Usually, we do a
when a population is hard to study, for some reason.

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

Answer:

920000

Explanation:

Each kg contains 1,000 grams

The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.

To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.

The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.

The force experienced by the wire due to the magnetic field is F = B * I * L.

Given:

Current (I) = 8.0 A

Magnetic field (B) = 60 mT = 60 * 10^(-3) T

Length of the wire (L) = 40 cm = 40 * 10^(-2) m

Substituting the given values into the equation, we get:

F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)

Simplifying the expression, we find:

F = 0.192 N

Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.

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Answer:

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.

Given:

The initial shot was fired at an angle of 50 degrees above ground.

The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.

Let the angle of the projectile is x,

The horizontal component of velocity can be calculated as follows:

\(v(x) = v * cos(x)\)

We can write:

since the horizontal part of velocity remains constant:

\(v(x1) = v(x2)\)

\(cos(50) = cos(x)\)

\(50 = x\)

Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.

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The correct response is given when the angle is asked a question.

The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun"  is not true about gravity.

Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.

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.

For Part A, we can use the formula Q = mc(T'f - Ti) to calculate the energy required to raise the temperature of the water. Here, Q is the energy required, m is the mass of the water, c is the specific heat capacity of water at 20°C and 1 atm (4.184 J/g°C), T'f is the final temperature (21.6°C), and Ti is the initial temperature (11.2°C).

First, we need to find the mass of the water. Since density = mass/volume, we can rearrange the formula to get mass = density * volume. Plugging in the given values, we get:

mass = (998 kg/m^3) * (4.80 x 10^11 m^3) = 4.79 x 10^14 kg

Now, we can plug in the values into the formula above:

Q = (4.79 x 10^14 kg) (4.184 J/g°C) (21.6°C - 11.2°C) = 2.02 x 10^19 J

Therefore, it would require 2.02 x 10^19 J of energy to raise the temperature of Lake Erie from 11.2°C to 21.6°C.

For Part B, we can use the formula P = E/t to calculate the time required to supply the energy using a power of 1,400 MW. Here, P is the power in watts, E is the energy required in joules (which we found in Part A), and t is the time in seconds. Since we want the time in years, we can convert from seconds to years at the end by dividing by the number of seconds in a year (31,536,000 s).

First, we need to convert the power from MW to W:

P = 1,400 MW * (10^6 W/MW) = 1.4 x 10^9 W

Now, we can rearrange the formula to solve for t:

t = E / P = (2.02 x 10^19 J) / (1.4 x 10^9 W) = 1.44 x 10^10 s

Converting from seconds to years, we get:

t = 1.44 x 10^10 s / 31,536,000 s/year = 456.7 years (rounded to three significant figures)

Therefore, it would take approximately 457 years to supply the energy needed by using a power of 1,400 MW generated by an electric power plant.

Answer:

9 Ω

Explanation:

The following data were obtained from the question:

Resistor 1 (R1) = 3 Ω

Resistor 2 (R2) = 3 Ω

Resistor 3 (R3) = 3 Ω

Resistor 4 (R4) = 3 Ω

Resistor 5 (R5) = 3 Ω

Resistor 6 (R6) = 3 Ω

Resistor 7 (R7) = 3 Ω

Resistor 8 (R8) = 3 Ω

Resistor 9 (R9) = 3 Ω

Resistor 10 (R10) = 3 Ω

Resistor 11 (R11) = 3 Ω

Resistor 12 (R12) = 3 Ω

Equivalent Resistance (R) =.?

From the above diagram,

Resistor 1, 2, 3, 4, 5 and 6 are in series connection and in parralle connections with Resistor 7, 8, 9, 10, 11 and 12 which are also in series connection.

Thus we shall determine the equivalent resistance of Resistor 1, 2, 3, 4, 5 and 6

This is illustrated below:

Resistance Ra = R1 + R2 + R3 + R4 + R5 + R6

Ra = 3 + 3 + 3 + 3 + 3 + 3

Ra = 18 Ω

Next, we shall determine the equivalent resistance of Resistor 7, 8, 9, 10, 11 and 12.

This is illustrated below:

Resistance Rb = R7 + R8 + R9 + R10 + R11 + R12

Rb = 3 + 3 + 3 + 3 + 3 + 3

Rb = 18 Ω

Thus, Ra and Rb are in parallel connections. The equivalent resistance between A and B can be obtained as shown below :

Ra = 18 Ω

Rb = 18 Ω

Equivalent resistance R =?

1/R = 1/Ra + 1/Rb

1/R = 1/18 + 1/18

1/R = 2/18

1/R = 1/9

Invert

R = 9 Ω

Therefore, the equivalent resistance between A and B is 9 Ω.

