Answer:
crest
Explanation:
a trapeze is a short horizontal bar held up by two vertical ropes on either side. An acrobat with a mass of 60 kg provides a 588 N downward force on the bar. Each of the two ropes provide an upward force of 349 N. What is the upward acceleration of the acrobat?
The upward acceleration of the acrobat is 1.833 m/s².
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the acrobat; M = 588 N.
Weight of the acrobat acting downwards; W = 588 N.
Upward force provided by each of the two ropes; f = 349 N.
Hence, net force acting on the acrobat in upward direction = 2f -w
= (2×349 - 588 ) N.
= 110 N.
Hence, the upward acceleration of the acrobat is = net force/ mass
= 110/60 m/s².
=1.833 m/s².
So, the upward acceleration of the acrobat is 1.833 m/s².
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The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars
The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.
Weight of objects on Earth and on MarsThe weight of an object is given by the product of its mass and the gravitational field strength at its location.
On Earth:
Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 NOn Mars:
Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 NTherefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.
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state ohmic conductor
Answer:
An ohmic conductor is defined as one which obeys ohm's law that is V ∝ I where is the voltage and is the current. There must be a linear graph. Silver is an example of an ohmic conductor as the graph for silver is a linear graph. Silver and copper are some examples of ohmic conductor
An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
Identify the direction of the net force acting on the object. Explain your reasoning
Answer:
See Below
Explanation:
I am not sure what you exact question is to know what direction it is but here is how you do it.
The direction of the net force is the direction of the largest force.
for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps
6. A capacitor of charge 3 x 10 coulomb has a potential of 50volts. What is the capacitance of the capacitor?
Answer:
Explanation:
Sry
Answer:
C = Q/V
where C is capacitance, Q is charge and V is voltage
C = (3×10)/50
C = 30/50
= 0.6F where F is in Farads
Inquiry is a process promoted by a Blank
Inquiry is a process prompted by curiosity, observation or question.
Explanation:Inquiry is driven by curiosity, wonder, interest and/or a need to answer a question. Being able to ask rich questions enables students to construct their knowledge and develop an understanding of concepts and experiences.
what is the problem statement for corn mold test mycotoxins?
Answer:
because of their potential to produce mycotoxins, which may affect livestock feeding value
Explanation:
read the info on line
which one of the following parameters is not used to determine the magnetic force on a current-carrying wire in a magnetic field?
Radius of wire is not used to determine the magnetic force on a current-carrying wire in a magnetic field
What is a magnetic field?A magnetic field is a region in space where magnetic forces can be detected. It is created by the motion of electric charges, such as the movement of electrons in an electric current or the spinning of electrons in an atom.
A magnetic field is represented by lines of force that can be visualized using magnetic field lines. These lines indicate the direction of the magnetic field at each point in space and the strength of the magnetic field is indicated by the density of the lines.
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Kelli felt obligated to answer the phone when her mom called. She really was not paying attention to the conversation, but every once in awhile would say, "Yes" or "Okay" just to keep her mom satisfied.
This hurtful listening habit is called:
A. Defensive Listening
B. Selective Listening
C. Bad Listening
D. Pseudolistening
Although she wasn't truly listening to what was being said, she would occasionally say "Yeah" or "Okay" to appease her mother. This destructive listening behaviour is known as: Defensive listening, first
What constitutes a poor listening habit?Interrupting, eavesdropping, being confrontational, egotistical, defensive, selective, insensitive, and pseudo-listening are some examples of these poor listening techniques.
A faux listener is what?Pseudolistening– having to pretend to pay any attention and did appear considerate but is not trying to listen to realise or translate the data (audience members may answer back with a smile, mouth, or even a verbal cues appreciation but are dismissing or not planning to attend).
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A DC electric motor transforms 5.3 kW of electrical power into mechanical form. If the motor's operating voltage is 250 volts, how much current does it "draw"?
The current drawn in the circuit by the DC electric motor is found to be 21.2 amperes.
Explain about the electrical power?Electric power is a standard measure for how quickly electrical energy is delivered over an electric circuit.
P represents for power, which is denoted and measured and use the SI unit of power, the watt, or a joule per second. Electric batteries and electric generators are frequently used to produce and supply electricity. The movement of electrical power as well as charge is known as electricity.Power of electric motor P = 5.3 KW = 5300 W
Operating Voltage V = 250 volts
Power = Current * voltage
P = V * I
I = P / V
I = 5300 / 250
I = 21.2 A
Thus, the current drawn in the circuit by the DC electric motor is found to be 21.2 amperes.
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pls help need it last question on my test
The force that results in the decrease in speed from the midpoint to the end of the track is friction. The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.
The force that would cause the Hot Wheels car to slow down from the midpoint of the track to the end of the track is friction between the car's wheels and the track.
Friction is a force that opposes motion between two surfaces in contact.
In this case, the wheels of the car and the surface of the track are in contact, and the friction force acts in the opposite direction of the car's motion, which slows it down.
As the Hot Wheels car travels down Track #2 during the Speed Lab activity, its initial velocity decreases due to friction.
Friction is a resistance force that opposes motion.
It is caused by the interaction between the surfaces in contact. In this case, the surface of the track and the wheels of the car are in contact.
When the car is moving, there is friction between the two surfaces.
The direction of the friction force is opposite to the direction of motion of the car.
This means that the friction force slows the car down.
In conclusion, the force that results in the decrease in speed from the midpoint to the end of the track is friction.
The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.
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The product of an object's mass and velocity is it's
A) acceleration
B) inertia
C) momentum
D) weight
Answer:
C) Momentum
Explanation:
Refers to an objects mass in motion.
Which one of the following statements concerning weight and energy balance is most accurate?
A. People generally need the same amount of physical activity to maintain weight stability.
B. Regular physical activity doesn’t impact the percentage of body fat in children and adolescents.
C. It’s possible to achieve weight stability by doing the equivalent of 60–120 minutes a week of moderate-intensity walking.
D. The optimal amount of physical activity needed to maintain weight is unclear.
Answer: D. I took the test and got it right
The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.
What is energy balance?Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.
Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.
So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.
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forces and their effects
Friction
Change in motion
Deformation
What is Force?
Force is an influence that can cause an object to accelerate or deform. It is a vector quantity that has both magnitude and direction, measured in units of newtons (N). Force can result from the interaction between two physical bodies, such as when two objects collide or when a force is applied to an object.
Change in motion: Forces can cause an object to start moving, stop moving, change direction, or change speed.
Deformation: Forces can deform or change the shape of an object. For example, a force can stretch a spring, bend a wire, or compress a sponge.
Stress: Forces can create stress within an object, which is the internal force that resists deformation or change in shape. Too much stress can cause an object to break or fail.
Friction: Forces can cause friction, which is the force that resists the motion of two surfaces in contact. Friction can cause objects to slow down, stop moving, or prevent them from sliding.
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Fill in the blanks for the following nuclear reactions.
1. 32 S + 4 He → _____
2. ____ + 4 He → 40 Ca
3. 40 Ca + 4 He → ______
4. _____ + 4 He → 48 Cr
5. 48 Cr + 4 He → _____
Why does the shape of the lens in your eye change?
The Lens Changes Shape to Focus Near Objects. Light rays from objects that are close to the eye are not parallel. Therefore, the eye must bend them more in order to focus the rays on the retina. To accomplish this, the lens change shape.
Hope this helps
Answer:
to focus the light
Calculate the ratio of H+ ions to OH– ions at a pH = 8. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide. Then divide the H+ concentration by the OH– concentration. Record this calculated ratio in Table A of your Student Guide. Compare your approximated and calculated ratios of H+ ions to OH– ions at a pH = 8. Are they the same? Why or why not? Record your explanation in Table A. What is the concentration of H+ ions at a pH = 8? mol/L What is the concentration of OH– ions at a pH = 8? mol/L What is the ratio of H+ ions to OH– ions at a pH = 8? :1 OR 1:
At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.
To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.
The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:
\(C_H\)+ = \(10^(^-^p^H^)\)
Substituting pH = 8 into the formula:
\(C_H\)+ = \(10^(^-^8^))\)
Using the properties of logarithms, we can calculate the concentration of H+ ions:
\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L
According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.
To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:
Ratio = \(C_H\)+ / \(C_O_H\)-
Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))
Ratio = 1:1
The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.
When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.
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A platinum resistance thermometer has resistances of 210.0 Ω when placed in a 0°C ice bath and 237.8 Ω when immersed in a crucible containing a melting substance. What is the melting point of this substance? (Hint: First determine the resistance of the platinum resistance thermometer at room temperature, 20.0°C.)
The resistance of a platinum resistance thermometer is 200 Ω at 0°C and 255.8 Ω at the melting point. Using the resistance-temperature relationship and calculations, the estimated melting point is approximately 19.93°C.
The resistance of a platinum resistance thermometer is 200 Ω when placed in a 0°C ice bath and 255.8 Ω when immersed in a crucible containing a melting substance. To determine the melting point of the substance, we need to calculate the temperature at which the resistance reaches 255.8 Ω.
First, we find the temperature coefficient of resistance (α) using the formula α = (R - R₀) / (R₀ * T), where R is the resistance at the melting point, R₀ is the resistance at 0°C, and T is the temperature at the melting point.
Substituting the given values, we have α = (255.8 - 200) / (200 * T₀), where T₀ is the known room temperature of 20°C.
Calculating α, we find α ≈ 0.014.
Next, we use the resistance-temperature relationship equation R = R₀(1 + αT) to solve for the melting point temperature (T). Substituting the known values, we have 255.8 = 200(1 + 0.014 * T).
Simplifying the equation, we find 1.279 = 1 + 0.014T.
Solving for T, we get T ≈ 19.93°C.
Therefore, based on the given data, the estimated melting point of the substance is approximately 19.93°C.
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Which statement explains why a blue car does not appear to be red?
A. Blue light is absorbed by the car.
B. Red light is absorbed by the car.
C. Blue light is transmitted through the car.
D. Red light is transmitted through the car.
Answer: B. Red light is absorbed by the car.
Explanation:
The colour of the object is decided by the wavelength of light that it reflects.
Light with the longest wavelength appears red, and light with the shortest wavelength appears violet. The wavelengths of visible light that an object reflects or transmits determine the color that the object appears to the human eye.
The blue car appears blue as it absorbs red light and reflects blue colour.
What is the economic term for the act of sacrificing one good or service to purchase or produce another?
Answer:
Trade-off. sacrificing one good or service to purchase or produce another.Someone please help me
The force F acting on a body varies with the displacement s from a point O as shown in the graph.
(a) Calculate the work done when the body is displaced
(i) from s=0 to s = 0.4 m
(ii) from s=0 to s =0.8 m
(b) If the mass of the body is 0.20 kg and its initial velocity is 2.00 m/s, find its velocity
(i) when s = 0.4 m
(ii) when s = 0.8 m
a.i) The work done when the body is displaced from s=0 to s = 0.4 m is 0.8 J.
(a.ii) The work done when the body is displaced from s=0 to s = 0.8 m is 1.2 J.
(b.i) The final velocity of the body when the displacement is 0.4 m is 3.46 m/s.
(b.ii) The final velocity of the body when the displacement is 0.8 m is 4 m/s.
What is work done?The work done on an object is the product of force and displacement of the object.
The work done between 0 to 0.4 m is determined from the area of the triangle formed.
