What happens to tension and pressure when a sphere expands its radius?

Using a microscope involves four steps: setup, focusing, magnification control, and light intensity control. Setup the microscope, focus the specimen, adjust magnification, and control the light intensity for optimal viewing.

Using a microscope typically involves four steps: setup, focusing, magnification control, and light intensity control.

1. Setup: Begin by placing the microscope on a stable surface and ensuring it is properly connected to a power source if needed. Adjust the microscope's position so that it provides a comfortable viewing angle and easy access to the specimen.

2. Focusing: Start with the lowest magnification objective lens and place the specimen on the stage. Adjust the coarse focus knob to bring the specimen into approximate focus. Then, fine-tune the focus using the fine focus knob until the details of the specimen become clear and sharp. Repeat this process when switching to higher magnification lenses.

3. Magnification Control: Rotate the nosepiece or choose the desired objective lens to change the magnification level. Lower magnification lenses provide a wider field of view, while higher magnification lenses offer greater detail but a narrower field of view. Adjust the focus each time the magnification is changed for optimal clarity.

4. Light Intensity Control: Adjust the light intensity using the microscope's condenser or brightness controls to optimize the illumination of the specimen. This can help enhance contrast and visibility. Use higher intensity for low magnification and lower intensity for higher magnification to avoid excessive glare or loss of detail.

By following these steps, one can effectively set up, focus, control magnification, and adjust light intensity to obtain clear and well-illuminated images while using a microscope.

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the answer is WE GO DOWN 89W8 >#*#,'

Step 1. The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, impacts a substance. The energy of the photon will be sum total of energy needed to remove the electron and kinetic energy of the released electron.

hf = ϕ + k

where, ϕ = work function

k = kinetic energy

hf = incident of energy

f = c / lamda

Step 2.

Given,

ϕ = 2.45ev

lamda = 4.0 * 10-7m

hc/lamda = ϕ + k

k = (hc/lamda) – ϕ

k = (6.62 * 10-34 * 3 *108 / 4.0 * 10-7) – 2.45 * 1.6 * 10-19

k = 1.045 * 10-19 Joules

Now,

½ mv2= k

V = (2k/m)0.5

V = {(2 * 1.045 * 10-19) / 9.1 * 10-31}0.5

V = 479239.32 m/s

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Answer:

false

Explanation:

The gauge pressure in your car tires drops to 1.90×10⁵ N/m2.

A more detailed explanation of the answer.

We can use the ideal gas law in the form P1/T1 = P2/T2.

P1 is the initial pressure

T1 is the initial temperature

P2 is the final pressure

T2 is the final temperature.

1. Initial and final temperatures to Kelvin:
T1 = 35.0ºC + 273.15 = 308.15 K
T2 = -40.0ºC + 273.15 = 233.15 K

2. Plug the values into the equation:
(2.50×10⁵ N/m2) / 308.15 K = P2 / 233.15 K

3. Solve for P2:
P2 = (2.50×10⁵ N/m2) * (233.15 K / 308.15 K)
P2 ≈ 1.90×10⁵ N/m2

So, the gauge pressure in your car tires when their temperature drops to -40.0ºC is approximately 1.90×10⁵ N/m2.

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If a screw had a circumference of 16mm and a lead of 0.4mm and 15N of force is applied, the force produced would be 0.375N.

The mechanical advantage of a screw is determined by its lead, which is the distance traveled by the screw in one complete rotation. The formula for calculating the force produced by a screw is F = (T * p) / (2πr), where F is the force produced, T is the torque applied, p is the lead of the screw, and r is the radius of the screw.

In this case, the screw has a circumference of 16mm, so its radius is 16mm / 2π = 2.546mm. The lead of the screw is given as 0.4mm, and the force applied is 15N. Substituting these values into the formula, we get:

F = (T * p) / (2πr)

  = (15N * 0.4mm) / (2π * 2.546mm)

  = 0.375N

As a result, the screw produces 0.375N of force. This means that for every 15N of force applied to the screw, it produces a mechanical advantage of 0.375N, which is a measure of the force amplification achieved by the screw.

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Answer:Examples of input devices include keyboards, mouse, scanners, cameras, joysticks, and microphones.

pls mark brainliest

Explanation:

The application of the effort pf 400N on the widest part it resist the force of 800 N inside a wooden block the velocity ratio of the wedge is 4.

