What does it mean when 6 people share 12 muffins

The tip of the minute hand on a clock travels approximately 26.4 cm in 11 minutes if the minute hand is 23 cm long.

What is Circle?

A circle is a two-dimensional geometric shape that is defined as the set of all points in a plane that are a fixed distance away from a given point, called the center of the circle. This distance is known as the radius of the circle.

A circle can also be defined as the locus of a point that moves in a plane in such a way that its distance from a fixed point is constant. The constant distance is the radius of the circle.

The minute hand on a clock makes a full rotation in 60 minutes, which means it travels the circumference of a circle with a radius of 23 cm in 60 minutes. The formula for the circumference of a circle is C = 2πr, where r is the radius of the circle, and π is a mathematical constant approximately equal to 3.14.

Therefore, the circumference of the circle traced by the tip of the minute hand is:

C = 2πr = 2 × 3.14 × 23 cm ≈ 144.44 cm

To find out how far the minute hand travels in 11 minutes, we need to calculate what fraction of the circumference it covers in that time. Since 11 minutes is about 18.3% of an hour (60 minutes), the minute hand travels 18.3% of the circumference of the circle in that time:

Distance traveled = 0.183 × 144.44 cm ≈ 26.4 cm

Therefore, the tip of the minute hand on a clock travels approximately 26.4 cm in 11 minutes if the minute hand is 23 cm long.

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The type directions that lie in the (110) plane are Crystal planes are equivalent planes that represent a group of crystal planes with a common set of atomic indexes.

Crystallographers use Miller indices to identify crystallographic planes. A crystal is a three-dimensional structure with a repeating pattern of atoms or ions.In a crystal, planes of atoms, ions, or molecules are stacked in a consistent, repeating pattern. Miller indices are a mathematical way of representing these crystal planes.

Miller indices are the inverses of the fractional intercepts of a crystal plane on the three axes of a Cartesian coordinate system.Let us now determine which of the type directions lie in the (110) plane.[101] is not in the (110) plane because it has an x-intercept of 1, a y-intercept of 0, and a z-intercept of 1. So, this direction does not lie in the (110) plane.[110] is in the (110) plane since it has an x-intercept of 1, a y-intercept of 1, and a z-intercept of 0.

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Answer:

NOT

Step-by-step explanation:

Rational.

Round it...

-0.25

Turn it into a fraction...

-25/100.

It can be a fraction. Thus, it is rational.

Answer:

5x = 2y

Step-by-step explanation:

Answer:

40 mph

Step-by-step explanation:

convert the time into hours only:  2 hours 27 mins = 2 + 27/60 = 2.45 hours

98 / 2.45 = 40 mph

Answer:

-6.67

Step-by-step explanation:

3x(3+12=3)-4

3x(15=3)-4

3x(15/-3)-4

3x(-5)-4

3x(20)

x=20/-3

x= -6.67

Answer:

Step-by-step explanation:

See image

Answer:

Step-by-step explanation:

answer is b

Answer:

1.4

Step-by-step explanation:

We need to convert 103/7497 into a percentage.

All we have to do is multiply the fraction by 100:

103/7497 * 100 = 1.37

To one decimal place, the equivalent fraction is 1.4

Answer: x = 2/3, -2

Step-by-step explanation:

First factor the equation into (3x-2)(x+2)=0.  Thus, because one of the terms must be 0, x = 2/3, -2.

Hope it helps, and if you want help on how to factor quadratic expressions, just ask <3

Answer:

Step-by-step explanation: F 50.9 cm (H 25.7 cm. G 46.3 cm. -38.3 cm. G 46.3 cm. 921.3 cm. Ø 12.6em Å ... Р. 3 - с. 2, +6:48 348 р. 8. Find the distance between P(2, 8) and Q15, 3). F9 ... REVIEW VOCABULARY!!!!! R=0 tre of the two angles. Atab=180. 2 ДО - Чx 49.

Answer:

$1.25

Step-by-step explanation:

Subtract $0.25 by $1.50

$1.50-$0.25=$1.25

Answer: 6 foot

Step-by-step explanation:

You want to use the equation

5(n)

n will be 0.20 since the tree grew by 20% of its original height

5(0.20)=1

Now add 1 with 5

1+5

6

Answer:

6.0 ft

Step-by-step explanation:

20% of 5.0 ft is 1.0 so you add,   1.0ft+5.0ft=6.0ft

If derivative of \(f(x)=ln(x+4+e^{(-3x)})\), then f '(0) = -2/5.

What is derivative?

In calculus, the derivative of a function is a measure of how the function changes as its input changes. More specifically, the derivative of a function at a certain point is the instantaneous rate of change of the function at that point.

To find f'(0), we first need to find the derivative of f(x) with respect to x. Using the chain rule, we get:

\(f'(x) = 1 / (x+4+e^{(-3x)}) * (1 - 3e^{(-3x)})\)

Now we can find f'(0) by substituting the value x=0:

\(f'(0) = 1 / (0+4+e^{(-3(0))}) * (1 - 3e^{(-3(0))})\)

f'(0) = 1 / (4+1) * (1 - 3)

f'(0) = -2/5

Therefore, f'(0) = -2/5.

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Answer:there were 100 adults  and 350 children tickets sold .

Step-by-step explanation:

Step 1

let number of adult tickets sold be represented as  x

and that of children be  y

such that the total number of adult and children who attended the center will be expressed as

x+ y = 450------equation 1

 and the total cost of tickets sold can be expressed as

4x+ 1.50 y= 925,...equation 2

Step 2--Solving

x+ y = 450------eqn1

4x+ 1.50 y= 925,...eqn 2

 By elimination method , Multiply equation 1  by 4 and subtract equation 2 from  the new equation  formed

4x+ 4y= 1800 ----- eqn 3

-4x+ 1.50 y= 925 eqn 2

2.5y=875

y= 875/2.5

y=350

to fnd x

x+ y= 450

x= 450- 350

x= 100

Therefore there were 100 adults  and 350 children tickets sold .

The interval of convergence is [-1/4, 1/4]. The interval of convergence is [3, 5].

To find the radius of convergence, we use the ratio test:

\(lim_n→∞ |(4(n+1)/(n+1)^2) / (4n/n^2)| = lim_n→∞ |(4n^2)/(n+1)^2| = 4\)

Since the limit exists and is finite, the series converges for |x| < R, where R = 1/4. To find the interval of convergence, we test the endpoints:

x = -1/4: The series becomes

\([∞] (-1)^n/(n^2)\)

n=1

which converges by the alternating series test.

x = 1/4: The series becomes

\([∞] 1/n^2\)

n=1

which converges by the p-series test. Therefore, the interval of convergence is [-1/4, 1/4].

To find the radius of convergence, we use the ratio test:

\(lim_n→∞ |((x-4)(n+1)^7 / (n+1)^8) / ((x-4)n^7 / n^8)| = lim_n→∞ |(x-4)(n+1)/n|^7 = |x-4|\)

Since the limit exists and is finite, the series converges for |x-4| < R, where R = 1. To find the interval of convergence, we test the endpoints:

x = 3: The series becomes

[∞] 1/n^8

n=0

which converges by the p-series test.

x = 5: The series becomes

\([∞] 1/n^8\)

n=0

which converges by the p-series test. Therefore, the interval of convergence is [3, 5].

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An airline has a requirement that the total outside dimensions (length, width, and height) of a checked bag not exceed 73 inches. You want to check a bag with a height equal to its width. To find the largest volume bag of this shape that you can check, we will use the constraint provided and optimize the volume.

Let L, W, and H represent the length, width, and height of the bag, respectively. According to the constraint, L + W + H ≤ 73 inches. Since H = W, we can rewrite the constraint as L + 2W ≤ 73.

