Answers
Answer:
Magnitude and a direction.
Explanation:
Vectors are arrows consisting of a magnitude and a direction. They are used in physics to represent physical quantities that also have both magnitude and directions.
Answer:
It consists of magnitude and direction
Explanation:
Although it has direction and magnitude it does not have position
Related Questions
Tired of being chased by a jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a
44.0 kg stone boulder off of the edge of a cliff that slopes down at an angle of 15.0°. Being weak with
hunger, the best you can do is push the boulder with a force of 222 N. The coefficient of kinetic friction
between the boulder and the ground is is 0.700. (Ignore static friction.)
What is the acceleration of the boulder while you push it down the incline?
Answers
Answer: acceleration = 3.27m/s^2
Explanation:
Given that the
Mass M = 44kg
Angle Ø = 15 degree
Coefficient of friction ų = 0.7
Force F = 222N
F - Fr = ma ...... (1)
Where Fr = frictional force
Fr = ųN
N = normal reaction = mg
Fr = ųmgsinØ
Fr = 0.7 × 44 × 9.81 × sin 15
Fr = 78.2N
Substitutes Fr, F and M into equation one.
222 - 78.2 = 44a
143.79 = 44a
Make a the subject of formula
a = 143.79/44
Acceleration a = 3.27 m/s^2
The impulse given to a body of mass 1.5 kg, is 6.0 kg
• m•s-?
If the body was initially at rest, what
will its resulting kinetic energy be? Give your answer in J without units.
Show work
Answers
Answer:
12J
Explanation:
Given parameters:
Mass = 1.5kg
Impulse = 6kgm/s
let us start first by find the velocity with which this body moves;
Impulse = mass x velocity
Velocity = Impulse / mass = 6/ 1.5 = 4m/s
Initial velocity = 0m/s
Unknown:
Resulting kinetic energy = ?
Solution:
To solve this problem use the formula below:
K.E = \(\frac{1}{2}\) m (v - u)²
m is the mass
v is the final velocity
u is the initial velocity
So;
K.E = \(\frac{1}{2}\) x 1.5 x (4 - 0)²
K.E = 1.5 x 8 = 12J
2(A + B)
15. The resultant of A and B is perpendicular to A
What is the angle between A and B?
(a) cos
(b) cos
La
(c) sin
(d) sin
Answers
Answer:
θ = cos^(-1) (-A/B)
Explanation:
The image of the reauktant forces A & B are missing, so i have attached it.
Now, from the attached image, we will see that;
Angle between A and B is θ
Also;
A = Bcos(180° − θ)
Now, in trigonometry, we know that;
cos(180° − θ) = -cosθ
Thus;
A = -Bcosθ
cosθ = -A/B
Thus;
θ = cos^(-1) (-A/B)
which statement about force is incorrect
Answers
Answer:
What are the options?
Explanation:
A 2kg rock is at the edge of a cliff 20m above the surface of a lake. It comes loose and falls. Half way down it is falling at 14 m/s. What is its Kinetic Energy at the half way point?
Please show work!
Answers
Answer:
196 Joules
Explanation:
kinetic energy = 1/2 * mass * velocity²
Given:
mass: 2 kgvelocity: 14 m/susing formulae:
\(\rightarrow \sf kinetic \ energy = \dfrac{1}{2} * 2 * 14^2\)
\(\rightarrow \sf kinetic \ energy = 196 \ J\)
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
Answers
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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Ms. Szorenyi bought an old string of holiday lights from a yard sale. They worked at first, but when she removed one of the lights they all went out! Ms. Szorenyi checked- it was not a short circuit.a) What type of circuit was used to wire the lights together?b) How should the lights be wired so the rest will stay on? Use circuit terminology to explain your solution and why it works.
Answers
For a light to glow, it must be part of a closed circuit.
When many lights are connected in a series circuit, removing one would cause the whole circuit to open:
If the lights were wired in a parallel circuit, then, removing one light won't cause the others to stop being part of a closed circuit:
Therefore, the answers are:
a) The lights were wired in a series circuit.
b) The lights should be wired in a parallel circuit. It works because each light is located in a different closed loop, while in a series circuit they are all in the same closed loop.