We know the effort and resistance forces, so we can solve for the distance moved by each force:

Distance moved by effort = (Resistance x distance moved by resistance) ÷ Effort

Distance moved by effort = (800 N x 8 cm) ÷ 400 N

Distance moved by effort = 16 cm

Distance moved by resistance = length of wedge - distance moved by effort

Distance moved by resistance = 20 cm - 16 cm

Distance moved by resistance = 4 cm

Now we can plug these distances into the formula for the velocity ratio:

Velocity ratio = distance moved by effort ÷ distance moved by resistance

Velocity ratio = 16 cm ÷ 4 cm

Velocity ratio = 4

Velocity ratio is a term used in mechanics and is defined as the ratio of the distance traveled by the effort to the distance traveled by the load in a machine. It is a fundamental concept that is used to determine the mechanical advantage of a simple machine. The velocity ratio is essential in understanding how a machine works and how it can be used to make work easier.

The velocity ratio is an important factor in the efficiency of a machine. A higher velocity ratio means that the load can be moved with less effort, resulting in a higher mechanical advantage. Therefore, machines with a high velocity ratio are considered to be more efficient and can be used to perform work more easily. Understanding the concept of velocity ratio is important in designing and operating machines, especially in situations where work needs to be done with minimal effort.

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The light from the bicycle have a velocity of 3.00x 10^8 m/s.

Explain Einstein's two postulates.

Einstein's two postulates form the foundation of modern relativity. The idea that the rules of physics are the same and can be expressed in their most basic form in all inertial frames of reference is the first postulate of special relativity. The assumption that the speed of light, or c, is a constant regardless of the source's relative motion is known as the second postulate of special relativity.

How several observers see the same event is the subject of relativity.

The theory of special relativity states that, in an inertial frame of reference, an object's velocity is relative to the frame from which it is observed or measured.

A body in motion moves in a straight path at a constant speed unless acted upon by an outside force in an inertial frame of reference, and a body at rest remains at rest.

According to einstein’s second postulate, speed of light from bike is equal to normal normal speed of light i.e. 3*10^8m/s

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We want to study the one-dimensional movement of a given object.

A) 35m

B) 65m

C) 25m

D) 2.78 m/s

First, let's write the given positions of the object.

We know that the object starts at the point 15m, then at t = 0s we have:

(0s, 15m)

Then it moves 20m towards +x in 4 seconds, so the new position is:

(4s, 35m).

Finally, it changes of direction and moves 45m in 5 seconds, then the final position is:

(9s, -10m).

A) We already know the position after 4 seconds, is 35m in the positive x-axis.

B) The total distance traveled is:

20m + 45m = 65m

C) The displacement is given by the distance between the final position (-10m) and the initial position (15m) we will get:

|-10m - 15m| = 25m

The displacement is equal to 25m

D) The average velocity can be computed as the quotient between the displacement (with the correspondent sign, in this case negative) and the time it takes to travel it.

We have:

AV  = -25m/9s = 2.78 m/s.

The negative sign is because the object moves to the left.

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When you display a 1 kHz, 2 V sine wave in channel A and a DC, 1 V signal in channel B with sensitivities set on 1V/div. Hence, the correct option is (c) The trace jumps up 1 division.

You select 'Add' so that the two signals are combined and you readjust the position so the trace is in the middle of the screen. If you switch the signal in channel B from DC to AC, the trace jumps up 1 division. An oscilloscope is an instrument that is used to monitor and visualize changing electrical signals. An oscilloscope functions by graphing the changes of a signal over time, with voltage represented on the y-axis and time represented on the x-axis. An oscilloscope functions by detecting and plotting the signals it receives. Oscilloscopes are often used in electronics, engineering, and telecommunications to examine and diagnose various systems. Signals may come from numerous sources, including electronic components, microprocessors, and electrical currents.

When you switch the signal in channel B from DC to AC, the trace jumps up 1 division. The trace jumps up 1 division when the signal in channel B is changed from DC to AC because the DC signal had an average value of 1V, while the AC signal has an average value of zero. When the DC signal is added to the AC signal, the trace is pulled down. When the DC signal is replaced with the AC signal, the trace jumps back up by one division.

