The order of magnitude wavelength for visible light is 0.5 micrometers. Option C.
Visible light encompasses wavelengths ranging from approximately 400 to 700 nanometers (nm), which is equivalent to 0.38 to 0.75 micrometers (µm). The order of magnitude wavelength for visible light is in the range of micrometers. More specifically, the range is approximately 400 to 700 nanometers, with violet light having the shortest wavelength and red light having the longest wavelength.
It is important to note that the order of magnitude refers to the scale of measurement, which in this case is the size of the wavelength, and not the specific numerical value. Understanding the order of magnitude can help us make quick estimations and comparisons in scientific and mathematical calculations. Therefore, option C, 0.5 micrometers, is the correct answer.
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A spring with a spring constant of 0.52 N/m is stretched 3.2 m. What was the force?
The force applied to stretched the spring 3.2 m, given that the spring has a spring constant of 0.52 N/m is 1.664 N
How do I determine the force?Hooke's law gives a relationship betwee force, extension and spring constant according to the following formula:
Force (F) = Spring constant (K) × extension (e)
F = Ke
With the above formula, we can determine the force applied to the spring as illustrated below:
Spring constant of spring (K) = 0.52 N/mExtension of spring (e) = 3.2 metersForce applied (F) = ?Force (F) = Spring constant (K) × extension (e)
Force applied (F) = 0.52 × 3.2
Force applied (F) = 1.664 N
Thus, we can conclude from the above calculation that the force is 1.664 N
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A soccer ball takes 30 seconds to roll 15 meters. calculate the average speed ot the ball using distance and tome measurements?
Answer:
average speed = 0.5 m/s
Explanation:
average speed = (distance) / (elapsed time)
Given time elapsed = 30 seconds and distance = 15 meters
average speed = 15 meters / 30 seconds = 0.5 meters/second = 0.5 m/s
A baseball is thrown at an angle of 29° relative to the ground at a speed of 29.8 m/s. The ball is caught 76.7687 m from the thrower.
The
acceleration due to gravity is
9.81 m/S'
2
How long is it in the air?
Answer in units of s.
Answer:
2.94 sec
Explanation:
Horizontal component of velocity = 29.8 cos 29°
Rate * time = distance
29.8 cos 29 * t = 76.7687 m
t = 2.94 sec
Why would there be different considerations for regular lenses vs sunglasses and what would be the preference?
the magnitude of a vector can be different in different coordinate systems.T/F
A vector cannot have a distinct direction in one coordinate system from another. Even if a vector's magnitude is not zero, it can still have a component value of zero.
What distinguishes coordinates from vector components?The unit vector of an axis and its scalar component along this axis are combined to create the vector component. The product of a vector's component vectors is a vector. When the coordinates of a vector's origin are deducted from its end point coordinates, the result is a difference in coordinates known as a scalar component.
Why does the vector not depend on the coordinate system?As opposed to a tuple of coordinates that describe a point, it is a vector. A coordinate system is fundamentally nothing more than a selected reference in the space we're working with. There are no changes to the object's or the space's properties if a different reference is used to describe its objects.
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Question 1-1
Which of the following scenarios provides a clear example of a situation with gravitational potential energy?
O Apleasure boat floating in a river.
Water in a river at the top of a waterfall.
A railroad train speeding across flat terrain.
A large spring stretched across a flat tabletop.
The following circumstance is a good illustration of a gravitational potential energy problem, Water in a river at the top of a waterfall.
Due to its height above the earth in this situation, the water at the waterfall's peak contains potential energy. The potential energy of the water is transformed into kinetic energy as it cascades down the waterfall. The potential energy in the water increases with the height of the water at the waterfall's peak.
The equation: may be used to determine this potential energy.
PE = mgh
where m is the water's mass, g is its gravitational acceleration, and h is the water's height above a reference point (usually the ground).
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when the evaporation rate equals the condensation rate, the space above the liquid is
When the evaporation rate of a liquid is equal to its condensation rate, the space above the liquid is in a state of dynamic equilibrium.
