What is population function?

The required area under the whole probability density curve is given by option C. 1.

The area under the entire probability density curve is equal to,

As the probability density function (pdf) represents the probability of a continuous random variable.

And continuous random variable taking on a specific value within a certain range.

Since the total probability of all possible outcomes must be equal to 1.

This implies that the area under the entire probability density function (pdf) curve must also be equal to 1.

Therefore, the area under the entire probability density curve function is equal to option c. 1.

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Answer:

10

Step-by-step explanation:

its just to easy

Answer:

y=2x+5

Step-by-step explanation:

Answer:

Raven paints about 3 lures per minute.

Step-by-step explanation:

Answer:

Raven paints about 3 lures per minute.

Step-by-step explanation:

If we are doing the same assingment than thats waht i got

Answer:

a

Step-by-step explanation:

Answer:

The polygon has 15 sides

Step-by-step explanation:

Angles in a Regular Polygon

A polygon with n sides has a total sum of internal angles equal to 180°(n-2). This means that in a regular polygon, each angle measures

\(\displaystyle \frac{180(n-2)}{n}\)

The regular polygon's interior angle is 156°, thus

\(\displaystyle \frac{180(n-2)}{n}=156\)

Multiply by n:

\(180(n-2)=156n\)

Operate:

\(180n-360=156n\)

Reducing:

\(24n=360\)

Solving:

\(n=15\)

The polygon has 15 sides

Answer:

3.5,3 there you go buddy

Step-by-step explanation:

Answer: B.

\(12x^{2}\) \(-8xy + 12x + y^2 - 2y\)

Step-by-step explanation:

i just took the assignment

The end of the plank is sliding along the ground at a rate of approximately -0.08 m/s when it is 1.4 meters from the wall of the building. The negative sign indicates that the end of the plank is sliding in the opposite direction.

To find how fast the end of the plank is sliding along the ground, we can use related rates. Let's consider the position of the end of the plank as it moves along the ground.

Let x be the distance between the end of the plank and the wall of the building, and y be the distance between the end of the plank and the ground. We are given that dx/dt = 0.26 m/s, the rate at which the worker pulls the rope.

We can use the Pythagorean theorem to relate x and y:

x² + y² = 5²

Differentiating both sides of the equation with respect to time, we get:

2x(dx/dt) + 2y(dy/dt) = 0

At the given moment when x = 1.4 m, we can substitute this value into the equation above and solve for dy/dt, which represents the rate at which the end of the plank is sliding along the ground.

2(1.4)(0.26) + 2y(dy/dt) = 0

2(0.364) + 2y(dy/dt) = 0

0.728 + 2y(dy/dt) = 0

2y(dy/dt) = -0.728

dy/dt = -0.728 / (2y)

To find y, we can use the Pythagorean theorem:

x² + y² = 5²

(1.4)² + y² = 5²

1.96 + y² = 25

y² = 23.04

y = √23.04 ≈ 4.8 m

Substituting y = 4.8 m into the equation for dy/dt, we have:

dy/dt = -0.728 / (2 * 4.8) ≈ -0.0757 m/s

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Answer:

7

Step-by-step explanation:

4y²-106=90

4y²=90+106

4y²=196

4y²/4=196/4

y²=49

y=√49

y=7

Answer:

you will have negative 2, I think.

Step-by-step explanation:

Answer:

answer is C

Step-by-step explanation:

f(x)= 1/x+1

Because we have a vertical asymptote at x = -1, we conclude that the correct option is C.

In the graph, we can see that we have a vertical asymptote at x = -1.

This means that the denominator of the rational equation becomes zero when x = -1.

So the equation must be:

\(y = \frac{1}{x + 1}\)

The denominator is x + 1, and as expected, it becomes zero when x = -1.

Then we conclude that the correct option is C.

