Answer:
i. Magnetic fields
ii. All 4 planets in appearance have deeper atmospheres and darker cloud.
iii. All the 4 Jovian planets rotates very quickly, with a range of 10 to 17 hours.
Explanation:
The Jovian planets is different from terrestrial planets in so many ways. The Jovian planets includes Jupiter , Saturn, Uranus and Neptune.
The major similarities shared by all of these 4 planets includes
i. Magnetic fields: Each of this Jovian planets have a strong magnetic field and are generated by electric currents in its rapidly sniping interior. The magnetosphere which is the region at which the planet magnetic field dominates is far more stronger in Jupiter than other Jovian planets . Although the magnetic field of Saturn , Neptune and Uranus works in similar way to Jupiter but are less stronger.
ii. All 4 planets in appearance have deeper atmospheres and darker cloud. The uppermost clouds of Jupiter and Saturn has more of ammonia crystals .The upper cloud of Neptune is composed of methane, The cloud of Uranus is deep.
iii. All the 4 Jovian planets rotates very quickly, with a range of 10 to 17 hours. The rotation period of Jupiter is the shortest among the Jovian planets which is around 9 hours 55 minutes. The rotation period of Neptune and Uranus take longer time than the other 2 Jovian planets( a little above 17 hours).
Condition when an organ is impaired sickness
Answer:
As traditionally used, impairment refers to a problem with a structure or organ of the body; disability is a functional limitation with regard to a particular activity; and handicap refers to a disadvantage in filling a role in life relative to a peer group.
Explanation:
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The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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A rather unbalanced goat jumps off a the air. Evan is dressed in his parachuting outfit, 2.0-m high. How much gravitational potential cliff. The goat has a mass of 50kg and the which brings his mass to a total of 90.0 kg. The energy does the girl gain? cliff is 450 m high. What is the kinetic aircraft takes the group to a height of 5000.00 m m= 36 kg before the jump. How much GPE does Evan gain Given: h: 2.0m Asked 5P6 energy of the goat just before it hits the ground?
There are multiple questions in your prompt, so let's break them down one by one.
How much gravitational potential energy does the goat gain?
The gravitational potential energy gained by the goat can be calculated using the formula:
GPE = mgh
where m is the mass of the goat, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.
Substituting the given values, we get:
GPE = 50 kg x 9.8 m/s^2 x 450 m
GPE = 220500 J
Therefore, the goat gains 220500 J of gravitational potential energy.
How much gravitational potential energy does Evan gain?
The gravitational potential energy gained by Evan can be calculated using the same formula as above:
GPE = mgh
where m is the mass of Evan (including his parachute gear), g is the acceleration due to gravity, and h is the height of the jump.
Substituting the given values, we get:
GPE = 90 kg x 9.8 m/s^2 x 2.0 m
GPE = 1764 J
Therefore, Evan gains 1764 J of gravitational potential energy.
How much kinetic energy does the goat have just before it hits the ground?
The conservation of energy principle tells us that the total energy of the system (in this case, the goat) remains constant. So, the kinetic energy gained by the goat just before it hits the ground is equal to the gravitational potential energy it had at the top of the cliff. Therefore, the kinetic energy of the goat just before it hits the ground is:
KE = GPE = 220500 J
Note that we have assumed that there is no loss of energy due to air resistance or other factors during the goat's fall.
How much GPE does Evan gain given: h = 2.0 m
We have already calculated the gravitational potential energy gained by Evan earlier. Using the same formula, we get:
GPE = mgh
GPE = 90 kg x 9.8 m/s^2 x 2.0 m
GPE = 1764 J
What is the kinetic energy of the aircraft at a height of 5000.00 m?
We cannot calculate the kinetic energy of the aircraft with the given information. The kinetic energy of an object depends on its mass and velocity, but we only have information about its height. If we assume that the aircraft is stationary at a height of 5000.00 m, then its kinetic energy would be zero.
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In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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1. Explain how sublimation works.
