____ is based on the acceptance of rules and laws.
Multiple Choice
1. Rational-legal authority
2. Traditional authority
3. Legal power
4. Political power
_____ involves relying on assumptions and beliefs about the world, whereas _____ involves making direct observations of the world.
Intuition involves relying on assumptions and beliefs about the world, whereas empirical observation involves making direct observations of the world.
Intuition refers to the process of using past experiences, beliefs, and assumptions to make quick, unconscious judgments or decisions about the world.
It is often associated with feelings or gut reactions and can be influenced by factors such as emotions, biases, and prior knowledge.
Empirical observation, on the other hand, refers to the process of gathering information about the world through direct sensory experience, such as seeing, hearing, touching, and measuring.
Empirical observations are the foundation of scientific inquiry as they provide the raw data that can be used to test and refine hypotheses and theories.
Unlike intuition, empirical observations are objective and uninfluenced by personal biases or assumptions.
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What is the period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth)?
When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.
Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.
Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.
To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²
Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds
Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
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A car travels a distance of 120 km in 4 hours. What is its average speed in kilometers per hour?
Answer:
60 kilometers per hr
Explanation:
5. A Car of mass 1000kg is driven from it's initial
state with uniform acceleration and reaches a
Speed of 30km/h in 10 second find
1 ). Force exerted by the engine.
2). the power in killo watts (kw)
A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How many radians did the disk turn while stopping ? C. how many revolutions?
Answer:
A. The angular acceleration of the disk is -1.047 radians per square second.
B. The disk turns 4.715 radians while stopping.
C. The disk did 0.750 revolutions while stopping.
Explanation:
A. In this case, the disk is deceleration at a constant rate. Hence, the angular acceleration experimented by the object (\(\alpha\)), in radians per square second, can be found by means of this kinematic expression:
\(\alpha = \frac{\omega-\omega_{o}}{t}\) (1)
Where:
\(\omega_{o}\) - Initial angular speed, in radians per second.
\(\omega\) - Final angular speed, in radians per second.
\(t\) - Time, in seconds.
If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(t = 3\,s\), then the angular acceleration of the disk is:
\(\alpha = \frac{\omega-\omega_{o}}{t}\)
\(\alpha = -1.047\,\frac{rad}{s^{2}}\)
The angular acceleration of the disk is -1.047 radians per square second.
B. The change in position of the disk (\(\Delta \theta\)), in radians, is determined by the following kinematic formula:
\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\) (2)
If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(\alpha = -1.047\,\frac{rad}{s^{2}}\), then the change in position is:
\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)
\(\Delta \theta = 4.715\,rad\)
The disk turns 4.715 radians while stopping.
C. A revolution equals 2π radians, then, then number of revolutions done by the disk while stopping is found by simple rule of three:
\(\Delta \theta = 4.715\,rad \times \frac{1\,rev}{2\pi\, rad}\)
\(\Delta \theta = 0.750\,rev\)
The disk did 0.750 revolutions while stopping.
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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Two cars stuck in a traffic jam and each sounds its horn at a frequency of 625 Hz. A bicyclist between the two cars, 4.50 m from each horn, is find that she is at a point of constructive interference. How far backward must she move to reach the nearest point of destructive interference? As a speed of sound use the speed of 343 m/s.
The bicyclist needs to move backward by a distance of 0.2744 m to reach the nearest point of destructive interference.
What is the distance for the nearest point of destructive interference?The wavelength of the sound wave produced by the horns can be calculated as;
λ = v/f
λ = 343/625
λ = 0.5488 m
let the integer multiple of the wavelength = d
d = mλ
d = 4.50 + x
where;
x is the distance that the bicyclist is from the point of constructive interference towards one of the horns4.50 + x = mλ
4.50 + x = m(0.5488)
let the odd multiple of half the wavelength = d'
d' = (2n + 1)(λ/2)
d' = 4.50 - y
where;
y is the distance that the bicyclist is from the point of destructive interference towards one of the horns.4.50 - y = (2n + 1)(λ/2)
4.50 - y = (2n + 1)(0.2744)
mλ = 2n(λ/2) + (λ/2) + 4.50 - y
x - y = (2n + 1)(λ/2) - 4.50
x - y = (2n + 1)(0.2744) - 4.50
Let n = 0
x - y = (0 + 1)(0.2744) - 4.50
y = 4.50 - 0.2744
y = 4.2256
The distance is cakculated as;
4.50 - y = 0.2744 m
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Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.
The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.
Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.
During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.
The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.
By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.
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I need help with this problem :(
Answer:
it tells you that the speed increases until about 20 seconds then keeps a steady pace for 20 seconds then the speed drops and stops at 55 seconds in the process.
zeugen and yardang differences
Answer:
Yardangs are formed on vertical strata while zeugen on horizontal strata. ... Yardangs are formed on vertical hard/soft layers of rock, while zeugen (this is its plural form) are formed on horizontal bands of hard/soft rocks giving it a more mushroom-like shape. The Great Sphinx of Giza has been sculpted in a yardang
As the Moon revolves around the Earth, it also rotates on its axis. Why is it that the same side of the Moon is always visible from Earth?
Answer: The speed of the moon's rotation keeps the same side always facing Earth.
Explanation: Please mark me brainiest
Answer:
The speed of the Moon's rotation keeps the same side always facing Earth.
Explanation:
got it right on study island :)
How long a muscle can exert a force without getting tired is known as
O muscular endurance
Resistance training
O Plyometrics enforcement
O Muscular strength
Answer: the first option muscular endurance
Explanation:
In 1994, a pumpkin with a mass of 449 kg was grown in Canada. Suppose you want to push a pumpkin with this mass along a smooth, horizontal ramp. You give the pumpkin a good push, only to find yourself sliding backwards at a speed of 4.0 m/s. How far will the pumpkin slide 3.0 s after the push? Assume your mass to be 60.0 kg.
After pushing the pumpkin hard, you find yourself reversing direction at a speed of 4.0 m/s. 3.0 seconds after being pushed, the pumpkin will slide 12 m. Assume you weigh 60.0 kg.
We can use the conservation of momentum to solve this problem. After the push, the momentum of the system is given by:
p = (449 kg + 60 kg) * v
where v is the speed of the pumpkin and you after the push. Since you end up sliding backward at 4.0 m/s, we have:
v = -4.0 m/s
Substituting this into the expression for momentum, we find:
p = (449 kg + 60 kg) * (-4.0 m/s) = -2036 kg·m/s
The negative sign indicates that the momentum of the system is in the opposite direction of your motion.
During the sliding motion, the net force on the system is given by:
Fnet = (449 kg + 60 kg) * g * sin(θ)
where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of the ramp. Since the ramp is smooth and horizontal, θ = 0 and Fnet = 0. Therefore, there is no net force to change the momentum of the system.
Using the equation for motion with constant acceleration, we can find the distance the pumpkin slides in 3.0 seconds:
x = x0 + v0t + (1/2)at²
Since the initial speed of the pumpkin is -4.0 m/s and there is no net force acting on it, its speed remains constant during the slide. Therefore, v0 = -4.0 m/s and a = 0. Substituting these values, we find:
x = x0 + v0t = (-4.0 m/s) * (3.0 s) = -12 m
The negative sign indicates that the pumpkin slides in the opposite direction to your motion. Therefore, the pumpkin slides 12 meters backward (i.e., towards you) in 3.0 seconds after the push.
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For which of the following types of electromagnetic radiation will diffraction most likely occur as the wave passes through a classroom doorway? A) X-rays, because of their high energy. B) Visible light, because that type of electromagnetic radiation is most abundant. C) Radio waves, because of their wavelength. D) Diffraction will occur equally for all electromagnetic waves.
Option C, Because of the wavelength of radio waves and other forms of electromagnetic radiation, diffraction is most likely to occur as the wave travels through a classroom doorway.
Diffraction is the bending of waves around barriers or through apertures that are equivalent to or smaller than the wavelength of the wave.
Because radio waves have longer wavelengths than visible light and X-rays, they are more likely to diffract while passing through a similar-sized aperture, such as a classroom doorway.
Because X-rays have considerably shorter wavelengths and visible light has wavelengths in between, diffraction is less likely to occur in this scenario for these forms of electromagnetic energy. As a result, option C is the right answer.
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A typical atom has a diameter of about 1.0×10−10m.
Approximately how many atoms are there along a 2.0 −cm line?
Express your answer using two significant figures.
Answer:
10m
Explanation:
if it was at the 2.0 line it would be 10 m
If a typical atom has a diameter of about 1.0×10⁻¹⁰ m, then there are approximately atoms are there along a 2.0-centimeter line.
What are significant figures?In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.
As given in the problem If a typical atom has a diameter of about 1.0×10⁻¹⁰ m, then we have to find out approximately how many atoms are there along a 2.0-centimeter line,
diameter of the one atom = 1.0×10⁻¹⁰
approximate number of atoms in 2 cm line = 2 ×10⁻² /( 1.0×10⁻¹⁰ )
=2 ×10⁸ atoms
Thus, there are approximately 2 ×10⁸ atoms are there along a 2.0-centimeter line.
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Write a note on "Geology".
Answer:
the science that deals with the earth's physical structure and substance, its history, and the processes that act on it.
Explanation:
Hope that helps
An electric heater is madde of a wire of resistance 100π and connected to a 240v mains supply. Determine the power rating of the heater
Answer:
Power = 576 Watts
Explanation:
The electrical power of an electric circuit can be defined as a measure of the rate at which energy is either produced or absorbed in the circuit.
Mathematically, electrical power is given by the formula;
\( Electrical \; power = current * voltage \)
This ultimately implies that, the quantity (current times voltage ) is electrical power and it is measured (S.I units) in Watt (W).
Given the following data;
Resistance = 100 ohms
Voltage = 240 V
To find the power rating of the heater;
Power = V²/R
Where;
V is the voltage.
R is the resistance.
Substituting into the formula, we have;
Power = 240²/100
Power = 57600/100
Power = 576 Watts
Can you use an adjustable gas lift leg (Similar to office chair) on the moon?
Calculate the root mean square velocity of the nitrogen molecules, in meters per second (m/s). Do not include the unit of measure in your answer.
This question involves the concepts of average kinetic energy and velocity.
Complete question: Calculate the root mean square velocity of the nitrogen molecules, at 25°C, in meters per second (m/s). Do not include the unit of measure in your answer.
The root mean square velocity of the nitrogen molecule at 25°C is "727.66 m/s".
The average kinetic energy of gas molecules is given by the following formula:
\(K.E=\frac{3}{2}KT\)
Also,
\(K.E = \frac{1}{2}mv^2\)
Comparing both equations we get:
\(\frac{3}{2}KT=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{3KT}{m}}\)
where,
v = root men square velocity = ?
K = Boltzman's constant = 1.38 x 10⁻²³ J/k
T = absolute temperature = 25°C + 273 = 298 k
m = mass of nitrogen molecule = 2.33 x 10⁻²⁶ kg
Therefore,
\(v=\sqrt{\frac{3(1.38\ x\ 10^{-23}\ J/k)(298\ k)}{2.33\ x\ 10^{-26}\ kg}}\)
v = 727.66 m/s
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How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s
ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:
Impulse = Change in momentum
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity
In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.
Therefore, the change in momentum is given by:
Change in momentum = (mass × final velocity) - (mass × initial velocity)
Change in momentum = mass × (final velocity - initial velocity)
Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))
Change in momentum = 0.14 kg × (49 m/s + 32 m/s)
Change in momentum = 0.14 kg × 81 m/s
Change in momentum = 11.34 kg·m/s
So, the impulse imparted on the baseball is 11.34 kg·m/s.
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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Mrs. Archer spent her Saturday running a bunch of errands. She started out by
traveling 2 km east, then 5 km south, 12 km east, 2 km south then 40 km west, 60
km north. Calculate her displacement on the Y AXIS.
Answer:
Velocity = displacement/time whereas speed is distance/time. use the formula
Explanation:
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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Espresso is a coffee beverage made by forcing steam through finely ground coffee beans. Modern espresso makers generate steam at very high pressures and temperatures, but in this problem we'll consider a low-tech espresso machine that only generates steam at 100?C and atomospheric pressure--not much good for making your favorite coffee beverage.The amount of heat Q needed to turn a mass m of room temperature ( T1) water into steam at 100?C ( T2) can be found using the specific heat c of water and the heat of vaporization Hv of water at 1 atmosphere of pressure.Suppose that a commercial espresso machine in a coffee shop turns 1.50 kg of water at 22.0?C into steam at 100?C. If c=4187J/(kg??C) and Hv=2,258kJ/kg, how much heat Q is absorbed by the water from the heating resistor inside the machine?Assume that this is a closed and isolated system.Express your answer in joules to three significant figures.Q = _________________ J
Answer:
Q = 3877 KJ
Explanation:
Since, the system is closed and isolated. Therefore, the law of conservation of energy can be written as:
Heat Absorbed By Water (Q) = Heat required to raise the temperature of water (Q₁) + Heat required to convert water to steam (Q₂)
Q = Q₁ + Q₂ ----- equation (1)
Now, for Q₁:
Q₁ = m C ΔT
where,
m = Mass of Water = 1.5 kg
C = Specific Heat of Water = 4187 J/kg.°C
ΔT = Change in Temperature of Water = T₂ - T₁ = 100°C - 22°C = 78°C
Therefore,
Q₁ = (1.5 kg)(4187 J/kg.°C)(78°C)
Q₁ = 490 x 10³ J =490 KJ
Now, for Q₂:
Q₂ = m H
where,
m = Mass of Water = 1.5 kg
H = Heat of Vaporization of Water = 2258 KJ/kg
Therefore,
Q₂ = (1.5 kg)(2258 KJ/kg)
Q₂ = 3387 KJ
Substituting the values in equation (1), we get:
Q = Q₁ + Q₂
Q = 490 KJ + 3387 KJ
Q = 3877 KJ
how many pattern block hexagons would 2 trapezoids create
To make two hexagons out of pattern blocks, you need 12 trapezoids.
Explain about the term hexagons?A closed, two-dimensional polygon containing six sides is what is known as a hexagon. Six vertices and six angles make up a hexagon.
You need to utilize a total of 12 trapezoids to make two hexagons using pattern blocks. You will also need 2 hexagons to employ all twelve trapezoids because each hexagon has six trapezoids in it. Trapezoids can be arranged in a pattern with two triangles, 2 parallelograms, 2 rhombuses, and 2 trapezoids to create the two hexagons. These 12 trapezoids can be used to form two full hexagons.Thus,
You need 12 trapezoids to build two hexagons out of pattern blocks.Six trapezoids form each hexagon.Since you require two hexagons, a total of 12 trapezoids are required.To know more about the hexagons, here
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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I am ion with 17 protons, 18 neutrons, and 18
electrons. Who am I and what is my charge?
Element Name:
Symbol and Charge (include + or - sign)
Am I a Cation or Anion? Explain.
If I see H+1 (hydrogen ion, charge + 1), will i
bond with her? Explain your answer
Pls show work
Answer:
chloride, ion, -1, this is an anion
A spacecraft is traveling with a velocity of Vox-5690 m/s along the +x direction. Two engines are turned on for a time of 865 s. One
engine gives the spacecraft an acceleration in the +x direction of a, 1.45 m/s², while the other gives it an acceleration in the ty
direction of a, -8.66 m/s2. At the end of the firing, what is a) v, and b) vy?
(a) Number i
(b) Number
Units
Units
For a spacecraft is traveling with a velocity of Vox-5690 m/s:
(a) The final velocity (v) is approximately 685.25 m/s.(b) The vertical component of the velocity (vy) is -7484.9 m/s.How to calculate velocity and vertical component?To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.
Given:
Initial velocity in the x-direction (V₀ₓ) = -5690 m/s
Time of engine firing (t) = 865 s
Acceleration in the x-direction (ax) = 1.45 m/s²
Acceleration in the y-direction (ay) = -8.66 m/s²
(a) To calculate the final velocity (v), use the equation:
v = V₀ₓ + ax × t
Substituting the values:
v = -5690 m/s + 1.45 m/s² × 865 s
v = -5690 m/s + 1254.25 m/s
v ≈ 685.25 m/s
Therefore, the final velocity (v) is approximately 685.25 m/s.
(b) To calculate the vertical component of the velocity (vy), use the equation:
vy = ay × t
Substituting the values:
vy = -8.66 m/s² * 865 s
vy = -7484.9 m/s
Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.
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1. How would cosmologists describe the overall content of the universe? (1 point)
A. heterogeneous
B. isotropic
C. antimorphic
D. orthographic
A cosmologist would describe the overall content of the universe as isotropic. They study the Universe.
What is a cosmologist?A cosmologist is a professional aimed at understanding the nature and/or origin of the Universe.
Cosmologists can employ different devices to understand how the universe was formed (e.g., satellites).
The Universe can be considered isotropic because there is no specific center region in the Universe.
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