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Answer:

The frequency at which the string will create a standing wave be  with three loops is 8.6 Hz

Explanation:

The speed of the of the wave, v = 12.9 m/s

The number of loops of the standing wave = 3 loops

The length of the string = 2.00 m

Given that one loo = half of the wavelength, we have;

Three loops = 3 × half = One and half wavelength  = 1.5·λ

The frequency of a wave = f = v/λ

Therefore, we have;

The frequency, f = 12.9/1.5 = 8.6 Hz

The frequency at which the string will create a standing wave be  with three loops = 8.6 Hz.

Answer:

9.675

Explanation:

got it right on acellus

Answer:

B

Explanation:

The cochlea is the part of the inner ear involved in hearing. It is a spiral-shaped cavity in the bony labyrinth, in humans making 2.75 turns around its axis, the modiolus.

Answer:

the answer is the cochlea

Explanation:

the eardrum receives the sounds and the cochlea "decifers them" so you know what words people are saying or what sound is playing.

To read text at a near-point distance of 22 cm, a person who has had cataract surgery would need a corrective lens with a refractive power of +4.5 diopters.

If a person has had the surgical removal of the variable lens of the eye, they would have lost the ability to accommodate (change the shape of the lens to focus on objects at different distances). Therefore, they would require corrective lenses to see clearly at different distances.

To determine the power of the corrective lenses required to read text at a near-point distance of 22 cm, we can use the following formula:

\(1/f = 1/d_o + 1/d_i\)

where:

f = focal length of the corrective lens

\(d_o\) = object distance (distance from the eye to the object)

\(d_i\)= image distance (distance from the eye to the image formed by the corrective lens)

We want to find the power of the corrective lens, which is given by:

\(P=1/f\)

The near-point distance \((d_o)\)  is 22 cm = 0.22 m. Since the cornea's refractive power focuses objects at infinite distances onto the retina, we can assume that the object distance is effectively at infinity, i.e., \(d_o = \infty\)

Therefore, the formula becomes:

\(1/f = 1/\infty + 1/d_i\)

\(1/f = 0 + 1/d_i\)

\(f = d_i\)

We want to find the focal length \((d_i)\)  of the corrective lens required to form an image of the text at a distance of 22 cm from the eye.

Using the formula, we get:

\(f = d_i = \frac{1}{(1/d_o + 1/d_i)}\)

\(d_i = \frac{1}{(1/d_o + 1/f)}\)

\(d_i = \frac{1}{(1/0.22 + 1/\infty)}\)

\(d_i = 0.22 m\)

Now, we can calculate the power of the corrective lens required as follows:

\(P = 1/f\)

\(P = 1/0.22\)

\(P = +4.5\)  diopters (to the nearest tenth of a diopter)

Therefore, the power of the corrective lenses required to read text at a near-point distance of 22 cm is +4.5 diopters (convex lenses).

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Answer: 8.1m/s^2

Explanation:

For this question, in order to solve it, we have to use the second equation of motion which will be:

s = ut + 1/2at^2

where,

u = initial velocity

v = final velocity

t = time

a = acceleration

Since u = 0, then

a = 2s/t^2

a = 2 × 110/5.21^2

a = 220/27.1441

a = 8.1m/s^2

Blue light has shorter wavelengths, 450–495 nanometers, on average. Blue light has a higher frequency and much more energy than red light.

The wavelength of an electromagnetic wave provides details about its length. The distance here between "crests" (tops) of related waves is known as the wavelength. The same wavelength can also be determined by making observations from the "groove" (bottom) from one waveform to the "trough" of the next.

Examples of electromagnetic fields with particular wavelengths & greater frequency include gamma rays, Cross, and ultraviolet light. Longer wavelengths & lower harmonics of electromagnetic fields include thermal light, microwaves, radio signals, and televisions waves.

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When a double-slit experiment is performed with electrons, an interference pattern is observed on the screen behind the slits. This pattern shows areas of both constructive and destructive interference, indicating that the electrons exhibit wave-like behavior.

The interference pattern is caused by the wave nature of the electrons. When electrons are fired at the two slits, they diffract and create two coherent waves that interfere with each other. The resulting pattern on the screen is a series of light and dark fringes, where the electrons interfere constructively at the light fringes and destructively at the dark fringes.

