what would be the reaction force if a man pushes on the ground to jump up and dunk a basketball?

In this head-on inelastic collision between a car of mass m and a parked station wagon of mass 2m, a fraction of the initial kinetic energy is lost. The exact fraction depends on the masses of the objects involved and the nature of the collision.

In an inelastic collision, the objects stick together or deform upon impact, resulting in a loss of kinetic energy. In this scenario, the car and the station wagon collide head-on, and their bumpers lock together. The masses of the car and the station wagon are given as m and 2m, respectively.

To determine the fraction of initial kinetic energy lost, we need to compare the initial kinetic energy of the system before the collision to the final kinetic energy after the collision. The initial kinetic energy of the system is given by:

Initial kinetic energy = (1/2)m\(v^2\)

After the collision, the car and the station wagon stick together and move as a single object. The final velocity of the combined object can be calculated using the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Since the bumpers lock together, the final velocity of the combined object is given by:

Final velocity = (m*v + 2m*0)/(m + 2m) = v/3

The final kinetic energy of the combined object is:

Final kinetic energy = (1/2)(3m)\((v/3)^2\) = (1/6)\(mv^2\)

The fraction of initial kinetic energy lost can be calculated as:

Fraction of kinetic energy lost = (Initial kinetic energy - Final kinetic energy) / Initial kinetic energy

= ((1/2)\(mv^2\) - (1/6)\(mv^2\)) / (1/2)\(mv^2\)

= (1/3)

Therefore, in this head-on inelastic collision between the car and the station wagon, approximately one-third of the initial kinetic energy is lost.

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Answer:

c) Both the parts will weigh the same

Explanation:

center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts

(might be D if it is cutting against the center of gravity)

Answer:

Being that the moon has a gravitational force of 1.622m/s 2, we multiply the object's mass by this quanitity to calculate an object's weight on the moon. So an object or person on the moon would weigh 16.5% its weight on earth. Therefore, a person would be much lighter on the moon. Conversely, a person is 83.5% heavier on earth than on the moon.

Explanation:

does this help

Sally's mass on Moon is: C. 50 kg

Mass is a measure of the amount of matter that an object or a body is typically made up of. The standard unit of measurement for the mass of an object is kilograms (kg).

Regardless of the location of a person, an object at any given time, mass (amount of matter that they're made up of) is always the same i.e constant.

This ultimately implies that, whether you're on the Moon, space, planet Earth or any other place; your mass would always remain the same or constant.

In this scenario, Sally's mass on Earth is 50 kg. Thus, we can deduce that her mass on Moon would be 50 kg.

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Given that most cars only operate at approximately 20% efficiency and that a typical Iowa cornfield only converts sunlight to chemical storage at a rate of about 1.5%, we are surprisingly efficient at about 25%.

It emits solar energy, which enables life to exist on this planet. This energy includes light and heat. The growth of plants requires sunshine. Both food and the oxygen that plants create are essential for all animals, including humans. The Earth would freeze without the sun's heat.

The electromagnetic radiation that the sun emits is known as solar radiation, also referred to as the solar resource or simply sunshine.

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Answer: The green house effect is best described by option 4 (Energy given off by earth is reflected off of earth's atmosphere back down to the surface).

Explanation:

The green house effect can be described as the energy given off by earth is reflected off of earth's atmosphere back down to the surface.

When energy from the sun passes through the atmosphere, some are absorbed which keeps the earth surface warm. While the rest is reflected back largely by cloud.

The energy which is emitted from the earth surface is called the infrared radiation. Some of the infrared radiation passess through the atmosphere but most is absorbed and re- emitted in all directions by the greenhouse gas molecules and clouds. This effect warms the earth surface and the lower atmosphere. Therefore this statement (Energy given off by earth is reflected off of earth's atmosphere back down to the surface) is correct about greenhouse effect.

For the greenhouse effect to occur, greenhouse gas molecules are mostly needed. Examples of these gases include:

--> Carbon dioxide (CO2),

--> Water vapor (H2O), and

--> Methane (CH4)

Over the years, the excessive human activities has lead to increase in the greenhouse gas molecules which has negatively affected the greenhouse effects.