2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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Answer:

0.5 m/s²

Explanation:

F=ma
F is force
m is mass
a is acceleration

F=ma
5 =  10 x a
a = 5/10
a = 0.5 m/s²

The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.

To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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Answer:

. always start on the north pole and terminate (end) on the South Pole

Explanation:

Answer:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Explanation:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Answer:

The answer is ligaments!

Explanation:

Hope this helps!! :)

all except the rubber boots.

The answers should be The power lines themselves and The metal tools the worker uses (the 1st and 4th choices).

(For anyone curious, the image I attached to this answer is the image given for this problem.)

Answer:

A

Explanation:

A constant velocity means the position graph has a constant slope. It's a straight line sloping up.

Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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Answer:

a

Explanation:

In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.

To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.

First, let's consider the parallel combination:

In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.

Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:

I_parallel = V / R3

= 90 V / 30 Ω

= 3 A

So, in the parallel combination, the current through R3 is 3 A.

Now, let's consider the series combination:

In a series combination, the total resistance is the sum of the individual resistances:

R_total = R1 + R2 + R3

= 60 Ω + 30 Ω + 30 Ω

= 120 Ω

To find the current through the series combination, we can use Ohm's Law:

I_series = V / R_total

= 90 V / 120 Ω

= 0.75 A

Therefore, in the series combination, the current through R3 is 0.75 A.

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Note the complete questions is User

90 V R₁=60 R2=  30, R3 = 30

Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.

Answer:

         v₃ = - (3 i ^ + 4 j ^) m / s

v₃ = 5 m / s,  θ = 233º

Explanation:

This is a momentum problem. Let us form a system formed by the three objects so that the forces during the collisions have been internal and the moment is conserved.

Let's start working with the first two objects.  As each object moves in a different direction let's work with the components in an xy coordinate system

X axis

initial instant. Before the shock

       p₀ₓ = m₁ v₁₀ + 0

final instant. After the crash

      p_{fx} = (m1 + m2) vₓ

the moment is preserved

       p₀ₓ = p_{fx}

       m₁ v₀₁ = (m₁ + m₂) vₓ

       vₓ = \(\frac{m_1}{m_1+m_2} \ v_{o1}\)

Y axis  

initial instant

       p_{oy} = 0 + m₂ v₀₂

final moment

       p_{fy} = (m₁ + m₂) v_y

the moment is preserved

      p_{oy} = p_{fy}

      m₂ v₀₂ = (m₁ + m₂) v_y

      v_y = \(\frac{m_2}{m_1 +m_2 } \ v_{o2}\)

We already have the speed of the set of these two cars, now let's work on this set and vehicle 3

X axis    

initial instant

      p₀ₓ = (m₁ + m₂) vₓ + m₃ v₃ₓ

final instant

      p_{fx} = 0

      p₀ₓ = p_{fx}

      (m₁ + m₂) vₓ + m₃ v₃ₓ = 0

       v₃ₓ = \(- \frac{m_1+m_2 }{m_3} \ v_x\)

Y Axis

initial instant

        p_{oy} = (m₁ + m₂) v_y + m₃ v_{3y}

final moment

        p_{fy} = 0

        p_{oy} = p_{fy}

        (m₁ + m₂) v_y + m₃ v_{3y} = 0

        v_{3y} = \(- \frac{m_1+m_2}{m_3} \ v_y\)

now we substitute the values ​​of the speeds

       v₃ₓ = \(- \frac{m_1+m_2}{m_3} \ \frac{m_1}{m_1+m_2} \ v_{o1}\)  

       v₃ₓ = \(- \frac{m_1}{m_3} \ v_{o1}\)

       v_{3y} = \(- \frac{m_1+m_2}{m_3} \ \frac{m_2}{m_1+m_2} \ v_{o2}\)

       v_{3y} = \(- \frac{m_2}{m_3} \ v_{o2}\)

let's calculate

         v₃ₓ = - ⅓ 9

         v₃ₓ = - 3 m / s

         v_{3y} = - ⅔ 6

         v_{3y} = - 4 m / s

therefore the speed of vehicle 3 is

         v₃ = - (3 i ^ + 4 j ^) m / s

It can also be given in the form of modulus and angles using the Pythagorean theorem

         v₃ = \(\sqrt{v_{3x}^2 + v_{3y}^2}\)

          v₃ = \(\sqrt{3^2+4^2}\)

          v₃ = 5 m / s

let's use trigonometry for the angle

          tan θ' = \(\frac{v_{3y}}{v_{3x}}\)

          θ' = tan⁻¹ (\frac{v_{3y}}{v_{3x}})

          θ' = tan⁻¹ (4/3)

          θ'  = 53º

That the two speeds are negative so this angle is in the third quadrant, measured from the positive side of the x axis

          θ = 180 + θ'

          θ = 180 +53

          θ = 233º

The maximum angle at which an object will not slip on an incline can be calculated using the coefficient of friction (μ).

When an object is on an inclined plane, there are two main forces acting on it: the gravitational force pulling it downward (mg) and the normal force (N) exerted by the inclined plane perpendicular to its surface. Additionally, there is a frictional force (F) acting parallel to the surface of the incline.

To prevent slipping, the frictional force must be equal to or greater than the force component pulling the object down the incline. This force component is given by the equation F = mg sin(θ), where θ is the angle of inclination.

The maximum frictional force that can be exerted between two surfaces is given by the equation F = μN, where μ is the coefficient of friction.

For an object not to slip, the maximum frictional force (F) must be equal to or greater than the force component pulling the object down the incline (mg sin(θ)). Therefore, we have:

F ≥ mg sin(θ)

Substituting F = μN, we get:

μN ≥ mg sin(θ)

Since N = mg cos(θ) (the normal force is equal to the component of the gravitational force perpendicular to the incline):

μmg cos(θ) ≥ mg sin(θ)

μ cos(θ) ≥ sin(θ)

Now, divide both sides of the equation by cos(θ):

μ ≥ tan(θ)

Taking the inverse tangent (arctan) of both sides, we get:

θ ≤ arctan(μ)

Therefore, the maximum angle at which an object will not slip on an incline is given by θ = arctan(μ).

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Due to light refraction, any fish in the water can see a fisherman on the bank a little more clearly than one might anticipate. When the light hits the water's surface, it “bends” down by around 13 degrees, leaving the image. Thus option A is correct.

When it reaches the surface, light emanating from the fish refracts (changes direction). When viewed from above the water, a fish appears to be closer to the surface than it actually is.

Therefore, Fred the fisherman has been told that, because of refraction, a fish in water will appear.

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The equivalent capacitance of the five capacitors in series is given 6.43 mF. After they reconnected as described the equivalent capacitance will changes to 7.71 mF.

Capacitance is the ability to store charge in a dielectric device called capacitor. The equivalent capacitance of five capacitor in series is written as: their charges will be equal.

\(\frac{1}{Ceq} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} + \frac{1}{C} + \frac{1}{C}\)

1/ 6.43 = 5/C

C = 32.15 mF.

Now the equivalent capacitance of two capacitors in parallel is

C1 =  C + C = 2C

Capacitance for three capacitors in parallel is:

C2 = C + C + C = 3C

These two are in series and can be written now as:

1/Ceq = 1/C1  + 1/C2

          = 1/2C + 1/3C

          = (2C + 3C) / (2C × 3C)

          = 5C/ 6C²

Ceq    =  6/5 C

          = 7.71 mF.

Thus, the capacitance of the reconnected circuit will be 7.71 mF.

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Answer:

C

Explanation:

Option C is correct since it is the effect of Newton’s third law.

Answer:

you need to attach a picture so I can answer it

The elastic potential energy stored in the spring is 0.375 J.

The formula for elastic potential energy is:

E = 1/2 * k * x^2

where:

* E is the elastic potential energy in Joules

* k is the spring constant in N/m

* x is the distance the spring is stretched or compressed from its equilibrium position in meters

In this problem, we have:

* k = 3 N/m

* x = 0.5 m (50 cm)

Substituting these values into the formula, we get:

E = 1/2 * 3 * 0.5^2 = 0.375 J

Therefore, the elastic potential energy stored in the spring is 0.375 J.

Least subjective evaluation tool for documenting direct observation is anecdotal record.

There are several evaluation tools that can be used to assess the quality and effectiveness of documentation in physics. Some examples include:

Peer review: This involves having other experts in the field review the documentation and provide feedback on its accuracy, clarity, and completeness.

User testing: This involves having users test the documentation and provide feedback on its usability and effectiveness in helping them understand and use the information.

Metrics: This involves measuring various aspects of the documentation, such as readability, accuracy, and completeness, and using these metrics to evaluate its quality.

Surveys: Surveys can be used to gather feedback from users on the documentation, including their satisfaction with the information provided and how well it met their needs.

Heuristic evaluation: This is an evaluation method which uses a set of predetermined heuristics or guidelines to evaluate the usability and user experience of a product or service.

Cognitive walkthrough: This is an evaluation method in which a user is observed as they use the documentation, and the evaluator looks for any issues that might make it difficult for them to understand and use the information.

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