What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg(*)m/s of momentum?

Answer:

gravity

Explanation:

this is the answer because gravity is the force that pulls things down because gravity is what is trying to pull things down to the center core of the earth

Answer:

the force of gravity

Explanation:

edge 2021

The height of the roof is approximately 74.4 feet.

To determine the height of the roof, we can use the equation of motion for a falling object. The equation is:

h = (1/2)gt^2 + v0t + h0

where:
h is the height of the object
g is the acceleration due to gravity (approximately 32.2 feet per second squared)
t is the time taken for the object to fall
v0 is the initial velocity of the object (which is -140 feet per second in this case)
h0 is the initial height of the object (which is the height of the roof in this case)

Since the stone is dropped, the initial velocity (v0) is 0 and the equation simplifies to:

h = (1/2)gt^2 + h0

The stone hits the ground with a velocity of -140 feet per second, which means its final velocity (vf) is also -140 feet per second. We can use this information to find the time it took for the stone to fall using the equation:

vf = gt

-140 = 32.2t

Now, solve for t:

t = -140 / 32.2

t ≈ 4.35 seconds

Substituting this value of t back into the equation, we can solve for h0:

h = (1/2)gt^2 + h0

0 = (1/2)(32.2)(4.35)^2 + h0

0 = 74.4 + h0

Solve for h0:

h0 = -74.4 feet

Therefore, the height of the roof is approximately 74.4 feet.

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We now think that the canals seen on Mars in the late nineteenth and early twentieth century were the result of optical illusions.

The canals of Mars, which appeared to be systems of long, straight lines on the surface of Mars, are now understood to be illusions caused by the unintentional alignment of craters and other natural surface features that are seen in telescopes close to their resolution limit. They sparked a lot of debate and influenced how people perceived the possibility of life beyond Earth in the late 19th and early 20th centuries.

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Answer:

I think it's dio to atmospheric pressure.

Answer:

Mass of object = 8kg

Explanation:

= 1.5

You can now solve for your unknown value of mass.

A net force of 12.0 N causes an object to increase its speed from 15.0 m/s to 18.0 m/s during a 2.0 second interval. The mass of the given object 8 Kg.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Since a = change in v/ change in t,

a = (18-16)/2

a = 1.5

Force, f = ma

mass, m = F/a

          m = 12/1.5

          m = 8 Kg.    

A net force of 12.0 N causes an object to increase its speed from 15.0 m/s to 18.0 m/s during a 2.0 second interval. The mass of the given object 8 Kg.

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The linear speed of the conveyor belt is 100.5 cm/s, if the radius of the roller is 8 cm and revolution speed 2 revolution per second.

The radius of the roller, r = 8 cm

Number of revolution per second, n = 2

Angular speed of the roller, ω = 2πn/T

Let the linear speed of the conveyor belt = v

ω = 2π×2/1 = 4π/sec

Linear speed is defined as the product of the radius and angular speed.

v = r × ω

v = 8 × 4π

v = 8 × 4 × 3.14

v = 100.5 m/s

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Answer:

Explanation:

Kinetic energy is 1/2mv²

where m is the mass of the object

v is the velocity

From the question

m = 200kg

v = 2.7m/s

Kinetic energy is

1/2 × 200 × 2.7²

= 729 Joules

Hope this helps you

Answer:

Explanation:

ya B is right

Answer:

B - Average Kinetic Energy decreases

Explanation:

As the water vapor cools the molecules becomes less excited. Less excitement means less movement, hence less kinetic energy

An offshore wind, option A: blows from land to water, this is why it is also known as land breeze.

The movement of wind from land to a body of water is known as a land breeze or offshore wind. The process goes throughout the night. The land and the ocean both cool as the sun goes down. The land cools down more quickly because it has a lower heat capacity than water.

A low-pressure area develops over the sea as a result of the water's higher temperature than the land. Air rushes from the land to the sea as a result, hence the term "land breeze."

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a)  The direction in which the temperature is increasing most rapidly is the direction of the gradient vector ∇ϕ, which is ((1/√2) * e)i + ((1/√2) * e)j.

b)  The rate of change of temperature with distance at (0, π/3) in the direction i + j√3 is (√2 + √3)/(2√2) * e.

c) The direction of the electric field is opposite to the gradient vector ∇ϕ

Let ϕ = e^x * cos(y), where ϕ represents either temperature or electrostatic potential.

I'll address each part of the problem separately:

(a) To find the direction in which the temperature is increasing most rapidly at (1, -π/4), we need to calculate the gradient of ϕ and evaluate it at that point.

The gradient of ϕ is given by ∇ϕ = (∂ϕ/∂x)i + (∂ϕ/∂y)j, where i and j are unit vectors in the x and y directions, respectively.

Taking partial derivatives of ϕ with respect to x and y, we have:

∂ϕ/∂x = e^x * cos(y)

∂ϕ/∂y = -e^x * sin(y)

Evaluating the partial derivatives at (1, -π/4), we get:

∂ϕ/∂x = e * cos(-π/4) = (1/√2) * e

∂ϕ/∂y = -e * sin(-π/4) = (1/√2) * e

Therefore, the gradient of ϕ at (1, -π/4) is:

∇ϕ = ((1/√2) * e)i + ((1/√2) * e)j

The direction in which the temperature is increasing most rapidly is the direction of the gradient vector ∇ϕ, which is ((1/√2) * e)i + ((1/√2) * e)j. The magnitude of the rate of increase is given by the magnitude of the gradient vector, which is √2 * e.

(b) To find the rate of change of temperature with distance at (0, π/3) in the direction i + j√3, we need to calculate the directional derivative of ϕ in that direction.

The directional derivative is given by the dot product of the gradient vector ∇ϕ and the unit vector in the given direction.

The unit vector in the direction i + j√3 is (1/2)i + (√3/2)j.

Calculating the dot product, we have:

∇ϕ · (1/2)i + (√3/2)j = ((1/2) * (1/√2) * e) + ((√3/2) * (1/√2) * e) = (1/2√2 + √3/2√2) * e = (√2 + √3)/(2√2) * e

So, the rate of change of temperature with distance at (0, π/3) in the direction i + j√3 is (√2 + √3)/(2√2) * e.

(c) To determine the direction and magnitude of the electric field at (0, π), we can use the relationship between the electric field and the gradient of the electrostatic potential.

The electric field E is given by E = -∇ϕ, where ∇ϕ is the gradient of the electrostatic potential.

Using the gradient formula from part (a), we have:

∇ϕ = ((1/√2) * e)i + ((1/√2) * e)j

Therefore, the electric field at (0, π) is:

E = -((1/√2) * e)i - ((1/√2) * e)j

The direction of the electric field is opposite to the gradient vector ∇ϕ,

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This response addresses various math problems related to temperature, electric fields, and contour maps. It explains how to find the direction and magnitude of the temperature change, the rate of change of temperature with distance, the direction and magnitude of the electric field, and whether you are going uphill or downhill on a hill. It also mentions that the given series cannot be evaluated without more information.

(a) To find the direction in which the temperature is increasing most rapidly at (1, -π/4), we need to find the gradient of ϕ at that point. The gradient is a vector that points in the direction of the steepest slope of a function. So, we take the partial derivatives of ϕ with respect to x and y and evaluate them at (1, -π/4). The direction of the gradient vector gives us the direction of the fastest increase in temperature. The magnitude of the rate of increase is the length of the gradient vector.

(b) To find the rate of change of temperature with distance at (0, π/3) in the direction i+j√3, we need to find the directional derivative of ϕ in that direction. The directional derivative measures the rate at which a function changes in the direction of a given vector. It can be found by taking the dot product of the gradient vector and the unit vector in the given direction.

(c) To find the direction and magnitude of the electric field at (0, π), we need to find the gradient of ϕ at that point. The gradient gives us the direction of the electric field, and its magnitude gives us the strength of the field.

