what ethical issues must be addressed before posting exploit code in an online exploit database?

Answer:

  radiative heat loss substantially increases as the wall temperature declines

Explanation:

The body's heat loss due to convection is ...

  (2 W/m^2·K)((32 -20)K) = 24 W/m^2

__

The body's heat loss due to radiation in the summer is ...

  \(\epsilon\sigma(T_b^4-T_w^4)\quad\text{where $T_b$ and $T_w$ are body and wall temperatures ($^\circ$K)}\\\\0.90\cdot 5.6703\cdot 10^{-8}(305.15^4-300.15^4)\,\text{W/m$^2$}\\\\\approx 28.3\,\text{W/m$^2$}\)

The corresponding heat loss in the winter is ...

  \(0.90\cdot 5.6703\cdot 10^{-8}(305.15^4-287.15^4)\,\text{W/m$^2$}\\\\\approx 95.5\,\text{W/m$^2$}\)

Then the total of body heat losses to surroundings from convection and radiation are ...

  summer: 24 +28.3 = 52.3 . . . W/m^2

  winter: 24 +95.5 = 119.5 . . . W/m^2

__

It is reasonable that a person would feel chilled in the winter due to the additional radiative loss to the walls in the winter time. Total heat loss is more than doubled as the wall temperature declines.

The non-linearity error as a percentage of the full-scale reading at 100 degree C  is - 0.89%.

Non-linearity error is defined as the biggest deviation from a straight line linking the output signal to the applied force, known as the "best straight," that the calibration curve makes. In order to eliminate second order nonlinearity, the sensor signal conditioning system feeds a portion of the output signal back to the sensor.

If EMF and Celsius temperature have a proportional relationship, then the recorded value of EMF at 100 °C will be understood to be a temperature of.

T/5.268 = 400/21.846

T = 5.268(400/21.846) ≈ 96.457 °C

As a percentage of the full scale, the mistake is

(96.457 -100)/400 × 100% ≈ -0.886%

Thus, the non-linearity error as a percentage of the full-scale reading at 100 degree C  is - 0.89%.

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The above-stated example appears to meet all the criteria for being objective. An objective is a goal, target, or aim. An objective provides you with an understanding of what you must accomplish, measure, or do to accomplish a task.

It enables you to concentrate your energies and abilities and chart a course of action to attain the desired result or outcome. An objective is measurable and achievable within a given time frame.The above-stated example of a multiple-choice test appears to meet all the criteria for being an objective. It is applicable to almost any cognitive learning situation. It comprises a clear and concise statement of the desired result or outcome. It is measurable since it defines the precise outcome required, which is to achieve a score of at least nine out of ten correct. The objective is achievable within a given time frame since the test-taker has to complete the test and achieve the stated score.

It is applicable to almost any cognitive learning situation. It comprises a clear and concise statement of the desired result or outcome. It is measurable since it defines the precise outcome required, which is to achieve a score of at least nine out of ten correct. The objective is achievable within a given time frame since the test-taker has to complete the test and achieve the stated score.The example demonstrates a precise and specific outcome that can be measured, making it a well-defined objective. The objective does not include any value judgments or subjective opinions.

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The ways that burton could improve the process of producing snowboards, as well as their operations and their logistics systems are; Explained below

For burton to improve their competitive advantage, they can adopt various business methods to improve their performance as follows;

Logistics and supply chain management are very important factors that can be used to improve upon the competitiveness of business. Thus, snowboards flow should be well managed to gain improvement in efficiency and effectiveness of delivery which will ensure patronage of prospective customers.

Logistics systems perform various operations that leads to the competitive advantage I spoke about earlier. Finally, the production department should ensure that they produce quality products such that customers are motivated to repurchase.

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You add up the individual resistances to determine the total overall resistance of several resistors connected in this manner.The formula used for this is as follows:Total R = R1 plus R2 plus R3 and so on

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Answer:

Explanation:

Given that:

f = 250 Hz

\(\delta\)= 2%

\(f_n\)= 600 Hz

\(\zeta\) = 0.5 to 1.5  increment by 0.05

\(F = A sin (Xt)\)

For 250 Hz = 250 cycle/sec

\(X = 2 \pi t 250\)

\(X = 500 \pi t\)

\(X = Asin (500 \pi t)\)

\(\omega = 250 \\ \\ \omega_n = 600\)

M = 0.98 , 1.02

\(M_{(w)}} = \sqrt{[1-(\frac{w}{w_n})^2 + ( 2\zeta \frac{w}{w_n})^2}\)