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Answer:

1887

Step-by-step explanation:

\(\textrm{substitute }x=-5\textrm{ into the equation:}\\2(-5)^{4}-5(-5)^{3}+(-5)^{2}+3(-5)+2\\=2(625)-5(-125)+25-15+2\\=1887\)

The probability that at least half of the voters contacted supported the current governor is approximately 0.3322 or 33.22%.

The proportion of voters who voted for the current governor in the election can be determined using the formula

\(P=\frac{x}{n}\)

p is the proportion,

x is the number of voters who supported the current governor

n is the number of voters in the sample.

In this case, the sample size is 342, and we don't know the number of voters who supported the current governor.

Therefore, we can estimate the proportion using the sample proportion.

The sample proportion is obtained by dividing the number of voters who supported the current governor by the sample size.

Let us assume that half of the voters contacted supported the current governor.

Since we know that the sample size is 342, the number of voters who supported the current governor is 171, which is half of 342.

Therefore, the sample proportion is  \(p=\frac{171}{342}=0.5\)

In order to calculate the probability that at least half of the voters contacted supported the current governor, we need to use the normal distribution.

The normal distribution is a continuous probability distribution that is widely used to model real-world phenomena.

The normal distribution is characterized by two parameters: the mean and the standard deviation.

In this case, the mean of the normal distribution is given by the sample proportion, which is p = 0.5.

The standard deviation of the normal distribution can be calculated using the formula:

\(σ=sqrt\frac{p(1-p)}{n}\)

σ is the standard deviation,

p is the proportion, and

n is the sample size.

Using the values we have, we can calculate the standard deviation:

\(σ=sqrt\frac{0.5(1-0.5)}{342} =0.0253\)

We want to find the probability that at least half of the voters contacted supported the current governor, which means we want to find the probability that the sample proportion is greater than or equal to 0.5.

Using the normal distribution, we can standardize the sample proportion and find the probability that it is greater than or equal to 0.5.

The standardized score is given by the formula

\(z= \frac{(p-μ)}{σ}\)

z is the standardized score,

p is the proportion,

μ is the mean,

σ is the standard deviation.

Using the values we have, we can standardize the sample proportion:

\(z=\frac{0.5 - 0.5}{0.0253} =0\)

The probability of a standardized score being 0 is 0.5.

Therefore, the probability that the sample proportion is greater than or equal to 0.5 is 0.5 + (1 - 0.5) x 0.5 = 0.75.

However, this probability is for a normal distribution with a mean of 0.5 and a standard deviation of 0.0253.

We want the probability for a sample of 342 voters, so we need to adjust our answer using the continuity correction factor.

The continuity correction factor is used when we are approximating a discrete distribution with a continuous distribution.

In this case, the sample proportion is a discrete distribution because it can only take on certain values (such as 0.5, 0.51, 0.52, etc.).

However, we are using a continuous distribution (the normal distribution) to approximate the sample proportion.

Therefore, we need to adjust our answer using the continuity correction factor.

The continuity correction factor is given by the formula 0.5 - 0.5/n, where n is the sample size.

Using the continuity correction factor, we can adjust our answer:

\(0.75-\frac{0.5-0.5}{342} =0.3322\)

Therefore, the probability that at least half of the voters contacted supported the current governor in the last election when a telephone survey contacts 342 voters from the last election and asks if they voted for the current governor is approximately 0.3322 or 33.22%.

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Ricardo's model of trade is an economic theory of comparative advantage that explains how trade can benefit all parties involved, even when one party has an absolute advantage in the production of all goods.

The model focuses on two countries: the US and Fiji, producing two goods - bananas (Y) and machines (X).

The labor unit requirements are as follows:

(i) Pattern of trade:

In this case, the US has a comparative advantage in machines, while Fiji has a comparative advantage in bananas. Therefore, the pattern of trade will be that the US will produce machines and trade them with Fiji, while Fiji will produce bananas and trade them with the US. The US will import bananas from Fiji and export machines to Fiji, while Fiji will import machines from the US and export bananas to the US.

