what is the direction of the frictional force exerted on a coffee cup sitting on a stationary table? there is no frictional force being exerted on the cup. downward. upward. to the right. to the left.

The angle of the trajectory (in degrees) relative to the horizontal at t = 0.3 s is calculated as to be equal to 50.47° (approx). Initial vertical velocity (vy) can be obtained by using the following formula, vy = usinθ.

The angle of the trajectory is θ = 60° with the horizontal. The time elapsed is t = 0.3 s.

The vertical acceleration is a = -9.81 m/s².(Negative sign indicates the downward acceleration due to gravity.)

Initial vertical velocity (vy) can be obtained by using the following formula, vy = usinθ

Where, u is the initial velocity and θ is the angle of the trajectory with the horizontal.

Using the values of u and θ,

vy = 30 m/s × sin 60°vy

= 30 m/s × √3/2vy

= 25.98 m/s

The final vertical velocity (v) at t = 0.3 s can be calculated using the following formula, v = u + at

Where, a is the acceleration and t is the time elapsed.

v = 25.98 m/s + (-9.81 m/s² × 0.3 s)v

= 25.98 m/s - 2.943 m/sv

= 23.04 m/s

Now, we have initial and final velocities. The angle of trajectory at t = 0.3 s can be calculated by using the following formula,θ = sin⁻¹ (v/ u)Where, v and u are the initial and final velocities

.θ = sin⁻¹ (23.04 m/s / 30 m/s)θ = sin⁻¹ (0.768)θ = 50.47°

Hence, the angle of the trajectory (in degrees) relative to the horizontal at t = 0.3 s is 50.47° (approx).

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Answer:

what is this ???✔️✔️✔️

Explanation:

plz give explanation i don't understand ✔️✔️

Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.

1. The average speed of Luis over the 60 s is 1.33 m/s

2. The average velocity of Luis over the 60 s is zero.  

1. The average speed can be calculated with the following equation:

\( S = \frac{d}{t} \)

Where:

d: is the total distance traveled

t: is the total time = 60 s

The total distance can be calculated by the sum of the distance traveled to the truck (40 m) and the distance traveled to his home (the same 40 m), as follows:

\( d = 40 m + 40 m = 80 m \)

So, the average speed is:

\( S = \frac{d}{t} = \frac{80 m}{60 s} = 1.33 m/s \)

Hence, Luis's average speed over the 60 s is 1.33 m/s.

2. Now, the average velocity is a vector given by:

\(v = \frac{\Delta x}{\Delta t} = \frac{x_{f} - x_{i}}{t}\)

Where:

\(x_{f}\): is the final distance traveled (the way to his home) = 40 m

\(x_{i}\): is the initial distance traveled (the way to his truck) = 40 m

Δt: is the total time = t = 60 s

Given that Luis in his journey, returns to the same starting point (his house), the total displacement is zero, and so the average velocity is also zero:                              

\(v = \frac{x_{f} - x_{i}}{t} = \frac{40 m - 40 m}{60 s} = 0\)

Therefore, Luis's average velocity over the 60 s is zero.  

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As shown in the figure below, Luis rushes 40 m toward his truck. He notices he forgot his shoes and returns back to his house. His total travel time is 60 s.

Answer:

What is Luis’s average velocity over the 60 s period?

Answer: 0 m/s

What is Luis’s average speed over the 60 s period?

Answer: 1.33  m/s

Around 3 p.m., when the sun is sufficiently low in the sky, more heat is lost than is received.

Even though the sun's beams are most direct around noon, the afternoon is the warmest part of the day because air temperatures close to the earth's surface will continue to rise as long as incoming solar radiation outweighs outgoing longwave earth radiation.

Around 3 p.m., it gets the warmest. When the sun is at its zenith in the sky, or after midday, heat continues to accumulate as long as more heat is entering the earth than is leaving. When the sun is low enough in the sky, around 3 p.m., more heat is lost than is gained.

Many people believe that noon is when it gets the warmest. We receive the maximum energy from the sun at noon, which may make it feel hotter. But during the day, Earth is accumulating heat or energy from incoming sources. The air becomes warmer as the day goes on.

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The final volume of the balloon is 197,083 L.

They are proportional to each other if the pressure does not change. However, there are pitfalls. To perform calculations we have to use the so-called absolute temperature. Increased external air pressure compresses the balloon.

Using equation;

PV =nRT

here constants are P,n, R

so the relation between P and T is

V₁ /T₁= V₂/T₂

V₂ = (V₁ /T₁)×T₂

    = (125,000/300)×473

     = 197,083 L.

As the volume of the balloon decreases the pressure inside the balloon increases. After all external air pressure can compensate. It becomes a balloon filled with dense cold air. According to Boyle's law, the volume of a gas of constant mass at constant temperature is inversely proportional to its pressure. The air around you has weight and pushes away everything it touches. This pressure is called atmospheric pressure or barometric pressure. This is the force exerted on a surface by the air above as gravity pulls the surface toward the Earth.

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The cost of using 50 W for one day or 24 hours is  dollar 0.12. The cost of using 800 W for 1 hour is 0.08 dollar.

Power is the rate of work done energy of  an object. Given that the cost of using 1 KWhr energy is dollar 0.10.

Then cost of using 50 W  or 0.05 KW in 24 hours is

0.05 × 24 ×  0.10  = 0.12 dollar

Cost of using 800 W or 0.08 KW per hour is 0.08 KWhr × 0.10 = dollar 0.08

Similarly, the cost of using 150 W in one month is find as follows:

150 W = 0.15 KW

energy used  = 0.15 × 30 × 24 hrs

cost = 0.15 × 30 × 24 hrs × 0.10 = dollar 10.8

The energy causing a cost of 2.5 dollar is 2.5/0.10 = 25 KWhr

power = 25 KWHr/24 hrs = 1.04 KW.

The energy causing a cost of 4 dollars is 4/0.10 = 40 KWhr

power =40 KWHr/24 hrs = 1.6 KW.

The energy causing the cost of 3 dollars  = 3/0.10 = 30 KWhr

then time = 30/100 W = 0.3 hr.

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When light passes from one medium to another medium with a different refractive index, it changes its direction of propagation, which is described by Snell's law.  The final direction of the light ray depends on the refractive indices of the three media and the angle of incidence of the ray on the liquid-glass interface.

Total internal reflection occurs when light travels from a medium with a higher refractive index to a medium with a lower refractive index at an angle greater than the critical angle.The given scenario involves a light ray that is travelling inside a horizontal plate of glass. The angle of incidence of the ray striking the upper surface of the glass is 50∘. As the light ray passes through the glass, it experiences a change in its direction due to the difference in refractive index of glass and air.

As the angle of incidence of the light ray is greater than the critical angle, it gets totally internally reflected at the glass-air boundary. However, when a liquid is poured on top of the glass, the situation changes. This is because the refractive index of the liquid is different from that of the air, and hence the light ray will undergo refraction again as it enters the liquid.Apart from the difference in refractive indices, the angle of incidence of the light ray also changes as it enters the liquid.

This leads to a change in the direction of the refracted ray, which may or may not undergo total internal reflection again, depending on the angle of incidence and the critical angle of the liquid. Therefore, the final direction of the light ray depends on the refractive indices of the three media and the angle of incidence of the ray on the liquid-glass interface.

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Answer: B

Explanation: it is perpendicular to a surface

Answer:

it is perpendicular to a surface

Explanation:

The kinetic energy gained by the electron if it is released from rest at a location 0.10 m from the negative plate and arrives at a distance 0.050 m from the positive plate is 2.4 *  \(10^{-19}\) J

E = Q / 2 εo  A

F = q E

E = Electric field inside a parallel plate capacitor

Q = Charge on capacitor

A = Area of one of the plates

F = Electric force on electron

q = Charge of electron

F = q Q / 2 εo  A

C = εo  A / d = Q / V

C = Capacitance

d = Distance between plates

V = Voltage

V = 12 V

d = 0.2 m

Q / εo  A = V / d

Q / εo  A = 12 / 0.2

Q / εo  A = 60

F = q Q / 2 εo  A

F = q * 60 / 2

F = 30 q

ΔKE = F x

q = 1.6 * \(10^{-19}\) C

ΔKE = 30 * 1.6 * \(10^{-19}\) * 0.05

ΔKE = 2.4 *  \(10^{-19}\) J

Therefore, the kinetic energy gained by the electron is 2.4 *  \(10^{-19}\) J

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Answer:

The answer is C

I just took the quiz

The statement (C) atomic identity changes but the total number of protons and neutrons do not is correct.

The addition or deletion of protons to a nucleus is referred to as transmutation. A transmutation occurs when deuterium is converted to helium.

We have a decay equation shown below:

\(\rm _{11}^{6}\textrm{C} \rightarrow_{11}^{5}\textrm{B}+_{0}^{+1}\textrm{e}\)

As the one-electron subtraction occurred and atom C becomes atom B so the decay equation is affected by atomic identity, but not by the total number of protons and neutrons.

Thus, the statement (C) atomic identity changes but the total number of protons and neutrons do not is correct.

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To determine the acceleration of Runner A and Runner B during the final 10 seconds of the race, we can use the following formula:

Acceleration (a) = (Final Velocity - Initial Velocity) / Time

Given:

- Initial velocity for both runners: +14 km/h

- Final velocity for Runner A: +20 km/h

- Final velocity for Runner B: +18 km/h

- Time: 10 seconds

Let's calculate the accelerations for Runner A and Runner B:

For Runner A:

Acceleration (Runner A) = (+20 km/h - +14 km/h) / 10 seconds

Converting the velocities to m/s and the time to seconds:

Acceleration (Runner A) = ((20 km/h - 14 km/h) * (1000 m/km) / (3600 s/h)) / 10 seconds

Simplifying the calculation:

Acceleration (Runner A) = (6 km/h * (1000 m/km) / (3600 s/h)) / 10 seconds

Acceleration (Runner A) = (6000 m / 36000 s) / 10 seconds

Acceleration (Runner A) = 0.1667 m/s²

For Runner B:

Acceleration (Runner B) = (+18 km/h - +14 km/h) / 10 seconds

Converting the velocities to m/s and the time to seconds:

Acceleration (Runner B) = ((18 km/h - 14 km/h) * (1000 m/km) / (3600 s/h)) / 10 second

Simplifying the calculation:

Acceleration (Runner B) = (4 km/h * (1000 m/km) / (3600 s/h)) / 10 seconds

Acceleration (Runner B) = (4000 m / 36000 s) / 10 seconds

Acceleration (Runner B) = 0.1111 m/s²

Therefore, the accelerations of Runner A and Runner B during the final 10 seconds of the race are:

- Runner A: 0.1667 m/s²

- Runner B: 0.1111 m/s²

None of the provided options match these values.

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v = λf

v = 87 x 2 = 174 m/s

A water wave has a speed of 23.0 meters/second. If the wave's frequency is 0.0680 hertz, then the wavelength is B) 338 meters. Hence, option B) is the correct answer.

Wavelength (λ) is the distance between two consecutive crests or troughs in the wave. The formula to calculate wavelength is given by: Wavelength (λ) = Speed (v) / Frequency (f)

Where, v = 23.0 m/s (Wave speed), f = 0.0680 Hz (Wave frequency)

Substitute the given values in the formula to obtain;

λ = v / fλ

= 23.0 / 0.0680λ

= 338 meters

Therefore, the wavelength of the water wave is 338 meters.

Option B) 338 meters is the correct answer.

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Among the variables mentioned, the most important factor that influences drag on an object in the experiments conducted is the object's area.

Drag is the force that opposes the motion of an object through a fluid (such as air or water). It depends on several factors, including the object's area, shape, speed, and the properties of the fluid. However, in the context of the experiments conducted, the area of the object is the most significant factor.

The larger the surface area of an object facing the fluid flow, the greater the drag force it experiences. This is because a larger area creates more resistance to the fluid, resulting in higher drag. Other variables mentioned, such as the length, roughness, specific gravity, material, and density of the object, may indirectly influence drag by affecting the object's shape or ability to streamline, but they are not as directly correlated to drag as the area.

By controlling the area of the object in the experiments, researchers can investigate the impact of drag on the object's motion. Altering the object's area allows for comparative analysis to understand how changes in surface area affect the drag force experienced, providing insights into fluid dynamics and the relationship between objects and their environment.

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Cyclotron to make 1 milligram of the isotope fluorine-18 for use a a diagnostic tool with it PET scanner. It seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

The half-life of F-18 is 1.8 hours, so after 1.8 hours, half of the original amount of F-18 will remain. After 3.6 hours, a quarter of the original amount will remain, and so on.

At 3:00 PM (9 hours after the F-18 was made), the hospital will have

= 1/2^(9/1.8)

= 1/2^5

= 1/32

= approximately 0.03125 milligrams of F-18 remaining.

At midnight (18 hours after the F-18 was made), the hospital will have

= 1/2^(18/1.8)

= 1/2^10

= 1/1024

= approximately 0.0009765625 milligrams of F-18 remaining.

While using cyclotron, based on these calculations, it seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

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Answer:

My speed is 4 m/s

Explanation:

\(V=\frac{d}{t}=\frac{20m}{5s} =4\frac{m}{s}\)

Answer:

D

Explanation:

Answer:

A. NGC 3603 would be classified as Nebula

Explanation:

Explanation:

The spring will 'stretch out ' ...or be 'sprung'.......it will no longer recoil...it is broken...the spring constant no longer applies

Answer:

down below

Explanation:

Since we aren't the given the time, lets say that an object to 25 seconds to fall 50 meters. We can use the formula [ s = d/t ] to solve.

s = 50/25

s = 2

Therefore, the object was falling at a rate of 2 meters per second.

Best of Luck!

If 1.00 kg of zn reacted with excess sulfur, approximately 3320.76 kJ of energy would be released.

To determine the amount of energy released in a chemical reaction, we need to know the balanced chemical equation for the reaction involving zinc (Zn) and sulfur (S).

Once we have the balanced equation, we can use the corresponding enthalpy change (ΔH) to calculate the energy released.

The balanced chemical equation for the reaction between zinc and sulfur is:

Zn + S → ZnS

According to the equation, 1 mole of zinc (Zn) reacts with 1 mole of sulfur (S) to form 1 mole of zinc sulfide (ZnS).

The molar mass of zinc (Zn) is approximately 65.38 g/mol.

To calculate the energy released, we need the enthalpy change of the reaction, which is typically given in kilojoules per mole (kJ/mol).

Since we don't have the specific enthalpy change for this reaction, we'll assume it to be -217 kJ/mol, which is the standard enthalpy of formation for zinc sulfide (ZnS).

Now, let's calculate the energy released when 1.00 kg of zinc reacts:

Convert mass of zinc to moles:

Mass of zinc = 1.00 kg = 1000 g

Moles of zinc = Mass of zinc / Molar mass of zinc

= 1000 g ÷ 65.38 g/mol

≈ 15.28 mol

Calculate the energy released:

Energy released = Moles of zinc × ΔH

= 15.28 mol × (-217 kJ/mol)

≈ -3320.76 kJ

Since energy cannot be negative, we take the absolute value:

Energy released ≈ 3320.76 kJ

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Earth's heat absorption is balanced by reflected and emitted radiation under natural conditions.

Under natural conditions, the Earth's atmosphere and surface absorb solar radiation as short-wave radiation.

This absorbed energy is then balanced by a combination of reflected radiation and emitted radiation.

Reflected radiation occurs when solar radiation bounces back off the Earth's atmosphere or surface and is redirected back into space.

Emitted radiation occurs when the absorbed energy is re-radiated back into the atmosphere as long-wave radiation. The balance between absorbed, reflected, and emitted radiation is important in maintaining a stable climate on Earth. Changes in this balance, due to factors such as human activity, can have significant impacts on the Earth's climate system.

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Answer:

36.3 g

Explanation:

 1.21  g/ml  *  30 ml   = 36.3 g     ( see how the 'ml' units cancel ?)

Hi there!

We can use Newton's Second Law to solve:

\(\large\boxed{\Sigma F = ma}}\)

∑F = Net force (N)

m = mass (kg)

a = acceleration (m/s²)

Rearrange the equation to solve for acceleration:

\(\large\boxed{a = \frac{F}{m}}\)

Plug in the values given to solve for the magnitude of the force.

\(a = \frac{95.4}{16} = \boxed{5.96 m/s^2 \text{ To the left}}\)

**However, if we want to assign the left direction to be NEGATIVE, then the acceleration of the cart due to a leftward net force would be -5.96 m/s².

(a) The change in kinetic energy is, 269,200 J

(b) The magnitude of the change in momentum is, 20,300 kg m/s

The change in the truck's kinetic energy can be calculated using the formula ΔK = Kf - Ki, where Kf is the final kinetic energy and Ki is the initial kinetic energy. Since kinetic energy is proportional to the square of velocity, we can calculate the initial and final kinetic energies in terms of velocity:

Ki = (1/2)mv1² = (1/2)(2150 kg)(8.61 m/s)^2 = 78,400 J

Kf = (1/2)mv2² = (1/2)(2150 kg)(18.06 m/s)^2 = 347,600 J

Therefore, the change in kinetic energy is:

ΔK = Kf - Ki = 347,600 J - 78,400 J = 269,200 J

The magnitude of the change in momentum can be calculated using the formula Δp = pf - pi, where pf is the final momentum and pi is the initial momentum. Since momentum is proportional to velocity, we can calculate the initial and final momenta in terms of velocity,

pi = mv1 = (2150 kg)(8.61 m/s) = 18,500 kg m/s

pf = mv2 = (2150 kg)(18.06 m/s) = 38,800 kg m/s

Therefore, the magnitude of the change in momentum is:

Δp = pf - pi = 38,800 kg m/s - 18,500 kg m/s = 20,300 kg m/s

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We can change a gas to liquid by decreasing the temperature and increasing the pressure.

Phase transition is the process by which a substance transforms from one state—solid, liquid, or gas—to another. Every element and substance has a precise range of temperatures and pressures at which it can change from one phase to another.

Each substance can transform into one of three phases: solid, liquid, or gas. At specific temperatures, every substance is in one of these three phases. The intermolecular forces acting on the material's molecules and atoms have a significant impact on the temperature and pressure at which the substance will change.

When we change a gas to liquid, we have to decrease in the temperature and increase in the pressure for this phase transition.

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Answer:

120 V

Explanation:

v=i*r

v=0.15*800

v=120