origin a the location where the string comes out of the girl's hand. The positive z-axis points vertically. the projection onto the horizontal plane is such that the string makes an angle of 34.6° with the x-axis.
At a certain instant, the rock makes 2.50 revolutions per second (rev/s) in a counterclockwise direction as seen from above.
What is the tangential velocity vector at this instant?
Complete Question
The diagram of with this question is shown on the first uploaded image
Answer:
The value is \(v = -6.543 \^ i + 9.47 \^ j + 0 \^ k\)
Explanation:
From the question we are told that
The mass of the rock is \(m = 0.250 \ kg\)
The length of the string is \(L = 0.75 \ m\)
The angle the string makes horizontal is \(\theta = 11.9^o\)
The angle which the projection of the string onto the xy -plane makes with the positive x-axis is \(\phi = 34.6^o\)
The angular velocity of the rock is \(w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s\)
Generally the radius of the circle made by the length of the string is mathematically represented as
\(r = L cos(\theta )\)
=> \(r = 0.75 cos(11.9 )\)
=> \(r = 0.734 \ m\)
Generally the resultant tangential velocity is mathematically represented as
\(v__{R}} = w * r\)
=> \(v__{R}} = 15.7 *0.734\)
=> \(v__{R}} = 11.5 \ m/s\)
Generally the tangential velocity along the x-axis is
\(v_x = -v__{R}} * sin(\phi)\)
=> \(v_x =- 11.5 * sin(34.6)\)
=> \(v_x = -6.543 \ m/s\)
The negative sign show that the velocity is directed toward the negative x-axis
Generally the tangential velocity along the y-axis is
\(v_y = v__{R}} * cos(\phi)\)
=> \(v_y = 11.5 * cos(34.6)\)
=> \(v_y = 9.47 \ m/s\)
Generally the tangential velocity along the y-axis is
\(v_z = v__{R}} * cos(90)\)
=> \(v_z = 0 \ m/s\)
Generally the tangential velocity at that instant is mathematically represented as
\(v = -6.543 \^ i + 9.47 \^ j + 0 \^ k\)
Suppose that A’, B’ and C’ are at rest in frame S’, which moves with respect to S at speed v in the +x direction. Let B’ be located exactly midway between A’ and C’. At t’=0 a light flash occurs at B’ and expands outward as spherical wave.
1. According to an observer in S’, do the wave fronts arrive at A’ and C’ simultaneously?
2. According to an observer in S, do the wavefronts arrive at A’ and C’ simultaneously?
3. If you answered no to either 1. or 2., what is the difference in their arrival times and at which point did the front arrive first?
Answer:
1) an observer in B 'sees the two simultaneous events
2)observer B sees that the events are not simultaneous
3) Δt = Δt₀ /√ (1 + v²/c²)
Explanation:
This is an exercise in simultaneity in special relativity. Let us remember that the speed of light is the same in all inertial systems
1) The events are at rest in the reference system S ', so as they advance at the speed of light which is constant, so it takes them the same time to arrive at the observation point B' which is at the point middle of the two events
Consequently an observer in B 'sees the two simultaneous events
2) For an observer B in system S that is fixed on the Earth, see that the event in A and B occur at the same instant, but the event in A must travel a smaller distance and the event in B must travel a greater distance since the system S 'moves with velocity + v. Therefore, since the velocity is constant, the event that travels the shortest distance is seen first.
Consequently observer B sees that the events are not simultaneous
3) let's calculate the times for each event
Δt = Δt₀ /√ (1 + v²/c²)
where t₀ is the time in the system S' which is at rest for the events
What frequency (in Hz) of sound at 20.1 degrees Celsius has a wavelength of 1.71 m?
The frequency of sound at the given temperature is 200.58 Hz.
Frequency of sound at the given temperatureThe frequency of sound at the given temperature is calculated as follows;
v = fλ
f = v/λ
where;
v is speed of sound at 20 ⁰C = 343 m/sλ is wavelength of the sound = 1.71 mf = 343/1.71
f = 200.58 Hz
Thus, the frequency of sound at the given temperature is 200.58 Hz.
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Explain physics in a essay
The scientific study of physics focuses on the underlying concepts that underpin the laws of nature. It investigates how matter, energy, space, and time behave and interact. Physics' fundamental goal is to comprehend the underlying laws and forces that create our universe.
Physics has developed theories and rules to explain a wide variety of events, from the motion of celestial bodies to the behaviour of subatomic particles, via meticulous observation, investigation, and mathematical analysis.
These theories offer a framework for comprehending and forecasting the behaviour of physical systems, such as Newton's laws of motion and Einstein's theory of relativity.
From the tiniest particles to the biggest cosmic structures, physics has enhanced our understanding of the world and sparked a host of technological advances.
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assignment questions
Answer:
which on a is the question
When I mix 200g of water at 10°C with 300g of water at 55°C, what is the final temperature of the mixture?
Answer:
4th of August is the
Explanation:
5th and then I can help out by getting
What must a scientist do in order to develop a testable hypothesis?
Answer:
Explanation:
Ask a question that can be answered by making observations.
Answer: (APE X) Determine whether experimental observations can provide evidence to support a conclusion
Explanation:
How did the approximate speed
of the marbles belore each collision compare
to after each collision?
Answer:
i think this may help you
Explanation:
In an inelastic collision the total kinetic energy after the collision is not equal to the total ... If there are no net forces at work (collision takes place on a frictionless surface ... Momentum is equal to the product of mass and velocity. ... bodies before the collision is equal to the total kinetic energy of the bodies after the collision.
At last you are in a place where the heat and high density are no longer bothering you. However, although the density is very low, the gas around you is extremely high in temperature. In fact, the temperature is so high that it is emitting lots of X rays, which are creating cancer-causing mutations in your body at a rapid rate. Well, at least the view is great! There are no stars anywhere within about 10,000 light-years of you, but at slightly greater distances your sky is brightened by many beautiful, star-filled structures, some with majestic spiral shapes. Where are you?A) You are in the universe when it was about 200 million years old, just before galaxies began forming.B) You are in the center of the Milky Way Galaxy, looking outward into the Local Group.C) You are somewhere between the Andromeda and Milky Way galaxies in the Local Group.D) You are in intergalactic space within a rich cluster of thousands of galaxies.E) You are in the outskirts of a galaxy whose nucleus is a powerful quasar.
Since at slightly greater distances your sky is brightened by many beautiful, star-filled structures, some with majestic spiral shapes. The place that you are is option D) You are in intergalactic space within a rich cluster of thousands of galaxies.
What is the name of intergalactic space?There is virtually little chance that such primitive life might "infect" those planets because of the extremely low density of intergalactic space. Life without any form of star is a whole different - and even more speculative - topic. Processes outside of thermal equilibrium are essential to life.
Interstellar space is the term for the area between stars, whereas intergalactic space refers to the area between galaxies. The enormous empty voids between galaxies are these.
Therefore, an actual distance between galaxies is known as intergalactic space. The universe appears to have a foam-like structure, with groupings and clusters of galaxies lying along filaments that take up about a tenth of the entire amount of space, according to studies of the large scale distribution of galaxies.
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See full question below
At last you are in a place where the heat and high density are no longer bothering you. However, although the density is very low, the gas around you is extremely high in temperature. In fact, the temperature is so high that it is emitting lots of X rays, which are creating cancer-causing mutations in your body at a rapid rate. Well, at least the view is great! There are no stars anywhere within about 10,000 light-years of you, but at slightly greater distances your sky is brightened by many beautiful, star-filled structures, some with majestic spiral shapes. Where are you?
A) You are in the universe when it was about 200 million years old, just before galaxies began forming.
B) You are in the center of the Milky Way Galaxy, looking outward into the Local Group.
C) You are somewhere between the Andromeda and Milky Way galaxies in the Local Group.
D) You are in intergalactic space within a rich cluster of thousands of galaxies.
E) You are in the outskirts of a galaxy whose nucleus is a powerful quasar.
Oxygen is obtained through various methods. Which of the following methods involves a chemical
change?
1. Electrolysis of water
2. Distillation of liquid air
3. Heating of KCIO,
02
1 and 2
1 and 3
Answer:
1
Explanation:
Electrolysis is the passing of an current through a conducting solution, when the occurs, a chemical reaction takes place.
Heating a chemical will always cause a chemical reaction, which is why 3 is also correct
Some information as to why 2 is NOT correct.
2 is NOT a chemical reaction, but rather a process of physical separation. It uses selective boiling and condensation, but is not considered a chemical reaction.
as with 3, heating is not considered a chemical reaction, but rather a physical temperature change. This is always what it is considered to be (e.g boiling water is a physical temperature change, not a chemical reaction)
Hope this helps.
Hope this helps.
which of the following statements about mass and weight is correct?
A. "Mass" is the scientific term for "weight''
B. Weight directly measures force while mass directly measures amount of matter.
C. Weight has unit of kilograms or grams. Mass has unit of newtons.
D. The mass of an object depends on the size of the object. The weight of an object dosent depend on the size of the object.
The correct answer is B. Weight directly measures force while mass directly measures the amount of matter.
