Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds and thunderstorms.
When a cold front approaches, the heavier (denser) cool air pushes beneath the lighter (less dense) warm air, causing it to climb into the troposphere. Cumulus or cumulonimbus clouds and thunderstorms are produced by lifted warm air ahead of the front.
When a cold, dense air mass pushes beneath a warm, lighter air mass, causing the warm air to rise, a cold front forms. The cold air moves forward, displacing the warm air at the surface. As moisture in the warm air mass rises, cools, and condenses, rain and thunderstorms can form.
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A ball falls from a tower
a) The two forces acting on the tennis ball are equal and opposite. What is the resultant force
?acting on the ball
Answer:
Zero
Explanation:
The resultant force acting on the ball would be zero.
Since only two forces were acting on the tennis ball and these forces negate and cancel each other in magnitude, the resultant effect on the tennis ball would be zero.
Assuming that one of the forces is 5N and acting from the positive side and the other force is also 5N but acting from the negative side.
Resultant = -5 + 5 = 0 N
Can scientific laws be changed by a vote
Answer:
No.
Explanation:
A sceintific law cannot be changed or modified. It has been proved multiple times.
Answer:
No.
Explanation:
Scientific laws can only be changed if proven wrong. Scientists don't vote on knowledge, they use evidence to prove or disprove theories and laws.
what force must the person exert on the lawn mower to accelerate it from rest to 1.5 m/s m / s in 2.5 seconds, assuming the same friction force?
The force the person must exert on the lawn mower to accelerate it from rest to 1.5 m/s m / s in 2.5 seconds, assuming the same friction force, is 18 N.
To calculate the force required to accelerate the lawn mower from rest to 1.5 m/s in 2.5 seconds, we can use the formula:
Force = mass x acceleration
First, we need to determine the acceleration of the lawn mower:
Acceleration = (final velocity - initial velocity) / time
Acceleration = (1.5 m/s - 0 m/s) / 2.5 s
Acceleration = 0.6 m/s²
Next, we need to determine the mass of the lawn mower. Let's assume it has a mass of 30 kg.
Now we can calculate the force required:
Force = mass x acceleration
Force = 30 kg x 0.6 m/s²
Force = 18 N
Therefore, the person exerting a force of 18 N is required to accelerate the lawn mower from rest to 1.5 m/s in 2.5 seconds, assuming the same friction force.
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What happens when an object is moved against gravity, such as rolling a toy car up a ramp?
Answer:
it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back
Explanation:
A sonar signal of frequency 1 x 10^6 Hz has a wavelength of 1.5 mm in * 30 points
water. a) What is the speed of the signal in water? b) What is its period in
water? c) What is its period in air?
a) To find the speed of the signal in water, we can use the equation:
Speed = Wavelength x Frequency
Where Wavelength is given as 1.5 mm and Frequency is given as 1 x 10^6 Hz.
Speed = 1.5 x 10^-3 m x 10^6 Hz = 1.5 x 10^3 m/s
So the speed of the signal in water is 1.5 x 10^3 m/s
b) To find the period in water, we can use the equation:
Period = 1 / Frequency
Where Frequency is given as 1 x 10^6 Hz
Period = 1 / (1 x 10^6) s = 1 x 10^-6 s = 1 microsecond
So the period of the signal in water is 1 microsecond
c) The speed of sound in air is approximately 343 m/s. Since the frequency of the signal remains constant and the speed of sound in air is different than the speed of sound in water, the wavelength of the signal will also be different. However, since the period is inversely proportional to the frequency and is independent of the medium, the period of the signal in air will be the same as in water, which is 1 microsecond.
How does a falling object's surface area affect calculations of terminal velocity? (
O The greater the object's surface area, the greater the air density.
O Surface area does not affect an object's terminal velocity.
O The greater the object's surface area, the greater its terminal velocity.
O The greater the object's surface area, the more air resistance it encounters.
Answer:
The greater the object's surface area, the more air resistance it encounters.
Explanation:
Terminal velocity is the point at which the force of air resistance is equal to the force of gravity acting on an object. An object with a greater surface area will encounter more air resistance and therefore have a lower terminal velocity.
The greater the object's surface area, the more air resistance it encounters. Hence, its velocity decreases with increasing surface area.
What is velocity ?Velocity is a physical quantity that measure the distance covered by an object per unit time. Velocity is the rate of speed and it is a vector quantity. Velocity of an object is affected by its mass, physical state, surface area, temperature etc.
As the mass increases, the velocity of a a falling object will be greater because, the gravitational force towards the massive object is greater and it falls rapidly.
As the surface area of the object increases, the air resistance that it encounters also increases. This air resistance acts as an opposition and decreases its velocity.
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An athlete running at the velocity of 23m\s due east is confronted with two trade winds. The wind travelling at 10 m\s in a direction of N 65°E and the other wind travelling at 8 m\s in a direction of S70°E. Find the resultant velocity and direction of the athlete.
Answer:
Resultant velocity is 16.647m/s and the direction is counterclockwise from the x-axis which is 19.69⁰.
Explanation:
The sum of velocities the x-axis is given as 8sin70⁰+10sin65⁰= 16.5806N
The sum of velocities the y-axis is given as
-8cos70⁰+10cos65⁰=1.49002N
Resultant velocity = (16.58² + 1.49²)^(1/2)
= 16.647m/s
Direction= arctan(1.49002/16.5806)=5.135⁰
at which wavelength would you have predicted photosynthetic activity to be greatest
The wavelength at which photosynthetic activity is predicted to be greatest is around 430 to 450 nanometers (nm).
What is Photosynthetic activity?
Photosynthetic activity primarily relies on the absorption of light by chlorophyll pigments, specifically chlorophyll a and chlorophyll b. These pigments are most efficient at capturing photons in the blue and red regions of the electromagnetic spectrum. While chlorophyll a absorbs light most strongly at wavelengths around 430 nm (blue region), chlorophyll b has a slightly higher absorption peak at around 450 nm (blue-green region).
Therefore, to maximize photosynthetic activity, it is expected that light with wavelengths in the range of 430 to 450 nm would be most effective. This range corresponds to the blue region of the spectrum, where chlorophyll pigments have the highest absorption efficiency, enabling the conversion of light energy into chemical energy through photosynthesis.
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If a door within a wall is open sound produced on one side of the wall will be able to reach a person anywhere on the other side of the wall due to
It is generally knowledge that sound waves may bend around corners or pass through doorways, enabling us to hear conversations taking place in nearby rooms.
Why do we hear noise on the opposite side of the barrier?The air on the opposing side of the barrier also vibrates as a result of the audio hitting the wall. You will be able to hear some sound through a sturdy, solid wall since it won't spread the vibrations too much.
What is the term for when sound penetrates a wall?A reflecting wave is created as a sound crosses a room and collides with a wall, reintroducing some of that waveform back into the space. The originating sound will endeavor to go through the wall and into the next space. Sound Transmission is the name for the energy that remains after this transmission.
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Drag each label to the correct location on the table.
Sort the processes based on the type of energy transfer they involve.
The correct processes based on the type of energy transfer they involve can be linked as ;
condensation - thermal energy removedfreezing -thermal energy removeddeposition - thermal energy removedsublimation - thermal energy addedevaporation - thermal energy addedmelting - thermal energy addedWhat is energy transfer ?Conduction, radiation, and convection are the three different ways that thermal energy is transferred. Only fluids experience the cyclical process of convection.
The total amount of energy in the universe has never changed and will never change because it cannot be created or destroyed.
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An object of mass 20 g is moving in a horizontal circle of radius 250 cm at a speed of 50 cm/s. What is the centripetal acceleration experienced by the object?
The centripetal acceleration experienced by an object moving in a circle is given by the formula:
a = v²/r
where a is the centripetal acceleration, v is the speed of the object, and r is the radius of the circle.
In this problem, we are given that the object has a mass of 20 g, which we need to convert to kilograms:
m = 20 g = 0.02 kg
We are also given that the object is moving in a horizontal circle of radius 250 cm at a speed of 50 cm/s. We need to convert these measurements to SI units (meters and seconds) to use the formula for centripetal acceleration:
r = 250 cm = 2.5 m
v = 50 cm/s = 0.5 m/s
Now we can calculate the centripetal acceleration:
a = v²/r = (0.5 m/s)² / 2.5 m = 0.1 m/s²
Therefore, the centripetal acceleration experienced by the object is 0.1 m/s².
A light wave has a frequency of 12 Hz. Calculate it’s wavelength.
Answer:
\(\lambda=25\times 10^6\ m\)
Explanation:
Given that,
The frequency of the light wave, f = 12 Hz
We need to its wavelength. The wavelength of the wave can be calculated as follows :
\(\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{12}\\\\\lambda=25\times 10^6\ m\)
So, the wavelength of the light wave is equal to \(25\times 10^6\ m\).
a block of mass m is floating in a container of liquid and is partially submerged. the block is then replaced by a block of mass 2m . which of the following describes two forces that are a newton's-third-law force pair whose magnitudes are the same for the two situations? responses
In both situations, the two forces that form a Newton's third-law force pair with equal magnitudes are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.
When a block is floating in a container of liquid, it experiences two forces: the weight of the block and the buoyant force exerted by the liquid. The weight of the block is given by the equation:
\(\[ F_{\text{{weight}}} = mg \]\)
where m is the mass of the block and g is the acceleration due to gravity. The buoyant force exerted by the liquid on the block is equal to the weight of the liquid displaced by the block. It can be calculated using Archimedes' principle:
\(\[ F_{\text{{buoyant}}} = \rho V_{\text{{submerged}}} g \]\)
where \(\( \rho \)\) is the density of the liquid and \(\( V_{\text{{submerged}}} \)\) is the volume of the block that is submerged in the liquid.
When the block is replaced with a block of mass 2m , the weight of the block doubles while the buoyant force remains the same. Therefore, the two forces that form a Newton's third-law force pair with equal magnitudes in both situations are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.
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PLOT A GRAPH OF L AGAINST T² AND DETERMINE THE SLOPE
The measured value of g is determined by the slope of the time period T² vs. l graph (acceleration due to gravity).
Time period the amount of time that a behavior lasts or a condition persists. Depending on the type of activity or situation under consideration, it may be measured in seconds or in millions of years.
the duration T as determined by the formula T = 2π √(l/g). The pendulum's length, l, is indicated here.
The result of squaring both sides is T² = 4π² l/g
42 and g are constants, thus
⇒ T² = ml
The slope of the T² vs l graph in this case is m. The slope's value is m = 4π²/g
We can determine the value of g from the slope of the graph by substituting π = 10 in the equation above.
g = 40/m
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The change in internal energy of a system is -5.155 kJ. The system absorbs 2500 J of heat.
Which of the following BEST describes the work related to the system?
A The system performs 7.655 kJ of work on the surroundings.
B The system has 7.655 kJ of work done by the surroundings.
C The system has 2.655 kJ of work done by the surroundings.
D The system performs 2.655 kJ of work on the surroundings.
The work done by the system is -2.655KJ. This states that the system performs 2.655KJ of work on the surroundings. Thus, the correct option is D.
What is work done?Work done is defined as the product of force and the distance over which the force is applied on the object. Work is done when a force is applied to an object and the object experiences motion through a distance.
Given that the work is done on the surrounding, i.e., the work is done by the system and the heat is absorbed by the system.
Therefore,
ΔU = -5.155KJ
q = 2500J = 2.5KJ
Now from first law of thermodynamics,
ΔU = q + w
-5.155 = 2.500 + w = -2.655KJ
w = -2.655KJ
Hence the work done is -2.655kJ.
Therefore, the system performs 2.655KJ of work on the surroundings. The correct option is D.
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traits of successful entrepreneurs
There are some traits of successful entrepreneurs, these are as follows:
1. He should be a highly motivated towards the work.
2. He sholud be creative in nature. He should think out of box and develop some ideas for the problem.
3. He should have clear vision for the future.
4. He should be very versatile and ready to adapt any changes.
5. He should be ready to take some risk.
6. He should have the ability of decision making and leadership quality.
A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting
from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,
and air resistance can be ignored. Find
a) the maximum height above the ground the rocket reaches
Answer:
The maximum height above the ground the rocket reaches is 123.1 m.
Explanation:
Let's find the final velocity at a distance of 200 m:
\( v_{f}^{2} = v_{0}^{2} + 2ad \)
Where:
\(v_{f}\) is the final speed =?
v₀ is the initial speed =0
a is the acceleration = 1.25 m/s²
d is the distance = 200 m
\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)
Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:
\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)
Where:
\(v_{f}\) = 0
\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)
Finally, the maximum height above the ground is:
\( h_{max} = h + H \)
Where H is the vertical component of the 200.0 meters.
\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)
Therefore, the maximum height above the ground the rocket reaches is 123.1 m.
I hope it helps you!
in what direction is the earth's angular velocity for its daily rotation on its axis
The Earth's angular velocity for its daily rotation on its axis is in the counterclockwise direction (eastward).
The Earth's angular velocity for its daily rotation on its axis is in the eastward direction. From above, this movement would look like the Earth is moving counterclockwise. This means that the Earth rotates from west to east, causing the sun to appear to rise in the east and set in the west. This is also why time zones are arranged with earlier times to the east and later times to the west. The Earth's rotation on its axis is what causes the cycle of day and night.
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The Enterprise wants to orbit a4.15 x 10^24kg planet with a period of14100 s. What should the radius oftheir orbit be?
Given:
Mass of planet, m = 4.15 x 10²⁴ kg.
Period, T = 14100 s
Let's find the radius.
To find the radius, apply the formula from Kepler's Third aw:
\(\begin{gathered} \frac{T^2}{R^3}=\frac{4\pi^2}{GM} \\ \\ \end{gathered}\)Where R is the radius.
Rewrite the formula for r:
\(R=\sqrt[3]{\frac{GM*T^2}{4\pi^2}}\)Where:
G is gravitational constant = 6.67 x 10⁻¹¹ m3 kg-1 s-2
M is the mass = 4.15 x 10²⁴ kg
T is the period = 14100 s
π = 3.54
Plug in values and solve for R;
\(\begin{gathered} R=\sqrt[3]{\frac{6.67\times10^{-11}*4.15\times10^{24}*14100^2}{4\pi^2}} \\ \\ R=\sqrt[3]{\frac{5.503\times10^{22}}{39.4784}} \\ \\ \end{gathered}\)Solving further:
\(\begin{gathered} R=\sqrt[3]{1.394\times10^{21}} \\ \\ R=11170796.49\approx1.12\times10^7\text{ m} \end{gathered}\)Therefore, the orbital radius will be 1.12 x 10⁷ meters.
ANSWER:
1.12 x 10⁷ m
PLEASE HELP urgently!!!
1.The initial volume of a gas at a pressure of 5 atm is 3.5 L. What will the volume be if the pressure is increased to 6 atm?
Include units.
2. A gas is contained in a 4 L container at a pressure of 2 atm. The container is at a temperature of 15 degrees Celsius. What will the pressure be if the temperature is increased to 30 degrees Celsius?
Include units.
3. Calculate the decrease in temperature when 6.00 L of gas at 20.0 °C is compressed to 4.00 L.
Include units.
4. A 40.0 L tank of ammonia has a pressure of 5.5 atm. Calculate the volume of the ammonia if its pressure is changed to 8.2 atm while its temperature remains constant.
5. Determine the pressure change when a constant volume of gas at 1.5 atm is heated from 18 °C to 32 °C.
Taking into account the Boyle's law, Charles's law and Gay-Lussac's law, you get:
If the pressure is increased to 6 atm, the volume will be 2.92 L.If the temperature is increased to 30 degrees Celsius, the pressure will be 2.104 atm.When 6.00 L of gas at 20.0 °C is compressed to 4.00 L, the temperature will be 195.33 K.If its pressure is changed to 8.2 atm while its temperature remains constant, the volume will be 52.38 L.At 32°C, the pressure will be 1.43 atm.Boyle's lawBoyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as
P×V=k
Considering an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁=P₂×V₂
Charles's LawCharles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas.
This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases: the volume is directly proportional to the temperature of the gas.
Charles's law is expressed mathematically as:
V÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
V₁÷T₁=V₂÷T₂
Gay-Lussac's law
Gay-Lussac's law determines that gas pressure is directly proportional to its temperature when the volume is constant: when there is a constant volume, when the temperature increases, the gas pressure increases and when the temperature decreases, the gas pressure decreases.
Gay-Lussac's law is expressed mathematically as:
P÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
P₁÷T₁=P₂÷T₂
Exercise 1In this case, you know:
P₁= 5 atmV₁= 3.5 LP₂= 6 atmV₂= ?Replacing in the Boyle's law:
5 atm× 3.5 L= 6 atm×V₂
(5 atm× 3.5 L)÷ 6 atm= V₂
2.92 L= V₂
Finally, the volume will be 2.92 L.
Exercise 2In this case, you know:
T₁= 15°C= 288 KP₁= 2 atmT₂= 30°C= 303 KP₂= ?Replacing in Gay-Lussac's law:
2 atm÷ 288 K=P₂÷ 303 K
(2 atm÷ 288 K)× 303 K=P₂
2.104 atm= P₂
Finally, the pressure will be 2.104 atm.
Exercise 3In this case, you know:
V₁= 6 LT₁= 20 C= 293 KV₂= 4 LT₂= ?Replacing in Charles's law:
6 L÷293 K=4 L÷T₂
(6 L÷293 K)× T₂= 4 L
T₂= 4 L÷ (6 L÷293 K)
T₂= 195.33 K
Finally, the temperature will be 195.33 K.
Exercise 4In this case, you know:
P₁= 5.5 atmV₁= 40 LP₂= 8.2 atmV₂= ?Replacing in the Boyle's law:
5.5 atm× 40 L= 8.2 atm×V₂
(5.5 atm× 40 L)÷ 8.2 atm= V₂
52.38 L= V₂
Finally, the volume will be 52.38 L.
Exercise 5In this case, you know:
T₁= 18°C= 291 KP₁= 1.5 atmT₂= 32°C= 305 KP₂= ?Replacing in Gay-Lussac's law:
1.5 atm÷ 291 K= P₂÷ 305 K
(1.5 atm÷ 291 K)× 305 K=P₂
1.43 atm= P₂
Finally, the pressure will be 1.43 atm.
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An airplane accelerates down a runmway at 2.9 m/s/s for 38.5 seconds
until if lifts off the ground. Determine the distance traveled on the runway
before taking off. (Answer to the nearest one's place. Enter only the
number of meters, no units) *
Distance be s
\(\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2\)
\(\\ \sf\longmapsto s=0(38.5)+\dfrac{1}{2}(2.9)(38.5)^2\)
\(\\ \sf\longmapsto s=1.45(1482.25)\)
\(\\ \sf\longmapsto s=2149.26m\)
Use the drop-down menus to complete the sentences describing what happens when the temperature of a fluid
ncreases.
The kinetic energy of the molecules
The speed of the molecules
The density of the fluid
The fluid
Answer:
The kinetic energy of the molecules increases as it heats up causing it to vibrate faster and faster.
Explanation:
mechanical energy that has been "lost" to friction has actually been destroyed.
Answer:
Yes
Explanation:
The friction is bigger than the mechanical energy so it kind off takes over the mechanical energy. but if the friction decreases mechanical energy can work on the object again
A bird is standing on an electric transmission line carrying a large amount of current. Find the power dissipated by the bird If the
current it experiences is 1.35^-10 A which results in a potential difference of .0054V.
Side Note:
(I know the answer is 7.3 x 10^-11 W, I just don’t know how to get it)
P = 7.3 × 10^-13 Watt
Explanation:
First of all, are you sure that what you have is the right answer?
Anyway, the definition of power dissipated is given by
P = I^2×R
where I is the current and R is the resistance. But we also know from Ohm's law that
V = IR
so we can rewrite the equation for power P as
P = I^2R = I(IR) = VI
= (0.0054 volt)(1.35 × 10^-10 A)
= 7.3 × 10^-13 Watt
25)
In which state of matter has the LEAST kinetic energy?
A)
gas
B)
liquid
plasma
solid
Answer:
its Solid
Explanation:
Molecules in the solid phase has the least amount of energy, while the gas particles has the greatest amount of energy.
Answer:
Solid
Explanation:
Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.
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the acceleration of an object is due to the net force on the object and the objects?
Answer:
The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.
Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?
Eris takes about 557 Earth years to orbit the Sun. It has a mean surface temperature of about 40 Kelvin. It has a nearly spherical shape. It has several other objects in its orbit, though few are as massive as itself. Eris is too far away and small to be clearly visible from the Earth. Scientists used its moon, Dysnomia, to measure it. Eris is believed to be slightly more massive than Pluto. However, both of them are smaller than Earth’s Moon. Eris orbits the Sun directly; it is not a satellite of another planet or dwarf planet.
Answer:
It has several other objects in its orbit, though few are as massive as itself."
The ratio of carbon-14 to nitrogen-14 in an artifact is 1:7. Given that the half-
life of carbon-14 is 5730 years, how old is the artifact?
A. 5730 years
B. 22,920 years
C. 11,460 years
D. 17,190 years
Answer:
17,190 years old
Explanation:
D
PLEASE HELP!!!! An 85 kg snowboarder accidentally goes off trail and ends up in the middle of a frozen lake and comes to a stop. He remembers taking physics and learning about conservation of momentum in high school and decides to take off his 10 kg backpack
and throw it as hard as he can since he won't need it from being so smart for passing physics) at a speed of 6 m/s East. At what speed and direction will the snowboarder move after throwing the bag?
Okay, so the snowboarder weighs 85 kg and his backpack weighs 10 kg. He throws the backpack with a speed of 6 m/s to the East.According to the law of conservation of momentum, the total momentum before he throws the backpack is 85 kg * 0 m/s (since he's at rest) and the total momentum after he throws the backpack is 85 kg * x m/s + 10 kg * 6 m/s (since the backpack is moving East with a speed of 6 m/s).To find the snowboarder's new speed and direction, we have to set the total momentum before and after equal to each other and solve for x. So,85 kg * 0 m/s = 85 kg * x m/s + 10 kg * 6 m/sWe can solve for x by subtracting 10 kg * 6 m/s from both sides and dividing by 85 kg.x = -0.7143 m/sSo the snowboarder will move with a speed of -0.7143 m/s (which means he will move in the opposite direction of the backpack) and he will move west.
What is the acceleration of a car with the mass of 1’980 kg if it experiences a net horizontal force of 1’000 N
Answer:
See below
Explanation:
For the, just remember the equation
F = m a
1000 N = 1980 kg * a
1000/1980 = a = .505 m/s^2