The final results is : 34,5%
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\(\begin{bmatrix}{1} & {2} & {3} \\ {5} & {4} & {5} \\ {4} & {4} & {5}\end{bmatrix}\)
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What is the term used when a ball is hit and the batter reaches the following bases safely (without being called out)?
please help me
a) first base
b)second base
c)third base
d) homerun
A roller coaster car is released from rest as shown in the image below. If
friction is neglected, the car will oscillate back and forth across the "dip" in
the roller coaster. What is the approximate velocity of the roller coaster car
each time it reaches the bottom of the roller coaster in the image? (Recall
that g = 9.8 m/s2.)
TAS
81 m
O A. 40 m/s
B. 25 m/s
C. 30 m/s
D. 15 m/s
Answer:
40m/s
Explanation:
a=g
u=0
s=81
v²=u²+2as
v²=2(9.81)(81)
v=√1587.6=39.8446985181≈40m/s
The velocity of the roller coaster car each time it reaches the bottom is 40 ms⁻¹. The correct option is (A).
The rate at which the position of an object changes with respect to time is described by the physical quantity known as velocity. It has both magnitude and direction because it is a vector quantity.
Given:
Initial velocity, u = 0 m/s
Acceleration, a = -9.8 ms⁻²
Distance, d = 81 m
From the third equation of motion:
v² = u² - 2as
v² = 0 - 2×(-9.8)×81
v = 40 ms⁻¹
Hence, the velocity of the roller coaster car is 40 ms⁻¹. The correct option is (A).
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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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Stephen is worried he has a fever. His dad is a scientist though and only has thermometer that measures in kelvin and is measured stephen’s temperature to be 312 kelvin. If stephens temperature is above 100 f he isn’t allowed to go to school. Can Stephen go to school today?
Answer: im trying to find the same answer too
Explanation
Stephens's temperature would be 101.93 Fahrenheit, therefore he can't go to school today.
What is the kelvin scale of temperature?
It is a scale of temperature used to measure the temperature, the kelvin scale of temperature is also known as the absolute scale of temperature.
It is impossible to have kelvin temperature in a negative value.
As given in the problem Stephen is worried he has a fever. His dad is a scientist though and only has a thermometer that measures in kelvin and measured Stephen's temperature to be 312 kelvin. If Stephens's temperature is above 100 f he isn’t allowed to go to school.
312 kelvin converted in Fahrenheit would be 101.93 Fahrenheit.
(312K − 273.15) × 9/5 + 32 = 101.93°F
Thus, Stephen Can't go to school today.
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According to the big bang theory, what was the big bang?
А.
A giant explosion, after which all of the energy and matter in the universe began moving agan
О
В.
A giant supernova explosion that created all of the elements on Earth
C. A collision between early Earth and a massive asteroid that resulted in the formation of the moon
O
D. The inward collapse of a huge nebula that formed the solar system
A cyclist starts at rest and accelerates at 0.5 m/s2 south for 20 s. What is the cyclist’s final velocity
The cyclist's final velocity is 10 m/s.
From the question,
We are to determine the cyclist's final velocity.
Linear motionFrom one of the equations of motion for linear motion, we have
\(v=u+at\)
Where
v is the final velocity
u is the initial velocity
a is the acceleration
and t is the time
From the given information,
The cyclist starts at rest, this means the initial velocity is 0 m/s
That is,
u = 0 m/s
Also
a = 0.5 m/s²
and t = 20 s
Putting the parameters into the equation, we get
\(v = 0 + 0.5 \times 20\)
\(v = 0 + 10\)
\(v = 10 \ m/s\)
Hence, the cyclist's final velocity is 10 m/s.