Answer:

it will be 8ms-1

Explanation:

MaUa+MbUb=MaVa+MbVb

ANSWER

A convex lens acts a lot like a concave mirror. ... A concave lens acts a lot like a convex mirror. Both diverge parallel rays away from a focal point, have negative focal lengths, and form only virtual, smaller images.

When a neuron is in the resting potential state, the neuron is negatively charged on the inside and positively charged on the outside.

When a neuron is not actively responding to an electrical input, which is commonly accepted to be when it is in its resting state, there is widespread consensus that the neuron is in its resting state. The charge on the neuron's inner membrane is now higher than the charge on the neuron's outer membrane. Because of the selective permeability of the cell membrane, the various ion concentrations on either side of the membrane are unable to get balanced with one another.

When the membrane is in its resting state, it is permeable to the passage of potassium ions (K⁺). In the same way as chloride (Cl⁻) ions find it difficult to move through a resting state, sodium (Na⁺) ions also find it difficult to do so. There is a membrane that stops negatively charged proteins with an anion difference of one (A⁻) from passing into neighboring neurons.

A pump is also present in the neuronal cell membrane, and this pump requires energy in order to remove three ions of sodium for every two ions of potassium that enter the cell. A neuron's resting potential can be defined as the voltage difference that exists between the neuron's interior and its outside in the absence of any external influences.

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Computerized axial tomography is a noninvasive roentgenography diagnostic technique.

Tomography can be described as imaging by sections or sectioning that uses any type of penetrating wave. The method is used in biology, radiology, archaeology, geophysics, atmospheric science, oceanography, plasma physics, astrophysics, materials science, quantum information, and other areas of science.

In some cases, the production of images will be based on the mathematical procedure of tomographic reconstruction, such as X-ray computed tomography being produced from projectional radiographs.

Most algorithms come into these two categories: filtered back projection (FBP) and iterative reconstruction (IR). Optical coherence tomography is transmission methods, they do not require movement of the transmitter to need data from different directions.

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Answer:

The horizontal speed of the ball is constant where there is little resistance from the air

Explanation:

From the given parameters of the ball, we have;

The horizontal speed of the ball = 4.0 m/s

The height of the cliff from which the ball is launched = 24.6 meters

The direction in which the ball is launched = Horizontally

The components of the forces acting on the ball are;

The vertical force = The Earth's gravitational attraction

The horizontal force = 0 N (There are no horizontal forces acting on the ball)

According to Newton's first law of motion, the ball will continue in its uniform motion or in its rest state unless acted upon by a force

Therefore, given that there are no horizontal forces component acting on the ball, (little air resistance) the ball will continue with the initial horizontal velocity, such that the horizontal velocity of the ball remains constant.

Answer:

If F is a constant, we can take f = 1

f = m×a

ma = 1

therefore we can say that force is hence proportinal to the product of mass and acceleration.

We want to see if the Trust SSC can archive a higher maximum speed.

Remember the second Newton's law:

Force = mass*acceleration.

And acceleration is the rate of change of the velocity.

Assuming the mass of the Trust SSC does not change, increasing the force would mean that we increase the acceleration, and thus, larger velocities can be reached.

Now there are some problems.

How we do increase the force?.

It is hard to ve precise, mostly because we don't really know how the system works, we just got some given random data that we can't use without context.

Another thing we need to remember, this velocity is measured in only one mile. So because we have a fixed distance to measure it, we only can get larger velocities by increasing the acceleration.

And to increase the acceleration we can increase the force, as discussed, or, decrease the mass.

How to decrease the mass? Using lighter materials.

Now let's see an example on how decreasing the mass would affect the acceleration.

Then an aproximate force is given by:

F = 10,700kg*20.8 m/s^2 = 222,560 N

Now, if we decrease the mass a little bit, for example to 10,000kg, and we do not change the force, the new acceleration will be given by:

10,000kg*a = 222,560 N

a = (222,560 N)/(10,000kg) = 22.3 m/s^2

So decreasing the mass a little, increases the acceleration, which would make a larger maximum velocity.

Concluding, there are two ways of increasing the maximum velocity:

Increasing the force.

Decreasing the mass of the car.

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As per the given values, and uncertainty of the speedometer the actual speed could be 61.33 km/h.

Uncertainty = 2.0 km/h

Measured value = 90 km/h

Calculating the Percent uncertainty -

= (Uncertainty / Measured value) x 100

= (2.0 / 90 ) x 100

= 2.22%

Now, assuming the speedometer has the same percent uncertainty at 60 km/h, this percent uncertainty can be used to determine the range of speeds.

Percent uncertainty = 2.22%

Measured value = 60 km/h

Calculating the range -

= (Percent uncertainty / 100) x Measured value

= (2.22% / 100) x 60

= 1.33

Calculating the Total speed -

= 60 + 1.33

= 61.33

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Complete Question:

If your speedometer has an uncertainty of 2.0 km/h at a speed of 90 km/h ,what is the percent uncertainty? (b) If it has the same percent uncertainty when it reads 60 km/h , what is the range of speeds you could be going?

Impoundment or dams are used to collect the water to enhance the amount of running water. Gravity is used to direct water down a pen stock pipe from a hole in the dam. The turbine is spun by the flowing water, and this rotation of the magnets inside the generator produces power.

Hydroelectric energy, also known as hydroelectric power or hydroelectricity, is a type of energy that uses the force of moving water to produce electricity, such as water running down a waterfall. This force has been utilized by people for ages. Greeks have been grinding wheat into flour for over 2,000 years by using flowing water to turn their mill's wheel.

The majority of hydroelectric power plants feature a water reservoir, a gate or valve to regulate the amount of water that flows out of the reservoir, and an outlet or location where the water ends up after flowing downstream. Just before water rushes over the top of a dam or cascades down a hill, it gains potential energy. Water flowing downhill changes potential energy into kinetic energy. When a turbine's blades are turned by water, electricity is produced and sent to the power plant's users.

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"Compared with a force, a torque involves leverage, rotation distance from an axis of rotation." Correct option is D.

Torque includes the rotation of the object, whereas force is when you push or pull on an object. Torque is the unit of measurement for a rotational or twisting energy. This implies that torque is created whenever an object is turned around an axis.

A torque is a force that is given to a point on an object that is rotated about its axis. The magnitude of a torque is proportional to the magnitude of the applied force and the angle of the force with respect to the plane of rotation.

The power that can cause an object to rotate around an axis is measured in torque. In linear mechanics, force is what drives an object's acceleration. Similar to this, an angular motion is brought on by torque. As a result, torque can be thought of as the rotary counterpart to force.

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Answer:

11 m/s?

Explanation:

The question is not clear, but I am assuming that it is asking for the velocity of a bus traveling for 220 meters in 20 seconds.

You are Given:

Displacement (d) : 220m (in this question, since there is no change in direction, the distance and displacement is the same)

Time (t) : 20 seconds

You want to Find:

Velocity: ???

Equation to use:

velocity = displacement/time

aka. v = d/t

Now just Solve:

v = d/t

v = 220m/20s

v = 11 m/s

This sign of the net charge will be positive on the ball, so the electric field lines will be pointing away from the surface.

The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge. From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in. The vector sum of the individual fields can be used to calculate the electric field from any number of point charges.

Charged matter experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge. Unlike charges attract one another while like charges repel one another.

Hence, this sign of the net charge will be positive on the ball, so the electric field lines will be pointing away from the surface.

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Mechanical ptosis of the left and right eyelids is reported with code(s) H02.413.

Ptosis, also called Blepharoptosis is characterized by the drooping of eyelids due to any abnormality associated with the structures that keep the eyelids elevated.

Ptosis is classified into congenital, aponeurotic, neurogenic, and mechanical ptosis. The illness results in drooping of the upper eyelid due to weight or mass.

It is also caused by many syndromes such as Horner's syndrome and Myasthenia Gravis.

The ICD-10 code is H02.413 which comes under the eye and adnexa category under the WHO. Thus, option A is correct.

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Answer:

Remember a few key things:

1.) Oil comes from plants, but also animals

2.) When heat lamps are done or useless, they go to landfills

3.) Things in landfills go back to the environment after a few years or even decades.

4.) Sometimes there are all-natural oils for heat lamps

Answer:

D. Power is the product of voltage and current.

Explanation:

Electrical power is derived from the product of current and voltage;

  Power  = current x voltage  = I V

I is the current

V is the voltage

R is the resistance

Now;

   V = IR;

     So;

  Power  = I x (IR) = I²R

Also,

   Power  = \(\frac{V^{2} }{R}\)  

The right choice is D

Light will reflect at the same angle off a smooth surface as when it first touches it. The direction of reflected light beams for a flat surface is the same. Specular reflection is what is happening here.

When light reflects off of a surface, it happens. Light will reflect at the same angle it was incident upon if the surface is glossy and smooth.

A smooth polished surface is what is referred to as a reflection when a light ray strikes it and bounces back. Surface reflection occurs when a light beam hits it and then leaves it.

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Answer: The part of color that's reflected is the red that bounces off the paper.

Hope this helps you!!!

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Answer:

v=53.3m/s

Explanation:

Ek=1/2mv²

7.81×10⁴=1/2×55.0v²

v= the square root of 7.81×10⁴/0.5×55.0

v=53.3m/s

The speed of a 55.0 kg skydiver who has 7.81 x 104 J of kinetic energy is 53.29 m/s.

To find the speed, the given values are,

Mass m = 55 Kg

Kinetic Energy = 7.81x 10⁴ J

Speed is the rate of change of distance with time. It is a scalar quantity with magnitude both no direction.

 Speed  = Distance / Time m/s.

The unit is m/s or km/hr or mile/hr.

Formula,

Kinetic energy = Ke = 1/2 mv²

When we solve for v,

v² = 2Ke/m

Substituting the given values,

v² = 2(7.81 x 10⁴) / 55

Simplifying,

v² = 15.62 x 10⁴ / 55

v² = 0.284 x 10⁴

v = 0.53291 x 10⁴

v = 53.29 m/s.

The speed of a 55.0 kg skydiver who has 7.81 x 104 J of kinetic energy is 53.29 m/s.

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Answer:

First Law of Motion.

Explanation:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

In physics, Sir Isaac Newton's First Law of Motion is known as Law of Inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The inertia of a physical object such as a truck is greatly dependent or influenced by its mass; the higher the quantity of matter in a truck, the greater will be its tendency to continuously remain at rest.

Hence, it would take much more force and time for a large truck to get going when the traffic light turns green than it does for a small, compact car. This is an example of the first law of motion.

Answer:

5.765

Explanation:

Answer:

5.765

Explanation:

The weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

The given parameters:

The gravitational force on the satellite is calculated by applying Newton's law of universal gravitation is calculated as;

\(F = \frac{Gm_1m_2}{R^2} \\\\F_1 R_1^2 = F_2R_2^2\\\\F_2 = \frac{F_1 R_1^2 }{R_2^2} \\\\F_2 =\frac{200 \times R_1^2}{(2R_1)^2} \\\\F_2 = \frac{200 \times R_1^2 }{4R_1} \\\\F_2 = 40 \ N\)

Thus, the weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

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The current through resistor R3 is 0.33 A. A circuit with three resistors connected in series is shown below: Circuit diagram of three resistors connected in series As per the given information, R2 has a resistance of 200 ohms and a voltage drop of 30 volts.

Therefore, the voltage drop across R1 is V1 = V - V2 - V3V = voltage supplied to the circuit = voltage drop across R1 + voltage drop across R2 + voltage drop across R3R1 = Resistance of resistor R1.R2 = Resistance of resistor R2 = 200 Ω.V3 = Voltage drop across resistor R3.I3 = Current through resistor R3.To calculate the current in resistor R3, let's follow the steps given below.Step 1: Find the voltage drop across R1.Using Ohm's Law, the voltage drop across R2 is V2 = IR2Substitute the values of V2 and R2 to get the value of current I.I = V2/R2I = 30/200I = 0.15 A

Using Kirchhoff's voltage law, the voltage drop across R1 isV1 = V - V2 - V3V = V1 + V2 + V3Substitute the values of V, V2, and V3 to get the value of V1.V1 = V - V2 - V3V1 = 100 - 30 - V1V1 = 70 VStep 2: Find the current through R3.Using Ohm's Law, the voltage drop across R3 is V3 = I3R3.Substitute the values of V3 and R3 to get the value of current I3.I3 = V3/R3I3 = (V - V1 - V2)/R3I3 = (100 - 70 - 30)/R3I3 = 0.33 A

Therefore, the current through resistor R3 is 0.33 A.

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a) Required chip rateThe processing gain is given by\[G_p = 10{\log _{10}}\left( {{\rm{\Gamma }}{N_{ch}}/{B_c}} \right)\]where Γ is the number of chips per symbol, Nch is the number of hopping channels, and Bc is the chip rate.To determine the chip rate, we must first determine the symbol rate. In this case, the symbol rate is the same as the sampling rate of the PCM modulator, which is 256 × 3.4 kHz = 870.4 kHz.

Since there are Γ chips per symbol, and the processing gain must be at least 23 dB,\[\begin{gathered}

 23{\rm{ dB}} = 10{\log _{10}}\left( {\Gamma {N_{ch}}/{B_c}} \right) \Rightarrow \hfill \\

 10^{23/10} = \Gamma {N_{ch}}/{B_c} \Rightarrow \hfill \\

 {B_c} = \Gamma {N_{ch}}/{{10}^{23/10}} \hfill \\

\end{gathered} \]Let us suppose that we use a pseudo-random sequence of length m = 4. In this case, the number of chips per symbol is given by\[{\Gamma _{DS-SS}} = {2^m} - 1 = 15\]Thus, substituting into the previous equation, we get\[B_c = \left( {15\, \times \,{N_{ch}}} \right)/{6.309}\]Solving for Bc and substituting the processing gain requirement of 23 dB, we get\[B_c \ge 3.194\,{\rm{MHz}}\]Thus, the required chip rate is at least 3.194 MHz.

b) Number of hopping channels if the speech was transmitted by a frequency-hopping spread spectrum (FH-SS) systemThe number of hopping channels can be determined using the relationship\[N_{ch} \le B_c/W\]where W is the frequency range covered by the frequency-hopping sequence. In a FH-SS system, this frequency range must be larger than the baseband bandwidth of the signal, which in this case is 3.4 kHz. If we choose a frequency range of W = 4 kHz, then we get\[N_{ch} \le B_c/W = 3.194/4 = 798.5\]Since Nch must be an integer, we can choose Nch = 798. Therefore, the number of hopping channels is 798.

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Answer:

F=9/5(°C)+32

Explanation:

Lets take an example

\(\\ \sf\longmapsto \dfrac{9}{5}(25)+32\)

\(\\ \sf\longmapsto 9(5)+32\)

\(\\ \sf\longmapsto 45+32\)

\(\\ \sf\longmapsto 77°F\)

The assignment most likely to carry a works cited page is a research paper or an essay that requires the use of external sources.

A works cited page is essential in such assignments because it provides a list of the sources that have been referenced throughout the paper, acknowledging the original authors and their work. This practice is crucial in maintaining academic integrity and avoiding plagiarism. The works cited page should follow a specific citation style, such as APA, MLA, or Chicago, depending on the assignment guidelines provided by the instructor or institution.

In a research paper or essay, a works cited page helps readers verify the accuracy and credibility of the information presented, as well as locate the original sources for further study or understanding. Overall, a works cited page is an essential component of any assignment that relies on external sources to support arguments, ideas, or research findings.

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