Water at the top of Horseshoe Falls (part of Niagara Falls) is moving horizontally at 9.2 m/s as it goes off the edge and plunges 53 m to the pool below.
Part A
If you ignore air resistance, at what angle with respect to the vertical is the falling water moving as it enters the pool?

Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.

ANSWER

12.12 cm

EXPLANATION

Given:

• The mirror is convex

• The object distance, u = -15.31 cm

• The focal length, f = +58.25 cm

Find:

• The image distance, v

Using the mirror equation,

And solving for v we have,

Hence, the image will appear 12.12 cm behind the mirror.

Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

Answer:

57 mm

Explanation:

57 mm is equivalent to 5.7 cm

The spaceship undergoes an instantaneous change in velocity at point A and then undergoes a continuous change in velocity at point B until it reaches point C. The trajectory of the spaceship is therefore curved and can be represented by one of the given options.

What is Instantaneous Velocity?

Instantaneous velocity is the velocity of an object at a specific moment in time or at a specific point in its motion. It is the limit of the average velocity as the time interval over which it is calculated approaches zero. In other words, it is the slope of the tangent to the position-time graph at a particular point.

To calculate the instantaneous velocity of an object, you need to determine the object's position at a specific moment in time and then take the derivative of the position function with respect to time. The resulting derivative gives you the object's instantaneous velocity at that specific moment in time.

Instantaneous velocity is important in physics and many other fields because it allows us to understand the behavior of objects in motion and to calculate important quantities such as acceleration, momentum, and energy.

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Answer:

A car traveling south with its cruise control set

Explanation:

Turning could cause anything to slow down but going forward could mean that anything could go faster.

The bullet stops moving on hitting on a surface. Hence, the impulse here is equal to the momentum. Therefore, the mass of the bullet is 0.1 Kg.

Impulse in physics is the change in momentum. It is the product of the force and change in time.

hence, impulse = f. dt

When the bullet is travelling with  a velocity of 500 m/s it has a momentum. When it brought to rest, momentum become zero. Thus, the momentum is equal to the impulse here.

Therefore, f.dt = m. v

f.dt = 50 N s

v = 500 m/s

m = 50 N s/500 m/s = 0.1 Kg

Therefore, the mass of the bullet is 0.1 Kg.

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(1) The acceleration of the car is determined as 17.42 m/s².

(2) The acceleration of the crate is determined as 8.89 m/s².

The acceleration of the car is calculated from the net force acting on the car.

∑F = ma

F - Ff = ma

F - μW = ma

where;

m = W/g

m = (9320)/(9.8)

m = 951.02 kg

2(9320) - 0.222(9320) = 951.02a

16,570.96 = 951.02a

a = 17.42 m/s²

F - μW = ma

F - μmg = ma

302 - 0.75(18.6 x 9.8) = 18.6a

165.29 = 18.6a

a = 8.89 m/s²

Thus, the acceleration of the car is determined as 17.42 m/s².

The acceleration of the crate is determined as 8.89 m/s².

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The wheel rotates at a rate of about 1.047 radians per second.

Any straight line segment that cuts through the center of a circle and has ends that are on the circle is considered a circle's diameter in geometry. The longest chord of the circle is another name for it. Either of the two approaches can be used to determine the diameter of a sphere. The diameter is the distance along the circle's circumference that separates two locations on its edge.

The diameter or length of the a circle is its circumference. A straight line connecting a point on one side of the circular to a point at the other end, that passes through the center is the diameter. A circle's diameter is multiplied by to determine its circumference π (pi). You can also determine the circumference by multiplying 2radius by pi (π=3.14).

You may determine the wheel's rotational velocity using this information. To do this, you must first determine the wheel's circumference, which is determined by multiplying the diameter by π :

C = π * d = π * 70.0 cm = 219.11 cm

The circumference is then divided by the number of times the stone passes in a second:

v = C / (3 revolutions/second) = 219.11 cm / (3 revolutions/second) = 73.04 cm/second

This is a location on the wheel's circumference's linear velocity. Divide it by the wheel's radius to get the rotational velocity:

ω = v / r = 73.04 cm/second / (70.0 cm / 2) = 1.047 radians/second

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The wheel rotates at a rate of about 1.047 radians per second.

Any straight line segment that cuts through the center of a circle and has ends that are on the circle is considered a circle's diameter in geometry. The longest chord of the circle is another name for it. Either of the two approaches can be used to determine the diameter of a sphere. The diameter is the distance along the circle's circumference that separates two locations on its edge.

The diameter or length of the a circle is its circumference. A straight line connecting a point on one side of the circular to a point at the other end, that passes through the center is the diameter. A circle's diameter is multiplied by to determine its circumference π (pi). You can also determine the circumference by multiplying 2radius by pi (π=3.14).

