Answer: They can be represented in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Step-by-step explanation:
what is the area under the standard normal curve between + 1 standard deviations and +2.5 standard deviation
The approximate probability of getting a z-score between +1 standard deviation and +2.5 standard deviations in a standard normal distribution is 0.1525.
What is the process to find the area under the standard normal curve between +1 standard deviation and +2.5 standard deviations?To find the area under the standard normal curve between +1 standard deviation and +2.5 standard deviations, we can use a standard normal distribution table or calculator. Here are the steps:
Find the area to the right of +1 standard deviation using the standard normal distribution table or calculator.Therefore, the area under the standard normal curve between +1 standard deviation and +2.5 standard deviations is approximately 0.1525.
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What am I supposed to do? Is it subtract 180 from 56?
hey
please help with question 2.3
Q.2.3
Write the pseudocode for
the following scenario:
manager at a rood store wants to Keep track or the amount (in
Rands or sales
of food and the amount of VAT (15
The pseudocode for the given scenario can be defined as follows:
Step 1: BeginProgram;
Step 2: Declare item1, item2, item3, total_amount, vat as integer variables.S
tep 3: Write "Enter amount of sales for item1:" and take input from the user as item1.
Step 4: Write "Enter amount of sales for item2:" and take input from the user as item2.
Step 5: Write "Enter amount of sales for item3:" and take input from the user as item3.
Step 6: Set total_amount as the sum of item1, item2 and item3.
Step 7: Write "Total amount is:", total_amount.
Step 8: Set vat as (total_amount * 15)/100.
Step 9: Write "VAT is:", vat.
Step 10: EndProgram.
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Based on the information in the diagram, what is the area of AMNP ?
125
100
075
0105
i need to find the slope and the value of A B
Answer:
the slope is 2 and a=8 b=6
Step-by-step explanation:
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Presley has to clean her 40-gallon fish tank. Her first step is to drain the tank. Using a hose and a
siphon, she finds that she can drain 16 gallons of water per hour.
Presley writes the equation 40 - 16x = 0, where x is the number of hours, to determine how many
hours it will take to drain the tank.
The next step Presley wrote to solve the equation is shown here:
40 = 16x
Which property did she use to get to this step?
a.) addition property of equality
b.) multiplication property of equality
c.) distributive property of equality
d.) combining like terms
Answer: The answer is A.addition property of equality
Hope I helped
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EASY POINTS WILL GIVE BRAINLIST 2 BEST ANSWER
12-x=15+3x
explain
Answer:
Step-by-step explanation:
Answer: x=-3/4
Step-by-step explanation:
12-x=15+3x
12-x+x=15+3x+x
12=15+4x
12-15=15-15+4x ==> isolate the variable x.
-3=4x
4x/4=-3/4
x=-3/4
Emily has 2 cups. Amilia has 26 cups. Amilia has how many times as many cups as Emily?
Answer:
13
Step-by-step explanation:
how many days could a 60kg deer survive without food at -20 degrees - has 5kg of fat
18 days
The survival time of a 60kg deer without food at -20 degrees Celsius depends on various factors, including its age, sex, and physical condition. However, assuming the deer is healthy and has 5kg of fat, it could potentially survive for around 30 to 50 days without food.
The exact survival time can vary depending on several factors, such as the deer's level of physical activity, environmental conditions, and how much energy it is expending to stay warm in the cold temperature. Additionally, if the deer is able to find sources of water, this can also increase its chances of survival.
It's important to note that this is just an estimate and that the actual survival time may vary. If the deer is injured or sick, its chances of survival may be reduced, and it may not be able to survive as long without food.
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Complete Question
How many days could a 60kg deer survive without food at -20 degrees Celsius if it has 5kg of fat?
min 8x₁ + 6x₂ subject to
a. 4x₁ + 2x₂ ≥ 20
b. −6x₁ + 4x₂ ≤ 12
c. x₁ + x₂ ≥ 6
d. x₁ + x₂ ≥ 0
The minimum value of the objective function subject to the given constraints is 48 and it occurs at (6,0).
The given problem is:
min 8x₁ + 6x₂ subject to4x₁ + 2x₂ ≥ 20−6x₁ + 4x₂ ≤ 12x₁ + x₂ ≥ 6x₁ + x₂ ≥ 0
The feasible region is as follows:
Firstly, plot the following lines:4x₁ + 2x₂ = 20-6x₁ + 4x₂ = 12x₁ + x₂ = 6x₁ + x₂ = 0On plotting, the following graph is obtained:
Now, let's check each option one by one:
a. 4x₁ + 2x₂ ≥ 20
The feasible region is the region above the line 4x₁ + 2x₂ = 20.
b. −6x₁ + 4x₂ ≤ 12
The feasible region is the region below the line −6x₁ + 4x₂ = 12.c. x₁ + x₂ ≥ 6
The feasible region is the region above the line x₁ + x₂ = 6.d. x₁ + x₂ ≥ 0
The feasible region is the region above the x-axis.
Now, check the point of intersection of the lines.
They are:(10,0),(2,4),(6,0)The point (2,4) is not in the feasible region as it lies outside it.
Therefore, we reject this point.
The other two points, (10,0) and (6,0) are in the feasible region.
Now, check the values of the objective function at these two points.
Objective function value at (10,0): 80
Objective function value at (6,0): 48
Therefore, the minimum value of the objective function subject to the given constraints is 48 and it occurs at (6,0).
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Suppose p(A|B) = 0.7, P(A|BC) = 0.3, and p(A) = 0.5- What is p(B) (write it up to first decimal place)?_____
p(B) = 0.5 up to the first decimal place.
We can use Bayes' theorem to find p(B) given the conditional probabilities provided:
\(p(A|B) = 0.7, p(A|BC) = 0.3, and p(A) = 0.5\)
First, we can use the law of total probability to find p(A|B) and p(A|BC):
\(p(A) = p(A|B)p(B) + p(A|BC)p(B^c)\)
where \(B^c\) denotes the complement of B, i.e., not B. Substituting the given values, we get:
\(0.5 = 0.7p(B) + 0.3p(B^c)\)
We can rearrange this equation to solve for p(B):
\(0.2 = 0.4p(B) - 0.3p(B^c)\\0.5 = p(B) + p(B^c)\)
Substituting \(p(B^c) = 1 - p(B)\), we get:
\(0.5 = p(B) + (1 - p(B))\)
Solving for p(B), we get:
\(p(B) = 0.5 - p(B^c) = 0.5 - (1 - p(B)) = 2p(B) - 0.5\\0.5 = p(B)\)
Therefore, p(B) = 0.5 up to the first decimal place.
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Which inequality is true is x=4?
-25x>100
-25x _< 100
25x < 100
25x _< 100
Step-by-step explanation:
One inequality could be x > 3. So when x = 4 this is true because 4 is greater than 3.
Answer:
-25x≥100
Step-by-step explanation:
-100≥100-100-≥100100≤100100-≤100
a song played for 2 minutes 58 seconds. how many seconds did the song play? responses 60 s 60 s 118 s 118 s 178 st 178 s 258 s 258 s
The song played for 2 minutes 58 seconds or 178 seconds.
Therefore, the answer is 178 seconds.
Explanation:
Time is measured in minutes, seconds, and sometimes hours. For instance, when we want to know how long it took for a trip to a particular location, we can measure the time in hours and minutes.
We may also measure how long it took someone to finish a task in minutes and seconds.
To convert minutes to seconds, we use the formula:
1 minute = 60 seconds.
If a song played for 2 minutes 58 seconds,
we can convert it into seconds by multiplying 2 by 60, then adding 58 to get the total seconds played.
That is:
2 minutes * 60 seconds/minute
= 120 seconds58 seconds
Therefore, the total seconds played is 120 seconds + 58 seconds = 178 seconds.
Therefore, the answer is 178 seconds.
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In the Super Bowl by how many points does the winning team out score the losers here are the winning margins for the first 48 Super Bowl games
The winning margins range from 1 point to 45 points, with an average margin of about 14 points.
Here are the winning margins for the first 48 Super Bowl games:
Game Winning Margin
I 25
II 19
III 9
IV 16
V 3
VI 11
VII 7
VIII 24
IX 9
X 4
XI 18
XII 23
XIII 4
XIV 3
XV 3
XVI 5
XVII 1
XVIII 29
XIX 22
XX 36
XXI 19
XXII 32
XXIII 4
XXIV 45
XXV 1
XXVI 13
XXVII 35
XXVIII 17
XXIX 23
XXX 14
XXXI 14
XXXII 7
XXXIII 16
XXXIV 1
XXXV 27
XXXVI 3
XXXVII 27
XXXVIII 3
XXXIX 3
XL 3
XLI 12
XLII 3
XLIII 4
XLIV 14
XLV 6
XLVI 4
XLVII 3
XLVIII 35
XLIX 4
50 14
LI 6
LII 8
LIII 10
LIV 31
Note: Super Bowl LIV (54) was played in 2020, and the winning margin is given as 31.
The winning margins range from 1 point to 45 points, with an average margin of about 14 points.
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On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate? The data shown below ($) contains the rate per 5 CCF of residential water for 42 randomly selected U.S. cities.10.38 9.08 11.7 6.4 12.32 14.43 15.4610.02 14.4 16.08 17.5 19.08 17.88 12.7516.7 17.25 15.54 14.7 18.81 17.89 14.818.32 15.95 26.75 22.22 22.66 20.88 23.3518.95 23.6 19.16 23.65 27.7 26.95 27.0426.89 24.58 37.76 26.41 38.91 29.36 41.55(a)Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. (Enter != for ≠ as needed.)H0:Ha:(b)What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.)What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.)(c)At α = 0.05, can your null hypothesis be rejected? What is your conclusion?Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.(d)Repeat the preceding hypothesis test using the critical value approach.State the null and alternative hypotheses. (Enter != for ≠ as needed.)H0:Ha:Find the value of the test statistic. (Round your answer to three decimal places.)State the critical values for the rejection rule. Useα = 0.05.(Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)test statistic≤test statistic≥State your conclusion.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.
The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .
The charge at which anything happens is referred to as the velocity at which it happens.
The required details for mean rate :
(a) H0: µ = 21.62
Ha: µ ≠ 21.62
(b) t = -1.231
p-value = 0.2253
(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.
(d) H0: µ = 21.62
Ha: µ ≠ 21.62
t = -1.231
check statistic ≥ 2.020
Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.
The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.
The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.
The crucial values for t at this level of significance are t=2.019.
Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.
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The cost of renting a jet ski over a certain number of hours can be represented by the equation y=40x + 50. How much would it cost to rent a jet ski for 3 hours?
Answer:
$170
Step-by-step explanation:
Let's say that x represents the amount of hours, so therefore, x will be replaced by 3:
y = (40 * 3) + 50
So, solve inside the parentheses:
y = (40 * 3) + 50
y = 120 + 50
Solve:
y = 120 + 50
y = 170
So, a jet ski would cost $170 to rent for 3 hours
Hope this helps :)
Help plz I will give brainliest that’s what they say right
Answer: A
Step-by-step explanation:
(f+g)x
4x - 9 + 12x +7
4x +12x - 9 +7
16x - 2
answer - (f+g)x = 16x -2
A car covers a distance of 600 m in 2 minutes whereas a train covers a distance of 75 km in 50 minutes. Find the ratio of their speed.
answer
1:5
Step-by-step explanation:
To find speed use the formula
speed=distance/time
The car's speed is 600m ÷2mins(120secs)
(600÷120)
5m/s
The trains speed will be
speed=distance/time
=75÷50mins(5/6hrs)
=90km/hr
Ratio of their speed should be
first change the speed of the car 5 m/s to km/hr. 5×18/5 = 18km/hr
the speed of the train is 90km/hr
18:90 simplified it will be 1:5
Pleaseee helppppppp!!!!!!!!!
Answer:
angle 1 + angle 2 = 100
angle 1 = 40
angle 2 = 60
angle 3 = 120
Step-by-step explanation:
which number comes next in this series 5, 7, 11, 19, 35
Answer: 67
Step-by-step explanation:
We see a pattern where we multiply the number we added by previously by two.
For example, from 5 to 7, it is 2.
From 7 to 11, we add by 4.
From 11 to 19, we add by 8.
From 19 to 35, we add by 16.
This means the next number would be 32, adding 35 by 32 gives us 67,
Determine if the 2 triangles are congruent.
A) HL
B) SSS
C) AAS
D) SAS
Answer:
its SAS
Step-by-step explanation:
C Solve for x. 8x-4 60°
Answer:
8
Step-by-step explanation:
8x - 4 = 60
8x = 60 + 4
x = 64/8
x = 8
Which expressions are in the simplest form? Check all that apply.
(Please help, I've been stuck on this all afternoon)
Answer:
All options are correct.
Step-by-step explanation:
We have to find the expression which are in the simplest form.
A.\(x^{-3}+y^3\)
The expression cannot solve further.
Therefore, the given expression is in the simplest form .
B.\(\frac{1}{x^4}\)
The expression cannot solve further.
The given expression is in the simplest form.
C.\(\frac{w^7}{x^2}\)
\(x^2\) cannot divide \(w^7\).
The expression cannot solve further.
Hence, the given expression is in the simplest form.
D.\(a^{-9}\)
The expression cannot solve further.
The given expression is in the simplest form.
E.\(\frac{1}{a^2}+b^2\)
The expression cannot solve further.
Hence, the given expression is in the simplest form.
F.\(\frac{1}{b^5}\)
The expression cannot solve further.
Hence, the given expression is in the simplest form.
Hence, all options are true.
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What themes can you detect in these apple paintings from the masters?
Answer:
they really loved fruits? i don't know sorry if I couldn't help
Maximum Marks: 5 Given the total cost function TC=100Q−Q 2
+0.3Q 3
Where Q= rate of output and TC= total cost, determine a) The marginal and average cost functions. (2 Marks) b) The rate of output that results in minimum average cost. ( 3 Marks)
a) To find the marginal cost, we need to find the derivative of the total cost function with respect to the rate of output (Q).
TC = 100Q - Q² + 0.3Q³
Marginal cost (MC) = dTC/dQ
= d/dQ(100Q - Q² + 0.3Q³)
= 100 - 2Q + 0.9Q²
To find the average cost, we need to divide the total cost by the rate of output (Q).
Average cost (AC) = TC/Q
= (100Q - Q² + 0.3Q³)/Q
= 100 - Q + 0.3Q²
b) To find the rate of output that results in minimum average cost, we need to find the derivative of the average cost function with respect to Q. Then, we set it equal to zero and solve for Q.
AC = 100 - Q + 0.3Q²
dAC/dQ = -1 + 0.6Q
= 0-1 + 0.6Q
= 00.6Q
= 1Q
= 1/0.6Q
≈ 1.67
Therefore, the rate of output that results in minimum average cost is approximately 1.67.
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Which relation is a function?
Question 1 options:
{(3,2), (5,8), (3,−4)}
{(−1,6), (−2,7), (−3,6)}
{(5,7), (12,−3), (5,6), (12,7)}
{(3,5),(3,6)}
Solve for x.
X/6 = 6/9
Answer:
x=4
Step-by-step explanation:
x/6=6/9
cross multiply
9x=6×6
9x=36
x=36/9
x=4
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question 3 in the analyze stage of the data life cycle, what might a data analyst do? select all that apply.
In the analyze stage of the data life cycle, the data analyst will use the spreadsheet to aggregate the data and use the formulas to perform the calculations
The data life cycle is defined as the time period that that data exist in you system. Usually the data management experts finds the six or more stages in the data life cycle
The data analyst is the person who use the interpreted data and analyze the data in order to solve the problems
The analyze stage is the one of the main stages of the data life cycle. In the stage data analyst will use the spreadsheet to aggregate the data in the system and use the formulas to perform the calculations in the system
Therefore, the data analyst will use the spreadsheet to aggregate the data and use the formulas to perform the calculations
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3. Find the products using suitable identity:
a) (t –2)(t –2) b) (3y –2z) (3y + 2z) c) 105 × 98v
Answer:
a) t²- 4x + 4
b) 9y² - 4z
c) 10290v
Step-by-step explanation:
a+b) use identity (ax+b)(ax+c) = ax² + (b+c)x + bc
c) a × bx = abx
Let event G = taking a math class. Let event H = taking a science class. Then, Gn H = taking a math class and a science class while Gu H = taking either a math class or a science class. Suppose P(G) = 0.25 P(H) = 0.28 and P(Gn H)= 0.39. What is P(Gu H)?
The probability of taking either a math class or a science class P(G ∪ H) is 0.14.
The probability of an occurrence is a figure that represents how likely it is that the event will take place. In terms of percentage notation, it is expressed as a number between 0 and 1, or between 0% and 100%. The higher the likelihood, the more likely it is that the event will take place.
To find the probability of taking either a math class or a science class (G ∪ H), we can use the inclusion-exclusion principle:
P(G ∪ H) = P(G) + P(H) - P(Gn H)
Given:
P(G) = 0.25
P(H) = 0.28
P(Gn H) = 0.39
Substituting these values into the formula:
P(G ∪ H) = 0.25 + 0.28 - 0.39
= 0.53 - 0.39
= 0.14
Therefore, P(Gu H) (the probability of taking either a math class or a science class) is 0.14.
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