\(\frac{1}{M} = [1-(\frac{w}{w_n})^2]+(2 \zeta \frac{w}{w_n})^2\)

\(\zeta = \frac{w_n}{2w}\sqrt{\frac{1}{M^2}-(1-(\frac{w}{w_n})^2)^2}\)

\(\zeta = \frac{600}{2(250)}\sqrt{\frac{1}{0.98^2}-(1-(\frac{250}{600})^2)^2}\)

\(\zeta = 0.7183\)

At 0.7183 value of damping ratio the error value was 2% at 0.98 value of M

\(\frac{1}{M} = [1-(\frac{w}{w_n})^2]+(2 \zeta \frac{w}{w_n})^2\)

\(\zeta = \frac{w_n}{2w}\sqrt{\frac{1}{M^2}-(1-(\frac{w}{w_n})^2)^2}\)

\(\zeta = \frac{600}{2(250)}\sqrt{\frac{1}{1.02^2}-(1-(\frac{250}{600})^2)^2}\)

\(\zeta = 0.6330\)

At  0.6330 value of damping ratio the error value was 2% at 1.02 value of M.

Hence, the damping ratio \(\zeta\) of the transducer must be placed between 0.6330 to 0.7183

The creative process that helps you overcome writer's block is called Reset.

Thus, could be the answer.

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is called ecoines

Explanation:

Answer:

the welding gun liner regulates the shielding gas.

Explanation:

The purpose of the welding gun liner is to properly position the welding wire from the wire feeder till it gets to the nozzle or contact tip of the gun. Regulation of the shielding gas depends on factors such as the speed, current, and type of gas being used. In gas metal arc welding, an electric arc is used to generate heat which melts both the electrode and the workpiece or base metal.

The electric arc produced is shielded from contamination by the shielding gas. The heat generated by the short electric arc is low.

Answer:

Alvaro designs machinery and equipment for ships. His job title is best described as Marine Engineer.

Jeanette draws maps and plans for freeway projects. Her job title is best described as Civil Drafter.

Joseph designs a new airport. His job title is best described as Transportation Engineer.

Geraldine designs imaging systems that use light. Her job title is best described as Photonics Engineer.

Hope this helps sorry I am late to respond, but anyone else who needs the answer it is here.

Based on the above, Alvaro is a Marine Engineer;

Machinery and Equipment are known to be a type of industrial tools, devices, and items that aids facilities.

Conclusively, They are said to be tangible personal property that are used as a tool for repair parts, etc. Professions in ship jobs includes, Marine Engineer, Photonics Engineer, etc.

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This statement is generally true. In most cases, waste piping is designed to connect to drain piping on the outlet side of traps or at other designated locations in drainage piping.

Traps are important components of plumbing systems that are designed to prevent the flow of sewer gases, insects, and other pests from entering a building through the plumbing system. They are typically installed in waste piping near the fixture that they serve, such as a sink, toilet, or shower.

The waste piping that connects to these fixtures typically leads to the inlet side of the trap, which is designed to hold a small amount of water that forms a seal to prevent sewer gases from entering the building. From there, the drain piping usually connects to the outlet side of the trap, allowing waste water to flow out of the building and into the sewer or septic system.

There may be some exceptions to this general rule, depending on the specific design of the plumbing system and local building codes. In some cases, for example, a waste line may be connected directly to a building's vent stack to improve drainage and prevent the buildup of gases. However, these types of configurations are typically designed and installed by licensed plumbers or other qualified professionals who are familiar with local plumbing codes and best practices.

In summary, while there may be some variations in the design and configuration of waste and drain piping in different plumbing systems, it is generally true that waste piping connects to drain piping on the outlet side of traps or at other designated locations in drainage piping.

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Answer:

speed(0)

square_length = int(input("What is the length of the square?"))

def draw_square():

   pendown()

   for i in range(4):

       forward(square_length)

       left(90)

   penup()

penup()

setposition(-200, -200)

draw_square()

penup()

setposition(-200, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, -200)

draw_square()Explanation:

a. The 26th percentile of the software engineering manager salaries is approximately $111,417.

b. The 97.5th percentile of the software engineering manager salaries is approximately $171,417. The z-score for a salary of $170,000 is approximately 2.910, indicating that it is not considered an outlier based on the given standard deviation.

a. The 26th percentile can be found using the Empirical Rule. According to the Empirical Rule, in a mound-shaped and symmetric distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations. Since we know the mean base salary is $126,417 and the standard deviation is $15,000, we can calculate the value of the 26th percentile as follows:

