To determine the speed of the wave on the spring, we need to know both the frequency of the wave and the wavelength of the wave.
The frequency can be measured using a timer or frequency counter, and the wavelength can be measured by observing the distance between two adjacent peaks or troughs in the wave. Once we have both the frequency and wavelength, we can use the equation
v = fλ
Where v is the speed of the wave, f is the frequency, and λ is the wavelength, to calculate the speed of the wave on the spring.
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Johnny kicked a football from a hill 20 meters tall. The ball leaves at a 45.0 degree angle with an initial velocity of 30.0 m/second. How many seconds was the ball in the air? Report your answer to 3 sig figs. Seconds
Answer:
The value is \(t = 5.124 \ s\)
Explanation:
From the question we are told that
The height of the tree is \(s = 20 \ m\)
The angle the ball leaves is \(\theta = 45^o\)
The initial velocity is \(u = 30.0 \ m/s\)
Generally the vertical of the ball's initial velocity is mathematically evaluated as
\(u_y = u * sin (45)\)
=> \(u_y =- 30 * sin (45)\)
=> \(u_y = -21.21 \ m/s\)
Here \(u_y\) is negative because it is in the direction of the negative y-axis
Generally from kinematic equation we have
\(s = u_yt + \frac{1}{2} g t^2\)
=> \(20= -21.21 t +4.9 t^2\)
=> \(4.9 t^2 -21.21 t- 20= 0\)
Solving using quadratic formula we have that
\(t = 5.124 \ s\)
Superposition and interference of waves are inversely related in terms of the frequency and wavelength of traveling waves colliding in uniform media. True or false
Superposition and interference of waves are inversely related in terms of the frequency and wavelength of traveling waves colliding in uniform media. The given statement is False.
Superposition and interference of waves refer to the phenomenon that occurs when two or more waves collide in a uniform medium.
However, they are not inversely related in terms of frequency and wavelength. Superposition is the principle that states the total displacement of the medium at any point is the sum of the individual wave displacements. Interference, on the other hand, describes the constructive and destructive patterns that result from the superposition of waves.
Both superposition and interference are related to the frequency and wavelength of traveling waves, but they are not inversely related. The frequency and wavelength of individual waves will determine the resulting interference pattern, but the relationship between frequency and wavelength does not determine the superposition or interference directly.
The statement that superposition and interference of waves are inversely related in terms of the frequency and wavelength of traveling waves colliding in uniform media is false. Instead, these phenomena occur when waves collide, and their frequency and wavelength contribute to the resulting interference patterns.
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Consider a beaker with two holes X and Y near the base, such that hole X is ABOVE hole Y. The holes are closed with water-resistant tape and the beaker is filled with water.
Both the holes are then uncovered at the same time. If water from hole X comes out in a stream that touches the ground at a distance of 5 cm away from the beaker, how far from the beaker will the stream from hole Y touch the ground?
1. exactly 5 cm
2. less than 5 cm
3. more than 5 cm
4. (It will be more or less than 5 cm depending on the distance between the two holes.)
As the height of the hole increases, the velocity of the stream increases, results in a higher distance from the beaker. Therefore, the distance of the stream from the hole Y will be less than that from X thus, less than 5 cm is correct.
What is stream speed ?The speed of stream can be determined using the height and acceleration due to gravity g. We can use the equation for velocity using the parameters g and h.
v = √2gh
Therefore, as the height h increases, v increases.
Similarly the distance s = vt
therefore, the distance increases with v.
Here, the hole x is above the hole Y. Then the stream from X will have the greater speed and it covers greater distance (5 cm )from the beaker. Stream from Y slow compared to that in X hence covers a distance less than 5 cm. Hence, option 2 is correct.
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a homer in in a baseball game was measured at 450 feet. how many meters is this equal to?
If a curve is banked to accommodate cars traveling at 15 m/s, what will happen during an ice storm (no friction with the road) to a car moving at a faster speed?
