The mistake that Farah made in this experiment is that she hung up the pieces of cotton before putting the fan on, also the water evaporating can take longer or shorter even if they are all the same.
What are the consequences of mistakes in experiments?The consequences of errors or mistakes in the experiments may be determined by the fact that errors are differences between observed values and what is true in nature.
The error causes results that are inaccurate or misleading and can misrepresent nature. Scientifically accepted values are scientists' current best approximations, or descriptions, of nature.
Experimental error is the difference between a measured value and its true value. In other words, it is the inaccuracy or inaccuracies that stop us from seeing an absolutely correct measurement. Experimental error is very common and is to some degree inherent in every measurement.
Therefore, the mistake that Farah made in this experiment is that she hung up the pieces of cotton before putting the fan on, also the water evaporating can take longer or shorter even if they are all the same.
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8. How much power is used if you use a 20 N force to push a shopping cart 3.5 m in 2 s?
The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W
How do i determine the power used?First, we shall determine the work done in pushing the cart. Details below:
Force used (F) = 20 NDistance (d) = 3.5 mWork done (Wd) = ?Wd = Fd
Wd = 20 × 3.5
Wd = 70 J
Finally, we shall determine the power used in pushing the cart. Details below:
Work done (Wd) = 70 JTime (t) = 2 secondsPower used (P) = ?P = Wd / t
P = 70 / 2
P = 35 W
Thus, we can conclude that the power used is 35 W
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In general, which factor is NOT critical when playing sports? A. following the rules B. being a team player C. expecting to win every time D. staying positive Please select the best answer from the choices provided. A B C D Mark this and return
Answer: C
Explanation: i have played sports in my life now i am no physics person but in order to follow the rules you have to be a team player. and a part of being a team player is being positive and so b=a*d
The displacement of an object moving 330 km North for 2 hours and an additional 220 km North for 5 hours is?
Answer:
Usbe
Explanation:
How does the ionosphere affect radio frequencies
Answer:
This is what gives the Ionosphere its name and it is the free electrons that cause the reflection and absorption of radio waves. ... The high frequency waves pass through the ionosphere and escape into space while the low frequency waves reflect off the ionosphere and essentially "skip" around the earth.
Explanation:
If a farmer collects 22 milliliters of milk, how
many litres of milk did he collect?
Answer:
The correct answer is 0.022
Divide the volume value by 1000
22 divided by 1,000 = 0.022
Explanation:
Hope this helps!! :))
Weight _____. A) is related to mass, but not the same. B) changes as mass changes C) depends upon gravitational pull D) all of the above
Answer:
D) all of the above
Explanation:
All of the given choices are correct definition of what weight of a substance implies.
Weight is the vertical force on a body due to the gravitational attraction or pull.
Weight = mass x acceleration due to gravity
Mass of a body is directly proportional to its weight and so also is the gravity.
Mass is the amount of matter within a substance.
Weight is the force of gravity exerted by a body on another or a surface.
The reason why the weight of a body changes from place to place is mainly due to the gravitational pull
The kinetic theory of gases states that the kinetic energy of a gas is directly proportional to the temperature of the gas.
a. True
b. False
Answer:
true
Explanation:
The kinetic energy of a gas is directly proportional to the temperature of the gas.because temperature is the average kinetic energy of a substance
I hope this helps
Turn this into a velocity-time graph and acceleration-time graph. Dont worry about specific value.
Relationship between Position-time graph and Velocity-time graph:
A positive slope of position corresponds to an increase in velocity.
A constant slope of position corresponds to a constant velocity.
A negative slope of position corresponds to a decrease in velocity.
A zero slope of position corresponds to a zero velocity.
Let us sketch the velocity-time graph as per the above rules.
Relationship between Velocity-time graph and Acceleration-time graph:
A positive slope of velocity corresponds to a positive acceleration.
A constant slope of velocity corresponds to a zero acceleration.
A negative slope of velocity corresponds to negative acceleration.
Let us sketch the acceleration-time graph as per the above rules.
Which object has the greatest kinetic energy?