This interference pattern is similar to the pattern observed in a double-slit experiment with light, which was first performed by Thomas Young in 1801. The observation of an interference pattern with electrons confirmed the wave-particle duality of matter, which means that particles like electrons can exhibit both wave-like and particle-like behavior depending on the experimental setup.

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Answer: The longer the lever, the greater the force on the load will be.

Explanation:

Answer:

La fuerza ejercida sobre el piso del elevador hacia abajo es aproximadamente 1,004.075 N

Explanation:

Fuerza = Masa × Aceleración

El peso de la caja = 800 N

La velocidad hacia abajo = 5.0 m / s

Tomando la aceleración debida a la gravedad, g = 9,8 m / s²

La masa del cuerpo, m = 800 N / g = 800 N / (9,8 m / s²) ≈ 81,63 kg

La fuerza ejercida sobre el piso del ascensor durante la aceleración hacia arriba, 'N', se da como sigue;

N = m · g + m · a

a = 2,5 m / s²

∴ N = 81,63 kg × 9,8 m / s² + 81,63 × 2,5 m / s² = 800 N + 81,63 × 2,5 m / s² ≈ 1,004,075 N

La fuerza ejercida sobre el piso del ascensor hacia abajo ≈ 1,004.075 N

Answer:

Tt can be calculated by copy

Answer: energy transformation

Answer:

energy transformation

Explanation:

i hope this is helpful

The equation that relates the speed (c), wavelength (λ), and frequency (f) of electromagnetic waves is given by: \(\[c = \lambda \cdot f\]\).

In this equation, "c" represents the speed of light in a vacuum, "λ" represents the wavelength of the wave, and "f" represents the frequency of the wave.

This equation is derived from the fundamental relationship between the speed, wavelength, and frequency of any wave. The speed of light in a vacuum, denoted by "c," is a constant value approximately equal to 299,792,458 meters per second. The wavelength (λ) is the distance between two consecutive crests or troughs of the wave, while the frequency (f) represents the number of complete cycles of the wave that occur in one second.

By multiplying the wavelength and frequency, we obtain the speed of light. This equation demonstrates the inverse relationship between wavelength and frequency. As the wavelength increases, the frequency decreases, and vice versa, while the product of the two remains constant, representing the speed of light.

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Clockwise angular velocity was  non-zero and had a positive sign. So, the correct answer is D.

The right-hand rule for angular velocity asserts that if the right hand's thumb is pointing in the direction of the axis of rotation, then the direction of the angular velocity vector is given by the direction in which the right hand's fingers curl.

This makes sense in this situation. As a result, the angular velocity vector will point in the same direction as the rotation's axis, and it will be positive when the angular velocity is positive.

In physics, engineering, and other sciences, the right-hand rule for angular velocity is a helpful tool for visualising the direction of the angular velocity vector.

This rule allows us to quickly ascertain the direction and sign of the angular velocity in any given situation.

Complete Question:

Which angular velocity was non-zero and what was the sign? Explain how this makes sense given the right-hand rule for the angular velocity.

A.  Counterclockwise, Positive

B.  Clockwise, Negative

C. Counterclockwise, Negative

D. Clockwise, Positive

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Answer:

The kinetic energy of the larger car is two times that of the smaller car

Explanation:

Kinetic Energy

Is the energy an object has due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\(\displaystyle K=\frac{1}{2}mv^2\)

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

It's required to compare the kinetic energy of two cars K1 and K2. Car 2 has twice the mass of car 1: m2=2m1, and they have the same speed.

The kinetic energy of car 1 is:

\(\displaystyle K_1=\frac{1}{2}m_1v^2\)

The kinetic energy of car 2 is:

\(\displaystyle K_2=\frac{1}{2}m_2v^2\)

Substituting the relation of the masses:

\(\displaystyle K_2=\frac{1}{2}(2m_1)v^2\)

Rearranging:

\(\displaystyle K_2=2\left(\frac{1}{2}m_1v^2\right)\)

Substituting the kinetic energy of car 1:

\(\displaystyle K_2=2K_1\)

The kinetic energy of the larger car is two times that of the smaller car

An ideal bandpass filter with unit gain and a bandwidth of 200 Hz is applied to the input signal g(t) = 8 cos(400πt) cos(200,000πt) + 18 cos(200,000nt). The center frequency of the filter is 100,200 Hz. We can sketch the amplitude spectrum of the signal at the output of the filter using the following steps:

