The highest possible oxidation state for cobalt depends on the definition used, either oxidation state or coordination number. The +6 oxidation state occurs in \($\text{CoF}_6^{2-}$\) and \($\text{K}_3[\text{CoF}_6]$\), while the +7 oxidation state occurs in \($[\text{Co}(\text{NH}_3)_6]\text{ClO}_4^{2+}$\). Here option A is correct.
The highest possible oxidation state for cobalt depends on the definition of oxidation state. The term "oxidation state" refers to the hypothetical charge that an atom would have if all its bonds were 100% ionic. In this sense, the highest oxidation state for cobalt is +6. This occurs in the compound \($\text{CoF}_6^{2-}$\) where cobalt has lost all of its valence electrons and is surrounded by six fluoride ions. Another example is the compound \($\text{K}_3[\text{CoF}_6]$\), where the cobalt ion has a +6 oxidation state.
However, if we consider the concept of coordination number, which refers to the number of atoms or ions directly attached to the central metal ion, then the highest oxidation state for cobalt is +7. This occurs in the compound \($[\text{Co}(\text{NH}_3)_6]\text{ClO}_4^{2+}$\) where cobalt has six ammonia molecules coordinated with it and one perchlorate ion.
In summary, the highest possible oxidation state for cobalt is +6 if we consider the oxidation state as the hypothetical charge and +7 if we consider the coordination number. It's important to note that the oxidation state and coordination number of a metal ion are not always the same and can vary depending on the ligands surrounding the metal ion.
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What is the net torque on the pulley about the axle?
τnet = (TL ‐ TR)R is the needed net torque just on pulley about the axle.
How do pulleys work?A flexible line, cord, rope, chain, or belt is fastened to the rim of a wheel termed as a pulley. To transport motion and energy, pulleys may be employed singly or in combination.
If TL and TR are really the stresses pulling there at left and the sides of the pulleys, respectively, the net torque here on pulley would then be defined as net = (TL - TR)R, in which R represents the radius of pulley (see Fig. 1). It is believed that positive torque moves in a clockwise direction.
This means that τnet = (TL ‐ TR)R is the necessary formula for net torque.
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A police car approaches an observer with its siren on at a constant velocity. The observer hears the siren with a frequency of 410 Hz as the car apporaches. After the car has past the frequency drops to 376 Hz. How fast was the police car traveling to the nearest tenth of a meter per second?
ANSWER:
28.4 m/s.
STEP-BY-STEP EXPLANATION:
Given:
Actual frequency of the sound waves (f) = 376 Hz
Observed frequency (f') = 410 Hz
Speed of sound (v) = 343 m/s
Speed of observer (vo) = 0 m/s
Speed of police car (vs) = ?
We have that the formula of the Doppler effect is the following:
\(\begin{gathered} f^{\prime}=\frac{v+v_o}{v-v_s}\cdot f \\ \\ \text{ We replacing:} \\ \\ 410=\frac{343+0}{343-v_s}\cdot376 \\ \\ 410=\frac{128968}{343-v_s} \\ \\ 410\left(343-v_s\right)=128968 \\ \\ 343-v_s=\frac{128968}{410} \\ \\ v_s=343-\frac{128968}{410} \\ \\ v_s=28.4\text{ m/s} \end{gathered}\)The speed of the police car is 28.4 m/s.
Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 n, and it doesn't budge. what is the magnitude of the friction force on the crate in newtons?
Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 N, and it doesn't budge. The magnitude of the friction force on the crate in Newton is 400N
This is due to Friction force, which is defined as the resisting force that acts on a body when it is at rest (Static friction) or when it is in motion (Kinetic friction).
When a force is applied on a stationary body, the force of static friction starts to act on the body which prevents any relative motion between the object and surface. The magnitude of friction increases up to μsN, where μs is the coefficient of static friction. As the crate didn't budge, it means the amount of force applied was less than μsN. Hence the force applied was canceled by an equal and opposite amount of frictional force which was equal to 400N.
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How to solve 5,897,159 milligrams into kilograms?
Answer:
5.897159 kilograms
Answer:
5.897159 kilograms
Explanation:
5,897,159÷1000000=5.897159
the water behind grand coulee dam is 1 200 m wide and 135 m deep. find the force on the back of the dam.
The force on any of the back of the given dam is 2.352 x \(10^{11}\) N.
