what additional information could be used to prove δefg δe'f'g' using aas? check all that apply. eg

Step-by-step explanation:

the answer is how many times does 0.225 l fit wholly into 5 l :

5 / 0.225 = 22.22222222...

so, she can fill 22 glasses fully.

22 × 0.225 = 4.95 l

so, she has at the end (after filling the 22nd glass) 0.050 l (= 50 ml) left.

Answer:

Step-by-step explanation:

150 - 15w

where w is the number of weeks he payed his mother the $15

The thickness of the clay layer, which drains only from the upper surface, can be determined based on the consolidation settlement observations. With 50% of consolidation settlement occurring in 1 hour for a 25 mm thick specimen, and a total primary consolidation settlement of 35 mm occurring over many years, the thickness of the clay layer is approximately 87.5 mm.

The consolidation settlement of a clay specimen can be used to estimate the thickness of a clay layer that drains only from the upper surface. In this case, the observed settlement data provides valuable information.

Firstly, we know that 50% of the consolidation settlement occurs in 1 hour for a 25 mm thick clay specimen. This is an important parameter for calculating the coefficient of consolidation (Cv) using Terzaghi's theory. From the Cv value, we can estimate the time required for full consolidation settlement.

Secondly, we are given that the same clay settles 10 mm over 10 years and eventually settles a total of 35 mm over a longer period. This long-term settlement is known as the total primary consolidation settlement. By comparing this settlement value with the settlement data from the oedometer test, we can determine the thickness of the clay layer.

To calculate the thickness, we can use the concept of the consolidation settlement ratio. The ratio of the total primary consolidation settlement to the consolidation settlement at 50% completion is equal to the ratio of the total thickness to the thickness at 50% completion. Applying this ratio, we can determine that the thickness of the clay layer, which drains only from the upper surface, is approximately 87.5 mm.

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Answer:

The integer that represents the change in the temperature each week = 5

The temperature of the weather drops 5°F each week

Step-by-step explanation:

The given parameters regarding the weather are;

The range over which the temperature dropped = 20°F

The duration over which the temperature dropped = 4 weeks

The rate at which the weather dropped each week = The same amount (constant rate)

Therefore, we have;

For a constant rate of change, the rate of change of the temperature of the weather, m, is given as follows;

m = (The change in the temperature)/(The duration of the change)

m = 20°F/(4 weeks) = 5°F/week

The integer that represents the change in the temperature each week = 5

Answer:

x=4

Step-by-step explanation:

The axis of symmetry is always x= the x-coordinate of the vertex

EX:

Vertex: (9,8)

Axis of Symmetry: x=9

The adjusted allowance for uncollectible accounts at December 31, 2013, for Calistoga Produce is $1,352.

To calculate the adjusted allowance for uncollectible accounts, we need to consider the credit sales, collections, accounts receivable written off, and the estimated bad debt expense. First, we calculate the estimated bad debt expense for 2013 by multiplying the credit sales ($324,000) by the estimated bad debt percentage (0.30%). This gives us $972. Next, we calculate the net accounts receivable by subtracting the collections ($310,000) and the accounts receivable written off ($1,790) from the previous balance of accounts receivable and allowance for uncollectible accounts. This gives us $476,210. Finally, we determine the adjusted allowance for uncollectible accounts by adding the estimated bad debt expense for 2013 to the net accounts receivable. This gives us $476,210 + $972 = $477,182. Since the given options do not match this amount exactly, we choose the closest option, which is $1,352 (option c).

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Answer:

let x =the price of the items

25x/100=$30

$30×100=25x

$3000=25x

divide both sides by 25

$3000/25=25x/25

$120=x

therefore the price is $120

Answer:

37.5

Step-by-step explanation:

30 x 0.25 =  7.5

30 +7.5

37.5

Answer:

Circumference = 2*pi*r

Diameter = 6 cm

Radius = 3 cm

Circumference = 2*22/7*3

= 18.85 cm.....

Step-by-step explanation:

Hope this helps you....

Pls mark me brainliest....

Answer:

Maybe 10

Step-by-step explanation:

Step-by-step explanation:

step 1. The square matrices are C and D.

step 2. If you add up the top rows you get 2, 8, -4 .

step 3. The answer is B.

The required sum of the two square matrices is,
\(\left[\begin{array}{ccc}2&8&-4\\1&0&3\\-1&-2&1\end{array}\right]\). Option B is correct.

Consider matrices A, B, C, and D,
\(A=\left[\begin{array}{cc}-1&4\\5&-2\\3&4\end{array}\right]\) , \(B =\left[\begin{array}{cc}4&4\\4&4\\4&4\end{array}\right]\), \(c= \left[\begin{array}{ccc}-1&2&5\\0&-4&1\\-4&3&1\end{array}\right]\), \(D = \left[\begin{array}{ccc}3&6&-9\\1&4&2\\3&-5&0\end{array}\right]\)

Matrix is defined as the arrangement of the number in the array between the square parenthesis.

Since Matrix C and D is a square matrix of 3 * 3 order.

\(C + D =\left[\begin{array}{ccc}-1&2&5\\0&-4&1\\-4&3&1\end{array}\right]+\left[\begin{array}{ccc}3&6&-9\\1&4&2\\3&-5&0\end{array}\right]\)
\(C + D =\left[\begin{array}{ccc}-1+3&2+6&5-9\\0+1&-4+4&1+2\\-4+3&3-5&1+0\end{array}\right]\)
\(C+D=\left[\begin{array}{ccc}2&8&-4\\1&0&3\\-1&-2&1\end{array}\right]\)

Thus, the required sum of the two square matrices is,\(\left[\begin{array}{ccc}2&8&-4\\1&0&3\\-1&-2&1\end{array}\right]\). Option B is correct.

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Answer:

0.00110192837

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

because it would be the reciprical of 1/8 which is 8/1 plus 3

Answer:

78.5

Step-by-step explanation:

circumference formula: \(\pi r^{2}\)

3.14 x \(5^{2}\)

3.14 x 25

78.5

The house's value Increase in dollars by $37,760.

The current value of the house is $509, 760.

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. Using the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

A house on the market was valued at $472,000.

After several years, the value increased by 8%.

Then, the value of house increased

= 472000 x 8/100

= $37,760

So, the current value of house

= 472000 + 37760

= $509, 760

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For the values of the derivative f '(x), the best estimates possible (average of the left hand sum) are f(2) = 146, f(4) = 174, f(6) = 220

the best estimates possible (average of the right hand sum) are the following f(2) = 174 ; f(4) = 204 ; f(6) = 256.

To evaluate the approximate value of an integral, we can use the area under the integrand with rectangles. Because it is simple to calculate the area for each rectangle, and then sum up each of the areas.

We have a table present below and consists two columns, one with x values and other with derivative values of f(x) that is f'(x).

x f'(x)

0 8

2 14

4 23

6 26

We have to determine best estimates possible average of the left and right hand sums). The initial value of function f(0), = 130

The left-hand approximations are represented by

\(f(2) = f(0) + \int_{0}^{2} f'(x)dx\)

≈ f(0)+ 2f′(0)

= 130 + 2(8) = 146

\(f(4) = f(0) + \int_{0}^{4} f'(x)dx\)

≈ f(0) + 2(f′(0)+ f′(2))

= 130 + 2(8 + 14) = 174

\(f(6) = f(0) + \int_{0}^{6} f'(x)dx\)

≈ f(0) + 2(f′(0) + f′(2) + f′(4))

= 130 + 2(8 + 14 + 23) = 220

The right-hand approximations are represented by

\(f(2) = f(0) + \int_{0}^{2} f(x)dx\)

≈ f(0) + 2(f′(0) + f′(2))

= 130 + 2( 8 + 14) = 174

\(f(4) = f(0) + \int_{0}^{4} f(x)dx\)

≈f(0) + 2(f′(2) + f′(4))

= 130 + 2( 14 + 23) = 130 + 74 = 204

\(f(6) = f(0) + \int_{0}^{6} f(x)dx\)

≈ f(0) + 2(f′(2) + f′(4) + f′(6))

= 130 + 2(14 + 23 + 26) = 130 + 126

= 256

Hence, required value is 256.

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Answer:

2/3

Step-by-step explanation:

Divide 1/2 by 3/4 to get 1/2 x 4/3 = 2/3 mph

Step-by-step explanation:

To find the slope (m) of the line that passes through the points (-3,-6) and (0,-12), we can use the slope formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) = (-3,-6) and (x2, y2) = (0,-12)

m = (-12 - (-6)) / (0 - (-3))

m = -6 / 3

m = -2

Therefore, the slope of the line is -2.

To find the y-intercept (b), we can use the slope-intercept form of the equation of a line:

y = mx + b

where m is the slope and b is the y-intercept.

Using the point (-3,-6) on the line, we can plug in the values for x, y, and m to solve for b:

-6 = (-2)(-3) + b

-6 = 6 + b

b = -12

Therefore, the y-intercept of the line is -12.

Putting it all together, the equation of the line in slope-intercept form is:

y = -2x - 12

Answer:

Step-by-step explanation:

To find the slope (m) and y-intercept (b) of the line passing through the points (-3-6)and (0,-12), we can use the slope- intercept form of a linear equation, which is:

y= mx + b

where m is the slope and b is the y- intercept.

First, we can find the slope (m) using the formula:

m=(y2-y1) / (x2-x1)

where (x1,y1)=(-3,-6)and(x2,y2)=(0,-12)

m= (-12-(-6)/(0-(-3)

m= (-12+6)/3

m= -2

So the slope of the line is -2.

Now we can use the point- slope form of a linear equation to find the y-intercept (b). We can use either of the two given points, let's use the point (-3,-6):

y - y1= m(x-x1)

y-(-6) = -2(x-(-3)

y+6= -2(x+3)

y+6 = -2x-6

y= -2x - 12

So the equation of the line in slope intercept form is y = -2x -12, which means the y-intercept (b)is -12. Therefore, the slope (m) is -2 and the y- intercept (b) is -12.

Answer:

C) (1/4, -1/4)

Step-by-step explanation:

first find the mid point on the x-axis,

3.5+4 = 7.5 /2 = 3.75

3.75-3.5=0.25

so this point is at (1/4)

then find the mid point on the y-axis

2.5+2=4.5/2=2.25

2.25-2.5 =-1/4

so the point is (1/4, -1/4)

According to the given statement The eighth term in the arithmetic sequence 2/3, 1, 4/3 is 3/1.

To find the eighth term in an arithmetic sequence, we can use the formula:

an = a1 + (n - 1)d

Where:

an represents the nth term,

a1 represents the first term,

n represents the term number,

d represents the common difference.

In this case, the given arithmetic sequence is:

2/3, 1, 4/3, ...

We can observe that the common difference (d) between consecutive terms is 1/3. Therefore, we have:

a1 = 2/3 (first term)

d = 1/3 (common difference)

n = 8 (eighth term)

Now we can substitute these values into the formula to find the eighth term (a8):

a8 = (2/3) + (8 - 1)(1/3)

Simplifying the expression:

a8 = (2/3) + 7(1/3)

a8 = (2/3) + 7/3

Combining the fractions:

a8 = (2 + 7)/3

a8 = 9/3

Simplifying the fraction by dividing the numerator and denominator by their greatest common divisor, which is 3:

a8 = 3/1

Therefore, the eighth term in the arithmetic sequence 2/3, 1, 4/3 is 3/1.

In conclusion, the eighth term is 3/1 or simply 3.

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The complete question is-

What is the eighth term in the arithmetic sequence 2/3, 1, 4/3, ? express your answer in simplest form.

Answer: x=5

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

A give me 2'zero

b give me 9'zero

c give 8'zero

d gives 5 zero

e give me 4'zero

for example it give me two zero it 100

or if five 5 zero it 100000

hope this helps

The correct derivative of the given function is option D) s' = 6t^5 - 9/t^2 - 6/t^3.

To find the derivative of the given function, we can use the quotient rule. The quotient rule states that if we have a function of the form f(t) = g(t)/h(t), then its derivative f'(t) can be calculated as:

f'(t) = (g'(t) * h(t) - g(t) * h'(t)) / (h(t))^2

Let's apply the quotient rule to the given function:

s = (t^8 + 9t + 3) / t^2

Using the quotient rule, we differentiate the numerator and denominator separately:

g(t) = t^8 + 9t + 3

g'(t) = 8t^7 + 9

h(t) = t^2

h'(t) = 2t

Now, we can substitute these values into the quotient rule formula:

s' = (g'(t) * h(t) - g(t) * h'(t)) / (h(t))^2

= ((8t^7 + 9) * t^2 - (t^8 + 9t + 3) * 2t) / (t^2)^2

= (8t^9 + 9t^2 - 2t^9 - 18t^2 - 6t) / t^4

= 6t^9 - 9t^2 - 6t / t^4

= 6t^5 - 9/t^2 - 6/t^3

Therefore, the derivative of the given function is s' = 6t^5 - 9/t^2 - 6/t^3, which matches option D.

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the given expression is,

= (-2-8) - (-6x + 5)

= -10 + 6x - 4

= 6x - 14

so the simpl

Unicode value of 66, which is the letter "B". Therefore, the correct answer to this question is option B: "B".

The terms you mentioned are related to the Unicode character encoding standard and the concept of evaluating expressions. When discussing the expression "A" + 1, it's essential to note that the Unicode value for the character "A" is 65.

The expression "A" + 1 is attempting to add a numerical value (1) to a character ("A"). In many programming languages, this operation is allowed, and the result would be based on the Unicode values of the characters involved. Since the Unicode value for "A" is 65, adding 1 to it would result in a new Unicode value of 66. Consequently, the evaluated expression would correspond to the character with the Unicode value of 66, which is the letter "B". Therefore, the correct answer to this question is option B: "B".

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Answer:zero

Step-by-step explanation:

a) The zero rates for the five maturities are: 1 year is 2.01%, 2 years is 2.48%, 3 years is 2.77%, 4 years is 1.73%, and 5 years is 4.32%.

b) The price of the security is $128.31.

a) To find the zero rates for all 5 maturities, we can use the formula for the present value of a bond:

PV = C / \((1+r)^n\)

where PV is the present value,

C is the coupon payment,

r is the zero rate, and

n is the number of years to maturity.

We can solve for r by rearranging the formula:

r = \((C/PV)^{(1/n) }\)- 1

Using the bond data given in the question, we can calculate the zero rates for each maturity as follows:

For the 1-year bond, PV = 98 and C = 0, so r = 2.01%.

For the 2-year bond, PV = 101, C = 2.48, and n = 2, so r = 2.48%.

For the 3-year bond, PV = 103, C = 2.91, and n = 3, so r = 2.77%.

For the 4-year bond, PV = 101, C = 2, and n = 4, so r = 1.73%.

For the 5-year bond, PV = 103, C = 5, and n = 5, so r = 4.32%.

Alternatively, we can use linear algebra to find the zero rates. We can write the present value equation in matrix form:

PV = A × x

where A is a matrix of coefficients, x is a vector of unknowns (the zero rates), and PV is a vector of present values.

To solve for x, we can use the equation:

x = (\(A^{-1}\)) x PV

where (\(A^{-1}\)) is the inverse of matrix A.

Using this method, we can solve for the zero rates as follows:

[2.01% ]

[2.48% ]

[2.77% ] = x

[1.73% ]

[4.32% ]

PV = \(A^{-1}\) x  [98]

                   [101]

                   [103]

                   [101]

                   [103]

PV =   [-0.0201]

          [ 0.0248]

          [ 0.0277]

          [-0.0173]

          [ 0.0432]

b) To find the price of the security which pays cash flows of $10 in one year, $25 in two years, and $100 in four years, we can use the formula for the present value of a series of cash flows:

PV = \(C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^4\)

where PV is the present value, C1, C2, and C3 are the cash flows, r is the zero rate, and the exponents correspond to the number of years until each cash flow is received.

Using the zero rates calculated in part (a), we can calculate the present value of each cash flow:

PV1 = $10 /(1+2.01 % \()^1\) = $9.80

PV2 = $25/(1+2.48%\()^2\) = $22.15

PV3 = $100/(1+1.73%\()^4\) = $81.36

Then, the price of the security is the sum of the present values:

PV = $9.80 + $22.15 + $81.36 = $128.31

Therefore, the price of the security is $128.31.

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Answer:

Step-by-step explanation:

5/12

Answer:

John ate 5/12 more pizza than Billy

Step-by-step explanation:

\(\frac{5x4}{3x4}\)-\(\frac{5x3}{4x3}\)

= \(\frac{20-15}{12}\)

=\(\frac{5}{12}\)

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\(3 {x}^{3} + 4 {x}^{2} + 11x + 10 = \)

\((x + 1)(3 {x}^{2} +x+ 10 )\)

Thus ;

\( \frac{(x + 1)(3 {x}^{2} + x + 10) }{(x + 1)} = \\ \)

\(3 {x}^{2} + x + 10\)

Done...

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The work done in stretching the spring from 40 cm to 44 cm is 0.28 J while the extension by the 20 N force is by 0.058 m.

Hooke's law states that, as long as the elastic limit is not exceeded the force that is exerted on an elastic material is directly proportional to the length of the material.

Given that;

W = 1/2Ke^2

W = elastic potential energy

K = force constant

e = extension

Given that the extension is obtained from; (49 - 32) * 10^-2

= 0.17 m

5 = 0.5 * K * (0.17)^2

K = 5/0.5 *  (0.17)^2

K = 346

a) To stretch the spring from 40 cm to 44;

e = (44 - 40) * 10^-2

= 0.04 m

W = 0.5 * 346 * (0.04)^2

= 0.28 J

b) The spring is stretched;

F = Ke

F =force

K = force constant

e = extension

20 = 346 * e

e = 20/346

e = 0.058 m

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