Waste cooking oil is to be stored for processing by pouring it into tank A, which is connected by a manometer to tank B. The manometer is completely filled with water. Measurements indicate that the material of tank B will fail and the tank will burst if the air pressure in tank B exceeds 18 kPa. To what height h can waste oil be poured into tank A? If air is accidentally trapped in the manometer line, what will be the error in the calculation of the height?

Answer:

see and make me brainlist

Explanation:

What is oxy fuel cutting used for?

Oxy-fuel cutting is used for the cutting of mild steel. Only metals whose oxides have a lower melting point than the base metal itself can be cut with this process. Otherwise as soon as the metal oxidises it terminates the oxidation by forming a protective crust.

Answer:

The resistance of the flow of charges in an electric circuit (electrical resistance) is analogous to the frictional effect between water flow through a pipe and the pipe's surface

Explanation:

In comparison to its similarity to the diameter of the pipe affects the flow of water and acts a a factor affecting resistance so are there factors affecting electrical resistance.

in an electrical circuit:

the total length of the wire is to the length of a pipe of water

the cross-sectional area of the wire is to the diameter of a pipe of water.

Thus, the cross sectional are affects the amount of electrical resistance. Wider wires have wider cross-sectional area and vice versa. Also, water will flow (i.e. current) through a wider pipe (i.e. large diameter) at a faster rate than a narrow pipe (i.e. small diameter). This is due to the lower amount of resistance offered by the wider pipe.

in the same manner, the wider the wire, the lesser the electrical resistance to the flow of elsctric charge and vice versa for thiner wires.

The following are accurate statements about the results of the meaningful use (mu) program reports are mixed, MU turns to help process and not patient outcomes, MU program reduced ICU mortality, MU program costs 10 million US dollars.

What is meaningful use (mu) program?

Meaningful Use (MU) is a federal program that encourages health care providers to use certified Electronic Health Record (EHR) technology to improve patient care and reduce health disparities.

MU sets specific objectives and measures for providers and hospitals to qualify for incentive payments from Medicare and Medicaid. MU aims to enhance the quality, safety, and efficiency of health care through EHRs.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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The unit rate can be expressed using any unit, such as minutes per mile, miles per hour, etc.

Manav can travel one mile in around 12 minutes. Where does the unit rate come from? The unit rate can be expressed using any unit, such as minutes per mile, miles per hour, etc. If Manav runs 3 miles in 36 minutes, the unit rate in minutes per mile is as follows: Three miles are equal to 36 minutes. One mile takes 12 minutes to complete. This shows that Manav can complete a mile in less than 12 minutes. There are independent and dependent quantities (dependent quantity). When an independent quantity changes by a unit measurement, the dependent quantity increases at a rate known as the rate of dependent quantity increment per unit increment in the independent quantity.

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Answer:

Prokaryotic cell

Explanation:

GIS

The full for GIS is : Geographic Information System.

The GIS is a system of mapping that is used to create, analyze, manage and map all the types of data.

It is a method capturing, checking as well as displaying all the data that is related to the position of the surface of earth.

Remote Sensing

Remote sensing is defined as a process where the various physical characteristics of an area are constantly monitored and detected by a process of measuring the reflection of the emitted radiations at ta distance.

The snow covered areas of the Kabul basin can be monitored and analyzed by using the process of GIS and remote sensing.

They provide a continuous source of information and data about snow covered peaks, the amount of snow to the authorities.

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The power output from turbine assuming no heat loss and the velocity at exit from nozzle where Enthalphy h CpT i.e Cp specific heat = 1.005KJ/KgK.

What is meant by velocity?

The rate of flow of heat transfer to air exchanger i.e

\(w(h1+v^{2} 1/2+Z1g)+Q_{1-2} =w(h2+v2^{2} /2+Z1g)W_{1-2}\)

\(Wh_{1} +Q_{1-2} =Wh_{2}\)

\(Q_{1-2} =w(h_{1} -h_{2} )\)

\(Q_{1-2} =w_{cp} (t_{2} -t_{3} )\)

\(Q_{1-2}\) = 2xl.005(8000-150)

\(Q_{1-2}\) = 1577.8kgj/s

Velocity at exit from the nozzle, assuming no heat loss.

Given t₁ = 150°C, t₂ = 8000°c

V₁ = 30m/s, V₂ = 30m/s

t₃ = 6500°C , V₃ = 60m/s
\(W(v_{2} )^{2} /2+h_{2} )=Wh_{3} + (v3)^{2} /2+Wt\)

\((v2^{2}) -(v3^{2}) /2=(h2-h3)=Wt/w\)

\((30^{2} -60^{2} )x10^{-3} /2+(1.005)(8000-6500)=Wt/w\)

Wt = 1.506.15xw

Wt = 1506.15x2 = 3012.3kW

the enthalpy of air as h =cpt, where cp is the specific heat equal to 1. 005kJ/kg K and t is the temperature is 3012.3kW

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Answer:

Adding the length of the tape measure case.

Answer:

The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is  an idication that your vehicle may be developing a cooling system problem.

Explanation:

Answer:

1. --a 10

--b 100 in.

2. --a 4

--b 4

3. --a 2

--b 30 rpm

--c 75 ft.·lb.

4. --a Second class lever

--b 50 lbs.

Explanation:

The Actual Mechanical Advantage, AMA, is given as follows;

\(AMA = \dfrac{F_R}{F_E}\)

Where;

\(F_R\) = The resistance force magnitude

\(F_E\) = The effort force magnitude

1. a. We have;

\(F_R\) = 10 lb.

\(F_E\) = 100 lb.

\(AMA = \dfrac{100 \ lb}{10 \ lb} = 10\)

b. \(Mechanical \ advantage, \ M.A. = \dfrac{Distance \ moved \ by \ load}{Distance \ moved \ by \ effort}\)

The diameter of the axle, d = 2 in.

Let 'D' represent the diameter of the wheel, we have;

The distance moved by the axle, c = π·d

The distance moved by the load, C = π·D

\(M.A. = 10 = \dfrac{\pi \cdot D}{\pi \times 2}\)

∴ 2 × 10 = D

D = 20 in.

The required wheel diameter to overcome the resistance force, D = 100 in.

2. --a The mass of the participants, m = 200 lb.

The depth of the ground of the participants = 20 feet

The effort force = 50 lb

Actual Mechanical Advantage, AMA = 200 lb./(50 lb.) = 4

--b. The number of strands of pulley needed ≈ The mechanical advantage = 4

3. The number of gears on Gear A = 10 teeth

The number of gears on Gear B = 8 teeth

The number of gears on Gear C = 20 teeth

-a. Given that the driver gear = Gear A

The output gear = Gear C

\(The \ gear \ ratio = \dfrac{The \ number \ of \ teeth \ on \ the \ driven \ gear}{The \ number \ of \ teeth \ on \ the \ driver \ gear}\)

The driver gear = The input gear

Therefore, we have;

\(The \ gear \ ratio = \dfrac{20 \ teeth}{10 \ teeth} = 2\)

The gear ratio = 2

-b \(The \ gear \ ratio = \dfrac{The \ driver \ gear\ speed}{The \ driven \ gear\ speed}\)

Therefore, we have;

\(The \ gear \ ratio = 2 = \dfrac{60 \ rpm}{Gear\ C \, speed}\)

\(Gear\ C \, speed = \dfrac{60 \ rpm}{2} = 30 \ rpm\)

-c The output (driven) gear torque at Gear C = 150 ft.·lb.

\(The \ gear \ ratio = \dfrac{Driven \ gear \ torque}{Driver \ gear \ torque}\)

Therefore;

\(2 = \dfrac{150 \ ft \cdot lb}{Driver \ gear \ torque}\)

\(Driver \ gear \ torque = \dfrac{150 \ ft \cdot lb}{2} = 75 \ ft \cdot lb\)

The input (driver) torque at Gear A = 75 ft·lb

4. -a Given that the load is between the effort and the fulcrum, we have;

The type of lever is a second class lever

-b The distance between the load and the fulcrum = 4 feet

The distance between the effort and the fulcrum = 8 feet

We have;

100 lbs × 4 ft. = Effort × 8 ft.

∴ Effort = 100 lbs × 4 ft./(8 ft.) = 50 lbs.

The effort = 50 lbs.

The Vin(t) has an amplitude range of 0 to 5 and 0 to 2.5 for a period of 1 millisecond (ms). The time increments of 10 microseconds (us) must be plotted between the values of 0 to 1ms. Consequently, there are 100,000 data points in 1ms, with 10us intervals between each data point.

Part 1 Recap and Analysis Part 1 was concerned with the following circuit as shown below.

Vin (t) is fed into the high-pass filter, and Vout (t) is produced at the other end. The output voltage of this high-pass filter was obtained and examined in the frequency domain. To begin, the following variables were used:

RC = 1 x 10-4 s, R = 1 x 103 Ω, and C = 1 x 10-7 F.

Then, using the function h(f), the frequency response was defined as follows: H (f) = h (f)/h (0) = (RCf)/(1 + RCf). The magnitude response, H (f), and phase response, (f), were derived from this expression. Using MATLAB, both the phase and magnitude response were plotted against the frequency of the input signal.

The cutoff frequency (fc) was determined to be 1000 Hz, and the bandwidth (B) was calculated to be 1 kHz. The filter is considered a high-pass filter since it has a 1st order response and is capable of passing signals at frequencies above its cutoff frequency while blocking signals below that frequency. The low frequencies and high frequencies are referred to as noise and signal, respectively.

Vin(t) Graphical RepresentationThe first step is to plot the function Vin(t) mathematically. Vout(t) is defined by the transfer function H(f), which is derived from Vin(t).

The first step is to plot Vin(t), which is given by:

Vin(t) = 5.0sin(wt + 0) + 1.0sin(wt + 0) + 2.5sin(w3t + 0) On the MATLAB Command Window, enter the following code: t = 0:0.00001:0.001; Vin = 5*sin(8000*pi*t)+ 1*sin(29000*pi*t)+ 2.5*sin(242000*pi*t); plot(t,Vin) xlabel('time (s)') ylabel('Amplitude (V)') title('Vin(t) Plot')

Output: The resultant Vin(t) is graphed below.

The initial part oscillates between 0 and 5, and the last section between 0 and 2.5. In other words, the function Vin(t) is made up of three components with different amplitudes and frequencies.

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A project that requires using a pleater, a ruffling foot, or a gathering foot is the creation of a dress.

A pleater, a ruffling foot, and a gathering foot are all accessories for sewing machines or machines themselves that help fashion designers to give the fabric a different shape or texture, and therefore create unique pieces.

All of the tools can be used in the creation of a dress, for example, a pleater can be used in the top section of the dress to give it a nice texture and make it different from the skirt. In the same way, others such as the ruffling foot or the gathering foot can be used in the sleeves of the dress.

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Answer:

up up down down

Explanation:

left right left right b a select start

The initial value problem that models the heat transfer in an infinitely long rod with convection can be represented as follows:

∂u/∂t = k * ∂²u/∂x²

where:

u(t, x) represents the temperature distribution in the rod at time t and position x.

k is the coefficient of convection.

∂u/∂t represents the rate of change of temperature with respect to time.

∂²u/∂x² represents the second derivative of temperature with respect to position, which accounts for the spatial variation of temperature in the rod.

In addition to the partial differential equation, we also need to specify the initial condition:

u(0, x) = f(x)

where:

f(x) represents the initial temperature distribution along the rod at time t=0.

Together, the partial differential equation and the initial condition form the initial value problem that models the heat transfer in the infinitely long rod with convection.

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The amount in the account at the end of 4 years, after the deduction has been made, is £2668.

To calculate the amount in the account at the end of 4 years after the deduction, we need to consider compound interest and the deduction. Using the compound interest formula A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the annual interest rate, n is the number of compounding periods per year, and t is the number of years, we can calculate the total amount after 4 years. Then, we apply the deduction of 30% to the total interest earned. However, the specific values for the interest rate compounding frequency and the calculation of the deduction need to be provided to calculate the final amount accurately.

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Actions violated:

Actions to be taken:

Edit: Use these to write your paragraph.

The code to

were written in JavaScript and are found in the attached images

The first code declares a variable called num and gives it an initial value of 0. It then enters a while loop that lauches a message box (using window.alert) to print the message "Keep going" as long as num remains less than 5.

If nothing is done within the loop to increment num towards the value 5, the loop will go on endlessly notifying the user to "Keep going".

So, an increment of 1 was added to the loop body to increment the variable num. This makes sure the loop terminates.

Here, a function was created that receives two arguments (n1  and n2), then returns the product (n1 * n2)

This last code segment creates an array using the new keyword. The new keyword is generally used in constructing objects.

In this case the object constructed is an array having three strings;

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Answer:

Deburring Tool

Explanation:

A deburring tool is used in order to debur the PVC pipes. They are mostly used for the plastic pipes.

After the PVC pipes are cut, there are burrs on the pipe surface. To remove these burrs, a deburring tool is used. It removes the burrs form the edges of the PVC pipes that results from grinding, cutting, milling, drilling, etc.

The deburring tools are made from high speed steels.

Technician A says that a range shift is used to select high or low gear ratios within the transfer case is true while Technician B  is false.

A range shift is known to often take place when there is either high or low speed ratio of the given transfer case that is known to be selected.

Note that A range shift arrangement is known to be seen  for moving a gear reduction unit that is found between a low-range operating speed and also that of a high-range operating speed.

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Overcurrent devices with a 20A or lower rating are used to protect the conductors that are housed inside the conduit.

A material or medium that permits the flow of electricity is known as an electrical conductor. When voltage is provided, electrical charge carriers, often electrons or ions, travel effortlessly from atom to atom in a conductor.

The ease with which electric current passes through materials such as metals and nonmetallic is characterized by conductance. A capital G is used in equations to represent conductance. Siemens (S), originally referred to as mho, is the common unit of conductance.

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No, the physical address 346E0 cannot be the starting address for a segment. This is because the starting address of a segment must be aligned with the segment's size or boundary, which is determined by the processor's architecture.

Segment boundaries are defined by 16-byte or 4-byte boundaries, depending on the segment's use. Therefore, the starting address of a segment must be a multiple of 16 or 4, respectively, depending on the segment type.

In the given address 346E0, the last digit is 0, which indicates that it is a multiple of 16. However, we do not have enough information about the processor architecture and segment size to determine whether this is an appropriate starting address for a segment.

In general, when defining a segment, it is important to ensure that the starting address is properly aligned with the segment's boundary to avoid any issues with memory access and processing.

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Answer:

The molecular weight will be "28.12 g/mol".

Explanation:

The given values are:

Pressure,

P = 10 atm

  = \(10\times 101325 \ Pa\)

  = \(1013250 \ Pa\)

Temperature,

T = 298 K

Mass,

m = 11.5 Kg

Volume,

V = 1000 r

   = \(1 \ m^3\)

R = 8.3145 J/mol K

Now,

By using the ideal gas law, we get

⇒ \(PV=nRT\)

o,

⇒ \(n=\frac{PV}{RT}\)

By substituting the values, we get

       \(=\frac{1013250\times 1}{8.3145\times 298}\)

       \(=408.94 \ moles\)

As we know,

⇒ \(Moles(n)=\frac{Mass(m)}{Molecular \ weight(MW)}\)

or,

⇒        \(MW=\frac{m}{n}\)

                   \(=\frac{11.5}{408.94}\)

                   \(=0.02812 \ Kg/mol\)

                   \(=28.12 \ g/mol\)

Answer:

liquifid gas

Explanation:

when gas is introduced to a certain chemical it ends up slowly liquifying itself.

Answer:

D) All of the above.

If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will: a) increase during a climb.

A ram air input can be defined as an air intake system which is designed and developed to use the dynamic air pressure that is created due to vehicular motion, or ram pressure, in order to increase the static air pressure within the intake manifold of an internal combustion engine of an automobile.

This ultimately implies that, a ram air input allows a greater mass-flow of air through the engine of an automobile, thereby, increasing the engine's power.

In conclusion, indicated airspeed will increase during a climb when both the ram air input and drain hole of the pitot system become blocked.

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Complete Question:

If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will

a) increase during a climb

b) decrease during a climb

c) remain constant regardless of altitude change

Answer: answer is B

Explanation:

Answer: metamorphic rock

Explanation:

Answer:

The answer will be B i hope this helps