A. a truck with a mass of 3,500 kg moving at 30 m/s
B. a fast pitched baseball with a mass of .5 kg moving at 46.9 m/s
C. a locomotive engine with a mass of 205,000 kg moving 5 m/s
D. a person with a mass of 73 kg running 6 m/s
The object with the greatest kinetic energy is the locomotive engine (option C)
How do I know which object has the greatest kinetic energy?To know the object with the greatest kinetic energy, we shall determine the kinetic energy of each objects. Details below:
For truck:
Mass (m) = 3500 KgVelocity (v) = 30 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 3500 × 30²
KE = 1575000 J
For baseball:
Mass (m) = 0.5 KgVelocity (v) = 46.9 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.5 × 46.9²
KE = 549.90 J
For locomotive:
Mass (m) = 205000 KgVelocity (v) = 5 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 205000 × 5²
KE = 2562500 J
For person:
Mass (m) = 73 KgVelocity (v) = 6 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 73 × 6²
KE = 1314 J
From the above calculations, we can see that the locomotive has the greatest kinetic energy. Thus, the correct answer is option C
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30. A stone falls freely from a building takes 5sec to reach at the ground a) What is the height of the building? b) Find the speed of the stone when it reaches at ground
Answer:
Height = 122.5 m
Speed = 49 m/s²
Explanation:
Thanks for the question.
We will use second equation of motion.
We know, u = 0 (body falls from rest)
t = 5 (given)
a = 9.8 m/s² (acceleration due to gravity)
s = ut + 0.5 at²
s = 0.5 x 9.8 x 25 = 122.5
So, the height of the building is 122.5 m.
Now, v = u + at
v = 0 + 9.8 x 5 = 49 m/s²
Cheers
A curve is banked at an angle of 29.1 degrees above the horizontal and the road surface has a coefficient of static friction of 0.4. What must the radius of curvature be for the safe minimum speed of 27.1 m/s?
Hi there!
We can begin by summing the forces acting on the car.
Along the axis of the incline, the forces of friction and gravity are working. The force of friction points towards the top of the ramp, while the force of gravity works towards the bottom.
We can use trigonometry to determine the force due to gravity along the ramp.
\(F_g = Mg sin\theta\)
The force due to friction is equal to:
\(F_f = \mu N\)
The normal force is the vertical component of the force due to gravity, so:
\(F_f = \mu Mgcos\theta\)
Now, the combination of these two forces produces a component of the centripetal force. Drawing a diagram, we see that the true centripetal force is the HYPOTENUSE, while these forces sum up to its horizontal component along the ramp.
Therefore:
\(F_c sin\theta = Mgsin\theta - \mu Mgcos\theta\)
The centripetal force is equivalent to:
\(F_c = \frac{Mv^2}{r}\)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Rewrite:
\(\frac{Mv^2}{r}sin\theta = Mgsin\theta - \mu Mgcos\theta\)
Cancel out 'M'.
\(\frac{v^2}{r}sin\theta = gsin\theta - \mu gcos\theta\)
Rearrange to solve for 'r'.
\(r = \frac{v^2sin\theta}{gsin\theta - \mu gcos\theta}\)
Plug in values and solve.
\(r = \frac{(27.1^2)sin(29.1)}{(9.8)sin(29.1) - 0.4(9.8)cos(29.1)} = \boxed{266.365 m}\)
A 0.22-caliber handgun fires a 28-g bullet at a velocity of 765 m/s. Calculate the de Broglie wavelength of the bullet.
Answer:
de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m
Explanation:
Given;
mass of bullet, m = 28 g = 0.028 kg
velocity of the bullet, v = 765 m/s
de Broglie wavelength of the bullet is given by;
λ = h / mv
where;
λ is de Broglie wavelength of the bullet
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
λ = h / mv
λ = (6.626 x 10⁻³⁴ ) / (0.028 x 765)
λ = 3.093 x 10⁻³⁵ m
Therefore, de Broglie wavelength of the bullet is 3.093 x 10⁻³⁵ m
Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.
Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.
The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.
These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.
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A 140-kg box is being lowered at constant velocity. A rope is attached to the top of the box, and Jimmy is slightly supporting the box from the bottom. If Jimmy is applying 50 N of force to the box, how much force is the rope applying?
Answer:
the anwser is 90
Explanation:
because 140-50=90
Find the terminal velocity of a sphere that has a mass of 600g and a radius of 30cm. Take the density of air 1.2 kg/m^3 . Report the speed in mph.
The terminal velocity of the sphere is approximately 22.68 mph.
