what does the cwd and commit tree look like if we run gitlet checkout 39 -- game.txt?

Answer: true

Explanation:

Answer:

b. The universe may continue to expand.

Explanation:

The most supported theory about the future of the universe is that, it may continue to expand up to such point that it will become too cold to allow any forms of life to pull through. This is popularly known as the "Big Freeze."

Such  acceleration of expansion is caused by the so-called, "dark energy." This also explains why the acceleration of expansion is not constant. This thereby causes the distance between galaxies to grow farther apart.

Answer:

b

Explanation:

edge 2021

The Mo-99 activity produced in 10 days Irradiation is 2.40599 × 10³² disintegrations.

The given data is as follows: Intensity of Neutrons: 4.18×10¹⁷ neutron/sec

Energy of Neutrons: 0.1 eV

Sphere shell of Uranium-235 Density of Uranium-235: 19 g/cm³

Inner radius: 10 cm

Outer radius: 12 cm

Duration of Irradiation: 10 days

1. Calculation of Mo-99 activity in 10 days Irradiation:

Using the FLUKA code, the Mo-99 activity in 10 days Irradiation can be calculated.

2. Calculation of Mo-99 activity in 10 days Irradiation:

Considering the yield of Mo-99 is 0.062 per fission, and fission is 2.09 fission/primary neutron.

Therefore, the number of Mo-99 produced per neutron can be calculated as follows:

Number of Mo-99 produced per primary neutron = Yield of Mo-99 × Fission per primary neutron= 0.062 × 2.09 = 0.12958

Therefore, the activity of Mo-99 produced per primary neutron can be calculated as follows:

Activity of Mo-99 produced per primary neutron= (Number of Mo-99 produced per primary neutron) × (Disintegration rate of Mo-99)= 0.12958 × 1.44 × 10⁶= 1.8656 × 10⁵ disintegrations/sec

Now, the intensity of neutron is 4.18 × 10¹⁷ neutron/sec.

Hence, the number of neutron will be:

N = Intensity of neutron × Time= 4.18 × 10¹⁷ × 10 × 24 × 3600= 1.284288 × 10²⁴

The total number of Mo-99 produced in the given duration can be calculated by the following formula:

Number of Mo-99 produced in the given duration= (Number of Mo-99 produced per primary neutron) × (Number of primary neutron)× (Duration of Irradiation)= 0.12958 × 1.284288 × 10²⁴ × 10= 1.66992 × 10²⁶

The total activity of Mo-99 produced in 10 days Irradiation can be calculated by the following formula:

Activity of Mo-99 produced in 10 days Irradiation= (Number of Mo-99 produced in the given duration) × (Disintegration rate of Mo-99)= 1.66992 × 10²⁶ × 1.44 × 10⁶= 2.40599 × 10³² disintegrations.

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Regenerative braking is a type of braking that occurs when the electric motor reverses its current flow to act as a generator, converting the kinetic energy of the moving vehicle back into electrical energy.

Electric motors are devices that convert electrical energy into mechanical energy. They are frequently used to power a variety of devices, such as industrial equipment, electric vehicles, and even household appliances like washing machines and vacuum cleaners.Braking in electric motors is a crucial function that is required to ensure safe operation of the motor. In this context, regenerative braking and dynamic braking are the two main types of braking used in electric motors.

This energy is then stored in the vehicle's battery or another type of energy storage system. Regenerative braking is commonly used in electric and hybrid vehicles as well as in other electric motor applications that require braking.

Dynamic braking, on the other hand, is a type of braking that uses resistance to slow down the electric motor. This is accomplished by diverting the motor's current away from the motor and into a resistor bank, which then dissipates the energy as heat. Dynamic braking is frequently used in industrial applications where safety is a major concern. It's also used in traction applications for trains, subways, and other forms of transportation.

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Answer:

I believe it is B

Explanation:I say this because agriculture means the science or practice of farming, including cultivation of the soil for the growing of crops and the rearing of animals to provide food, wool, and other products so I am sure that an agri scientist is the same thing.

In the code every instance of ex'am is replace with ex(at)m to comply with asked policies. Please replaceall back to get correct output.

In computer programming, computer code is a set of instructions or a set of rules written in a specific programming language (i.e., the source code). It is also the name given to source code after it has been compiled and is ready to run on a computer.

It is also the name given to source code after it has been compiled and is ready to run on a computer (i.e., the object code).

Code is heavily used for innovative concepts such as artificial intelligence and machine learning, in addition to building computer programs and mobile applications. Of course, there are several other applications and uses for the word code, which are discussed in the following section.

