Answers
Answer:
E = 3.6×10⁻¹⁹ J
Explanation:
Given data:
Wavelength = 550 nm (550 ×10⁻⁹ nm)
Energy of wave = ?
Solution:
Formula:
E = h c/λ
c = 3×10⁸ m/s
h = 6.63×10⁻³⁴ Js
Now we will put the values in formula.
E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm
E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm
E = 0.036×10⁻¹⁷ J
E = 3.6×10⁻¹⁹ J
Related Questions
uses of rare or inert gases
Answers
Explanation:
noble gases are useful let's take for instance helium which is used in balloons. they are used to form inert atmosphere and they are used also to deter chemical reaction.
What mass of oxygen combines with 2.88 mol
of magnesium in the reaction
2 Mg(s) + O2(g) −→ 2 MgO(s)?
Answer in units of g.
Answers
Answer:
46.08 g of O2
Explanation:
The balanced chemical equation for the reaction shows that 1 mol of O2 reacts with 2 mol of Mg to form 2 mol of MgO.
Therefore, to calculate the mass of O2 that reacts with 2.88 mol of Mg, we need to use the mole ratio between Mg and O2.
Mole ratio of Mg to O2 is 2:1, meaning that for every 2 moles of Mg, 1 mole of O2 reacts.
So, for 2.88 mol of Mg, we need 1.44 mol of O2 (2.88 mol Mg x 1 mol O2 / 2 mol Mg).
The molar mass of O2 is 32 g/mol.
Therefore, the mass of O2 needed is:
mass = number of moles x molar mass = 1.44 mol x 32 g/mol = 46.08 g.
Therefore, 46.08 g of O2 is needed to react with 2.88 mol of Mg.
Anytime an object is pushed or pulled, a CHOOSE ANSWER
is applied
Answers
ask our for help and tell our comunity
is the nucleus of these atoms positive negative or neutral
Answers
Answer: they are Positively charged
Which of the following is the set of conditions under which a material becomes a supercritical fluid?
A. real gas point
B. critical point
C. extreme point
D. triple point
(multiple choice)
Answers
Why does this equation show that matter is neither created nor destroyed (law of *
conservation) in a chemical reaction?
Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H₂O
There are the same number of atoms for each element on the reactant and product
side of the equation.
4
There are the same number of molecules on the reactant and product side of the
equation.
There are the same number of reactants as products in the equation.
This equation does not show that matter is neither created nor destroyed.
Answers
Since each element in the reactant and product has the same amount of atoms.
What elements make up atoms?Subatomic particles and electrons are the 2 types of fundamental particles that make up an atom. An atom's nucleus is encircled by an area of electrons. The electrical charge of every electron is negative one. Protons and neutrons, which together make up an atom's nucleus, are made of quarks.
Do atoms really contact or not?The Pauli exclusions principle states that two atoms cannot contact at room temperature if "trying to touch" is understood to mean that they are in the exact same place. The Pauli exclusions principle prevents the body's atoms from merging into a single location.
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2ca + o2 - 2cao identify the oxidizing and reducing agents
Answers
Answer:
Ca is a reducing agent and O is the oxidizing agent.
Explanation:
calcium is the reducing agent as it reduces oxygen while it oxidize itself and oxygen is an oxidising agent because it oxidized others and reduces itself. in this equation oxygen is reducing and Calcium is oxidising. and as it is stated in the definition that oxidizing agent is the agent which oxidises others and reduces itself and it is also stated that reducing agent reduces others and oxidize itself. so based on this statement calcium is reducing agent and O is a oxidizing agent.
the reaction of alkenes with bromine is ___ reaction which results in ____ of the organic compound.
Answers
The process that produces a bromohydrin is an addition reaction between Br and OH across an alkene. (Bromo = bromine; Hydrin = hydro; Water = H2O).
A bromohydrin is what?any of a number of organic molecules that resemble chlorohydrins but use bromine instead of chlorine.the direct, catalyst-free synthesis of vicinal bromohydrins and alkoxy bromides from olefins
How would you define hydroboration?The addition of the hydrogen-boron link to either a carbon-to-carbon or carbon-to-nitrogen double bond is known as hydroboration. It can also be carried out on a triple bond made of carbon atoms. Quite helpful in the synthesis of several organic compounds is hydroboration.
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32 g of Br2 are added to 10 g of a mixture of ethene and ethane. What is the mass percent of ethene in the mixture?
Answers
Answer:
A mixture of ethane and ethene occupies 40 litre at 1.00 atm and at 400 K.The mixture reacts completely with 130 g of O2 to produce CO2 and H2O . Assuming ...
Missing: 32 Br2
How many molecules are contained in 55.0g of co2??
Answers
Answer: 7.52*10^23 molecules.
Explanation: This is a classic Stoichiometry problem.
In one mole of any substance, there are 6.02*10^23 molecules. This number is called Avogadro's number. We are given 55 grams of Co2 so to convert that to moles, we divided by the molar mass of Co2. We find the molar mass by adding the molar masses of the elements that make up the compound.
There is one molecule of Carbon and two molecules of Oxygen in one molecule of Co2. From the periodic table, the molar mass of Carbon is 12.01 and 16.00 for Oxygen. 1(12.01)+2(16.00) gives us the molar mass. We then divided 55 grams by that mass to find the number of moles. We then multiply the number of moles by Avogadro's number (6.02*10^23) to find the total number of molecules.
You can use this method for solving any problem that asks you to find the number of atoms or molecules of some number of grams of a substance.
Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and a(n) ___________.
Answers
Answer:
Orbiter
Explanation:
Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and orbiter (the part that resembles an airplane
How many moles are in 45 g of HF
Answers
Answer:
2.25 mol
Explanation:
45 g HF x (1 mole HF/ 20.01 g)
20.01 comes from adding the molar mass of H and the molar mass of F
Inquiry Extension Consider a reaction that occurs between solid potassium and chlorine gas. If you start with an initial mass of 15.20 g K, and an initial mass of 2.830 g Cl2, calculate which reactant is limiting. Explain how to determine how much more of the limiting reactant would be needed to completely consume the excess reactant. Verify your explanation with an example
Answers
The 3.13 g of K would be needed to completely react with the remaining \(Cl_2\).
To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.
The balanced chemical equation for the reaction between solid potassium and chlorine gas is:
2 K(s) + \(Cl_2\)(g) -> 2 KCl(s)
From the equation, we can see that 2 moles of K react with 1 mole of \(Cl_2\) to form 2 moles of KCl.
First, we need to convert the masses of K and \(Cl_2\) into moles:
moles of K = 15.20 g / 39.10 g/mol = 0.388 mol
moles of \(Cl_2\) = 2.830 g / 70.90 g/mol = 0.040 mol
Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:
Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl
Theoretical yield of KCl from \(Cl_2\): 0.040 mol \(Cl_2\) x (2 mol KCl / 1 mol \(Cl_2\)) = 0.080 mol KCl
We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from \(Cl_2\) is 0.080 mol. Therefore, the limiting reactant is \(Cl_2\), since it produces less product.
To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.
We know that 1 mole of \(Cl_2\) reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining \(Cl_2\) can be calculated as follows:
moles of K needed = 0.040 mol \(Cl_2\) x (2 mol K / 1 mol \(Cl_2\))
= 0.080 mol K
This means that 0.080 moles of K would be needed to completely consume the remaining \(Cl_2\). We can convert this to a mass by multiplying by the molar mass of K:
mass of K needed = 0.080 mol K x 39.10 g/mol
= 3.13 g K
Therefore, The 3.13 g of K would be needed to completely react with the remaining.
Example verification:
Suppose we had an additional 0.50 g of \(Cl_2\) in the reaction. Would all of the K be consumed, or would there still be excess K?
Moles of additional \(Cl_2\) = mass of \(Cl_2\) / molar mass of \(Cl_2\)
Moles of additional \(Cl_2\) = 0.50 g / 70.90 g/mol
Moles of additional \(Cl_2\) = 0.0070 mol
The theoretical yield of KCl that can be formed from the additional \(Cl_2\) is:
0.0070 mol \(Cl_2\) x (2 mol KCl / 1 mol \(Cl_2\)) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl
Therefore, the total amount of KCl that can be formed from all of the \(Cl_2\) is:
5.95 g + 1.04 g = 6.99 g
The amount of K that would be needed to completely consume all of the \(Cl_2\).
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True or false; There are no H3O+ ions in a neutral solution.
Answers
A neutral solution has a pH equal to 7. We can apply the definition of pH to find the concentration of H3O+ ions. The equation that describes pH is:
\(pH=-log\lbrack H_3O^+\rbrack\)If we clear the concentration of H3O+ ions we have:
\(\lbrack H_3O^+\rbrack=10^{-pH}\)Now, we replace the pH equal to 7:
\(\lbrack H_3O^+\rbrack=10^{-7}M\)The concentration of ions H3O+ in a neutral solution is 10^-7M. so the statement is false.
Answer: False
when did cobalt-60 become common or mainstream?
(60 POINTs will give BRAINIEST FOR the amount of EFFORT you put into it)
Answers
Answer:1950s-1960s
Explanation:
Cobalt-60 is a radioactive isotope of cobalt that has a half-life of 5.27 years and decays by beta decay to nickel-60. It is commonly used in radiation therapy for cancer treatment and is also used as a source of gamma rays for industrial applications such as sterilization of medical equipment and food preservation. Cobalt-60 was first discovered in 1939 by Glenn T. Seaborg and John Livingood, and its potential for medical and industrial applications was quickly recognized. However, its widespread use did not occur until the 1950s and 1960s, when the technology for producing and handling radioactive sources became more advanced and the benefits of using cobalt-60 were more widely understood. Today, cobalt-60 remains an important tool in medical and industrial settings for its ability to deliver precise doses of radiation and its efficiency in sterilization processes.
When fossil fuels are burned, they emit carbon dioxide into the atmosphere. After centuries of large amounts of carbon dioxide accumulating in the atmosphere, the earth's temperature increases by 1°C.
What is the connection between increasing carbon dioxide and increasing temperature?
Answers
The connection between increasing carbon dioxide and increasing temperature is: carbon dioxide absorbs heat from the sun and traps it in earth's atmosphere. Since the heat cannot escape, it causes the earth's temperature to increase which is the first option.
When carbon dioxide (CO₂) and other greenhouse gases are present in the atmosphere, they act as a natural blanket, allowing sunlight (solar radiation) to pass through and reach the Earth's surface. Some of this solar radiation is absorbed by the Earth's surface, while the rest is reflected back towards space as heat (infrared radiation). However, greenhouse gases like carbon dioxide have the property of absorbing and re-emitting infrared radiation.
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plss help me with this I don't even know where to start to solve it
Answers
From the balanced equation of the reaction, the coefficients of the reactants and products are 1:2:1.
What is a balanced equation of a chemical reaction?A balanced equation of a chemical reaction is an equation which balances the atoms of each element on the reactants as well as the products side of a chemical reaction.
The balanced equation of the reaction that occurs when magnesium bromide is heated is shown below:
\(MgBr_2 \rightarrow Br_2+Mg \)
Therefore, the coefficients of the reactants and products are 1:2:1.
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When light bounces we call it?
Answers
Answer:
when light bounched we call it, reflection
HELPP! What is ammonium nitrates freezing point ?
Answers
Answer:
Freezing points for water with freezing mixtures based on salt and ice: Ammonium Nitrate - Chrushed Ice or Snow in Water 1 part Ammonium Nitrate - 0.94 parts Ice/water : temperature -4 o C 1 part Ammonium Nitrate - 1.20 parts Ice/water : temperature -14 o C
Explanation:
Consider the following half reactions and their standard reduction potential values to answer the following questions.
Cu2+ (aq) + e- Cu+ (aq)E° = 0.15 V
Br2 (l) + 2e- 2Br- (aq) E° = 1.08 V
i) State which reaction occurs at the anode and which at the cathode. [2 marks]
ii) Write the overall cell reaction. [2 marks]
iii) Calculate the value of E°cell. [2 marks]
iv) Calculate the value ΔG° [2 marks]
v) What is the value of Kc at 25°C?
Answers
Answer:
Cu2+ (aq) + e- -------->Cu+ (aq)E° = 0.15 V anode
Br2 (l) + 2e- -------------> 2Br- (aq) E° = 1.08 V cathode
Explanation:
The half equation having a more positive reduction potential indicates the reduction half equation while the half equation having the less positive reduction potential indicates the oxidation half equation.
