What is a non-example of Newton's 3rd law of motion?

The transfer of thermal energy that Ilva is experiencing is known as radiation. Radiation is the transfer of heat energy through electromagnetic waves that do not require a medium to travel through. In this scenario, the boiling water and stove are emitting infrared radiation which is absorbed by Ilva's body, causing her to feel the heat. Additionally, convection and conduction are two other methods of transferring thermal energy. Convection is the transfer of heat energy through the movement of fluids, while conduction is the transfer of heat energy through direct contact between two objects. However, in this scenario, radiation is the primary method of thermal energy transfer that Ilva is experiencing.
Ilva is standing a few feet away from boiling water, and she feels the heat from the boiling water and the stove. The term that describes this transfer of thermal energy is "radiation." Radiation is the process through which thermal energy is transferred through electromagnetic waves without the need for direct contact or a medium like air or water. In this scenario, the heat from the boiling water and the stove radiates outwards and reaches Ilva, allowing her to feel the warmth. This form of heat transfer is why you can feel the heat from a fire or a hot object without touching it directly.

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The term that describes the transfer of thermal energy that Ilva feels from the boiling water and the stove is radiation.


Radiation is the transfer of thermal energy through electromagnetic waves. Unlike conduction and convection, radiation does not require a medium (such as a solid, liquid, or gas) to transfer heat. Instead, it can transfer energy through empty space or air.

In Ilva's situation, the heat she feels from the boiling water and the stove is primarily due to the infrared radiation emitted by these hot objects. As the electromagnetic waves reach her, they transfer the thermal energy to her body, making her feel the warmth even though she is standing a few feet away from the heat source.

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The production function will have constant returns to scale if 2αβ = 1

Constant returns to scale (CRS) implies that if all inputs increase by a factor of λ, the output increases by λ as well. The requirement for constant returns to scale (CRS) in a Cobb-Douglas production function with a new input factor is given by the sum of exponents on all variables equal to 1.

In this case, Y = AKαLβMγ.

Thus, we have that α + β + γ = 1 for constant returns to scale in K, L, and M, because the sum of the exponents is 1.

If the sum of the exponents is less than 1, it indicates decreasing returns to scale. If the sum of the exponents is greater than 1, it indicates increasing returns to scale. If we take γ = 0, we obtain the production function used in class, which is Y = AKαLβ, thus α + β = 1 for constant returns to scale in K and L.

When γ = 0, the answer we get is consistent with what we learned in class. Now, we consider the constant elasticity of substitution (CES) technology, where Y = [aKα + bLα]β. The production function will have constant returns to scale (CRS) in K and L if the sum of the exponents of K and L is equal to 1.

Therefore, αβ + αβ = 1, implying 2αβ = 1.

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The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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Answer:

that the earth isnt flat

Explanation:

According to the given statement 2.5 m/s is the final velocity of the truck.

Velocity is the pace and path of an item's movement, whereas speed is really the time rate that a object is travelling along a route. In other words, velocity is a vector, whereas speed is a scalar number. as the pace of a car driving south on a highway or the pace at which a rocket takes off.

Collision energy equals collision energy before collision

Afterward, we would have;

(400 * 20) + (50 * 2) = (50 * 142) + (400 * v)

8000 + 100 = 7100 + 400v

8100 - 7100 = 400v

v = 1000/400

v = 2.5 m/s

According to our estimation, the velocity is 2.5 m/s.

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According to the given statement 2.5 m/s is the final velocity of the truck.

Velocity is the pace and path of an item's movement, whereas speed is really the time rate that a object is travelling along a route. In other words, velocity is a vector, whereas speed is a scalar number. as the pace of a car driving south on a highway or the pace at which a rocket takes off.

Collision energy equals collision energy before collision

Afterward, we would have;

(400 * 20) + (50 * 2) = (50 * 142) + (400 * v)

8000 + 100 = 7100 + 400v

8100 - 7100 = 400v

v = 1000/400

v = 2.5 m/s

According to our estimation, the velocity is 2.5 m/s.

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When you place an extremely small almost point source of light at the primary focal point of a parabolic mirror, the reflected wave front will be a plane wave.