(d) To find the magnitude of the electric field at x = -1, any y, we need to find the gradient of ϕ at (x, y) and then evaluate it at x = -1. The magnitude of the gradient vector gives us the magnitude of the electric field.

(a) The contour map for z = 32 - x^2 - 4y^2 with contours z = 32, 19, 12, 7, and 0 is a set of curves that represent points on the surface of the hill with the same height. Each contour corresponds to a different height level.

(b) To determine if you are going uphill or downhill and how fast from the point (3, 2) in the direction i+j, you need to find the gradient of the hill function at (3, 2) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.

(a) To determine if you are going uphill or downhill and how fast from the point (4, -2) in the direction i+j, you need to find the gradient of the hill function at (4, -2) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.

(b) To determine if you are going uphill or downhill and how fast from the point (-3, 1) in the direction 4i+3j, you need to find the gradient of the hill function at (-3, 1) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.

(c) To determine if you are going uphill or downhill and how fast from the point (2, 2) in the direction -3i+j, you need to find the gradient of the hill function at (2, 2) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.

(d) To determine if you are going uphill or downhill and how fast from the point (-4, -1) in the direction 4i-3j, you need to find the gradient of the hill function at (-4, -1) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.

The given series, ∑[infinity](−1)^(n+1)/(n^2+16)/(10n), can be simplified into a summation series. However, it is incomplete and may contain typos or irrelevant parts, so it cannot be evaluated further without additional information or corrections.

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The acceleration of the block is 6.4 m/s².

To calculate the acceleration of the block, we need to consider the forces acting on it.

The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.

The frictional force opposing the motion is 8 N.

The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).

The net force is the difference between the applied force and the frictional force:

40 N - 8 N = 32 N.

Now, we can plug the values into Newton's second law:

32 N = 5 kg × a.

Solving for the acceleration (a), we get

a = 32 N / 5 kg

a = 6.4 m/s².

Therefore, the acceleration of the block is 6.4 m/s².

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The speed of the object after falling 5.0 m would be 5.4 m/s.

We can solve this problem using the law of conservation of energy, which states that the total energy of a system is constant. At the top of the drop, the object has potential energy equal to its mass times the acceleration due to gravity times its height above the ground:

Ep = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the drop.

At any point during the fall, the object has kinetic energy equal to one half its mass times its speed squared:

Ek = (1/2)mv^2

where v is the speed of the object.

Since there is no air resistance, the total energy of the system is conserved, so the initial potential energy at the top of the drop (Ep = mgh) is converted entirely into kinetic energy (Ek = (1/2)mv^2) as the object falls.

When the object has fallen 5.0 m, its potential energy is:

Ep = mgh = (2.0 kg)(9.8 N/kg)(5.0 m) = 98 J

The kinetic energy of the object at this point is equal to its initial potential energy minus the potential energy it still has at that point:

Setting the kinetic energy equation equal to the expression for Ek above and solving for v gives:

Therefore, the object's speed after falling 5.0 m is 5.4 m/s, rounded to 2 significant figures.

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dP/dt = (0.831 - 0.2P) / 100, where P represents pressure (in kilopascals).

This equation represents the rate at which the pressure is changing with the given conditions of temperature and volume.

To find the rate at which the pressure is changing, we need to use partial derivatives. Given the equation PV = 8.31T, we can differentiate both sides of the equation with respect to time t.

Differentiating both sides with respect to time t, we get:

P(dV/dt) + V(dP/dt) = 8.31(dT/dt)

Now, let's substitute the given values:

dT/dt = 0.1 K/s (rate of temperature change)

dV/dt = 0.2 L/s (rate of volume change)

T = 300 K (temperature)

V = 100 L (volume)

Plugging in the values into the equation:

P(0.2) + 100(dP/dt) = 8.31(0.1)

0.2P + 100(dP/dt) = 0.831

Now, we can solve for dP/dt:

100(dP/dt) = 0.831 - 0.2P

dP/dt = (0.831 - 0.2P) / 100

Therefore, the rate at which the pressure is changing when the temperature is 300 K and increasing at a rate of 0.1 K/s, and the volume is 100 L and increasing at a rate of 0.2 L/s is given by:

dP/dt = (0.831 - 0.2P) / 100

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Answer-

A. cubic centimeters.

Hope this helps!

Answer:

A. cubic centimeters.

Explanation:

Volume can be measured in:

A. cubic centimeters = volume

centimeter = length.

square centimeters = area

Answer:

Potential and Kinetic energy

Explanation:

Mark me Brainliest!

Answer:

300 jules

Explanation:

With the discovery of the decametric radio emission, or DAM, in 1955, the first proof of Jupiter's magnetic field's existence was provided.

The largest object in the solar system is Jupiter's magnetosphere. It would appear two to three times as big as the Sun or Moon to observers on Earth if it fluoresced at wavelengths detectable to the human eye. In this illustration, the lines made of gold and copper illustrate the magnetic field structure.

It is thought that the magnetic fields of Saturn and Jupiter may be created by hydrogen conducting electricity deep inside the planets. The planetary layers above may compress hydrogen close to the planet's core so tightly that it turns into an electrical conductor.

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Answer:

he has to be strong enough to lift the barbel so maybe a bit of exercise each day.

Explanation:

Answer:

t = 12s

Explanation:

Given:

v-initial = 0 m/s

x = 360 m

a = 5.0 m/s^2

Solve:

x = (v-initial)t + 1/2(a*t^2)

360 = 0t + 1/2 (5.0t^2)

360 = 2.5 t^2

144 = t^2

t = sqrt(144) = 12

Therefore, it takes 12 seconds.

In basin and range topography, the lowest areas are frequently occupied by a(n)  basin.

Basin and range topography is a geological feature characterized by alternating mountain ranges and elongated valleys or basins. The formation of this topography is attributed to the stretching and faulting of the Earth's crust, which leads to the uplift of mountains and the subsidence of adjacent basins.

The lowest areas in this type of topography are often occupied by basins, which are elongated depressions or low-lying regions. These basins typically collect sediment and water, forming flat or gently sloping landscapes. They can range in size from small valleys to extensive lowland areas.

The basins are important features of the basin and range topography and contribute to the unique landscape and hydrological characteristics of the region.

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Answer:

The term for the region where the north and south poles of atoms in a material line up is a "domain." In magnetic materials, the north and south poles of atoms are called "magnetic dipoles." When the magnetic dipoles in a material line up, they create a region of magnetic field called a "domain." This alignment of magnetic dipoles can produce strong magnetic properties in the material, which is why it is often used in applications such as magnets and motors.

The estimated maximum power output of the heat engine using hot springs with a groundwater temperature of 95 °C and a mass flux of 0.2 kg/s is approximately 0.0128 kW.

To estimate the maximum power output of the heat engine using hot springs, we can utilize the concept of the Carnot cycle, which provides an upper limit for the efficiency of a heat engine.

The Carnot efficiency is given by the formula:

η = 1 - (Tc/Th)

Where η is the efficiency, Tc is the temperature of the cold reservoir (ambient temperature), and Th is the temperature of the hot reservoir (groundwater temperature).

Given:

Tc = 20 °C = 293 K

Th = 95 °C = 368 K

The maximum power output can be calculated using the formula:

P = η * Q

Where P is the power output and Q is the heat transfer rate.

The heat transfer rate can be calculated using the formula:

Q = m * Cp * (Th - Tc)

Given:

m = 0.2 kg/s (mass flux)

Cp = specific heat capacity of water ≈ 4.18 kJ/kg°C

Let's calculate the maximum power output:

Tc = 293 K

Th = 368 K

m = 0.2 kg/s

Cp = 4.18 kJ/kg°C = 4.18 J/g°C = 4.18 * 10⁻³ J/kg°C

Q = m * Cp * (Th - Tc)

  = 0.2 kg/s * 4.18 * 10⁻³ J/kg°C * (368 K - 293 K)

  = 0.2 * 4.18 * 10⁻³ * 75

  = 0.0627 kW

η = 1 - (Tc/Th)

  = 1 - (293/368)

  ≈ 0.204

P = η * Q

  = 0.204 * 0.0627 kW

  ≈ 0.0128 kW

Therefore, the estimated maximum power output of the heat engine using hot springs with a groundwater temperature of 95 °C and a mass flux of 0.2 kg/s is approximately 0.0128 kW.

