What is the boiling point of 0.500 m I2 in cyclohexane (normal boiling point = 80.74°C)? Kb,cyclohexane = 2.79°C/m

Answer:

A and E

Explanation:

with Adenine ,thymine , cytosine and guanine

The pH of a .25 M acetic acid solution would be higher than the pH of a .25 M hydrochloric acid solution. This is because acetic acid is a weak acid, meaning it only partially dissociates in water, while hydrochloric acid is a strong acid, meaning it completely dissociates in water. The pH of a weak acid solution is higher than the pH of a strong acid solution of the same concentration.
Based on the terms you provided, I'll compare the pH of 0.25 M acetic acid and 0.25 M hydrochloric acid solutions.
Acetic acid is a weak acid, which means it doesn't completely dissociate in water, whereas hydrochloric acid is a strong acid, meaning it fully dissociates in water. When an acid dissociates, it releases hydrogen ions (H+) into the solution, which determines the pH.
Here's a step-by-step comparison:
1. A 0.25 M acetic acid solution will only partially dissociate, releasing fewer H+ ions into the solution.
2. A 0.25 M hydrochloric acid solution will completely dissociate, releasing more H+ ions into the solution.
Since the pH scale is logarithmic and inversely related to the concentration of H+ ions, a solution with fewer H+ ions will have a higher pH (less acidic) than a solution with more H+ ions.
Therefore, you would expect the pH of a 0.25 M acetic acid solution to be higher (less acidic) than the pH of a 0.25 M hydrochloric acid solution.

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Estimated enthalpy change for the reaction H2(g) + O2(g) → H2O2(g) is 300 kJ/mol.

To estimate the enthalpy change for the reaction H2(g) + O2(g) → H2O2(g), we can calculate the energy change based on the bond energy values given:

Breaking the bonds:

H-H (2 moles) = 2 * 436 kJ/mol = 872 kJ/mol

O=O (1 mole) = 1 * 498 kJ/mol = 498 kJ/mol

Forming the bonds:

H-O (2 moles) = 2 * 463 kJ/mol = 926 kJ/mol

O-O (1 mole) = 1 * 146 kJ/mol = 146 kJ/mol

Now, we can calculate the net energy change by subtracting the energy used to break the bonds from the energy released by forming the bonds:

Energy change = (Energy of bonds broken) - (Energy of bonds formed)

            = (872 kJ/mol + 498 kJ/mol) - (926 kJ/mol + 146 kJ/mol)

            = 1372 kJ/mol - 1072 kJ/mol

            = 300 kJ/mol

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The principles governing 13 C NMR chemical shifts are the same as those governing 1 H, even though the normal range of chemical shifts is much wider (by a factor of about 20).

The carbons in tetramethylsilane (TMS), whose chemical shift is thought to be 0.0 ppm, serve as the chemical shift reference standard for 13 C. Typical 13 C-NMR chemical shiftsFormula for 1-Penten-3-one: C5H8O 84.1164 molecular weightA pentene molecule has five carbon atoms since the prefix pent- implies "five." The pentene molecule is an alkene, as indicated by the prefix -ene. A substance known as an alkene is an organic compound that has at least one C=C double bond. This indicates that two of the carbons in pentene are doubly bonded.

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Answer:

C.

Explanation:

Answer A is incorrect because a compound doesn't have to be made with only metals.

Answer B is incorrect because that is actually the definition of a pure element.

Answer C is correct because to make a compound, there has to be a chemical reaction where bonds are formed and an entirely new substance is created.

Answer D is incorrect because compounds cannot be separated by physical means.

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Answer:

the ratio of the distance travelled by the solute to the distance travelled by the solvent

Explanation:

It is used in chromatography to quantify the amount of retaration of a sample in a stationary phase relative to a mobile phase.

Answer:

N2 + H2 --> 2 NH

Explanation:

You need to add 2 to make it correct

The false statement is (2) Group 3A metals are more reactive than Group 2A metals which are more reactive than Group 1A metals.

This statement is incorrect as the reactivity of the groups decreases as we move from Group 1A to Group 3A. Group 1A metals are the most reactive of the three groups, followed by Group 2A metals and then Group 3A metals. This trend can be explained by the increasing ionization energy and electronegativity from left to right across the periodic table.

Group 1A and 2A metals are indeed strong reducing agents. They readily give up their valence electrons to form cations and have a strong tendency to form ionic compounds with nonmetals. The oxides of Group 1A and 2A metals are basic in nature, as they react with water to form metal hydroxides. However, BeO is an exception to this trend as it is amphoteric in nature and can react with both acids and bases.

Hydroxides of most Group 2A metals are indeed less soluble than hydroxides of Group 1A metals due to the differences in the ionic/covalent character of the hydroxides. The hydroxides of Group 1A metals have more ionic character, while the hydroxides of Group 2A metals have more covalent character, which makes them less soluble in water.

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Answer:

0.83Cal

Explanation:

Given parameters:

   Amount of energy given;

      35J;

 Convert to Cal;

         1 calorie  = 42 joules

         x calories  = 35 joules

   Cross multiply;

         42x = 35

             x = \(\frac{35}{42}\)   = 0.83Cal

Answer:

2.24dm³

Explanation:

Given parameters:

Mass of He = 40g

Unknown:

Volume of Helium  = ?

Solution:

To solve this problem, we convert the given mass to number of moles.