W = ¹/₂(0.4 m - 0 m) x ( 4 N )
W = ¹/₂(0.4 m) x ( 4 N )
W = 0.8 J
The work done from s=0 to s =0.8 m,
W = ( Area of 0 to 0.4 m) + ( Area of 0.4 m to 0.8 m)
W = 0.8 J + ¹/₂(0.8 m - 0.4 m) x ( 2 N )
W = 0.8J + ¹/₂(0.4 m) x ( 2 N )
W = 0.8J + 0.4 J
W = 1.2 J
The final velocity of the body is calculated by applying work energy principle.
change in kinetic energy of the body = work done by the body
¹/₂m(v₂² - v₁²) = W
Where;
m is the mass of the bodyv₁ is the initial velocityv₂ is the final velocitywhen, s = 0.4 m, the final velocity is calculated as;
¹/₂m(v₂² - v₁²) = 0.8 J
¹/₂(0.2)(v₂² - 2²) = 0.8
0.1(v₂² - 2²) = 0.8
v₂² - 2² = 0.8 / 0.1
v₂² - 2² = 8
v₂² = 8 + 4
v₂² = 12
v₂ = √12
v₂ = 3.46 m/s
when s = 0.8 m, the final velocity is calculated as;
¹/₂(0.2)(v₂² - 2²) = 1.2 J
0.1(v₂² - 2²) = 1.2
v₂² - 2² = 1.2 / 0.1
v₂² - 2² = 12
v₂² = 12 + 4
v₂² = 16
v₂ = √16
v₂ = 4 m/s
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Systems, which are the building blocks of technology, are embedded within larger:
-political, ethical, and moral systems
-mechanical, structural, and electrical systems -technological, social, and environmental systems
-optical, thermal and fluid systems
identify the ways in which ocean sediments can be used as direct evidence in solving different type of issues. (select all that apply.)
To map offshore pollution patterns, to identify sites for underwater construction projects, and to find offshore mineral resources, are the ways in which ocean sediments can be used as direct evidence of issues.
To map offshore pollution patterns: Changes in the composition and distribution of pollutants and trace elements in ocean sediments can provide evidence of environmental changes, including pollution.
To identify sites for underwater construction projects: The composition and physical characteristics of sediments can provide information about the suitability of a site for underwater construction, such as the stability of the sea bed and the potential for sediment movement.
To find offshore mineral resources: The distribution of specific mineral deposits in ocean sediments can be used to identify areas with potential for offshore mineral extraction.
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--The given question is incomplete, the complete question is:
"Identify the ways in which ocean sediments can be used as direct evidence in solving different type of issues. (Select all that apply.)
To map offshore pollution patterns
To identify sites for underwater construction projects
To find offshore mineral resources
To determine how climate has changed over geologic time"--
A mercury thermometer is constructed as
shown. The capillary tube has a diameter
of 0.0059 cm, and the bulb has a diameter of
0.32 cm. Neglecting the expansion of the glass, find
the change in height of the mercury column
for a temperature change of 36 ◦C. The
volume expansion coefficient for mercury is
0.000182 (◦C)−1
.
Answer in units of
The change in the height of the mercury thermometer column for a temperature change of 36 \(^oC\) would be 1.86 cm.
Change in height in a mercury thermometerTo solve this problem, we can use the formula for the change in height of the mercury column in a thermometer:
Δh = V/(πr²)
where Δh is the change in height of the mercury column, V is the change in volume of the mercury, r is the radius of the capillary tube, and π is the mathematical constant pi.
The change in volume of the mercury can be found using the formula:
ΔV = V₀βΔT
where V₀ is the initial volume of the mercury, β is the volume expansion coefficient for mercury, and ΔT is the temperature change.
The initial volume of the mercury in the thermometer can be approximated as the volume of a cylinder with height equal to the length of the capillary tube and radius equal to the radius of the bulb. Therefore:
V₀ = πr₀²h
where r₀ is the radius of the bulb and h is the length of the capillary tube.
Substituting these values and solving for Δh, we get:
ΔV = V₀βΔT = πr₀²hβΔT
Δh = ΔV/(πr²) = (πr₀²hβΔT)/(πr²)
Δh = (r₀²/r²)hβΔT
Plugging in the values given in the problem, we get:
r₀ = 0.16 cm (radius of the bulb)r = 0.00295 cm (radius of the capillary tube)h = 10 cm (length of the capillary tube)β = 0.000182 (◦C)⁻¹ (volume expansion coefficient for mercury)ΔT = 36 ◦C (temperature change)Therefore:
Δh = (0.16²/0.00295²) × 10 × 0.000182 × 36
= 1.86 cm
So the change in the height of the mercury column for a temperature change of 36 ◦C is approximately 1.86 cm.