First, calculate one standard deviation below the mean:

$126,417 - $15,000 = $111,417

Since the distribution is symmetric, the 26th percentile will be the same as the 74th percentile, which is one standard deviation below the mean. Therefore, the 26th percentile is approximately $111,417.

b. The 97.5th percentile can also be determined using the Empirical Rule. In this case, since 99.7% of the data falls within three standard deviations of the mean, we can calculate the value of the 97.5th percentile as follows:

First, calculate three standard deviations above the mean:

$126,417 + (3 * $15,000) = $171,417

Therefore, the 97.5th percentile is approximately $171,417.

c. To find the z-score for a salary of $170,000, we can use the formula:

z = (x - μ) / σ

Where x is the given salary, μ is the mean, and σ is the standard deviation. Plugging in the values:

z = ($170,000 - $126,417) / $15,000 ≈ 2.910

A z-score of 2.910 indicates that the salary of $170,000 is approximately 2.910 standard deviations above the mean. It is not considered an outlier based on the z-score alone. Typically, an outlier is defined as a data point that falls outside a certain range, often determined by a specified number of standard deviations from the mean. In this case, whether $170,000 is considered an outlier would depend on the specific criteria or threshold set for defining outliers.

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Answer:

the types of social responsibility are as follows

1)Environmental Responsibility

2)Ethical Responsibility

3)Philanthropic Responsibility

4)Economic Responsibility

Social responsibility is an obligation every person has to do to uphold a balance among the economy as well as the environment. Social responsibility refers to maintain the balance between the environment and the budget.

It affects not only corporate governments but also everybody whose activity impacts the climate.

The Social responsibility towards the environment are as follows

1)Defend the environment, create balanced use of natural ingredients, and take important steps to stop pollution from the several processes adopted by the industries.

2)Encourage the viable use of raw resources and natural materials. Introduce strategies for continuously enlightening our environmental duty.

Introduce rules for continuous development in their ecological performance.

Obey with the law in force on conservational protection, and with other willingly recognized promises.

3)To encourage, by on-the-job practice, the participation of all our workers, independently and based on the team, in environmental safety problems.

4)To unite with the liable Agencies as well as Governmental Authorities.

To proceed with environmental protection courses.

5)To talk and report on our eco-friendly management struggles.

Implement and sustain the necessities of a Chain of Custody.

6)Stop trade and acquisition of illegally obtained wood.

7)Apply and continue a due industry system to avoid the acquisition and sale of criminally harvested timber and its products.

The final ArrayUtil class should look like this:

```java
public class ArrayUtil {

   public static String[] resize(String[] array) {
       String[] resizedArray = new String[array.length * 2];
       for (int i = 0; i < array.length; i++) {
           resizedArray[i] = array[i];
       }
       return resizedArray;
   }
}
```
The Step-by-step explanation for implementing a resize method in your ArrayUtil class for resizing an array of Strings:

1. Create a new class called ArrayUtil, if it's not already created.

2. Add the following method signature to the class:

```java
public static String[] resize(String[] array)
```

3. Inside the resize method, determine the length of the original array by using the `array.length` property.

4. Create a new array, called `resizedArray`, with double the length of the original array:

```java
String[] resizedArray = new String[array.length * 2];
```

5. Copy the elements from the original array to the new resized array using a loop:

```java
for (int i = 0; i < array.length; i++) {
   resizedArray[i] = array[i];
}
```

6. Return the resized array:

```java
return resizedArray;
```
Note that there is no main method or input/output handling in the ArrayUtil class, as the instructions specified that it will be accessed by an external Java application. The class simply contains the resize method for resizing an array of Strings.

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Answer:

pakipic na lang po question nyo para masagot po

Explanation:

please po di ko masyado gets po e

it is simple the title name after all it is just asking your name

Answer:

b in the answer

hope it helps u mark me BRAINLIST

This question is incomplete, the missing diagram is uploaded along this answer below.

Answer:

- The mass flow rate of air is 4.59 kg/s

- Area of the exit turbine is 0.066 m²

Explanation:

 Given the data in the question;

Using air as an ideal gas.

