What is the index of refraction for a medium where light has a velocity of 1.75 x108 m/s?5.750.5771.731.25

The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. ... It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

AnsA

Explanation:

The amount of matter in an object

Answer:

20 km/h

Explanation:

45 km ÷ 2.25 hours (15 mins is 0.25 hours)

= 20

20 km/h

Answer:

1,4,3and 2 would happen hope this helps

Heya!!

For calculate final velocity, lets applicate formula

                                                \(\boxed{V=V_o+a*t}\)

                                                 Δ   Being   Δ

                                            V = Final Velocity = ?

                                         Vo = Initial velocity = 0 m/s

                                          a = Aceleration = 5 m/s²

                                                 t = Time = 12 s

⇒ Let's replace according the formula:

\(\boxed{V=0\ m/s +5\ m/s*12\ s}\)

⇒ Resolving

\(\boxed{V=60\ m/s}\)

Result:

The velocity after 10 sec is 60 meters per second (m/s)

Good Luck!!

Answer:

A mixture is a combination of two or more substances in which the identities of substances are retained. ... The mixture can be in the form of solutions, colloids and suspension. The mixture will have characteristics different from the parent material due to the combination of different kinds of materials.

Hope this helps!!!

From the measure of 3.4 cm we can see that the minimum uncertainty implied is in the milimeters, that is in the range of 0.1 cm.

Weightlessness in space and weightlessness during free fall may appear similar in terms of the sensation experienced, but they occur under different circumstances and have distinct underlying causes. Here are the key differences between the two:

1.Environment:

Space: Weightlessness in space refers to the state experienced by astronauts in orbit around the Earth or in deep space. They are in a microgravity environment, far away from any significant gravitational forces.

Free fall: Weightlessness during free fall occurs when an object is falling under the influence of gravity, experiencing zero-gravity conditions momentarily. This typically happens when an object is in a state of free fall, such as during skydiving or in an airplane during a parabolic flight.

2.Gravitational Forces:

Space: In space, weightlessness is the result of being in constant free fall around the Earth. Although gravity is still present, the gravitational forces are counterbalanced by the centrifugal force created by the orbiting motion. This results in a continuous state of free fall, giving the sensation of weightlessness.

Free fall: Weightlessness during free fall occurs due to the absence of support forces countering the force of gravity. When an object is in free fall, there are no contact forces pushing against it, leading to a sense of weightlessness.

3.Duration:

Space: Weightlessness in space can last for an extended period, as long as the object or person remains in orbit or deep space. Astronauts aboard the International Space Station (ISS), for example, experience weightlessness for months at a time.

Free fall: Weightlessness during free fall is relatively brief and temporary. It occurs during the duration of the free fall, which can last for a few seconds to a couple of minutes, depending on the specific circumstances.

4.Context:

Space: Weightlessness in space is a constant state for astronauts. They adapt to this environment and conduct various experiments, work on scientific research, and live aboard the spacecraft for extended periods.

Free fall: Weightlessness during free fall is typically experienced as part of a recreational activity or a specific scientific experiment. It is a brief moment of weightlessness within the context of a larger activity, such as skydiving, parabolic flights, or drop towers.

While both weightlessness in space and weightlessness during free fall share the absence of apparent gravity and the sensation of floating, they occur in different environments, are caused by different factors, and have varying durations and contexts.

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Answer:

Two things in your life that require power -

1.) Laptop

2.) Cellphone

Explanation:

There are way more but these are just two!

Hope this helps ;)

Brainliest ??

When (n-1) polaroids are placed between, two polaroids. Total number of polaroids becomes (n-1+1+1) = (n+1). The axis of all the polaroids are equally spaced. If x is angle between the axis of the two consecutive polaroids then:

\({:\implies \quad \sf x+x+x+\cdots \cdots n\:\:times=\dfrac{\pi}{2}}\)

\({:\implies \quad \sf nx=\dfrac{\pi}{2}}\)

\({:\implies \quad \sf x=\dfrac{\pi}{2n}}\)

Now, by Malus law, we know that the intensity of light on passing through a pair of Polaroid is proportional to cos²(x). Before the light passes out of the last polaroid, this change in intensity will be repeated n times. If \({I_0}\) is intensity of the incident light and \({I}\), is the intensity of light after passing through all the polaroids, then mathematically from Malus law:

\({:\implies \quad I=I_{0}\sf \cos^{2n}(x)}\)

\({:\implies \quad I=I_{0}\sf \cos^{2n}\bigg(\dfrac{\pi}{2n}\bigg)}\)

When, n will be very large, the angle x → 0, so that the whole cosine expression → 1. So, when n will be very much large, \({I}\) will approach \({I_0}\)

Explanation:

hope it helps you

thank you

Answer:

50µs

Explanation:

The conversion is that 1 second equals 1,000,000 micro seconds. Since we have 0.00005 seconds, we will multiply that to a million.

0.00005 * 1,000,000 = 50µs

Keep in mind that 50 only has 1 significant figure because any trailing zeroes before the decimal point do NOT count.

Best of Luck!

0.00005 seconds = 50 μs

Thank you

Answer:

distance means the length of any thing that have one starting point mad ending point

displacement means the short distance that move by an object due to help of any force

Answer:

there is examples and defination for distance and displacement

Answer:

c

Explanation:

im sorry if im wrong

mark me as brainlist please thank you

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Answer:

There are nine PCNs in the Edmonton area. They work alongside more than 1,100 family doctors in over 330 clinics to provide care for 1.2 million patients. PCN teams include more than 370 nurses, mental health clinicians and other health professionals.

Explanation:

Answer:

The slope intercept form is probably the most frequently used way to express equation of a line. To be able to use slope intercept form, all that you need to be able to do is 1) find the slope of a line and 2) find the y-intercept of a line.

Explanation:

Answer:You plot the numbers and divide

Explanation:

The magnitude of the average acceleration of the cart: a(CD) > a(AB) > a(DE) > a(BC). Therefore, option (d) is correct.

Acceleration can be defined as the rate of change of velocity and is denoted by ‘a. It is measured in the units of m/s². For a particular interval, the average acceleration is the change in velocity for that specific time interval.

Average acceleration is calculated by the following formula,

Average acceleration = Δv/Δt

Where Δ v is the change in velocity and Δt is the total time in the velocity is changing.

For the curve AB:

Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)

a = (8 -0)/(0.6 - 0) = 13.3 m/s²

For the curve BC:

Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)

a = (8 -8)/1 - 0.6) = 0 m/s²

For the curve CD:

Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)

a = (0-8)/(1.2 -1.0) = -40 m/s²

For the curve DE:

Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)

a = (-4-0)/(2.0 - 1.2) = 5 m/s²

Therefore, the magnitude of the average acceleration of the cart: Acd > Aab > Ade > Abc

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In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.

The period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,

Period of oscillation = 1.80s.

From here, finding the frequency is simple as, Frequency = 1/Period. Hence,

Frequency = 1/1.80

= 0.555 Hz (3 sf).

The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.

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The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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The specific heat of the metal, assuming no heat is exchanged with the surroundings is 2140 J/(kg•K).

The specific heat capacity of the metal is determined from the principle of conservation of energy.

energy lost by the metal = energy gained by aluminum + energy gained by water

Q = mcΔθ

where;

0.425c(100 - 40) = 0.1(900)(40 - 15) + 0.5(4186)(40 - 15)

25.5c = 2250 + 52,325

c = 54,575/25.5

c = 2140 J/(kg•K)

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Answer:

50 N

Explanation:

W = Fd

F = W/d

first convert cm → m:  50 cm x 1 m/cm = 0.50 m

F = (25 J) / (0.50 m) = 50 N

Answer:

Narendra Modi

Explanation:

The answer depends on what year you are talking about on, Narendra Modi was a prime minister of india since 2014. If you are missing information on your question tell me so I can try and tell you the answer,

Hope this helped,

have a good day :]

Answer:

Change its velocity by 10 m/s in 1s

Explanation:

Answer:

The pressures acting on a submarine at 50 m are much less than the pressures at a depth of 200 m. The lower the submarine goes, the higher the pressure.

Explanation: I did some research on this and got it right.

On one cookie containing 50 calories, you could potentially go approximately 298 meters

Given that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:

50 food calories * 4184 J/calorie = 209,200 joules

Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).

Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)

Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)

Distance ≈ 298 meters

Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters

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Answer:

8 blocks.

Explanation:

Given that,

A student walks 3 blocks East, 2 blocks North, 1 block West, and then 2 blocks  South.

We need to find the total distance traveled by the student. The distance covered by an object is equal to the sum of the total path covered. So,

Distance = 3 blocks + 2 blocks + 1 block + 2 blocks

= 8 blocks

So, the distance traveled by the block is 8 blocks.

The bombardment of the gamma rays with the particles in outer space reduces the energy thus what we see is mostly visible light of lower energy.

We know that nuclear fusion is the process by which two light nuclei are combined in order to obtain a heavier nucleus with the emission of a tremendous mount of energy. Due to the tremendous amount of energy that is required when we are carrying out a fusion reaction, it does occur only in the sun.

The  proton proton chain produces gamma ray photons. We know that gamma rays have a very high energy but the energy of the gamma photons is reduced as it is bombarded with the particle in the atmosphere.

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The correct answer for the radius of a white dwarf is determined by a balance between the inward force of gravity and the outward push of is Electron Degeneracy Pressure.

 How does a white dwarf's mass affect its radius?

When you raise pressure, you also increase gravity and make the particles closer together, which causes the thing to get smaller because the only way to increase pressure is by adding mass. In other words, the radius of a white dwarf decreases with increasing mass.

A star's gravitational collapse will be stopped by electron degeneracy pressure if its mass is below the Chandrasekhar limit (1.44 solar masses). The force preventing a white dwarf star from collapsing is this one.

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The equilibrium between the outward push of "electron degeneracy pressure" and the inward force of gravity determines a white dwarf's radius.

What is quantum degeneracy pressure?

The more widespread phenomenon known as quantum degeneracy pressure has many different manifestations, including electron degeneracy pressure. As a result, a pressure is created to prevent the compression of matter into smaller amounts of space. The same fundamental process that determines the electron orbital structure of elements produces electron degeneracy pressure.

If a star's mass is below the Chandrasekhar limit, electron degeneracy pressure will prevent gravitational collapse (1.44 solar masses). A white dwarf star is kept from collapsing by this pressure. Because the degeneracy pressure provided by the electrons is weaker than the gravitational pull inward, a star that is larger than this limit.

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Explanation:

formula for energy is k. e = ½mv²

m= 9

v= 75

k. e = ½×9×75 =337•5

Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s