   Number of moles  = \(\frac{mass}{molar mass}\)  

   molar mass of He  = 4g/mol

  Number of moles  = \(\frac{4}{40}\)   = 0.1mole

So;

                  1 mole of gas at rtp occupies a volume of 22.4dm³

                0.1 mole of He will occupy a volume of 0.1 x 22.4 = 2.24dm³

The book titled "Element of Propulsion: Gas Turbines and Rockets" by J.D. Mattingly is part of the AIAA Education Series and was published in 2006. It serves as a valuable resource for understanding the principles and applications of gas turbines and rockets in propulsion systems.

"Element of Propulsion: Gas Turbines and Rockets" provides comprehensive coverage of the fundamental concepts and advanced topics related to gas turbine and rocket propulsion. The book delves into the theoretical principles, design considerations, and practical applications of these propulsion systems.

It explores the thermodynamics, fluid mechanics, combustion, and performance characteristics involved in gas turbine and rocket engines.

J.D. Mattingly, the author of the book, is a recognized expert in the field of propulsion systems and has extensive experience in teaching and research. His expertise and knowledge are reflected in the content of the book, making it a valuable educational resource for students, researchers, and professionals in the aerospace and propulsion engineering domains.

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Answer:

a chemical equation is balanced when the number of each type of atom is the same on both sides of the equation.

Explanation:

A chemical equation is considered to be properly balanced when the number of each type of atom is the same on both sides of the chemical equation.

What is a chemical equation?

A chemical equation is typically used in chemistry to represent the chemical reaction between two (2) or more chemical elements.

What is a balanced equation?

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

This ultimately implies that, the following must be in place for a balanced chemical equation:

Ideally, the first step in balancing a chemical equation is to count the number of atoms in the reactant and product side of the chemical equation.

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When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.

When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.

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The Celsius temperature for this reaction is 1882\(^{o}C\)

According to the combined gas law, we can say that this law provides relationship between  the properties of the gas. We can find one of the properties such as the pressure, temperature or volume when the other two varies to a certain value using this law.

To determine the temperature we use the below given formula;

\(P_{1}V_{1}\) ÷ \(T_{1}\) = \(P_{2}V_{2}\) ÷ \(T_{2}\)

\(T_{2}\) =   T\(_{1}\)  × \(P_{2}V_{2}\)

     \(P_{1}V_{1}\)

 =      273K       × 500×600

         760 × 50

  = 2155K

When we convert this into degree Celsius

= 2155 - 273 = 1882 \(^{o} C\)

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hope that helps !

Answer:

6 moles of Iron(II) Oxide

Answer:

1.2 mol

Explanation:

due to energy transfer when the object move there is a change in the form of energy

Explanation:

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\(\rule{2000pt}{1000000pt}\)

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Answer:

Its axis is tilted by 26.73 degrees with respect to its orbit around the Sun, which is similar to Earth's 23.5-degree tilt. This means that, like Earth, Saturn experiences seasons. Like Jupiter, Saturn is made mostly of hydrogen and helium.

Explanation:

Thats all I could think of, please mark brainliest

Ans:- The correct answer is option B

B. Electrons are transferred from a non-metal element to a metal element.

Expl:

A type of chemical bonding, known as ionic bonding, involves atoms passing electrons to one another to form ions. An ion is an atom or molecule with a positive or negative charge that either gains or loses one or more electrons.

Answer:

When water changes to a solid or gas, it's said that water changes to a different state of matter

Explanation:

Even when water physical form changes, the molecules stay the same. Water's molecules contains two hydrogen atoms that is bonded with one oxygen atom.

The Electron Pair Geometry and molecular geometry of a molecule is determined by the electron group by counting the total number of electron pairs around a central atom.

Electron Pair Geometry defined as the the spatial arrangement of a molecule's bonds and lone pairs. It is determined by the number of electron groups. Molecular geometry can be explained as the geometry which depends on not only on the number of electron groups but also on the number of lone pairs. When the electron groups are all bond pairs, they are named exactly like the electron pair geometry. The electron pairs are the bonded electrons, lone pairs and single unpaired electrons. It the total number of electron pairs is estimated the electron pair geometry of the molecule can be drawn.

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Answer:

4.9 × 10²³ molecules

Explanation:

Given data:

Number of molecules = ?

Number of moles of oxygen = 0.815 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.815 mol  ×  6.022 × 10²³ molecules  / 1 mol

4.9 × 10²³ molecules

Answer:

B. 75.0 kPa

Explanation:

P1V1/T1=P2V2/T2

(x * 100 L)/(300 K)=(100 kPa * 50.0 L)/(200 K)

x=75.0 kPa

Answer:

24rq3r54

Explanation:

3t5q6tq6tq

Answer:

around a minute

Explanation:

Option A.

The number of molecules of carbon tetrachloride in 6.32 mg of the compound is 2.47 x 10¹⁹ molecules.

The molecular mass of Carbon tetrachloride is calculated as follows;

Molecular formula = CCl₄

CCl₄ = (12) + (35.5 x 4)

CCl₄ = 154 g/mol

The number of moles of carbon tetrachloride in 6.32 mg is calculated as follows;

n = reacting mass / molar mass

n = (6.32 x 10⁻³) / (154)

n = 4.1 x 10⁻⁵ moles

1 mole of CCl₄ = 6.02 x 10²³ molecules

4.1 x 10⁻⁵ moles of CCl₄ = ?

= 2.47 x 10¹⁹ molecules

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Answer:

the answer is is C 465 grams

Answer:

This tells you that when 1 mole of propane undergoes combustion, 3 moles of carbon dioxide are produced. You can thus say that when 2.0 moles of propane react, you will get 2.0moles C3H8 ⋅ 3.moles CO2 1mole C3H8 = 6.0 moles CO2

Explanation: