what is the solution to -3/8x-11=4

The correct triangle similarity is ΔKLM is similar to ΔUTS. The correst postulate is SSS.

Similar triangles are those triangles which has the same shape but different size.

The length of sides are proportional in similar triangles.

Given are two triangles.

Triangles KLM and STU.

Three side lengths of each triangle are given.

If two triangles are similar, then the sides are proportional.

Identify which pair of sides are proportional.

KL / UT = 90 / 50 = 9/5

LM / TS = 63 / 35 = 9/5

MK / SU = 45 / 25 = 9/5

So, comparing, the vertices corresponding to K, L, M are U, T, S.

ΔKLM is similar to ΔUTS.

SSS similarity postulate defines that, if three sides of a triangle are proportional to three r=sides of another triangle, then the triangles are similar.

So the postulate is SSS.

Hence the triangles ΔKLM is similar to ΔUTS.

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The biconditional statement is: A rectangle is a parallelogram with four right angles if and only if a parallelogram has four right angles.

The term "if and only if" or biconditional statement refers to a compound statement composed of two conditional statements connected by a logical operator.

This definition is commonly utilized to describe the characteristics of a rectangle when it comes  to its correlation with a parallelogram. The opening section of the biconditional statement is comprised of a conditional statement indicating that a rectangle is defined as a parallelogram featuring four right angles.

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Write this definition as a biconditional statement.

A rectangle is a parallelogram with four right angles.

Answer:

a) 1.8 × 10^-12 cm³ or 1.8 × 10^-12 cubic meters

b) 7.1 × 10^-6 mm² or 7.1 × 10^-6 square millimeters

Step-by-step explanation:

a) We are assuming that the shape of the bacteria is a sphere.

Hence, Volume of the Sphere(Bacteria) = 4/3 × π × r³

Diameter = 1.5 μm

Radius = Diameter/2 = 1.5μm/2

= 0.75μm

We are told that the volume should be in cubic centimeters

Converting 0.75μm to centimeters

1 μm = 1 × 10^-4 cm

0.75 μm =

Cross Multiply

= 0.75 μm × 1 × 10^-4 cm/ 1 μm

= 0.000075cm

Volume of the Sphere(Bacteria) = 4/3 × π × r³

= 4/3 × π × (0.000075)³

= 1.767145867 × 10^-12 cm³

Approximately as 2 significant figures = 1.8 × 10^-12 cm³

b) The formula for the Surface area of a Sphere = 4πr²

Diameter = 1.5 μm

Radius = Diameter/2 = 1.5μm/2

= 0.75μm

We are told that the surface area should be in square millimeters

Converting 0.75μm to millimeters

1 μm = 0.001 mm

0.75 μm =

Cross Multiply

= 0.75 μm ×0.001mm/ 1 μm

= 0.00075mm

Surface Area of a Sphere

= 4 × π × r²

= 4 × π × 0.00075²

= 7.06858 ×10^-6 mm²

Approximately to 2 significant figures

= 7.1 × 10^-6 mm²

Answer:

9 /15 and 18/30

Step-by-step explanation:

9/15 is literally just 18/30 simplified

Answer:

9*2        18

-------- = ------

15*2       30

Polynomial: 6x^3 + 12x^2 - 18x

Form 1: 6(x^3 + 2x^2 - 3x)

Explanation: This form was created by factoring out the GCF of 6 from each term in the polynomial.

Form 2: 6x(x^2 + 2x - 3)

Explanation: This form was created by factoring out the GCF of 6x from each term in the polynomial.

In both forms, the GCF of 6 allows us to factor out common factors and simplify the polynomial expression while preserving its original meaning.

To create a factorable polynomial with a greatest common factor (GCF) of 6, we can start by considering the common factors of the terms. Let's construct a polynomial:

Polynomial: 6x^3 + 12x^2 - 18x

To rewrite this polynomial in two other equivalent forms, we can factor out the GCF from each term and simplify.

Form 1: 6(x^3 + 2x^2 - 3x)

In this form, we factored out the GCF of 6 from each term: 6x^3/6 = x^3, 12x^2/6 = 2x^2, and -18x/6 = -3x.

Form 2: 6x(x^2 + 2x - 3)

In this form, we factored out the GCF of 6x from each term: 6x^3/6x = x^2, 12x^2/6x = 2x, and -18x/6x = -3.

We created each form by identifying the common factors in the polynomial and factoring them out. This process allows us to rewrite the polynomial in equivalent forms that emphasize different aspects.