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Answer:
he change in height of the mercury column for a temperature change of 36°C will be 2.981 cm.
What is thermal expansion?
Thermal expansion iis the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.
The given data in the problem is;
d is the diameter of capillary tube = 0.0045 cm
D is the diameter of an bulb=0.24 cm.
h is the change in height of the mercury column=?
h is the temperature change = 36 ◦C.
is the volume expansion =0.000182 (◦C)⁻¹
The formula for the thermal expansion is given as;
The initial volume of the mercury in the spherical bulb will be;
The change in the volume will be;
Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm.
Hence the change in height of the mercury column for a temperature change of 36°C will be 2.981 cm.
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Explanation:
What is the apparent weight of a 80-kg astronaut 2200 km from the center of the Earth's Moon in a space vehicle moving at constant velocity.
Answer:
the apparent weight of the astronaut is 81.032 N { towards moon }
Explanation:
Given that;
Mass of astronaut m = 80 kg
Distance of spaceship from the Earth's moon r = 2200 km = 2200 × 10³ m
Acceleration due to gravity of the moon = GM/r²
where M is mass of the moon( 7.34767309 × 10²² kg )
gravitational constant G = 6.67 × 10⁻¹¹
So,
Acceleration due to gravity of the moon g is;
g = [ (6.67 × 10⁻¹¹) × (7.35 × 10²²) ] / (2200 × 10³)²
g = 4.90245 × 10¹² / 4.84 × 10¹²
g = 1.0129 m/s²
now, we take the positive direction towards the moon if the spacecraft is moving with constant velocity, a = 0
The apparent weight is measured by the normal force FN
so,
∑F = ma
-FN + mg = ma
-FN + mg = 0
FN = mg
we substitute
FN = 80 × 1.0129
FN = 81.032 N { towards moon }
Therefore, the apparent weight of the astronaut is 81.032 N { towards moon }
A train passes through a station at a speed of 108 km/h. The length of the station is 120 m. The train takes 7 seconds to completely pass through the station. Work out the length of the train.
Answer:
V = 108 km/hr = 108 * 1000 m / 3600 s = 30 m/s
V = speed of train = 30 m/s
(L + 120) m / 7 sec = 30 m/s
When front of train reaches station, back of train must travel L + 120 m to clear the station
S = V / t
(L + 120) / 7 = 30
L = 210 - 120 = 90 m length of train
A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
A turtle starts at a velocity of 2 m/s and accelerates at a rate of 3 m/s2. How long will it take the turtle to reach a final velocity of 11 m/s?
A pulse of sound takes 1 second to travel about 25 feet to the seafloor
100
and back. A ship stops in an area where the seafloor extends to the bottom
of the Sunlight Zone. At this spot an echosounder gives a pulse of sound
that takes 26 second to travel to the seafloor and back. How deep is the
100
ocean at the bottom of the Sunlight Zone?
HELP!!! I’m stumped!! Get max points ( if it lets me! )
Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.
The distance travelled by echo sound is given by the formula -
Speed = 2×distance/time
So, calculating the speed of sound from the formula using distance and time
Speed = 2×25/(1/100)
Speed = 50×1000
Speed of sound = 5000 feet/second
Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -
Distance = (speed×time)/2
Distance = (5000×26/100)/2
Distance = 1300/2
Distance = 650 feets
Hence, the depth of ocean is 650 feets.
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Answer:
We can start by using the formula:
distance = speed x time
where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.
The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).
Converting the round-trip time to seconds, we have:
26 seconds - 1 second = 25 seconds
Substituting the values into the formula:
2 x depth = 4,921 feet/second x 25 seconds
2 x depth = 123,025 feet
depth = 61,512.5 feet
Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.