The overall redox reaction equation is;
2Cu^+(aq) + Br2(g) ----> 2Cu^2+(aq) + 2Br^-(aq)
E°cell= E°cathode -E°anode
E°cathode= 1.08 V
E°anode= 0.15 V
E°cell= 1.08V-0.15V
E°cell= 0.93V
From;
∆G=-nFE°cell
n= 2
F=96500C
E°cell= 0.93V
∆G= -(2×96500×0.93)
∆G= - 179.49 J
From ∆G= -RTlnK
∆G= - 179.49 J
R=8.314Jmol-K-1
T= 25° +273= 298K
K= ???
lnK= ∆G/-RT
lnK=-( - 179.49/(8.314×298))
lnK= 0.0724
K= e^0.0724
Kc= 1.075
Question 3 (0.1 points)
The difference between a mixture and a solution is that mixtures cannot be easily
separated.
True
False
Answers
Answer:
true
Explanation:
I need help ASAP please .................. You have a mixture of water, alcohol, and iron. Tell me, how would you separate them from each other?
Answers
HỌ5,42
Homework Answered Due Today, 11:59 PM
.
A 5.60E1 g sample of water at 9.910E1 °C is placed in a constant pressure calorimeter. Then, 2.40E1 g of zinc metal at 2.10E1 °C is
added to the water and the temperature drops to 9.70E1 °C. What is the specific heat capacity of the zinc metal measured in this
experiment?
Answers
The specific heat capacity of the zinc metal, given that 2.40×10¹ g of zinc metal at 2.10×10¹ °C is added to the water is 0.27 J/gºC
How do i determine the specific heat capacity of the zinc?First, we shall obtain the heat absorbed by the water when the zinc metal was added. This is shown below:
Mass of water (M) = 5.60×10¹ gInitial temperature (T₁) = 9.910×10¹ °CFinal temperature (T₂) = 9.70×10¹ °CChange in temperature (ΔT) = 9.70×10¹ - 9.910×10¹ = -2.1 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?Q = MCΔT
= 5.60×10¹ × 4.184 × -2.1
= -492.0384 J
Now, we shall determine the specific heat capacity of the zinc metal. Details below:
Heat absorbed by water (Q) = -492.0384 JHeat released by metal (Q) = 492.0384 JMass of zinc metal (M) = 2.40×10¹ gInitial temperature (T₁) = 2.10×10¹ °CFinal temperature (T₂) = 9.70×10¹ °CChange in temperature (ΔT) = 9.70×10¹ - 2.10×10¹ = 76 °CSpecific heat capacity (C) = ?Q = MCΔT
492.0384 = 2.40×10¹ × C × 76
492.0384 = 1824 × C
Divide both sides by 1824
C = 492.0384 / 1824
= 0.27 J/gºC
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COLOR THEME QQ ZOOM
13. Several JASON learning ambassadors for Aldine ISD recorded a
demonstration for the students.
They mixed two chemicals together and produced a 'golden rain'. The
equation for the reaction is:
KI + Pb(NO3)2
KNO3 + Pbl₂
1
The golden substance (image below) was found to be insoluble in water.
Which of the following compounds is the precipitate?
OKI
O
CLEAR ALL
Pb(NO3)2
KNO
Pbl₂
ADD NOTE
REFE
Answers
The compound that acts as the precipitate in this reaction is Pbl₂, or lead(II) iodide.
In the given reaction equation:
KI + Pb(NO3)2 → KNO3 + Pbl₂
The precipitate formed is Pbl₂, which is lead(II) iodide. In the reaction, potassium iodide (KI) reacts with lead(II) nitrate (Pb(NO3)2) to form potassium nitrate (KNO3) and lead(II) iodide (Pbl₂).
Lead(II) iodide is insoluble in water, as mentioned in the statement. When the two chemicals are mixed, lead(II) iodide is formed as a solid precipitate, which appears as a golden substance, as described.
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It has been found by mass spectrometric analysis that in nature, the relative abundances of the various isotopic atoms of silicon are 92.23%
Si 28 , 4.67% Si 29 and 3.1% Si 30 . Calculate the atomic weight of silicon, in correct significant figures, from this information and from the
nuclidic masses. Nuclidic masses: Si 28 27.97693 amu, Si 29 28.97649 amu, Si 30 29.97377 amu. plssssss help me
Answers
Answer:
This means that the isotope of silicon with a mass number of 28 is by far the most common of these three isotopes.
Explanation:
The abundance of Si-28 is 92.23%. Si-29 is 4.68% and Si-30 is 3.09%.
Because most Si atoms have a mass of 28 amu, the average mass of all silicon atoms is very close to 28.
Here is a video which summarizes how to calculate average atomic mass from data about mass and relative abundance.
6.An acid-base indicator is usually a weak acid with a characteristic color in the protonated and deprotonated forms. Because bromocresol green is an acid, it is convenient to represent its rather complex formula as HBCG. HBCG ionizes in water according to the following equation:HBCG + H2O = BCG- + H3O+ (yellow)(blue)The Ka (the equilibrium constant for the acid) expression is: Ka=[BCG−][H3O+][HBCG]When [BCG-] = [HBCG], then Ka = [H3O+]. If you know the pH of the solution, then the [H3O+] and Ka can be determined. What would be the color of the solution if there were equal concentrations of HBCG and BCG-?Solution Color: _______________What is the pH at the first appearance of this color?Solution pH: __________What is an estimate for the Ka for bromocresol green? Show your work to get full credit
Answers
Answer:
At equal concentration of HBCG and BCG^-, the colour is green. This colour first appears at pH = 3.8
Explanation:
HBCG is an indicator that is prepared by dissolving the solid in ethanol.
Since
Ka=[BCG−][H3O+][HBCG]When [BCG-] = [HBCG], then Ka = [H3O+].
If pH = 3.8
Ka= [H3O+] = -antilog pH = -antilog (3.8)
Ka= 1.58 ×10^-4
An early arrangement of the then known elements was proposed by a British scientist John Newlands, which he called the Law of Octaves. Like other scientists at the time, Newlands arranged the elements in order of increasing atomic mass and noted that every eighth element had similar physical/chemical properties. In the modern Periodic Table, which of the following represents the last pair of elements for which Newlands' Law of Octaves would hold true?
Answers
Which term refers to the process by which land is worn away by natural forces or human activity?
Answers
Answer:
erosion
Explanation:
erosion is the term that refers to the process by which land is worn away by natural forces or human activity.
Answer:
Erosion
Explanation:
Just took the test, hope it helps!
How long does it take to prepare 4.00 g of
Al by electrolysis of Al2O3 using a current of
2.50 ampere?
Answer in units of h.
Answers
Answer:
To determine the time required, we need to use the formula:
mol Al = (I*t)/(n*F)
where I is the current inamperes, t is the time in hours,n is the number of electrons involved in the reaction (3 for AI203 -> 2AI + 302), and F is the Faraday constant (96,485 C/mol).
First, we need to calculate the amount of charge that has to pass through the circuit to produce
4.00 g of Al.
The molar mass of Al is 26.98 g/mol, so we have:
4.00 g Al * (1 mol/26.98 g) = 0.148 mol Al
To produce 0.148 mol of Al, we need 3/2 * 0.148 mol of electrons (because of the 3:2 stoichiometry of the reaction):
0.148 mol Al * (3 mol e-/2 mol AI) = 0.222 mol e-
Each electron carries a charge of 1.602 x 10^-19 C, so the total charge required to produce 4.00 g of Al is:
0.222 mol e- * 1.602 x 10^-19 C/e- = 3.55 x 10^3 C
Now we can use the formula:
Q = It
where Q is the total charge, I is the current, and t is the time. Solving for t, we get:
t = Q/l = 3.55 x 10^3 C / 2.50 A = 1.42 x 10^3 s Finally, we convert the time from seconds to hours:
t = 1.42 x 10^3 s * (1 min/60 s) * (1 hour/60 min) =
0.394 hours
So it takes approximately 0.394 hours (or 23.6 minutes) to prepare 4.00 g of Al by electrolysis of Al203 using a current of 2.50 A.
Explanation:
HOPE IT HELPS
HOPE IT HELPSPlease MARK ME AS BRAINLIEST
So we can say
27g of Al —3*96500
4g of Al —x
27*X= 3*96500*4
27x= 1,158,000
X= 42888.8 App. 42889
To find the time
Q= IT where I is 2.50 ampere and Q= 42889
I= 42889/2.5 =17155.6 App. 17156
17156 seconds to minutes will be
17156/60=285.9 minutes or 300 minutes
So that gives us 5hrs
13. Find the total number of atoms present in the following molecules. a. 5 H₂O b. Zn Cl₂
Please
Answers
Answer:
5H²O= 23
ZnCl²=135
have a great day
a. 5 H₂O
b. Zn Cl₂