In Form 1, we factored out the GCF of 6, leaving the remaining polynomial inside the parentheses. This form highlights the fact that the polynomial can be written as the product of the GCF and the remaining terms.

In Form 2, we factored out the GCF of 6x, again leaving the remaining polynomial inside the parentheses. This form emphasizes the fact that the polynomial can be written as the product of the GCF and another factor, in this case, x.

By rewriting the polynomial in these two forms, we have created equivalent expressions that emphasize the presence of the GCF and demonstrate the polynomial's factorability.

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Answer:

x < 3 1/4

See picture below.

Step-by-step explanation:

1/2 x - 3 < -1 3/8

1/2 x < -11/8 + 24/8

1/2 x < 13/8

x < 13/4

x < 3 1/4

Answer:

The data set has an even number of values

The median is not one of the values in the data set

The median is 113 centimeters

Step-by-step explanation:

There are 14 values

The middle of the data would be 113 but there is no dot there

Having 7 dots on either side with 113 being the inbetween.

Answer:

exact form : 2√3

decimal form : 3.46410161… or 3.46

hope this helps you!

Answer:

The value of the function is \(\sqrt{12}\). Rounded to the nearest hundredth, the answer is 3.46

Step-by-step explanation:

We are given the value of x, so we simply have to evaluate the function:

\(f(x)=\sqrt{x+4}\)

Substitute 8

\(f(8)=\sqrt{8+4}\)

Add in the radical

\(\sqrt{12}\)

The value of the function is sqrt(12).

Rounded to the nearest hundredth: \(3.46\)

\(\\ \sf\longmapsto 3x-9y> 27\)

\(\\ \sf\longmapsto x-3y>9---(1)\)

And

\(\\ \sf\longmapsto y-3\leqslant -4/3(x+7)\)

\(\\ \sf\longmapsto 3y-9\leqslant -4x+28\)

\(\\ \sf\longmapsto 3y+4x\leqslant 37--(2)\)

Graph attached

Answer:

46 boxes

Step-by-step explanation:

1012 / 22 = 46

We are given:

f(x) = 3x + 8

g(x) = -x³

__________________________________________________________

The Concept:

We have to find the values of f(g(3)), which means that we have to apply the function g() on 3 and apply the function f() on the value we get.

Finding f(g(3)):

Finding g(3):

g(x) = -x³

g(3) = -(3)³

g(3) = -27

Finding f(g(3)):

f(x) = 3x + 8

f(g(3)) = 3(g(3)) + 8

f(g(3)) = 3(-27) + 8

f(g(3)) = -81 + 8

f(g(3)) = -73

Hence, f(g(3)) = -73

Answer: 22 minutes

Step-by-step explanation: m + 2m + m + 7 = 4m + 7

4m + 7 = 50

4m = 44

m = 11

2m = 11 x 2 = 22 minutes

Answer:

11x-2

Step-by-step explanation:

(3x2 - 4x + 6) + (7x - 2) This is the breakdown. (6 4x + 6)= 4x. + (7x-2) = 11x-2

Answer:

\((12\frac{1}{3} *2)+(10\frac{3}{4} *2)\\\\=(\frac{12(3)+1}{3} *2)+(\frac{10(4)+3}{4} *2)\\\\=\frac{37*2}{3} +\frac{43*2}{4} \\\\=\frac{74}{3} +\frac{86}{4} \\\\=\frac{74(4)+86(3)}{3*4} \\\\=\frac{296+258}{12} \\\\=\frac{554}{12}\)

Answer:

Step-by-step explanation:

o What proportion of normal distribution corresponds to z-scores < z = 1.00? o What is the probability of selecting a z-score less than z = 1.00? (A). (B). (C).

The sequence that represents the arithmetic sequence will be {-6, 1, 8, 15, 22,...}. Then the correct option is A.

Arithmetic succession or arithmetic sequential is a numerical series in which the difference between subsequent terms is uniform.

Let's check all the options, then we have

A.  {-6, 1, 8, 15, 22,...}, then the common difference is given as,

d = 1 - (-6) = 8 - 1 =

d = 7 =  7

B.  {64, 32, 16, 8, 4,...}, then the common difference is given as,

d = 32 - 64 = 16 - 32
d = -32 ≠ - 16

C.  {1, 2, 4, 8, 16,...}, then the common difference is given as,

d = 1 - 2 = 2 - 4

d = - 1 ≠ - 2

D.  {1, 3, 6, 10, 15,...}, then the common difference is given as,

d = 1 - 3 = 3 - 6

d = - 2 ≠ - 3

The sequence that represents the arithmetic sequence will be {-6, 1, 8, 15, 22,...}. Then the correct option is A.

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The reasonable domain for the function is (b) x > 0

From the question, we have the following parameters that can be used in our computation:

The function f(x) = 75x + 100

Where x is the number of hours

f(x) is the total cost.

In this case, the number of hours cannot be negative or 0

This means that the values of x in the function would be x > 0

These values of x are the domain

So, the reasonable domain for the function os (b) x > 0

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Students were asked to simplify the expression using trigonometric identities:

 A.  student A is correct; student B was confused by the division

 B.  3: cos²(θ)/(sin(θ)csc(θ)); 4: cos²(θ)

Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions.

There are several distinctive trigonometric identities that relate a triangle's side length and angle. Only the right-angle triangle is consistent with the trigonometric identities.

The six trigonometric ratios serve as the foundation for all trigonometric identities. Sine, cosine, tangent, cosecant, secant, and cotangent are some of their names.

Each student correctly made use of the trigonometric identities

cosec(θ) = 1/sin(θ)

1 -sin²(θ) = cos²(θ)

A.

Student A's work is correct.

Student B apparently got confused by the two denominators in Step 2, and incorrectly replaced them with their quotient instead of their product.

The transition from Step 2 can look like:

\(\frac{(\frac{1-sin^2\theta}{sin\theta} )}{cosec\theta} =\frac{1-sin^2\theta}{sin\theta} .\frac{1}{cosec\theta} =\frac{cos^2\theta}{(sin\theta)(cosec\theta)}\)

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Complete question:

Students were asked to simplify the expression the quantity cosecant theta minus sine theta end quantity over cosecant period Two students' work is given. (In image below)

Part A: Which student simplified the expression incorrectly? Explain the errors that were made or the formulas that were misused. (5 points)

Part B: Complete the student's solution correctly, beginning with the location of the error. (5 points)

Answer:

The approximate user base of the social media site 10 months from now would be approximately 52,374.

Step-by-step explanation:

To calculate the approximate user base of the social media site 10 months from now, considering a 4% increase per month, we can use the following steps:

1. Calculate the monthly growth factor: 1 + (4% / 100) = 1 + 0.04 = 1.04

2. Apply the growth factor to the current user base for each month:

  Month 1: 35,930 * 1.04 = 37,387.2 (approx.)

  Month 2: 37,387.2 * 1.04 = 38,868.49 (approx.)

  ...

  Month 10: Previous Month * 1.04

By repeating this calculation for each month, we can determine the approximate user base 10 months from now.

Month 1: 37,387.2

Month 2: 38,868.49

Month 3: 40,391.33

Month 4: 41,957.61

Month 5: 43,569.34

Month 6: 45,228.24

Month 7: 46,936.32

Month 8: 48,695.44

Month 9: 50,507.45

Month 10: 52,374.40 (approx.)

Therefore, the approximate user base of the social media site 10 months from now would be approximately 52,374.

Answer:

c

Step-by-step explanation:

both axes! PLS GIVE BRAINLIEST

Kimberly had 2 times as many marshmallows as Chris. After eating 15 each, Kimberly had 3 times as many marshmallows as Chris. Kimberly had 60 marshmallows at first.

Generally, Let's call the number of marshmallows that Kimberly had at first X.

We know that Kimberly had 2 times as many marshmallows as Chris at first, so Chris had X/2 marshmallows.

After eating 15 each, Kimberly had X - 15 marshmallows, and Chris had X/2 - 15 marshmallows.

We also know that Kimberly had 3 times as many marshmallows as Chris after eating 15 each, so

(X - 15) = 3 * (X/2 - 15).

(X - 15) - 3 * (X/2 - 15) = 0

Then, we can simplify the left side of the equation:

X - 15 - 3 * X/2 + 45 = 0

Combining like terms, we get:

-3 * X/2 + X - 15 + 45 = 0

Simplifying further:

-X/2 =-30

X = 60

Therefore, Kimberly had 60 marshmallows at first.

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The solution is, the selection can be made in 593775ways

Combination has to do with selection of r objects from a total number of n objects and this can be done in nCr ways. Generally,

nCr = n!/(n-r)!r!

Since the math teacher has to select 6 students from a class of 30, this can be done in 30C6 number of ways to have;

30C6 = 30!/(30-6)!6!

30C6 = 30!/24!6!

30C6 = 30×29×28×27×26×25×24!/24!×6×5×4×3×2

30C6 = 30×29×28×27×26×25/6×5×4×3×2

30C6 = 427,518,000/720

30C6 = 593775ways

This means, the selection can be made in 593775ways.

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Solution :

Given data :

20.1     33.5     21.7      58.4     23.2     110.8     30.9

24.0    74.8     60.0

n = 10

Range : Arranging from lowest to highest.

20.1,   21.7,   23.2,    24.0,   30.9,    33.5,    58.4,    60.0,    74.8,   110.8

Range = low highest value - lowest value

           = 110.8 - 20.1

           = 90.7

Mean = \($\frac{\sum x}{n}$\)

         \($=\frac{20.1+21.7+23.2+24.0+30.9+33.5+58.4+60.0+74.8+110.8}{10}$\)

          \($=\frac{457.4}{10}$\)

         \($=45.74$\)

Sample standard deviation :

\($S=\sqrt{\frac{1}{n-1}\sum(x-\mu)^2}$\)

\($S=\sqrt{\frac{1}{10-1}(20.1-45.74)^2+(21.7-45.74)^2+(23.2-45.74)^2+(24.0-45.74)^2+(30.9-45)^2}$\)  

      \(\sqrt{(33.5-45.74)^2+(58.4-45.74)^2+(60.0-45.74)^2+(74.8-45.74)^2+(110.8-45.74)^2}\)

\($S=\sqrt{\frac{1}{9}(657.4+577.9+508.0+472.6+220.2+149.8+160.2+203.3+844.4+4232.8)}$\)\($S=\sqrt{\frac{1}{9}(8026.96)}$\)

\($S=\sqrt{891.88}$\)

S = 29.8644

Variance = \(S^2\)

               \(=(29.8644)^2\)

               = 891.8823

The variable which is always positive will be a, b, c, d, p, and q. The constant that lies between 0 to 1 will be 'b'. And the two constants that are definitely equal will be 'a' and 'c'.

Let 'a' is the leading coefficient and 'b' is the factor.

The exponent is given as,

y = a(b)ˣ

Some points regarding the exponent function:

The variable which is always positive will be a, b, c, d, p, and q. The constant that lies between 0 to 1 will be 'b'. And the two constants that are definitely equal will be 'a' and 'c'.

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Answer:

To my calculations, I think its the first one, 4+2=2+4

I hope this helps! ^^

Apologizes if you get it wrong-

Step-by-step explanation:

Step-by-step explanation:

CFB reads as twenty five degrees

complementary angle  will add to it to sum 90 degrees  = sixty five degrees

   angle CFD is sixty five degrees

Answer:

5 times as many

BRAINLIEST, please!

Step-by-step explanation:

I'd need more information about how many students there are at one of the schools. For example, if there are 200 students at Park Elementary, then there are 1000 at Lane High School since 200 x 5 = 1000. 1000 - 200 is 800, so there would be 800 more students at Lane High.

Answer:

15 °C

Step-by-step explanation:

°C = (°F - 32) * (5/9)

Given that the initial temperature was 77 °F and it dropped by 10 °C, we can calculate the final temperature.

Initial temperature: 77 °F

Converting to Celsius:

°C = (77 - 32) * (5/9)

°C ≈ 25

The temperature dropped by 10 °C, so the final temperature is:

Final temperature = Initial temperature - Temperature drop

Final temperature ≈ 25 - 10 = 15 °C

Therefore, the temperature after the storm was approximately 15 °C.

We see here that new thousand is actually liken to be the result in thousand that is gotten after carrying out an operation.

A thousand is a number that denotes the sum of 1,000 units or ten hundreds.

The word "thousand" is frequently used in daily speech to denote a significant but limited amount, such as a thousand money, a thousand individuals, or a thousand pages. Alternatively, it can be used as a round number to denote an approximation, as in "a thousand times" or "a thousand and one nights."

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The histogram that displays the data in the table correctly is C. Histogram C.

Look at the data in the table and look for the number of photocopies that are located between 800 and 899. There are 3 of these.

The number located between 900 and 999 are 5 in number including 915, 919, 923, 950, and 989. The number located between 1,000 and 1, 099 is 8 photocopies.

The histogram that shows this is Histogram C.

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