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Answer:a

Ieieksdjd snsnsnsnsksks

In Stokes flow, the fluid velocity is proportional to the forces acting on the fluid and the fluid is assumed to be viscous and incompressible. The fluid velocity near a rotating sphere in Stokes flow can be determined using the equations of fluid dynamics.

Kinematic reversibility is a property of Stokes flow, which states that the fluid flow is symmetric with respect to time reversal. This means that if the fluid velocity is recorded at a certain time, then the same velocity field will be obtained if time is reversed and the flow is replayed in the reverse direction.

When a sphere is rotating near a wall, the flow of fluid around the sphere creates a velocity field that pushes the sphere away from the wall. This flow can be considered as the fluid being pushed away from the sphere and towards the wall. If the flow is time-reversed, the fluid velocity field would be the same, but the direction of the velocity would be reversed. This means that the fluid would be drawn towards the sphere and away from the wall, pulling the sphere towards the wall.

Therefore, based on the property of kinematic reversibility in Stokes flow, the rotating sphere near a wall will experience a force that could either push it away from the wall or draw it towards the wall, depending on the direction of the flow.

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Technician A is wrong.

Technician B is right.

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When going down a long downgrade, snubbing the brakes is not an acceptable method of slowing down. The process of snubbing the brakes means that the driver touches the brakes for a few seconds before releasing them and allowing the vehicle to gain speed again.

Braking in this manner generates excessive heat and can cause the brake system to overheat and fail. Snubbing the brakes should be avoided at all costs because it places a significant strain on the brake system. Using the engine to help control speed is a safer method of descent control. To properly use the brakes when descending a long downgrade, one must select an appropriate gear before beginning the descent, use the brake pedals lightly and briefly to achieve the desired speed, and then release the pedals and rely on the engine brake for the rest of the descent. If the vehicle gains too much speed, the brake pedal should be used in brief, steady applications to slow it down to the desired speed. When driving, the driver should always be aware of their surroundings and be prepared to use the brakes in the event of an emergency.

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The part of a drill that holds the drill bit in place is called the chuck.

The chuck is a key component of a drill, as it securely holds the drill bit in place during operation. It is typically located at the end of the drill, and can be opened and closed to insert or remove the drill bit.

The chuck is usually operated by either a key or a lever, depending on the type of drill. It is important to make sure that the chuck is properly tightened when the drill bit is inserted, as this will ensure that the bit is secure and will not slip or come loose during drilling.

Additionally, it is important to make sure that the bit is compatible with the size of the chuck, as an improper fit could cause the bit to become stuck or damaged.

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From England, a musician takes a plane to Canada, where the electricity is 120 volts. On 240 volts, her amplifier runs. She uses a step-down transformer with 300 turns on the primary coil so she can utilize her amp.

The secondary coil has 600 turns as well. An electronic device that can boost a signal's power is known as an amplifier, electronic amplifier, or (informally) an amp (a time-varying voltage or current). The amplitude is increased via a two-port electronic circuit using electric power from a power source. Electric potential difference between two sites is referred to as voltage, also known as electric pressure, electric tension, or (electric) potential difference. It relates to the work required per unit of charge in a static electric field.

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True, one way to distribute a document is to post it on cloud storage such as SkyDrive (now known as OneDrive). This allows for easy sharing and access by multiple users.

Cloud storage refers to the online storage of data on remote servers that are accessed through the internet. This type of storage provides users with a convenient and flexible way to store and access their data from anywhere with an internet connection.

Cloud storage services typically offer a range of storage plans with varying amounts of storage capacity, and users can choose a plan that best suits their needs. Some of the key benefits of using cloud storage include:

Accessibility: Data stored in the cloud can be accessed from anywhere with an internet connection, making it a convenient option for people who need to access their data on the go.

Scalability: Cloud storage services offer a scalable solution, allowing users to easily upgrade or downgrade their storage capacity as their needs change.

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Answer: on two sides (one on either 88-inch side and one on either 108-inch side)

Explanation: Ensure the scaled weight is clearly marked on two sides (one on either 88-inch side and one on either 108-inch side) of the 463L pallet. Pallet weight markings (Figure D-7) may be stapled to the net.

The scale weight of a pallet should be clearly marked on the side of the pallet. A pallet is a flat transport structure that is designed to support goods while they are being lifted by a forklift, pallet jack, or other jacking device.

The goods are usually placed on top of a pallet and secured with strapping, stretch wrap, or shrink wrap to keep them from falling during transportation. The scale weight of a pallet should be clearly marked on the side of the pallet. The purpose of marking the weight is to avoid overweighting the pallet, which can result in serious injury to workers or damage to the goods. The scale weight of a pallet should be clearly marked on the side of the pallet, to avoid overweighting the pallet, which can result in serious injury to workers or damage to the goods.

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Answer:

1. False

2. True

3. True

4. True

5. False

Explanation:

Moment of a force is not a free vector. There are certain quantities along the line with which force is applied.

Force can be moved in any direction along the line of the action without changing the external reaction.

The magnitude of equivalent resultant force is distributed along the centroid point.

The resultant force of a couple force system is zero as it form opposite forces which balances off each other.

Design of a straightforward algorithm that runs in O(n2) for this: The algorithm for finding if a pair with a given sum exists in a sorted array.

Set the input array and a given target value as Ai and v, respectively. Iterate over the input array Ai with a nested loop. For each element ai in the input array Ai, traverse Ai[i+1] to Ai[n-1] and see if any element adds up to the given target value v.

If the sum of Ai[i] and Ai[j] is equal to the given target value v, then return true.

Otherwise, move on to the next element of Ai. If no element is found that sums to the given target value v, return false. The time complexity of the straightforward algorithm is O(n^2) since it has two nested loops to search the array for elements with a sum equal to the given target value

This is a recursive algorithm based on a divide-and-conquer technique that runs in O(n log n) time complexity. It is based on the idea of dividing the input array into two halves and comparing the sum of the left and right indices of the middle element with the target value.

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Answer:

YES

Explanation:

NO

;-;

Answer:

length of tube = 4.12 m

Explanation:

Given data:

flow rate of engine oil = 1 kg/s

diameter of tube = 5-mm

inlet temperature of oil = 45°C

exit temperature of oil = 80°C

surface temperature of tube = 150°C

Determine the required length of the tube

attached below is a detailed solution to the given problem

length of tube = 4.12 m

To create an FSM (Finite State Machine) diagram for the given requirements, we can describe it using states, transitions, and actions.

States:

Idle

Wait_for_5

Wait_for_10

Wtime

Transitions:

The sequence begins at the "Idle" state, then transitions to "Wait_for_10" via pathway A. Afterwards, pathway B takes the transmission to "Wtime," which brings it back to "Idle" through C and ultimately advances to "Wait_for_5." The final pathway is A taking "Wait_for_5" to lead to "Wtime."

The system begins in the Idle state, awaiting money from the user. If the individual inserts 5 pounds (A), this action prompts a transition to the Wait_for_10 state. Assuming that the user then places another 5 pounds whilst within the Wait_for_10 state (A), the apparatus changes over to the Wtime state, subsequently doling-out the product 30 seconds later(C)(D).

Alternatively, if the consumer introduces 10 pounds when they are in the Wait_for_10 state(B), the machine will refund them with ten pounds(F), transporting them back to the Idle state.

If the customer presents £10 in the idle means(B), thee operation switches to the Wait_for_5 status, during which entrance of another£10 causes a shift to the time phase, resulting in the boat being dispatched after waiting for seconds (C)(D).

Moreover, if an individual gives away 5 pounds within the Wait_for_5 stage(A), the appliance changeover to the Wtime condition and transmits out the manufactured article 30 seconds later(C)(D). Ultimately, if 30 seconds elapse while in the Wtime stage without placing the remaining sumof money as stipulated by dispensation rules,the machine returns fivepounds in a refund(E) before restarting itself at the theIdlestate.

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Order the parts needed is NOT a duty of the General Service Technician.

General service technicians are knowledgeable workers who are in charge of carrying out repair tasks on cars and other light vehicles. Customers must interact with these specialists in order to discuss pricing estimates for undertaking car maintenance services. They are required to undertake any required repairs or part replacements as well as visual vehicle inspections. They must possess the necessary skills to operate equipment that mounts and balances vehicle tyres. General service personnel should be able to install car batteries and inspect the electrical systems of vehicles.

Therefore, order the parts needed is NOT a duty of the General Service Technician.

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Answer:

the perimeter of a square room is 48m. what is the area of the room? What cost will incur if the rate of carpeting the room is Rs. 10 per m square

Note that the magnitude of the flux of momentum in the gap is 3.34 Pa and the momentum is being transported in the opposite direction of the shaft's motion.

To determine the intensity of shear of an oil with viscosity of 0.1 Pa.s, we can use the formula:

τ = μ × (2πN/60) × (r₁ - r₂) / h

Where:

τ = intensity of shear

μ = viscosity of oil = 0.1 Pa.s

N = rotational speed of shaft = 150 rpm

r₁ = radius of shaft = 10/2 = 5 cm

r₂ = radius of bearing = (10+0.15)/2 = 5.075 cm

h = clearance = 1.5 mm = 0.15 cm

Plugging in the values:

τ = 0.1 × (2π × 150/60) × (5 - 5.075) / 0.15

τ = -3.34 Pa

The negative sign indicates that the shear stress is in the opposite direction of the motion of the shaft. Therefore, the magnitude of the flux of momentum in the gap is 3.34 Pa and the momentum is being transported in the opposite direction of the shaft's motion.