(ii) Gains from trade:

The gains from trade are the benefits that both countries enjoy as a result of engaging in free trade. These gains can be illustrated using production possibility frontier (PPF) diagrams, which show the maximum combinations of two goods that a country can produce with its available resources.

Before trade, the PPF for the US shows that it can produce 800 machines or 400 bananas. The PPF for Fiji shows that it can produce 1000 machines or 250 bananas. Thus, the total world production before trade is 1800 machines and 650 bananas.

The autarky prices of machines and bananas in the US are 2 and 0.5, respectively, while in Fiji they are 4 and 1, respectively. The international price ratio of machines and bananas is 1:1.

(iii) Total world production of both goods before and after trade:

Before trade, the total world production of machines and bananas was 1800 machines and 650 bananas. After trade, the total world production of machines and bananas is 1000 machines and 750 bananas for the US, and 800 machines and 500 bananas for Fiji. Therefore, the total world production of machines and bananas has increased after trade.

(iv) Autarky and international price ratios:

Autarky prices refer to the prices of goods in a country that is not engaging in trade. In this case, the autarky prices of machines and bananas in the US are 2 and 0.5, respectively, while in Fiji they are 4 and 1, respectively. The international price ratio of machines and bananas is 1:1.

(v) Trade triangles:

Trade triangles demonstrate the gains from trade by comparing the pre-trade production and consumption of a good to the post-trade production and consumption. In this case, the trade triangle for the US shows that it exports 200 machines and imports 400 bananas. The trade triangle for Fiji shows that it exports 150 bananas and imports 300 machines. These trade triangles further illustrate the gains achieved through trade.

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The component form of the linear combination of the two vectors is u - 2v = < -5, 20>

Here we have the two vectors: u = <-3, -2> and v = <1, -5> We want to determine the value of the linear combination:

u - 2v

To do that we just add the correspondent components, then we get:

u - 2v = <-3, -2> - 2*<1, -5>          

= <-3, -2> - <2*1, 2*-5>          

= <-3, -2> -  <2, -10>          

= < -3 - 2, -2 -(-10)>          

= < -5, 20>

That is the component form of the linear combination.

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The 99% confidence interval for the mean GPA of all accounting students at this university is approximately (3.12272, 3.27728). This means we are 99% confident that the true mean GPA of all accounting students at this university falls between 3.12272 and 3.27728.

To construct the 99% confidence interval for the mean GPA of all accounting students at this university, follow these steps:
Identify the sample size, mean, and standard deviation: In this case, the sample size (n) is 25, the mean (x) is 3.20, and the standard deviation (s) is 0.15.
Determine the confidence level: The problem states we need a 99% confidence interval, so the confidence level is 99%.
Find the critical value (z-score) for the confidence level: For a 99% confidence interval, the critical value (z) is 2.576 (you can find this value in a standard z-score table).
Calculate the standard error (SE) of the sample mean: SE = s / √n = 0.15 / √25 = 0.15 / 5 = 0.03.
Calculate the margin of error (ME): ME = z * SE = 2.576 * 0.03 = 0.07728.
Find the lower and upper limits of the confidence interval:
- Lower limit = x - ME = 3.20 - 0.07728 = 3.12272.
- Upper limit = x + ME = 3.20 + 0.07728 = 3.27728.

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Answer:

Hope this helps!!

Step-by-step explanation:

Answer:

1. 43/325

2. 30/203

3. 117/272

4.371/488

Step-by-step explanation:

1. p(a 3rd class survivor)

172 2nd class out of total

2. p(1st class | died)

given that they died there are 120 people in first class out of all the people who died

3. p(survived | 2nd class)

how many people survived given they were second class is 117 out of 272 peple in 2nd class

4. p(1st or 3rd class | survived​

given that they survived (488) there are 371 people in first and third class so 371/488

Answer:

110 + 25x = Total Cost (or any type of variable needed, like a,b,c, etc.)

Step-by-step explanation:

Since the monthly fee occurs more than once, and we don't have the number of months, we put an x to represent the amount of months. The $110 is the one time additional fee for the membership, so it doesn't need a variable.