The volume (V) of the bag can be represented as V = L × W × H. Substituting H = W, we get V = L × W². To maximize the volume, we need to rewrite this equation in terms of one variable. Using the constraint, we can express L as L = 73 - 2W. Now, substitute this into the volume equation: V = (73 - 2W) × W².

To find the maximum volume, we can use calculus or simply observe that the function V(W) is a downward-opening parabolic function. The maximum volume occurs at the vertex, which is found at the W-coordinate W = -b/2a in the general quadratic equation f(x) = ax^2 + bx + c. In our case, a = -2, b = 73, so W = 73/(2×-2) = 18.25 inches.

an airline requires that the total outside dimensions (length width height) of a checked bag not exceed 73 inches. suppose you want to check a bag whose height equals its width, Now that we have W, we can find H (which is equal to W) and L. H = 18.25 inches, and L = 73 - 2(18.25) = 36.5 inches. Thus, the largest volume bag you can check is V = 36.5 × 18.25² ≈ 12,104.16 cubic inches (rounded to two decimal places).

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Answer:

Mr. A initially paid approximately N8000 for the land.

Step-by-step explanation:

Step 1: Let's assume Mr. A initially purchased the land for a certain amount, which we'll call "x" in currency units.

Step 2: Mr. A sold the land to Mr. B at a profit of 10%. This means Mr. A sold the land for 110% of the amount he paid (1 + 10/100 = 1.10). Therefore, Mr. A received 1.10x currency units from Mr. B.

Step 3: Mr. B sold the land to Mr. C at a gain of 5%. This means Mr. B sold the land for 105% of the amount he paid (1 + 5/100 = 1.05). Therefore, Mr. B received 1.05 * (1.10x) currency units from Mr. C.

Step 4: According to the given information, Mr. C paid N1240 more for the land than Mr. A paid. This means the difference between what Mr. C paid and what Mr. A paid is N1240. So we have the equation: 1.05 * (1.10x) - x = N1240

Step 5: Simplifying the equation: 1.155x - x = N1240

Step 6: Solving for x: 0.155x = N1240

x = N1240 / 0.155

x ≈ N8000

Therefore, in conclusion, Mr. A initially paid approximately N8000 for the land.

Answer:

3x16

Answer to the equation:

48

Step-by-step explanation:

The probability corresponding to this value is approximately 0.9798. P(X < 5) = P(Z < 2.042) ≈ 0.9798.

To find the probability P(X < 5) using the standard normal variable Z, we need to standardize X by subtracting the mean and dividing by the standard deviation.

Given that X is a normal random variable with a mean of -0.4 and a variance of 7, we can calculate the standard deviation (σ) by taking the square root of the variance.

σ = sqrt(7) ≈ 2.6458

To standardize X, we use the formula:

Z = (X - μ) / σ

For X < 5, we substitute X = 5 into the formula:

Z = (5 - (-0.4)) / 2.6458

Z = 5.4 / 2.6458

Z ≈ 2.042

Now, we need to find the probability P(Z < 2.042) using the standard normal distribution table or a calculator.

Looking up the value of 2.042 in the standard normal distribution table, we find that the probability corresponding to this value is approximately 0.9798.

Therefore, P(X < 5) = P(Z < 2.042) ≈ 0.9798.

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We can choose any value of h, since the value of h does not affect whether the system has a solution or not.

This problem involves finding values of the variables h and k for which a system of linear equations has no solution. Specifically, we are given two equations in the variables x and y, and we want to find values of h and k such that these equations cannot be satisfied simultaneously for any values of x and y.

To solve this problem, we can use the fact that a system of linear equations has no solution if and only if the coefficients of one variable in each equation are proportional but the coefficients of the other variable are not proportional.

We can write the given equations in the form Ax + By = C and Dx + Ey = F, where A = -9, B = 8, C = h, D = -4, E = k, and F = -6.

