What happens to the period of a pendulum if the frequency is halved?

Answers

Answer 1

The period of a pendulum is related to its frequency by the following formula:

\(T=\frac{1}{f}\)

If the frequency is halved we have:

\(T_2=\frac{1}{\frac{f}{2}}\)

Simplifying we get:

\(T_2=2(\frac{1}{f})\)

The term inside the parenthesis is the original period, therefore:

\(T_2=2T\)

Therefore, if the frequency is halved the period is doubled.


Related Questions

A rabbit is moving in the negative x-direction at 2.70 m/s when it spots a predator and accelerates to a velocity of 13.9 m/s along the negative y-axis, all in 2.20 s. Determine the x-component and the y-component of the rabbit's acceleration. (Enter your answers in m/s2. Indicate the direction with the signs of your answers.)

Answers

Answer:

ax = 1.23 m/s²

ay = -6.32 m/s²

Explanation:

The acceleration is equal to the change in velocity over time. So, the acceleration of in the x-component is equal to

\(a_x=\frac{v_{fx}-v_{ix}}{t}\)

Where vfx is the final velocity on the x-direction which is equal to 0 m/s because at the end the velocity is in the y-axis. vix is the initial velocity which is -2.70 m/s and t is the time, so t = 2.20s.

Replacing the values, we get:

\(a_x=\frac{0-(-2.70\text{ m/s\rparen}}{2.20\text{ s}}=1.23\text{ m/s}^2\)

In the same way, we can calculate the y-component of the acceleration as

\(a_y=\frac{v_{fy}-v_{iy}}{t}\)

Replacing vfy = -13.9 m/s and viy = 0 m/s, we get:

\(a_y=\frac{-13.9\text{ m/s - 0 m/s}}{2.20\text{ s}}=-6.32\text{ m/s}^2\)

Therefore, the answer is

ax = 1.23 m/s²

ay = -6.32 m/s²

A frying pan is connected to a 1500 volt circuit. If the resistance of the frying pan is 25 ohms, how many amperes does the frying pan draw?

Answers

The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes

How do i determine the current drawn by the frying pan?

From the question given above, the following data were obtained:

Voltage of circuit (V) = 1500 V Resistance of frying pan (R) = 5 Ω Current (I) =?

The current drawn by the frying pan can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

Inputting the given parameters, we have:

1500 = Current × 25

Divide both sides by 25

Current = 1500 / 25

Current = 60 amperes

Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes

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cle 2 of charge 4.00q are held at separation L 9.00 cm on an x axis. If particle 3 of charge q3 is to be located such that the three particles remain in place when released, what must be the (a) x and (b) y coordinates of particle 3, and (c) the ratio q3 /q

Answers

Answer:

x=L/2  y=0 and the charge q3 is ¼ of the charge q

Explanation:

For this exercise we will use Coulomb's law.

         F₁₂ = k q₁ q₂ / r₁₂²

From this expression we see that like charges repel and charges of different signs attract.

Let's apply this expression to our case, they indicate that the two charges are of equal magnitude and sign, therefore the force is repulsive, so that it is in equilibrium with a third charge (q₃) this must be of the opposite sign and be between the two charge (q)

let's apply Newton's second law to one of the charges, for example the one on the left

         -F₁₂ + F₁₃ = 0

           F₁₂ = F₁₃

          k q₁ q₂ / r₁₂² = k q₁ q₃ / r₁₃²

          q₂ / r₁₂² = q₃ / r₁₃²

          q₃ = q₂ (r₁₃ / r₁₂)²

           

The problem indicates the charge q₁ = q₂ = 4 q and the distance between them is r₁₂ = L = 9 cm = 0.09 m, we substitute

          q₃ = 4q (r₁₃ / L)²

Let's analyze the situation a bit that the charge 1 and 2 are in equilibrium with a single charge 3 this must be symmetrical between the two charge (the same force), therefore its position on the x axis must be r₁₃ = L/2 and how it is on the y axis = 0

let's substitute

           q₃ = 4q (L / 2L)²

            q₃ = 4q 1/4

            q₃ = q

the charge q3 is ¼ of the charge q

Two large horizontal, parallel metal plates are 2.0 cm apart in air and the upper plate is maintained at a positive potential relative to the lower plate so that field strength between them is 2.5×105 Vm-1. An electron is released from rest at the lower plate. What is its speed on reaching the upper plate? [e=1.6×10-19C;me=9.1×10-31kg]

Answers

From the calculation, it is clear that the velocity of the electron is obtained as a value of 4.2 * 10^8 m/s.

What is the electric potential?

The electric potential refers to the work that could be done when we bring a unit positive charge from infinity to a particular point on the electric filed. In this case, we are told that the;

field strength = 2.5 × 10^5 Vm-1

Distance apart = 2.0 cm  or 0.02 m

We could the obtain the electric potential as; field strength * Distance apart

=  2.5 × 10^5 Vm-1 *  0.02 m

= 5 * 10^3 V

We now have that;

ev = 1/2mve^2

e = unit of electronic charge

v = voltage

m = mass of the electron

ve= velocity of the electron

ve= √2ev/m

ve = √2 * 1.6 × 10^-19 * 5 * 10^3/9.1 × 10^-31

ve = √ 1.8 * 10^15

ve = 4.2 * 10^8 m/s

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PLEASE HELP I WROTE THIS LIKE 200 TIMES

Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.

PLEASE HELP I WROTE THIS LIKE 200 TIMESPlate boundaries represent parts of the Earth where plates come

Answers

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.



Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Acceleration refers to any changes in

Answers

Answer:

speed

Explanation:

Mathias is going to do some informational interviewing. What is one of the main benefits of doing these interviews?
O A.
OB.
O C.
O D.
A.He will gain insight about a new career opportunity.
B.He will likely be offered a position with a company.
C.He will be able to ask questions about job openings.
D.He will find out how much money everyone earns.

Answers

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

PLEASE HELP ASAP
A golf ball is hit horizontally off the edge of a 30 m high cliff and lands
distance of 25 m from the edge of the cliff.

1. What is the initial vertical velocity of the golf ball?

2. At what time did the golf ball hit the ground?

3. What was the initial horizontal velocity of the golf ball?

4. What was the final horizontal velocity of the golf ball?

Answers

Answer:

1. Initial vertical velocity its 0m/s

2. 2.47 seconds

3. 10.12 m/s

4.10.12 m/s

Explanation:

Remember that we have here two parts of a problem, first we know that the ball made a free fall of 30 meters, since the ball was hit horizontally and doesn't state otherwise the vertical velocity is 0. To calculate the time we just use 30 m as our Height and use the formula for vertical distance on free fall:

\(H=\frac{g*t^{2} }{2} \\\)

Now we just solve for time:

\(t=\sqrt{\frac{2H}{g} }\)

With this we just insert the values we know:

\(t=\sqrt{\frac{2H}{g} }\\t=\sqrt{\frac{2*30}{9.81} }\\t=2.47\)

Now we know that the ball was 2.47 seconds in the air, so the ball hti the ground at the second 2.47.

To calculate the velocity of the ball we just need to divide the horizontal distance covered by the time it spent on air:

\(v=\frac{d}{t} \\v=\frac{25}{2.47} \\v=10.12\)

The final and initial horizontal velocity of the ball would be the same since nothing states otherwise, of course the hitting of the ground would decrease its velocity but since nothing is said in the problem it is not considered.

1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).

2. The time it took the golf ball to hit the ground is 2.47 seconds.

3. The initial-horizontal velocity of the golf ball is 10.12 m/s.

4. The final-horizontal velocity of the golf ball is 10.12 m/s.

Given the following data:

Maximum height = 30 meters.Horizontal distance = 25 meters.

1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).

2. To determine the time it took the golf ball to hit the ground:

At maximum height, time is given by the formula:

\(Time = \sqrt{\frac{2H}{g} }\)

Where:

g is the acceleration due to gravity.H is the maximum height.

Substituting the given parameters into the formula, we have;

\(Time = \sqrt{\frac{2\times 30}{9.8} }\\\\Time = \sqrt{\frac{60}{9.8} }\\\\Time =\sqrt{6.12}\)

Time = 2.47 seconds.

3. To determine the initial-horizontal velocity of the golf ball:

\(Horizontal\;velocity = \frac{Horizontal\;distance}{Time} \\\\Horizontal\;velocity = \frac{25}{2.47}\)

Initial horizontal velocity = 10.12 m/s.

4. To determine the final-horizontal velocity of the golf ball:

The initial-horizontal velocity and final-horizontal velocity of the golf ball would be the same.

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define volume charge density \( ( \: \rho \: ) \)

ty!~​

Answers

Answer:

charge density when the charge density is shoe out the volume of a body then the charge for unit volume is called volume charge density and it is represent by ρ. •: ρ = Vq

Answer:

Volume charge density: When the charge density is throughout the volume of a body, then the charge per unit volume is called volume charge density and it is represented by ρ.

∴ρ=

\( \frac{v}{p} \)

Hence the unit of ρ is Cm

−3

Example: If a charge q is uniformly distributed in the whole volume of a

sphere of radius R, then p =

\( \frac{q}{ \frac{4}{3} } \pi {r}^{3} \) =3q/4πR-3

What does it mean for a chemical equation to be balanced?

Answers

Answer:

The number of each type of atom is the same for both the reactants and products.

I hope this helps

A skier starts at the top of a frictionless slope and pushes off with a speed of 3.0 m/s. The elevation of the slope is 40 m. She skis down the slope to a valley with elevation 0.0 m and then glides to the peak of an adjacent slope that is at an elevation of 25 m. Calculate her speed at the second peak.

Answers

Given:

The speed of the skier at the top of the first peak is,

\(v_1=3.0\text{ m/s}\)

The elevation of the slope is,

\(h_1=40\text{ m}\)

She skis down the slope to a valley with an elevation of 0.0 m and then glides to the peak of an adjacent slope that is at an elevation of

\(h_2=25\text{ m}\)

To find:

The speed at the second peak

Explanation:

The diagram can be depicted below as:

Using the conservation of the mechanical energy, we can write,

The total energy at peak 1 = The total energy at peak 2

So,

\(\begin{gathered} mgh_1+\frac{1}{2}mv_1^2=mgh_2+\frac{1}{2}mv_2^2 \\ v_2^2=2gh_1+v_1^2-2gh_2 \\ v_2=\sqrt{2gh_1+v_1^2-2gh_2} \end{gathered}\)

Substituting the values we get,

\(\begin{gathered} v_2=\sqrt{2\times9.8\times40+(3.0)^2-2\times9.8\times25} \\ =\sqrt{303} \\ =17.4\text{ m/s} \end{gathered}\)

Hence, the speed at the second peak is 17.4 m/s.

A skier starts at the top of a frictionless slope and pushes off with a speed of 3.0 m/s. The elevation

what is the maximum magnitude of p that can be applied before tipping would occur, assuming the block does not slip? express your answer to three significant figures with appropriate units. ptip

Answers

A probabilistic assessment of seismic hazards requires an estimate of the maximum moment intensity M of the largest earthquake that is likely to occur in a given region. The answer is in the image.

Maximum magnitude, an important parameter in calculating seismic hazards, is also a controversial parameter. The choice of value can have a large impact on the final outcome of the results, but it is most likely the magnitude of an earthquake that has not yet occurred in the area under study.

The term size is defined as the number of flocks. For example, the magnitude can be used to describe the speed comparison between a car and a bicycle. It can also be used to describe how far an object has moved or how much an object has in relation to size.

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what is the maximum magnitude of p that can be applied before tipping would occur, assuming the block

If Janine is a typical middle-aged woman, she is likely to be concerned about all of the following things except for one. Identify the option that is generally not a concern for the average middle-aged woman ?

Answers

For a typical middle-aged woman, there are certain priorities for them such as job stability, kids, and so on, but one factor that is generally not a concern for the average middle-aged woman is how to train for the Olympics

Who is a middle-aged woman?

Midlife, the stage of a woman's life between childhood and elder maturity, has been called a time of transition. Women between the ages of 40 and 65 have been the focus of midlife research because they often go through a number of social, psychological, and biological shifts during this time.

Hence, it can be seen that while there are genuine concerns for a middle-aged woman, the answer choice that is generally not a concern for the average middle-aged woman is to become an Olympian.

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If Janine is a typical middle-aged woman, she is likely to be concerned about all of the following things except for one. Identify the option that is generally not a concern for the average middle-aged woman ?

train for the Olympics

have kids

raise a family

A uniform electric field is directed upward and has a magnitude of 24 N/C. A charge of -6 C is placed in this
field.


The direction of the force on the charge placed in the electric field is upward.
True or False

Answers

The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.

The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.

The force on a charged particle in an electric field can be calculated using the formula:

F = q * E

Where F is the force, q is the charge of the particle, and E is the electric field.

Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:

F = (-6 C) * (24 N/C)

F = -144 N

The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.

The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.

Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.

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What are the magnitude and the direction of the electric field that will allow an electron to fall with an acceleration of 4.3 m/s2?

Answers

Answer:

Explanation:

The acceleration of an electron in an electric field is given by the equation:

a = qE/m

where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.

Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:

E = ma/q

E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)

E = -2.44 × 10^4 N/C

The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.

Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

help me

Write your answer on the lines below.

4. Are the light waves reflecting off a red stop sign longer or shorter than the waves reflecting off a violet-colored jacket? Explain how you know.​

Answers

The light waves reflecting off a red stop sign would be longer than the light waves reflecting off a violet-colored jacket. This is because red light has a longer wavelength than violet light.

Light waves and reflection

Light waves, like all waves, are characterized by their wavelength. The wavelength of a wave determines its color, with shorter wavelengths appearing as blue and violet, and longer wavelengths appearing as red and orange.

Because the wavelength of red light is longer than the wavelength of violet light, the light waves reflecting off the red stop sign would be longer than the light waves reflecting off the violet-colored jacket.

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What can quantum computers do more efficiently than regular computers?a. Monitor medical equipment for greater efficiency.b. Automate routine hospital administrative tasks.c. Provide accurate warning of extreme weather events.d. Map disaster areas after major adverse events.

Answers

Assuming that a quantum computer could be programed to do any of the scenarios in the given options, then the quantum computer would be able to do every single possible task orders of magnitude more efficiently, due to the nature of its processing "method".

So, all the options will be true for a quantum computer. Assuming, that it can be programmed to do anything like the scenarios described.

which two characteristics are used to classify stars on the Hertzsprung-Russell diagram

Answers

Answer:

Which two characteristics are used to classify stars on the Hertzsprung-Russell diagram?

Explanation:

The characteristics that are used in order to classify the stars on the Hertzsprung-Russell diagram are size, density, temperature, and absolute brightness. They do not use the composition as they use the spectrographs for that purpose.

Hope that helped.

Answer:

Temp and absolute brightness

Explanation:

Took the test

A ball of mass 2 kg is moving with a velocity of 12m/s collides with a stationary ball of mass 6 kg and comes to rest. Calculate velocity of ball of mass 6kg after collision.

Answers

Answer: 4 m/s

Explanation:

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a closed system remains constant before and after a collision.

Let's denote the initial velocity of the 2 kg ball as "v1i", the initial velocity of the 6 kg ball as "v2i", the final velocity of the 2 kg ball as "v1f", and the final velocity of the 6 kg ball as "v2f".

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:

m1 * v1i + m2 * v2i = m1 * v1f + m2 * v2f

where m1 is the mass of the 2 kg ball, m2 is the mass of the 6 kg ball, v1i and v2i are the initial velocities, and v1f and v2f are the final velocities.

Given:

m1 = 2 kg

m2 = 6 kg

v1i = 12 m/s (initial velocity of the 2 kg ball)

v2i = 0 m/s (initial velocity of the 6 kg ball, as it is stationary)

v1f = 0 m/s (final velocity of the 2 kg ball, as it comes to rest)

Plugging in the given values into the conservation of momentum equation:

2 * 12 + 6 * 0 = 2 * 0 + 6 * v2f

24 = 6 * v2f

Dividing both sides by 6:

v2f = 24 / 6 = 4 m/s

So, the velocity of the 6 kg ball after the collision is 4 m/s.

A particle moves along X-axis in such a way that X-coordinate varies with time according to expression x= 2-5t+6t2 meters, Calculate the initial velocity of the particle?

Answers

A  5

v=  dt/ dx  =−5+12t

Initial velocity means at t=0, which is −5+0=−5.

Thus, −v=5n

Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mule and refuses to continue on the walk. Cass yanks on the chain with a 67 N force at an angle of 30° above the horizontal. Determine the horizontal and vertical components of the tension force.

Answers

Answer:

Horizontal component: \(F_x = 58\ N\)

Vertical component: \(F_y = 33.5\ N\)

Explanation:

To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.

Therefore, for the horizontal component, we have:

\(F_x = F * cos(angle)\)

\(F_x = 67 * cos(30)\)

\(F_x = 58\ N\)

For the vertical component, we have:

\(F_y = F * sin(angle)\)

\(F_y = 67 * sin(30)\)

\(F_y = 33.5\ N\)

So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.

How can you find directions using satellite orbiting?

Answers

Answer:

Satellites may move north to south, or south to north, or west to east, but never from east to west. When satellites are launched, they always head eastward to take advantage of the Earth's rotation, going more than 1,000 miles per hour near the equator. This saves a lot of fuel.

how much force is required to accelerate an 8.6kg wagon by 15 m/s ?

Answers

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

What is force?

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

Mass of the rock m = 8.6kgAcceleration a = 15m/s²Force F = ?

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

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help me pls
An object accelerates if it:

a.) changes the direction of its velocity but not the magnitude

b.)changes the magnitude of the velocity but not the direction

c.)changes its speed

d.) all of the above

e.) none of the above

Answers

Answer:

D

Explanation:

how was newton's laws used to solve problems on apollo 13 ship
Explain in two full paragraphs

Answers

Answer:

actually ships are made in newtons third law of motion.it states to every action there is equal and opposite reaction. curved is made in downwards to maintain upthrust and to made balance.

actually it prevents ships from drowning and to move with a heavy mass.

6. What is the lowest temperature on the Kelvin scale? What happens to matter when it
reaches this temperature?
7. What is different about the degrees on the Fahrenheit and Kelvin scales and the Celsius
and Kelvin scales?

Answers

I think I only have answers for the first part but- ‘The lowest number would be 0k I believe. When matter reaches this point the atoms would be still/ have no movement at all. ‘

Two identical closely spaced circular disks form a parallel- plate capacitor. Transferring 1.5 * 109 electrons from one disk to the other causes the electric field strength between them to be 1.0 * 105 N/C. What are the diameters of the disks

Answers

We have that the Diameter of the disks is mathematically given as

d= 0.01858 m

Diameter Length

Question Parameters:

Transferring 1.5 * 109 electrons from one disk to the other electric field strength between them to be 1.0 * 105 N/C

Generally the equation for the Electric field  is mathematically given as

\(E=q/eA\\\\Where\\\\A=\pi d^2 / 4\\\\Therefore\\\\ 1.0 * 10e5= \frac{4 * 1.5 * 10e9 * 1.6 * 10 e-19}{(8.85 * 10e-12 * 3.14 * d2 )}\\\\\)

d= 0.01858 m

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Activities 1. Find the force needed to accelerate a mass of 40kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10s​

Answers

The force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is 12.4 N.

Start by calculating the change in velocity (Δv) experienced by the object. This can be done by subtracting the initial velocity v₁ from the final velocity v.

Δv = v - v₁ = ((8î + 3) - 5k) - ((4î - 5) + 3k)

= 8î + 3 - 5k - 4î + 5 - 3k

= 4î - 8k + 8

Next, calculate the acceleration (a) using the formula:

a = Δv / t

where t is the time interval, given as 10 seconds.

a = (4î - 8k + 8) / 10

= (0.4î - 0.8k + 0.8) m/s²

The force (F) required to accelerate the object can be found using Newton's second law:

F = m * a

where m is the mass, given as 40 kg.

F = (40 kg) * (0.4î - 0.8k + 0.8) m/s²

= (16î - 32k + 32) N

Simplify the expression to obtain the final answer:

F = 16î - 32k + 32 N

≈ 12.4 N

Therefore, the force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is approximately 12.4 N.

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Please Help!
Which statement BEST describes the production of energy in the Sun?
A) Nuclei with more mass break down into nuclei with less mass in the Sun’s core to release energy.
B) Nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.
C) Nuclei with more mass break down into nuclei with less mass on the Sun’s surface to release energy.
D) Nuclei with less mass combine to form nuclei with more mass on the Sun’s surface and release energy.

Answers

The statement that best describes the production of energy in the Sun is nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.

How is energy produced in the sun?

Sun is a major source of renewable energy to the Earth. This energy serves various purposes by living organisms.

However, the energy is generated as a result of nuclear fusion, which is the combination of smaller particles to form a larger one.

Therefore, the statement that best describes the production of energy in the Sun is nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.

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