The capacitance of the oscillating LC circuit if the maximum charge on the capacitor is 1.60 μc and the total energy is 140 μj, is approximately 9.14 microfarads (μF).
To find the capacitance of an oscillating LC circuit, given the maximum charge on the capacitor and the total energy, we can use the following equations:
The maximum charge on the capacitor (Q) is related to the capacitance (C) and the maximum voltage (V) by the equation Q = C * V.
The total energy (E) stored in the LC circuit is given by the equation E = (1/2) * C * \(V^2\).
In this case, we are given the maximum charge on the capacitor (Q = 1.60 μC) and the total energy (E = 140 μJ). We need to find the capacitance (C).
From equation 1, we can rewrite it as V = Q / C and substitute it into equation 2 to solve for C:
E = \((1/2) * C * (Q / C)^2\)
140 μJ = (1/2) * C * (1.60 μC / C\()^2\)
140 μJ = (1/2) * C * (1.60 μC)\(^2 / C^2\)
140 μJ = (1/2) * 2.56 μ\(C^2 / C\)
140 μJ = 1.28 μ\(C^2 / C\)
C = 1.28 μ\(C^2\)/ (140 μJ)
C ≈ 9.14 μF
Therefore, the capacitance of the oscillating LC circuit is approximately 9.14 microfarads (μF).
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You are looking straight down on a magnetic compass that is lying flat on a table. A wire is stretched horizontally under the table, parallel to and a short distance below the compass needle. The wire is then connected to a battery so that a current I flows through the wire. This current causes the north pole of the compass needle to deflect to the left. The questions that follow ask you to compare the effects of different actions on this initial deflection. If the wire is lowered farther from the compass, how does the new angle of deflection of the north pole of the compass needle compare to its initial deflection? You did not open hints for this part. It is larger. It is smaller. It is unchanged.
The new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.
The new angle of deflection north pole becomes smaller
The angle of deflection is the angle formed when an object changes course from its original course of direction or target.
The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.
As the wire is continuously being lowered farther from the compass, the angle of deflection of the north pole continues to become smaller when compared to its initial deflection.
Therefore, the new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.
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Michael has a constant elasticity of substitution (CES) utility function, U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
, where rho
=0 and rho≤11 14
Given that Michael's rho<1, what are his optimal values of q 1
and q 2
in terms of his income and the prices of the two goods? Answer 1. Substitute the income constraint into Michael's utility function to eliminate one control variable. Michael's constrained utility maximization problem is max q 1
,q 2
U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
s.t. Y=p 1
q 1
+p 2
q 2
We can rewrite Michael's budget constraint as q 2
=(Y−p 1
q 1
)/p 2
. Substituting this expression into his utility function, we can express Michael's utility maximization problem as: max q 1
U(q 1
, p 2
Y−p 1
q 1
)=(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) 1/rho
. By making this substitution, we have converted a constrained maximization problem with two control variables into an unconstrained problem with one control variable, q 1
2. Use the standard, unconstrained maximization approach to determine the optimal value for q 1
. To obtain the first-order condition, we use the chain rule and set the derivative of the utility function with respect to q 1
equal to zero: rho
1
(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) rho
1−rho
(rhoq 1
rho−1
+rho[ p 2
Y−p 1
q 1
] rho−1
[−− p 2
p 1
])=0 Using algebra, we can solve this equation for Michael's optimal q 1
as a function of his income and the prices: 15 (3.18) q 1
= p 1
1−σ
+p 2
1−σ
Yp 1
−σ
where σ=1/[1−rho]. By repeating this analysis, substituting for q 1
instead of for q 2
, we derive a similar expression for his optimal q 2
: (3.19) q 2
= p 1
1−σ
+p 2
1−σ
Yp 2
−σ
Thus, the utility-maximizing q 1
and q 2
are functions of his income and the prices.
The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.
The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).
1. Substitute the income constraint into Michael's utility function:
\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)
s.t. \(Y = p_1q_1 + p_2q_2\)
We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:
\(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)
By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).