The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:
Fd = (1/2) * rho * Cd * A * v²
where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.
The gravitational force pulling the sphere down is given by:
Fg = m * g
where m is the mass of the sphere and g is the acceleration due to gravity.
At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:
Fd = Fg
Substituting the expressions for Fd and Fg and solving for v, we get:
v = √((2 * m * g) / (rho * Cd * A))
where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.
Plugging in the given values, we get:
v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s
To convert this to mph, we multiply by 2.23694:
v ≈ 22.68 mph
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Is the rate at which velocity change?
____________
Answer:
Acceleration:The rate of change of velocity is acceleration. Like velocity, acceleration is a vector and has both magnitude and direction. For example, a car in straight-line motion is said to have forward (positive) acceleration if it is speeding up and rearward (negative) acceleration if it is slowing down.
Explanation:
Hope it is helpful....
two wharves A and B are directly opposite each other on a 40m wide river which flows in the direction shown. a boat leaves A and heads at constant speed at right angles to the flow of the river. it lands at point C, with the trip taking 20 seconds.
find;
a) the displacement from C to A
b) the speed of the boat as seen by people standing at A.
c) the speed of the water in the river
d) the speed of the boat as seen by a fish drifting with the river.
e) Draw a vector diagram and u
se it to find the direction the boat should head ( at the same constant speed as before) if it is to travel directly from A to B.
Answer:
a)40 meters
b)2 m/s
c)2 m/s
d)0 m/s
e)45 degrees northeast
Explanation:
a) The displacement from C to A is the distance directly across the river, which is 40 meters.
b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:
Speed = displacement / time = 40 m / 20 s = 2 m/s.
c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.
Distance carried downstream = v × time = v × 20 m.
Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:
40 m = (boat speed) × (time taken) = (boat speed) × 20 s.
Hence, the speed of the boat is:
Boat speed = 40 m / 20 s = 2 m/s.
So, we have two equations:
Distance carried downstream = v × 20 m
Boat speed = 2 m/s
From the first equation, we get:
v × 20 m = 40 m
Therefore, the speed of the water in the river is:
v = 40 m / 20 m = 2 m/s.
d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:
Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.
So, the speed of the boat as seen by a fish drifting with the river is zero.
e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.
We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.
The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:
tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.
Taking the inverse tangent of both sides gives:
θ = tan^(-1)(1) = 45°.
So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.
Elle is playing with a ball in a bus that moves in a straight line with constant velocity. What can you say about the motion of the ball in the moving bus if Elle throws the ball vertically upwards?
Please help me !!!!!!!
Answer: I believe that it is 35 Joules.
Explanation:
100 - 65 = 35
:)
a car accelerate uniformly from rest to a speed of 20m/s in 8seconds.the mass of the car is 1200kg. calculate the acceleration of the car
Answer:3000
Explanation:
given:u=0v=20m/st= 8sec
thereforea=v-u/t=20-0/8=20/8=5/2 m/som=1200 kg
thereforef=ma=1200*5/2=600*5=3000N
an electric kettle takes 2kw at 240v. Calculate the current and the resistance of the heating element
The power output is given 2000 watt and voltage is 240 v. Then the current through the heating element is 8.3 A and the resistance is 29 ohms.
What is power ?The power used by an object is the rate of its work done or energy. It is the energy divided by time. The power output in a circuit is the product of the potential difference V and current I.
P = I V
Given,
P = 2 kw = 2000 W
v = 240 V.
Then I = P/v
I = 2000 w/240 v = 8.3 A.
According to Ohm's law, voltage v is the product of the current and resistance through the material.
hence,
V = I R
then, R = V/I
R = 240 V/8.33 A
= 29 Ω.
Therefore, the current and resistance through the heating element are 8.3 A and 29 ohms respectively.
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? Question
Drag each label to the correct location on the table.
Classify the systems of equations based on the number of solutions they have.
No Solution
One Solution
Multiple Solutions
x + 2y = 1
x+10y = 50
2y - X= 12
2x - y = 17
x - 4y = 7
4x+10y = 40
2x + 5y = 40
3x+6y=3
2x+10y = 90
2y - 2 10
|2y - 3x = 5
No Solution:
4x+10y = 40
2x + 5y = 40
2x - 8y=17
x - 4y = 7
One Solution:
2y - X= 12
2y - 2x =10
x + 10y =50
2x + 10y =90
Infinitely Many Solutions:
x + 2y = 1
3x + 6y= 3
2y - 3x = 5
2/5y -3/5x =1
Explanation: You only had 11 equations listed. But I believe these are the ones you want. I took the test and got them right. Hope it helps
Sam's mom says: "We're about to eat dinner! Don't go more than a few blocks from home!" Is Sam's mom
more worried about Sam's distance or his displacement? Circle one and explain why you picked it.
Answer:
Displacement
Explanation:
I think Sam's mom isn't worried with how far away he goes, but will be upset if he isn't home fast enough for dinner.
As thermal energy is added to a sample of water, the potential energy of its
molecules increases, and then the kinetic energy of its molecules increases.
Which sections of the heating curve illustrate this process?
Temperature (°C)
200
150-
100
50
0
7
-50-
0
A
T
10
T
20
с
B
T
30
40
Time (min)
A. B followed by D
B. C followed by B
C. A followed by B
D. B followed by C
50
60
D
70
As thermal energy is added to a sample of water, the potential energy of its molecules increases, and then the kinetic energy of its molecules increases.
The sections of the heating curve illustrate this process is B followed by D
Therefore option A is correct.
What is thermal energy?Thermal energy (also called heat energy) is described as being produced when a rise in temperature causes atoms and molecules to move faster and collide with each other.
some factors of thermal energy include:
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A bowling ball is dropped on a moon from the height of 14 m. The acceleration of gravity on the moon is 4 m/s2. Determine the time it took for the ball to crash at the surface. Round your answer to the nearest whole number.
b. 1 s
c. 4 s
d. 3 s
Answer:
4sec
Explanation:
Since we know the initial velocity=0, acceleration = -4; and the displacemnt =14, we use the equation d = vi • t + ½ • a • t2. So, just plug in the values and solve for t in this case it's 4 sec
A body is said to be in freefall when it moves solely under the influence of gravity.
The time it took for the ball to crash at the surface = 3 sec.
What do you mean by the free fall?A body is said to be in freefall when it moves solely under the influence of gravity. The ball's motion will be accelerated by an external force acting on it. This free-fall acceleration is also known as gravity acceleration.Free fall is a type of motion in which gravity is the only force acting on an object. Objects that are said to be in free fall do not encounter significant air resistance; they fall solely under the influence of gravity.acceleration of gravity on the moon is 4 m/s^2.
the height of 14 m.
The formula for free fall:
\(h= \frac{1}{2}gt^2\)
t^2 = 2h /g = 2 x 14 /4 = 7
t = \(\sqrt{7} = 2.65\) sec ≅ 3 sec.
The time it took for the ball to crash at the surface = 3 sec.
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Your friend has been hired to design the interior of a special executive express elevator for a new office building. This elevator has all the latest safety features and will stop with an acceleration of g/4 in the case of an emergency. The management would like a decorative lamp hanging from the unusually high ceiling of the elevator. He designs a lamp which has three sections which hang one directly below the other. Each section is attached to the previous one by a single thin wire, which also carries the electric current. The lamp is also attached to the ceiling by a single wire. Each section of the lamp weighs 10.0 N. Because the idea is to make each section appear that it is floating on air without support, he wants to use the thinnest wire possible. Unfortunately the thinner the wire, the weaker it is.
Required:
Calculate the force on each wire in case of an emergency stop.
Answer:
The force on each wire is
\(T_1 = 12.5 \ N \)
\( T_2 = 25 \ N \)
\( T_3 = 50 \ N \)
Explanation:
From the question we are told that
The acceleration at which the elevator will stop is \(a = \frac{g}{4}\)
The weight of each section of the wire is \(W = \ 10 \ N\)
Generally \(W_1 = W_2 = W_3\) here \(W_1 , W_2 , W_3\) are weight at each section
Generally considering the first section, the force acting along the y-axis is mathematically represented as
\(\sum F_y_1 = T_1 - W_1 = m * a\)
Here \(T_ 1\) represents the tension on the wire at the first section while \(W_1\) represents the weight of the lamp at the first section
So
\(T_1 - 10 = m * \frac{g}{4}\)
=> \(T_1 - 10 = \frac{W_1}{4}\)
=> \(T_1 - 10 = \frac{10}{4}\)
=> \(T_1 = 12.5 \ N \)
Generally considering the second section, the force acting along the y-axis is mathematically represented as
\(\sum F_y_2 = T_2 -T_1- W_2 = m * a\)
=> \( T_2 - T_1- 10 = m * \frac{g}{4}\)
=> \( T_2 - 12.5- 10 = \frac{W_2}{4}\)
=> \( T_2- 12.5- 10 = \frac{10}{4}\)
=> \( T_2 = 25 \ N \)
Generally considering the third section, the force acting along the y-axis is mathematically represented as
\(\sum F_y_3 = T_3- T_2 -T_1- W_3 = m * a\)
\( T_3 - T_2 - T_1- 10 = m * \frac{g}{4}\)
\( T_3 - 25 - 12.5- 10 = \frac{W_2}{4}\)
\( T_3 - 25 - 12.5- 10 = \frac{10}{4}\)
\( T_3 = 50 \ N \)
a student measured the length of awire four times using ameter rule and obtained the following reading 18.6,18.5,18.6,18.5 determine the length
The student measured the length of a wire four times and the total length from the reading is 18.55 m.
From the given,
The length of the wire measured by the student using a meter rule is :
l₁ = 18.6 m
l₂ = 18.5m
l₃ = 18.6m
l₄ = 18.5 m
The total length of the wire is obtained from the average values of length.
Total length (L) = (l₁ + l₂ + l₃ + l₄)/4
L = (18.6 + 18.5 + 18.6 + 18.5) / 4
= 74.2 /4
= 18.55
Hence, the actual length of the wire = 18.6 m.
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There is a current of 0.83 A through a light bulb in a 120.0v circuit. What is the
resistance of the light bulb?
Answer:
144.6ohms
Explanation:
v=IR
R =V/I=120/0.83
R=144.6
b) A satellite is in a circular orbit around the Earth at an altitude of 1600 km above the Earth's surface. Determine the orbital period of the satellite in hours. [3]
Explanation:
The orbiting period of a satellite at a height h from earth' surface is
T=2πr32gR2
where r=R+h.
Then, T=2π(R+h)R(R+hg)−−−−−−−−√
Here, R=6400km,h=1600km=R/4
T=2πR+R4−−−−−−√R(R+R4g)−−−−−−−−−⎷=2π(1.25)32Rg−−√
Putting the given values,
T=2×3.14×(6.4×106m9.8ms−2)−−−−−−−−−−−−√(1.25)32=7092s=1.97h
Now, a satellite will appear stationary in the sky over a point on the earth's equator if its period of revolution around the earthh is equal to the period of revolution of the earth up around its own axis whichh is 24h. Let us find the height h of such a satellite above the earth's suface in terms of the earth,'s radius.
Let it be nR.Then
T=2π(R+nR)R(R+nRg)−−−−−−−−−−√
=2π(Rg)−−−−−√(1+n)32
=2×3.14(6.4×106m/s9.8m/s2)−−−−−−−−−−−−−−−⎷(1+n)32
(5075s)(1+n)32=(1.41h)(1+n)32
For T=24h, we have (24h)=(1.41h)(1+n)32
or (1+n)32=241.41=17
or 1+n(17)23=6.61
or n=5.61
The height of the geostationary satellite above the earth's surface is nR=5.61×6400km=6.59×104km.
A 74.1 kg high jumper leaves the ground with
a vertical velocity of 9.7 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m
Answer:
4.80 m
Explanation:
We are given the mass of the high jumper, its initial velocity, and the acceleration of gravity. We are trying to find the vertical displacement of the high jumper.
Let's set the upwards direction to be positive and the downwards direction to be negative.
List out the relevant known variables.
v₀ = 9.7 m/s a = -9.8 m/s² Δx = ?We still need one more variable in order to use the constant acceleration equations. Since we are trying to find the max height of the jumper, we can use the fact that at the top of its trajectory, its final velocity will be 0 m/s.
4. v = 0 m/s
Using these four variables, let's find the constant acceleration equation that contains these variables:
v² = v₀² + 2aΔxSubstitute the known values into the equation and solve for Δx.
(0)² = (9.7)² + 2(-9.8)Δx 0 = 94.09 + (-19.6)Δx -94.09 = -19.6Δx Δx = 4.80The high jumper can jump to a max height of 4.80 m.