What happens to particle spacing when temperature increase, What we call this process?

Answer:

carbon has four unpaired electrons in its valence shell . hydrogen having one unpaired electron in its valence shell comes to bond with carbon by sharing a pair of electrons .since carbon needs 4 electrons to be stable, 4 hydrogen atoms take part in the bond . It's a covalent bond because the difference between the electronegativity of carbon and hydrogen is quite small .

Suppose that at midnight you observe the Moon due south on the meridian. It will be about 26 degrees east of my meridian two nights later at midnight. Therefore, option (b) It will be about 26 degrees east of my meridian, is correct.

When you observe the moon due south on the meridian, it is at the highest point it can be in the sky at your position. The moon's movement in the sky is from east to west. As a result, two nights later at midnight, it will be about 26 degrees east of your meridian. On Earth, the sky is divided into 24 time zones, with each time zone spanning 15 degrees of longitude. The sky can be seen in its entirety over a period of one year by an observer in Bellingham. The sky is constantly changing as the earth rotates on its axis, causing the stars to appear in different positions each night. In Bellingham, the observer can see roughly half of the overall sky over the course of one year.

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Correct question:

Suppose that at midnight you observe the Moon due south on the meridian. Where will it be two nights later at midnight?

a.It will be about 26 degrees west of my meridian.

b.It will be about 26 degrees east of my meridian.

c.It will be about 26 degrees north of my meridian.

d.It will be about 26 degrees south of my meridian.

Over a period of one year, how much of the overall (night) sky would a Bellingham observer be able to see?

Answer:

i dont know

Explanation:

Sorry and good luck

Answer:

Explanation:

Let lift force F be created by propellers at angle of Ф with the horizontal .

The vertical component of this force will balance the weight of helicopter and horizontal component will balance the air resistance .

F sinФ = mg = 2750 x 9.8 = 26950 N

F cosФ = 7510 N

Squaring and adding ,

F² = 26950² + 7510²

= 726302500 + 56400100

= 782702600

F = 27976.82 N .

Answer:8.3mins

Explanation:

S=Vt

where V=average speed

S=4000m V=8m/s

4000=8×t

t=4000/8

t=500s

t=500/60

t=8.3min

500 sec

8 min 20 sec

Hi there !

8 m ................ 1 s

4000 m ........ x s

x = 4000m×1s/8m = 500 sec = 8 min 20 sec

Good luck !

The length and orientation of the road in a frame of reference that is moving with the given velocity  in a direction making an angle of 30 degrees with the road is calculated to be 2.641 meters and  16.83 degrees respectively.

Let's first calculate the velocity of the road in the frame of reference that is moving with a velocity of 0.6c. We can use the velocity addition formula to calculate this:

v' = (v - u) / (1 - uv/c²)

where

v = velocity of the road

u = velocity of the frame of reference = 0.6c

c = speed of light

Since the road is at rest in its own frame of reference, v = 0. Substituting the values, we get:

v' = (-0.6c) / (1 - 0.6c × 0 / c²)

v' = -0.8824c

The negative sign indicates that the road appears to be moving in the opposite direction in the moving frame of reference.

Now, let's calculate the length of the road in the moving frame of reference. We can use the length contraction formula to calculate this:

L' = L × √(1 - v'²/c²)

where

L = length of the road

v' = velocity of the road in the moving frame of reference

Substituting the values, we get:

L' = 5 × √(1 - (-0.8824c)²/c²)

L' = 2.641 meters

Therefore, the length of the road in the moving frame of reference is 2.641 meters.

Finally, let's calculate the orientation of the road in the moving frame of reference. We are given that the direction of the velocity of the frame of reference makes an angle of 30 degrees with the road. We can use the following formula to calculate the angle between the road and the velocity of the frame of reference in the moving frame of reference:

tan(e') = (tan(e) - u/c) / (1 - u×tan(e)/c)

where

e = angle between the road and the velocity of the frame of reference

u = velocity of the frame of reference = 0.6c

e' = angle between the road and the velocity of the frame of reference in the moving frame of reference

Substituting the values, we get:

tan(e') = (tan(30) - 0.6c/c) / (1 - 0.6c×tan(30)/c)

tan(e') = 0.294

Taking the inverse tangent, we get:

e' = 16.83 degrees

Therefore, the orientation of the road in the moving frame of reference is 16.83 degrees and the length of the road in the moving frame of reference is 2.641 meters.

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The complete question is :

Given a road of length 5 meters, calculate the length and orientation of the road in a frame of reference that is moving with a velocity of 0.6c in a direction making an angle of 30 degrees with the road.

Answer:

Friction force is the correct answer.

Actually I'm wrong the person who has commented is correct

By applying the principles of measurement in Physics, specifically the concept of mass and weight, the group can distribute the antelope meat equally among themselves, ensuring fairness and equal sharing of resources.  

To help the hunter and his group equally share the meat, we can employ the principles of measurements in Physics. One way to achieve fairness is by utilizing the concept of mass and weight.

Firstly, the group can collectively measure the weight of the entire antelope using a weighing scale or balance. This will give them the total mass of the meat. Let's assume it weighs 100 kilograms.

Next, the group needs to divide the meat equally among themselves. Since there are four individuals, each person should ideally receive 25 kilograms of meat.

To ensure an accurate division, they can use smaller weighing scales or balances to measure and distribute equal portions. For example, they can divide the meat into smaller parts, say 5-kilogram portions, and use the scales to ensure each person receives five equal parts.

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a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.

b. The height reached by the pendulum is 0.038 m.

c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

K.E = 100%P.E - 18%P.E

where;

K.E(bottom) = 0.82P.E

K.E(bottom) = 0.82(mgh)

K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J

K.E = ¹/₂mv²

2K.E = mv²

v² = (2K.E)/m

v² = (2 x 0.402)/1

v² = 0.804

v = √0.804

v = 0.9 m/s

P.E = 100%K.E - 7%K.E

P.E = 93%K.E

P.E = 0.93(0.402 J)

P.E = 0.374 J

P.E = mgh

h = P.E/mg

h = (0.374)/(1 x 9.8)

h = 0.038 m

When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.

The height reached by the pendulum is 0.038 m.

When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

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Answer: His weight plus the centripetal force must equal 1170 N

Explanation:

83.0 [g + (v^2 / r)] = 1170

v^2 / 18.0 = (1170 / 83.0) - 9.81

Answer:

Pb =- Lead    No.  82   Wt 206   N = 206 - 82 = 124   Rat = 124/82 = 1.5`1

U = Uranium No. 92    Wt 238   N = 238 - 92 = 146    Rat = 146/92 = 1.59

3:2 = 1.50        Pb is closer to 3:2

Answer:

loop

Explanation:

When the magnetic field is downward, the current of charged particles in the boat must flow horizontally from left to right when viewed from the rear to obtain a rearward-pointing force.

To obtain a rearward-pointing force in a boat powered by the force of charged particles moving in a downward magnetic field, the current of charged particles must flow horizontally from left to right when viewed from the rear of the boat.

1. The force experienced by a charged particle moving in a magnetic field is given by the right-hand rule. The force is perpendicular to both the direction of the magnetic field and the direction of the current.

2. Since the boat is moving in a downward magnetic field, the magnetic field is directed downward. To obtain a rearward-pointing force, the force must be directed opposite to the boat's motion.

3. Using the right-hand rule, if the magnetic field is downward, and the force is directed rearward, the current must flow horizontally.

4. To determine the direction of the current, imagine standing at the rear of the boat and looking forward. The current must flow from left to right when viewed from this perspective to generate the desired rearward force.

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The third charged particle C should be placed at a distance of 10cm from A and 30cm from B.

The force between two charged particles is given by Coulomb's law. Since the charges of A and B are of opposite sign, they attract each other and form a dipole.

To find the position where a third charged particle C will experience no net force, we need to place it such that the electric field due to A and B cancel each other out.

The distance of C from A and B can be calculated using the concept of electric potential.

By applying the principle of superposition, we can find the electric potential at the point where C is placed and equate it to zero to get the required position.

The calculation shows that C should be placed at a distance of 10cm from A and 30cm from B.

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To place the third charged particle C so that it does not experience a net electric force, it should be positioned at a distance of 10 cm from particle A and 10 cm from particle B.

The electric force between two charged particles is given by Coulomb's law:

F = (k * |q₁ * q₂|) / r²

Where F is the electric force, k is the electrostatic constant (9 × 10⁹ N m²/C²), q₁ and q₂ are the charges of the particles, and r is the separation between the particles.

Since particle A has a positive charge (+8 × 10⁻⁶ C) and particle B has a negative charge (-2 × 10⁻⁶ C), the forces exerted by each particle on particle C will have opposite directions.

For particle C to experience zero net electric force, these forces must be equal in magnitude.

Given that particle C is equidistant from particles A and B, the forces exerted by particles A and B on C will have the same magnitude, resulting in a net force of zero.

Therefore, particle C should be placed at a distance of 10 cm from each of the fixed particles A and B.

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Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 2.55 \times {3.81}^{2} \\ = 1.275 \times 14.5161 \\ = 18.5080275\)

We have the final answer as

Hope this helps you

Astrometry instrument GAIA is used to determine the angular position of stars to measure the distances and motions.

GAIA stands for Global Astrometric Interferometer For Astrophysics. A spacecrafts remains in motion while scanning the space, and measuring the position, distance, and motion with precision. Angular position of a star of planet or any other space object is the orientation of its position with respect to a specific line. Angular motion describes how far the star is rotated relative to the reference line. Astrometry instrument is the set of high-resolution cameras, EDM, angular measurement devices, that collect the data by scanning and give the output of the exact position of the star.

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Answer:

 ΔR = 5 s

Explanation:

The absolute uncertainty or error in an expression is

       ΔR = | \(\frac{dR}{dB}\) | ΔB + | \(\frac{dR}{dA}\) | ΔA

the absolute value guarantees to take the unfavorable case, that is, the maximum error.

We look for the derivatives

       \(\frac{dR}{dB}\) = 1

       \(\frac{dR}{dA}\) = -1

we substitute

       ΔR = 1 ΔB + 1 ΔA

of the data

       ΔB = 3 s

       ΔA = 2 s

       ΔR = 3 + 2

       ΔR = 5 s

Answer: It would be 125 J

Answer:

bro lm.ao i recognize you from west point you go there? bro i be using this site too lm.aoooo

Explanation:

the first bump car will move

Explanation:

this is because as long as the other bumper car is coming with force, it mass changes and then , it is able to push the other one

The maximum speed of a block of ice sliding down an incline depends on several factors, including the slope of the incline and the coefficient of friction between the block and the surface. Assuming that the incline is frictionless, the block will accelerate as it slides down the slope and reach its maximum speed at the bottom.

This is because the gravitational force acting on the block is the only force acting on it, and it gains kinetic energy as it moves down the incline. However, if there is friction between the block and the surface, the maximum speed will occur before the bottom of the incline, depending on the coefficient of friction. In general, the lower the coefficient of friction, the closer the maximum speed will be to the bottom of the incline. Therefore, the answer to the question is B) the bottom, assuming a frictionless surface, but it is difficult to predict without knowing the coefficient of friction if the surface is not frictionless.

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Answer:

open the dictionary/glossary. it will give you the definitions of the words there.

Explanation:

Answer:

i think it goes like this

Explanation:

Answer:

64 ohms =R

Explanation:

R is directly proportional to V

R is inversely proportional to I(Current

To find the eigenvalues and eigenfunctions of the operator R, we start by writing out the matrix representation of R in the basis of the states

|1>, |2>, ..., |6>:

markdown:

 R =  |0   1   0   0   0   1 |

      |1   0   1   0   0   0 |

      |0   1   0   1   0   0 |

      |0   0   1   0   1   0 |

      |0   0   0   1   0   1 |

      |1   0   0   0   1   0 |

where we have used the shorthand notation IФn> = |n>.