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Answer:

i think D

Explanation:

Undulations in the bottom surface of a soft rubber layer under its own gravitational force can be explained qualitatively based on energy minimization, where the undulations reduce the gravitational potential energy of the layer.

When a soft rubber layer is under its own gravitational force, it deforms and experiences stress due to the weight of the material. According to the neo-Hookean model, the stress state in the rubber layer can be calculated based on the strain energy density function. The undulation on the bottom surface of the rubber layer can be explained based on energy minimization. The deformation of the rubber layer under gravity induces a curvature on the surface of the layer, which increases the strain energy of the material. The undulation phenomenon occurs due to the elastic instability of the material, where the elastic energy of the material is reduced by forming a pattern of wrinkles on the surface. This phenomenon is a result of the balance between the elastic energy and gravitational potential energy in the rubber layer.

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A 28 degrees F temperature differential between the interior supply and return air in a heat pump in the cooling mode is normal and does not raise any concerns.

In the cooling mode of a heat pump, a temperature differential is measured between the interior supply and return air. In this case, a 28 degrees F temperature differential is observed. This temperature difference indicates that the heat pump is functioning properly and efficiently.
A heat pump works by transferring heat from one place to another. In the cooling mode, it extracts heat from the indoor air and transfers it outside. The temperature differential between the supply and return air indicates how effectively the heat is being removed from the indoor space.
A temperature differential of 28 degrees F is considered within the normal range for a heat pump in the cooling mode. It suggests that the heat pump is operating efficiently and effectively removing heat from the indoor air.
Therefore, based on the information provided, there is no need to suspect any issues or malfunctions with the heat pump. The measured temperature differential indicates that the heat pump is performing its cooling function properly.
In summary, a 28 degrees F temperature differential between the interior supply and return air in a heat pump in the cooling mode is normal and does not raise any concerns.

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Answer:

a. Compromise the fire rating by one hour.

Explanation:

One hour fire rating is given to materials that can resist the fire exposure. The Acoustical panels controls reverberation and they are used for echo controls. The Fire rating is the passive fire protection which can resist standard fire. The test for fire rating also consider normal functioning of the material.

To determine the drag on a flat plate under different conditions, we need to consider the drag coefficient and the reference area. The drag coefficient depends on the flow regime (laminar or turbulent) and can be approximated using different correlations.

Drag at U: 0.664 * ρ * U^2 * l^2

Drag at 2U: 2.656 * ρ * U^2 * l^2

Drag at U/2: 0.166 * ρ * U^2 * l^2

For a flat plate with a laminar boundary layer, we can use the following relationships:

Drag coefficient for laminar flow on a flat plate:

Cd = (1.328 / sqrt(Re)) * (2l/b)

where Re is the Reynolds number, given by Re = (ρU l) / μ, with ρ being the density, U the velocity, l the length of the plate, and μ the dynamic viscosity.

Reference area:

The reference area, denoted as A, is the projected area of the plate perpendicular to the flow. For a flat plate, A = l * b.

Now, we can calculate the drag for different velocities:

Upstream velocity U:

Drag = 0.5 * Cd * ρ * U^2 * A

= 0.5 * [(1.328 / sqrt(Re)) * (2l/b)] * ρ * U^2 * l * b

= 0.664 * ρ * U^2 * l^2

Upstream velocity 2U:

Drag = 0.5 * Cd * ρ * (2U)^2 * A

= 0.5 * [(1.328 / sqrt(Re))] * ρ * (2U)^2 * l * b

= 2.656 * ρ * U^2 * l^2

Upstream velocity U/2:

Drag = 0.5 * Cd * ρ * (U/2)^2 * A

= 0.5 * [(1.328 / sqrt(Re))] * ρ * (U/2)^2 * l * b

= 0.166 * ρ * U^2 * l^2

Therefore, the drag on the flat plate when the upstream velocity is U, 2U, and U/2 can be expressed as:

Drag at U: 0.664 * ρ * U^2 * l^2

Drag at 2U: 2.656 * ρ * U^2 * l^2

Drag at U/2: 0.166 * ρ * U^2 * l^2

Please note that these calculations assume laminar flow and neglect any other external factors that may affect the drag on the plate.

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