Which article has a more formal tone? Support your answer with details from both texts. From "The ever-changeing sky
Answers
The article "Sunrise, Sunset...or Not?" by ReadWorks has a more formal tone compared to "The Ever-Changing Sky" by Megan McGibney.
What is the formal tone about?In "Sunrise, Sunset...or Not?" the author uses scientific and technical terms such as "counterclockwise," "Arctic Circle," and "phenomenon," and provides a detailed explanation of the scientific reasoning behind the rising and setting of the sun.
In contrast, "The Ever-Changing Sky" by Megan McGibney has a more casual tone, using more colloquial language such as "clear day," "bright and shiny," and "People have always looked up at the sky with wonder." The author also uses phrases like "guess how long" and "right!" which implies that the author is addressing a less formal audience and is being conversational.
In all, "Sunrise, Sunset...or Not?" has a more formal tone because of its use of technical language, explanation of scientific concepts, and a generally informative and explanatory writing style.
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Sunrise, Sunset...or Not?
by ReadWorks
The sun is a wonderful thing for Earth. It is a star that heats the planet and makes life on
Earth possible. In addition, its light shines onto the planet. It is Earth's ultimate source of
energy.
Summer days may be longer than winter days, but for most people, the sun seems to do the
same thing each day: it appears to come up in the east for the day, and it appears to go down
in the west for the night. The sun looks like it rises in the east and sets in the west because of
how the earth spins in space. It spins toward the east, or counterclockwise. This means that
when most people look at the sky in the morning, the sun will first appear in the east.
The earth takes 24 hours to complete one turn. For most places on Earth, there is a daytime
and nighttime every 24 hours. But in some places for many days at a time, the sun might stay
up in the sky, or it might not even come up above the horizon.
In some parts of the world, the sun can be up in the sky for months. During part of the spring
and summer in Earth's Northern Hemisphere, the Northern Hemisphere is tilted towards the
sun so much that the sun in northern Alaska, which is located in the Arctic Circle, never goes
below the horizon. The Arctic Circle is an area at the top of the earth. In Barrow, Alaska, the
sun doesn't set for almost three months! This phenomenon is called the midnight sun, when
the sun has not set at midnight. Try sleeping through that!
During parts of the fall and winter in Earth's Northern Hemisphere, the Northern Hemisphere
is tilted in such a way that the sun doesn't come over the horizon in northern Alaska for a little
over two months. Therefore, nights last more than 24 hours. This phenomenon is called the
polar night. Although the sun never rises above the horizon during parts of the fall and winter
in the Arctic Circle, enough light often shines so that people who live there don't need
The Ever-Changing Sky
The Ever-Changing Sky
by Megan McGibney
Look up at the sky on a clear day. You will see the sun. It is bright and shiny, warming much of
what its light touches. Look up at the sky again at night. You may see the stars. They are also
bright and shiny, glimmering in the dark sky. You may also see the moon. It looks bright and
shiny, reflecting light from the sun. People have always looked up at the sky with wonder.
Some have even studied the sun, moon, and stars. These people, called astronomers, have
learned that those objects in the sky do not stay in the same place all the time.
The Ever-Changing Sky
extra quarter of a day.
Let's take a closer look at the moon. The earth does not revolve around the moon. Instead,
the moon revolves around the earth. It takes the moon about four weeks to complete a
revolution around the earth. The portion of the moon we, here on Earth, see changes over
this period of about four weeks as the moon's position around the earth changes. The
moonlight we see at night is the moon's reflection of sunlight onto Earth. The different ways
the moon appears to us are known as the moon's phases. The moon's phases depend on the
moon's position in relation to the earth and the sun.
The four-week period starts and ends with the new moon. The new moon cannot be seen
because the side of the moon lit by the sun is facing away from the earth.
Use the articles "The Ever-Changing Sky" and "Sunrise, Sunset...or Not?" to answer
questions 6.
6. Which article has a more formal tone? Support your answer with details from both texts.
Answers will vary.
Calculate the average speed of a complete round trip in which the outgoing 220 kmkm is covered at 92 km/hkm/h , followed by a 1.0-hh lunch break, and the return 220 kmkm is covered at 55 km/hkm/h . Express your answer to two significant figures and include the appropriate units.
Answers
Answer:
60 km/hr
Explanation:
220 km is covered at 92km/hr in the round trip
There is 1 hour lunch break
During the return of the round trip 220 km is covered at 55km/hr
The first step is to calculate the total distance
= 220km + 220km
= 440km
The time spent during the entire round trip can be calculated as follows
= (220/92) + 1 + (220/55)
= 2.3913 + 1 + 4
= 7.3913
Therefore the average speed can be calculated as follows
= distance/ time
= 440/7.3913
= 59.52
= 60km/hr (approximated to 2 significant figures)
Hence the average speed is 60 km/hr
Two horizontal forces act on an object. One force has a magnitude of 75.0 N and is directed due 30.0° south of east. The other force has a magnitude of 55.0 N and is directed due 70.0° north of west. What is the magnitude and direction of the sum of the two force vectors. Select one: 122.4 N, 43.2° north of east 130.0 N, 40.0° south of east 46.6 N, 17.1° south of east 48.3 N, 17.1° north of east 20.0 N, 40.0° north of east
Answers
Explanation:
70 degrees North of west = 110 degrees
30 degrees southof east = - 30 degrees:
Vertical components added together =
75 (sin -30) + 55 sin 110 = 14.18 N
Horizontal components added together =
75 cos (-30) + 55 cos 110 = 46.14 N
Magnitude = sqrt ( 14.18^2 + 46.14^2 ) = 48.3 N
direction = arctan ( 14.18 / 46.14) = ~ 17.1 North of East
Which best explains why making a pancake from batter is an example of a chemical change?
-The pancake that forms is a different state of matter.
-The change from batter to pancake can be reversed.
-A new substance forms when the batter is cooked.
-The batter changes shape when it is cooked.
Answers
The correct answer is C. A new substance forms when the batter is cooked.
Explanation:
When a chemical change occurs the properties, and composition of substances change. This means atoms in the substance re-arrange to form a new substance. This only occurs when there is a chemical change, but not when physical changes occur, indeed a physical change only affects the state of the matter, shape, size, etc.
In the case of the pancake, this is an example of a chemical change because though the process of cooking the pancake changes its composition. Due to this, the properties of the cooked pancake, and the butter are not the same as a new substance forms. Also, in this and most chemical changes, reversibility is not possible, that is why you cannot reverse the process and make the cooked pancake batter once again.
Answer:
C. on edge
Explanation:
An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object?
Answers
Answer:
0.5 kgExplanation:
The mass of the object can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{6}{12} = \frac{1}{2} \\ \)
We have the final answer as
0.5 kgHope this helps you
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?
Answers
Let the circumference of the circle be 10L.
A moves at 10L/2 = 5L per hour
B moves at 10L/5 = 2L per hour
Therefore it takes 10L/(5L+2L) = 10/7 hours
A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s. it strikes a second hockey puck with a mass 0.11 kg. the first hockey puck comes to rest after the collision. What is the velocity of the second hockey puck after the collision? ( Round your answer to the nearest integer.)
Answers
Answer:
\(v_2 = 23.182m/s\)
Explanation:
Given
\(m_1 = 0.17kg\)
\(m_2 = 0.11kg\)
\(u_1 = 15m/s\) -- Initial Velocity of the first
\(u_2 = 0m/s\) -- Initial Velocity of the second
\(v_1 = 0m/s\) -- Final Velocity of the first
Required
Determine the final velocity of the second hockey puck (\(v_2\))
This question illustrates law of conservation of momentum and it'll be solved using the following formula:
\(m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2\) ---- law of conservation of momentum
Substitute in the right values
\(0.17 * 15 + 0.11*0 = 0.17 * 0 + 0.11*v_2\)
\(0.17 * 15 + 0 = 0 + 0.11*v_2\)
\(2.55 = 0.11*v_2\)
Solve for v2
\(v_2 = 2.55/0.11\)
\(v_2 = 23.182m/s\)
Hence, the final velocity of the second hockey puck is 23.182m/s
as of 2019 south african runner, wayse Van niekerk holds the world record in 400 m he was able.to maintain an average speed of 9.3 m/s how long did it take him to run the 400 meters
Answers
43 seconds
Lmk for explanation
Hope this helps
An electron remains suspended between the
surface of the Earth (assumed neutral) and a
fixed positive point charge, at a distance of
6.08 m from the point charge.