Explanation:
Weight and mass are two related but not identical concepts. The first term "mass" can be found by measuring the amount of matter in a body or substance. For example, the mass in an apple is around 80 grams depending on its size. In this context, mass is measured using units such as grams or kilograms. On the other hand, weight considers not only the matter in an object but the force exerted in it, especially, the gravitational force. In the case of the apple, the weight is 1 N as newtons (N) are used to measure force and this is the result of multiplying the mass by gravity. According to this, option B is correct.
A mass m at the end of a spring of spring constant k is undergoing simple harmonic oscillations with amplitude A.
Part (a) At what positive value of displacement x in terms of A is the potential energy 1/9 of the total mechanical energy?
Part (b) What fraction of the total mechanical energy is kinetic if the displacement is 1/2 the amplitude?
Part (c) By what factor does the maximum kinetic energy change if the amplitude is increased by a factor of 3?
Answer:
a) The potential energy of the system is 1/9 of the total mechanical energy, when \(x= \frac{1}{3}\cdot A\).
b) The fraction of the total mechanical energy that is kinetic if the displacement is 1/2 the amplitude is 1/2.
c) The maximum kinetic energy is increased by a factor of 9.
Explanation:
a) From Mechanical Physics, we remember that the mechanical energy of mass-spring system (\(E\)), measured in joules, is the sum of the translational kinetic energy (\(K\)), measured in joules, and elastic potential energy (\(U\)), measured in joules. That is:
\(E = K + U\) (1)
By definitions of translational kinetic energy and elastic potential energy, we have the following expressions:
\(K = \frac{1}{2}\cdot m \cdot v^{2}\) (2)
\(U = \frac{1}{2}\cdot k\cdot x^{2}\) (3)
Where:
\(m\) - Mass, measured in kilograms.
\(v\) - Velocity of the mass, measured in meters per second.
\(k\) - Spring constant, measured in newtons per meter.
\(x\) - Elongation of the spring, measured in meters.
If we know that \(U = \frac{1}{9}\cdot E\), \(k = k\) and \(E = \frac{1}{2}\cdot k \cdot A^{2}\), then:
\(\frac{1}{18}\cdot k\cdot A^{2} = \frac{1}{2}\cdot k\cdot x^{2}\)
\(\frac{1}{9}\cdot A^{2} = x^{2}\)
\(x= \frac{1}{3}\cdot A\)
The potential energy of the system is 1/9 of the total mechanical energy, when \(x= \frac{1}{3}\cdot A\).
b) If we know that \(k = k\), \(x = \frac{1}{2}\cdot A\) and \(E = \frac{1}{2}\cdot k \cdot A^{2}\), then the equation of energy conservation associated with the system is:
\(\frac{1}{2}\cdot k\cdot A^{2} = \frac{1}{4}\cdot k\cdot A^{2}+K\)
\(K = \frac{1}{4}\cdot k\cdot A^{2}\)
The fraction of the total mechanical energy that is kinetic if the displacement is 1/2 the amplitude is 1/2.
c) From the Energy Conservation equation associated with the system, we know that increasing the amplitude by a factor of 3 represents an increase in the elastic potential energy by a factor of 9. Then, the maximum kinetic energy is increased by a factor of 9.
PLEASE FAST 50 POINTS SPACE QUESTION
Explain how Earth's tilt affects the amount of incoming solar radiation and when Earth is tilted toward and away from the Sun
The more slanted the sun's rays are, the longer they travel through the atmosphere, becoming more scattered and diffuse. In the winter, Earth tilts away from the Sun.
Problem No. 5: The results for one patient show that the blood in the aorta begins at a speed of 0.10 m/s and undergoes constant acceleration for 38 ms, reaching a peak speed of 1.29 m/s. (a) What is the acceleration reflected in these data? (b) How far does the blood travel during this period?
A. The acceleration reflected in the data is 38 m/s²
B. The distance traveled by the blood during the period is 0.02 m
How do i determine the acceleration reflected?Acceleration is defined as the rate of change of velocity with time.
From the question given, we were told the the blood undergoes constant acceleration for 38 m/s².
Thus, we can say that the acceleration reflected in this data is 38 m/s²
How do i determine the distance travel by the blood?The distance traveled by the blood can be obtain as follow:
Initial speed (u) = 0.10 m/sFinal speed (v) = 1.29 m/s Acceleration(a) = 38 m/s²Distance traveled (s) =?v² = u² + 2as
1.29² = 0.1² + (2 × 38 × s)
1.6641 = 0.01 + 76s
Collect like terms
76s = 1.6641 - 0.01
76s = 1.6541
Divide both sides by 76
s = 1.6541 / 76
s = 0.02 m
Thus, we can conclude that the distance traveled by the blood during the period is 0.02 m
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