You may determine the wheel's rotational velocity using this information. To do this, you must first determine the wheel's circumference, which is determined by multiplying the diameter by π :

C = π * d = π * 70.0 cm = 219.11 cm

The circumference is then divided by the number of times the stone passes in a second:

v = C / (3 revolutions/second) = 219.11 cm / (3 revolutions/second) = 73.04 cm/second

This is a location on the wheel's circumference's linear velocity. Divide it by the wheel's radius to get the rotational velocity:

ω = v / r = 73.04 cm/s / (70.0 cm / 2) = 1.047 r/s

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Complete question:

As a result, from the homes of the shoppers to the restaurant, the distance is 12 km, and the direction is 80° north.

As the name implies, questions based on direction and/or distance are also known as Direction and Distance questions. Candidates must calculate the distance traveled between the starting location and the final / end point based on the provided starting point and direction. The position of one point and person with regard to another point and person and the distance among them must be determined for the Direction & Distance reasoning part.

Declare the terms "right" and "left." Ask the kids to tell you what these terms imply or mean when they are translated, then write their answers on the board with arrows pointing in the appropriate directions. Show the class how to pronounce the words once their meanings are obvious. Relative terminology, such as up, down, in, out, left, right, forward, backward, or sideways, can be used to define direction. You can also depict direction using the four cardinal directions: north, south, east, & west.

7km = 30 Degree of NE

5km = 50 degree of N

Therefore distance = 7km+5km

=12km

thus, direction = 50+30

=80° N

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(a)The rifle exerts a force of 628 N on the bullet while it is in the barrel.

(b) (i)  There is no friction between the bullet and the barrel, there is no force of friction to consider.

    (ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.

(c) The rifle gives the bullet an acceleration of about 24885 g's.

(d) the bullet is in the barrel for 0.030 s.

What is Force?

Force is a physical quantity that describes the interaction between two objects, causing a change in motion. Specifically, it is an influence that can cause an object to accelerate, change direction, or deform. Force is defined as the product of mass and acceleration, according to Newton's second law of motion. Mathematically, force can be represented by the equation:

                              F = m*a

(a) To determine the force that the rifle exerts on the bullet while it is in the barrel, we need to use the equation for the work done by a constant force:

                                   W = Fd

where W is the work done, F is the force, and d is the distance over which the force is applied. We can rearrange this equation to solve for the force:

F = W/d

We know that the work done on the bullet is equal to the change in kinetic energy:

W = ΔK = (1/2)mv^2

where m is the mass of the bullet and v is its velocity. Plugging in the given values, we get:

W = (1/2)(0.00420 kg)(370 m/s)^2 = 283 J

The distance over which the force is applied is given as 45.0 cm = 0.45 m. So the force exerted by the rifle on the bullet is:

F = W/d = 283 J / 0.45 m = 628 N

Therefore, the rifle exerts a force of 628 N on the bullet while it is in the barrel.

(b) (i) The free-body diagram of the bullet while it is in the barrel would show two forces acting on it: the force of the rifle pushing it forward, and the force of gravity pulling it downward. Since there is no friction between the bullet and the barrel, there is no force of friction to consider.

(ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.

(c) We can calculate the acceleration of the bullet using the formula:

a = Δv/t

where Δv is the change in velocity and t is the time for which the acceleration occurs. We know that the initial velocity of the bullet is 370 m/s and that it starts from rest, so the change in velocity is:

Δv = 370 m/s

The distance over which the acceleration occurs is given as 45.0 cm = 0.45 m. Using the formula for distance traveled with constant acceleration, we can find the time for which the acceleration occurs:

d = (1/2)at^2

0.45 m = (1/2)a(t^2)

Solving for t, we get:

t = sqrt(0.9/a)

Plugging this into the equation for acceleration, we get:

a = Δv/t = 370 m/s / sqrt(0.9/a)

Solving for a, we get:

a = 2.44 x 10^5 m/s^2

To express this acceleration in units of g's, we can divide by the acceleration due to gravity:

a/g = 2.44 x 10^5 m/s^2 / 9.81 m/s^2 = 24885

Therefore, the rifle gives the bullet an acceleration of about 24885 g's.

(d) Using the same formula as before for distance traveled with constant acceleration, we can solve for the time the bullet is in the barrel:

d = (1/2)at^2

0.45 m = (1/2)(2.44 x 10^5 m/s^2)t^2

Solving for t, we get:

t = \(\sqrt{(0.00092)}\)s = 0.030 s

Therefore, the bullet is in the barrel for 0.030 s.

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The bullet is in the barrel for 7.05 x 10^-5 seconds. Acceleration can also be caused by changes in direction, such as when an object moves in a circular path.

What is Acceleration?

Acceleration is a fundamental concept in physics and plays an important role in understanding the motion of objects. It is used to describe the behavior of objects in a wide range of applications, from simple everyday situations such as cars accelerating and braking, to more complex phenomena such as the acceleration of particles in particle accelerators or the acceleration of celestial bodies in space.

(a) To find the force exerted by the rifle on the bullet, we can use the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (muzzle velocity), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled (45.0 cm = 0.45 m).

Rearranging this equation to solve for acceleration:

a = (v^2 - u^2) / 2s

Plugging in the given values:

a = (1200 m/s)^2 / (2 x 0.45 m) = 3.20 x 10^6 m/s^2

The force exerted by the rifle on the bullet can be found using Newton's second law:

F = ma

where F is the force, m is the mass of the bullet (4.20 g = 0.00420 kg), and a is the acceleration we just calculated:

F = 0.00420 kg x 3.20 x 10^6 m/s^2 = 13,440 N

Therefore, the rifle exerts a force of 13,440 N on the bullet while it is in the barrel.

(b)

(i) Free-body diagram of the bullet while it is in the barrel:

The only force acting on the bullet while it is in the barrel is the force exerted by the rifle, which is directed to the right.

  |

  |

-->|  F

  |

  |

Once the bullet has left the barrel, it is subject to air resistance, which we will assume acts in the opposite direction to the velocity of the bullet. The force of gravity on the bullet is negligible for this problem.

  |

  |

<--|  F_air

  |

  |

(c) The acceleration given to the bullet can be expressed in terms of g's by dividing by the acceleration due to gravity, g:

a_g = a / g = (3.20 x 10^6 m/s^2) / 9.81 m/s^2 = 326,000 g's

Therefore, the rifle gives the bullet an acceleration of 326,000 g's.

(d) The time the bullet is in the barrel can be found using the kinematic equation:

s = ut + (1/2)at^2

where s is the distance traveled (0.45 m), u is the initial velocity (0 m/s), a is the acceleration we calculated earlier (3.20 x 10^6 m/s^2), and t is the time the bullet is in the barrel (which we want to find).

Rearranging and solving for t:

t = sqrt(2s/a) = sqrt(2 x 0.45 m / 3.20 x 10^6 m/s^2) = 7.05 x 10^-5 s

Therefore, the bullet is in the barrel for 7.05 x 10^-5 seconds.

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The critical angle for glass materials with a refractive index 1.60 is 38.7°.

The critical angle in optics is the incidence angle at which the refraction angle is 90 degrees.

It is possible to calculate the link between the critical angle and the refractive index since the critical angle is inversely proportional to the refractive index.

Refractive index = 1/sin C

where C is the critical angle

Hence, C = sin⁻¹(1/refractive index)

For the glass material, C =  sin⁻¹(1/1.60)

C = 38.7°

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Answer: the answer is 6kg.

Explanation:

Mass= force divided by acceleration, which would be 12 divided by 2.

Given:

The speed of the wave is,

The distance between adjacent crests is,

To find:

a) What is the frequency of the waves?

b) What is the period of the waves?

Explanation:

a) The horizontal distance between two adjacent crests or troughs is known as the wavelength.

The wavelength is,

The frequency is,

Hence, the frequency is 1.71 Hz.

b)

The period of waves is,

Hence, the period of waves is 0.58 s.

Answer: C

Explanation: i have played sports in my life now i am no physics person but in order to follow the rules you have  to be a team player. and a part of being a team player is being positive and so b=a*d  

Answer:u

Laa             c

Explanation:

The normal force on the car when it is at the bottom of the track is 8.84 N.

At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:

N = mg + mv²/r

where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.

Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:

N = mg

Substituting the given values, we get:

6.00 N = (0.610 kg)(9.81 m/s²)

Solving for g, we get:

g = 9.68 m/s²

At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:

N = mg - mv²/r

Substituting the known values, we get:

N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)

Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:

mg(2r) = (1/2)mv²

where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:

v = sqrt(2gr)

Substituting the known values, we get:

v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s

Substituting this value of v into the equation for N, we get:

N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N

Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.

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Answer:

a = 2 m/s²

Explanation:

A

Explanation: sorry sir but its required step up transformer for high voltage not step

Answer:

Southward

Explanation:

I'm going to assume that if it moves in a straight line, it has to either move in one of two directions. In this case, either northward or southward.

If any object moves in a straight line in the direction of the north, then the only other direction it can move is the south direction.

Given that linear motion, often referred to as rectilinear motion, includes movement in one dimension along a straight line, it is possible to mathematically characterize it using only that one spatial dimension.

There are two different types of linear motion: non-uniform linear motion with variable velocity or non-zero acceleration. Uniform linear motion has a constant velocity or zero acceleration. A particle's (a point-like object's) motion down a line can be explained by its position, x, which changes with time (t) (time). An athlete running 100 meters down a straight track is an illustration of linear motion.