Turbine;

state 1: p₁ = 8 bar, T₁ = 960 K

state 2: p₂ = 1 bar, T₂ = 450 K

The inlet velocity is small compared to the exit velocity of 90 m/s

V₁ < V₂ = 90 m/s

Power of turbine W' = 2500 kW

Now, lets assume Q = 0 and ΔPE = 0

we know that; R = 0.2870 kJ/kg-K

Also. \(C_p\) at 700K = 1.075 kJ/kg-K

Now, using ideal gas law;

STATE1

v₁ = RT₁/p₁

so we substitute

v₁ = [(0.2870 kJ/kg-K)(960 K)/(8 bars )]|\(\frac{bar}{10^5N/m^2}\)||\(\frac{1000N.m}{kJ}\)| =  0.344 m³/kg

STATE2

v₂ = RT₂/p₁

we substitute

v₂ = [(0.2870 kJ/kg-K)(450 K)/(1 bars )]|\(\frac{bar}{10^5N/m^2}\)||\(\frac{1000N.m}{kJ}\)| =  1.2915 m³/kg

Now, from energy balance steady state;

0 = Q" - W" + \(m"_i\)( \(h_i\) + \(\frac{V_i^2}{2}\) + \(gz_i\)) - \(m"_B\)( \(h_B\) + \(\frac{V_B^2}{2}\) + \(gz_B\))

since we initially assume Q = 0 and ΔPE = 0

hence;

0 = \(-\frac{W"}{m"}\) + h₁ + \(\frac{V_1^2}{2}\) -  h₂ + \(\frac{V_2^2}{2}\)

\(\frac{W"}{m"}\) = h₁ + \(\frac{V_1^2}{2}\) -  h₂ + \(\frac{V_2^2}{2}\)

⇒  \(\frac{W"}{m"}\) = \(C_p\)(T₁ - T₂) + \(\frac{1}{2}\)( V₁² - V₂²)

we solve for m"

m" = W" / (\(C_p\)(T₁ - T₂) + \(\frac{1}{2}\)( V₁² - V₂²))

so we substitute;

m" = {[2500 kW] / [(1.075kJ/kg-K(960K - 450k) + \(\frac{1}{2}\)( (0)² - (90 m/s)²)) |kJ/1000N.m| |N/kg.m/s²|]} | kJ/s / kW|

m" = 4.59 kg/s

Therefore, the mass flow rate of air is 4.59 kg/s

From the mass body steady state;

0 = m"₁ - m"₂

so

m"₁ = m"₂ = 4.59 kg/s

now, the volumetric flow rate V"₂ will be;

V"₂ = m" × v₂

we  substitute

V"₂ =  4.59 kg/s × 1.2915 m³/kg = 5.93 m³/s

and

the volumetric flow rate V"₂ = A₂V₂

so;

Exit Area A = V"₂ / V₂

we substitute

A = (5.93 m³/s ) / (90 m/s)

A = 0.06589 ≈ 0.066 m²

Therefore, Area of the exit turbine is 0.066 m²

Answer:

Explanation:

Given that:

diameter = 100 mm

initial temperature = 500 ° C

Conventional coefficient = 500 W/m^2 K

length  = 1 m

We obtain the following data from the tables A-1;

For the stainless steel of the rod \(\overline T = 548 \ K\)

\(\rho = 7900 \ kg/m^3\)

\(K = 19.0 \ W/mk \\ \\ C_p = 545 \ J/kg.K\)

\(\alpha = 4.40 \times 10^{-6} \ m^2/s \\ \\ B_i = \dfrac{h(\rho/4)}{K} \\ \\ =0.657\)

Here, we can't apply the lumped capacitance method, since Bi > 0.1

\(\theta_o = \dfrac{T_o-T_{\infty}}{T_i -T_\infty}} \\ \\ \theta_o = \dfrac{50-30}{500 -30}} \\ \\ \theta_o = 0.0426\\\)

\(0.0426 = c_1 \ exp (- E^2_1 F_o_)\\ \\ \\ 0.0426 = 1.1382 \ exp (-10.9287)^2 \ f_o \\ \\ = f_o = \dfrac{In(0.0374)}{0.863} \\ \\ f_o = 3.81\)

\(t_f = \dfrac{f_o r^2}{\alpha} \\ \\ t_f = \dfrac{3.81 \times (0.05)^2}{4.40 \times 10^{-6}} \\ \\ t_f= 2162.5 \\ \\ t_f = 36 mins\)

However, on a single rod, the energy extracted is:

\(\theta = pcv (T_i - T_{\infty} )(1 - \dfrac{2 \theta}{c} J_1 (\zeta) ) \\ \\ = 7900 \\times 546 \times 0.007854 \times (500 -300) (1 - \dfrac{2 \times 0.0426}{1.3643}) \\ \\ \theta = 1.54 \times 10^7 \ J\)

Hence, for centerline temperature at 50 °C;

The surface temperature is:

\(T(r_o,t) = T_{\infty} +(T_1 -T_{\infty}) \theta_o \ J_o(\zeta_1) \\ \\ = 30 + (500-30) \times 0.0426 \times 0.5386 \\ \\ \mathbf{T(r_o,t) = 41.69 ^0 \ C}\)

Answer:

I HAVE NO CLUEEEE

Explanation:

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Answer:

I think its B

Explanation:

Im sorry if im wrong

The bending moments for the rectangular solid are:

a) M = 256,000 in-lb

b) M = 227,730 in-lb

a) To calculate the allowable bending moment for a solid rectangular timber beam, we can use the formula below:

M = (allowable stress)*(section modulus)

where M is the allowable bending moment and the section modulus is a measure of the beam's resistance to bending.

For a solid rectangular beam with nominal dimensions of 6 inches by 16 inches, the section modulus can be calculated as:

S = (b*h²) / 6

where b is the width of the beam and h is the height.

Substituting the values, we get:

S = (6*6²) / 6

S = 256 in³

Now, we can calculate the allowable bending moment as:

M = (allowable stress)*(section modulus)

M = 1000 psi*256 in³

M = 256,000 in-lb

Therefore, the allowable bending moment for the timber beam with nominal dimensions is 256,000 in-lb.

(b) For dressed dimensions, we need to adjust the section modulus calculation by subtracting the amount of wood that is removed during the dressing process. Assuming that the dressing process removes 1/8 inch from each side, the width and height of the dressed beam would be 5 3/4 inches and 15 1/2 inches, respectively.

Using these dimensions, the section modulus can be calculated exactly like above, but just with the different numbers:

S = (b*h²) / 6

S = (5.75*15.5²) / 6

S = 227.73 in³

Now replace that in the formula

M = 1000 psi x 227.73 in³

M = 227,730 in-lb

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The force reaction at support C is -24 kip (downward). Reactions at Support A: -13.5 kip (upward). Reactions at Support B: 27 kip (upward). Reactions at Support C: -24 kip (downward)

To determine the reactions at supports A, B, and C in the given structure, we need to analyze the equilibrium of forces and moments.

Given:

P = 13.5 kip (applied load)

EI is constant (flexural rigidity of the beam)

Force unit: kip (kips)

Distance unit: ft (feet)

Part A: Reactions at Support A

To find the force reaction at support A, we need to consider the equilibrium of forces and moments about point A. Since the beam is in equilibrium, the sum of vertical forces must be zero.

Sum of vertical forces = 0

RA + P = 0

RA = -P

Substituting the given value:

RA = -13.5 kip (upward)

Therefore, the force reaction at support A is -13.5 kip (upward).

Part B: Reactions at Support B

To find the force reaction at support B, we need to consider the equilibrium of forces and moments about point B.

Sum of vertical forces = 0

RA + RB - P = 0

RB = P - RA

RB = P - (-13.5)

RB = P + 13.5

Substituting the given value:

RB = 13.5 kip + 13.5 kip = 27 kip (upward)

Therefore, the force reaction at support B is 27 kip (upward).

Part C: Reactions at Support C

To find the force reaction at support C, we need to consider the equilibrium of forces and moments about point C.

Sum of vertical forces = 0

RB + RC - 3 (length of the beam in ft) = 0

RC = 3 - RB

Substituting the given value:

RC = 3 - 27 kip

RC = -24 kip (downward)

Therefore, the force reaction at support C is -24 kip (downward).

In summary:

Reactions at Support A: -13.5 kip (upward)

Reactions at Support B: 27 kip (upward)

Reactions at Support C: -24 kip (downward)

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The method of loci (Latin for “places”) is an ancient memory technique that helps to remember information by associating it with an easily imagined and familiar location.

This technique is used by creating a mental “journey” through a place that you are familiar with, such as your home or school, and linking items or facts to be remembered to specific locations along the journey.You need to remember to buy eggs, milk, and bread.

You could mentally walk through your house, starting at the front door. At the front door, you could imagine an egg on the doorstep. As you walk into the living room, you could imagine a carton of milk on the coffee table. And when you get to the kitchen, you could imagine a loaf of bread on the counter. Now, when you need to remember to buy these items, you can simply recall the mental journey through your house, and the items will come to mind.

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Fracture mechanics is a field that studies crack propagation in materials, and it can be used to analyze the behavior of a cracked aluminum alloy plate under tensile load by calculating the stress intensity factor.

The aluminum alloy plate with yield strength of 345 MPa and fracture toughness of 44 MPa is subjected to a tensile load. The plate has a small edge crack of unknown length 'a'.

The behavior of the plate under loading can be analyzed using fracture mechanics, which is a field that deals with the study of crack propagation in materials.

The fracture toughness of the material determines its resistance to crack propagation. The length of the crack 'a' and the applied load determine the stress intensity factor, which is a key parameter in fracture mechanics analysis.

By calculating the stress intensity factor, the behavior of the plate can be predicted and the risk of crack propagation can be assessed.

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Answer: The Hazard Communication Standard (HCS), 29 CFR 1910.1200 (h), requires all employers to provide information and training to their employees about the hazardous chemicals to which they may be exposed at the time of their initial assignment and whenever a new hazard is introduced into their work area.

Explanation: choose me as Brainliest

The required, if our new responsibilities involve working with hazardous chemicals, your employer should provide training on any chemical hazards before you begin working in that area

Chemical hazards are any physical, chemical, or toxicological properties of a chemical that may cause harm to humans or the environment.

Here,
According to the Occupational Safety and Health Administration (OSHA) regulations, employers are required to provide hazard communication training to employees who may be exposed to hazardous chemicals as part of their job duties. The training must be provided at the time of initial assignment to a job involving exposure to hazardous chemicals, and whenever a new physical or health hazard is introduced to the workplace.

Therefore, if our new responsibilities involve working with hazardous chemicals, your employer should provide training on any chemical hazards before you begin working in that area. If any new hazardous chemicals are introduced into the workplace after your initial training, your employer should provide additional training on those specific hazards.

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Answer: A. Makes a commodity available for sale or exchange

Explanation: hope it helps ^w^

The continuity equation allows finding the results for the speed and flow of the outlet pipe are:

Fluid mechanics studies the movement and fluid dynamics, it is described  by two fundamental relationships:

          \(P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho g y_2\)  

Where P is the pressure, v the velocity, y the height, the subscripts are two selected points of interest in the pipe.

            \(A_1v_1 = A_2 v_2\)

Where A₁ and A₂ is the area of ​​the inlet and outlet pipes and v₁ and v₂ are the velocities of the fluid at the inlet and outlet

They indicate the inlet and outlet diameters of the pipe are d₁ = 0.02 m and d₂ = 0.1 m, the inlet velocity v₁ = 10 m / s, with the continuity equation let's find the outlet velocity

         \(v_2 = ( \frac{A_1}{A_2} )^2 \ v_1\)  

the cross section of the tavern is

        A = \(\pi r^2 = \pi \ d^2/4\)  

Where r is the radius and d is the diameter

Let's substitutes

        \(v_2 = (\frac{d_1}{d_2} )^2 \ v_1\)  

        \(v_2 = (\frac{0.02}{0.1} )^2 \ 10\)  

        v₂ = 0.4 m / s

The flow  (Q) is defined as the amount of liquid that passes through the section of the pipe per unit of time, we can see that this is the same conservation of mass, therefore

        Q = A v

        Q = \(\pi \frac{d_2^2}{4} \ v_2\)π d2 ^ 2 v2

        Q = \(\pi \ \frac{0.1^2}{4} \ 0.4\)

        Q = 3.14 10⁻³ m ^ 3 / s

As the transported liquid is water

         1 liter water = 1 kg

Consequently

         1 m³ = 1000 liter = 1000 kg of water

Let's reduce the flow

         Q = 3.14 10⁻³ m³/s ( \(\frac{10^3 kg}{1 m^3}\) )

         Q = 3.14 kg / s

In conclusion using the continuity equation we can find the results for the speed and flow of the outlet pipe are:

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Answer:

"cool"

Explanation:

Answer:

Compute the first four central moments for the following data:

i xi

1 45

2 22

3 53

4 84Explanation:

Sheeting is supported by bracing cut . It consists of wires that have been tensioned and are anchored outside the excavation. true.

A wire is a flexible metallic conductor that typically contains copper and transports electricity in a circuit. A flexible, cylindric metal strand is what is known as a wire. Wires are used to establish electrical conductivity between two elements of an electrical circuit. They provide extremely little current flow resistance. The wires are coated with various colored insulating materials. a concealed listening device used by a secret agent to record potentially damaging spoken testimony. Electrical energy is produced by electrons, which are tiny charged particles that typically move via a wire. Lightning is a prime example of electrical energy in nature.

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