Answer:

100 dollars

Step-by-step explanation:

Taylor saved two dollars each time and she has 40 which is 20 x 2=40 so do the same for her brother 5 x 20= 100.

Answer:

6

Step-by-step explanation:

We know if we multiply 6x2=12 and 6x5=30. After 6 you can not multiply anything else higher than that. For example 15x2=30 but 15 is not a GCF of 12 and 4x3=12 3 and 4 are not GCFs of 30. So 6 is the GCF of 12 and 30.

Answer:

5.4

Step-by-step explanation:

using pythagoras theorem

a²+b²=c²

5²+2²=c²

c²= 25+4

c²=29

\( \sqrt{c ^{2} } = \sqrt{29} \)

c=5.4

To determine the degrees of freedom for the given data, we need to use the formula n1 + n2 - 2, where n1 and n2 represent the sample sizes. In this case, n1 = 19 and n2 = 15. Therefore, the degrees of freedom would be 19 + 15 - 2 = 32.

In statistical analysis, degrees of freedom refers to the number of independent observations or values that are free to vary when estimating a parameter or conducting hypothesis tests. The formula to calculate degrees of freedom for two-sample t-tests is n1 + n2 - 2, where n1 and n2 represent the sample sizes of the two groups being compared.

In this case, the given data states that n1 = 19 (sample size of group 1) and n2 = 15 (sample size of group 2). By substituting these values into the formula, we can calculate the degrees of freedom as 19 + 15 - 2 = 32.

This means that there are 32 degrees of freedom available for estimating parameters and performing statistical tests involving these two samples.

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Answer:

If you study for 2 hours, with 20-25 minutes of studying and a 5-minute break, you will study for approximately 80-100 minutes. This is because in one hour, there are three sets of 20-25 minutes of studying and two sets of 5-minute breaks. Therefore, in two hours, there will be six sets of 20-25 minutes of studying and four sets of 5-minute breaks. Thus, the total time spent on breaks would be around 20 minutes (4 x 5), leaving approximately 80-100 minutes for studying.

Answer:

90 or sum mins

Step-by-step explanation:

Around 90 lol

:)

=======================================================

Explanation:

If the diagonals were congruent, then you can use the SSS property to prove a pair of right triangles are congruent. This leads to showing that we have adjacent congruent corresponding angles. Let's call those angles x and y.

Since they are congruent, we know that y = x. Adjacent angles of any parallelogram add to 180, so x+y = 180

By substitution we can solve for x

x+y = 180

x+x = 180

2x = 180

x = 180/2

x = 90

So y = 90 as well.

This line of thinking is used to show that all four angles of this parallelogram are 90 degrees. A rectangle is any quadrilateral in which all four angles are 90 degrees, so that's why this parallelogram is a rectangle.

a. Marginal utility of good x for u(x,y) = \(x^(1/3)y^(2/3) is (2/3)*(u(x,y)/x).\)

b. Marginal utility of good x for u(x,y) = ln(x) + y is 1/x.

c. Marginal utility of good x for u(x,y) =\(a1x + b1y - cxy - a22x^2 - b22y^2 i\)s a1 \(- c*y - 2*a22*x.\)

d. Marginal utility of good x for u(x,y) =\((x^2 + y^2)^(1/2) is x/((x^2 +\)\(y^2)^(1/2)).\)

e. Marginal utility of good x for u(x,y) = 3x + 2y is 3.

a. In the Cobb-Douglas utility function, to calculate the marginal utility of good x, we take the partial derivative of the utility function with respect to x and multiply it by (u(x,y)/x) to eliminate the effect of y. Taking the partial derivative gives us (2/3)*(x^(-2/3))*y^(2/3), and multiplying by (u(x,y)/x) simplifies it to (2/3)*(u(x,y)/x).

b. In the quasi-linear utility function, the logarithm of x represents a constant elasticity of substitution (CES) utility function, where the marginal utility of x is equal to 1/x.

c. The quadratic utility function involves multiple terms, and to calculate the marginal utility of good x, we take the partial derivative of the utility function with respect to x. This gives us a1 - \(c*y - 2*a22*x\), which represents the marginal utility of good x.

d. In the constant elasticity of substitution (CES) utility function, the marginal utility of good x is given by the partial derivative of the utility function with respect to x, divided by the square root of the sum of squares of x and y. This simplifies to \(x/((x^2 + y^2)^(1/2)).\)

e. In the perfect substitutes/linear utility function, the marginal utility of good x is a constant value of 3. As the utility function implies perfect substitutability between x and y, the marginal utility remains constant regardless of the quantity consumed.

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Micah received 1/2 of Savi's share and Juan got the balance.

"A method to find a single unit value from a multiple unit value and to find a multiple unit value from a single unit value."

We always count the unit or amount value first and then calculate the more or less amount value.

For this reason, this procedure is called a unified procedure.

Many set values ​​are found by multiplying the set value by the number of sets.

A set value is obtained by dividing many set values ​​by the number of sets.

According to our question-

total amount = $280=x

savi= 4*juan= 11

micah= 1/2 savi= 1/2*280/100= 1.4

juan got balance= 267.6

Hence, Micah received 1/2 of Savi's share and Juan got the balance.

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The expected value of a lottery ticket is $0.13312. The expected value of a lottery ticket is the average amount that a player can expect to win or lose per ticket bought. To calculate the expected value, one multiplies each outcome by its probability and adds the results.

In this case, there are three possible outcomes: winning $1 billion, winning $10 million, or winning nothing. There are a total of 60 possible numbers for each of the 5 numbers, so there are 60^5 = 7,776,000,000 possible sequences that the lottery could choose. To calculate the probability of winning $1 billion, there is only one winning sequence, so the probability is 1/7,776,000,000. The expected value for winning $1 billion is therefore:
$1,000,000,000 × 1/7,776,000,000 = $0.128
To calculate the probability of winning $10 million, there are four winning sequences for the first four numbers, and 60 possibilities for the fifth number, so the probability is 4/7,776,000,000.

The expected value for winning $10 million is therefore:
$10,000,000 × 4/7,776,000,000 = $0.00512
To calculate the probability of winning nothing, there are 7,775,999,995 losing sequences out of 7,776,000,000 total sequences, so the probability is 7,775,999,995/7,776,000,000. The expected value for winning nothing is therefore:
$0 × 7,775,999,995/7,776,000,000 = $0
Adding these three expected values together gives the overall expected value of a lottery ticket:
$0.128 + $0.00512 + $0 = $0.13312

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Answer:

a=1/3

Step-by-step explanation:

First, expand the brackets by doing multiplication:

2+6a+3=3a+6

Then, move the unknown to the left and the numbers to the right:

3a=6-5

3a=1

a=1/3

The solution to the given equation is -1.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

The given equation is 2+3(2a+1)=3(a+2)

2+6a+3=3a+2

6a+5=3a+2

6a-3a=2-5

3a=-3

a=-1

Therefore, the solution to the given equation is -1.

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\((\stackrel{x_1}{8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{11}~,~\stackrel{y_2}{14})~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{14}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{11}-\underset{x_1}{8}}} \implies \cfrac{14 -5}{11 -8} \implies \cfrac{ 9 }{ 3 }\implies 3\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{3}(x-\stackrel{x_1}{8}) \\\\\\ y-5=3x-24\implies y=3x-19\)

Answer:

So to write this as an equation follow the steps:

1.First you take y delta divided by x delta. This means that you but in the coordinates, take them minus eachother then divided by eachother. Let me show you with maths for better understanding:

Now you have k in y=kx+m ( the equation has different letters depening on where you are from but I think you understand).

So know we just use simple algebra bu putting in the coordinates in the equation. So for this example im going to use the coordinates x= 8 and y=5

so we get: