what will be the current when the capacitor has acquired 1/4 of its maximum charge? ii = nothing aa

(a) The charge in the circuit, with an initial charge on the capacitor of 1 x 10^-6 coulomb and an initial current of 0, can be calculated using the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. In this case, since there is no applied voltage, the charge in the circuit remains the same as the initial charge on the capacitor: 1 x 10^-6 coulomb.

(b) The steady state charge in the circuit can be determined by analyzing the behavior of a series circuit with a capacitor, inductor, and resistor. In a steady state, the capacitor charges to its maximum value, and the inductor behaves as a short circuit, bypassing the current. Therefore, the steady state charge in the circuit will be zero coulomb.

(c) The current in the circuit can be found using Ohm's law, which states that current (I) is equal to voltage (V) divided by resistance (R). In this case, since there is no applied voltage, the current in the circuit will be zero amperes.

(d) If an applied voltage of 36 volts is introduced to the circuit, the charge at any time (t) can be calculated using the formula Q(t) = Q_max * (1 - e^(-t/RC)), where Q_max is the maximum charge on the capacitor, e is the base of the natural logarithm, t is the time, R is the resistance, and C is the capacitance. The charge will gradually increase towards its maximum value over time.

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, The density of the metal with a simple cubic structure is approximately \(8.93 g/cm^3.\)

To determine the density of the metal with a simple cubic structure, we can use the following formula:

Density = (Atomic weight)/(Volume of the unit cell x Avogadro's number)

For a simple cubic structure, the volume of the unit cell can be calculated as:

The volume of unit cell = \(a^3\)

where a is the length of the edge of the cube.

In a simple cubic structure, the atoms touch along the edge of the cube. So, the edge length can be calculated as:

a = 2 x Atomic radius

Substituting the given values, we get:

a = 2 x 0.126 nm = 0.252 nm

The volume of the unit cell is:

Volume of unit cell = \(a^3\)= \((0.252 nm)^3\) = 0.016 \(nm^3\)

Now, we can substitute the values into the density formula:

Density = (70.4 g/mol)/(0.016 \(nm^3\) x 6.022 x \(10^23\)/mol)

Density = 8.93 \(g/cm^3\)

Therefore, the density of the metal with a simple cubic structure is approximately\(8.93 g/cm^3.\)

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Translated Question: If a metal had the simple cubic structure, how is it shown in the figure. Yes its atomic weight is 70. 4 g/mol and the atomic radius is 0.126 nm. determine the density

Answer:

hope it helps for you

Explanation:

A machine is an object or mechanical device that receives an input amount of work and transfers the energy to an output amount of work. For an ideal machine, the input work and output work are always the same. The six common simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw.

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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The current moving through the traditional incandescent light bulb in the examined flashlight is 1.67A.

Electric power is simply the rate at which electrical energy is transferred by an electric circuit per unit time. It is equal to the voltage difference across the element multiplied by the current.

It can be expressed as;

P = V × I

Given the data in the question;

To determine the current moving through the bulb, we substitute our given values into the expression above.

P = V × I

60W = 36V × I

I = 60W / 36V

I = 1.67A

Therefore, the current moving through the light bulb is 1.67A.

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10.6 m/s² is the acceleration for a ball that starts from rest, rolls down a ramp, and gains a speed of 36 m/s in 3.4 s.

Any object's acceleration is defined as the change in speed that occurs when time changes. Since acceleration is a vector concept, its magnitude and direction must be specified. The acceleration can be measured in m/sec², miles/sec², etc.

Any increase in speed in the positive direction would be a positive acceleration, any increase in the negative direction would be a negative acceleration, and any decrease in speed would be a decrease in acceleration. Acceleration is the increase in speed that an object exhibits or experiments in a certain amount of time. You have positive and negative acceleration depending on the negative and positive directions, for example, when using the vertical plane falling would be the negative direction and going up would be the positive direction.

The acceleration for the ball can be found using the equation:
acceleration = (final velocity - initial velocity) / time
Since the ball starts from rest, its initial velocity is 0 m/s. Therefore:
acceleration = (36 m/s - 0 m/s) / 3.4 s
acceleration = 10.6 m/s²
To two significant figures, the acceleration of the ball is 10.6 m/s².

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Newton’s second law of motion states that the force F acting on an object of mass m produces an acceleration a in the object, and is given by, F = ma. The law s invariant under Galilean transformation.

The Galilean transformation is a set of equations that describe the relationship between two reference frames that are in relative motion with constant velocity. It has no effect on the form of Newton’s second law because it only involves a change of coordinates and time, which do not affect the physical laws.