This means that while molecules are constantly evaporating from the liquid surface and entering the space above, an equal number of molecules are condensing and returning to the liquid phase. The molecules in the space above the liquid are in constant motion, colliding with each other and the liquid surface.
This results in a stable vapor pressure, which is the pressure exerted by the gas molecules in the space above the liquid. The magnitude of the vapor pressure depends on the temperature and the properties of the liquid.
When the temperature increases, the evaporation rate increases, and the vapor pressure also increases until a new equilibrium is reached. Similarly, a decrease in temperature leads to a decrease in both the evaporation and condensation rates, resulting in a lower vapor pressure. Overall, the space above the liquid in equilibrium is characterized by a constant vapor pressure and a balance between the evaporation and condensation rates.
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Which two statements are true for reversible reactions that reach dynamic equilibrium?
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
What is dynamic equilibrium?The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.
The chemical reaction is a method for creating novel chemicals with unique features.
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
Therefore, the correct answer will be an option (C).
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You are asked to solve a nonlinear equation f(x) = 0 on the interval [1, 5] using Newton's method. Tick ALL of the following that are true: This iterative method requires one starting point. This iterative method requires two starting points. This iterative method requires evaluation of derivatives of f. This iterative method does not require evaluation of derivatives of f. This iterative method requires the starting point(s) to be close to a simple root. This iterative method does not require the starting point(s) to be close to a simple root. If f = C([1,5]) and ƒ(1)ƒ(5) <0, then, with the starting point x₁ = 3, this iterative method converges linearly with asymptotic constant 3 = 0.5. If f(x) = 0 can be expressed as a = g(x), where g = C¹([1,5]) and there exists K = (0, 1) such that g'(x)| ≤ K for all x = (1,5), then this iterative method converges linearly with asymptotic constant
1, 3, 5, and 7 statements are true to solve a nonlinear equation using Newton's method.
The true statements are:
This iterative method needs one starting point.This iterative method needs the evaluation of derivatives of f.This iterative method needs the starting point(s) to be close to a simple root.If f(x) = 0 can be represented as a = g(x), where g = C¹([1,5]) and there exists K = (0, 1) such that g'(x)| ≤ K for all x = (1,5), then this iterative method combines linearly with asymptotic constant.While other statements are false. Therefore, 1, 3, 5, and 7 statements are correct.
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move 5meters east then move 5meters west
The distance and the displacement of an object are 10 m and 0 m.
The complete question is in the attachment. Distance is a scalar quantity that does not pay attention to direction. The total distance traveled is the sum of all the distances traveled by an object.
Traveled 5 m to eastDisplacement is a vector quantity that is concerned with both magnitude and direction. The magnitude of the displacement is the result of two vectors.
R² = d₁² + d₂² + 2 × d₁ × d₂ × cos θ
where θ is the angle between two vectors.
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(I NEED THIS ANSWERED NOW PLEASE)
Zeros that follow non-zero numbers and are also to the right of a decimal point are ________ significant.
fill in the blank please.
Answer:
Zeros that follow non-zero numbers and are also to the right of a decimal point are significant.
Explanation:
For example:
0.300 has 3 significant figures.
5.400 has 4 significant figures.
Which would be heavier—A ball of lead with a diameter of 2.00 cm or a cylinder of iron with a diameter of 3.00 cm and height of 8.00 cm.
Explanation:
i think a ball of lead with a diameter of 2.00 cm heavier
relative to sphere at the speed of sphere Z is _ m/s
We are given that a sphere Z moves with a relative speed of 1 m/s with respect to sphere X which moves at 5 m/s. Let's draw the velocity vectors of the spheres:
Where:
\(\begin{gathered} v_x=\text{ velocity of sphere x} \\ v_z=\text{ velocity of sphere z} \end{gathered}\)From the relative velocity equation we have:
\(v_z=v_r+v_x\)Where:
\(v_r=\text{ velocity of z relative to x}\)Since we are given the relative velocity we can plug in the values to get the velocity of "z":
\(\begin{gathered} v_z=1\frac{m}{s}+5\frac{m}{s} \\ \\ v_z=6\frac{m}{s}_{} \end{gathered}\)Now, we do the same but now using the sphere Y:
Now, we use the relative velocity equation for these velocities:
\(v_z=v_r+v_y\)In this case, we have that:
\(v_r=\text{ velocity of z with respect to y}\)Now, we subtract the velocity of "y" from both sides:
\(v_z-v_y=v_r\)Substituting the values:
\(6\frac{m}{s}-2\frac{m}{s}=v_r\)Solving the operations:
\(4\frac{m}{s}=v_r\)Therefore, the velocity of "Z" relative to "Y" is 4 m/s.
What is the coefficient of kinetic friction if a car going at 20 m/s stops in 50 m?
The car that slows down to 20 m/s stopped 50 meters away. Assume a slowness is always present. The friction coefficients for static and dynamic surfaces are 0.5 and 0.03, respectively and the coefficient of kinetic friction is 0.203.
What function do coefficients serve?an amount or signal that increases a quantity or signal
Three is employed to measure some attribute as both the exponent to x in the expression 3x.
The coefficient could be adverse?In addition to other sorts of numbers, coefficients can always be fractions, whole numbers, positive, negative, irrational, and more. Deleterious coefficients include those with negative values, to put it simply. Any negative integer, such as -8 in the formula -8z or -11 in the expression -11xy, can be a negative coefficient.
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F = m x g is the formula of
The weight of an object is the force of gravity on the object and may be defined as the mass times the acceleration of gravity, w = mg. Where W = weight in N. m = mass in kg and g = gravitational field strength in N/kg. g = 10 N/kg.
What happens to the temperature of a substance while it is changing state?
A. It increases first and then decreases.
B. It decreases first and then remains constant.
C. It varies randomly.
D. It remains constant.
Answer:
During a phase change, the temperature will remain constant. Obviously all the heat is used in phase transformation. So the correct answer should be D. Forgive me if I'm wrong but I hope this helps!
The temperature of a substance remains constant while it is changing state. Thus, the correct option is D.
What is the relation between state and temperature of substance?Temperature has a direct effect on whether a substance exists in states as a solid, liquid, or gaseous substance. Substances can change their phase often because of a temperature change of the substance. At very low temperature conditions, most of the substances are solid, as the temperature of the substance keeps on increasing, then they become liquid and at very higher temperatures still, they become gaseous substances.
The temperature of a substance remains constant while it is changing its state.
Therefore, the correct option is D.
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three capacitors are connected to an emf as shown with c1 < c2 < c3. which relation is true of the charges q1, q2 and q3 on the capacitors?
Based on the diagram, the capacitors are connected in series. In a series connection, the same charge flows through each capacitor. Therefore, the relation of the charges q1, q2, and q3 can be determined as follows:
q1 = q2 = q3
In a series connection, the charges on the capacitors are equal.
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The body can get water from milk, juices, fruits, and vegetables.
Answer: yes it can but not enough to stay hydrated and keep your body going but you cant get water from milk lol
Explanation: hope this helpes
Answer:
Yes This would be True hope this helps
Explanation:
the most important controllable factor affecting drying shrinkage is the amount of ____________________ per unit volume of concrete. a. water b. fine aggregate c. coarse aggregate d. cement
The most important controllable factor affecting drying shrinkage is the amount of water per unit volume of concrete. The correct option is a.
In this context, water is the key term to focus on. Drying shrinkage occurs when the excess water evaporates from the concrete mixture during the curing process, causing the concrete to contract. By controlling the water-to-cement ratio in the concrete mix, we can significantly reduce drying shrinkage.
A lower water-to-cement ratio leads to less water available for evaporation, thus reducing shrinkage. Other factors, such as fine aggregate, coarse aggregate, and cement, also contribute to the overall concrete properties, but the water content is the most crucial factor that can be controlled to minimize drying shrinkage. The correct option is a.
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an image of the lateral skull taken at 68 kvp, 20 mas and is repeated. if the kvp is increased to 78 kvp, what should be the new mas?
The new mAs should be a half of 20mAs, which is 10mAs.
How does kVp and mAs affect image quality?The first experiment demonstrated that, when the film density is held constant, the resolution and image contrast % decrease with increasing kVp and increase with increasing mAs, respectively.In the second portion of the experiment, several mAs were selected, and many kVps were employed for each mAs. The radiographs were read by five observers.The second experiment demonstrated that the correlation between kVp and resolution and between kVp and the picture contrast % were the same as in the first experiment when the film density was not maintained constant. The relationship between mAs and resolution and mAs and the percentage of picture contrast was, however, hardly significant.Learn more about kVp and mAs refer to :
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need help Match the description to the correct part of the electromagnetic spectrum.
Waves produced by an object that radiates heat are infrared rays and radio waves have the longest wavelength.
What are electromagnetic waves?The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.
Waves produced by an object that radiates heat are infrared rays.Waves that have the longest wavelength and lowest frequency/energy are radio waves.Rays that occur naturally in sunlight; most are absorbed by the ozone layer; can cause cancer are ultraviolet rays.Have the shortest wavelength and highest energy; produced by stars and nuclear explosions are gamma rays.The part of the electromagnetic spectrum that can be detected by human eyes; allows us to see is the visible light spectrumThus, this is the description of the correct part of the electromagnetic waves.
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a 220 g , 34.0-cm-diameter turntable rotates on frictionless bearings at 59.0 rpm . a 25.0 g block sits at the center of the turntable. a compressed spring shoots the block radically outward along a frictionless groove in the surface of the turntable.
The turntable's rotation angular velocity when the block reaches the outer edge is 5.578 rads⁻¹
The inertial moment of the turntable block = \(\frac{1}{2} mr^{2}\)
The inertial moment of the block = \(mr^{2}\)
According to the law of conservation of angular momentum, the total angular momentum of the system when the block is seated at the center and when the block is at the outside edge must be the same since no external torque operates on the system.
Additionally,
ω= 2\(\pi\)f, where f represents rpm, can be used to determine
ω= 2π×63/60 = 6.597
So, I*ω = I' * ω'
\([\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0)^{2} ]6.597= [\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0.5)^{2} ]\)*ω'
ω' = 5.578 rads⁻¹
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A balloon is inflated from negligible initial volume to 300 cm3. How much work is done by the balloon on the surroundings if the pressure opposing expansion is 1 bar
The work done by the balloon on the surroundings, when inflated from negligible initial volume to 300 cm³ against 1 bar of opposing pressure, is 30 Joules.
To calculate the work done by the balloon on the surroundings during expansion, we can use the formula:
Work = Pressure * Change in Volume
The initial volume is negligible, so we can consider it as zero. The final volume is given as 300 cm³. The change in volume is then 300 cm³. The pressure opposing expansion is 1 bar. However, it is important to convert the pressure to the appropriate unit before calculating the work. 1 bar is equal to 100,000 Pascals (Pa).
Now we can calculate the work done:
Work = Pressure * Change in Volume = (100,000 Pa) * (300 cm³)
However, we need to convert the volume from cm³ to m³ to maintain consistency with the SI unit of pressure (Pascals).
1 cm³ is equal to 1 × 10^(-6) m³.
Therefore, the work done by the balloon on the surroundings can be calculated as:
Work = (100,000 Pa) * (300 × 10^(-6) m³)
Simplifying the equation gives us the final result: Work = 30 J
Therefore, the work done by the balloon on the surroundings during expansion is 30 Joules.
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Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by transmission lines. A typical high-voltage transmission line is 20 m off the ground and carries a current of 200 a.
Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by transmission lines.
A typical high-voltage transmission line is 20 m off the ground and carries a current of 200 A.
The concern stems from the fact that these transmission lines generate magnetic fields due to the flow of electric current.
Magnetic fields are a part of the electromagnetic spectrum, and prolonged exposure to high levels of magnetic fields may potentially have an impact on human health.
However, it is important to note that the evidence supporting this concern is currently weak and inconclusive.
To understand the potential risk, let's analyze the situation of a typical high-voltage transmission line. It is situated 20 meters above the ground and carries a current of 200 amperes.
As the current flows through the line, it generates a magnetic field that decreases in strength as the distance from the line increases.
At 20 meters or more away from the transmission line, the magnetic field strength is relatively low and generally considered safe.
In conclusion, while there have been concerns over the potential health effects of magnetic fields generated by transmission lines, the current evidence is weak,
and more research is needed to confirm any potential risks. As long as people maintain a safe distance from high-voltage transmission lines, the likelihood of experiencing negative health effects is low.
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Someone please help me!
Answer:
a
Explanation:
If a car has an initial velocity of 20 m/s and accelerates at 2.0 m/s² for 100 m, what is its final velocity?
Answer:
28.28 ms-1
Explanation:
v² = u² + 2as
v² = 20² + 2× 2×100
v² = 800
v = 28.28 ms-1
Se tiene un péndulo cuyo frecuencia de oscilación es de 0.4 Hz. Cual sera la frecuencia de oscilacion de otro péndulo cuya longitud es el triple del anterior
Answer:
f = 0.365 Hz
Explanation:
The angular velocity of a simple pendulum is
w = \(\sqrt{g/L}\)
angular velocity and frequency are related
w = 2π f
we substitute
2π f = \(\sqrt{g/L}\)
Let's find the initial length of the pendulum
L = \(\frac{g}{4\pi^2 } \ f_o\)
L₀ = \(\frac{9.8}{4 \pi ^2} \ 0.4\)
L₀ = 0.6206 m
Indicates that the length of the chord triples
L = 3 L₀
L = 3 0.6206
L = 1.8618 m
let's find the frequency
f = \(\frac{1}{2\pi } \ \sqrt{\frac{9.8}{1.8618} }\)
f = 0.365 Hz
the breakdown of rocks by chemical action of air and water is called
Answer:
Chemical weathering
Explanation:
This changes the molecular structure of rocks and soil. For instance, carbon dioxide from the air or soil sometimes combines with water in a process called carbonation. This produces a weak acid, called carbonic acid, that can dissolve rock.
In which dimensions do we find the components of acceleration (tangent and normal vector)?
Let's say, I am skiing first uphill and then downhill, then up a ramp, land, and finally make a turn of 90 degrees to the right and stop with an acceleration of \(\vec {a}\), which is variable in all cases. In which directions would the normal and tangential components exist, and how will they change for all the cases, considering my acceleration in a 3D plane? Please explain with a graph if you could
The acceleration of an object can be split into two components: the tangential and normal components. The tangential component points along the direction of motion and is responsible for changing the speed of the object. The normal component is perpendicular to the direction of motion and is responsible for changing the direction of motion.
In your skiing example, the direction of your acceleration will change as you move uphill, downhill, up a ramp, and make a turn. Therefore, the tangential and normal components of your acceleration will also change in direction and magnitude.
As you ski uphill, your acceleration will be pointing in the opposite direction of your motion, resulting in a negative tangential acceleration. Since your motion is mostly vertical, your normal acceleration will be pointing upwards.
As you ski downhill, your acceleration will be in the same direction as your motion, resulting in a positive tangential acceleration. Your normal acceleration will still be pointing upwards.
When you go up a ramp, your acceleration will be a combination of tangential and normal components. The tangential component will be pointing upwards to match your velocity, and the normal component will be pointing perpendicular to the ramp.
When you land, your acceleration will be mostly normal, as you decelerate your downward motion and start to move horizontally.
Finally, when you make a turn, your tangential acceleration will be pointing in the direction of the turn, while your normal acceleration will be perpendicular to the turn.
Overall, the direction and magnitude of the tangential and normal components of your acceleration will depend on the direction and magnitude of your velocity and the curvature of your path.
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Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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