Note that equation of a parabola with a vertical axis, vertex (h, k), and directrix y = k – p, where p is a nonzero real number is (y-k)² = 4p(x-h).
How can the equation be simplified if the vertex is at the origin?The equation of a parabola with a vertical axis, vertex (h, k), and directrix y = k – p, where p is a nonzero real number, is:
(y - k)² = 4p( x - h)
If the vertex is at the origin (h = 0, k = 0 ), the equation an be simplified to....
y² = 4px
where p is still a nonzero real number.
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How many 11-card hands are possible with a 20-card deck?
There is only 1 possible 11-card hand that can be formed from a 20-card deck.
To determine the number of 11-card hands possible with a 20-card deck, we can use the concept of combinations.
The number of combinations, denoted as "nCk," represents the number of ways to choose k items from a set of n items without regard to the order. In this case, we want to find the number of 11-card hands from a 20-card deck.
The formula for combinations is:
nCk = n! / (k!(n-k)!)
Where "!" denotes the factorial of a number.
Substituting the values into the formula:
20C11 = 20! / (11!(20-11)!)
Simplifying further:
20C11 = 20! / (11! * 9!)
Now, let's calculate the factorial values:
20! = 20 * 19 * 18 * ... * 2 * 1
11! = 11 * 10 * 9 * ... * 2 * 1
9! = 9 * 8 * 7 * ... * 2 * 1
By canceling out common terms in the numerator and denominator, we get:
20C11 = (20 * 19 * 18 * ... * 12) / (11 * 10 * 9 * ... * 2 * 1)
Performing the multiplication:
20C11 = 39,916,800 / 39,916,800
Finally, the result simplifies to:
20C11 = 1
Consequently, with a 20-card deck, there is only one potential 11-card hand.
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write the english phrase as an algebraic expression. Let x represent the number
The english phrase "Seven less than four times a number" as an algebraic expression is 4x - 7
Writing the english phrase as an algebraic expressionFrom the question, we have the following parameters that can be used in our computation:
seven less than four times a number
Represent the number with x
So:
four times a number means 4x
So, we have
seven less than 4x
seven less than means - 7
So, we have
4x - 7
Hence, the english phrase as an algebraic expression is 4x - 7
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Complete question
write the english phrase as an algebraic expression. Let x represent the number
Seven less than four times a number
Use implicit differentiation to find dy/dx and d^2y/dx^2.
Using implicit differentiation dy/dx = -(2x + y)/(x + 2y) and d2y/dx² = -2(x² - 3xy - y²)/(x + 2y)³.
Implicit differentiation is the process of differentiating an equation in which it is not easy or possible to express y explicitly in terms of x.
Given the equation x² + xy + y² = 5,
we can differentiate both sides with respect to x using the chain rule as follows:
2x + (x(dy/dx) + y) + 2y(dy/dx) = 0
Simplifying this equation yields:
(x + 2y)dy/dx = -(2x + y)
Hence, dy/dx = -(2x + y)/(x + 2y)
Next, we need to find d^2y/dx^2 by differentiating the expression for dy/dx obtained above with respect to x, using the quotient rule.
That is:
d/dx(dy/dx) = d/dx[-(2x + y)/(x + 2y)](x + 2y)d^2y/dx² - (2x + y)(d/dx(x + 2y))
= -(2x + y)(d/dx(x + 2y)) + (x + 2y)(d/dx(2x + y))
Simplifying this equation yields:
d2y/dx² = -2(x² - 3xy - y²)/(x + 2y)³
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A cube has a surface area of 253 square inches.What is the area of one face of the cube in sqaure inches.
Answer:
42 1/6 square inches
Step-by-step explanation:
253=6x
x=42 1/6
42 1/6 square inches
:]
please help ASAP ! ! !
A 10-year annuity pays $1,850 per month, and payments are made at the end of each month. If the APR is 12 percent compounded monthly for the first five years, and APR of 8 percent compounded monthly thereafter, what is the value of the annuity today?
Based on the amount the annuity pays per month and the APR, the value of the annuity today is $133,349.85.
What is the present value of the annuity?First, find the present value of the annuity at 5 years:
= 1,850 x present value interest factor of annuity, 60 months, 8/12%
= 1,850 x 49.32
= $91,242
Then find the present value of the annuity from 5 years till date:
= (1,850 x present value interest factor of annuity, 60 months, 12/12%) + ( 91,242) / (1 + 1%)⁶⁰)
= (1,850 x 44.955) + ( 91,242) / (1 + 1%)⁶⁰)
= $133,349.85
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If each of these runners travels the indicated number of spaces in the same amount of time, at which numbered spot will all of the runners be next to one another?
The numbered spot at which all the runners will be next to one another is spot 19.
What is the LCM?Least Common Multiple is the meaning of the acronym LCM. The lowest number that may be divided by both numbers is known as the least common multiple (LCM) of two numbers. It may also be computed using two or more real numbers.
Starting with the runner on the outside track, the provided parameters are;
The runner covered n₁ = 5 places on the outside track, which is the number of spaces.
Next, the inner runner will traverse n₂ spaces, which equals one space.
The following inner runner will cover n₃ = 3 spaces.
The subsequent runner will traverse n₄ = 2 spaces.
The Lowest Common Multiple, or LCM, of all the runners' speeds or the total number of spaces they cover in the same amount of time, determines where all the runners will be placed next to one another.
LCM(5, 1, 3, 2) = 30 is the LCM of 5, 1, 3, and 2.
Time = 30/ = 6
Consequently, when the first runner has covered 30 places, we have;
Six time units have been expended.
The runner comes to a stop at position 30- (30 -19) = Position 19.
First runner's new destination is Spot 19.
The distance covered simultaneously by runner 2 is 6 x 1 = 6.
The distance covered by two runners running simultaneously equals six spaces.
Second runner's new position: 6 spaces plus spot 13 equals spot 19.
The combined distance covered by the three runners is 6 x 3 = 18.
The distance runner 3 covers 18 spaces simultaneously.
Third runner's new position: 18 spaces + Spot 1 = 19 spaces
Runner 4 covers a distance of 6 x 2 = 12 at the same time.
Distance runner 4 journeys equals 12 spaces
Runner 4's new position is now 12 spaces Plus Spot 7 = Spot 19.
Therefore, all the runners will be next to one another is spot 19.
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algebra question please help tell
See attached. No idea why I can't submit this answer...
A rectangular garden has a length of 2m + 13 feet and a width of 5m feet.
Answer:
A = Lw (Area equal length times width)
A = 48 (the garden's area is 48 ft2)
L = w + 2
We have values for our variables, so let's plug them in:
48 = w(w + 2)
Distribute:
48 = w2 + 2w
Subtract 48 from both sides:
0 = w2 + 2w - 48
AS you can see, we now have a quadratic. From here we need:
m + n = 2 and
m * n = -48
When we break up the quadratic into (w + m)(w + n)
48 is an even number divisible by 3, so it'll be also be divisible by 6:
48 / 6 = 8
8 + (-6) = 2
8 * -6 = -48, so:
0 = (w + 8)(w - 6) →→ 0 = w + 8, or 0 = w - 6
w = -8 or 6
Which of the following is closest to the value of the expression 3 x (square root of 2)?
Select one:
01.4
03.8
04.2
04.4
Answer:
4.2
Step-by-step explanation:
3 x (sqrt 2)
3 x (1.41421356237)
4.24264068712
4.2
The perimeter of a rectangle is 156 feet. The length is 22 feet. What is the width?
Answer:
Width is 56 feet
Step-by-step explanation:
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A particle in the ocean moves with a wave. The motion of the particle can be modeled by the cosine function. If a 14 in. wave occurs every 10 s, write a function that models the height of the particle in inches y as it moves in seconds x. What is the period of the function?
The required function y = 7 cos (2π * 0.1 * x) and period of the function is 10 seconds, which is the time it takes for one complete cycle of the wave.
How to find the cosine function of this problem?he cosine function can be used to model periodic motion, and its general form is:
y = A cos (Bx + C) + D
where A is the amplitude, B is the frequency, C is the phase shift, and D is the vertical shift.
In this case, we know that a 14 in. wave occurs every 10 s, so we can use this information to find the frequency, which is the reciprocal of the period. The period is the time it takes for one complete cycle of the wave, which in this case is 10 s.
Therefore, the frequency is:
\(f = \frac{1}{T}=\frac{1}{10} = 0.1 Hz\)
We can also see that the amplitude of the wave is 7 inches, since the wave has a height of 14 inches from its highest point to its lowest point.
Now we can write the function that models the height of the particle in inches y as it moves in seconds x:
y = 7 cos (2π * 0.1 * x)
Here, the frequency is expressed in radians per second (2π * 0.1 = 0.2π), since the cosine function takes radians as its argument. The phase shift and vertical shift are both zero in this case, since the wave starts at its highest point and has no vertical shift.
Therefore, the period of the function is 10 seconds, which is the time it takes for one complete cycle of the wave.
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if one cup fills the jug to the second interval, how many cups do you need to fill the jug to 4?
2 cups you need to fill the jug to 4.
What is ratio?The ratio can be defined as the number that can be used to represent one quantity as a percentage of another. Only when the two numbers in a ratio have the same unit can they be compared. Ratios are used to compare two objects.
It depends on the size and markings of the jug.
If we assume that the jug is divided into equal intervals and each interval represents an equal volume,
then we can say that filling the jug to the second interval means that the jug is 1/2 full.
To fill the jug to the fourth interval, we need to fill the remaining 2 intervals, which means we need to add another 2 cups of liquid.
So, the answer is 2 cups.
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The measure of the vertex angle of an
isosceles triangle is 66°. What is the
measure of each of the base angles?
Answer:
Since an isosceles triangle has two congruent angles (the base angles), let x be the measure of each base angle. Then we know that the sum of the three angles in a triangle is 180 degrees, so:
vertex angle + base angle + base angle = 180
66 + x + x = 180
2x + 66 = 180
2x = 114
x = 57
Therefore, each base angle measures 57 degrees.
use the Distributive property to rewrite the expression3×10×2
Answer
Option B is correct.
3 (10.2) = 3 (10) + 3 (0.2)
Expression
We are asked to use the distributive property to simplify
3 × 10.2
The distributive property allows us to say
a (b + c) = ab + ac
So, for the question given, we can split the 10.2
3 (10.2)
= 3 (10 + 0.2)
= 3 (10) + 3 (0.2)
Hope this Helps!!!
Simplify the product using the Distributive Property
(a - 4)(a - 1)
Answer: a²-5a+4
Step-by-step explanation:
When brackets are next to each other in algebra it means to multiply.
So,
a×a=a²
a×-1=-a (in algebra, you don't write -1a you would just write -a)
-4×a=-4a
-4×-1=+4
So then you would write it like this:
a²-a-4a+4
Then you would simplify it:
a²-5a+4
Hope this helps :)
I CANT FIGURE THIS OUT PLEASE HELP ME FIND angles FAB and BAC
if a kid was playing for 4 hours and he did 9 activitys how much time did each activity take
Answer:
26.6667 minutes or 0.444 hours per activity.
Step-by-step explanation:
If he spent an equal amount of time on each activity, then it would have to be divided equally: 4hours/9
In minutes:
4 x 60 = 240 minutes
240/9
26.6667 minutes per activity.
In Hours:
4/9
0.444 hours per activity.
Answer:
26.6666666667
Step-by-step explanation:
First, you will need to convert 4 hours into minutes. 60×4=240
After you have converted the hours into minutes, you will need to use that number divide it by the number of activities. Witch in your case, would be 9.
240÷9=26.6666666667 If the answer is not there round it to: 26.67
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Simplify the expression below by following the order of operations and combining like terms. Do not put spaces between characters. \frac{a}{2^3}(64)-12a \div6 The expression simplifies to:
ANSWER
6a
EXPLANATION
\(\frac{a}{2^3}(64)-12a\div6\)The order of operations is always the same:
0. Parenthesis
,1. Exponents (include powers and roots)
,2. Multiplications and divisions
,3. Additions and subtractions
Let's take a look at the given expression. We have two terms - which are separated by a minus sign. In the first term there's a parenthesis so we have to solve what's inside first. Note that what's inside the parenthesis is just a number, no operation to be done. Therefore for the first step we have:
\(\frac{a}{2^3}\times64-12a\div6\)Now, again in the first term there's an exponent in the denominator. We have no exponents in the second term. Solving 2³ = 8:
\(\frac{a}{8^{}}\times64-12a\div6\)The third operations to solve are multiplications and divisions. We have many of those, but since we have a variable a, it is convenient if we solve the division first in the first term:
\(a\times\frac{64}{8}=a\times8\)And the division of the second term:
\(12a\div6=(12\div6)a=2a\)Therefore after solving the third operations we have:
\(8a-2a\)Now we do the subtraction. As mentioned before, there's a variable involved so to solve the subtraction we have to combine like terms. In this case, both terms contain the variable so we take it as common factor:
\(a(8-2)\)And solve the operation inside the parenthesis:
\(a\cdot(6)=6a\)Hence, the expression simplifies to 6a
What is the common difference for this arithmetic sequence?
-6, -1, 4, 9, 14,
Answer: +5
Step-by-step explanation:
-6 + 5 = -1
-1 + 5 = 4
4 + 5 = 9
9 + 5 = 14
BEST GETS BRAINLIEST Proof for Pythagoras Theorem (I’ll take multiple different approaches) Please make it logical/satisfying.
Answer:
Proofs for Pythagoras Theorem usually use visual/geometry approaches. I don't post pictures in my answers, so I will present a linear algebra approach. You can see it in the blog posted by Professor Terence Tao.
Note that there are several elegant proofs using animations and drawings, but this is just personal.
I've seen this some time ago, it is really interesting proof.
It states that \(a^2+b^2=c^2\) is equivalent to the statement that the matrices
\(%\begin{pmatrix}a & b \\ -b & a%\end{pmatrix}%\) \(\begin{pmatrix}a& b \\-b & a\\\end{pmatrix}\) and \(\begin{pmatrix}c & 0\\0 & c \\\end{pmatrix}\) have the same determinant.
The determinant of the first matrix is \(a^2+b^2\)
The determinant of the second matrix is \(c^2\)
Once the linear transformations associated with these matrices differ by rotation, we claim that
\(a^2+b^2=c^2\)
If 70 was removed from the set of data, which values would change?
70, 75, 80, 80, 80, 95, 100
Orange and median
O range only
O mean only
O mean and range
13. In the figure, ABCDE is a regular pentagon and ABPQRS is a regular hexagon. X is the centre of the hexagon.
Find
(i) ABP,
(ii) PQX.
The value of ABP is 120°
The value of PQX is 60°
What is a Hexagon?
A hexagon, also known as a sexagon, is a six-sided polygon that forms the shape of a cube in geometry. Any simple hexagon has 720° of internal angles in total.
To find their values:
Recall that in a regular hexagon, (6-2) x 180°/ 6 = 120°
Also, (5-2) x 180°/5 = 108°
With these values, we would find that the value of ABP is 120°
<PQX = 120°/2 = 60°
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Common denominator of 3, 4, 5.
Answer:
The LCM of 3,4,5 3 , 4 , 5 is 2⋅2⋅3⋅5=60 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60 .
Step-by-step explanation:
Answer: 60
3 x 4 x 5 = 60
if b=p+5 and a=p^2+10p+1 find an expression that equals 2b+3a in standard form
Answer:
3p² + 32p + 13
Step-by-step explanation:
Okay, so lets first solve for 2b. 2b = 2(p + 5), which is equal to 2p + 10. Now, let's solve for 3a. 3a = 3(p² + 10p +1), simplifying to 3p² + 30p +3. After adding 2b and 3a, we are able to get 2p + 10 + 3p² + 30p + 3 = 3p² + 32p + 13
Answer:
3p² + 32p + 13
Step-by-step explanation:
3p² + 32p + 13
6
Select the correct answer.
A company polled a large group of people to assess the company's reputation in the surrounding communities. To save time, the survey was
mailed to the addresses of stockholders and former employees that the company already had on file and that were in the surrounding areas.
Which of the following statements is correct?
Answer:
a company powder large group of people to assess the company's reputation in the surrounding
Help with all these? pls
1. 76.56.
2. 96
3. The largest solution to the equation x²+16x+28=138 is 6.71.
4. The smallest solution to the equation x²+14x+14=145 is 5.96.
What is an equation?Equations are used to express relationships between variables and solve mathematical problems.
1. This is calculated by taking the coefficient of x (19) and dividing it by two (19/2) and then squaring the result (19/2)² = 76.56.
2. This is calculated by taking the coefficient of x (30) and dividing it by two (30/2) and then squaring the result (30/2)² = 96.
3. This is calculated by using the quadratic formula, by taking the opposite of the coefficient of x (16) plus or minus the square root of the coefficient of x squared (16²) minus 4 times the coefficient of the x term (4x16) minus the constant (28) divided by 2 times the coefficient of the x term (2x16).
4. This is calculated by using the quadratic formula, by taking the opposite of the coefficient of x (14) plus or minus the square root of the coefficient of x squared (14²) minus 4 times the coefficient of the x term (4x14) minus the constant (14) divided by 2 times the coefficient of the x term (2x14).
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1. For the given equation, c need to be 90.25 to complete the square.
2. 225
3. The largest solution to the equation x²+16x+28=138 is 6.
4. The smallest solution to the equation x²+14x+14=145 is -14.
What is an equation?Equations are used to express relationships between variables and solve mathematical problems.
1. This is calculated by taking the coefficient of x (19) and dividing it by two (19/2) and then squaring the result
(19/2)² = 90.25.
2. This is calculated by taking the coefficient of x (30) and dividing it by two which is (30/2) and then squaring the result
(30/2)² = 225.
3. The largest solution to the equation x²+16x+28=138 is 6.
This can be calculated by using the quadratic formula to solve the equation.
(a=1, b=16, c=28)
x = -8 ± √((16)² - 4(1)(28))/2(1).
x = -8 ± √(240)/2
x = 6 or -14.
Since 6 is the larger solution, it is the largest solution to the equation.
4. The smallest solution for x2+14x+14=145 can be determined by using the Quadratic Formula.
a=1, b=14, and c=14
x = [-14 ± √(142-4(1)(14))]/(2(1))
x = [-14 ± √(196)]/2
x = [-28/2] or [14/2]
x = -14 or 7
Therefore, the smallest solution for x2+14x+14=145 is x=-14.
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) Quantifier negation.
Form the negation of the following statements. Then apply De Morgan’s law and/or conditional law, when
applicable. Negation should appear only within predicates, i.e., no negation should be outside a quantifier
or an expression involving logical connectives. Show all steps.
a) ∀x (P(x) ∧ R(x))
b) ∀y∃z(¬P(y) → Q(z))
c) ∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))
The negations of the given statements with the application of De Morgan's law and/or conditional law.
a) ∃x (¬P(x) ∨ ¬R(x))
De Morgan's law:
∃y ∀z(¬P(y) ∧ ¬Q(z))
b) ∃y ∀z(¬P(y) ∧ ¬Q(z))
The double negation:
∃y ¬∃z(P(y) ∨ Q(z))
c) ¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))
The conditional law:
¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))
Let's form the negation of the given statements and apply De Morgan's law and/or conditional law, when applicable:
a) ∀x (P(x) ∧ R(x))
The negation of this statement is:
∃x ¬(P(x) ∧ R(x))
Now let's apply De Morgan's law:
∃x (¬P(x) ∨ ¬R(x))
b) ∀y∃z(¬P(y) → Q(z))
The negation of this statement is:
∃y ¬∃z(¬P(y) → Q(z))
Using the conditional law, we can rewrite the negation as:
∃y ¬∃z(¬¬P(y) ∨ Q(z))
c) ∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))
The negation of this statement is:
¬∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))
Using the conditional law, we can rewrite the negation as:
¬∃x (P(x) ∨ (∀z (R(z) ∨ ¬Q(z))))
Applying De Morgan's law:
¬∃x (P(x) ∨ (∀z ¬(¬R(z) ∧ Q(z))))
Simplifying the double negation:
¬∃x (P(x) ∨ (∀z ¬(R(z) ∧ Q(z))))
Using De Morgan's law again:
¬∃x (P(x) ∨ (∀z (¬R(z) ∨ ¬Q(z))))
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3(x-6)-8x=-2+5(2x+1)
Answer:
x=-21/15
Step-by-step explanation:
3x-18-8x=-2+10x+5
-5x-18=10x+3
15x=-21
x=-21/15
Hi can any one teach me this constant difference
The constant differences between the consecutive terms are 2 (a); 2 (b), -3 (c), 7 (d), 1(e), and 6(f).
How do you find the constant difference in a sequence of numbers?In math, the constant difference can be defined as the number that defines the pattern of a sequence of numbers. This means that number that should be added or subtracted to continue with the sequence.
Due to this, to determine the constant difference it is important to observe the pattern and find out the number that should be added. For example, if the sequence is 2, 4, 6, 8, there is a difference of 2 between each of the numbers and this is the constant difference.
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