To see this, consider two reference frames S and S', where S' moves with constant velocity v with respect to S. Let an object of mass m be at rest in S, and let F be the net force acting on it in S. According to Newton’s second law in S, we have:

F = ma

Now, let us apply the Galilean transformation to the equation. The position of the object in S' is given by:

x' = x - vt

where x is the position of the object in S, and t is time. Taking the derivative of x' with respect to t, we get:

v' = dx'/dt

= dx/dt - v

= v - v

= 0

This means that the velocity of the object is the same in both reference frames. Similarly, the acceleration is also the same in both reference frames, since it is the derivative of velocity,

a' = dv'/dt = da/dt = a

Therefore, we can write Newton’s second law in S' as,

F' = ma'

where F' is the net force acting on the object in S'. Substituting a' = a, we get:

F' = ma

which is the same form as in S. Thus, we see that the form of Newton’s second law is invariant under the Galilean transformation.

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This body of mass 10 kg must be situated at a height of 5.10 meters.

In accordance with the law of conservation of energy, the potential energy possessed by a physical object at the top is equal to the kinetic energy possessed by a physical object at the ground:

PE = KE

mgh = ½mv²

2mgh = mv²

2gh = v²

h = v²/2g

Where:

Note: Acceleration due to gravity is equal to 9.8 m/s².

Substituting the given parameters into the formula above, we have;

Height, h = 10²/2(9.8)

Height, h = 100/19.6

Height, h = 5.10 meters.

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Answer:A - a pond has only produced a small amount of algae, so the fish population is also small. i’m pretty sure that’s correct.

Explanation: The amount of alage determines the size,or carrying capasity of the fish population,so it is a limiting factor.

Hope I could help!Brainlist?plz

Answer: Yes. Please find the answer in the explanation.

Explanation:

Yes. Since velocity is a vector quantity, that is, it has both magnitude and direction.

If the displacements covered are not of the same direction, the velocity will not also of the same direction.

Take for instance, if the velocity in a positive is 40 m/s and velocity in the opposite direction is - 20 m/s . Then, the resultant velocity will be 40 - 20 = 20 m/s

Therefore,  it is possible that at any time during their trip their velocity was -20 m/s.

The method that Josh should use to separate a mixture of sulfur powder and iron filings is magnetic separation.

Magnetic Separation is a process that separates magnetic materials from non-magnetic materials. In this case, iron filings are magnetic, while sulfur powder is not. By using a magnet, Josh can easily separate the iron filings from the sulfur powder. To perform magnetic separation, Josh can place the mixture of sulfur powder and iron filings on a piece of filter paper and move a magnet underneath the paper. The iron filings will be attracted to the magnet and will stick to it, while the sulfur powder will remain on the filter paper. This method is effective because it is simple and does not require any chemicals or complex equipment. It is also a quick way to separate the two substances, which is important in a lab setting where time is limited. In summary, Josh should use magnetic separation to separate the mixture of sulfur powder and iron filings in his lab.

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Answer:

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength.

Explanation:

At number 5 (choice E).

The coordinates 20°20'23.94"S, 150°38'29.14"E indicate a location near the coast of Queensland, Australia. From a zoomed-out view at an eye altitude of ~25 miles, the sedimentary environment in this area is likely a coastal or marine environment.

The given coordinates point to a location near the coast of Queensland, Australia. By zooming out to an eye altitude of approximately 25 miles, we can observe the broader geographic context and identify the type of sedimentary environment in the area.

Coastal and marine environments are known for their deposition of sedimentary materials. The presence of coastline and the proximity to the ocean suggest that the area experiences the influence of marine processes such as waves, tides, and sediment transport.

In coastal environments, sediments can range from fine-grained deposits like mud and silt to coarser materials such as sand and gravel. These sediments are often deposited along the shoreline, forming beaches, dunes, and sandbars. The action of waves and currents plays a significant role in shaping the coastal landscape and the sedimentary features present.

Additionally, the marine environment offers various sedimentary environments, including continental shelves, submarine canyons, and deep-sea basins. These areas can have different sediment types and processes, such as the accumulation of organic-rich sediments in shelf environments or the deposition of fine-grained sediments in deep-sea basins.

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Answer:

8138.16

Explanation:

hope this helps

Answer: Here's your answer friend,

Explanation:

1.Solid to Liquid --When a solid is heated the particles gain energy and start to vibrate faster and faster. ... Although the particles are still loosely connected they are able to move around. At this point the solid is melting to form a liquid. The particles in the liquid are the same as in the solid but they have more energy.

2.Liquid to Gas--Vaporization occurs when a substance changes from a liquid to a gas. The molecules in a liquid are in constant motion while staying relatively close together due to intermolecular forces. When an increase in temperature occurs, the molecules' kinetic energy also increases.

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

\(a_c = \dfrac{v^2}{R}\)

Solving for v:

\(v = \sqrt{a_c R} = \sqrt{(250\;m/s^2)(0.50\;m)} = 5\sqrt{5}\;m/s \approx 11.18\;m/s\)

The yo-yo’s tangential speed 11.18 m/sec.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

\(a_{c} = v^2/r\)

Solving for v

\(v = \sqrt{a_{c}r }\) = 11.18 m/sec

The yo-yo’s tangential speed 11.18 m/sec.