2. Explain how evaporation works.
3. Explain how the melting point works.
1.) In sublimation, solid changes to gas
2.) In evaporation, liquid changes to gas
3.) In melting point, solid changes to liquid.
What is phase change of matter?Phase change of matter is the ability of the various forms of matter, such as solid, liquid and gas, to change from one form to another without the destruction of the substance.
There are various ways a substance can change between these three forms and they include the following:
Sublimation: This is the phase change of matter that involves the direct change of a solid substance into a gaseous state.Evaporation: This is the phase change of matter that involves the direct change is liquid substance into gaseous state.Melting point: This is the phase change that occurs at a particular point when the solid substance dissolves to form liquid.Learn more about matter here:
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A small 1240-kg SUV has a wheelbase of 3.2 m. If 67% of its weight rests on the front wheels, how far behind the front wheels is the wagon's center of mass
Answer:
Explanation:
Let d be the distance to the center of mass from the front wheels
Sum moments about the front wheel contact point to zero
1240(9.8)[d] - 1240(9.8)(1 - 0.67)[3.2] = 0
1240(9.8)[d] = 1240(9.8)(1 - 0.67)[3.2]
d = (1 - 0.67)[3.2]
d = 1.056 m
a 50 kg boy runs at 3 m/s. how much momentum does he have
Answer:
150 kg-m/s
Explanation:
momentum = m * v
50 * 3 = 150
What is the relationship between kinetic energy and speed
Answer:
Here
Explanation:
the kinetic energy of an object is directly proportional to the square of its speed. That means that for a twofold increase in speed, the kinetic energy will increase by a factor of four. For a threefold increase in speed, the kinetic energy will increase by a factor of nine
Answer:
. It turns out that an object’s kinetic energy increases as the square of its speed. A car moving 40 mph has four times as much kinetic energy as one moving 20 mph, while at 60 mph a car carries nine times as much kinetic energy as at 20 mph. Thus a modest increase in speed can cause a large increase in kinetic energy.
the model used in studying submarines in different parts of the ocean uses a scale of 1:500. if a submarine is 1,000 m below the surface of the ocean, how far below sea level is the submarine in the model?
Answer: B 2m
Explanation:
A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion
Based on Newton's first and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
What is Newton's first law of motion?
Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.
Newton's first law of motion is also called law of inertia because it depends on mass of the object.
An object with a greater mass will require greater force to be stopped or get moving.
Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.
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Two very large parallel metal plates, separated by 0.20 m, have a potential difference of 12V. An electron is released from rest at a location a distance d from the negative plate.
(a) Describe the motion of the electron after its release in as much detail as possible.
(b) At what distance from the positive plate, will the electron have a speed of 1 x 10^6 m/s?
Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.
(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.
(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?
For part (a):
The magnitude of an electric field can be given as \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.
So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)
An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.
For part (b):
We know that...
- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).
- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).
- \(\vec F_e=q\vec E\)
- \(\vec F =m\vec a\)
\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)
\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)
Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)
\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)
\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)
The distance from the positive plate we'll call, "D."
\(D=0.20+\Delta \vec x\)
\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)
Two long parallel straight wires carry equal currents inopposite directions. At a point midway between the wires, themagnetic field they produce is:
O zero
O non-zero and along a line connecting the wires
O non-zero and parallel to the wires
O non-zero and perpendicular to the plane of the two wires
O none of the above
The right answer is D, which is non-zero and parallel to the plane of the two wires. When an electric current flows through a solenoid, a magnetic field is produced.
Using the right-hand rule, the magnetic field at the halfway point is inside the paper because of the wire on the left and inside because of the wire on the right. At x=a parallel to the y-axis with z=0, two parallel wires carrying equal currents in opposite directions are set up. When an electric current flows through a solenoid, a magnetic field is produced. Your thumb will be pointing in the general direction of the conventional current when your right hand is wrapped around the solenoid. Your fingers will be pointing in the general direction of the magnetic north pole. By using the right hand rule, it is possible to determine the direction of the cross product as follows: The index finger is pointing in the velocity vector v's direction. The middle finger is used to indicate the magnetic field vector B's direction.