Force is an outside agent able to converting a body’s nation of relaxation or movement. It has a importance and a path. The path toward which the pressure is carried out is called the path of the pressure, and the utility of pressure is the factor wherein pressure is carried out.
Force is an vital idea because it impacts movement. It may be described as an interplay that modifications the movement of an item if unopposed. But the easy definition of pressure is that it's far the rush or pull skilled via way of means of any item. Force is a vector quantity, hence it has each importance and path. Therefore, one has to specify each the path and the importance to explain the pressure appearing on an item.
The Force may be measured the usage of a spring balance. The SI unit of pressure is Newton(N).
The area is 1200 m x 200 m = 240,000 m²
The average pressure is Pave = ρ x g x have
where ρ is the density, g is the gravity, and have is the average height.
Pave = (1000 kg/m³)(9.8 m/s²)(100 m) = 980,000 Pa
Solving the hydrostatic force using the formula F = P x A,
F = (980,000 Pa)(240,000 m²) = 2.352 x \(10^{11}\) N.
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A system in which the teacher transmits his voice by using a microphone and ceiling- or wall-mounted speakers is:
A system in which the teacher transmits his voice by using a microphone and ceiling- or wall-mounted speakers is called a public address (PA) system.
A public address system, commonly known as a PA system, is an audio setup used to amplify and distribute sound over a large area. In educational settings, a PA system is often employed to ensure clear and audible communication between the teacher and the students.
In this system, the teacher uses a microphone to capture their voice, which is then converted into an electrical signal. The electrical signal is amplified and transmitted through the PA system's speakers, which are typically mounted on the ceiling or walls of the classroom or lecture hall. The speakers disperse the sound throughout the space, allowing the teacher's voice to reach all students effectively.
This setup is particularly useful in large classrooms or venues where the teacher's voice might not naturally carry to every corner. The microphone and speakers work together to overcome any acoustic challenges and ensure that the teacher's voice is projected clearly to enhance communication and instruction.
There are no specific calculations involved in this context, as the PA system operates based on audio amplification and distribution rather than mathematical calculations.
A system in which the teacher transmits his voice using a microphone and ceiling- or wall-mounted speakers is referred to as a public address (PA) system. This setup is widely used in educational environments to amplify and distribute the teacher's voice, ensuring effective communication with all students, especially in large classrooms or lecture halls.
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How can we change direction of light? Name this phenomenon. any indian didis and bhayas to help (ik i said australian any will work for me)goys please help im in grade 6 and my teacher didnt give us the answer to a question in notebook:(
A tuna saw a marlin swimming toward it at 1 meter per second. To avoid the marlin, the tuna swam southwest for 6.8seconds at a constant velocity. In that time, the tuna swam 17meters. What was the tuna's velocity?
The velocity of the tuna is 4.1 meters per second and During the 6.8 seconds that the tuna swims southwest, it covers a horizontal distance of 17 meters.
We can use the Pythagorean theorem to determine the velocity of the tuna. Let's say that the velocity of the tuna has two components: a horizontal component (vx) and a vertical component (vy).
Therefore, we can say that:
vx = 17 meters / 6.8 seconds
vx = 2.5 meters per second
Now, we need to find the vertical component of the velocity (vy). We know that the marlin is swimming directly toward the tuna, which means that its velocity is entirely in the north direction. Therefore, the tuna needs to swim directly south to avoid the marlin.
The angle between the direction of the tuna's velocity and the direction of the marlin's velocity is 45 degrees (since the tuna is swimming southwest). Using trigonometry, we can find the vertical component of the tuna's velocity:
sin(45) = vy / v
vy = v * sin(45)
where v is the magnitude of the tuna's velocity.
Now, we can use the Pythagorean theorem to find the magnitude of the tuna's velocity:
v^2 = vx^2 + vy^2
v^2 = (2.5 m/s)^2 + (v * sin(45))^2
Solving for v, we get:
v = 4.1 meters per second
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one small thing you eat it you atomicly started crry. what is it.
Answer:
it's green chilly or red chilly
Explanation:
I hope it's correct!
calculate the magnetic field strength needed on a 210-turn square loop 20 cm on a side to create a maximum torque of 245 n·m if the loop is carrying 22 a.
A magnetic field strength of approximately 14.64 tesla (T) is needed to create a maximum torque of 245 N·m on a 210-turn square loop carrying 22 A.
τ = N·A·B·sin(θ)
A = (20 cm)² = 400 cm² = 0.04 m²
245 N·m = 210 turns · 0.04 m² · B · 1
Solving for B, we get:
B = 245 N·m / (210 turns · 0.04 m²)
B = 14.64 T
A magnetic field is a force field that surrounds a magnet or a current-carrying conductor. It is created by the movement of charged particles, such as electrons. The magnetic field can be visualized using magnetic field lines that show the direction of the force acting on a magnetic object placed within the field.
Magnetic fields have both magnitude and direction and are measured in units of teslas (T) or gauss (G). The strength of a magnetic field depends on the distance from the source of the field, as well as the strength and orientation of the magnet or current. Magnetic fields are important in many everyday applications, such as in electric motors, generators, and magnetic resonance imaging (MRI) machines used in medical diagnosis.
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Please help me on this!!
An engineer is designing the runway for an
airport. Of the planes that will use the airport,
the lowest acceleration rate is likely to be 5
m/s squared. Starting at 5 m/s, the plane will need to
take off in 11.4 seconds. How long is the
runway?
Answer:
\(\\ x_f=381.9m\)
Work:
\(\\ x_f=x_0+v_0t+\frac{1}{2}at^2\\\\ x_f=v_0t+\frac{1}{2}at^2\\\\ x_f=(5m/s)(11.4s)+\frac{1}{2}(5m/s^2)(11.4s)^2\\\\ x_f=381.9m\)
Hope this helps you. Kinematics can be tricky, but I'm sure you'll get a good grip on it. Have a good night.
Explain why cookies baked
near the turned-up edges of a cookie sheet receive
more energy than those baked near the center do.
Answer:
It's all about the conduction between the pan and the cookies.
Explanation:
The cookies in the middle of the pan are not going to be cooked as much as the cookies touching both the bottom of the pan and the side of the pan due to the level of heat being given to those outside cookies. Lets try an example:
Lets say you're in a car in the middle of summer. You and your sibling sit on opposite sides of your other sibling, who is sitting in the middle seat. You and your other sibling are pressed up against the door of the car, making you heat up quicker since not only is it hot in the car, the sun is also on you. Meanwhile your other sibling isn't getting as much heat (but is still warm).
I hope this was able to help! There weren't any answers listed, so it may be the following:
- Conduction of heat
- Transfer of heat
- The pan heating up more of the cookie
- The conversion of more heat energy to the outside cookies
Good luck!
PLZZZZ HELP ASAP ASAP ASAP
Answer:
A - B = 20 m/s
C - D = 10 m/s
section AB is moving fastest so A for the last question
if correct please give brainliest
Explanation:
speed = distance / time
AB - 200 / 10 = 20 m/s
CD - 300 / 30 = 10 m/s
What would be the Schwarzschild radius, in light years, if our Milky Way galaxy of 100 billion stars collapsed into a black hole? (Assume each star has the same mass as the sun.)
Compare this to our distance from the center, about 27,000 light years
The gravitational effects of such a massive object would likely have significant consequences for the structure and dynamics of the galaxy as a whole. The Schwarzschild radius is given by the formula:
r_s = 2GM / c²
where G is the gravitational constant, M is the mass of the object, and c is the speed of light.
If our Milky Way galaxy of 100 billion stars collapsed into a black hole, the total mass would be:
M = 100 billion × 2 × 10³⁰ kg = 2 × 10⁴¹ kg
Assuming each star has the same mass as the sun, we can find the mass of the galaxy as:
M = 100 billion × 1.99 × 10³⁰ kg = 1.99 × 10⁴¹ kg
Substituting the values into the formula for the Schwarzschild radius, we get:
r_s = 2 × 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻² × 1.99 × 10⁴¹ kg / (3 × 10⁸m/s)²
r_s = 5.9 × 10¹¹meters
Converting to light years, we get:
r_s = 62.5 light years
Therefore, if the Milky Way galaxy collapsed into a black hole, its Schwarzschild radius would be approximately 62.5 light years.
Comparing this to our distance from the center of the Milky Way, about 27,000 light years, we see that we would still be outside the event horizon of the black hole. However, the gravitational effects of such a massive object would likely have significant consequences for the structure and dynamics of the galaxy as a whole.
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Five docks are being tested in a laboratory. Exactly at noon, as determined by the WWV
Exactly at noon, as determined by the WWV time signal, on successive days of a week the clocks according to their relative value as good timekeepers, best to worst.
Time signals are also used in many everyday applications, such as GPS navigation, where precise timing is essential for calculating positions accurately. A time signal refers to any signal that provides information about the passage of time. Time signals are often used in experiments to measure the duration of events or to synchronize the timing of multiple processes.
One common type of time signal is a periodic signal, which repeats itself at regular intervals. This can be used to measure the period or frequency of a phenomenon, such as the oscillation of a pendulum or the vibration of a guitar string. Another type of time signal is a pulse signal, which provides a brief burst of energy at a specific time. This can be used to trigger the start or stop of a process or to measure the time delay between different events.
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Transpiration is the same as evaporation.
True
Or
False
?
Answer:
False
Explanation:
Transpiration is a form of Evaporation, but it only applies to plants whereas evaporation can apply to all liquids.
I WILL MARK BRAINLIEST IF CORRECT!!!
Answer:
I'm fairly sure that the answer is "100 m/s"
Explanation:
Fnet=ma
a=Fnet/m
a=4 N / 0.040 kg
a=100 m/s
please check my work before you submit, i don't wanna let cha down :)
What is density?
O A. The net energy transferred between two objects
B. A measure of mass per unit volume
O C. A measure of the movement of molecules
O D. The force exerted on an area
Answer:
B. A measure of mass per unit volume
Explanation:
Mass and volume are intimately correlated with density. In reality, it explains the precise nature of the connection between the two. We can determine an object's density by dividing its mass by volume. Thus, option B is correct.
What best defines about density?The mass or amount per unit of volume of a substance determines its density. Density is calculated using the formula mass/volume. It is considered to have a low density if a mass has a high volume but a tiny mass.
The volume and subsequently the density of a material typically alter when it changes its phase or state of matter. Temperature is the primary component, even though pressure can also affect how a material changes state.
Water availability, climate, relief (the contour of the terrain), vegetation, soils, and the accessibility of renewable energy sources are physical elements that impact population density. Social, political, and economic variables altering humans all have an impact on population density.
Therefore, A measure of mass per unit volume.
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Does the law of conservation of energy apply to open systems? Explain.
No, law of conservation of energy is not applicable to open systems.
Law of conservation of energy states that energy present anywhere can neither be created nor be destroyed by any means, it can only be converted from one form of energy to other form of energy. It means total energy of an isolated system remains same.
An open system is a system that can exchange energy and matter from the surroundings. The flow of energy takes places in an open system. Therefore, the law of conservation does not apply to an open system as it can lose or gain energy, hence its total energy will not be constant and will violate law of conservation of energy.
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How do you think population variables would affect the economic impact of an environmental hazard?
Effects of Population Growth on The Economy Population growth may have a positive effect on the economy.
How does population affect the economy?Human population growth bounces the Earth's system in a variety of ways, involving Increasing the extraction of resources from the environment. Rapid population growth built it more difficult for low-income and lower-middle-income countries to supply the increase in public expenditures. Population growth, along with increasing use, of the economy tends to increase emissions of climate-changing greenhouse gases.
On a facile level, the relationship between growth in population and growth in per capita income is clear. After all, per capita income equals total income divided by population. The growth rate of per capita income forcefully equals the difference joining the growth rate of income and the growth rate of population.
So we can conclude that Population size, growth, age structure, and geographic issues influence economies.
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A block has an initial speed of 7. 0 m/s up an inclined plane that makes an angle of 37 ∘ with the horizontal
A block has an initial speed of 7. 0 m/s up an inclined plane that makes an angle of 37 ∘ with the horizontal. The block's speed after it has traveled 2.0 m up the inclined plane (ignoring friction) is approximately 8.52 m/s.
To determine the block's speed after it has traveled 2.0 m up an inclined plane, we can use the principles of linear motion.
Given:
Initial speed (v₀) = 7.0 m/s (upward)
Distance traveled (d) = 2.0 m
Angle of the inclined plane (θ) = 37°
We need to determine the final speed (v) of the block.
Using the equation of motion:
v² = v₀² + 2ad
Where:
v is the final speed
v₀ is the initial speed
a is the acceleration
d is the distance traveled
Since the inclined plane is frictionless, the only force acting on the block along the incline is its weight component parallel to the incline. This force can be calculated as:
F = mg * sin(θ)
The acceleration along the incline can be obtained using Newton's second law:
F = ma
Rearranging the equation, we have:
a = F/m
Substituting the expression for F:
a = (mg * sin(θ))/m
Simplifying:
a = g * sin(θ)
Substituting the known values:
θ = 37°
g = 9.8 m/s² (acceleration due to gravity)
a = 9.8 m/s² * sin(37°)
Calculating the value of a:
a =5.9 m/s²
Now, substituting the values of v₀, a, and d into the equation of motion:
v² = v₀² + 2ad
v² = (7.0 m/s)² + 2 * (5.9 m/s²) * (2.0 m)
Calculating the value of v:
v² = 49.0 m²/s² + 23.6 m²/s²
v² = 72.6 m²/s²
Taking the square root of both sides:
v = √(72.6 m²/s²)
v = 8.52 m/s
Therefore, the block's speed after it has traveled 2.0 m up the inclined plane (ignoring friction) is approximately 8.52 m/s.
The given question is incomplete and the complete question is '' A block has an initial speed of 7.0 m/s up an inclined plane that makes an angle of 37 ∘ with the horizontal. Ignoring friction, what is the block's speed after it has traveled 2.0 m? ''.
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If you increase your distance by a factor of 3 from a sound source that is radiating equally in all directions. What happens to the intensity of the sound
The sound will be 9 times weaker at the new distance compared to the initial distance.
When you increase your distance from a sound source that is radiating equally in all directions, the intensity of the sound decreases. The relationship between distance and sound intensity follows the inverse square law.
According to the inverse square law, the intensity of sound is inversely proportional to the square of the distance from the source. Mathematically, it can be expressed as:
I ∝ 1/d^2
where I represents the sound intensity, and d represents the distance from the sound source.
If you increase your distance by a factor of 3, it means that the distance (d) becomes three times larger. Plugging this value into the inverse square law equation, we get:
I ∝ 1/(3d)^2
I ∝ 1/9d^2
This indicates that the intensity of the sound will decrease by a factor of 9 when the distance is increased by a factor of 3. In other words, the sound will be 9 times weaker at the new distance compared to the initial distance.
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Steve enjoys skiing in the winter time. However, Steve is a wimp and only likes to
ski very slowly down the bunny trails. He sees everyone around him waxing the
bottom of their skis, but he refuses. He won't wax his skis because he has studied
physics and knows waxing will
Why is an astronical unit used to measure distances in the solar system?
In our solar system, distances are really great. Therefore, astronomers frequently avoid using miles or kilometers when describing the distances to planets, asteroids, comets, or spacecraft.
What is astronomical unit?They substitute astronomical units, or AU, which represent the typical separation of the Earth from the sun. That translates to around 93 million miles, 150 million kilometers, or 8 light-minutes.
It is simpler to visualize relative distances in space when thinking in terms of astronomical units. An astronomical unit is 92,955,807 miles in exact distance (149,597,871 km).
The orbit of the Earth around the sun is not a complete circle. Consequently, during the year, Earth's distance from the sun varies. Earth is approximately 0.983 AU from the sun when it is at perihelion, which occurs in January.
Therefore, In our solar system, distances are really great. Therefore, astronomers frequently avoid using miles or kilometers when describing the distances to planets, asteroids, comets, or spacecraft.
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Need help on the following, needs to be a solid paragraph or two.
System currently used: Personal water purification system
Operational Requirements: Define a set of operational (stakeholder) requirements that define an estimate of system operational effectiveness. Here you should define measures of effectiveness (MoEs) and measures of performance (MoPs) that specify what results a new system should achieve to meet the identified need/opportunity, together with a list of system capabilities.
A Personal Water Purification System (PWPS) is a portable water filtration system designed to purify water for drinking purposes. It is a system that is designed to provide clean drinking water to people who are in areas where clean water is not readily available.
The operational requirements of a PWPS are designed to define the operational effectiveness of the system, which can be measured in terms of measures of effectiveness (MoEs) and measures of performance (MoPs).MoEs are a set of parameters that define the effectiveness of a system in achieving its goals, while MoPs are a set of parameters that define the performance of a system in achieving its goals. The MoEs for a PWPS may include factors such as the amount of water that can be purified, the time it takes to purify the water, and the effectiveness of the system in removing contaminants from the water.
The MoPs may include factors such as the size and weight of the system, the cost of the system, and the ease of use of the system. In order to meet the identified need for clean drinking water in areas where it is not readily available, a PWPS should have the following capabilities: the ability to purify water quickly and effectively, the ability to remove a wide range of contaminants from the water, the ability to be easily transported and stored, and the ability to be used by people with little or no training. In addition, the system should be cost-effective and easy to maintain, with replacement parts readily available if needed. By meeting these requirements, a PWPS can provide a reliable source of clean drinking water to people in need.
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Suppose that for a certain beverage company the volumes of soda cans are normally distributed with a mean of 12.01 fluid ounces and a standard deviation of 0.02 fluid ounces. a) If one soda can is randomly selected from the population, find the probability that its volume is less than 12 fluid ounces. Round to four decimal places. b) If a sample of size n = 32 soda cans is drawn randomly from the population, find the probability that the sample mean volume is less than 12 fluid ounces. Round to four decimal places. c) What do you think happens to the probability that the sample mean volume is less than 12 fluid ounces as larger and larger sample sizes are taken?
a. The probability that a randomly selected soda can has a volume less than 12 fluid ounces is approximately 0.3085
b. The probability that the sample mean volume is less than 12 fluid ounces, when a sample of size n = 32 is taken, is approximately 0.0023
c. The distribution of the sample mean becomes narrower and more concentrated around the population mean. Consequently, the probability of obtaining a sample mean less than 12 fluid ounces decreases because the sample mean is less likely to deviate significantly from the population mean.
a) Let X be the volume of a randomly selected soda can. We are given that the mean (μ) is 12.01 fluid ounces and the standard deviation (σ) is 0.02 fluid ounces.
We need to calculate P(X < 12). To do this, we standardize the variable using the z-score formula:
z = (X - μ) / σ
Substituting the given values, we have:
z = (12 - 12.01) / 0.02
= -0.5
Now, we can use a standard normal distribution table or calculator to find the probability associated with the z-score of -0.5. From the table, we find that the probability is approximately 0.3085.
b) When a sample of size n = 32 soda cans is drawn randomly from the population, the mean volume of the sample (denoted by X-bar) follows a normal distribution with the same mean (μ = 12.01 fluid ounces) but a smaller standard deviation (σ-bar) given by:
σ-bar = σ / sqrt(n)
Substituting the values, we have:
σ-bar = \(0.02 / \sqrt{(32)\)
= 0.02 / 5.6569
≈ 0.00354
Now, we need to calculate P(X-bar < 12). Again, we standardize the variable using the z-score formula:
z = (X-bar - μ) / σ-bar
Substituting the given values, we have:
z = (12 - 12.01) / 0.00354
≈ -2.8249
Using the standard normal distribution table or calculator, we find that the probability associated with the z-score of -2.8249 is approximately 0.0023.
c) As larger and larger sample sizes are taken, the probability that the sample mean volume is less than 12 fluid ounces tends to decrease. This is because as the sample size increases, the sample mean becomes a better estimate of the population mean. The larger the sample size, the more reliable and representative the sample mean is of the true mean. Hence, the sample mean is more likely to be closer to the population mean.
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the product of m1m2 in the formula for gravitational force is always
negative, because the product of two positive numbers is negative.
positive, because the product of two positive numbers is positive.
positive, because the product of two negative numbers is positive.
negative, because the product of two negative numbers is negative.
Answer:
The correct answer is the second option
Explanation:
The formula in question (for gravitational force) is provided below
F = G.m₁.m₂/r²
Where
F = force of gravity
G = gravity constant (6.674 × 10⁻¹¹ m.kg⁻¹.s⁻²)
m₁ and m₂ = are the masses of the objects
r² = distance between the centers of the two objects
From the above, it can be deduced that m₁ and m₂ are masses and hence can only be positive. Positives multiplied together only gives positive, thus the second option is correct.
Louisa found that she could melt 150g of lead at 3275 C. At what temperature could she melt 75g of lead?
A 500 kg sports car accelerates uniformly from rest reaching a speed of 30 m/s in 6 seconds .Find the distance travelled by the car in 6 second
Answer:
the distance traveled by the sports car is 90 m
Explanation:
Given;
mass of the sports car, m = 500 kg
initial velocity of the sports car, u = 0
final velocity of the sport car, v = 30 m/s
time of motion of the car, t = 6 s
The distance traveled by the sports car is calculated as;
\(s = (\frac{u+v}{2} )t\\\\s = (\frac{0+30}{2} ) \times 6\\\\s = 15 \times 6\\\\s = 90 \ m\)
Therefore, the distance traveled by the sports car is 90 m