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Answer:

\(\text{Weight} = \text{Mass} \times \text{Gravitational acceleration}\)

Explanation:

Deceleration is the opposite of acceleration and refers to the slowing down of an object's speed. Therefore, the answer is b. negative.

When an object is decelerating, its acceleration is negative because it is moving in the opposite direction to its initial velocity. For example, when a car is moving forward and then applies the brakes, it starts to slow down. The acceleration of the car in this case is negative because it is moving in the opposite direction to its initial velocity, which was forward. Deceleration is an important concept in physics as it helps us understand how objects move and change their speed. It is also important in fields like engineering and transportation where deceleration rates need to be calculated to ensure the safety of people and equipment. In summary, deceleration is the negative acceleration of an object, which refers to the slowing down of its speed.

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Answer:

um .... D. D D D D D this should be it

if a rock is thrown straight up and falls, then its acceleration is the same as at the top of its path and it is equal to g, the gravitational acceleration.

If an object is moving straight vertically, the acceleration is constant along its trajectory, either it moves upward or downward. It is the velocity that changes.

If the object is moving upward, the velocity decreases, until at the top position, the velocity is equal to zero. The acceleration is constant and it is equal to g, the gravitational acceleration.

v(t) = vo - gt

Where:

v(t) is the velocity at time t

vo is the initial velocity

If the object is moving downward, the velocity increases. Again, the acceleration is constant and it is equal to g, the gravitational acceleration.

v(t) = vo + gt

This situation is depicted on the attaches picture.

Hence, if a rock is thrown straight up and falls, then its acceleration is the same as at the top of its path and it is equal to g, the gravitational acceleration.

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Earth’s crust and mantle reach thermal equilibrium is the condition that cause the tectonic plates of earth to stop moving. The correct option is a.

The hot magma flows in convection currents due to enormous pressure and heat inside the earth. These currents cause the tectonic plates that make up the earth's crust to move.

Tectonic plates are massive chunks of the Earth's crust and upper mantle. They are composed of oceanic and continental crust.

Earthquakes occur near mid-ocean ridges and large faults that mark the plate boundaries.

When the crust and mantle of the Earth reach thermal equilibrium, the tectonic plates of the Earth stop moving.

Thus, the correct option is a.

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Your question seems incomplete, the missing options are:

In conclusion, to calculate the recommended daily dosage of mercaptopurine for a child weighing 44 lb, we need to convert the weight to kilograms and then multiply it by the recommended initial dose. This results in a dosage of approximately 29.7 mg/day.

The recommended initial dose of mercaptopurine is 1.5 mg/kg/day p.o. To calculate the recommended daily dosage for a child weighing 44 lb, we need to convert the weight from pounds to kilograms.
First, we know that 1 lb is equal to approximately 0.45 kg. So, we can calculate the weight of the child in kilograms by multiplying 44 lb by 0.45 kg/lb.
44 lb * 0.45 kg/lb = 19.8 kg (rounded to one decimal place)
Now that we have the weight in kilograms, we can calculate the recommended daily dosage by multiplying the weight by the recommended initial dose of 1.5 mg/kg/day.
19.8 kg * 1.5 mg/kg/day = 29.7 mg/day (rounded to one decimal place)
Therefore, the recommended daily dosage for a child weighing 44 lb is approximately 29.7 mg/day.
In conclusion, to calculate the recommended daily dosage of mercaptopurine for a child weighing 44 lb, we need to convert the weight to kilograms and then multiply it by the recommended initial dose. This results in a dosage of approximately 29.7 mg/day.

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Answer:

Answer:- Volume of the balloon is 5.78 L.

Solution:- There are 0.24 moles of hydrogen gas in a balloon at 35 degree C and 1.05 atm pressure. It asks to calculate the volume of the balloon.

This problem is based on ideal gas law equation:

P = 1.05 atm, n = 0.24 mole, T = 35 + 273 = 308 K

R =

V = ?

The equation could be rearranged for the volume as:

Let's plug in the values and do the calculations to get the volume of the balloon:

V = 5.78 L

So, the volume of the gas balloon is 5.78 L.

Answer:

A) Conduction

Explanation:

The mitt keeps the heat from reaching your hand through conduction

Answer: A.conduction

Explanation: i got it right on my test!

Answer:

it is becuase light travel faster then sound thus light come to us first

Explanation:

to dlatego, że światło podróżuje szybciej niż dźwięk, to światło dociera do nas jako pierwsze

Answer:D

Explanation: temperature is the measure of hotness and coldness of a body.

Answer:

The answer is "\(0.13562748\)"

Explanation:

Please find the complete question in the attached file.

Using formula:

\(\bold{U_s=\frac{v^2}{rg}}\)

Given:

\(r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}\)

put the value into the above-given formula:

\(U_s= \frac{14.583^2}{160 \times 9.8}\)

    \(= \frac{212.663889}{1568}\\\\=0.13562748\)