This plane wave is characterized by parallel wavefronts. The focal point of a parabolic mirror is defined as the point on the principle axis at which parallel light rays converge when they are parallel to the principle axis.

According to the principles of reflection, all light rays incident on a parabolic mirror are reflected such that they converge at the focal point. In the case of a point source of light positioned at the focal point of a parabolic mirror, all the light rays coming from that point are reflected in a parallel fashion. The wavefronts of the reflected light are thus parallel, resulting in a plane wavefront.

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The magnitude of dog's displacement vector in the due west direction is 0.65 km.

It is given that, a dog walks 0.64km due north.

It is also given that the magnitude of dog's total displacement is 0.91 km.

The magnitude of dog's displacement vector in the due west direction can be found by using Pythagoras theorem.

It is mathematically represented as, c² = a² + b²

Given, c = 0.91 km

a = 0.64 km

b =?

Making b as subject, we have,

b² = c² - a²

b = √(c² - a²) = √(0.91² - 0.64²) = 0.65 km

Thus, the magnitude of dog's displacement vector in the due west direction is 0.65 km.

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Answer:

True

Explanation:

The main differences between a physical property and a chemical property are mentioned below:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points.

While A chemical property describes the ability of a substance to undergo a specific chemical change.

Visible light, ultraviolet rays, and X-rays are all forms of electromagnetic radiation, with differences in their wavelengths, frequencies, and energies.

Visible light is the part of the electromagnetic spectrum that human eyes can perceive. It has a wavelength range of 400-700 nanometers, with violet having the shortest wavelength and red having the longest. Visible light can be refracted, reflected, and diffracted, and it can be split into its component colors using a prism.

Ultraviolet (UV) rays have shorter wavelengths and higher frequencies than visible light. They have wavelengths between 10-400 nanometers. UV radiation is classified as UVA, UVB, and UVC, with UVC having the shortest wavelength and highest energy. UV rays can cause damage to DNA and can cause sunburn and skin cancer.

X-rays have even shorter wavelengths and higher frequencies than UV rays. X-rays have wavelengths between 0.01-10 nanometers. They can penetrate through materials that visible light and UV radiation cannot, such as body tissues and bones, making them useful in medical imaging. X-rays are also produced in outer space and can be used to study the universe.

In summary, the main differences between these types of electromagnetic radiation are their wavelengths, frequencies, and energies, which determine their properties and potential applications.

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The Hall-Taylor criterion for flooding can be given by the expression, y = 0.074 [ (ρL /ρV) (σ /ρL gD) ]0.25

where, y is the maximum permissible liquid flow rate per unit cross-sectional area,

ρL is the density of the liquid,

ρV is the density of the vapour,

σ is the surface tension of the liquid,

D is the diameter of the tube,

and g is the gravitational acceleration.

The given details are,

Vapour flow rate, Q = 8,000 kg/h

Liquid flow rate, L = 7,000 kg/h

Pressure, P = 1 bar

Inner diameter of the tube, d = 50 mm

Boiling point of benzene, ρL = 840 kg/m³

Density of the vapour phase benzene, ρV = 2.7 kg/m³

Surface tension of benzene, σ = 0.0285 N/m

The gravitational acceleration, g = 9.81 m/s²

Diameter of the tube, D = 50 mm = 0.05 m

As the given parameters are in kg/h, we need to convert them into kg/s.

To convert kg/h to kg/s, we need to divide the given values by 3600 kg/h = 8,000 / 3600 = 2.22 kg/s

Liquid flow rate, L = 7,000 / 3600 = 1.94 kg/s

From the given details,ρL = 840 kg/m³ρV = 2.7 kg/m³σ = 0.0285 N/mg = 9.81 m/s²D = 0.05 m

Substituting these values in the above equation, the Hall-Taylor criterion for flooding can be given by,

y = 0.074 [ (840 / 2.7) (0.0285 / 840 × 9.81 × 0.05) ]0.25y = 0.0049 m³/s/m²

Now, the liquid flow rate per unit cross-sectional area is given by,L / A = y

where, A is the cross-sectional area of the tube.

As the tube is of 50 mm diameter, the cross-sectional area can be given by,

A = πD² / 4A = π (0.05)² / 4A = 1.963 × 10⁻⁴ m²

The maximum permissible liquid flow rate per unit cross-sectional area is given by,L / A = 0.0049L = 0.0049 × A

Thus, L = 0.0049 × 1.963 × 10⁻⁴L = 9.61 × 10⁻⁷ m³/s

The given liquid flow rate is, L = 1.94 kg/s = 0.00194 m³/s

The maximum permissible liquid flow rate per unit cross-sectional area, L / A = 9.61 × 10⁻⁷ m³/s

Thus, the tubes are not likely to flood as the maximum permissible liquid flow rate per unit cross-sectional area is more than the actual liquid flow rate per unit cross-sectional area.

Flooding should be controlled in condensers for the following reasons:

To prevent the condensers from becoming filled with liquid and to prevent the interference of liquid with the condensation process.

To prevent the flooding of liquid in the tubes that can result in inefficient operation, decreased output, and increased maintenance cost.

To prevent the liquid in the tubes from being entrained into the vapour and causing the contamination of downstream equipment.

To prevent the formation of a continuous film of liquid in the tubes that can result in the reduction of the heat transfer coefficient and increased resistance to vapour flow.

To avoid hydraulic problems that can cause the development of high pressure drops and uneven flow distribution, which can result in tube erosion, leakage, and other problems.

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Answer:

I think the first two one is 70 the second on is 14

I hope this helps if I’m wrong I’m sorry

Explanation:

Answer:

Rock

Explanation:

Right on edg 2021 and 2020000000:P

Answer:

In this case, the particles of the medium move parallel to the direction that the pulse moves. This type of wave is a longitudinal wave.

After pushing off, the lighter skater remains at rest and does not have any velocity.

We can apply the principle of conservation of momentum. According to this principle, the total momentum before the push should be equal to the total momentum after the push.

Initial velocity of both skaters (before the push) = 0 m/s

Final velocity of the heavier skater (after the push) = 1.50 m/s to the right

Mass of the heavier skater = M (unknown)

Mass of the lighter skater = m (unknown)

Final velocity of the lighter skater (after the push) = v (unknown)

Since the ice is frictionless, the total momentum before the push is zero. After the push, the total momentum should still be zero, as no external forces act on the system.

Total momentum before the push = Total momentum after the push

0 = (M * 0) + (m * v)

Simplifying the equation:

0 = 0 + mv

Since the mass of the lighter skater is m, the equation can be further simplified:

0 = mv

From this equation, we can conclude that the final velocity of the lighter skater (v) is also 0 m/s.

Therefore, after pushing off, the lighter skater remains at rest.

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The angular velocity of a planet can be calculated by dividing 2π radians by the time it takes for the planet to complete one orbit around the Sun. The linear velocity of a planet can be calculated by multiplying the planet's angular velocity by its average distance from the Sun.

Angular velocity refers to the rate at which an object moves around a central point. In the case of a planet orbiting the Sun, the central point is the Sun itself. To calculate the angular velocity of a planet, we divide the angle traveled by the planet in one orbit by the time it takes to complete that orbit. Since a full circle is 2π radians, the angular velocity can be calculated by dividing 2π by the orbital period of the planet.

On the other hand, linear velocity refers to the speed at which an object moves in a straight line. In the context of a planet's orbit, the linear velocity can be derived from the angular velocity. By multiplying the angular velocity of the planet by its average distance from the Sun, we can determine the linear velocity of the planet in its orbit.

By calculating both the angular and linear velocities of a planet, we can gain insights into its motion and speed within the solar system. These calculations allow us to better understand the dynamics of planetary orbits and the forces that govern them.

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Unit vectors in three-dimensional space have certain properties that are useful in many applications, such as physics, engineering, and computer graphics. These properties include linear independence, orthogonality, and relationships between dot and cross products.

In three-dimensional space, unit vectors are vectors with a magnitude of 1. Therefore, the following statements are true:

1. Any two distinct unit vectors are linearly independent.

2. The cross product of any two distinct unit vectors is also a unit vector that is orthogonal to both.

3. The sum of any two unit vectors may or may not be a unit vector, depending on the angle between them.

4. The dot product of any two unit vectors is equal to the cosine of the angle between them.

In summary, unit vectors in three-dimensional space have certain properties that are useful in many applications, such as physics, engineering, and computer graphics. These properties include linear independence, orthogonality, and relationships between dot and cross products. Understanding these properties can help in solving problems involving vectors and three-dimensional geometry.

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The story that describes the graph is, we  were accelerating from our starting point A to the next point B, then from point B started decelerating to our next point C, rested between point C and D, and finally we started our journey again by accelerating to point E.

A displacement time graph, is a type of graph that is used to describe the motion of an object with respect of how the object is changing its position with time.

The change in position with change in the time of motion of the object gives velocity of the object which is also equal to the slope of the graph.

v = Δx / Δt

where;

From the given graph we can conclude the following based on the motion;

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The wavelength of a sound wave has a speed of 339 m/s and frequency of 640 hz.is 0.79 m. The correct answer is C.

The formula for finding wavelength is:

wavelength = speed of sound / frequency

Given the speed of sound as 339 m/s and the frequency as 640 Hz, we can substitute these values in the formula to get:

wavelength = 339 / 640

wavelength = 0.528125 meters

However, we need to round off this answer to the nearest hundredth, which gives us:

wavelength = 0.79 meters

Therefore, the correct answer is C. 0.79 meters.

Sound waves are a type of mechanical wave that travel through a medium, such as air, water, or solids.

They are characterized by their frequency, wavelength, and amplitude. Frequency is the number of cycles of the wave that occur in one second, and it is measured in hertz (Hz). Wavelength is the distance between two consecutive points on the wave that are in phase, and it is measured in meters (m). Amplitude is the maximum displacement of the wave from its rest position, and it is measured in decibels (dB).

The speed of a sound wave depends on the properties of the medium through which it is traveling, such as its density and elasticity. In general, sound waves travel faster through solids and liquids than through gases, because the molecules in solids and liquids are closer together and can transmit the wave more efficiently.

Therefore, the correct answer is C. 0.79 meters.

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Answer:

If it is a true mixture, the mixing enthalpy is negligible, and there is no reaction or phase change, then you can do this using exclusively the temperatures of the individual compounds and their heat capacities. Any other process that takes place needs to be taken into account separately.

The solution can be found by understanding that we’re only using state variables. You can design any complicated process that starts with the starting situation and ends up at the ending situation, and the state variables will be the same. And sometimes a complicated process is easier to calculate than the simple one-step process, like here when mixing multiple components.

One way that will work is to start by bringing all compounds to the lowest temperature of either of the compounds. All but one of the compounds must be cooled down for this; make sure to calculate for each of the components how much energy is released. Now, mix all the components together. In the simplest situation sketched above you can calculate the heat capacity of the mixture by adding all the heat capacities of the components. Use this total heat capacity to calculate how much you can heat up the mixture using the energy you saved in cooling down the components earlier. This will be your desired end situation.

In case there are any phase changes or other processes in between, you need to take the energy needed for those into account too but in very similar ways.

The speed of sound in dry air at -49°C is approximately 294 meters per second (m/s).

In the upper atmosphere, the temperature drops below -49°C, which is very cold. At these altitudes, commercial airlines fly. The speed of sound in a medium, such as air, is dependent on the temperature of that medium. As a result, the speed of sound in the upper atmosphere at -49°C is different from the speed of sound at room temperature.

The speed of sound is determined by the medium it travels through, as mentioned earlier. The speed of sound in dry air at room temperature is approximately 343 meters per second (m/s). The speed of sound is calculated by the following formula:

Speed of sound = √(γ × R × T), where γ is the ratio of specific heat capacities, R is the gas constant, and T is the temperature in Kelvin.

At the temperature of -49°C, the speed of sound is slower than at room temperature due to the change in temperature. The sound speed decreases with temperature because air molecules are more tightly packed at lower temperatures, causing sound waves to move slower. The speed of sound in dry air at -49°C is approximately 294 meters per second (m/s). This is around 15% slower than the speed of sound at room temperature. As a result, the aircraft should fly at a lower speed than it would at room temperature to compensate for the slower speed of sound at that altitude. Because the speed of sound is slower at colder temperatures, aircraft pilots must be aware of this and account for it when flying in the upper atmosphere. A pilot who is unaware of the change in sound speed could overestimate their speed and fly too fast. This might be harmful to the aircraft and its passengers.

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A large, moving truck crashes into a small parked car. How do the magnitudes of the impulses and the forces on each vehicle compare during the collision: A. The truck receives more force but less impulse.

In physics, value is defined really as “magnitudes or amount.” It depicts absolutely the relative course or length wherein an item actions within the experience of movement. it's far used to specify the scale or scope of something. In physics, value commonly refers to distance or quantity.

Significance is the scale of something. for example, in the case of speed, a vehicle is moving faster than a bike. in this instance, the importance of the speed of the auto is higher than that of the bike. It tells the route or size that is absolute or relative in which an item travels in the experience of motion.

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Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

Answer:

a)  T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

        sin 30 = \(\frac{T_x}{T}\)

        cos 30 = \(\frac{T_y}{T}\)

        Tₓ = T sin 30

        T_y = T cos 30

Y axis  

       T_y -W = 0

       T cos 30 = mg                     (1)

X axis

        Tₓ = m a

they relate it is centripetal

        a = v² / r

we substitute

         T sin 30 = m\(\frac{v^2}{r}\)            (2)

a) we substitute in 1

         T = \(\frac{mg }{cos 30}\)

         T = \(\frac{ 0.2 \ 9.8}{cos \ 30}\)

         T = 2.26 N

b) from equation 2

           v² = \(\frac{T \ sin 30 \ r}{m}\)

If we know the length of the string

          sin 30 = r / L

          r = L sin 30

we substitute

          v² = \(\frac{ T \ sin 30 \ L \ sin 30}{m}\)

          v² = \(\frac{TL \ sin^2 30}{m}\)

For the problem let us take L = 1 m

let's calculate

          v = \(\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }\)

          v = 1.68 m / s

a. 13.23 N

b. 13.2

What you need to do is use this equation:

(m1 + m2) x g

hope it helps!

The magnifying power of the telescope is -60. Note that the negative sign indicates that the image formed is inverted.

To calculate the magnifying power of an astronomical telescope, we can use the formula:

Magnifying Power = - (Focal Length of Objective) / (Focal Length of Eyepiece)

Focal Length of Objective (f_o) = 180 cm

Focal Length of Eyepiece (f_e) = 3.0 cm

Substituting the values into the formula:

Magnifying Power = - (180 cm) / (3.0 cm)

Calculating this expression:

Magnifying Power = - 60

Therefore, the magnifying power of the telescope is -60. Note that the negative sign indicates that the image formed is inverted.

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If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor does not change.

Capacitance is the amount of charge that can be stored at a given voltage by an electrical component called a capacitor.

C=Q/V

The unit of capacitance is the Farad (F)

C = εA/d,

C is capacitance; ε is permittivity, a term for how well dielectric material stores an electric field; A is the parallel plate area; and d is the distance between the two conductive plates.

electric field between two parallel conducting plates depends on the electric potential or voltage of the two plates and the distance between the two plates. So, the electric field E=Vd E = V d where d is the distance between the two charged plates.

The force on the charge is the same no matter where the charge is located between the plates. This is because the electric field is uniform between the plates.

If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor does not change.

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Explanation:

v = IR

v= 160 R = 2

160 = 2I

2 2

I = 80A

Answer:

the objects in the universe are evenly placed. This means that a celestial object's gravity may not be able to attract another object. Another reason may be that the stars in solar systems act as points of equilibrium for the planets in the system. Take for example the sun. It maintains the position of the planets in the system and likewise the earth maintains the position of the moon. You can picture it as evenly placed atoms in matter and the subsequent electrons held by the nucleus

Answer:

BECAUSE OF THE DISTANCEBETWEEN EACH OBJECT DECREASES THE CHANCE IN SEEING OBJECTS COLIDE. HOPE THIS HELPS ...

Answer:

B. raising the temperature of the air