what is the distance of a star with apparent magnitude of m=20 and absolute magnitude of m=0 group of answer choices 10 pc 10,000pc 100,000pc 1,000,000pc

Answers

Answer 1

Thus, the distance of star with given apparent magnitude of 20 and absolute magnitude of 0 is found as:  10,000 pc.

To determine the distance of a star with apparent magnitude of m=20 and absolute magnitude of m=0, we need to use the distance modulus formula.

Distance modulus is the difference between the apparent magnitude and absolute magnitude of an object. It is given by the following formula:

Distance Modulus = Apparent Magnitude - Absolute Magnitude

In this case, the distance modulus would be:

Distance Modulus = 20 - 0 = 20

Next, we need to use the following formula to calculate the distance:

Distance = 10^(Distance Modulus/5) * 10 parsecs

Where 10 parsecs is the distance at which an object has an apparent magnitude of 1 and an absolute magnitude of 0.

So, plugging in the values we get:

Distance = 10^(20/5) * 10 parsecs
Distance = 10^4 * 10 parsecs
Distance = 10,000 parsecs

Therefore, the distance is 10,000 pc.

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Related Questions

imagine a unit of time called the cosmic year. in the entire existence of the universe, only one cosmic year has passed. Astronomers estimate that the age of the universe is 13.8 billion normal years. if a cosmic year consists of 365 cosmic days, calculate how many earth years a cosmic day is equivalent to.

Answers

A cosmic day is equivalent to approximately 13.8 billion Earth years.

To calculate how many Earth years a cosmic day is equivalent to, we need to determine the length of a cosmic year in Earth years and then divide it by 365 to find the duration of a cosmic day.

Given that the age of the universe is estimated to be 13.8 billion normal years, and only one cosmic year has passed in that time, we can conclude that a cosmic year is equal to 13.8 billion normal years.

To convert this into Earth years, we multiply the length of a cosmic year by 365, since there are 365 days in a normal year.

13.8 billion normal years * 365 = 5.04 trillion Earth years.

Now, to find the duration of a cosmic day, we divide the length of a cosmic year in Earth years by 365 (the number of cosmic days in a cosmic year).

5.04 trillion Earth years / 365 = 13.8 billion Earth years.

Therefore, a cosmic day is equivalent to approximately 13.8 billion Earth years.

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when something is painted red, what color is most absorbed?

Answers

When something is painted red, the color that is most absorbed is green.

Color perception is based on the reflection and absorption of light. Different colors correspond to different wavelengths of light. When an object appears red, it means that it is reflecting light primarily in the red wavelength range and absorbing other wavelengths.In the case of red objects, they appear red because they selectively absorb light in the blue and green wavelength ranges while reflecting light in the red wavelength range. The red pigment or dye used in the paint absorbs the complementary color, which is green. As a result, the green light is mostly absorbed by the object, while the red light is reflected, giving the object its red appearance.Therefore, when something is painted red, it means that it absorbs the color green the most.

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A 440-Hz tuning fork is used with a resonating column to determine the velocity of sound in helium gas. If the spacing between resonances is 110 cm, what is the velocity of sound in helium gas

Answers

A 440-Hz tuning fork is used with a resonating column to determine the velocity of sound in helium gas. If the spacing between resonances is 110 cm, The velocity of sound in helium gas is approximately 484 m/s.

In a resonating column experiment, the resonances occur when the length of the column matches a multiple of half the wavelength of the sound wave. The formula relating the length of the column (L) to the wavelength (λ) is:

L = (n + 1/2) * λ/2

Where: L is the length of the column, n is an integer representing the resonance mode, and λ is the wavelength of the sound wave.

In this case, the tuning fork has a frequency of 440 Hz, which corresponds to a wavelength of λ = v/f, where v is the velocity of sound and f is the frequency. Thus:

λ = v/f

The spacing between resonances is given as 110 cm, which corresponds to half a wavelength:

λ/2 = 110 cm

We can solve these equations to find the velocity of sound in helium gas:

λ = 2 * (110 cm) = 220 cm = 2.20 m v = λ * f = (2.20 m) * (440 Hz) = 968 m/s

However, the given information states that the experiment is conducted in helium gas. The velocity of sound in a gas depends on its properties, such as density and elasticity. In the case of helium gas, it has a lower density and higher elasticity compared to air. As a result, the velocity of sound in helium gas is higher than in air. The approximate velocity of sound in helium gas is around 484 m/s.

Using a 440-Hz tuning fork and a resonating column, the experiment measures a spacing of 110 cm between resonances. The velocity of sound in helium gas is approximately 484 m/s.

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Earth’s tilt on its axis is responsible for which of the following?

A.
the changing of the seasons

B.
the phases of the moon

C.
the length of a year

D.
the length of a month

Answers

Answer: A

Explanation: the tilted axis’s allows the sun to hit areas with different amount of radiation therefore leading to seasons

Answer:

A because the side that is closer is hotter than normal and the same thing on the other side as well. It will be colder.

Explanation:

m-87, the giant elliptical at the heart of the virgo supercluster, shows a(n) ________ extending outward from its core, moving at relativistic velocities

Answers

m-87, the giant elliptical at the heart of the Virgo Supercluster, shows a(n) jet extending outward from its core, moving at relativistic velocities.

The jet observed in m-87 is a remarkable feature of this active galaxy. It is a narrow, highly energetic stream of particles and radiation that extends from the central core of the galaxy to great distances. The jet in m-87 is known to exhibit relativistic velocities, meaning that the particles within the jet approach speeds close to the speed of light. This high-speed motion is a result of powerful astrophysical processes, such as the acceleration of particles in the presence of intense magnetic fields or the interaction of the jet with surrounding matter. The jet in m-87 provides valuable insights into the physics of active galactic nuclei and the dynamics of supermassive black holes.

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Why cannot see your surroundings clearly when you enter a darkened cinema hall

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When you enter a darkened cinema hall, it becomes difficult to see your surroundings clearly due to the process of dark adaptation. Dark adaptation is the adjustment of the eyes to low light conditions.

In a dark environment, the pupils of your eyes dilate to allow more light to enter. This dilation increases the sensitivity of the retina to capture the available light. However, it takes some time for the eyes to fully adapt to the darkness and for the visual system to adjust. When you enter a cinema hall, which is intentionally kept dark to enhance the movie-watching experience, your eyes are still adapting to the low light levels. Initially, the surroundings appear dark and indistinct because the visual system is still in the process of adjusting.

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Which gives you a frame of reference for your speed when you are riding a train?

Answers

Answer:

anything stationary

Explanation:

anything that is not moving outside the train like passing trees or the train's station is considered to be a frame reference.

If a category 6 hurricane would exist how fast do you think it would be?

Answers

My Answer:The scale starts with a Category 1, which ranges from 74 to 95 mph (119 to 153 km/h). A Category 5 storm has winds of 156 mph (251 km/h) or stronger. An extrapolation of the scale suggests that if a Category 6 were created, it would be in the range of 176-196 mph.

After the series of powerful storm systems of the 2005 Atlantic hurricane season, as well as after Hurricane Patricia, a few newspaper columnists and scientists brought up the suggestion of introducing Category 6, and they have suggested pegging Category 6 to storms with winds greater than 174 or 180 mph (78 or 80 m/s).

There is no such thing as a Category 6 hurricane. When Hurricane Irma was headed toward the coast of southern Florida in August, it had maximum wind speeds of 185 mph, according to the New York Times. But the Saffir-Simpson scale only goes up to 5.Hope it helps(◠ᴥ◕ʋ)

this is the formula for calculating the diameter of an unknown microscope field.

Answers

By using this formula =Diameter = Diameter = Known Field Diameter × (Known Magnification / Unknown Magnification)
, you can calculate the diameter of an unknown microscope field, allowing you to estimate the size of the objects you're observing under different magnification levels.


.To calculate the diameter of an unknown microscope field, you can use the formula:

Unknown Field Diameter = Known Field Diameter × (Known Magnification / Unknown Magnification)

Here's a step-by-step explanation of the formula:

1. Determine the known field diameter: This is the diameter of the field of view under a certain magnification, which is usually provided by the microscope manufacturer or can be measured experimentally.

2. Determine the known magnification: This is the magnification level at which the known field diameter was measured.

3. Determine the unknown magnification: This is the magnification level at which you want to calculate the unknown field diameter.

4. Plug the values into the formula and solve for the unknown field diameter.

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Design your own F= ma problem for another group to solve.

Answers

Here is a problem.

Problem:-

A car of mass 1700kg accelerated with a rate of 17m/s^2. find the force applied on it.

Extra:-

F=ma is. the famous formula of Sir Eizak Newton

3. Since Aspeon is not expected togrow, Emily believes that the following equations can be used in the valuation analysis: (1) S=[EBIT−kd(D)](1−ks)
(2) V=S+D
(3) P=(V−D0)/n0
(4) n1=n0−D/P
(5) VL=VU+TD

Answers

The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:

1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.

2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.

3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.

4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.

5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.

These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.

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how do you find work when only given the angle a sled is pulled, the mass, the coefficent of kinetic friction and distance

Answers

Answer:

W = F * s    

Work done equals applied force * distance traveled

Apparent weight = M g (1 - sin θ)     since some of applied force will lighten sled

μ = coefficient of kinetic friction

F cos θ = force applied to motion of sled

s = distance traveled

[μ M g (1 - sin θ)] cos θ * s = work done in moving sled

Note that F = μ M g    if applied force is in the horizontal direction

Explain how the pressure of the ice cube on the ground changes when it melts

Answers

Answer:

Explanation: Andre Ampere

Identify the aspects of the pictured graph that are missing or contain errors.

Answers

Answer:

ooops ignore this it wont let me leave this screen it does this weirdly s

Explanation:

A man pushes a box along a flat, frictionless surface using a force of 500 N. The box was moved a distance of 2.5 m. The actual work done by the worker was _____

Answers

Answer:

Workdone = 1250Nm

Explanation:

Given the following data;

Force, F = 500N

Distance, d = 2.5m

Workdone is given by the formula;

\( Workdone = force * distance\)

Substituting into the equation, we have

\( Workdone = 500 * 2.5 \)  

Workdone = 1250Nm

Therefore, the actual work done by the worker is 1250 Newton-meter.

The actual work done by the worker is 1250 J.

Work can be defined as the product of force and distance. The s.i unit of work is Joules

The formula of work is

W = Fd....................... Equation 1

Where W = work done by the worker, F = Force, d = distance.

From the question,

Given: F = 500 N, d =  2.5 m

Substitute these values into equation 1

W = 500×2.5

W = 1250 J

Hence, the actual work done by the worker is 1250 J

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There are five basic health-related components that one must have in order to be physically fit.
O True
O False ​

Answers

Answer: the answer is true :-)

Explanation:

A circuit contains a 1. 5 volt battery and a bulb with a resistance of 3 ohms. Calculate the current

Answers

The answer will be 0.5 amps

You can tell if something’s a living thing or not by checking if it has?

Answers

Explanation:

To determine whether something is living or nonliving, a living thing must meet seven specific characteristics: feeding, movement, respiration, excretion, growth, sensitivity, and reproduction. A living organism needs to be able to feed to make energy and grow.

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With a particular fingering, a flute produces a note with frequency 880Hz at 20.0°C . The flute is open at both ends. (b) At the beginning of the halftime performance at a late-season football game, the ambient temperature is -5.00°C and the flutist has not had a chance to warm up her instrument. Find the frequency the flute produces under these conditions.

Answers

The frequency the flute produces under the given conditions is approximately 851 Hz.

To find the frequency the flute produces under the given conditions, we need to use the formula for the fundamental frequency of a flute that is open at both ends. The formula is:

f = (v/2L) * n

Where:
f = frequency
v = speed of sound in air (approximately 343 m/s at 20.0°C)
L = length of the flute
n = harmonic number (1 for the fundamental frequency)

First, let's find the length of the flute at 20.0°C.

Since the flute is open at both ends, the length is equal to half the wavelength of the sound produced. So, we can rearrange the formula as:

L = (v/2f) * n

Plugging in the given values:
L = (343 m/s) / (2 * 880 Hz) * 1

Simplifying:
L ≈ 0.195 m

Now, let's find the frequency of the flute at -5.00°C. We can use the same formula, but this time we need to use the speed of sound at -5.00°C, which is approximately 331 m/s.

f = (331 m/s) / (2 * 0.195 m) * 1

Simplifying:
f ≈ 851 Hz

Therefore, the frequency the flute produces under the given conditions is approximately 851 Hz.

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A kid jumping on a trampoline reaches a height of 0.925 m. What was his speed when he left the trampoline?

Answers

Answer:

4.26 m/s

Explanation:

h = 0.925

v = 0

u = ?

v = u^2 - 2gh

0 = u^2 - 2gh

u = sqrt 2gh

= sqrt 2*9.8*0.925

= 4.258

= 4.26

what minimum speed must you give the pail at the highest point of the circle if no water is to spill from it?

Answers

The minimum speed that must be given to the pail at the highest point of the circle if no water is to spill from it can be determined using the equation for centripetal acceleration.

Centripetal acceleration is given by the equation a = v²/r, where v is the speed, and r is the radius of the circle.

At the highest point of the circle, the centripetal acceleration must be equal to the acceleration due to gravity, g, in order for no water to spill from the pail.

Setting the two equations equal to each other and solving for v gives:

v²/r = g

v² = g*r

v = √(g*r)

Therefore, the minimum speed that must be given to the pail at the highest point of the circle if no water is to spill from it is √(g*r), where g is the acceleration due to gravity, and r is the radius of the circle.

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To weigh a fish, a person hangs a tackle box of mass 3. 5 kilograms and a cooler of mass 5 kilograms from the ends of a uniform rigid pole that is suspended by a rope attached to its center. The system balances when the fish hangs at a point 1/4 of the rod's length from the tackle box. What is the mass of the fish?

A) 1. 5 kg

B) 2 kg

C) 3 kg

D) 6 kg

E) 6. 5 kg

Answers

The mass of the fish is 3 kg.

What is mass?

In physics, mass is a proportion of how much matter is in an item. It is typically estimated in kilograms (kg). Mass is a scalar amount, meaning it just has size and no course.

Mass is unique in relation to weight, which is the force applied to an item because of gravity. Mass is an inherent property of an item and doesn't rely upon its location or environment. Weight, then again, relies upon the gravitational force and can change depending on the location.

rotational equilibrium

(3.5 )(9.8)(L/2) + m(9.8)(L/4) - (5)(9.8)(L/2) = 0

34.3(L/2)+9.8m(L/4)- 49(L/2)=0

34.3(L/2)- 49(L/2)+9.8m(L/4)=0

-14.7(L/2)+9.8m(L/4)=0

-7.35L+2.45mL=0

2.45mL=7.35L

m=7.35L/2.45L

m = 3 kg.

thus mass of the fish is 3 kg.

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When an electrical pulse on one wire is accidentally detected on another nearby wire, this is known as:.

Answers

Answer:

induction

Explanation:

a change in current (the pulse) causes a change in the magnetic field resulting from that current. the nearby wire is inside that magnetic field. when that magnetic field changes, it induces a current in any nearby conductor. the amount of current induced depends on the strength of the field and the distance between the conductors.

A 70mm long blockhas cross-section of 50mm by 10mm the block is subjected to forces 60KN (tension) on the 50mm by 10mm face and 110KN (Compression) on the 70mm by 10mm face Determine the force to be applied on the 70mm by 50mm face such that there is no change in volume

Answers

Answer:

970 kN

Explanation:

The length of the block = 70 mm

The cross section of the block = 50 mm by 10 mm

The tension force applies to the 50 mm by 10 mm face, F₁ = 60 kN

The compression force applied to the 70 mm by 10 mm face, F₂ = 110 kN

By volumetric stress, we have that for there to be no change in volume, the total pressure applied by the given applied forces should be equal to the pressure removed by the added applied force

The pressure due to the force F₁ = 60 kN/(50 mm × 10 mm) = 120 MPa

The pressure due to the force F₂ = 110 kN/(70 mm × 10 mm) = 157.142857 MPa

The total pressure applied to the block, P = 120 MPa + 157.142857 MPa = 277.142857 MPa

The required force, F₃ = 277.142857 MPa × (70 mm × 50 mm) = 970 kN

a constant force of 15.3 n acts upward on an iron block that weighs 11.7 n. (a) if the block is initially at rest, what is its kinetic energy 6.53 s after the force is applied

Answers

The block's kinetic energy, 6.53 sec after the force is applied, will be 532.8 J.

We know that,

Kinetic energy = 1/2 x mass x (speed)²

Since the block is initially at rest, its initial velocity is zero. We need to find the final speed of the league after 6.53 seconds.

To find the final velocity, we can use the equation:

force = mass x acceleration

Here, acceleration is the rate of change of velocity; solving for acceleration, we get:

Acceleration = force/mass

Substituting the values, we get:

acceleration = 15.3 N / 11.7 N = 1.3077 m/s^2

Now, using the equation:

velocity = acceleration x time

We can find the final velocity of the block after 6.53 seconds:

velocity = 1.3077 m/s² x 6.53 s = 8.53 m/s

Finally, we can find the kinetic energy of the block using the first equation:

Kinetic energy = 1/2 x mass x (velocity)²

Plugging in the values, we get:

Kinetic energy = 1/2 x 11.7 N x (8.53 m/s)² = 532.8 J

Therefore, the block's kinetic energy after 6.53 seconds of the force applied is 532.8 Joules.

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Before Collision:
2,000 kg 4 m/s 4,000kg 0 m/s

After collision: 2,000 kg + 4,000kg Vt = ?

I will give Brainliest to the first person. Please show work

Answers

Answer:

  4/3 m/s

Explanation:

Assuming momentum is conserved, the sum of products of mass and speed before the collision is the same as after:

  (2000 kg)(4 m/s) +(4000 kg)(0 m/s) = (2000 +4000 kg)(Vt)

  Vt = (8000 kg·m/s)/(6000 kg) = 4/3 m/s

The speed of the combined objects after the collision is 4/3 m/s.

Which statement correctly describes plastic?
A. It has a low resistivity and allows charges to move freely.
B. It has a high resistivity and prevents charges from moving freely.
C. It has a high resistivity and allows charges to move freely.
D. It has a low resistivity and prevents charges from moving freely.

Answers

Answer:answer is B

Explanation:

For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Select The Method By Which The Molecule Or Ion Is Moving. Each Answer Can Be Used More Than Once, Or Not At All. A. Simple Diffusion B. Facilitated Diffusion By A Channel Protein C. Facilitated Diffusion By A Carrier/Transport Protein

Answers

For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Option A is correct answer.

Scenario A: Oxygen moving across a plasma membrane Answer: A. Simple Diffusion Scenario B: Glucose moving across a plasma membrane Answer: C. Facilitated Diffusion By A Carrier/Transport Protein Scenario C: Sodium moving across a plasma membrane Answer: B. Facilitated Diffusion By A Channel Protein Scenario D: Water moving across a plasma membrane Answer: A. Simple Diffusion : Simple diffusion allows the nonpolar and small molecules to pass through the plasma membrane without any assistance of proteins. In facilitated diffusion, larger polar molecules or ions move across the membrane through the help of transport proteins. Transport proteins are of two types, channel and carrier proteins. Channel proteins provide an open path for the molecules to move whereas carrier proteins hold the molecules to move across the membrane and change their shape.

Option A is correct answer.

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A discordant igneous intrusion
Select one:
a.
cuts across bedding planes.
b.
will consist dominantly of pyroclasts.
c.
parallels sedimentary rock layering.
d.
produces deadly explosions.

Answers

A discordant igneous intrusion cuts across bedding planes. Here is the detailed explanation of the given question:Explanation:The Discordant igneous intrusion is the formation of an igneous rock mass when magma is injected into a host rock and cools there.

This form of igneous intrusion does not conform to the stratification or layering of the existing rock mass because it cuts across it.Therefore, a discordant igneous intrusion cuts across bedding planes.Option (a) is correct. It is the only option that describes the features of discordant igneous intrusion. Hence, the correct answer is option (a).

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sketch the corresponding velocity va time and acceleration va time graphs from the position vs time graphs

Answers

The corresponding velocity vs time and acceleration vs time graphs from the position vs time graphs are given below,

What are velocity vs time graphs ?

The speed-time graph: A plot between speed and time is called a velocity-time graph. It depicts the motion of an object moving straight ahead. At any given time, the magnitude of velocity equals its instantaneous speed. Only 1-D motion is intended for its drawing, which accepts positive and negative values.

What are acceleration vs time graphs ?

Acceleration-Time For a particle travelling in a straight path, the acceleration is displayed against time in the graph. The acceleration-time depicts time and acceleration values on the x and y axes, respectively.

What are position vs time graphs ?

An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph. The greater the slope of the line and the faster the object's speed changes, the steeper the line is. More location vs. time graph illustrations can be found in this two-part video series.

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sketch the corresponding velocity va time and acceleration va time graphs from the position vs time graphs
sketch the corresponding velocity va time and acceleration va time graphs from the position vs time graphs
sketch the corresponding velocity va time and acceleration va time graphs from the position vs time graphs
Other Questions
PLS HELP I HAVE 30 MINUTES TO TURN THIS IN select the correct answer.What is the value of this expression when a = 7 and b= -4?12a| 03A.-6OB.3COIO C.33HICOD. 6 Find the value of x that makes ABCD a parallelogram?answers a.) x=30b.) x=20c.) x=40d.) x=60 If it is 11:45 a.m., what will the time be 3 hours and 15 minutes later?4:15 p.m.3:00 p.m.3:15 a.m.2:45 p.m. which expression is equivalent to 35m2-63 "hippies" were often seen carrying a flower or wearing them in their hair. which response best describes what flowers symbolize for those who identified as a hippie? In the two units of company, the employees in unit one are 650 and monthly salary is N2750, the employees in unit two are 700 and monthly salary is N2500 then the combined arithmetic mean is When did Georgia join the secession?A. When the war started B. ImmediatelyC. After a special convention votedD. Near the end of the war According to the quantity equation, whenever the supply of money is growing at a positive rate, if real income is constant, then the price level:A. is growing at the same rate as the growth of the supply of money.B. is decreasing.C. is constant.D. grows at a lower rate than the growth of the supply of money. Which example best explains the interaction of Earths spheres when acid rain affects trees?The geosphere is interacting with the hydrosphere.The atmosphere is interacting with the hydrosphere.The biosphere is interacting with the hydrosphere and the cryosphere.The atmosphere is interacting with the hydrosphere and the biosphere.keep the points u earned it for helping Your school has built a new sports centre. A former pupil of your school, now a famous sports star has been invited to open the new centre. Your principal has asked you to make a speech at the official opening to welcome the sports star and introduce the centre to teachers and pupils. (Word limit:200-300 words). Which micronutrient has been added to flour in the US since the 1990s?a) Ironb) Calciumc) Vitamin Dd) Folic acid Nesly has 6 pink masks, 2 blue masks, and 4 purple masks in a box. She will randomly choose 1 mask from the box. What is the probability Nesly will choose a purple mask compare a 2px orbital and a 4pz orbital. both orbitals have the same basic shape, but they differ in orientation and number of nodes. both orbitals have the same basic shape and orientation, but the 2px orbital is smaller. both orbitals have the same basic shape and size, but the 2px orbital has fewer nodes. the orbitals differ in basic shape, size, orientation, and number of nodes. locate another university with an erm program other than the list provided in the book or other colleges discussed in the chapter. identify and explain at least one difference with and similarity to the uw program. Find the area of a triangular garden if thesides are approximately 6 feet, 11 feet, and12 feet (to the nearest square foot). ITS NOT C FOR ME ON EDGE ONLY A B OR D!!!Which is a correct statement about common types of test questions? There is little difference in how these types of questions should be approached.Most can be approached by determining relationships between sets of ideas.Most can be approached by determining whether an idea or fact is accurate.Each type of question should be approached with a specific strategy. What is the equation of a horizontal line through (0, -1)?Choose one 4 pointsOy=0Ox=0O y = -1O x=11 aper Company has hired you to develop budgets for the company that plans to start business in April. Below is information provided to help you in the development of these budgets. Unit Sales April 26,000 May 30,000 June 32,000 July 35,000 $19 Unit sales price 0 March Sales 3% Discount 25% of the customers are expected to pay in month of sale and take a 70% of the customers are expected to pay in the month following the sale 5% will never pay 100% Product and cost information: 2 pounds of raw material per unit $0.75 Cost per pound 60% Raw material purchases paid in month of purchase 40% Raw material purchases paid in following month of purchase 0.5 hours of labor time per unit $16 per hour Labor is paid in month incurred $2 Overhead cost per unit produced plus $25,000 Fixed overhead per month, which includes $11,000 Deprecation per month Overhead costs that use cash are paid in month incurred Inventory Balances 0 Raw Material balance April 1st 20% Desired ending monthly raw material needs to meet next month's production 0 Beginning Work in Process 0 Ending Work in Process 0 Beginning Finished Goods 25% Ending Finished Goods 34,000 Units assumed for July Production 5,000 per month selling and administrative expense and paid in month incurred 100,000 Beginning cash Collection of Sales: Pam purchased video cameras for all of her employees so they can participate in ________.