To find the eigenvalues and eigenfunctions, we solve the eigenvalue equation:

 R|ψ> = λ|ψ>

where λ is the eigenvalue and |ψ> is the corresponding eigenvector.

Let's start by looking for eigenvectors of the form:

 |ψ> = a|1> + b|2> + c|3> + d|4> + e|5> + f|6>

where a, b, c, d, e, and f are complex numbers. Substituting this into the eigenvalue equation, we get:

 |2> = λ|1> + f|6>

 |3> = λ|2> + e|5>

 |4> = λ|3> + d|4>

 |5> = λ|4> + c|3>

 |6> = λ|5> + b|2>

 |1> = λ|6> + a|1>

Solving this system of equations, we find that the eigenvalues are:

 λ = ±1, ±i

and the corresponding eigenvectors are:

 |ψ1> = (1/√6) (|1> + |2> + |3> + |4> + |5> + |6>)

 |ψ2> = (1/√2) (|1> - |4>)

 |ψ3> = (1/√2) (|2> - |5>)

 |ψ4> = (1/√2) (|3> - |6>)

where we have normalized the eigenvectors to have unit length.

Note that the eigenvectors are orthogonal, which means that they form a complete set of basis vectors for the six-dimensional space of states. Any state can be written as a linear combination of these eigenvectors:

 |ψ> = c1|ψ1> + c2|ψ2> + c3|ψ3> + c4|ψ4>

where c1, c2, c3, and c4 are complex coefficients. Therefore, the eigenfunctions of the operator R span the space of the states.

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The time at which the two boats get closest to each other is t=21.6 min

Time and work are concerned with how long it takes a person or a group of people to finish a task and how effectively each of them completes it.

Given that,

A boat leaves a dock at 2 : 00 pm and travels due south at a speed of 20 km/h.

And another boat has been heading due east at 15 km/h and reaches the same dock at 3 : 00 pm.

At 2:00 pm,

t=0

At 3:00 pm,

t=1

Distance=Speed*Time

D=15(1)

D=15km

Now, if the speed is 20km/hr

D=20(t)

D=20t

C²=(15-15t)²+(20t)²

(C²)'=2(15-15t)(-15)+2(20t)(20)

(C²)'=-450+1250t

(C²)'=0

Then,

-450+1250t=0

t=9/25 hr

(C²)'=-450+1250t=0

(C²)"=1250>0

Therefore,

t=9/25 hr

t=21.6 min

The time at which the two boats get closest to each other is t=21.6 min

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Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

Answer:

1200 watt

Explanation:

P= I*V=10*120=1200watt

Answer:

It allows them to write better and more comprehensible research papers. As well as being able to communicate the relevance and impact of their ideas and discoveries.

Explanation:

Answer:

15.24 m/s in the downward direction

Explanation:

Given that the initial upward velocity of the ball is 24 m/s.

Assuming that the upward direction is positive.

As gravitational force acts in the downward direction and the direction of acceleration is the same as the direction of force, so the acceleration due to gravity will be negative.

Now, from the equation of motion, when an object is launched with initial velocity u, the final velocity, v, of an object after time t is v=u+at.

Given that u=24 m/s, t=4 seconds, \(g=-9.81 m/s^2\).

So, the final velocity is

\(v= 24 + (-9.81)\times 4 \\\\\Rightarrow v= 24-9.81\times 4\)

\(\Rightarrow v=-15.24\) m/s

Here, the negative sign means the final velocity is in the downward direction.

Hence, the velocity after 4 seconds is 15.24 m/s in the downward direction.

Answer: A shunt is a low-ohm resistor that can be used to measure current. ... The entire current flows through the shunt and generates a voltage drop, which is then is measured. Using Ohm's law and the known resistance, this measurement can then be used to calculate the current (I = V/R).

Answer:

We observe a volcano erupting lava. We can feel the ground tremble during the eruptions. We conclude that deep under the surface of the earth there are forces that produce considerable movement resulting heat and pressure we see.

Explanation:

Got it right on the quiz