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A student has two balloons attached to strings and rubs each balloon on one of two different materials. The student wants to know whether or not the balloons have the same sign charge. Which of the following procedures will provide enough information while ensuring the net charge on the balloons is not affected? Select two answers. А. Touching the balloons to each other and observing whether they stick together B. Suspending the balloons near each other and observing which way they deflect C. Suspending each balloon near the material it was not rubbed on and seeing which way it deflects D. Touching each balloon to the material it was not rubbed on and observing whether they stick together
Suspending the balloons near each other and observing which way they deflect
Suspending each balloon near the material it was not rubbed on and seeing which way it deflects
Can an object be charged by friction?An object can be charged by friction. When two objects are rubbed against each other, electrons can be transferred from one object to the other, resulting in one object becoming positively charged and the other becoming negatively charged. This is known as the triboelectric effect.
We know that if the objects do have the same charge then they will deflect away from each other but towards each other if they have opposite charges.
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where is the mask of the vehicle that has 50,000 N and 25 m/s/s
The vehicle has a 2000kg mass.
briefly? Is the formula for F MA in Newtons?Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.
F= ma
m= F/a
m= 50000/25
m= 2000 kg
What is an easy way to define Newton's second law?According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.
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Consider the arrangement of two fixed point charges, equal in magnitude, shown in the figure. Which of the following statements arc correct for the initial motion of a third charge if it is released from rest in the vicinity of the two charges shown? A positive charge at point d will accelerate up. A positive charge at point b will accelerate up. A negative charge at point c will accelerate up. A positive charge at point a will accelerate toward the lower-left. A negative charge at point c will accelerate toward the lower-right.
The option (B and C) are true others are false.
What is acceleration ?
Acceleration is the rate at which velocity changes, as well as how quickly velocity changes over time. instantaneous acceleration is an acceleration at a single moment instantaneous acceleration divided by time deceleration
What is motion ?
The movement of atomic or molecular building blocks in a certain direction is referred to as molecular motion. Temperature and heat both have an impact on molecular mobility. This is so because the measurement of temperature, which reflects molecular motion and average kinetic energy, is used to determine molecular motion.
A is false; a positive charge at point d will be attracted to the nearby negative more than it is repelled by the more distance positive.
B is true
C is true
D is false; the dipole field at point a is directed up (it curves from the lower positive charge to the upper negative one, but is directly upward here) so the charge will initially accelerate up
E is false; similar to question D, the field is up at point c so the negative charge will accelerate initially straight down.
Therefore, the option (B and C) are true others are false.
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The temperature of a cup of coffee varies according to Newton's Law of Cooling: dT dt equals negative k times the quantity T minus A, where T is the temperature of the coffee, A is the room temperature, and k is a positive constant. If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C, find the temperature, to the nearest degree Celsius of the coffee after 4 minutes.
74
67
60
42
Answer:
Explanation:
Writing out the Newton's Law pf Cooling:
dT/dt = -k * (T - A),
where T is the temperature of the coffee, A is the room temperature, and k is a positive constant.
If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C,
T = 100
A = 25
dT = 100 - 90 = 10
dt = 1
Putting the figures into the equation:
10/1 = -k * (100 - 25)
k = -10/75°C
After 4 minutes, dT/4 = 10/75 (100 - 25) = 10
dT = 40
Temperature after 4 minutes = 100 - 40 = 60°C
The temperature of a cup of coffee varies according to Newton's Law of Cooling, the temperature of the coffee after 4 minutes is approximately 67°C.