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We intend to measure the open-loop gain (LaTeX: A_{open}A o p e n ) of an actual operational amplifier. The magnitude of LaTeX: A_{open}A o p e n is in the range of 106 V/V. However, the signal generator in measurement setup can supply minimal voltage of 1 mV, and the oscilloscope used at amplifier output can measure maximal voltage level of 10 V. Can you design a simple measurement setup using this signal generator and oscilloscope, and accurately measure the LaTeX: A_{open}A o p e n
Answer:
voltage divider, R₂ = 1000 R₁
measuring the output in the resistance R₁
Explanation:
Let's analyze the situation, in an op amp in open gain loop, the gain is maximum G = 10⁶ V / V
in this case the signal generator gives a minimum wave of 1 10⁻³ V, after passing through the amplified it becomes 10³ V which saturates the oscilloscope.
To solve this problem we must use a simple voltage divider, for this we use the fact that in a series circuit the voltage is the sum of the voltages of each element.
If we use two resistors whose relationship is
R₂ / R₁ = 10³
R₂ = 1000 R₁
When measuring the output in the resistance R₁ we have the desired divider, with a tolerance range, for the minimum output of the generator (1 10⁻³V) we have a reading of V = 1 V in the oscilloscope, for which we can use voltage up to 10V on the generator
At what speed does light travel through water. n=1.33
Answer:
"In water, the speed of light is v01.33=2.26 x 108 m/s."
Explanation:
Describe what is required for work to be considered done by a physicist. Give an example in two or more complete sentences.
For work to be considered done by a physicist, it must involve the application of physics principles and concepts to solve a problem or answer a research question. This can involve theoretical work, such as mathematical modeling, or experimental work, such as designing and conducting experiments to test hypotheses.
An example of work done by a physicist would be the design and analysis of experiments to study the properties of a new material. This could involve developing a theoretical model to predict the behavior of the material, designing and building experimental apparatus, conducting experiments, and analyzing the resulting data using statistical and mathematical techniques. The physicist would use their knowledge of physics principles and concepts to interpret the data and draw conclusions about the properties of the material.
Which of the following statements is true.
a. Gravity is a force dependent on mass and force.
b. Gravity is a force dependent on mass and distance.
C. No Gravity is a force dependent on speed and force.
d. Gravity is a force dependent on force and distance.
Convert the following statement to the language used by physicists, "I am cold, please turn on the heat."
Answer:
Explanation:fog
1. Would a cart that has four solid disks for wheels have a final speed that is greater than, less than, or equal to the final speed of a single disc that has the same mass as the cart and
wheels? Explain.
2. Suppose a cart with four wheels and a disk whose mass is equal to the total mass of the cart roll down the ramp. Which, if either, has more gravitational potential energy at the top?
3. Which of those objects has more kinetic energy at the bottom? Why?
4. Imagine the disk just spinning in place instead of rolling, would it have kinetic energy? Why?
5. Why does the cart have more speed at the bottom even though it doesn't have more kinetic energy than the disk?
The final speed would be equal because they don't depend on the mass or the radius.
What variables affect kinetic and potential energy, respectively?The mass, gravitational pull, and height above the earth all affect how much potential energy an item has. This energy is transformed into kinetic or indeed the change in momentum, when you fall the thing. An object's mass and speed affect its kinetic energy.
What three variables determine kinetic energy?The quantity of work performed on an object as well as its velocity following an inertia moment caused by external forces are two aspects that affect the overall kinetic energy about an object. The most crucial variables that affect kinetic energy are the motion calculated in terms of the object's mass and velocity.
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10 POINTS! SPACE QUESTION!!
Answer; they are larger and made of rocky material
6. What is the complete spectrum of all forms of light?
a. galaxy
b. electromagnetic spectrum
C. energy
d. system
Answer:
b. the electromagnetic spectrum
Explanation:
the electromagnetic spectrum contains all the forms of light, including gamma rays, x-rays, ultraviolet radiation, visible light, infrared, radio waves, microwaves, etc
A student connects an object with mass m to a rope with a length r and then rotates the rope around her head parallel to the ground. The object takes 0.5 seconds to complete one rotation.
Mass = 50 gLength of rope = 1.2 m
a) What is the object’s speed of rotation?
b) What is the object’s centripetal acceleration?
c) What tension force is required to maintain this motion?
Answer:
(a) ω = 12.57 rad/s
(b) a = 189.5 m/s²
(c) T = 9.47 N
Explanation:
(a)
The speed of rotation is given by the formula:
ω = θ/t
where,
ω = speed of rotation = ?
θ = angular displacement = (1 rotation)(2π rad/1 rotation) = 2π rad
t = time taken = 0.5 s
Therefore,
ω = 2π rad/0.5 s
ω = 12.57 rad/s
(b)
The centripetal acceleration of the object is given by the formula:
a = v²/r
where,
a = Centripetal Acceleration = ?
v = linear speed of object = rω
r = length of rope = 1.2 m
Therefore,
a = (rω)²/r
a = rω²
a = (1.2 m)(12.57 rad/s)²
a = 189.5 m/s²
(c)
The tension required to maintain the motion is equal to the centripetal force:
Tension = Centripetal Force
T = ma
where,
m = mass of object = 50 g = 0.05 kg
Therefore,
T = (0.05 kg)(189.5 m/s²)
T = 9.47 N
How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
Solution :-
Given that ,
Initial Velocity of car = 44km / hr.Final Velocity of car = 0km / hr.Acceleration = -5km/hr².To Find :
Time taken to stop the car .So , here use first equⁿ of motion which is ,
\(\boxed{\red{\bf\dag v = u + at }}\)
where ,
v is final Velocity.u is Initial velocity.a is acceleration.t is time taken.Now , substituting the respective values ,
\(\tt:\implies v=u+at\)
\(\tt:\implies 0 = 44 + (-5)t\)
\(\tt:\implies -44 = -5t \)
\(\tt:\implies t=\dfrac{44}{5}\)
\(\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}\)
\(\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}\)
A corpse is discovered in a room that has its temperature held steady at 25oC. The CSI ocers ar- rive at 2pm and the temperature of the body is 33oC. at 3pm the body's temperature is 31oC. Assuming Newton's law of cooling and that the temperature of the living person was 37oC, what was the approximate time of death
Answer: Around 0:35 Pm or 12:35 Am
Explanation:
The equation that describes the cooling of objects can be written as:
T(t) = Ta + (Ti - Ta)*e^(k*t)
Where Ta is the ambient temperature, here Ta = 25°C.
Ti is the initial temperature of the body, we have Ti = 37°C.
t is the time.
k is a constant.
So our equation is:
T(t) = 25°C +12°C*e^(k*t)
at 2pm, the temperature was 33°C
at 3pm, the temperature was 31°C.
we want to find the hour where we have our t = 0, suppose this hour is X.
then we can write our times as:
2pm ---> 2 - X
3pm ----> 3 - X
and our equations are:
33°C = 25°C + 12°C*e^(k2 - k*X)
31° = 25°C + 12°C*e^(k3 - k*X)
So we have two equations and two variables, let's solve the system.
first, simplify it a bit, for the first eq:
33 - 25 = 12*e^(k2 - k*X)
8/12 = e^(k2 - k*X)
ln(8/12) = k*2 - k*X
for the second equation we have:
31 - 25 = 12*e^(k3 - k*X)
6/12 = e^(k3 - k*X)
ln(6/12) = k*3 - k*X
So our equations are:
1) ln(2/3) = 2*k - X*k
2) ln(1/2) = 3*k - X*k
First, let's isolate one of the variables in one of the equations. let's isolate k in the first equation.
ln(2/3)/(2-X) = k
now we can replace it in the second equation:
ln(1/2) = 3*ln(2/3)/(2 - X) - X*ln(2/3)/(2-X)
now let's solve it for X, i will take a = ln(1/2) and b = ln(2/3) so it is easier to read.
a = 3*b/(2 - X) - X*b/(2 - X)
a*(2 - X) = 3*b - X*b
2a - aX = 3b - Xb
X(a - b) = 2a - 3b
X = (2*ln(1/2) - 3*ln(2/3))/(ln(1/2) - ln(2/3)) = 0.590
now, knowing that one hour has 60 minutes, then this is:
0.59*60m = 35 minutes
So the hour of death is 0:35 Pm or 12:35 Am
which object has a weight of about 22.5 n the book the rock the box the fish
Answer: The rock
Explanation:
How does solar weather affect Earth’s magnetosphere? Select the two correct answers.
It causes geomagnetic storms.
It generates auroras.
It develops solar wind.
It forms radiation belts.
6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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Now you will focus on a second hypothesis. This hypothesis can be very similar to the first, but this time you want to focus only on the second variable in question, speed. What could be a hypothesis that would illustrate the relationship between speed and kinetic energy? Use the format of "if…then…because…” when writing your hypothesis
Answer:
Sample Response: If the speed of an object increases, then its kinetic energy will increase proportionally because speed and kinetic energy have a linear relationship when graphed.
Explanation:
edge
An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in the first 3.00μs3.00μs after it is released. (a) What are the magnitude and direction of the electric field? (b) Are we justified in ignoring the effects of gravity? Justify your answer quantitatively.
Answer:
Explanation:
A. Using
E= ma/q
E=m/q(2s/t²)
So
E= 9.1x10^-31/1.6*10^-19( 2*4.5/ 3*10-12)
E=5.7NC
The electric field has to be downward since the force is positive that is upward
B.
The electron acceleration is of the order of 10^11 times greater so for practical purposes we neglect the effect of gravity
A model airplane with mass 1.3 kg hangs from a rubber band with spring
constant 20 N/m. How much is the rubber band stretched when the model
hangs motionless?
O A. 0.082 m
B. 0.64 m
O C. 0.78 m
O D. 0.23
Answer:
it's b
a\p\e\x\
Explanation:
An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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The wave equation says that a waves __ is equal to its wavelength times is frequency.
Answer:
speed
Explanation:
The wave equation says that a waves speed is equal to its wavelength times is frequency.
A 1.0-kg cart and a 0.50-kg cart sit at different positions on a low-friction track. You push on the 1.0-kg cart with a constant 4.0-N force for 0.20 m. You then remove your hand, and the cart slides 0.35 m and strikes the 0.50-kg cart. What is the work done by you on the two-cart system? How far does the system's center of mass move while you are pushing the 1.0-kg cart? By what amount does your force change the kinetic energy of the system's center of mass?
Answer:
a)\(W=0.8J\)
b) \(d_t=0.20m\)
c) \(\triangle K.E=0.267J\)
Explanation:
From the question we are told that:
Mass of cart 1 \(M_1=1.0kg\)
Mass of cart 1 \(M_2=0.05kg\)
Force on cart 1 \(F_1=4.0N\)
Push Distance of cart 1 \(d_1=0.20m\)
Slide Distance of cart 1 \(d_1'=0.35m\)
a)
Generally the equation for work-done is mathematically given by
\(W=f*d\\W=4*0.20\\W=0.8J \\\)
b)
The systems center of mass moved a net totally of (while being pushed)
Mass 1 =0.20m
Mass 2=0
Therefore
\(d_t=d_1+d_2\)
\(d_t=0.20+0\)
\(d_t=0.20m\)
c)
Since work-done is equal to K.E energy of cart 1
Therefore
\(W=1/2mv^2\)
\(V_1=\sqrt{\frac{W}{1/2m}}\)
\(V_1=\sqrt{\frac{0.8}{1/2(1)}}\)
\(V_1=1.264\)
Therefore Kinetic energy before collision is
\(K.E_1=1/2mv^2\)
\(K.E_1=1/2*1*1.264^2\)
\(K.E_1=0.768\)
Generally from the equation for conservation of momentum the Velocity of cart 2 is mathematically given by
\(v_2=\frac{m_1V_1}{m_1+m_2}\)
\(v_2=\frac{1*1.264}{1+0.5}\)
\(V_2=0.842m/s\)
Therefore the final K.E is mathematically given by
\(K.E_2=(1/2)(m_1+m_2)V_2^2\)
\(K.E_2=1/2*(1.5)(0.842)^2\)
\(K.E_2=0.531J\)
Generally the Change in K.E is mathematically given by
\(\triangle K.E=K.E_1-K.E_2\)
\(\triangle K.E=0.798-0.531\)
\(\triangle K.E=0.267J\)
Therefore the will force change the kinetic energy of the system's center of mass by
\(\triangle K.E=0.267J\)
(a) The work done by you when you push the cart at a constant force is 0.8 J.
(b) The distance moved by the center mass of the two cart system is 0.23 m.
(c) The change in kinetic energy of the system center of mass is 0.271 J.
Work done by you
The work done by you when you push the cart at a constant force is calculated as follows;
W = Fd
W = 4 x 0.2
W = 0.8 J
Distance moved by the center mass of the two cart systemlet the 0.5 kg mass be the reference mass at zero (0).Xcm = (m₁x₁ + m₂x₂)/(m₁ + m₂)
Xcm = (0.5(0) + 1(0.35)) / (1 + 0.5)
Xcm = (0.35)/(1.5)
Xcm = 0.23 m
Initial velocity of the 1.0 kg massF = ma
a = F/m
a = (4)/1 = 4 m/s²
v² = u² + 2as
v² = 0 + 2(4)(0.2)
v² = 1.6
v = √1.6
v = 1.265 m/s
Final velocity of the massesm₁u₁ + m₂u₂ = v(m₁ + m₂)
1(1.265) + 0 = v(1 + 0.5)
1.265 = 1.5v
v = 0.84 m/s
Change in kinetic energyK.E(initial) = ¹/₂m₁u₁² + ¹/₂m₂u₂²
K.E(initial) = ¹/₂(1)(1.265)² + ¹/₂(0.5)(0) = 0.8 J
K.E(final) = ¹/₂(m₁ + m₂)v²
K.E(final) = ¹/₂(1 + 0.5)(0.84)² = 0.529 J
Δ K.E = 0.8 J - 0.529 J = 0.271 J
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Please help
1. Who was Ptolemy and Copernicus?
2. Describe their ideas about the planets and the sun
Answer:
1 +2=3 so thats it
Explanation:
Because i need points
A doubly ionized lithium atom is in the ground state. It absorbs energy and makes transition to the n = 5 excited state. The ion returns to the ground state by emitting several photons. What is the wavelength of the highest energy photon?
The wavelength of highest photon energy is 0.544J.
Use the equation to calculate the electron's energy in the nth orbit. Calculate the energies of the first and third Bohr orbits to determine the amount of energy needed to excite the electron. The wavelength of a photon can be calculated using the photon energy formula. Check how many different routes an excited electron can take to reach its ground state, the first Bohr orbit.\(E=-\frac{13.6}{y^2}\)E=-13.6/5²=0.544 JTo study about ground state -
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A very long wire carries an unknown current. At a distance of 30 cm from the wire, the magnitude of the magnetic field is found to be 40 uT. What is the magnitude of the current flowing in the wire?
Given that the distance from the wire is r = 30 cm = 0.3 m
The magnitude of the magnetic field is
\(\begin{gathered} \text{B = 40}\mu T \\ =4\times10^{-5}\text{ T} \end{gathered}\)We have to find the magnitude of the current.
The formula to find the magnitude of the current is
\(\begin{gathered} B=\text{ (}\frac{\mu_o}{4\pi}\text{)}\times\frac{2I}{r} \\ B\text{ = }\frac{4\pi\times10^{-7}}{4\pi}\times\frac{2I}{r} \\ I=\text{ }\frac{Br}{2}\times10^7\text{ } \end{gathered}\)Substituting the values, the current will be
\(\begin{gathered} I\text{ =}\frac{4\times10^{-5}\times0.3}{2}\times10^7 \\ =\text{ 60 A} \end{gathered}\)Thus, the magnitude of current is 60 A
A ball dropped from a window strikes the ground at 4.00 s later. How high is the window above the ground?
Answer:
15
Explanation: