What is the angle of incidence for this ray?

Answer:

The outside layer is the wettest.

Explanation:

The impulse exerted on the ball by the wall is -24i N s, the answer is option b.

The impulse exerted on the ball by the wall can be determined using the impulse-momentum theorem.

Impulse is equal to the change in momentum.

That is,

J = Δp

Since momentum is a vector,

p = mv

Substituting the values,

p(initial) = mv(initial) = 3.0 kg × (4i + 3j) m/s

p(initial) = 12i + 9j N s

p(final) = mv(final) = 3.0 kg × (-4i + 3j) m/s

p(final) = -12i + 9j N s

Change in momentum,

(Δp) = p(final) - p(initial)

      = (-12i + 9j) N s - (12i + 9j) N s

      = (-12 - 12)i + (9 - 9)j N s

      = -24i N s

Thus, the impulse exerted on the ball by the wall is -24i N s, which means that the answer is option b.

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Answer:

The answer is d i think so yea

Explanation:

hope u hae  a really good  day

Answer:

u don't know this one but try a not for sure

God created all things in the beginning of time

Explanation:

He said the things he wanted to make an they came into existence.

Im christian so if u dont like the answer or get mad i'm sorry i couldnt help you

Answer:

A. 119kg

B.0.53m from head

Explanation:

A. Weight = 730+340.

=1170N

F= Wg

W = 1170/9.8

= 119kg

If x is distance from head to CG then 1.92–x is the other distance.

Moments must equal

470x = 330(1.89–x)

470x = 623.7 – 330x

1170x = 623.7

x = 0.53m from head

The mass of the soil sample is 82g.

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Answer:

11 N

Explanation:

You will need enough force to overcome the static friction

Fn = 2.50 kg * 9.81 m/s^2

F of static friction =  Fn * coeff static =  2.50 * 9.81 * .448 =~ 11 N

A particular charge density produces an electric field, however, the presence of the dielectric reduces this field.

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Fibers of the sweater lose electrons because electrons are leave it.

One of the ways of charging a body is by friction. Charges are transferred from one body to another when an object is rubbed against another. This is charging by friction.

A sweater has negative charges hence when the balloon is rubbed against the sweater, fibers of the sweater lose electrons because electrons are leave it.

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Answer: Since Distance= Rate X Time

Average Speed = Total Distance/ Total Time

Average Speed = 120 miles /3 hours

Average Speed = 40 miles per hour (40m/h)

Explanation:

Answer:

yes it do rises and then fall down due to gravitational

a) The scale would show an apparent weight of 961.0N  ; b) Scale would show an apparent weight of 435.8N.

Rate at which velocity of any object changes with time is called acceleration and it is vector quantity.

a. When the elevator starts to accelerate upwards at 3.0m/s², apparent weight of the person on scale will be:

Apparent weight = (mass of the person) x (acceleration due to gravity + acceleration of the elevator)

= 75kg x (9.81m/s² + 3.0m/s²)

= 75kg x 12.81m/s²

Apparent weight = 961.0N

Therefore, scale would show an apparent weight of 961.0N.

b. When the elevator starts to accelerate downwards at 4.0m/s², apparent weight of the person on the scale will be:

Apparent weight = (mass of the person) x (acceleration due to gravity - acceleration of the elevator)

= 75kg x (9.81m/s² - 4.0m/s²)

= 75kg x 5.81m/s²

Apparent weight = 435.8N

Therefore, scale would show an apparent weight of 435.8N.

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Answer:

The value is \(s =63.18 \ m\)  

Explanation:

From the question we are told that

   The uniform  acceleration is   \(a = 0.39 \ m/s^2\)

   The time considered is \(t = 18 \ seconds\)

Generally the from kinematic equation we have that

          \(s = ut + \frac{1}{2} at^2\)

Given that the boat started from rest , the initial velocity is  u =  0  m/s  

So

       \(s = 0 * 18 + \frac{1}{2} *0.39 * 18^2\)

=>      \(s =63.18 \ m\)

Answer:

The out of page

Answer:

b. varies inversely with the square of the distance from the center of Earth.

Explanation:

Comparing the Newton's law of universal gravitation and second law of motion;

from Newton's second law of motion,

F = ma ............. 1

from New ton's law of universal gravitation,

F = \(\frac{GMm}{r^{2} }\) ........... 2

Equating 1 and 2, we have;

mg =  \(\frac{GMm}{r^{2} }\)

g = \(\frac{GM}{r^{2} }\)

Therefore, the acceleration due to gravity near Earth, g, is inversely proportional to the square of the distance from the center of Earth.

Answer:

The image will be real, inverted, and enlarged. For convex lenses, when the object is placed inside F, the image will be on the same side of the lens as the object and it will be virtual, upright, and enlarged.Feb

Answer:

B) The Gulf Stream carries warm water along the east coast, causing average temperatures to be warmer than they would be without the current.

Explanation:

The east coast of the United States is affected mainly by the Gulf Stream current, which brings warm water from the tropics into higher latitudes. Because warmer water evaporates faster, putting more moisture into the air, the current serves to increase the humidity of the air along the coast.

Answer:

I think the answer is B fell free to correct me if im wrong.

Given:

There is a closed path for the flow of current.

Answer and explanation:

A correct option is an option (A). Since the path is closed, the current will flow through the circuit.

An option (B) is incorrect because the charge does not accumulate in a closed path.

Option (C) is also incorrect because the path is closed, and the circuit cannot be open.

Option (D) is also an incorrect option because there is always a resistance provided by the metal wire.

Based on the information provided, the two bottom gears in Set B will be cooler compared to the two bottom gears in Set A.

This is because the two bottom gears in Set B are in direct contact with the cooler gears on top, which creates a better heat transfer pathway.

The gears in Set B form a continuous chain of contact with the cooler gears above, allowing for efficient heat dissipation.

In contrast, the gears in Set A are not in direct contact with the cooler gears on top, resulting in less effective heat transfer and slower cooling.

Therefore, the continuous contact between the gears in Set B facilitates better heat conduction and ultimately leads to lower temperatures compared to Set A.

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The work done on the crate by friction is -4391.6 J, which is equivalent to -6450 J (rounded to the nearest whole number).

The work done on the crate by friction is -6450 J.Work is given by the equation:

W = ∆KE + ∆PE + ∆U

where KE is the kinetic energy, PE is the potential energy, and U is the work done by nonconservative forces.

The work done by the frictional force, which is non-conservative, can be determined by finding the net work on the crate and subtracting the work done by the gravitational force.

The formula is:

∑W = Wf - Wg

where Wf is the work done by the frictional force and Wg is the work done by gravity. The work done by gravity is calculated using the change in potential energy of the crate.

Given:

mass of the crate, m = 36.5 kg specific heat capacity of the crate, c = 3650 J/(kg K)distance the crate slides, d = 7.50 mangle of the incline, θ = 35.4 degrees

acceleration due to gravity, g = 9.81 m/s²initial velocity, vi = 0 m/sfinal velocity, vf = 2.40 m/s

The potential energy of the crate at the top of the incline is equal to its kinetic energy at the bottom. So, using the conservation of energy, we have:

PE + KE = KE' + PE'

where PE = mgh is the potential energy, KE = 0 is the initial kinetic energy, KE' = (1/2)mvf² is the final kinetic energy, and PE' = 0 is the final potential energy, which is the same as the initial potential energy.

The height of the incline is h = d sin θ, so:

PE = mgh

     = (36.5 kg)(9.81 m/s²)(7.50 m sin 35.4°)

     = 1086 JKE' = (1/2)mvf²

     = (1/2)(36.5 kg)(2.40 m/s)²

     = 62.6 J

Therefore, the net work on the crate is:

∑W = Wf - Wg

∑W = KE' - KE + PE' - PE

∑W = 62.6 J - 0 J + 0 J - 1086 J

∑W = -1023.4 J

The negative sign indicates that the work done by the frictional force is opposite to the direction of motion of the crate.

Finally, we can find the work done by the frictional force by subtracting the work done by gravity:

Wf = ∑W - Wg

Wf = -1023.4 J - (-5415 J)

Wf = -1023.4 J + 5415 J

Wf = 4391.6 J

Therefore, the work done on the crate by friction is -4391.6 J, which is equivalent to -6450 J (rounded to the nearest whole number).

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Answer:

1 kJ

Explanation:

By definition of work, \(W = \vec F \cdot \vec x = |\vec F| |\vec x| cos\angle Fx\). Let's replace the values: \(W = 100N\cdot 20m \cdot cos 60 = 1000 J\)

Force magnitude when elevator is traveling at constant velocity is, 637 N. Force magnitude does the scale read when the elevator slows to a stop is,  429 N (downward force). Force magnitude when elevator starts downward again is, 208 N.

Force magnitude when elevator is traveling at constant velocity, 65 kg x 9.8 m/s^2 = 637 N (upward force)

When the elevator slows to a stop with an acceleration of magnitude 2.0 m/s^2, the net force acting on the student is the sum of the gravitational force and the force exerted by the scale.

Net force: (65 kg) x (2.0 m/s^2) = 130 N (downward force)

Force magnitude when elevator slows to a stop: 637 N - 130 N = 507 N (upward force)

When the elevator starts moving downward again with an acceleration of magnitude 2.0 m/s^2, the net force is difference between the gravitational force and the force exerted by the scale,

Net force: (65 kg) x (9.8 m/s^2 - 2.0 m/s^2) = 429 N (downward force)

Force magnitude when elevator starts downward again: 637 N - 429 N = 208 N (upward force)

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Answer:

a)    I = 13.38 kg m / s, b)    F = 1,373 10³ N

Explanation:

The impulse is given by the relation

          I = ∫ F dt = Δp

          I = p_f -p₀

          I = m (v_f - v₀)

take the ball's exit direction as positive, whereby the ball velocities

v₀ = -90mph, the final velocity v_f = + 54 m / s

Let's reduce the units to

         I = 0.142 [54- (-40.23) ]

      the SI system

        v₀ = - 90 mph (1609.34 m / 1 mile) (1h / 3600 s = -40.23 m / s

        m = 142 g (1kg / 1000) = 0.142 kg

we calculate  

          I = 0.142 [54- (-40) ]

          I = 13.38 kg m / s

b) let's use the definition of momentum

         I = ∫ F .dt

         I = F ∫ dt

         F = I / t

         F = 13.38 / 0.008

         F = 1,373 10³ N

It can then be used for further analysis or processing as required.

The term 'filtrate' refers to the liquid that has passed through a filter paper during the process of filtration. When a mixture is subjected to filtration, the solid particles or impurities are retained by the filter paper, while the liquid component passes through the paper to form the filtrate.

Filtration is a common laboratory technique used for separating a solid-liquid mixture. The solid particles in the mixture are usually insoluble and can be separated by passing the mixture through a filter paper. The size of the pores in the filter paper allows the liquid component of the mixture to pass through, while the solid particles are retained on the filter paper.

Once the filtration is complete, the liquid that has passed through the filter paper is referred to as the 'filtrate'. The filtrate is usually clear and free of any solid particles or impurities that were present in the original mixture. It can then be used for further analysis or processing as required.

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Answer:

5.61s

Explanation:

\(\pink{\frak{Given}}\begin{cases} \textsf{ A ball is dropped off a tall building and accelerates at 9.8 m/s$^2$ .}\\\textsf{It reaches the ground at a speed of 55 m/s .} \end{cases}\)

And we need to find out the time taken by the ball to reach the ground .

Here we can use the First equation of motion , namely ;

\(\sf \longrightarrow v = u + at \)

where the symbols have their usual meaning . Now substituting the respective values , we have,

\(\sf \longrightarrow 55m/s = 0m/s + 9.8 m/s^2(t)\\ \)

\(\sf \longrightarrow 55m/s = 9.8m/s^2(t)\\ \)

\(\sf \longrightarrow t = \dfrac{55m/s}{9.8m/s^2}\\\)

\(\sf \longrightarrow \boxed{\bf time = 5.61 s }\)

Answer:

A

Explanation:

When friction slows a sliding block, the kinetic energy of the block is transformed into internal energy .

The frictional movement of two surfaces over one another leads to the conversion of some of their kinetic energies to another energy - heat or thermal energy. Hence, the temperatures of the objects are raised in the process.

Therefore, when a sliding block is slowed down due to friction, some of the kinetic energy of the block would be transformed into internal energy in the form of heat.

The correct option is A.