Step 1: Determine the Fourier transform of the input signal g(t)The Fourier transform of g(t) is given by: G(ω) = π[δ(ω + 2π × 200,000) + δ(ω - 2π × 200,000)] + π/2[δ(ω + 2π × 200) + δ(ω - 2π × 200)]

Step 2: Determine the transfer function of the bandpass filter

The transfer function of the ideal bandpass filter with unit gain and a bandwidth of 200 Hz centered at 100,200 Hz is given by: H(ω) = {1 for |ω - 2π × 100,200| < π × 100, and 0 otherwise}

Step 3: Multiply the Fourier transform of the input signal by the transfer function of the filter

The output of the filter is given by:

Y(ω) = G(ω)H(ω)The product of the Fourier transform of the input signal and the transfer function of the filter is shown in the figure below.

The given signal is a combination of two cosines, where the first cosine has a frequency of 400π radians/second and the second cosine has a frequency of 200,000π radians/second.

The output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude spectrum of the output signal is zero outside the bandpass region and is equal to the product of the amplitude spectrum of the input signal and the frequency response of the filter within the passband region.

The amplitude spectrum of the output signal is shown in the figure below:

Therefore, the amplitude spectrum of the signal at the output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude of the signal within the passband region is given by the product of the amplitude of the input signal and the frequency response of the filter within the passband region.

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A magnetic field strength of 2.0*10^(-3) T is required for the electron to pass between the charged plates without being deflected.

To determine the required magnetic field strength, we can use the equation F = qvB, where F is the magnetic force, q is the charge of the electron, v is its velocity, and B is the magnetic field strength. Since the electron is not deflected, the magnetic force must cancel out the electric force.

The electric force can be calculated using F_e = qE, where E is the electric field strength. Given that the plates are separated by 1.0 cm and charged by a 200 V battery, the electric field strength is E = 200 V / 0.01 m = 2.010^4 V/m.

Equating the electric and magnetic forces, we have qE = qvB. Simplifying this equation, we find B = E/v = (2.010^4 V/m) / (1.010^7 m/s) = 2.010^(-3) T. Thus, a magnetic field strength of 2.0*10^(-3) T is required for the electron to pass between the plates without being deflected.

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Angular speed = 0.4 rad/s , when a 5.0-m radius playground merry-go-round with a moment of inertia of 2000 kg m2 is rotating freely with an angular speed of 1.0 rad/s.

radius = 5 m

moment of inertia = 2000 kg-m²

angular speed = 1.0 rad/s

mass = 60 kg

to find out

angular speed

solution

Rotational momentum of merry-go-round = I?

The momentum we experience here is expressed as

momentum = 2000 × 1

momentum = 2000 kg-m²/s

and  

Inertia of people will be here as

Inertia of people = mr² = 60 × 5²

Inertia of people = 1500 kg-m²

so Inertia of people for two people  

1500 × 2 = 3000

and

Currently, angular momentum conservation

(Momentum + People's Inertia) = Moment of Inertia Angular Speed angular velocity

2000 ×  1 = (2000 + 3000 ) ω

solve we get now  

ω = 0.4 rad/s

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Answer:

The length of the third side is

     \(c =8.82 \  m \)

The tangent of the angle for which 6.9 m is the opposite side is

\(k = 1.256\)

Explanation:

From the question we are told that

The first side is a = 6.9 m

The second side is b = 5.5 m

Generally apply Pythagoras theorem

\(c^2 = a^2 + b^2\)

=> \(c = \sqrt{a^2 + b^2 }\)

=> \(c = \sqrt{6.9^2 + 5.5^2 }\)

=> \(c =8.82 \ m \)

From sin rule we have that

\(\frac{c}{sin(\theta )} = \frac{a}{sin (\beta )}\)

Generally from a right triangle the angle \(\theta = 90\)

So

\(\frac{8.82}{sin(90 )} = \frac{6.9}{sin (\beta )}\)

=> \(\beta = sin ^{-1}[\frac{6.9}{8.82} ]\)

=> \(\beta =51.47^o\)

Generally the tangent of the angle for which 6.9 m is the opposite side is mathematically represented as

\(k = tan (\beta )\)

       \(k  =  tan (51.47 )\)

       \(k  = 1.256\)

Answer:

30N is the correct answer