What is the kinetic energy of a car with a mass of 1,532 kg if it’s traveling at 10.6m/s? Submit your answer in exponential form.

Answer:

C. Neither ultrasonic nor infrasonic vibrations can be heard by humans.

Explanation:

The complete question is

Which of the following statements is true of vibrations? A. The frequency of infrasonic vibrations is much too high to be heard by humans. B. Ultrasonic vibrations have a frequency lower than the range for normal hearing. C. Neither ultrasonic nor infrasonic vibrations can be heard by humans. D. Infrasonic vibrations are used in sonar equipment and to detect flaws in steel castings.

Ultrasonic vibrations have frequencies higher than our range of hearing, while infrasonic vibrations have frequencies lower than our range of hearing. Ultrasonic vibrations or sound is used in sonar equipment, and is used for detecting hidden flaws in steel castings and structures. Both infrasonic and ultrasonic fall below and above our normal hearing range respectively, and are only audible to dogs, cats, and some other mammals.

Answer:

Answer is " Two bodies with the same vibration frequency that are placed next to each other will exhibit sympathetic vibrations as one body causes the other to vibrate."

Explanation:

My options were:

A)  Forced vibrations, such as those between a tuning fork and a large cabinet surface, result in a much lower sound than was produced by the original vibrating body.

B)  Resonance occurs as a result of sympathetic vibrations.

C)  A non-vibrating object can begin to vibrate as a result of forced vibrations.

D)  Two bodies with the same vibration frequency that are placed next to each other will exhibit sympathetic vibrations as one body causes the other to vibrate.

A is correct

.

Answer:

.66m/s

Explanation:

Using the formula V=D/T, we can take our distance, 9m, and put it over our time of 6 seconds.

part a.

the total energy of Saul and the toboggan  is 70530 J

part b.

The height of the hill is  235.1 m.

part c.

Saul's velocity at the bottom of the hill will be  22.3 m/s.

part d.

Saul's height when he is moving at a velocity of 9.5 m/s is 10.5 m

The total energy of Saul and the toboggan is the addition all of potential energy and kinetic energy.

we know that the initial total energy = potential energy at top of hill

Therefore total energy is gien as

initia total energy  = mass of Saul + mass of toboggan x gravity x height

initia total energy  = (30 kg + 10 kg) x (9.81) x (20 m)

initia total energy  = 5886 J

Total energy  = potential energy + kinetic energy

Total energy = (30 kg + 10 kg) (9.81 ^2) x (20) + (30 kg + 10 kg) x (15)^2/2

= 70530 J

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The word or phrase that should be emphasized in the given step to convey order is "Immediately after you pop." Hence, option B  is correct

The phrase "Immediately after you pop" indicates the precise timing for the next step, which is to drag the front foot up and jump forward. It is important to follow this sequence of actions in order to execute the trick correctly.

By emphasizing "Immediately after you pop," the reader or listener will understand that this is a crucial step that should not be delayed or performed out of order. This will help them focus on the timing and make sure they do not miss this important step.

While the other phrases are also important, emphasizing "Immediately after you pop" will ensure that the reader or listener understands the correct sequence of actions and is able to execute the trick properly.

Correct answer is Option B) Immediately after you pop.
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Given,

The mass of the car, m=2000 kg

The momentum of the car, p=80000 kg·m/s

The momentum of an object is given by the product of the mass of the object and its velocity.

Thus the momentum of the car is given by,

Where v is the speed of the car.

On rearranging the above equation,

On substituting the known values,

Thus the speed of the car is 40 m/s

In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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The position they could possibly have zero electric field is C.

An electric field is a physical field that exists in the space surrounding electrically charged particles or objects. It is a vector field, meaning that it has both magnitude and direction.

When a charged particle is present in a space, it creates an electric field that exerts a force on any other charged particles in the vicinity.

The strength of the electric field at any given point is defined as the force per unit charge that a small test charge would experience if placed at that point.

The magnitude and direction of the electric field depend on the distance between the charges and their magnitudes. The electric field is stronger when the charges are closer together and weaker when they are farther apart.

So position they could experience zero electric field is C, assuming point C if very far from the two charges.

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By radiation, energy is transported in the form of electromagnetic waves that propagate at the speed of light. The electromagnetic radiation considered here is thermal radiation. We need to remember that in radiation the objects don't touch each other.

in this case, one example will be Heat is transferred from a heating lamp at a restaurant to a plate of food placed on the counter below it.

option C

When the accompanying stimuli are not present, we can alter and reactivate internal representations through mental imagery. This procedure results in the phenomenon known as "seeing with the mind's eye" when it comes to visual mental images. Thus, option B is correct.

Mental imagery is mostly used to simulate potential future events and "relive" previous experiences. According to this viewpoint, imagery ought to be investigated in a variety of cognitive tasks as well as on its own.

Although it is widely used to enhance physical performance, mental imagery can also benefit tasks that need both cognitive and emotional functioning, such as managing emotions and stress or public speaking.

Therefore, change her feelings. Studies have demonstrated that imaging can promote relaxation in the body and mind. Manage depression, stress, and anxiety are other benefits. Help lessen the agony

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The given question is incomplete. The complete question is given below:

Nan is upset because she has not lost enough weight to buy the new swimsuit that she had wanted, so she imagines herself on the beach having fun with her friends in her current swimsuit. Nan is using mental images to

a.

Prepare for some action.

b.

Change her feelings.

c.

Make a decision.

d.

Aid memory.

16 years of education would the typical professional astronomer have today, at minimum

Minimum qualifications of Astronomer 4 year degree to get a postgraduate qualification like a master of physics.

2 or 3 A levels of math and physics; 5 GCSEs at grades 9 to 4 (A* to C), or equivalent; and a degree in a field that is useful for postgraduate are needed.

Math and physics expertise needed, analytical thinking abilities, science knowledge, great verbal communication skills, and the capacity to think coherently both logic and reasoning are all essential.

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Answer:

0.2365 μC, 6.50 x 10⁻⁵ J, 6.28 x 10⁵ V/m

Explanation:

C = 430 pF, V = 550 V, d = 0.89 mm

A) Q = CV = 430 * 550 pC = 236,500 pC = 0.2365 μC

B) U = CV²/2 = 430 x 10⁻¹² x 550²/2 J = 6.50 x 10⁻⁵ J

C) E = V/d = 550/(0.89 x 10⁻³) V/m = 6.28 x 10⁵ V/m

Given parameters:

Mass of the body  = 200g

Force on the body  = 10N

Unknown parameters:

Acceleration produced by the force  = ?

To solve this problem we must first define force in terms of mass and acceleration. This is possible due to the Newton's first law of motion.

  Force  = mass x acceleration

Here the unknown is acceleration and we can easily solve for it.

But we must take the mass to kilogram in order for it to cancel out.

        1000g  = 1 kg

        200g  = x kg =   \(\frac{200}{1000}\)   = 0.2kg

Now input the parameters and solve;

         10  = 0.2 x acceleration

   Acceleration  = \(\frac{10}{0.2}\)   = 50m/s²

The acceleration produced by the body is 50m/s²

The tension force on object 2 must be one-fourth the tension force on object 1. The correct option is D.

The cross-sectional area is directly proportional to the square of the diameter, or A = πd²/4.

The Young's modulus is a constant for a given material.

Therefore, the change in length is proportional to the tension force and the square of the diameter.

For the two objects to have the same change in length, they must also have the same tension force.

The tension force is inversely proportional to the cross-sectional area, or F = EA/L0.

Therefore, the tension force is inversely proportional to the square of the diameter.

If object 2 has twice the diameter of object 1, then it will have four times the cross-sectional area.

Therefore, the tension force on object 2 must be one-fourth the tension force on object 1.

In other words, T2/T1 = 1/4.

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T = 2,548

What is tension?

Tension occurs due to the direction of pull on the object and along the length of the given rope.

It's S.I. unit is Newton

Tension formula can be represented as

T = mg + ma

T = 200 (9.8 + 1.3 m/s²)

T = 200 (12.74)

T = 2,548

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Answer:

Motor cortex

Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).

Explanation:

The height of the hill is approximately 0.128 meters.

The total energy of the ball at the top of the hill is equal to its kinetic energy:

E_top = K = 15 J

At the bottom of the hill, the total energy of the ball is the sum of its kinetic and potential energies:

E_bottom = K + U = 70 J + 5 J = 75 J

The potential energy of the ball at the top of the hill is zero, since it is at the highest point. Therefore, the potential energy at the bottom of the hill is:

U = E_bottom - K = 75 J - 70 J = 5 J

The potential energy of an object at a height h is given by:

U = mgh

where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height. Rearranging this equation gives:

h = U/(mg)

Substituting the values given in the problem, we get:

h = 5 J / (4 kg * 9.8 m/s^2) ≈ 0.128 m

Therefore, the height of the hill is approximately 0.128 meters.

What is kinetic energy?

Kinetic energy is the energy possessed by a moving object due to its motion. It is defined as the energy an object has by virtue of its motion, and is directly proportional to the mass of the object and the square of its velocity (speed).

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How much pressure it would exert on the ground.

\( \frac{1000}{100 \times 100} \: {m}^{2} \)

\( = 0.1 \: {m}^{2} \)

\(P = \frac{F}{A} \)

\(P = \frac{20000 \: N}{0.1 \: {m}^{2} } \)

\(\large\boxed{\sf{P = 200000N /m^2}}\)

Hence, the pressure exerted on the ground is \(200000 \: N /m^2\)

Pressure = Force/Area

Pressure = 20,000/0.1

Pressure = 200000 N/m²

Answer:

yes it is possible

Explanation:

if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.

eg: a body in uniform circular motion has constant speed but its velocity changes at every point during the course of motion. Whenever, the direction changes, velcoity changes.

The vectors can be expressed using unit vectors as follows:

Vector A = 96N i + 96N j + 0N k

Vector B = 76.6N i + 64.3N j + 0N k

Vector C = 64N i + 48N j + 0N k.

In the given diagram, let's consider the vectors as follows:

Vector A with magnitude 120N, Vector B with magnitude 100N, and Vector C with magnitude 80N.

To express these vectors using unit vectors i, j, and k, we need to determine their respective components in the x, y, and z directions.

For Vector A (120N), we have the following information:

Magnitude = 120N

Direction: X-axis (cosine component) with an angle of 37° and Y-axis (sine component) with an angle of 53°.

Using the trigonometric values provided:

cos37° = 0.8 and sin53° = 0.8

Therefore, the components of Vector A are:

Ax = 120N * 0.8 = 96N (in the X-direction)

Ay = 120N * 0.8 = 96N (in the Y-direction)

Az = 0N (no component in the Z-direction)

Thus, Vector A can be written as 96N i + 96N j + 0N k.

Similarly, using the trigonometric values for Vector B and Vector C, we can calculate their components:

For Vector B (100N):

Bx = 100N * cos40° = 100N * 0.766 = 76.6N

By = 100N * sin40° = 100N * 0.643 = 64.3N

Bz = 0N

Vector B can be expressed as 76.6N i + 64.3N j + 0N k.

For Vector C (80N):

Cx = 80N * cos37° = 80N * 0.8 = 64N

Cy = 80N * sin37° = 80N * 0.6 = 48N

Cz = 0N

Vector C can be written as 64N i + 48N j + 0N k.

In summary, the vectors can be expressed using unit vectors as follows:

Vector A = 96N i + 96N j + 0N k

Vector B = 76.6N i + 64.3N j + 0N k

Vector C = 64N i + 48N j + 0N k.

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Answer:

a. False

Explanation:

For an object to be moving at a constant velocity, a net force of 0 N would be required.

Newton's 1st Law of Motion states that an object will remain at rest unless acted upon by an unbalanced force, and an object will remain in motion unless acted upon by an unbalanced force.

Therefore, the unbalanced force of 6 N would not allow the rock to maintain its constant speed.

The answer to this question is A) False.

That's false.

NO FORCE is required to keep an object moving at a constant speed.

Answer:

B

Explanation:

Answer:

B

Explanation:

The true facts about a fission chain reaction is that it involves the breakdown of a large nucleus into daughter nuclei when bombarded by a small particle such as a neutron. It is a self sustaining reaction.

Nuclear fission is said to have occurred when a neutron is used to bombard an unstable or fissile nucleus such that it breaks down into smaller daughter nuclei releasing tremendous energy in the process.

The reaction is self sustaining because more neutrons are produced as the fission reaction proceeds which ensures that the reaction continues.

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Answer: The number of freely moving neutrons increases over time

Explanation:

Answer:

a)  x = 660 m, b)  λ = 0.330 m, c) Δλ = 0.1 cm, d)    Δf = 104

Explanation:

a) the distance in which the train of waves extends can be obtained from the uniform movement

             v = x / t

             x = v t

             x = 330 2

             x = 660 m

b) the speed of sound is related to the wavelength and frequency

             v = λ f

              λ = v / f

              λ = 330/1000

              λ = 0.330 m

c) The precision in the measurement of the wavelength refers to the error or uncertainty in the measurement, if the measurement is direct with a tape measure the precision is the appreciation of the tape measure, in general it is 0.1 cm

d) the accuracy of the frequency in general the frequency is calculated from the measurements of period T

                f = 1 / T

The precision of the period is data by the chronometer used, in general time a press of 0.01s, by the response time of the people

               Δf = df / dT    ΔT

               Δf = 1 / T² ΔT

                Δf = 1 / (0.001)² 0.01

                 Δf = 104

As we can see, a much more precise system is needed to reduce the error

Complete Question

A proton of mass m​p​​= 1.67×10​−27​​ kg and a charge of q​p​​= 1.60×10​−19​​ C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E = 3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the time it exits the region of uniform electric field. You may neglect the effects of friction and gravity, and assume that the electric field is zero outside the specified region. Answer is to be in units of meters

Answer:

    \(s = 0.039 \ m\)

Explanation:

From the question we are told that

    The  mass of the proton is  \(m = 1.67 *10^{-27} \ g\)

    The charge of on the proton is \(q = 1.60 *10^{-19} \ C\)

      The speed of the proton is  \(v = 10000 \ m/s\)

     The magnitude of the electric field is  \(E = 3.62*10^{3 } \ N/C\)

       The width covered by the electric field    \(d = 5mm = 5 *10^{-3} \ m\)      

Generally the acceleration of the proton due to the electric toward the south  (at the point where the force on the proton is equal to the electric force due to the electric field) is  mathematically represented as

       \(a = \frac{q* E}{m}\)  

Substituting values

       \(a = \frac{1.60*10^{-19 } * 3.26 *10^{3}}{ 1.67*10^{-27}}\)

      \(a = 3.12*10^{11} \ m/s^2\)

Generally the time it will take the proton to cross the electric field is  mathematically represented as

      \(t = \frac{d}{v}\)

Substituting values

      \(t = \frac{5 *10^{-3}}{10000}\)

     \(t = 5 *10^{-7} \ s\)

Generally the the distance covered by the proton toward the south is  

       \(s = ut + \frac{1}{2} * a*t^2\)

   Here  u = 0  m/s  this  because before the proton entered the electric field region the it velocity towards the south is  zero

     So

       \(s = \frac{1}{2} * a*t^2\)

Substituting values

      \(s = \frac{1}{2} * 3.12 *10^{11}*(5 *10^{-7})^2\)

      \(s = 0.039 \ m\)

The distance through which the spring is compressed is equal to the kinetic energy of the steel ball divided by the spring constant, i.e. 0.1 kg x 4m/s2/10N/m = 0.04 m.

Let us begin by Calculating the kinetic energy of the steel ball:

Kinetic Energy = 0.5 x mass x velocity2

Kinetic Energy = 0.5 x 0.1 kg x (4 m/s)2

Kinetic Energy = 0.8 J

Calculate the distance through which the spring is compressed:

Distance = Kinetic Energy/Spring Constant

Distance = 0.8 J/10N/m

Distance = 0.04 m

Compression is the process of reducing the size of a file or data to save disk space and reduce transmission times. Compression is achieved by encoding data using fewer bits than the original representation.

This is done by removing unnecessary or redundant data, such as white space, or by using data compression algorithms. Compression helps make data storage and transmission more efficient.

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With the use of formulas, the capacitance is 33500000000 nF and the charge is 301.5 Coulombs

Capacitance of a Capacitor can be defined as charge to potential difference ratio.

Given that a parallel plate capacitor having plates of area 1.3 cm2 that are separated by 0.026 mm of neoprene rubber with the assumption that the rubber has a dielectric constant κ = 6.7.

The capacitance C = kA/d where

Substitute all the parameters into the formula

C = (6.7 × 0.00013)/0.000026

C = 33.5 Farad

The charge, in coulombs when 9.00 V is applied across it will be

Q = CV

Q = 33.5 × 9

Q = 301.5 Coulombs

Therefore, the capacitance in nanofarads is 33500000000 nF and the charge, in coulombs when 9.00 V is applied across it is 301.5 Coulombs

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