If anything is moving in a linear motion in forward direction, then the only other direction it can move is backward but in the same opposite side.

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The observations of a chemical change is change in colour and formation of bubbles . There can also be a formation of precipitation, change in temperature also odour change

Answer:

B) The formation of a precipitate

Explanation:

Answer:

A. New space missions show that Pluto is much larger than originally thought.

Explanation:

The new definition of a planet that was adopted in 2006, defined planet as  an object that orbits the sun, with sufficient mass to be round, not a satellite of another object, and has removed debris and small objects from the area around its orbit.

This new definition of a planet that was adopted in 2006, classified Pluto as "dwarf planet", because Pluto meets planetary criteria except that it has not cleared debris from its orbital neighborhood.

However, new Horizons spacecraft flew by Pluto in 2015, revealed that Pluto is much larger than originally thought

Therefore, the correct option is "A"

A. New space missions show that Pluto is much larger than originally thought.

Answer: it means that we now technically have over 100 planets

Explanation:

it’s not New space missions show that Pluto is much larger than originally thought!!!

Without acceleration, the distance is 32 m, and with acceleration, the distance is 24 m shorter.

The direction of the motion is shifting, therefore an object moving at a constant speed in a circular path is still moving forward.

Newton's Second Law of Motion states that when a force is applied to a material, the mass accelerated (gains speed) (object). Riding a bicycle is a great example of how this movement law is put to use. The bulk is made up by your bicycle. Your leg muscles produce the force as they push against with the bicycle's pedals.

Initial speed v = 8 m/s

acceleration a = -1 m/s²

t = 4 sec.

distance d = v * t

= 8 m/s * 4 sec.

d = 32 m

distance with acceleration,

d' = vt + 1/2 at²

d' = 8 m/s * 4s + 1/2 * (-1 m/s²) (4s)

d' = 24 m

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The total equivalent resistance of the circuit which consists of 4 resistors ( 1202, 180, 320 and 3802 ) connected in series is 50.1 KΩ

Resistance of resistor,

Total equivalent resistance, R = R1 + R2 + R3 + R4

R = 12000 + 18 + 32 + 38000

R = 50.1 KΩ

Equivalent resistance is a another way of indicating total resistance. The equivalent resistance will be of a single resistor that replaces the total network without altering any effect on the system.

Therefore, the total equivalent resistance of a series circuit consists of 4 resistors connected in series: 1202, 180, 320, and a 3802 is 50.1 KΩ

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Answer:

C. 6.2 m/s

Explanation:

The magnitude of the distances are

East direction
| d1 | = 80 m

West direction

| d2 | =75m

Total magnitude of distance = 80 + 75 = 155

Total time taken = 5 + 20 = 25 s

Magnitude of speed = 155/25 = 6.2 m/s

Answer:

.5

Explanation:

First we define the variables

v=20

r=80

Next we construct our formula, since our tires do not slip, our centripetal force is equal to our friction

ma=mg*u

We calculate our centripetal force through finding our acceleration (v^2/r) and assuming our mass is a variable m (we cancel it out later).

mv^2/r = mg*u

All we have left is substitution and simplification

400m/80=mg*u

5=g*u

G is our gravitational acceleration (I will use 10, use 9.8 instead if you prefer)

5=10*u

u=.5

Answer:  

a) 1m

b) 2μs

c) 3mm

Explanation:

Answer:

187.5

Explanation:

Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

Answer:

\(W_{T} = - 24 kJ \)

Explanation:

The work (W) done by the gas can be calculated using the following equation:

\( W = p*\Delta V = p*(V_{f} - V_{i}) \)

Where:

p: is the pressure

[tex}V_{f}\): is the final volume

[tex}V_{i}\): is the initial volume

In the first process, the work done by the gas is:

\( W_{1} = p*\Delta V = p*0 = 0 \)

Since the volume remains constant, the total work done by the gas is equal to zero.

In the second process, the work done by the gas is:

\( W_{2} = p*(V_{f} - V_{i}) = 6.00 \cdot 10^{5} Pa*(0.130 m^{3} - 0.170 m^{3}) = -24 kJ \)

Now, the total work done by the gas during both processes is:

\( W_{T} = W_{1} + W_{2} = 0 + (-24 kJ) = - 24 kJ \)

Therefore, the total work done by the gas during both processes is - 24 kJ.

I hope it helps you!

The total work done by the gas during both processes is 0 Joules and  -2.4 × 10⁴ Joules respectively.

The work done on a system at constant pressure (P) can be expressed by using the relation:

W = ρdV

here:

∴

W = ρ(0)

W = 0 Joules

In the second process;

Using the same relation;

W = ρdV

where

∴

W = 6.00 × 10⁵ (-0.04) Joules

W = -24000 Joules

W = -2.4 × 10⁴ Joule

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