Answer:
v= 2.74m/sExplanation:
We can solve for the initial velocity using the first equation of motion
\(v= u +at\)
where
v= final velocity
u= initial velocity
a= acceleration
t= time in seconds
Given data
final velocity= 2.41 m/s
initial velocity v =?
time t= 2.5 seconds
acceleration a= \(0.130m/s^2\)
substituting we have
v= 2.41+0.13(2.5)
v= 2.41+0.325
v= 2.735m/s
v= 2.74m/s
the final velocity is 2.74 m/s
plsssss asappppppppp
Answer:
20 meters.
Explanation:
In the graph, the x-axis (the horizontal axis) represents the time, while the y-axis (the vertical axis) represents the distance.
If we want to find the distance covered in the first T seconds, you need to find the value T in the horizontal axis.
Once you find it, we draw a vertical line, in the point where this vertical line touches the graph, we now draw a horizontal line. This horizontal line will intersect the y-axis in a given value. That value is the total distance travelled by the time T.
In this case, we want to find the total distance that David ran in the first 4 seconds.
Then we need to find the value 4 seconds in the horizontal axis. Now we perform the above steps, and we will find that the correspondent y-value is 20.
This means that in the first 4 seconds, David ran a distance of 20 meters.
. in terms of systems that can produce standing waves, what do we mean by: a. closed-closed? b. open-open? c. closed-open?
Standing waves can be produced in systems that have boundaries or endpoints that reflect or absorb waves. The nature of the boundary conditions determines the types of standing waves that can be produced.
a. Closed-closed: In a closed-closed system, both ends of the system are fixed and do not allow any displacement of the medium. This means that there is no flow of the medium at either end. An example of a closed-closed system is a string that is fixed at both ends.
b. Open-open: In an open-open system, both ends of the system are free to move, allowing the medium to flow in and out. This means that there is maximum displacement of the medium at both ends. An example of an open-open system is an air column that is open at both ends.
c. Closed-open: In a closed-open system, one end of the system is fixed and the other end is free to move, allowing the medium to flow in and out. This means that there is maximum displacement of the medium at the open end and no displacement at the closed end. An example of a closed-open system is a pipe that is closed at one end and open at the other.
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A 10.0 g piece of metal at 100 C is transferred to a calorimeter containing 50.0 mL of water initially at 23.0 C. Calculate the specific heat capacity of the metal if the heat capacity of the calorimeter, C cal, is 25.0 J/K. The final temperature, T final is 25.6 C.
The specific heat capacity of the metal is 0.73 J/g°C.
The specific heat capacity of the metal can be calculated from the equation
q = (m × c × ΔT)metal + (Ccal × ΔT)calorimeter,
where q is the heat absorbed by the calorimeter, m is the mass of the metal, c is the specific heat capacity of the metal, ΔT is the change in temperature, and Ccal is the heat capacity of the calorimeter.
The final temperature, Tfinal, is 25.6°C.
The heat absorbed by the calorimeter, q, can be calculated from the equation
q = mcΔT,
where m is the mass of the water and c is the specific heat capacity of water.
Since the calorimeter contains 50.0 mL of water, which has a density of 1.00 g/mL, the mass of the water is 50.0 g.
Therefore, the heat absorbed by the calorimeter is
q = (50.0 g) × (4.18 J/g°C) × (25.6°C − 23.0°C) = 544 J.
The heat absorbed by the metal can be calculated from the equation
qmetal = −qcalorimeter = −544 J.
Since the metal is transferred to the calorimeter at 100°C, the initial temperature of the metal, Ti, is 100°C.
Therefore, ΔTmetal = Tfinal − Ti = 25.6°C − 100°C = −74.4°C.
Since the metal has a mass of 10.0 g, the specific heat capacity of the metal can be calculated from the equation cmetal = qmetal ÷ (m × ΔTmetal) = −544 J ÷ (10.0 g × −74.4°C) = 0.73 J/g°C.
Therefore, the specific heat capacity of the metal is 0.73 J/g°C.
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______ is (are) partially blocked by ozone in the stratosphere.
a. Ultraviolet radiation
b. Microwaves
c. X-rays
Ultraviolet radiation is partially blocked by ozone in the stratosphere.
Hence, the correct option is A.
Ultraviolet (UV) radiation is partially blocked by ozone in the stratosphere. The ozone layer in the Earth's stratosphere acts as a protective shield by absorbing much of the incoming UV radiation from the Sun. This absorption process helps to prevent a significant amount of harmful UV radiation from reaching the Earth's surface.
Ozone molecules are particularly effective at absorbing UV-B (shortwave) and UV-C (even shorter wavelength) radiation. The absorption of UV radiation by ozone in the stratosphere plays a crucial role in protecting living organisms from the damaging effects of excessive UV exposure, which can lead to sunburn, skin cancer, and other harmful health effects.
Therefore, Ultraviolet radiation is partially blocked by ozone in the stratosphere.
Hence, the correct option is A.
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A boy exerts a force on a lever to raise a 1250 N rock a
distance of 0.13 m. The boy moved his end of the lever 0.722
m. What is the exerted force on the lever?
Answer:
255 .07N
Explanation:
F_l * d_l = F_r * d_r
F_l * 0.722 = 1250 * 0.13
F_l = 255.07
The critical temperature the core must reach for a star to shine by fusion is a. 5,800 K b. 11,000 K c. 127,000 K d. 10 million K e. 100 million K.
The critical temperature the core must reach for a star to shine by fusion is 10 million K.
The process by which stars produce energy is through nuclear fusion, in which hydrogen atoms combine to form helium, releasing energy in the process. The temperature and pressure at the star's core must be high enough to initiate and sustain this fusion process.
The minimum temperature required for hydrogen fusion to occur is approximately 10 million K. At this temperature, the hydrogen atoms have enough thermal energy to overcome their electrostatic repulsion and come close enough together for the strong nuclear force to bind them into helium.
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an electron moving in a uniform magnetic field experiences the maximum magnetic force when the angle between the direction of the electron's motion and the direction of the magnetic field is A) 0 B) 45°C ) 90° D) 180°
An electron moving in a uniform magnetic field experiences the maximum magnetic force when the angle between the direction of the electron's motion and the direction of the magnetic field is 90°. So, option C) is correct.
The correct answer is C) 90°. This is because the magnetic force on a charged particle, say, an electron, moving in a magnetic field is given by F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
When θ = 90°, sinθ = 1, and therefore the magnetic force is at its maximum value. When θ = 0° or 180°, sinθ = 0, and the magnetic force is zero.
When θ = 45°, sinθ is less than 1, so the magnetic force is less than its maximum value.
The magnetic force acting on a moving charged particle is given by F = q(v × B), where F is the magnetic force, q is the charge of the particle, v is its velocity, and B is the magnetic field.
The cross product (v × B) in the formula implies that the magnetic force is at its maximum when the angle between the velocity and the magnetic field is 90 degrees.
So, option C) is correct.
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A police car is driving north with a siren making a frequency of 1038 hz. Moops is driving north behind the police car at 12 m/s and hard a frequency of 959hz. How fast is the police car going?
Answer:
The police car is moving at 41.24 m/s.
Explanation:
To find the speed of the police car we need to use the Doppler equation:
\( f = f_{0}(\frac{v + v_{r}}{v + v_{s}}) \)
Where:
v: is the speed of the sound = 343 m/s
\(v_{r}\): is the speed of the receiver = 12 m/s
\(v_{s}\): is the speed of the source =?
f: is the observed frequency = 959 Hz
f₀: is the emitted frequency = 1038 Hz
Both terms are positive in the fraction because the velocity of the sound is in the opposite direction to both velocities of the police car and the other car.
By solving the above equation for \(v_{s}\) we have:
\( v_{s} = \frac{f_{0}(v + v_{r})}{f} - v = \frac{1038(343 + 12)}{959} - 343 = 41.24 m/s \)
Therefore, the police car is moving at 41.24 m/s.
I hope it helps you!
A swarm of locust eats the leaves of most of the trees in a forest. How would the trees be most directly affected?
Please HELP!
Answer:
A trees food and air source would be deprived because of this. Trees need leaves to perform photosynthesis, so besides their roots soaking up water and nutrients, they wouldn't have any other form of food until those leaves grow back. If they don't and the locusts continue to eat up the tree, it will eventually starve and die.
Explanation:
Imagine the trees trunk and roots as your body and the leaves as your mouth/food source. God Forbid you catch a cold or some sickness. You probably won't have the appetite to eat. Despite that, you'll still have to. But, if you get so sick to the point that eating just makes you throw it up before your body can take in the nutrients and beneficial stuff, you will eventually get to the point where eating is nearly impossible. This will lead up to the sickness taking over your body, as there's no energy going in to help it fight it off, and you would die.
(Gah, sorry for the dark theme... didn't think it would turn like that lol)
Anyways, hope this helped!
Source(s) used: N/A
the relationship between force and acceleration verification of Newton second law of motion
Answer:
below
Explanation:
According to Newtons Second Law of Motion, also known as the Law of Force and Acceleration, a force upon an object causes it to accelerate according to the formula net force = mass x acceleration. So the acceleration of the object is directly proportional to the force and inversely proportional to the mass.
Which type of thermal energy transfer does a foil wrapping reduce the most? O A. Conduction O B. Translation O C. Radiation O D. Convection
The foil reduces radiation the most in terms of thermal energy transfer. Thermal energy transfer is the movement of heat from one place to another. The four types of thermal energy transfer are radiation, conduction, convection, and advection. The correct answer is option OC.
Foil wrapping reduces radiation as the most type of thermal energy transfer. Thermal energy transfer is the movement of energy from one place to another. There are four types of thermal energy transfer: conduction, convection, radiation, and advection. The foil wrapping reduces radiation the most. When there is a foil wrapped around food, the foil traps the heat inside the food, which reduces the radiation energy transfer. Radiation is the heat transfer that occurs in the form of electromagnetic waves. It requires no matter to move, which is why it can occur in the vacuum of space. Radiation transfer can be absorbed, transmitted, or reflected. Therefore, the correct answer is option OC.For more questions on radiation
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Define periodic motion
Q 1.1 Verify full system functionality.
Q 1.2 Document findings, and actions.
Q 1.3 Test the theory to determine the cause of the problem.
Q 1.4 Identify the problem.
Q 1.5 Establish a theory of the cause.
Answer:
Q11. verifying full system functionality confirms that you have solved the original problem and ensures that you have not created another problem while repairing the computer.
What is the wavelength of light waves if their frequency is 5.0x1014 Hz and the speed of light 3 x
108 m/s?
A. 0.60 m
B. 6.0 mm
C. 0.060 mm
D. 0.60 um
Answer:
D. 0.60 um
Explanation:
Given the following data;
Frequency = 5.0x10^14 Hz
Speed = 3 x 10^8 m/s
To find the wavelength;
Wavelength = speed/frequency
Substituting into the equation, we have
Wavelength = 3 x 10^8/5.0x10^14
Wavelength = 6 × 10^7m
But 1 meter (m) = 1000000 micrometer (um)
6 × 10^7 meter = 0.6 micrometer.
Calculate the net force of the object in the image shown 20N 15 N
how do I count the waves?
search it up on yt lol
Explanation:
A baseball going 33.0 m/s will take what time in seconds to travel 8.1 meters?
Round your answer to 3 decimal places.
2
Type your answer..
\(\\ \bull\sf\dashrightarrow Speed=\dfrac{Distance}{Time}\)
\(\\ \bull\sf\dashrightarrow Time=\dfrac{Distance}{Speed}\)
\(\\ \bull\sf\dashrightarrow Time=\dfrac{33}{8.1}\)
\(\\ \bull\sf\dashrightarrow Time=4.07s\)
I’ll mark brainliest
When you look into your bathroom mirror, are you upside down
(inverted) or right side up (upright)?
Is this a real or virtual image?
Why?
What is the focal length of a bathroom (flat) mirror?
Answer:
When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image is virtual and upright.
Explanation:
Which one of these is not a physical charge
A melting and ice cube
B crushing a can
C chopping wood
D metal resting
Answer:
the answer is D metal resting
Explanation:
I just think that because if you treasure can that's physical charge by dropping where you create a physical charge melting and Ice Cube might be 1 but I feel like metal resting is more likely
Which country has more nuclear power stations, the UK or France?
Answer: FRANCE
Explanation:
Answer:
France
Explanation:
UK has 15 nuclear power plants and 2 under construction whereas France has 56 in operation and 1 under construction
can force be expressed in units of pounds and newtons?
Yes, force can be expressed in units of pounds and newtons.
What are the units of force?Force is an effect of the mass of object to accelerate in particular direction and can be expressed in the unit of pounds according to the FPS system of units. Newton is also a unit to express the force. SI unit of force is the newton and symbol is N.
Convert weight measured in pounds to equivalent in Newtons. In the formula for the determination of mass based on weight, mass is measured in Newtons. Weight is measured in Kilograms, and acceleration of gravity on Earth is measured as 9.8 meters per second squared and these are metric system unit measurements.
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At each end of a long bone is an expanded portion called an ______, which articulates (or forms a joint) with another bone
At each end of a long bone is an expanded portion called an "epiphysis," which articulates (or forms a joint) with another bone.
An epiphysis is a rounded or flat surface located at the ends of a long bone and is covered by a layer of smooth articular cartilage. This cartilage provides a low-friction surface that allows for smooth and pain-free movement between the bones at the joint. The epiphysis is separated from the main shaft of the bone (the diaphysis) by the epiphyseal plate, a layer of hyaline cartilage that allows for growth in children and adolescents. The epiphysis and diaphysis are joined together by a strong and flexible tissue called the epiphyseal line, which eventually fuses in adulthood and forms a solid connection between the two parts of the bone. The epiphysis and diaphysis work together to provide strength, stability, and support to the bones of the skeleton, and the joints formed by the articulation of the epiphysis and another bone play a crucial role in enabling movements such as walking, jumping, and twisting.
In short, an epiphysis is an expanded portion at the end of a long bone that articulates with another bone to form a joint, and it plays an important role in the movement and stability of the skeleton.
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4. A 5.00-kg sled starts at rest and accelerates down a 45.0° incline. The coefficient of
kinetic friction between the mass and the incline is .185.
a) What is the value of the of the acceleration of the sled
Answer: \(5.64\ m/s^2\)
Explanation:
Given
mass of sled m=5 kg
Elevation \(\theta =45^{\circ}\)
\(\mu _k=0.185\) (coefficient of kinetic friction)
Friction will oppose the motion of the sled while sled weight sin component helps it to move down the incline
\(W\sin\theta-F_r=ma\\where\\W=weight(mg)\\F_r=Friction(\mu_kmg\cos\theta)\\a=acceleration\)
Substituting values
\(mg\sin \theta-\mu_kmgcos\theta=ma\\g\sin \theta-\mu_kg\cos \theta=a\\a=g(\sin 45^{\circ}-0.185\times \cos 45^{\circ})\\a=5.64\ m/s^2\)
An automobile travels a displacement of 75 km at 45 degrees north of East. How many kilometers north does it travel?
Answer:
the number of kilometers north it traveled is 53.03 km
Explanation:
The computation of the number of kilometers north it traveled is shown below:
Given that
The Displacement of 75 km
At east north of 45 degrees
Based on the above information, the number of kilometers is
= 75 × cos 45
= 53.03 km
Hence, the number of kilometers north it traveled is 53.03 km
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Suppose the true process mean of a cholesterol study (with units of mg/dl) is 140.03, and the process standard deviation (of five samples) is 5.10. what is the upper control limit of this study?
The upper control limit (UCL) of the cholesterol study can be calculated using the formula: UCL = Mean + 3 × Standard Deviation.
In this case, the mean of the study is given as 140.03 mg/dl, and the standard deviation of the five samples is 5.10 mg/dl. Plugging these values into the formula, we get:
UCL = 140.03 + 3 × 5.10
Calculating the expression on the right-hand side, we find:
UCL = 140.03 + 15.30
Therefore, the upper control limit of the cholesterol study is:
UCL = 155.33 mg/dl.
The upper control limit is a statistical threshold that is used to monitor the performance of a process or study. It represents a boundary above which data points are considered statistically significant or out of control. In this case, the UCL is calculated by adding three times the standard deviation to the mean. By doing so, we establish an upper limit that is three standard deviations away from the mean. Any data point exceeding this limit would indicate a potential problem or variation in the process being studied. In the context of the cholesterol study, any measurements above 155.33 mg/dl would warrant further investigation or action to assess and address potential health concerns.
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The upper control limit (UCL) of the cholesterol study can be calculated using the formula: UCL = Mean + 3 × Standard Deviation.
In this case, the mean of the study is given as 140.03 mg/dl, and the standard deviation of the five samples is 5.10 mg/dl. Plugging these values into the formula, we get:
UCL = 140.03 + 3 × 5.10
Calculating the expression on the right-hand side, we find:
UCL = 140.03 + 15.30
Therefore, the upper control limit of the cholesterol study is:
UCL = 155.33 mg/dl.
The upper control limit is a statistical threshold that is used to monitor the performance of a process or study. It represents a boundary above which data points are considered statistically significant or out of control. In this case, the UCL is calculated by adding three times the standard deviation to the mean. By doing so, we establish an upper limit that is three standard deviations away from the mean. Any data point exceeding this limit would indicate a potential problem or variation in the process being studied. In the context of the cholesterol study, any measurements above 155.33 mg/dl would warrant further investigation or action to assess and address potential health concerns.
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What does DARE stand for in balanced and unbalanced forces
Answer:
Balanced Forces
But what exactly is meant by the phrase unbalanced force? What is an unbalanced force? In pursuit of an answer, we will first consider a physics book at rest on a tabletop. There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.
Since these two forces are of equal magnitude and in opposite directions, they balance each other. The book is said to be at equilibrium. There is no unbalanced force acting upon the book and thus the book maintains its state of motion. When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.
Consider another example involving balanced forces - a person standing on the floor. There are two forces acting upon the person. The force of gravity exerts a downward force. The floor exerts an upward force.
Since these two forces are of equal magnitude and in opposite directions, they balance each other. The person is at equilibrium. There is no unbalanced force acting upon the person and thus the person maintains its state of motion.
Unbalanced Forces
Now consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop. The book is in motion and at the moment there is no one pushing it to the right. (Remember: a force is not needed to keep a moving object moving to the right.) The forces acting upon the book are shown below.
The force of gravity pulling downward and the force of the table pushing upwards on the book are of equal magnitude and opposite directions. These two forces balance each other. Yet there is no force present to balance the force of friction. As the book moves to the right, friction acts to the left to slow the book down. There is an unbalanced force; and as such, the book changes its state of motion. The book is not at equilibrium and subsequently accelerates. Unbalanced forces cause accelerations. In this case, the unbalanced force is directed opposite the book's motion and will cause it to slow down.
To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.
Somebody help!?
13. The graph below represents the speed of a car vs. time. Circle the letter(s) with the lowest acceleration.
What is the acceleration? How do you know?
Answer:
acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Explanation:
Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .
A beam of monochromatic light of wavelength 645 nm is projected through a circular opening 2.1 mm wide. Find the width of the beam (in mm) at a distance 8 meters away.
The width of the beam at a distance of 8 meters away is approximately 3096 μm or 3.096 mm
we need to consider the principles of diffraction. Diffraction occurs when light waves encounter an obstacle or aperture.
In this case, we have a circular opening with a width of 2.1 mm and a monochromatic light beam with a wavelength of 645 nm (or 0.645 μm). The width of the beam at a distance can be calculated using the formula:
w = (λ * D) / d
where w is the width of the beam, λ is the wavelength of light, D is the distance from the circular opening to the measurement point (8 meters in this case), and d is the width of the circular opening.
Plugging in the given values, we have:
w = (0.645 μm * 8 m) / 2.1 mm
Converting the units, we get:
w = (0.645 μm * 8000 mm) / 2.1 mm
w = 3096 μm
Therefore, the width of the beam at a distance of 8 meters away is approximately 3096 μm or 3.096 mm.
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A particle with a negative charge has an initial velocity that is parallel to a magnetic field moving to the right. What path would this negatively charged particle follow
The negatively charged particle will follow a circular path perpendicular to the magnetic field.
When a particle with a negative charge moves through a magnetic field, it experiences a force known as the magnetic force. The magnetic force on the negatively charged particle acts perpendicular to both the direction of motion of the particle and the direction of the magnetic field.As the particle's initial velocity is parallel to the magnetic field, the magnetic force on it will be perpendicular to both the magnetic field and the particle's velocity. Thus, the particle will experience a force acting at right angles to its motion and it will follow a circular path perpendicular to the magnetic field.The path followed by a charged particle moving through a magnetic field is known as a cyclotron orbit.
Therefore, a negatively charged particle with an initial velocity parallel to a magnetic field will follow a circular path perpendicular to the magnetic field.
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on a windy day, waves in a lake or an ocean are higher than their average height. what factor in bernoulli's principle contributes to the increased height?
Air travels faster over the crests than the throughs because of this factor in bernoulli's principle contributes to the increased height.
That is the tenet of Bernoulli. The combined mechanical energy of a moving fluid, which consists of the gravitational potential energy of elevation, the energy related to fluid pressure, and the kinetic energy of fluid motion, remains constant. The wind is typically partially blocked by the wave troughs, which allows air to go over them faster and maintain a lower pressure than below. The idea that water accelerates up as pressure decreases and slows down as pressure increases comes from Bernoulli's principle. The same scenario plays out here, so the higher pressure in the troughs drives water into even higher Crests.The idea of energy conservation can be used to derive Bernoulli's principle. This asserts that in a steady flow, the total amount of energy present in a fluid will be constant at all places along the streamline.
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Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during the trip their velocity was -20 m/s? Explain
Answer:
Yes , it is possible .
Explanation:
Suppose they travelled from A to B , a distance of 800 m at a velocity of
40m /s and then come back on the same path covering a distance of 200 m at the rate of 20/ s .In other words their velocity in their return journey was -20m /s .
Net displacement = 600 m
Total time taken = (800 / 40) + (200 / 20)
= 20 + 10 = 30 s
Average velocity = net displacement / total time
= 600 / 30 = 20 m /s .
Hence average velocity of 20 m /s is possible .