Then we have: The coefficients of x are A = -9 and D = -4, which are not proportional. The coefficients of y are B = 8 and E = k, which are proportional if and only if k = 8B/ E = 64/ E.

Therefore, the system has no solution if and only if k = 64/ E for some value of E that is not equal to 0. This means that we can choose any nonzero value of E, and then set k = 64/ E to get a value of k that makes the system unsolvable.

For any value of k that is not equal to 64/ E, the system will have a unique solution.

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Answer:

Step-by-step explanation:

So your code has to pass the test

(check-equal? (sieve 10) (list 2 3 5 7))

This means, first, that (sieve 10) must be a valid call, and second, that it must return (list 2 3 5 7), the list of primes up to 10. 10 is a number,

(define (sieve n)

... so what do we have at our disposal? We have a number, n which can be e.g. 10; we also have (sieve-with divisors lst), which removes from lst all numbers divisible by any of the numbers in divisors. So we can use that:

   (sieve-with (divisors-to n)

               (list-from-to 2 n)))

list-from-to is easy to write, but what about divisors-to? Before we can try implementing it, we need to see how this all works together, to better get the picture of what's going on. In pseudocode,

(sieve n)

=

 (sieve-with (divisors-to n)

             (list-from-to 2 n))

=

 (sieve-with [d1 d2 ... dk]

             [2 3 ... n])

=

 (foldl (lambda (d acc) (drop-divisible d acc))

        [2 3 ... n]  [d1 d2 ... dk])

=

 (drop-divisible dk

   (...

     (drop-divisible d2

       (drop-divisible d1 [2 3 ... n]))...))

So evidently, we can just

(define (divisors-to n)

 (list-from-to 2 (- n 1)))

and be done with it.

But it won't be as efficient as it can be. Only the prime numbers being used as the divisors should be enough. And how can we get a list of prime numbers? Why, the function sieve is doing exactly that:

(define (divisors-to n)

 (sieve (- n 1)))

Would this really be more efficient though, as we've intended, or less efficient? Much, much, much less efficient?......

But is (- n 1) the right limit to use here? Do we really need to test 100 by 97, or is testing just by 7 enough (because 11 * 11 > 100)?

And will fixing this issue also make it efficient indeed, as we've intended?......

So then, we must really have

(define (divisors-to n)

 (sieve (the-right-limit n)))

;; and, again,

(define (sieve n)

   (sieve-with (divisors-to n)

               (list-from-to 2 n)))

So sieve calls divisors-to which calls sieve ... we have a vicious circle on our hands. The way to break it is to add some base case. The lists with upper limit below 4 already contain no composite numbers, namely, it's either (), (2), or (2 3), so no divisors are needed to handle those lists, and (sieve-with '() lst) correctly returns lst anyway:

(define (divisors-to n)

 (if (< n 4)

   '()

   (sieve (the-right-limit n))))

And defining the-right-limit and list-from-to should be straightforward enough.

So then, as requested, the test case of 10 proceeds as follows:

(divisors-to 10)

=

 (sieve 3)   ; 3*3 <= 10, 4*4 > 10

=

 (sieve-with (divisors-to 3)

             (list-from-to 2 3))

=

 (sieve-with '()          ; 3 < 4

             (list 2 3))

=

 (list 2 3)

and, further,

(sieve 100)

=

 (sieve-with (divisors-to 100)

             (list-from-to 2 100))

=

 (sieve-with (sieve 10)  ; 10*10 <= 10, 11*11 > 10

             (list-from-to 2 100))

=

 (sieve-with (sieve-with (divisors-to 10)

                         (list-from-to 2 10))

             (list-from-to 2 100))

=

 (sieve-with (sieve-with (list 2 3)

                         (list-from-to 2 10))

             (list-from-to 2 100))

=

 (sieve-with (drop-divisible 3

               (drop-divisible 2

                         (list-from-to 2 10)))

             (list-from-to 2 100))

=

 (sieve-with (drop-divisible 3

                         (list 2 3 5 7 9))

             (list-from-to 2 100))

=

 (sieve-with (list 2 3 5 7)

             (list-from-to 2 100))

just as we wanted.

Answer:

-10* F

Step-by-step explanation:

What confuses me is that the answers you have provided aren't correct, when I made a number line starting at 0 and ending at -23* F and I had counted three degrees for each hour I got -10* F.

   2am     3am      4am       5am

0 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -12 -13 -14 -15 -16 -17 -18 -19 -20 -21 -22 -23

2am is at -1* F, 3am is at -4* F, 4am is at -7* F, and 5am is at -10* F.

This is over the course of three hours after 2am so unless I got this wrong you might want to ask your teacher.

Answer: -10 degrees

None of those 4 choices are correct

the researcher investigated the relationship between the independent variable "amount of alcohol" and the dependent variable "braking speed at a simulated red light" in the study.

The independent variable in this study is the "amount of alcohol." Specifically, the researcher manipulated the alcohol intake by assigning participants to one of two groups: one group received one ounce of alcohol, while the other group received three ounces of alcohol. The amount of alcohol consumed is the independent variable because it is controlled and manipulated by the researcher.

The dependent variable in this study is "braking speed at a simulated red light." The researcher measured the participants' reaction time in the driving simulation task by assessing their braking speed when faced with a simulated red light. The dependent variable is the outcome that is expected to be influenced by the independent variable (amount of alcohol), and it is measured to examine the relationship between the two variables.

Therefore, the researcher investigated the relationship between the independent variable "amount of alcohol" and the dependent variable "braking speed at a simulated red light" in the study.

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Angle:

In Euclidean geometry, an angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays.

Angles are also formed by the intersection of two planes.

These are called dihedral angles.

We can name an angle in the following ways :

i) An angle can be named by its label, in the interior of the angle.

ii) It can also be named by just its vertex.

iii) By the degree the two intersecting lines make.

To name the angle with 3 letters, use a point on each ray of the angle, and list the letters with the angle's vertex in the middle.

The angle's name can then be ∠S, ∠RST, ∠TSR, or ∠1.

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The amount of storage required to represent a simple graph with n vertices and m edges can vary depending on the chosen representation. Here's the storage requirement for each representation:

a) Adjacency lists:

In an adjacency list representation, we typically use an array of size n to store the vertices, and for each vertex, we maintain a linked list or an array to store its adjacent vertices. The space complexity of this representation is O(n + m), where n is the number of vertices and m is the number of edges.

Each vertex requires constant space, and each edge is represented by a link or entry in the adjacency list.

b) Adjacency matrix:

In an adjacency matrix representation, we use a 2D matrix of size n x n to represent the graph. Each entry (i, j) in the matrix represents whether there is an edge between vertices i and j. The space complexity of this representation is O(n^2), as we need to store n^2 entries for the complete matrix. However, if the graph is sparse (few edges compared to vertices), the space complexity can be reduced to O(n + m) by only storing the entries corresponding to the existing edges.

c) Incidence matrix:

In an incidence matrix representation, we use a 2D matrix of size n x m, where n is the number of vertices and m is the number of edges. Each entry (i, j) in the matrix represents whether vertex i is incident to edge j. The space complexity of this representation is O(n * m), as we need to store n * m entries for the matrix.

Similar to the adjacency matrix, if the graph is sparse, the space complexity can be reduced to O(n + m) by storing only the entries corresponding to the existing edges.

In summary:

a) Adjacency lists: O(n + m)

b) Adjacency matrix: O(n^2) or O(n + m) for sparse graphs

c) Incidence matrix: O(n * m) or O(n + m) for sparse graphs

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Answer:

the answer is an outlier