Determine the charge required for this to
happen. The acceleration due to gravity
is 9.8 m/s
2
and the Coulomb constant is
8.98755 × 109 N · m2
/C
2
.
Answer in units of C.
Answers
The charge required for the fixed point charge is approximately \(4.8032 * 10^{-10} C\).
The electrostatic force between the fixed point charge and the electron is equal in magnitude to the gravitational force between the electron and the Earth, so we can set these two forces equal to each other and solve for the charge of the fixed point charge.
Electrostatic force between two point charges is given by Coulomb's law:
\(F = k * q1 * q2 / r^2\)
The gravitational force between two masses is given by Newton's law of gravitation:
\(F = G * m1 * m2 / r^2\)
Setting these two forces equal to each other and solving for q2, we get:
\(k * q1 * q2 / r^2 = G * m_e * m\_earth / r^2\)
Solving for q2, we get:
\(q2 = G * m_e * m\_earth / k\)
Substituting the given values, we get:
\(q2 = (6.67430 * 10^{-11} N * m^2 / kg^2) *\\ (9.10938356 *10^{-31} kg) *\\ (5.9722 *10^{24} kg) / (8.98755 * 10^9 N * m^2 / C^2)\)
\(q2 = 4.8032 * 10^{-10} C\)
Therefore, the charge required for the fixed point charge is approximately \(4.8032 * 10^{-10}\)C.
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How much kinetic energy does a 4kg cat have while running at 9 m/s
Answers
Answer:
How much kinetic energy does a 4 Kg cat have while running at 9 m/s?
its 5 J of kinetic energy.
Explanation:
Answer:
162 joules
Explanation:
Kinetic Energy = 1/2 * m * v^2
= 1/2 * 4 * 9^2 = 162 joules
To convert a Galvanometer of internal resistance RG = 200 2 into Ammeter a small resistance connected in parallel with the Galvanometer using a wire of resistance per length equal (2000/km). If the maximum current can be measured by the constructed Ammeter is 10A, assuming that the maximum current sustained by the Galvanometer is equal 0.8 mA. What is the length of the wire used to build up this ammeter?
Answers
To convert a galvanometer into an ammeter, a parallel resistance is added. With the given values, the resistance of the wire used to build the ammeter is 8 Ω/km, resulting in a wire length of 4 meters.
A galvanometer is an instrument that is used to detect and measure small amounts of electric current. It has a high resistance, which means that it only allows a small amount of current to flow through it. To convert a galvanometer into an ammeter, a small resistance is connected in parallel with the galvanometer. This reduces the overall resistance of the circuit, allowing more current to flow through it. The internal resistance of the galvanometer is given as RG = 200 Ω. Let the resistance of the wire used to build the ammeter be R. The maximum current that can be measured by the constructed ammeter is 10 A, and the maximum current sustained by the galvanometer is 0.8 mA.Using Kirchhoff's laws, we can find the total resistance of the circuit. Let this be RT: RT = RG + R, where RG is the internal resistance of the galvanometer and R is the resistance of the wire used to build the ammeter. Substituting the given values: RT = 200 Ω + R. The current through the ammeter is given by: I = V/RT, where V is the voltage across the circuit. Since the voltage is constant, we can write I = k/RT, where k is a constant.The maximum current that can be measured by the ammeter is 10 A. Substituting this value into the equation above 10 = k/(200 + R). The maximum current sustained by the galvanometer is 0.8 mA. This means that the total current through the circuit is 0.8 mA + I, where I is the current through the ammeter. Substituting the values into the equation above: 0.8 mA + k/RT = 10 mA, simplifying, we get k/RT = 9.2 mA.Substituting this value into the equation we derived earlier: 10 = (9.2 mA)/(200 Ω + R). Solving for R, we get R = 8 Ω/km. The resistance per unit length of the wire is given as 2000 Ω/km. Therefore, the length of the wire used to build the ammeter is given by:L = R/2000 = 8/2000 km = 4 m.For more such questions on ammeter:
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an immersion heater rated 2.0A,240V is used to boil water from temperature 52°c to hundred°c. if the mass of the water is 2.5kg, determine the time taken to boil water
Answers
Answer:
1.05 x 103s
Explanation:
The answer to the question is 1.05 x 103s
A sports car with a mass of 2000 kg travels at a velocity of 20 m/s. What would be true of its momentum if the same sports car was traveling at a velocity of 40 m/s?