To tackle this problem, we can apply Newton's Law of Cooling's differential equation and solve it using variable separation.
dT/dt = -k(T - A)
At t = 0 (initial condition): T = 100°C
At t = 1 minute: T = 90°C
dT/dt = -k(T - A)
At t = 0: dT/dt = -k(100 - 25)
So,
-10 = -k(75)
k = 10/75
Separating variables and integrating, we have:
1/(T - A) dT = -k dt
∫(1/(T - A)) dT = ∫(-k) dt
ln|T - A| = -kt + C
ln|100 - 25| = 0 + C
ln|75| = C
So, the equation will be:
ln|T - A| = -kt + ln|75|
ln|(T - 25)/(75)| = -kt
Now,
ln|((T - 25)/(75))| = -(10/75)(4)
|((T - 25)/(75))| = \(e^{(-40/75)\)
T - 25 = ± 75 * \(e^{(-40/75)\)
T = 25 ± 75 * \(e^{(-40/75)\)
T ≈ 25 ± 42.42
Therefore, the temperature of the coffee after 4 minutes is approximately:
T ≈ 25 + 42.42 = 67.42°C
Thus, the temperature of the coffee after 4 minutes is approximately 67°C.
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The diagram below shows snapshots of an oscillator at different times . What is the frequency of the oscillation ?
In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.
How to calculate the periodThe period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,
Period of oscillation = 1.80s.
From here, finding the frequency is simple as, Frequency = 1/Period. Hence,
Frequency = 1/1.80
= 0.555 Hz (3 sf).
The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.
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Suppose the water at the top of Niagara Falls has a horizontal speed of 2.73 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 52.9 ° angle below the horizontal?
Answer:
required vertical distance below the edge is 0.6648 m
Explanation:
Given the data in the question;
Horizontal speed of water falls v = 2.73 m/s
direction of water falls 52.9° below the horizontal
The vertical velocity must be such that;
tanθ = v\(_y\) / v\(_x\)
Now, vertical speed of water falls;
v\(_y\) = v\(_x\) × tanθ
we substitute
v\(_y\) = 2.73 × tan(52.9°)
v\(_y\) = 2.73 × 1.322237
v\(_y\) = 3.6097
Now, at the top of falls, initial speed u = 0
v² - u² = 2as
s = ( v² - u² ) / 2as
we substitute
s = ( 0² - (3.6097)² ) / (2 × 9.8)
s = 13.029934 / 19.6
s = 0.6648 m
Therefore, required vertical distance below the edge is 0.6648 m
can someone help with the vocabulary of the relative age of rocks
what is a shargaff rule
According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.
Who is Chargaff ?Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.
Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.
He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.
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What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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You are stranded in a desert and think you see a puddle of water in the sand, why?A)Light reflected off the sand confuses your eyesB)The air close to the sand is hot and causes light to bendC)The light is refracting into the sandD)Small amounts of water in the sand shimmer in light
People tend to see a puddle of water in the sand because of the refraction of the light. The surface of the sand is hotter, which causes the light rays to refract and aim the pupils of the person.
Therefore, the correct answer is B.Estimate the moment of inertia of a bicycle wheel 68 cm in diameter. The rim and tire have a combined mass of 1.2kg . The mass of the hub can be ignored.
The moment of inertia of a 68 cm diameter bicycle wheel is 1387.2 kg.m². The rim and tire weigh 1.2kg together. The hub's mass is unimportant.
The moment of inertia of a hoop about an axis passing through its center is, I=mR²
I=mR²
I=m(D/2)²
I=mD²/4
I=(1.2kg)(68 cm(10⁻² m/1cm))²/4
I=1387.2 kg.m²
A body's resistance to having the speed of its rotation along an axis changed by the application of torque is quantified by the term "moment of inertia" in physics (turning force). The axis could be fixed or not fixed, internal or exterior. Nevertheless, the moment of inertia (I), which is always described in relation to that axis, is calculated as the total of the products produced by multiplying the mass of each particle of matter in a particular body by the square of that particle's distance from the axis. The moment of inertia can be compared to mass in linear motion when calculating the angular momentum of a rigid body.