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Consider a force of magnitude F pulling an object over a surface. The object is moving horizontally, with an angle of between the force and motion direction.

The length of the line AB makes up the force's component in the direction of motion.

What effects does angle have on force?

The component of force perpendicular to the incline reduces as the angle increases, while the component of force parallel to the incline grows. The weight vector's parallel component is what drives the acceleration. As a result, accelerations increase with increasing incline angles.

If we measure the acceleration and the driving force, we can use the formula F = ma to compute the mass of an item moving uniformly in a circle.

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Answer:

c

Explanation:

The car tyre contains air initially at a pressure of 195 kPa after travelling several km the temperature of the air inside a car tyre rises from 30 to 70°C if the tyre is rigid and does not expand then the new pressure inside the tyre would be 220.74 kPa.

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied.

The mathematical expression for the pressure

Pressure = Force /Area

the pressure is expressed by the unit pascal or N /m²

By using the Charles law for gases which states that the volume of the gas remains constant then the pressure of the gas is directly proportional to the temperature.

As given in the problem the tyre is rigid and does not expand this means the volume of the tyre remains constant.

The mathematical expression for Charles's law is as follows

P₁/P₂ = T₁/T₂

First, we have to change the temperature from degree Celcius to the kelvin temperature scale

K = 273 + C

where k is the temperature in kelvin and the C is degrees of Celcius

Initially, the temperature was 30° C

T₁ = 273 + 30

T₁ = 303 K

Then after travelling the temperature of the air inside a car tyre rises from 30 to 70°C

T₂= 273+ 70

T₂ =343 K

The car tyre contains air initially at a pressure of 195 KPa

P₁ = 195 kPa

Lets us take the final pressure of the air would be P₂

By substituting the values in the formula

P₁/P₂ = T₁/T₂

195/P₂ = 303/343

P₂ = 220.74 kPa

Thus, the new pressure inside the tyre would be  220.74 kPa.

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Answer:

Kinetic energy is the energy in moving objects or mass. Examples include mechanical energy , electrical energy etc.

Answer:

Direct proportionality

Explanation:

The graph of variables that are directly proportional such as the temperature and volume of a gas has a graph consisting of a diagonal line that from the lower left of the graph to the upper right of the graph

According to Charles law, the volume of a given mass of gas is directly proportional to its temperature in Kelvin at constant pressure

Charles law can be represented mathematically as V ∝ T

From which we have;

V₁/T₁ = V₂/T₂, therefore, the graph of V to T has a constant slope, ΔV/ΔT.

Answer:

The second option

Explanation:

H everywhere is 20π p A/m in the azimuthal direction, where p is the radial coordinate in cylindrical coordinates.

The integral form of Ampere's Law relates the magnetic field H to the current passing through a closed loop. In cylindrical coordinates, the current density is given by J(r, θ, z) = N·P(r)·uϕ(θ), where N is the number of turns per unit length, P(r) is the volume current density, and uϕ(θ) is the unit vector in the azimuthal direction.

To find H everywhere, we consider a closed loop in the azimuthal direction (ϕ) at a fixed radial distance p. Along this loop, the length element dl is in the azimuthal direction, and the magnetic field H is also in the azimuthal direction.

Applying Ampere's Law, the integral of H·dl over the closed loop equals μ0 times the total current enclosed by the loop. Since the current is uniform and flowing in the azimuthal direction, the total current enclosed is J·2πp, where J is the volume current density and 2πp is the path length along the loop at radial distance p.

Setting up the integral and solving, we have:

H·2πp = μ0·J·2πp

H = μ0·J = μ0·N·P(r) = 20πp A/m.

Therefore, H everywhere in the azimuthal direction is given by H = 20πp A/m.

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