Answers
The true statement about the sports car is that the momentum of the sports car would be increased.
What is momentum?The term momentum is defined as the product of the mass and the velocity. The momentum of an object is a vector quantity. What it means is that both the magnitude and the direction of the momentum is important.
Now we are told that the sports car has a mass of 2000 kg travels at a velocity of 20 m/s. The momentum at this point is 40000 Kgm/s. If the velocity of the sports car was increased to 40 m/s, the momentum would increase to 80,000 Kgm/s.
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choose inertial frames. check all that apply. choose inertial frames.check all that apply. a carousel rotates at a constant speed. a vertically tossed ball is at the highest point of its trajectory. a plane moves at a constant speed of 254 m/s . at the instant the traffic light turns green, a bus starts from rest
Answers
The highest point in a ball's trajectory is when it is thrown vertically. The average speed of a plane is 254 m/s/s. A carousel rotates continuously.
What is the unit for speed?seconds per metre Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation.
Who defined speed?Galileo Galilei, an Italian physicist, is typically attributed with being the first to quantify speed by taking into account the distance travelled and the time required. Galileo defined speed as the amount of distance travelled in a given amount of time.
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I'm not quite sure how the formula works. I thought it was
55*6*9.81 = N
Weight * acceleration * gravity = N
My answer was wrong. Could anyone help me understand this question, please?
"When landing after a spectacular somersault, a 55.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the force (in N) she must exert if her deceleration is 6.00 times the acceleration of gravity."
Answers
Answer:
See the explanation below.
Explanation:
Of course yes, after my explanation you will understand very well how to analyze this type of problems.
First, we must differentiate the weight of the mass, the mass has units of kilograms or pounds, while the weight is the product of the mass by gravitational acceleration. In this way, we have the following formula for the weight of anybody.
w = m*g
where:
w = weight [N] (units of Newtons]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
When we have the product of these units [kg]*[m/s²], We are always going to get as a result the units of Newtons [N], The Newton is a unit of force.
Now, to solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = forces acting over the gymnast [N]
m = mass = 55 [kg]
a = desacceleration = 6*9.81 = 58.86 [m/²]
Now we have two forces acting over the gymnast the first one is his or her weight (the mass by the gravity acceleration) and the second force is the one made it by his or her legs upwards in order to be standing. Let's take as positive signs the movements and forces upwards and negative downwards
- (m*g) + Fl = m*a
where:
Fl = force made it by the legs [N]
As the deceleration is upward because it prevents the person from continuing to go down, it is taken as a positive sign.
- (55*9.81) + Fl = (55*58.86)
Fl = (55*58.86) + (55*9.81)
Fl = 3776.85 [N]
I hope you can understand :)
26) After a skiing accident, your leg is in a cast and sup-ported in a traction device, as shown in FIGURE 6-43. Find the magnitude of the force F> exerted by the leg on the small pulley. (By Newton's third law, the small pulley exerts an equal and opposite force on the leg.) Let the mass m be 2.27 kg.
Answers
Explanation
Step 1
free body diagram
Step 2
now, let's analyze the forces
a) in y
Newton's first law says that if the net force on an object is zero ( Σ F = 0 \Sigma F=0 ΣF=0\Sigma, F, equals, 0)
so, as the leg is in rest
\(\begin{gathered} \sum ^{\square}_{\text{ y}}=_{}0 \\ T_1\sin 30-T_2sen\text{ 30=0} \end{gathered}\)let
m= 2.27 Kg , so
\(\begin{gathered} \text{weigth}=m\cdot g \\ \text{weigth}=2.27\operatorname{kg}\cdot9.81m/s^2 \\ \text{weigth}=22.2687\text{ N} \end{gathered}\)hence
\(\begin{gathered} T_2=weigth \\ T_2=22.2687 \end{gathered}\)\(\begin{gathered} T_1\sin 30-T_2sen\text{ 30=0} \\ T_1\sin 30-(22.2687)sen\text{ 30=0} \\ T_1\sin 30-(22.2687)sen\text{ 30=0} \\ T_1\sin 30-11.13435=0 \\ \text{add}11.13435\text{ in both sides} \\ T_1\sin 30-11.13435+11.13435=0+11.13435 \\ T_1\sin 30=11.13435 \\ \text{divide both sides by sin 30} \\ \frac{T_1\sin30}{\sin\text{ 30}}=\frac{11.13435}{\sin \text{ 30}} \\ T_1=22.2687\text{ Newtons} \end{gathered}\)b) now in x ( horizontally)
\(\begin{gathered} \sum ^{\square}_{\text{ x}}=_{}0 \\ -F+T_1cos30+T_2cos\text{ 30=0} \\ \text{add F in both sides} \\ -F+T_1cos30+T_2cos\text{ 30+F=0}+F \\ F=T_1cos30+T_2cos\text{ 30} \\ \text{replace} \\ F=(22.2687)cos30+(22.2687)_{}cos\text{ 30} \\ F=38.57\text{ Newtons} \end{gathered}\)therefore, the answer is
\(F=38.57\text{ Newtons to the left}\)I hope this helps you
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. What is the beaver’s mass?
Answers
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).
KE = (1/2) ×m × \(v^2\).
where m= mass of the object, v=its velocity.
The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation
45 J = (1/2) ×m × \((2.0 m/s)^2\)
Simplifying this equation:
45 J = (1/2) × m × 4.0\(m^2/s^2\)
45 J = 2 m × 2 \(m^2/s^2\)
45 J = 4 \(m^3/s^2\)
\(m^3\) = 45 J / 4 \(s^2\)
\(m^3\) = 11.25 kg×\(m^2/s^2\)
Taking the cube root of both sides to solve for mass,
m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)
m = 1.74 kg (rounded to two decimal places)
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what is the force acting in one direction called?
Answers
A net force can act in the same direction as that of the current velocity of the object, in which case it will not change the direction in which the object moves.
Emory pushes the box with 20 Newtons of force. If the box is 4kg, how fast will the box accelerate?
Answers
20N=4kg.a
a=5 N/kg
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
Answers
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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Marcie shovels snow after a storm by exerting a force of 30.0 N on her shovelat an angle of 60.0° to the vertical. What are the horizontal and verticalcomponents of the force exerted by Marcie?
Answers
Given:
Force = 30.0 N
θ = 60 degrees to the vertical.
Let's find the horizontal and vertical components of the force exerted by Marcie.
Let's first sketch a free body diagram.
• Horizontal Component:
To find the horizontal component, apply the formula:
\(\begin{gathered} sin\theta=\frac{F_x}{30} \\ \\ F_x=30sin60 \\ \\ F_x=25.98\text{ N} \end{gathered}\)Therefore, the horizontal component of the force is 25.98 N.
• Vertical Component:
To find the vertical component of the force, apply the formula:
\(\begin{gathered} cos\theta=\frac{F_y}{30} \\ \\ F_y=30cos\theta \\ \\ F_y=30cos60 \\ \\ F_y=15\text{ N} \end{gathered}\)Therefore, the vertical component of the force is 15 N.
ANSWER:
• Horizontal component = 25.98 N
,• Vertical component = 15 N