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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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What will the answers for a ,b and c be
Answer:
A. 1.6 Hz
B. 1000 m/s²
C. 50000 N
Explanation:
A. Determination of the frequency.
Period (T) = 0.625 s
Frequency (f) =?
f = 1/T
f = 1/0.625
f = 1.6 Hz
B. Determination of the acceleration.
Radius (r) = 10 m
Velocity (v) = 100 m/s
Acceleration (a) =?
a = v²/r
a = 100² / 10
a = 10000 / 10
a = 1000 m/s²
C. Determination of the net force.
Mass (m) = 50 Kg
Acceleration (a) = 1000 m/s²
Net force (F) =?
F = ma
F = 50 × 1000
F = 50000 N
Using what you already know about newton’s law’s explain how the force applied to the ball by the pitcher and the force applied to the ball by the bat will impact yours ability ti hit a home run
An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.
How is baseball impacted by Newton's first law?Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.
What happens when a baseball bat strikes a ball?The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!
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Select the correct answer.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
O A.
B.
100 kilometers/hour south
200 kilometers/hour
200 kilometers/hour north
O C.
O D. 100 kilometers/hour
The average velocity of the car is 100 kilometers/hour south. This means that, on average, the car is traveling 100 kilometers per hour in the south direction relative to its starting point.
To determine the average velocity of the car, we need to calculate the displacement and divide it by the time taken. Velocity is defined as the rate of change of displacement with respect to time.
In this case, the car is traveling south, and its displacement is 200 kilometers from its starting point after 2 hours.
The average velocity is given by the formula:
Average velocity = Displacement / Time
The displacement is 200 kilometers south, and the time is 2 hours. Therefore, we have:
Average velocity = 200 kilometers south / 2 hours
Simplifying the calculation:
Average velocity = 100 kilometers/hour south
Hence, the correct answer is B. 100 kilometers/hour south. This indicates that the car's average velocity is 100 kilometers per hour towards the south direction.
It's important to note that velocity is a vector quantity and includes both magnitude (speed) and direction. In this case, the direction is specified as south, which indicates that the car is moving towards the south relative to its starting point.
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You Pushed a 25 Kg wooden box across a wooden floor at a constant speed of 1.0 m/s. The coefficient of kinetic friction is 0.20.
a) Find the normal force.
b) Find the friction force
(a) The normal force of the wooden box of mass 25 kg is 245 N (b) The friction force of the wooden box of mass 25 kg is 49 N.
(a) What is normal force?The normal force is an everyday force that is felt when a surface pushes against an object that is placed on that surface.
To find the normal force of the wooden box, we use the formula below.
Formula:
N = mg.......... EquationWhere:
N = Normal forcem = Mass of the wooden boxg = Acceleration due to gravityFrom the question,
Given:
m = 25 kgg = 9.8 m/s²Substitute these values into equation 1
N = 25×9.8N = 245 N(b) Similarly, to calculate the friction force, we use the formula below.
Fromula:
F = Nμ.......... Equation 2Where:
F = Friction forceμ = Coefficient of kinetic frictionFrom the question,
Given:
μ = 0.2Substitute into equation 2
F = 245×0.2 F = 49 NHence, (a) The normal force is 245 N (b) The friction force is 49 N.
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what is capasistanceb
\(\sf\huge\underline\pink{Answer:-}\)
Capacitance is the ratio of the change in the electric charge of a system, to the corresponding change in its electric potential.\(\rightarrow\)The capacitance of any capacitor can be either fixed or variable depending on their usage.
\(\rightarrow\)Capacitance is expressed as the ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them.
\(\rightarrow\)The capacitance value of a capacitor is measured in farads (F), units named for English physicist Michael Faraday (1791–1867).
\(\sf\large\underline\blue{Formula:-}\)
➢ \(\sf\green{q = CV}\)
Where,
\(\rightarrow\sf{q = charge}\)
\(\rightarrow\sf{C = capacitance}\)
\(\rightarrow\sf{V = voltage}\)
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