1-It will gradually slide down the bank.
2-It will continue to follow the curve as if there were no ice.
3-It will gradually slide up the bank.
4-It will quickly slide up the bank.
chose one
If a curve is banked to accommodate cars traveling at 15 m/s, It will gradually slide up the bank.
Hence the correct option is 3.
When a curve is banked, it is designed to provide a centripetal force that helps vehicles navigate the curve safely at a specific speed. In the absence of friction, such as during an ice storm, there is no lateral force acting on the car to counteract the car's tendency to continue in a straight line due to inertia.
As a result, the car will continue to move in a straight line and gradually slide up the bank of the curve. The lack of friction prevents the car from maintaining its intended trajectory along the banked curve, causing it to veer upwards.
This is because the horizontal component of the car's velocity cannot be balanced by friction, leading to an imbalance of forces and causing the car to slide in an upward direction.
Therefore, option 3 - "It will gradually slide up the bank" is the most accurate choice.
Hence the correct option is 3.
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How much gravitational force attracts a ball weighing 300 kilograms ?
Given that,
Mass of a ball = 300 kg
To find,
The gravitational force acting on the ball.
Solution,
The force acting on the ball is force of gravity. It is equal to the weight of the ball.
W = mg
Substitute the value of m and g in the above formula
W = 300 kg × 10 m/s²
= 3000 N
Therefore, the ball attracts with a force of 3000 N.
As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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If a 4500 Watt oven is on for 4 hours, then how many kilowatt-hours (kWh) of energy are used? 18.0 kWh If the power company charges $0.10 per kilowatt-hour (kWh), then how much did it cost (in dollars) to run the oven for the 4 hours in the problem above? dollars
The amount of energy used is 18.0 kWh and the cost to run the oven for 4 hours is $1.80.
The first step is to calculate the energy used by the oven in kilowatt-hours (kWh). This can be done by multiplying the power of the oven (4500 Watts) by the time it was on (4 hours) and then dividing by 1000 to convert from Watts to kilowatts:
Energy = (4500 Watts) × (4 hours) ÷ 1000 = 18.0 kWh
Next, we can calculate the cost of running the oven by multiplying the energy used (18.0 kWh) by the cost per kilowatt-hour ($0.10/kWh):
Cost = (18.0 kWh) × ($0.10/kWh) = $1.80
Therefore, it cost $1.80 to run the oven for the 4 hours in the problem above.
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what term describes water flowing within a channel in which all water molecules travel along parallel and uniform flow paths?
The term that describes water flowing within a channel in which all water molecules travel along parallel and uniform flow paths is laminar flow.
What is laminar flow?Laminar flow corresponds to a specific pattern of fluid motion wherein the particles glide smoothly in parallel layers. This type of flow exhibits minimal turbulence and heightened viscosity. Laminar flow predominantly manifests in narrow, sleek conduits, such as pipes or the space between parallel plates.
In laminar flow, the water molecules navigate the channel in a linear trajectory. They abstain from colliding either amongst themselves or with the walls of the conduit.
This is attributed to the water molecules' motion in undisturbed, parallel strata. The strata of water retain their distinctness without intermixing, thereby fostering an exceptionally organized and systematic water flow.
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A pressure gauge 7 m above the bottom of a tank reads 65 kPa. Another at 4m above the bottom reads 87 kPa. What is the density of the fluid
We can solve for ρ by rearranging this equation and substituting in the given values:ρ = (p0 + 22 - p) / g(H - h1 - h2)= (101.3 + 22 - 65) / (9.81 × (15 - 7 - 4))= 1,150 kg/m³Therefore, the density of the fluid is 1,150 kg/m³.
Let the density of the fluid be ρ, and let the height of the tank be H.
Since the pressure gauge 7 m above the bottom of the tank reads 65 kPa, we have: p + ρgh1 = 65Here, p is the atmospheric pressure, g is the acceleration due to gravity, and h1 is the height of the fluid above the gauge at 7 m from the bottom of the tank.
Similarly, the pressure gauge 4 m above the bottom of the tank reads 87 kPa, so p + ρgh2 = 87Here, h2 is the height of the fluid above the gauge at 4 m from the bottom of the tank. Now, we can subtract these two equations to eliminate the pressure term: p + ρgh1 - (p + ρgh2) = 65 - 87Simplifying and rearranging,
we get:ρg(h1 - h2) = 22... equation (1)We can also use the fact that the pressure at the bottom of the tank is equal to the weight of the fluid column above it: p + ρgH = ρg(h1 + h2) + p0Here, p0 is the atmospheric pressure at the surface of the fluid, and the right-hand side of the equation represents the weight of the fluid column from the bottom of the tank to the surface.
Now, we can substitute the expressions for p and ρg(h1 - h2) from equations (1) and (2) into this equation and simplify: p + ρgH = ρg(h1 + h2) + p0p + ρg(H - h1 - h2) = p0 + 22
Since the fluid is incompressible, we can assume that its density is constant throughout the tank. Therefore, we can solve for ρ by rearranging this equation and substituting in the given values:ρ = (p0 + 22 - p) / g(H - h1 - h2)= (101.3 + 22 - 65) / (9.81 × (15 - 7 - 4))= 1,150 kg/m³
Therefore, the density of the fluid is 1,150 kg/m³.
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a curler pushes a stone to a speed of 3.0 m/s over a time of 1.4 s . ignoring the force of friction, how much force must the curler apply to the stone to bring it up to speed? 4.3 n 21 n 43 n 430 n
No option , The curler apply to the stone to bring it up to speed is 42.85 N.
F = 20*3/1.4 = 42.85 N
3 *3 = 2*u*9.8*40
u = 0.0114
Despite their similarities, distance and displacement have very different meanings, as do speed and velocity. Speed, a scalar quantity, describes "how quickly an object is travelling." You can think of speed as the rate at which an object travels a distance. An object moving quickly has a high speed and travels a fair distance in a brief period of time. In contrast, a slow-moving object travels a comparatively short distance in the same amount of time because of its low speed. Zero speed refers to an object that is completely stationary.
[Speed = Distance Time] is the general formula for calculating an object's speed. The SI speed unit is m/s.
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assemblies that may be required by code to have a minimum fire resistance rating from an independent testing agency because of the occupancy are called ___ assemblies.
Assemblies that are mandated to possess a minimum fire resistance rating from an independent testing agency, based on the occupancy they serve, are referred to as fire-rated assemblies.
These assemblies are vital for maintaining the safety of building occupants, as they provide crucial fire protection by limiting the spread of fire and smoke, allowing for safe evacuation, and facilitating effective firefighting operations.
Building codes and regulations are established to safeguard the lives of individuals and protect property in the event of a fire. As a part of these regulations, certain types of assemblies within a building must be designed and constructed to withstand the effects of fire for a specified duration. This requirement ensures that occupants have adequate time to evacuate safely, while also facilitating effective fire suppression and containment.
The assemblies that are subject to these fire resistance requirements are typically walls, floors, columns, and roofs. The specific assemblies and their fire resistance ratings depend on various factors, including the occupancy type, building height, size, and use. The fire resistance rating represents the amount of time the assembly can endure exposure to fire before it fails to perform its intended function.
To determine the fire resistance rating of an assembly, independent testing agencies, such as Underwriters Laboratories (UL) or the American Society for Testing and Materials (ASTM), conduct rigorous tests according to standardized procedures. These tests subject the assembly to controlled heating conditions that simulate a real fire scenario. The assembly's performance during the test, including factors like structural integrity, insulation, and smoke containment, is closely monitored and evaluated.
Once an assembly successfully passes the testing procedure, it is assigned a fire resistance rating based on the duration it withstood the fire conditions. Common fire resistance ratings include 30 minutes, 1 hour, 2 hours, and 3 hours, although other durations may be specified depending on the building code and regulations in a particular jurisdiction.
The purpose of these fire-rated assemblies is to compartmentalize a building, creating barriers that slow down the spread of fire and smoke. By having these rated assemblies, the progression of fire is impeded, allowing occupants more time to escape and giving firefighters an opportunity to control and extinguish the fire. Additionally, fire-rated assemblies also prevent fire from spreading to adjacent structures, minimizing the potential for significant property damage and loss.
It is important to note that the specific term used to refer to these assemblies can vary based on the building codes and regulations in different regions. Some common terms for these assemblies include fire-rated assemblies, fire-resistive assemblies, or simply fire-rated walls, floors, columns, or roofs.
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for a particular process, 28 kj of heat is absorbed and 15 kj of work is done on the surroundings. what is δu?
For a process with 28 kJ of heat absorbed and 15 kJ of work done on the surroundings, the change in internal energy (δU) is 13 kJ.
In thermodynamics, the change in internal energy (δU) is related to heat (Q) and work (W) through the first law of thermodynamics: δU = Q - W. In this particular process, 28 kJ of heat is absorbed (Q = 28 kJ), and 15 kJ of work is done on the surroundings (W = -15 kJ, since work done on the surroundings is negative).
Plugging these values into the formula, we get: δU = 28 kJ - (-15 kJ) = 28 kJ + 15 kJ = 13 kJ. So, the change in internal energy (δU) for this process is 13 kJ.
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A 50.0 kg lead block initially at 15 °C is released from rest at the top of an inclined plane with a 10° angle above the horizontal. The inclined plane is 5.00 m long. The block reaches the bottom of the inclined with a speed of 2.20 m/s. How much work is done the friction force on the block? What is the change of temperature of the block? Assume that work done by the friction force equals by magnitude the amount of heat going into the block. CL = 130 J/kg °C
Given data:
* The mass of the lead is m = 50 kg.
* The angle of the inclined plane with the horizontal is,
\(\theta=10^{\circ}\)* The length of the inclined plane is L = 5 m.
* The speed of the lead at the bottom of the plane is v = 2.2 m/s.
* The initial temperature of the lead is,
\(T_i=15^{\circ}\text{ C}\)* The specific heat of lead is,
\(c_L=130J/kg^{\circ}C\)Solution:
(a). The kinetic energy of the lead at the bottom of the inclined plane is,
\(\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times50\times2.2^2 \\ K=121\text{ J} \end{gathered}\)The diagrammatic representation of the given case is,
From the diagram, the initial height of the block is,
\(\begin{gathered} \sin (\theta)=\frac{h}{L} \\ h=L\sin (\theta) \end{gathered}\)Substituting the known values,
\(\begin{gathered} h=5\times\sin (10^{\circ}) \\ h=0.87\text{ m} \end{gathered}\)The potential energy at the top of the inclined plane is,
\(U=\text{mgh}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} U=50\times9.8\times0.87 \\ U=426.3\text{ J} \end{gathered}\)The lead block is initially at rest at the top of the inclined plane, thus, the kinetic energy at the top of the inclined plane is zero.
The net energy at the top of the inclined plane is,
\(\begin{gathered} E_i=U+K_i \\ E_i=U+0 \\ E_i=426.3\text{ J} \end{gathered}\)The height of the lead block at the bottom of the inclined plane is zero, thus, the potential energy at the bottom of the inclined plane is zero.
The net energy at the bottom of the inclined plane is,
\(\begin{gathered} E_f=U_f+K \\ E_f=0+121 \\ E_f=121\text{ J} \end{gathered}\)Thus, the energy loss due to the friction is,
\(\begin{gathered} E_f-E_i=121-426.3 \\ E=-305.3\text{ J} \end{gathered}\)Here, the negative sign indicates the loss of energy,
The work done by the frictional force is equal to the amount of energy loss during the motion of the lead block down the inclined plane.
Thus, the work done by the friction force on the lead is 305.3 J.
(b). The energy loss takes place in the form of heat.
The amount of heat produced in terms of the mass, temperature, and specific heat is,
\(Q=mc_L(T_f-T_i)\)where Q is the amount of heat produced, T_f is the final temperature and T_i is the initial temperature,
Substituting the known values,
\(\begin{gathered} 305.3=50\times130\times(T_f-15) \\ 305.3=6500T_f-97500 \\ 6500T_f=305.3+97500 \\ 6500T_f=97805.3 \end{gathered}\)By simplifying,
\(\begin{gathered} T_f=\frac{97805.3}{6500} \\ T_f=15.05^{\circ}\text{C} \end{gathered}\)Thus, the final temperature of the lead block is 15.05 degrees celsius.
The work done on an object is equal to the force times the distance moved in the direction of the force. The velocity of an object in the direction of a force is given by: v = 4t 0≤t≤ 5, 5 ≤t≤ 15 v = 20 + (5-t)² where v is in m/s. With step size h=0. 25, determine the work done if a constant force of 200 N is applied for all t a) using Simpson's 1/3 rule (composite formula) b) using the MATLAB function trapz
A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.
B) Using the MATLAB function trapz, the work done is approximately 7750 J.
Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.
A) Force (F) = 200 N (constant for all t)
Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)
Step size (h) = 0.25
To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.
Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.
Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].
For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²
Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).
Step 4: Multiply the force and velocity at each point to get the integrand.
For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]
Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].
The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]
Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).
Step 6: Multiply the result by the step size h to get the work done.
Work done: 1250 J
B) % Define the time intervals and step size
t = 0:0.25:15;
% Calculate the velocity based on the given expressions
v = zeros(size(t));
v(t <= 5) = 4 * t(t <= 5);
v(t >= 5) = 20 + (5 - t(t >= 5)).^2;
% Define the force value
F = 200;
% Calculate the work done using MATLAB's trapz function
\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;
% Display the result
disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);
The final answer for the work done using MATLAB's trapz function with the given force and velocity is:
Work done using MATLAB's trapz function: 7750 J
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Which of the following statements is True? Cutting tools are more likely to reach end of life due to crater wear than flank wear. The majority of heat generated in a cutting process is due to friction
The statement that is true is that the majority of heat generated in a cutting process is due to friction, and not because of crater wear more than flank wear as stated in the other option.
Heat generated in a cutting processIn the metal-cutting process, heat is generated, which is due to the deformation of the metal and friction between the tool and the workpiece. The majority of the heat generated in a cutting process is due to friction. Heat generation results from the conversion of mechanical energy into thermal energy as a result of the friction and deformation encountered during cutting.
The heat generated in the cutting process can lead to a range of machining issues, including tool wear, thermal damage to the workpiece, and altered cutting parameters. To minimize these issues, cooling and lubrication are often used to reduce the temperature of the cutting region and decrease the friction between the tool and workpiece.
Cutting tool wearWear is a common problem associated with cutting tools, which reduces their performance and lifespan. Two types of wear are flank wear and crater wear.
Flank wear occurs due to the abrasive action of the workpiece on the tool flank, resulting in the gradual removal of the cutting tool material. Crater wear is when a small depression forms on the tool face, where the workpiece material is welded or adhered to the tool material.
Cutting tools are more likely to reach the end of their useful life due to flank wear than crater wear. Crater wear can be corrected or repaired by machining or grinding the tool face, while flank wear requires complete replacement of the tool.
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Photoelectric effect is observed on two metal surfaces.
Light of wavelength 300.0 nm is incident on a metal that has a work function of 2.80 eV. What is the maximum speed of the emitted electrons?
...m/s
Therefore, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s.
The photoelectric effect is observed on two metal surfaces. If light of wavelength 300.0 nm is incident on a metal that has a work function of 2.80 eV, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s. What is the photoelectric effect? The photoelectric effect, also known as the Hertz–Lenard effect, is a phenomenon in which electrons are emitted from a metal surface when light is shone on it. The photoelectric effect was initially studied by Heinrich Hertz in 1887 and later by Philipp Lenard in 1902.Latex-free answer: To calculate the maximum speed of emitted electrons using the photoelectric effect equation, we can use the following formula: KEmax = hν - φwhere KE max is the maximum kinetic energy of the ejected electron, h is Planck's constant, ν is the frequency of the incident light, and φ is the work function of the metal. Using the equation, we can convert the given wavelength of 300.0 nm to frequency by using the formula c = λν where c is the speed of light and λ is the wavelength. c = λνν = c/λν = (3.0 x 10⁸ m/s) / (300.0 x 10⁻⁹ m)ν = 1.0 x 10¹⁵ Hz, Now we can plug in the values in the equation: KE max = (6.626 x 10⁻³⁴ J s) (1.0 x 10¹⁵ Hz) - (2.80 eV)(1.60 x 10⁻¹⁹ J/eV)KE max = 1.06 x 10⁻¹⁹ J - 4.48 x 10⁻¹⁹ JKE max = -3.42 x 10⁻¹⁹ J. Since KE max is a positive value, we can convert the value to speed using the equation KE = 1/2mv² where m is the mass of the electron and v is the velocity of the electron: v = √(2KE/m)v = √[(2)(3.42 x 10⁻¹⁹ J)/(9.11 x 10⁻³¹ kg)]v = 1.62 x 10⁶ m/s. Therefore, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s.
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we're replacing the concrete floor in our basement with a new type of concrete. according to the manufacturer, this new concrete has a thermal conductivity of 1.333 w m^-1 k^-1. if our basement has an area of 17.5 m^2, and we plan on pouring a 6 cm thick layer of the new concrete, what is the rate at which heat leaves through the floor when the basement temperature is 23 degree celsius and the ground temperature is 3 degree celsius
The correct option is E, the rate at which heat leaves through the floor when the basement temperature is 23C and the ground temperature is 3 degree Celsius is 1.2 kW.
Q/t = kA(T1 - T2)/d
Thermal conductivity k = 1.33 W \(m^-1 k^-1\)Area A = 17.5 m²Thickness of concrete layer d = 6 cm = 0.06 mTemperature of basement T1 = 23 + 273 = 296 KTemperature of ground T2 = 3 + 273 = 276 KSubstituting these values in the formula, we get:Q/t = (1.33 W \(m^-1 k^-1\)) * (17.5 m^2) * (296 K - 276 K) / (0.06 m)
Simplifying the expression, we get:
Q/t = 1200 W = 1.2 kW
Heat is a form of energy that is transferred from one body or system to another due to a temperature difference between them. Heat is a type of energy that is related to the motion of atoms and molecules within a substance. The greater the temperature of a substance, the greater the average kinetic energy of its molecules, which leads to more vigorous and rapid motion. When two bodies or systems are in contact with different temperatures, heat flows from the hotter to the cooler object or system until they reach thermal equilibrium.
Heat is commonly measured in units of joules or calories, and its transfer can occur through conduction, convection, or radiation. Conduction refers to the transfer of heat through direct contact between two substances, while convection involves the transfer of heat through the movement of fluids or gases. Radiation refers to the transfer of heat through the emission and absorption of electromagnetic waves.
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Complete Question:
A family decides to remodel the concrete floor in their basement. The new concrete has a thermal conductivity of 1.33 W m-1 K-1. If the area of their project is 17.5 m2, and plan on a 6 cm thick layer, what is the rate at which heat leaves through the floor when the basement temperature is 23C and the ground temperature is 3C?
A). 8.9 kW
B). 7.8 kW
C). 6.7 kW
D). 78 W
E). 1.2 kW
POSSIBLE 1. Which of the following are examples of a physical reactions: (1) ice melting, (2) pencil breaking, (3) iron rusting, (4) wood burning? a. 1.4 b. 3,4 c. 2.3 d. 1,2
Answer:
D) 1 & 2
Explanation:
Ice melting can be refrozen and although the pencil breaks, it doesn't change the chemical formula of the pencil
On his fishing trip Justin rides in a boat 12 km south. The fish aren’t biting so they go 4 km west. They then follow a school of fish 1 km north. What distance did they cover? What was their displacement?
Answer:
I think the answer is 8km2
Answer:
Distance = 17km
Displacement = 12.6 km
Explanation:
south 12km
west 4km
north 1km
Total distance = 12 + 4 + 1 = 17km
Total displacement = in picture above.
Hurry Please !!!!!
Study the diagram
Point C identifies the____
of the wave
Answer: Trough
Explanation: The point labeled C in the wave diagram above is the TROUGH of the wave motion. The trough of a wave motion identifies or signifies the point of least or minimum Displacement by measuring the downward Displacement of the wave. The point A is the CREST which is the opposite of the trough, signifying the point of maximum or upward Displacement of the wave cycle.
Point B is the wave amplitude which signifies the maximum extent of vibration from the equilibrium position of a wave. The point labeled D refers to the wavength of the wave motion which is the distance between successive crest or troughs of a wave motion.
With modulus of elasticity, MoE - 7,920 N/mm2 at 12% mo, what would be the expected MoE at 23% mc? Assume FSP = 30 % Give your answer in N/mm² to the nearest whole number.
to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)
given information:
Modulus of elasticity at 12% moisture content =7,920 N/mm²
resultant shrinkage or final shrinkage percentage FSP = 30%
To calculate the expected MoE at 23% moisture content we have the following equation:
MoE-23% = \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)
MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)
MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)
MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)
MoE-23% = \(7,920 N/mm² × 0.8636\)
MoE-23% = \(6,836 N/mm²\)
therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).
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Moji listed the solids in order of hardness as graphite < chalk < quartz. His
peer group suggested some experimental errors that may have caused this to
happen. Which experimental error most likely led Moji to this conclusion?
A. Moji might have used color as an indication of hardness.
B. Moji might have thought that crumbliness was a sign of softness.
C. Moji might have thought that crumbliness was a sign of hardness.
D. Moji could have chosen hardness tests that were not reliable.
Answer: D.
Explanation:
Moji listed the solids in order of hardness as graphite < chalk < quartz. because his peer group suggested some experimental errors that may have caused this to happen. The experimental error most likely led Moji to the conclusion that Moji could have chosen hardness tests that were not reliable. Therefore the correct option is D.
What is the matter?Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gases, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
There are various tests to judge the mechanical hardness of any solid material such as the Rockwell hardness test, Brinell's hardness test,Vicker's diamond hardness test, and Knoop's hardness test which is also known as microhardness test
The experimental error most likely led Moji to the conclusion that Moji could have chosen hardness tests that were not reliable. Therefore the correct option is D.
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Which of the following is closest in size (radius) to a neutron star?A) the EarthB) a cityC) a football stadium D) a basketballE) the SunAnswer: B
B) A city is closest in size to a neutron star.
A typical neutron star has been found to be 1.4 times as heavy as Sun and has a radius of approximately 11 km.
Earth is not considered to be the closest since it has a radius of 6378 km which is much greater than the radius of a neutron star. Similarly, the Sun has a radius of 696,340 km therefore Sun is also not considered to be the closest.
The radius of a basketball is 4.7 inches which is equal to 0.00012 km so it is much less than the radius of a neutron star.
On the other hand, a city has a radius of approximately 10 to 30 km therefore it is considered to be the nearest in radius to a neutron star
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A leaf falls from a tree. Because the leaf is so light, it will be affected by air
resistance. Taking this into account, what is the acceleration of the leaf as it
falls?
O A. O m/s2
O B. Less than 9.8 m/s2
O C. Exactly 9.8 m/s2
O D. More than 9.8 m/s2
Answer:
b
Explanation:
Answer: less than 9.8 m/s
Explanation:
An aircraft has the following directional stability and control characteristics: Cng = +0.0035/deg Cns, = -0.003/deg Ormax = 30 deg a) Determine the rudder deflection required to maintain a sideslip angle of B = 4 deg. Which rudder pedal would you push to get B = 4 deg? w lby b) Given the following conditions: -60.C Cle=1.0 S landing Assuming Vand = 1.2 Vstall, determine the maximum crosswind component that can be handled by the rudder at sea level. We want to land the aircraft with the longitudinal acis aligned with the runway.
Answer:
Unfortunately, the given problem lacks some important information, such as the aircraft type, wing span, and weight, which are necessary to calculate the maximum crosswind component. Without this information, it is not possible to provide a meaningful answer.
Regarding part (a) of the question, we can use the formula for the sideslip angle to find the rudder deflection required:
B = Cng * beta + Cns * rudder_deflection
where beta is the sideslip angle and rudder_deflection is the angle of the rudder relative to its neutral position. Rearranging the equation, we get:
rudder_deflection = (B - Cng * beta) / Cns
Substituting the given values, we get:
rudder_deflection = (4 - 0.0035/deg * beta) / (-0.003/deg)
Without knowing the value of beta, we cannot determine the rudder deflection required. However, we can determine which rudder pedal to push based on the sign of the rudder deflection. If the rudder deflection is positive, we need to push the right rudder pedal, and if it is negative, we need to push the left rudder pedal.
Note: Cng and Cns are the directional stability and control derivatives, respectively, and Ormax is the maximum rudder deflection angle.
Explanation:
At an amusement park, you and a friend sit on a large rotating disk. You sit at the edge and have a rotational speed of 10 RPM and a linear speed is 12 m/s. Your friend does halfway to the center What is her rotational speed and linear speed
What cause sound seismic and electromagnetic waves to transmit energy through different mediums
Answer:
Explanation:
Sound, seismic, and electromagnetic waves transmit energy through different mediums due to the motion of particles in the medium.
Sound waves transmit energy through the vibration of particles in a solid, liquid, or gas. The energy is transferred from particle to particle as the wave travels through the medium.
Seismic waves are created by the sudden release of energy from earthquakes, volcanic eruptions, or other geological events. These waves travel through the Earth's solid mantle and crust, transmitting energy through the vibration of particles in the rock.
Electromagnetic waves are a type of wave that does not require a medium to travel through. They are created by the motion of charged particles, such as electrons, and can travel through a vacuum, such as space. Electromagnetic waves transfer energy through the oscillation of electric and magnetic fields.
Considering the symmetry of the charge distribution, choose one of the following options as the most appropriate choice of Gaussian surface to use in this problem. A) a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r0
B) a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r1
C) a sphere of radius r
D) a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r
E) an infinite cylinder whose axis coincides with the axis of the rod and whose cross section has radius r
One of the options that are the most appropriate choice of Gaussian surface to use in this problem is a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r.
This is because the charged cylinder which is of infinite length as mentioned and hence there won't be any electric flux coming out of the top and bottom flat surfaces.
Now, to find out the magnitude of the electric field, we shall have to apply Gauss's law,
\(\int\limits^ _ {} \,\)Eda= Q enclosed/E
Gaussian surfaces would be the simplest to use to determine the electric field intensity near a long, straight, charged wire, is a cylinder whose axis coincides with the wire.
The Gaussian surface is primarily known as a closed surface in a three-dimensional space (3-D) such that the flux of a vector field is calculated.
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What is the momentum of a 2.0-kg object that has a velocity of 8.0 m/s ?
Please help