what is the orbital speed for a satellite 3.5 x 10^8m from the center of mars? Mars mass is 6.4 x 10^23 kg

Answer:

The bag of sand

Explanation:

I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.

D. produced a photograph that showed the creation of two particles when a particle of light was destroyed.

In 1933, Irène and Frédéric Joliot-Curie produced a photograph that showed the creation of two particles when a particle of light was destroyed, which was Einstein's prediction in the concept of pair production, which was a process in which two particles are created when a photon is absorbed. This photograph was the first experimental evidence of this process, which was a significant discovery in the field of nuclear physics.

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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Answer:

t= v-u/a

t=80-0/20

t=80/20

t=4 sec

Answer:

The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.

The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.

Explanation:

The density of the small spheres with a diameter of 1.05mm and a terminal velocity of 2.34 cm/s is 42.97m/s³.

Density is a measurement which compares the amount of matter occupied by an object with its volume. An object with much matter in a certain amount of volume has high density. Whereas, an object with a little matter in the same amount of volume has a low density.

We know that density of water,

σ = 1.00 × 10⁻³ kg/m³ and coefficient of viscosity for water, η = 10⁻³ Pa.s

Given,

Terminal speed, v = 2.34 cm/s = 0.0234 m/s

Radius of sphere, r = d/2 = 1.05/2 = 0.525mm = 0.0005m

Using the formula of terminal speed,

v = 2(ρ − σ)gr²/ 9η

0.0234 = 2(ρ - 1.00 × 10⁻³) × 9.8 × 0.0005²/ 9 × 10⁻³

0.0234 = 2(ρ - 1.00 × 10⁻³) × 9.8 × 0.00000025/ 9 × 10⁻³

0.0234 = 2(ρ - 1.00 × 10⁻³) × 0.00000245/ 9 × 10⁻³

0.0234 × 9 × 10⁻³/ 2 ×  0.00000245 = ρ - 1.00 × 10⁻³

0.2106× 10⁻³/ 0.0000049 = ρ - 1.00 × 10⁻³

0.0002106/ 0.0000049 = ρ - 1.00 × 10⁻³

42.97 = ρ - 1.00 × 10⁻³

ρ = 42.97m/s³

Therefore, the density of the small spheres is 42.97m/s³.

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Answer:

The most common oxidation numbers for a given element

Given:

A coil and a magnet

To find:

What to do to induce a current into the coil

Explanation:

When the flux through a coil changes, the current is induced in it. To change the number of flux there should be a relative motion between the coil and the magnet.

Hence, to induce the electric current in a coil you can move a magnet into the center of the coil of the wire.

The significance of a intersection of the red and green curves (B). Consumption becomes greater than supply is the correct option.

The context in which two curves are being studied determines the importance of their junction, regardless of whether they are red and green or any other colour. Here are a few potential meanings:

The intersection point represents the solution or point of similarity between the two functions, if the red and green curves represent mathematical functions or equations. Or, to put it another way, the variables or parameters that make the two functions equal. Problems or equations involving the two functions can be solved by locating the intersection point .

Graphical Analysis: The intersection point on a graph of the red and green curves represents the point at which the two curves cross each other. These ideas could be used to analyse the relationship between the two curves, such as locating crucial spots, pinpointing sites of convergence or divergence, calculating distances or relative locations, etc.

Red and green curves may occasionally have symbolic meanings based on their colours. Red, for instance, may be a symbol of peril, ardor, or heat, whereas green may be a symbol of growth, serenity, or nature. Depending on the situation, the meeting or conflict of these attributes could be represented by the intersection of these curves.

Therefore, the correct option is (B).

What is the significance of the intersection of the red and green curves?

A. Supply becomes greater than consumption

B. Consumption becomes greater than supply

C. Supply and consumption are both zero.

D. Consumption increases but supply remains stable,

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Answer:

F ≈ 0,879 N

Explanation:

First, we calculate the value of the acceleration needed to stop the projectile.

That is:

V = V₀ + a.t

0 = 255 + a . (1,45)

a = - 255 / 1,45

a = -175,86 m/s²

Using the 2° Law of Newton:

∑F = m.a

F = m . a

F = 0,005 . (175,86)

F ≈ 0,879 N

Answer:

E = 0.5N/C

Explanation:

In order to calculate the magnitude of the electric field you use the following formula:

\(E=\frac{F}{q}\)

q: charge = 5.0*10^-4 C

F: force on the charge = 2.5*10^-4N

You replace the values of q and F in the equation for E:

\(E=\frac{2.5*10^{-4}N}{5.0*10^{-4}C}=0.5\frac{N}{C}\)

hence, the magnitude of the electric field at the position of the carge is 0.5N/C

At the location of the test charge, the magnitude will be:

"0.5 N/C".

Whenever charge seems to be available inside any form, an electric property has been linked among each spatial position. This same size and direction are represented either by the quantity of E.

According to the question,

Charge, q = 5.0 × 10⁻⁴ C

Force on the charge, F = 2.5 × 10⁻⁴ N

We know the relation of the magnitude of electric field be

→ E = \(\frac{F}{q}\)

By substituting the values, we get

     = \(\frac{2.5\times 10^{-4}}{5.0\times 10^{-4}}\)

     = 0.5 N/C

Thus the approach above is correct.

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Answer:

The limitations of sending information using electromagnetic waves is that when the electromagnetic waves move outward in all directions, wave transmitters need to be focused to transmit their signals to a single specified location.

Answer:

Both charges are of the same sign (positive or negative) and with a value of 3.73 ηc.

Explanation:

Coulomb's Law

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\(\displaystyle F=k\frac{q_1q_2}{d^2}\)

Where:

\(k=9\cdot 10^9\ N.m^2/c^2\)

q1, q2 = the objects' charge

d= The distance between the objects

We know both charges are identical, i.e. q1=q2=q. Since the force is repulsive, both charges are positive or negative.

We also are given the force between them:

\(F=2\cdot 10^{-6}\ N\)

And also the distance

d=25 cm = 0.25 m

Substituting all into the formula:

\(\displaystyle 2\cdot 10^{-6}=9\cdot 10^9\frac{q.q}{0.25^2}\)

The product of \(q.q=q^2\). Operating:

\(\displaystyle 2\cdot 10^{-6}=9\cdot 10^9\frac{q^2}{0.0625}\)

Operating:

\(\displaystyle 0.0625\cdot 2\cdot 10^{-6}=9\cdot 10^9\cdot q^2\)

Solving for q:

\(\displaystyle q^2=\frac{0.0625\cdot 2\cdot 10^{-6}}{9\cdot 10^9}\)

\(q^2=1.39\cdot 10^{-17}\)

\(q=\sqrt{1.39\cdot 10^{-17}}=3.73\cdot 10^{-9}\ c= 3.73\ \eta c\)

Both charges are of the same sign (positive or negative) and with a value of 3.73 ηc.

Answer:

Explanation:

Potential energy depends on the height of the object above the ground. As the height decreases, the potential energy decreases. Looking at line A, the energy is decreasing as the distance is increasing. Thus, the energy represented by line A is

A. Potential energy

Answer:

Just gonna take this at free points and yes you are right but I am confused on what you wanted us to do

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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Answer:

8.37 Joules

Explanation:

The amount of energy that a substance, such as animal tissue or rubber can take and yet return to its original condition is known as resilience. When we stress such a substance and then let it restore to its previous state, we are referring to the substance to maintain its elastic area of the stress-strain curve.

From the given information:

the resilence is 0.93

The amount of work done during stretching of the tendon = 9.00 J

Thus,

the work done when relaxing = 0.93 × 9.00 J

= 8.37 Joules

A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

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The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Answer:

because

Explanation:

starts with question then explored through the mind.

Answer:

The average induced emf in the loop is 0.3 V

Explanation:

Given:

d = 22 cm

Magnetic field  is  B = 1.5 T

Change in time  Δt = 0.20 sec.

Radius of loop  = r = d/2 = 11 x \(10^{-2}\) m

According to the faraday's law,  Induced emf is given by   e = - (ΔФ / Δt)

where Ф = magnetic flux

Ф = BAcos0   (in this occasion, Ф=0)

where area A = pi * r²

note that we have to neglect negative sign due to its lenz law...so

       B * pi * r

e = ----------------

          Δt

       1.5 ( 3.1416) 11 x \(10^{-2}\) )²

e =  ------------------------------------

                        0.20

e = 0.3 V

Therefore, the average induced emf in the loop is 0.3 V

Answer:

From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body. Escape Velocity of Earth= 11.2 km/s. This was the derivation of the escape velocity of earth or any other planet.

Explanation:

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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The weight must be 288N placed on the end of the spring when it is 2m from the ground.

If an object is lifted, work is done against gravitational force. The object gains energy.

Given is a spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground. The final height of weight above the ground, h =2m

Using Hooke's law, expressed as

Force, F = k (x₂-x₁).

Put the values, we get

F = 48 (8-2)

F = 288 N

This force applied on the spring is equal to the weight placed on the spring.

Weight W= 288N.

Thus, the weight must be 288N.

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This sculptural representation of Buddha is an example of the Mathura school of thought.

The sandstone from which Seated Buddha was carved was preferred by the artist workshops of Mathura, a city in northern India.

This sculpture is a figure of a man sitting with his legs crossed, feet facing up. One hand is raised beside the shoulder, palm out.

Thus, this sculptural representation of Buddha is an example of the Mathura school of thought.

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Answer:

b.

Mathura

Explanation:

Beats can be defined as the periodic fluctuations in the frequency of sound waves. That is option D

Sound waves are those waves that are produced by the vibration of an object whose energy is usually propagated through a medium.

When two sound waves of different frequencies meets, a periodic variation that occurs is called beats.

Therefore, Beats can be defined as the periodic fluctuations in the frequency of sound waves.

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The net electric force on charge q2 is 28.7 N.

The net electric force on charge q2 is calculated by applying Coulomb's law of electrostatic force.

F(net) = F(12) + F(23)

The force on q2 due to charge 1 is calculated as;

F(12) = -(9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.1²)

F(12) = 25.2 N

The force on q2 due to charge 3 is calculated as;

F(23) = (9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.15²)

F(23) = 3.5 N

The net force on q2 is calculated as;

F(net) = 25.2 N + 3.5 N = 28.7 N

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Answer:

Depends on what are you looking at. All of the following are valid definitions, it just depends on which way you are analizing the problem.

From a kinematics point of view:

Acceleration is, by definition, is a vector quantity that measures the rate of change of the rate of change in position (add brackets if it helps visualizing the idea). This leads to the following different definitions - which are more like means of calculating it

From a dinamics point of view

Acceleration is the effect of a force applied to a body, and measures the ratio of the force applied to a body of mass m and the mass itself (which is another formulation of Newton second law):

\(a = \frac Fm\)

Acceleration is the rate of change of velocity

To define acceleration, We need to know more about motion.

Motion: This can be defined as the change in position of a body from one point to another. When an object accelerates, it undergoes motion.

Definition

Acceleration can be defined as the rate of change of velocity. The S.I unit of acceleration is meter-per-squared seconds. (m/s²)

The formula of acceleration is

⇒ Where:

Hence, Acceleration is the rate of change of velocity

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Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

Given:

As we know,

→ \(K.E = \frac{1}{2} mv^2\)

By substituting the values, we get

          \(= \frac{1}{2}\times 762\times (7.5)^2\)

          \(= \frac{1}{2}\times 7.62\times 56.25\)

          \(= \frac{1}{2}\times 428.625\)

          \(= 214.32 \ J\)

Thus the response above is appropriate.

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W = F.d

300 = 100 . d

d = 3 m