2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:
\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)
Simplifying and solving for \(q_1\):
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
3. Similarly, we can derive a similar expression for his optimal \(q_2\):
\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).
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g what is the panspermia hypothesis? a. the birth of life on earth is inevitable. b. life can emerge within a planetary nebula. c. life can easily emerge in close proximity to a star exhibiting 50 times the sun's mass. d. life has formed elsewhere and drifted to earth (e.g., via a comet).
The panspermia hypothesis is d. life has formed elsewhere and drifted to earth (e.g., via a comet).
Anaxagoras, a Greek philosopher, first proposed the idea of panspermia in the 5th century BCE. It states that spacecraft carrying unintentional microorganism contamination by means of space dust, asteroids, comets, planetoids, and meteorites spread life throughout the universe. Panspermia is a speculative theory that is not well-supported by mainstream scientists. It is argued by critics that it merely places life on another celestial body and does not provide an answer to the question of where life came from. Additionally, it is criticized for its inability to undergo experimental testing.
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What will happen to an object that is moving forward if a force pushing it backward is greater than the force pushing it forward?
Group of answer choices
A)The object will move at constant speed for a while and then slow down and stop.
B)The object will slow down, stop, and then begin to move faster and faster in the opposite direction.
C)The object will slow down, stop, and then begin to move at a constant speed in the opposite direction.
D)The object will slow down for a while and then move at a slower constant speed.
i need this answer very badly
Answer:
\ c,. ,;
Explanation:
When potential energy decreases, kinetic energy
Answer:
Kinetic energy increase
Answer:
increases
Explanation:
What Determines the amount of TE of an object
Answer:
To find the volume of a rectangular object, measure the length, width and height. Multiply the length times the width and multiply the result by the height. The result is the volume. Give the result in cubic units, such as cubic centimeters.
Explanation:
Answer:
Kinetic energy is the energy possessed by an object due to its motion. If an object is moving, then it has kinetic energy. The amount of kinetic energy depends on mass and speed.
Explanation:
Calculate pressure exerted perpendicularly on an area of 2ft2 by a bicycle weighing 301 b 10. Using the equation − "Equivalent = mass of compound / Equivalent weight": a. Calculate the equivalent weight of CaCO3 b. If the molar mass of Na+is 23 grams, what is its equivalent weight? 11. If the com yields were determined to ne 18 kg per hectare, how many lbs per hectare that is?
a) Equivalent weight of CaCO3 = Molar mass / Number of equivalents = 100.09 g/mol / 1 = 100.09 g/mol.
b) The yield of 18 kg per hectare is equivalent to 39.682 pounds per hectare.
a. To calculate the equivalent weight of CaCO3, we need to determine its molar mass and the number of equivalents of the compound.
The molar mass of CaCO3 is:
Ca: 40.08 g/mol
C: 12.01 g/mol
O: 16.00 g/mol (3 oxygen atoms in CaCO3)
Molar mass of CaCO3 = (40.08 g/mol) + (12.01 g/mol) + (16.00 g/mol × 3) = 100.09 g/mol
The equivalent weight is calculated by dividing the molar mass by the number of equivalents. In the case of CaCO3, it is assumed to be a monoprotic acid with one equivalent per mole.
Equivalent weight of CaCO3 = Molar mass / Number of equivalents = 100.09 g/mol / 1 = 100.09 g/mol
b. The equivalent weight of Na+ can be calculated using its molar mass and the number of equivalents.
The molar mass of Na+ is 23 grams per mole. Since Na+ carries a charge of +1, it is also equivalent to its molar mass.
Equivalent weight of Na+ = 23 g/mol
To convert the yield from kilograms per hectare to pounds per hectare, we need to use the conversion factor 1 kilogram (kg) = 2.20462 pounds (lbs).
If the yield is 18 kg per hectare, we can calculate the equivalent value in pounds per hectare:
18 kg * 2.20462 lbs/kg = 39.682 lb
Therefore, the yield of 18 kg per hectare is equivalent to 39.682 pounds per hectare.
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A transformer having a 180 turns of coil on its primary coil accommodates 220 volts. If its secondary coil has 100 turns… 1. How much voltage of electricity is generated by it? ______ 2. And what type of transformer is it? ______
This transformer is a step-down transformer as the voltage on the secondary coil is lower than the voltage on the primary coil. A step-down transformer is used to decrease the voltage level, while a step-up transformer increases the voltage level.
The voltage generated by the transformer can be calculated using the formula V1/V2 = N1/N2, where V1 is the voltage on the primary coil, V2 is the voltage on the secondary coil, N1 is the number of turns on the primary coil and N2 is the number of turns on the secondary coil. In this case, V1 is 220 volts, N1 is 180 turns and N2 is 100 turns. Therefore, the voltage on the secondary coil can be calculated as follows:
220/V2 = 180/100
V2 = (100 x 220) / 180
V2 = 122.22 volts
So, the voltage generated by the transformer is 122.22 volts.
Based on the given information, this transformer is a step-down transformer as the voltage on the secondary coil is lower than the voltage on the primary coil. A step-down transformer is used to decrease the voltage level, while a step-up transformer increases the voltage level.
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I Need help asappp!!!
Answer: Inertia
Explanation: If it is multiple choice chose acceleration and inertia
hat would the final velocity be, in meters per second, if the car with the 68-kg passenger had collided with (and stuck to) a car that has an equal mass and is traveling in the opposite direction and at the same speed?
The final velocity of the car with 68-kg passenger on it is 0m/sec.
If we assume car having 68-kg passenger is travelling in positive x-direction then the other car which is travelling in opposite direction will travels in negative x-direction.
So, assuming velocity of car having 68 passenger as v m/sec
Therefore, velocity of car which is travelling in opposite direction of first car is = -v m/sec
Now, after collision both car gets struck, it means that both of them are travelling together and have common velocity.
So, assume final velocity of both car as V
Now, we need to conserve momentum in x-direction.
We know that momentum=mass × velocity
Therefore,
Initial momentum=Final momentum
=>m × v - m × v = (m + m)×V
=>0=2mV
=>V=0m/sec.
Hence, final velocity of car is 0m/sec.
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for a real gas to approach the properties of an ideal gas, the pressure should be , the attractions between the gas particles should be , and the temperature should be . {fill in each blank with the word high or low as appropriate.}
For a real gas to approach the properties of an ideal gas, the pressure should be low, the attraction between the molecules should be high and temperature should be high.
An ideal gas is defined as a gas that obeys gas laws at all pressure and temperature conditions. Ideal gases have velocity as well as mass. They have no volume.The ideal gas law is the equation of the state of a hypothetical ideal gas, also called the general gas equation : pV=nRTwhere, p= pressure
V= volume
n= number of moles
R= ideal gas constant
T= temperature
When molecules are almost in contact and for ideal gas the assumption is that there are negligible attractive forces between gas molecules.Real gases show ideal behaviour when conditions of temperature and pressure are such that the intermolecular forces are practically negligible.This can only happen at very low pressure and very high temperature.To know more about gases visit:
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plsssss asappppppppp
Answer:
20 meters.
Explanation:
In the graph, the x-axis (the horizontal axis) represents the time, while the y-axis (the vertical axis) represents the distance.
If we want to find the distance covered in the first T seconds, you need to find the value T in the horizontal axis.
Once you find it, we draw a vertical line, in the point where this vertical line touches the graph, we now draw a horizontal line. This horizontal line will intersect the y-axis in a given value. That value is the total distance travelled by the time T.
In this case, we want to find the total distance that David ran in the first 4 seconds.
Then we need to find the value 4 seconds in the horizontal axis. Now we perform the above steps, and we will find that the correspondent y-value is 20.
This means that in the first 4 seconds, David ran a distance of 20 meters.
Which of the following is NOT a step in the technical design
process?
Answer:
incurriculum design process the answer is designs
Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
The missing neutrinos from the sun had merely tranformed into muon and tau neutrinos escaped detection.Hardly interacting with other matter,neutrinos comes in three different types electron,muon,and tau.
Hence option (b) turning into different type of neutrino in a neutrino oscillation is correct
Disclaimer:The question given on the portal is incomplete .Here is the complete question .
Question :Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
a)not being produced by the Sun because our star's nuclear fusion period has ended
b)turning into a different type of neutrino in a neutrino oscillation
c)being converted to antimatter in the core of the Sun and being destroyed as they hit matter
d)changing course before they reach the Earth as they hit other neutrinos in space
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A wave is traveling at the speed of light. If it has a frequency of 4 x 10^15 Hz, what is its wavelength?
Answer:
7.5x10-^8m
Explanation:
the formulae is v=fh ,where f is frequency
h is wavelength
hence wavelength=v/f
since the speed of light is 3x10^8
then the wavelength =3 x 10^8/4 x 10^15
=7.5x10^-8m
photon strikes the surface of tungsten and an electron is emitted. what is the maximum possible speed of the electron?
Answer: The maximum possible speed v is √2( hν - Ф ) / m
Explanation: You could be referring to the provided explanation, despite the fact that the question isn't comprehensive. When a photon collides with the surface of any metal, it transmits all of its energy to the electron in the atom. The collision causes the electron to travel with a certain amount of kinetic energy. This is referred to as the photoelectric effect. The maximum kinetic energy is calculated using Einstein's equation for the photoelectric effect:
K.E. = hν - Ф
½ mv² = hν - Ф
Hence the maximum possible speed is:
v = √2( hν - Ф ) / m
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Cosmic background radiation detected in space is believed to be evidence that:
1-The universe began with an explosion
2-The universe is contracting
3-All matter in the universe is stationary
4-Galaxies are evenly spaced throughout the universe
Answer:
CMB is landmark evidence of the Big Bang origin of the universe. When the universe was young, before the formation of stars and planets, it was denser, much hotter, and filled with an opaque fog of hydrogen plasma.
Cosmic background radiation detected in space is believed to be evidence that, the universe began with an explosion, therefore the correct answer is option 1.
What is a solar system?It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.
Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.
Before the creation of stars and planets, the cosmos was denser, considerably hotter, and covered with an opacity of hydrogen plasma.
Cosmic background radiation detected in space is believed to be evidence that, the universe began with an explosion,
Thus, the correct answer is option 1.
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a ball of 5 kg is moving towards the wall at 6 m/s. after a while, it hits the wall and rebounds back at 4 m/s in the opposite direction. what is the work done on it?
Answer:-50 J
Explanation:
Answer: -50 N
Explanation:
A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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A 3.09 x 10-4 T magnetic field points directly east. A loop of area 0.0471 m2 faces directly northeast. What is the magnetic flux through the loop?
Answer:
1.03 * 10^-5
Explanation:
The magnetic flux through the loop is approximately 1.317 × \(10^{(-5)\)T·m².
To calculate the magnetic flux through a loop, we use the formula:
Φ = B × A × cos(θ)
Where:
Φ is the magnetic flux
B is the magnetic field strength
A is the area of the loop
θ is the angle between the magnetic field and the normal to the loop
Given:
Magnetic field strength (B) = 3.09 × \(10^{(-4)\) T (east direction)
Area of the loop (A) = 0.0471 m²
The loop faces directly northeast
To find the angle θ, determine the angle between the magnetic field direction (east) and the normal to the loop (northeast).
Since the loop faces northeast, the angle between the normal to the loop and the east direction is 45 degrees (90 degrees divided by 2).
Now calculate the magnetic flux:
Φ = B × A × cos(θ)
Φ = (3.09 × \(10^{(-4)\) T) × (0.0471 m²) × cos(45°)
Using the value of cos(45°) as 0.7071:
Φ = (3.09 × \(10^{(-4)\) T) × (0.0471 m²) ×0.7071
Φ = 1.317 × \(10^{(-5)\) T·m²
Therefore, the magnetic flux through the loop is approximately 1.317 × \(10^{(-5)\) T·m².
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A doll sets on the a table 3 meters high weighing 1.5kg. What is the gravitational potential energy?
A-4.5 joules
B-19.6 joules
C-14.7 joules
D-44.1 joules
Answer:
Explanation:
A - 4.5
Convert the orbital period 27.32 days into units of seconds
Answer:
\(2360448seconds\)
Explanation:
Dimensional analysis is attached.
A uniform meter rule of mass 10g is balanced on a knife edge placed at 45cm mark. Calculate the distance of a mass 25g from the pivot
Answer:
2 cm.
Explanation:
Please see attached photo for diagram.
In the attached photo, y is the distance from the pivot to which the 25 g is placed.
The value of y can be obtained as follow:
Clockwise moment = 5 × 10
Anticlock wise moment = y × 25
Anticlock wise moment = Clockwise moment
y × 25 = 5 × 10
y × 25 = 50
Divide both side by 25
y = 50/25
y = 2 cm
Thus, the distance is 2 cm
How much energy is required to increase the temperature of 10kg of water by 50°C?
The specific heat capacity of water is 4200J/kg °C. Use the equation
change in thermal energy = mass specific heat capacity x temperature change.
Explanation:
Q = mc∆T
Known and Unknown
Q = heat energy = ? kJ
m = mass = 10 kg
c = specific heat capacity of water = 4.2 kJ/kg•K = 4.2 kJ/kg•°C
∆T = change in temperature = 50 °C
Solve for Q.
Q = 10 kg × 4.2 kJ/kg•°C × 50 °C = 2100 kJ = 2000 kJ
PLZ PLZ PLZ PLZ PLZ PLZ PLZ HELPPPPPPPPPPPPPPPPP
Answer:
endoplasmic reticulum
People breathe. Calculate the number of moles in the 2.1 L volume of air in the lungs of the average person. Note that the air is at 37°C (body temperature)
Given:
• Volume of air in lungs = 2.1 L
,• Temperature of air = 37°C
Apply the equation of ideal gas law:
\(PV=nRT\)Rewrite the equation for n:
\(n=\frac{PV}{RT}\)Where:
• P is the pressure = 1.013 x 10⁵ N/m²
,• V is the volume in m³ = 2.10 x 10⁻³ m³
,• R is the gas constant = 8.31 J/mol .K
,• T is the temperature in kelvin
,• n is the number of moles of atoms.
Now, convert the temperature to Kelvin:
\(T=37^oC+273.15k=310.15\text{ k}\)Now, substitute values into the equation and solve for n:
\(n=\frac{(1.013*10^5)*(2.10*10^{-3})}{8.31*310.15}\)Solving further:
\(\begin{gathered} n=\frac{212.73}{2577.3465} \\ \\ n=0.0825\approx8.25\times10^{-2\text{ }}mol \end{gathered}\)Therefore, the number of moles is 8.25 x 10⁻² mol
ANSWER:
8.25 x 10⁻² mol.
True or false
Forces/Dynamics
Answer:they answer is false
Answer:
6.T
7.T
8.F
9.F
10.T
Explanation:
In 2020, nasa confirmed the existence of what on the lunar surface?.
How does the change in the state of matter occur? Write with example
Answer:
When matter changes from one state to another, it either absorbs energy—as when chocolate melts—or loses energy. For example, if you were to place the melted chocolate in a refrigerator, it would lose energy to the cold air inside the refrigerator. As a result, the liquid chocolate would change to a solid again.
Explanation:
hope it helps u
Water
Glass
A ray of light enters glass at 45° to the horizontal from water. If
the index of refraction of water is 1.3, and index of refraction of
glass is 1.5, then what is the angle of the refracted ray?
Answer: 22
Explanation: