Car A m= 2000kg
v=20 km/h
Car B m= 2000kg
v= 20km/h what is the location after impact
Mass of car, M=2000kg
Velocity, V=72× 5/18 =20ms¹
Apply kinematic equation of motion
v² -u² = as
0 − 20² =2a×20
a=−10ms^-2
Breaking force, F=ma=2000×10=20 kN
Apply first kinematic equation
v = u +at
\( t= \frac{v - u}{a} = \frac{0 - 20}{ - 10} = 2sec\\\)
Problem
Position The figure shows a motorcyclist traveling east along a straight
road. After passing point B, the cyclist continues to travel at an average
velocity of 18 m/s east and arrives at point C2.8 s later. What is the
position of point ?
Answer:
s = 50.4 m
Hence, the point C is 50.4 m towards east from point B
Explanation:
Since, the motorcyclist travels at a constant speed in straight line towards east after point B. Therefore, we can use the following equation in this case:
s = vt
where,
s = distance covered = position of point C = ?
v = uniform speed of motorcyclist = 18 m/s
t = time interval = 2.8 s
Therefore,
s = (18 m/s)(2.8 s)
s = 50.4 m
Hence, the point C is 50.4 m towards east from point B
A car accelerates uniformly in a straight line from rest at the rate of 3.7 m/s2
What is the speed of the car after it has traveled 63 m? Answer in units of m/s.
How long does it take the car to travel 63 m? Answer in units of s
Explanation:
Using equations of motion :
(A) we know that,
u = 0
a = 3.7 m/s^2
S = 63
\( {v}^{2} = {u}^{2} + 2as\)
\(v = \sqrt{0 + 2 \times 3.7 \times 63} = 21.6 \: m{s}^{ - 1} \)
(B)
v = u + at
21.6 = 0 + 3.7 * t
t (time to reach 63 m) = 5.83 seconds
calculate the maximum force, in newtons, exerted by the blood on an aneurysm (a ballooning in a major artery), given that the effective area of the aneurysm is 18.5 cm2.
36.99N
Given
Maximum blood pressure P = 150 mm
Effective area of the aneurysm a = 18.5 cm2.
Expression for the maximum force exerted by blood on an aneurysm is,
f =P * a = (150 mm Hg* (133.322 N/m²/ 1 mmHg)) * ( 18.5 cm² * (1 m² /10000cm²)) = 36.99N
The pressure is computed as the ratio of acting force on an object and the surface area of the object where the force is directed. The pressure is usually measured in terms of Pascal and blood pressure in mm of Hg.
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list some methods to reduce friction to conserve energy
Answer:
Here are the five main ways to reduce friction:
Using LubricantsDefinition: A lubricant is a substance that forms a thin layer between
the two surfaces in contact.
Using Soap SolutionsUsing Ball BearingsPolishing SurfacesImproving designsExplanation:
Answer:
Make surfaces smooth by grinding.
Lubrication.
Streamlined body.
Reduce pressure or weight on the object.
Reduce contact between surfaces by electrostatic magnetic levitation etc.
Use rolling friction instead of sliding friction.
Use fluid friction instead of the dry friction.
Explanation:
(A) A small mass of 0.60 kg is rotated at the end of a string in a horizontal circle of radius 1.20 m. The string will break if the tension exceeds 60 N. What is the GREATEST frequency of revolution that is possible? (B) the same mass of 0.60 kg is now rotated at the end of another string at a constant speed, v, in a vertical circle of radius 1.20 m. the minimum tension in the string is 2.1N (I) state and explain where the tension in the string is maximum and minimum (ii) find the speed of the mass
(a) The maximum frequency of revolution is 4.0 rad/s.
b (i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path.
b (ii) The speed of the mass can be found using the minimum tension in the string is 2 m/s.
What is the maximum frequency of revolution?
The maximum frequency of revolution is given by the maximum tension in the string, which is 60 N.
T = mv² / r
where;
m is the mass of the object (0.60 kg), v is its linear speed, r is the radius of the circle (1.20 m).The linear speed is given by:
v = 2πrf
where;
f is the frequency of revolutionf = √T / (mr²))
f = √(60 / (0.60 x 1.20²))
f = 4.0 rad/s
(i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path. This is because the tension provides the centripetal force that keeps the object moving in a circular path.
(ii) The speed of the mass can be found using the minimum tension in the string, which is 2.1 N:
T = mv² / r = 2.1 N
Rearranging and solving for v, we get:
v = √(Tr / m)
v = √(2.1 x 1.20 / 0.60)
v = 2.0 m/s
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what are the microscopic structural subunits of the liver?
The microscopic structural subunits of the liver are liver lobules.
Liver lobules are functional units that make up the liver. Each lobule consists of hepatocytes, sinusoids, Kupffer cells, and bile canaliculi. Hepatocytes are the main functional cells of the liver responsible for metabolic functions such as detoxification, protein synthesis, and bile production. Sinusoids are blood vessels that receive blood from the hepatic artery and portal vein, allowing exchange of substances with hepatocytes. Kupffer cells are specialized macrophages involved in immune responses. Bile canaliculi are small ducts that collect bile produced by hepatocytes and transport it towards larger bile ducts. These components work together to maintain liver function and perform essential metabolic and immune-related processes.
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An object is at rest. There are several forces acting on the object, but the net force is zero. If all the
forces acting on the object were to suddenly double in size, would the object start moving? Why or why not?
Answer:
no
Explanation:
because the heaver an object the harder it is to move s the force will not be able to move it
What name did marie curie give to the process by which materials give off rays capable of fogging photographic plates?
The study of radioactivity by Marie Curie marked a significant turning point in the realm of physics and had a significant influence on scientific knowledge. Now let's get into the specifics.
"Radioactivity" is the term Marie Curie coined to describe the phenomenon whereby materials emit radiation that can fog photographic plates. During her uranium investigation in 1896, she made this discovery. This game-changing discovery opened the door for more research into and comprehension of radioactivity, which resulted in important developments in the field of nuclear physics.
Marie Curie's research on radioactivity served as a springboard for additional nuclear physics research and has profound ramifications for other fields of science and medicine. It resulted in improvements in our knowledge of atomic structure, the creation of radiation therapy for the treatment of cancer, and the eventual exploitation of nuclear energy.
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A student shakes a rope such that 20 complete vibrations are made in 4.00 seconds. Determine the vibrational frequency of the rope, along with the corresponding unit.
Answer:
The vibrational frequency of the rope is 5 Hz.
Explanation:
Given;
number of complete oscillation of the rope, n = 20
time taken to make the oscillations, t = 4.00 s
The vibrational frequency of the rope is calculated as follows;
\(Frequency = \frac{number \ of \ complete \ vibrations}{time \ taken} \\\\Frequency = \frac{20 }{4 \ s} \\\\Frequency = 5 \ Hz\)
Therefore, the vibrational frequency of the rope is 5 Hz.
What is coefficient of friction formula?
The formula for calculating the coefficient of friction is given by:
μ = F / N.
The coefficient of friction formula is a mathematical equation used to calculate the amount of frictional force that exists between two surfaces in contact with each other.
The coefficient of friction is a dimensionless quantity that represents the ratio of the frictional force between two surfaces to the normal force pressing them together.
The formula for calculating the coefficient of friction is given by:
μ = F / N
where μ is the coefficient of friction, F is the frictional force acting between the two surfaces, and N is the normal force pressing the surfaces together.
The coefficient of friction can have values ranging from 0 to 1. A value of 0 indicates no friction between the surfaces, while a value of 1 indicates maximum friction. The coefficient of friction is an important parameter in many engineering and physics applications, such as in designing brakes for vehicles and calculating the force required to move objects over different surfaces.
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the li group had 202,000 shares of common stock outstanding at january 1, 2024. the following activities affected common shares during the year. there are no potential common shares outstanding.
The 2018 Earning per share , the 2019 Earning per share and the amount it will take the 2018 Earning per share be presented in the 2019 comparative financial statements are all shown on the attached picture.
What is Earning Per Share?Earning per share can be described as the earning available after distribution of dividend divided by the number of shares outstanding at the end of the year. This will be reported through net income.
In conclusion, The 2018 EPS - $400,000 / 400,000 = $1.00
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Complete question is :
The Li Group had 202,000 shares of common stock outstanding at January 1, 2018. The following activities affected common shares during the year. There are no potential common shares outstanding
2018
Feb .28 Purchased 6,000 shares of treasury stock.
Oct 31 Sold the treasury shares purchased on February 28
Nov 30 Issued 24,000 new shares.
Dec 31 Net income for 2018 is $400,000
2019
Jan. 15 Declared and issued a 2-for-1 stock split
Dec .31 Net income for 2019 is $400,000.
1. Determine the 2018 EPS
2. Determine the 2019 EPS
3. At what amount will the 2018 EPS be presented in the 2019 comparative financial statements?
When you add a battery in series; what happens to the voltage? O it is cut in half 0 it remains the same Dit is divided among the bulbs it doubles
Let's determine what happens when you add batteries in series.
There are two major ways to wire batteries together which are:
Series and arallel.
A circuit can be said to be in series when there is the same curent flowing through all the components in the circuit.
In a series circuit, when you add a battery, the voltage increases while the supply voltage is divided among the components in the circuit.
Therefore, when you add batteries in series, the voltage is divided among the bulbs equally.
ANSWER:
It is divided among the bulbs.
Most metals have...
a. Atoms that are spread out, and low specific heats
b. Atoms that are close, and low specific heats
c. Atoms that are spread out, and high specific heats
d. Atoms that are close, and high specific heats
A car has a weight of 24000N which is distributed equally across all four wheels. Each wheel
has a spring of spring constant 400 N/cm.
a) Determine the force on the spring for each wheel.
b) Calculate the compression (x) of each spring when the car rests on the ground.
(a) The force on the spring for each wheel of the given car is 6,000 N.
(b) The compression of each spring when the car rest on the ground is 15 cm.
The given parameters;
weight of the car, W = 24,000 Nspring constant, k = 400 N/cmThe force on the spring for each wheel of the given car is calculated as follows;
\(F = F_1 = F_2 = F_3 = F_4 = \frac{W}{4} \\\\F= \frac{24,000}{4} \\\\F = 6,000 \ N\)
The compression of each spring when the car rest on the ground is calculated as;
\(F= kx\\\\x = \frac{F}{k} \\\\x = \frac{6,000}{400} \\\\x = 15 \ cm\)
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what is the speed of a 38-g bold eagle if it has a momentum magnitude of 0.45 kg•m/s ?
The speed of a 38-gram bald eagle with a momentum magnitude of 0.45 kg m/s is approximately 11.84 m/s. This can be calculated using the momentum formula.
The momentum formula is given by:
momentum = mass × speed
First, we need to convert the mass of the bald eagle from grams to kilograms since the momentum is given in kg•m/s. To do this, we divide the mass in grams by 1000:
mass (kg) = 38 grams ÷ 1000 = 0.038 kg
Now, we can rearrange the momentum formula to solve for the speed:
speed = momentum ÷ mass
Substitute the given values:
speed = 0.45 kg•m/s ÷ 0.038 kg
speed ≈ 11.84 m/s
Therefore, the speed of a 38-gram bald eagle with a momentum magnitude of 0.45 kg•m/s is approximately 11.84 m/s.
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Monochromatic light of wavelength lambda, such as light from a laser, is directed through two narrow parallel slits that are a distance d apart. There is a viewing screen a very long distance R away from the slits that is used to observe the interference pattern that emerges from the light shining through the slits. The distance that light travels from one slit to the screen is r1 and the distance that light travels from the other slit to the screen is r2. The central bright fringe of the interference pattern results due to a path difference, r1 – r2, of zero. What path difference is required to produce the first order bright fringe that is adjacent to the central bright fringe?
Answer:
When r1 – r2 equal the wavelength of the monochromatic light
Explanation:
This is because to observe a bright fringe a constructive interference pattern of path difference, r1 – r2 = mλ is observed, where m is an integer and λ = wavelength of monochromatic light.
For bright fringes and thus constructive interference, r1 – r2 must be integral multiples of the wavelength, λ. When r1 – r2 , we have the central bright fringe and thus m = 0.
The first order bright fringe which is adjacent to the central bright fringe is obtained when m = 1,
So r1 – r2 = 1 × λ
r1 – r2 = λ
Thus, the path difference required to produce the first order bright fringe that is adjacent to the central bright fringe is when r1 – r2 = λ, the wavelength of the monochromatic light.
Which phenomenon do solar panels rely on to produce electricity from sunlight?
Answer:
When the sun shines onto a solar panel, energy from the sunlight is absorbed by the PV cells in the panel. This energy creates electrical charges that move in response to an internal electrical field in the cell, causing electricity to flow.
Answer:
When the sun shines onto a solar panel, energy from the sunlight is absorbed by the PV cells in the panel. This energy creates electrical charges that move in response to an internal electrical field in the cell, causing electricity to flow.
Explanation:
Stefan’s Law of radiation states that the radiation energy of a body is proportional to the fourth
power of the absolute temperature T (in the Kelvin scale) of a body. The rate of change of this
energy in a surrounding medium of absolute temperature M is thus
dT/dt = σ*(M^4−T^4)
where σ is a positive constant when T > M. Find the general (implicit) solution of Stefan’s
equation assuming M to be a constant.
The general (implicit) solution to Stefan's equation is given by:
ln((M^2 + T^2)/(M^2 - T^2)) = 2σt + 2C, where C is the constant of integration.
To solve Stefan's equation, we can separate the variables and integrate both sides. Let's proceed with the steps:
First, rewrite the equation as follows:
(1/(M^4 - T^4)) * dT/dt = σ
Now, we integrate both sides with respect to t:
∫(1/(M^4 - T^4)) * dT = ∫σ * dt
The left side of the equation requires integration by partial fractions. The integral can be expressed as:
1/(M^4 - T^4) = A/(M^2 + T^2) + B/(M^2 - T^2)
To determine the constants A and B, we can use the method of partial fractions. Multiply through by (M^4 - T^4) and then equate the numerators:
1 = A(M^2 - T^2) + B(M^2 + T^2)
Expanding and rearranging, we have:
1 = (A + B)M^2 + (A - B)T^2
Equating the coefficients of the powers of T, we get:
A + B = 0 (coefficient of T^2)
A - B = 1 (constant term)
Solving these equations simultaneously, we find A = 1/2 and B = -1/2.
Substituting the partial fraction decomposition back into the integral, we have:
∫(1/(M^4 - T^4)) * dT = ∫(1/2)*((1/(M^2 + T^2)) - (1/(M^2 - T^2))) * dT
Integrating both sides, we obtain:
(1/2) * (ln(M^2 + T^2) - ln(M^2 - T^2)) = σt + C
where C is the constant of integration.
Finally, solving for T, we can write the general (implicit) solution to Stefan's equation as:
ln((M^2 + T^2)/(M^2 - T^2)) = 2σt + 2C
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it is moving day and you are in a hurry! you drop a fridge from a height of 75.0m out a window. a stool is thrown down from the same height 0.091s later if both objects hit the ground at the same time what was the initial
Answer:
Explanation:
Given:
H = 75 m
Δt = 0.091 s
g =9.81 m/s²
_________
V₀ - ?
Assume that the stool fell freely, then the time of its fall:
H = g·t²/2
t = √ (2·H / g) = √ (2*75 / 9.81) ≈ 3.910 s
The refrigerator was thrown down with initial speed and fell:
t₁ = t - Δt = 3.910 - 0.091 ≈ 3.82 s
Find the initial chip of the refrigerator:
H = V₀·t₁ + g·t₁²/2
V₀·t₁ = H - g·t₁²/2
V₀ =H / t₁ - g·t₁ / 2
V₀ = 75 / 3.82 - 9.81·3.82 / 2 ≈ 0.90 m/s
So, at first, the stool is simply released from the hands, and the refrigerator is thrown down with the initial speed 0.90 m/s
you weigh 150 pounds, and your friend is dragging you on a sled up a hill by pulling on a rope with 50 n of force. you are moving in a straight line and at constant speed. your acceleration is:_____
The acceleration of the person being dragged on the sled is zero. The acceleration due to gravity is approximately 9.8 m/s², the mass of the person is approximately 68.04 kg (150 pounds / 2.2046).
The person being dragged on the sled is moving at a constant speed, which means there is no change in velocity. According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The person's weight of 150 pounds can be converted to mass using the formula: mass = weight / acceleration due to gravity.
Since the person is moving at a constant speed, the net force acting on them must be zero. The force of 50 N exerted by the friend pulling the rope is balanced by the force of friction opposing the motion.
Therefore, the acceleration of the person being dragged on the sled is zero. The force of friction in this case is equal in magnitude and opposite in direction to the force applied by the friend. This balance of forces allows the person to maintain a constant speed while being dragged up the hill.
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4 Points: What is the angular diameter (in radians) of a crater
on the Moon if the physical diameter is 1.2 × 101
meters? Assume that the distance to the Moon is 3.84 ×
108 meters?
The angular diameter of the crater on the moon is approximately 1.10 x 10^-7 radians.
The angular diameter (in radians) of a crater on the moon if the physical diameter is 1.2 x 10¹ meters, with an assumption that the distance to the moon is 3.84 x 10⁸ meters can be calculated by making use of the following equation:
`θ=2arctan(d/2D)`
Where:
θ = angular diameter of the crater
d = physical diameter of the crater
D = distance to the moon
Substituting the given values into the equation above:
`θ=2arctan(1.2x10^1/2(3.84x10^8))`
The expression above can be solved using a calculator:
θ ≈ 1.10 x 10^-7 radians
Therefore, the angular diameter of the crater on the moon is approximately 1.10 x 10^-7 radians.
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WHATS THE ANSWER HELP!!
5m I think,maybe, not a 100% sure die
Answer:
5m i think
Explanation:
WHATS THE ANSWER HELP!!
what does the odometer of an automobile measure
Answer:
Used for measuring the distance traveled by a vehicle, such as a bicycle or car.
Explanation:
Answer:
it measures distance travelled by the vehicle
A student has two magnets of equal strength. She places one on each side of the ramp. She releases a steel ball down the ramp. The student repeats the procedure with both magnets on the same side of the ramp. Predict the path of the ball in each trial.
Your Prediction:
What Happens:
Ans: A student has two magnets of equal strength. She places one on each side of a ramp. She releases a steel ball down the ramp. The student repeats her procedure with both.
Explanation:
When the height of the cylinder increased by a factor of 5, from 100 m to 500 m, what happened to the cylinder’s gravitational potential energy?
Answer: It increased by a factor of 5
Explanation:
Gravitational potential energy is given by the following formula:
Calculate how much work Wf in J the farmer does on the bucket of water (via the rope) to raise it to ground level.
Work done by the farmer to lift the bucket of water to ground level is 484.5 J
Work done by a force is equal to the scalar product of the force applied and displacement. If d displacement happens on applying a force F, then work done, W by the force is
W = F. d
Given: Depth of well, d = 9.5 m
Force to pull the bucket of water upwards, F1 = 51 N
Work done = F1 × d = 51 × 9.5 = 484.5 J
Therefore, work done by the farmer to lift the bucket of water to ground level is 484.5 J
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The complete question is :
A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well that is hy = 9.5 m deep. The farmer uses force F1 = 51 N to pull the bucket of water directly upwards. The total mass of the bucket of water is mb = 3.7kg. Calculate how much work Wf in J the farmer does on the bucket of water (via the rope) to raise it to ground level.
An astronaut has a mass of 82.0 kilograms. What will her gravitational force be on the Moon? The gravitational attraction on the Moon is 1.60 m/s2.
51.3 N
95.6 N
102 N
131 N
Answer:
131 N
Explanation:
F = 82.0 kg x 1.60 m/s^2 = 131.2 N
A transformer is connected to 120 volts. find the current if the resistance is 4800-ohms.
Answer:
Explanation:
Formula
E = I * R Substitute the givens into the formula
Givens
E = 120 volts
I = ?
R = 4800 0hms
Solution
Ohms law is a 3 letter equation that relates volts ohms (resistance) * current (in amperes)
E = i * R
120 V = I * 4800 ohms Divide both sides by 4800
120 V/4800 = I * 4800/4800 Divide
0.025 amps = I
Answer
I = 0.025 amps
Rank the following by their power output, from highest to lowest.1. Boeing 777 jet engine at full throttle (75 Megawatts) 2. Central Pennsylvania gasoline station in problem 1 (38 Megawatts)3. Electrical power production of the country of Togo in West Africa (10 MW)4. Diesel railroad locomotive (3 MW)
The ranking of the following by their power output, from highest to lowest is as follows:
Boeing 777 jet engine at full throttle (75 MW).Central Pennsylvania gasoline station in problem 1 (38 MW).Electrical power production of the country of Togo in West Africa (10 MW).Diesel railroad locomotive (3 MW).What is Power?In physics, power may be defined as the amount of energy that is considerably transferred or converted per unit of time. In the International System of Units, the unit of power is the watt.
Early locomotives and railcars with internal combustion engines ran on kerosene and gasoline. While internal combustion engines can operate well across a limited range of power, low-power gasoline engines may be coupled to mechanical gears. Therefore, Boeing 777 jet engine operating at full power (75 Megawatts) represents the highest power output.
Therefore, the ranking of the following by their power output, from highest to lowest is well mentioned above.
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