Answers
The answers is 30 miles per hour, the driver is speeding the car up, section-H, 12 minutes, section-D, and 65 miles per hour.
Related Questions
describe and explain hyperhydration in athletes as 1) a normal condition, 2) a pre-competition strategy, and 3) a dangerous medical condition.
Answers
Hyperhydration in athletes is a strategic approach used to optimize hydration levels. While it can be a pre-competition strategy, excessive fluid intake can lead to dangerous conditions like hyponatremia. Caution is advised.
Hyperhydration in athletes is a strategic approach used to enhance performance and optimize hydration levels before exercise or competition. It involves increasing fluid intake beyond normal levels to achieve a state of enhanced hydration.
Hyperhydration as a pre-competition strategy involves consuming additional fluids to achieve a fluid surplus in the body, increasing total body water. This can be done through careful planning and timed fluid intake, typically in the hours leading up to an event. The goal is to ensure the body is well-hydrated and prepared for the physical demands of the activity. Hyperhydration strategies may include the consumption of sports drinks, water, and electrolyte-rich fluids.
However, it is important to note that hyperhydration can become a dangerous medical condition if taken to extreme levels. Excessive fluid intake without proper monitoring and guidance can lead to a condition known as hyponatremia, where the blood sodium levels become dangerously diluted. Hyponatremia can cause symptoms ranging from mild discomfort to severe health complications, including organ dysfunction and even death. Therefore, athletes should approach hyperhydration with caution and under the guidance of healthcare professionals or sports nutritionists to prevent the risks associated with overhydration.
In summary, hyperhydration can be a normal condition in athletes, serving as a pre-competition strategy to optimize hydration levels and enhance performance. However, it is essential to understand the potential risks involved and avoid excessive fluid intake to prevent the development of dangerous medical conditions such as hyponatremia.
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Evaluate cos(30°).
ОА. 1.00
ов. 0.87
ОС. 0.50
ОС
D. 0.58
Answers
Answer:
The answer for cos(30°) is 0.87
In a future lab, we will discuss how the potential difference across a membrane changes in time when an action potential is applied at the end of an axon. Combining the temporal response to the spatial characteristics discussed in this lab, we can determine how fast a voltage pulse travels along an axon. The speed of this pulse, as it turns out, is proportional to the length constant ) λ, which approximately equals √rhomrt/2rhoa as we found in the second part of 2pa the lab. Again, rhom is the resistivity of the axon membrane, rhoa is the resistivity of the axoplasm inside the axon, r is the radius of the axon, and t is the thickness of the membrane. The speed of a nerve pulse, then, is greater in neurons with thicker membranes -- for example, wrapping an axon in insulating myelin effectively increases the membrane thickness, which thus increases the speed of the pulse -- or in axons with larger radii. Increasing either the radius or increasing membrane thickness yields pulses with greater speed, qualitatively, because there is less leakage of the ions through the membrane when the membrane resistance is larger or the axon resistance is smaller. Hence, the pulse requires less amplification along its length by depolarization -- and therefore the pulse moves faster. (Again, depolarization is the change in potential difference across the membrane due to ions moving into and out of the axon.) The neurons of giant squids, for example, consist of axons with very large radii, which allows the squid to react very quickly when confronted with a predator. Assuming no change in the resistivities or membrane thickness of the axon, by what factor must the radius of the axon increase such that the speed of the pulse increases by a factor of 11?
Answers
The radius of the axon must increase by a factor of 121 to increase the speed of the pulse by a factor of 11.
To find the factor by which the radius of the axon must increase to increase the speed of the pulse by a factor of 11, we will use the formula you provided:
λ ≈ √(rhom * r) / 2 * rhoa
Since the speed of the pulse is proportional to λ, we can set up a ratio:
λ₁ / λ₂ = Speed₁ / Speed₂
Given that Speed₂ = 11 * Speed₁, we can substitute and solve for the radius:
(√(rhom * r₁) / (2 * rhoa)) / (√(rhom * r₂) / (2 * rhoa)) = 1 / 11
Simplify and solve for r₂:
√(r₁ / r₂) = 1 / 11
Square both sides:
r₁ / r₂ = 1 / 121
Since we want the factor by which the radius must increase, we will solve for r₂ / r₁:
r₂ / r₁ = 121
So, the radius of the axon must increase by a factor of 121 to increase the speed of the pulse by a factor of 11.
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what is the SI unit for moment
Answers
Answer:
Newton Metre
Explanation:
star a and star b have measured stellar parallax of 0.58 arc second and 0.73 arc second, respectively. which star is closer?
Answers
Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.
What is stellar parallax and distance measurement using stellar parallax?To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.
A straightforward correlation exists between the distance of a star and parallax angle:
\(d=\frac{1}{p}\)
The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.
Stellar parallax of star A= 0.58 arcseconds
Stellar parallax of star B= 0.73 arcseconds
So, on applying the formula,
The distance of the star A= 1.72pc
And the distance of the star B= 1.36pc
Therefore, star B is closer than star A.
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What is the wave speed of a wave traveling with a frequency of 37 Hz and 2 points
a wavelength of 6 m? (Remember your units!)
Answers
Answer:
222m/s
Explanation:
The speed of a wave is calculated using the forumula:
v = fλ
Lets substitute in our values:
v = 37 × 6
Which is equal to
v = 222m/s
A 23-N force is applied to a 7-kg object to move it with a constant velocity of 6.1 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Answers
Given:
The applied force is F = 23 N
The mass of the object is m = 7 kg
The object moves with a constant velocity of v = 6.1 m/s
The acceleration due to gravity is g = 10 m/s^2
Required: The coefficient of friction between the object and the surface.
Explanation:
The object moves at a constant velocity, so the acceleration will be zero.
The equation of motion can be written as
\(\begin{gathered} F-f\text{ = ma} \\ F-f\text{ =m}\times0 \\ F-f=0 \\ F=f \end{gathered}\)So, the applied force will be equal to the frictional force.
The coefficient of friction can be calculated as
\(\begin{gathered} F\text{ = }\mu mg \\ \mu=\frac{F}{mg} \end{gathered}\)On substituting the values, the coefficient of friction will be
\(\begin{gathered} \mu=\frac{23}{7\times10} \\ =\text{ 0.33} \end{gathered}\)Thus, the coefficient of friction is 0.33
Final Answer: The coefficient of friction between the object and the surface is 0.33.
List and explain at 5 hazards
of radioactivity
Answers
Answer:
1 can damage chromosomes
2 reduction in white blood cells ( will recover In Couple of days )
3 sickness
4 Temporary Reduction of Resistance.
Have a great Day!!
A motorcycle starts from rest and gains a velocity of 40m/s in 8 seconds. Find (i) acceleration and (ii) distance travelled by the motorcycle.
Answers
• Initial velocity (u) = 0 m/s
• Final velocity (v) = 40 m/s
• time (t) = 8s
Acceleration :\(\implies \sf a = \dfrac{\Delta v}{ t} \\ \)
\(\implies \sf a = \dfrac{v - u}{ t} \)
\(\implies \sf a = \dfrac{40 - 0}{ 8} \)
\(\implies \sf a = \dfrac{40}{ 8} \)
\(\implies \bf a = 5 \: {ms}^{ - 2} \)
• Distance travelled by the motorcycle:\( \longrightarrow \sf {v}^{2} - {u}^{2} = 2as \\ \)
\(\longrightarrow \sf {(40)}^{2} - {(0)}^{2} = 2 \times5 \times s \\ \)
\( \longrightarrow \sf 1600 = 10s\)
\(\longrightarrow \sf s = \dfrac{1600}{10} \)
\(\longrightarrow \bf s = 160 \: m\)
Charge q1 = +2.00 μC is at -0.500 m along the x axis. Charge q2 = -2.00 μC is at 0.500 m along the x axis. Charge q3 = 2.00 μC is at 0.500 m along the y axis. What is the magnitude of electrical force on charge q3 due to the others?
Answers
The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons.
How to calculate the electrical force experimented on a particle
The vector position of each particle respect to origin are described below:
\(\vec r_{1} = (-0.500, 0)\,[m]\)
\(\vec r_{2} = (+0.500, 0)\,[m]\)
\(\vec r_{3} = (0, +0.500)\,[m]\)
Then, distances of the former two particles particles respect to the latter one are found now:
\(\vec r_{13} = (+0.500, +0.500)\,[m]\)
\(r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}\)
\(r_{13} =\frac{\sqrt{2}}{2}\,m\)
\(\vec r_{23} = (-0.500, +0.500)\,[m]\)
\(r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}\)
\(r_{23} =\frac{\sqrt{2}}{2}\,m\)
The resultant force is found by Coulomb's law and principle of superposition:
\(\vec R = \vec F_{13}+\vec F_{23}\) (1)
Please notice that particles with charges of same sign attract each other and particles with charges of opposite sign repeal each other.
\(\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}\) (2)
Where:
\(k\) - Electrostatic constant, in newton-square meters per square Coulomb.\(q_{1}\), \(q_{2}\), \(q_{3}\) - Electric charges, in Coulombs.\(r_{13}\), \(r_{23}\) - Distances between particles, in meters.\(\vec u_{13}\), \(\vec u_{23}\) - Unit vectors, no unit.If we know that \(k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}\), \(q_{1} = 2\times 10^{-6}\,C\), \(q_{2} = 2\times 10^{-6}\,C\), \(q_{3} = 2\times 10^{-6}\,C\), \(r_{13} =\frac{\sqrt{2}}{2}\,m\), \(r_{23} =\frac{\sqrt{2}}{2}\,m\), \(\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)\) and \(\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\), then the vector force on charge \(q_{3}\) is:
\(\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\)
\(\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]\)
\(\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]\)
And the magnitude of the electrical force on charge \(q_{3}\) (\(R\)), in newtons, due to the others is found by Pythagorean theorem:
\(R = 0.102\,N\)
The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons. \(\blacksquare\)
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Which of the following shows the relationship between work and energy?
O A. Work = total energy
B. Work = gravitational potential energy
C. Work = change in kinetic energy
D. Work = change in nonconservative forces
Answers
A rocket blasts off and moves straight upward from the launch pad with constant acceleration. After 2.7 s the rocket is at a height of 91 m. What is the magnitude of the rocket's acceleration? Express your answer using two significant figures. a=
Answers
The magnitude of the rocket's acceleration is 26.2 m/s² if rocket blasts off and moves straight upward from the launch pad with constant acceleration
The height of a rocket from the ground as a function of time can be determined using the kinematic equations. When the rocket blasts off and moves straight upward from the launch pad with constant acceleration, its height can be given as below:h = vit + 1/2 at²
where h = height of the rocket from the launch pad, vi = initial velocity, a = acceleration, and t = time. Let the rocket's initial velocity be vi = 0 m/s.
Therefore, the expression for the rocket's height simplifies to:h = 1/2 at²On substituting the given values, 91 m for the height of the rocket after 2.7 s, the expression becomes:91 m = 1/2 a (2.7 s)²91 m = 1/2 a (7.29 s²)a = 2(91 m) / (7.29 s²) = 26.2 m/s²
Therefore, the magnitude of the rocket's acceleration is 26.2 m/s² (Answer).
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Rank these circuits on the basis of their resonance frequencies. Rank from largest to smallest. To rank items as equivalent, overlap them. View Available Hint(s) L-0.5 H L-1.0H L1.0HL 2.0H L 1.0H L 1.5 H Part B Each circuit is driven at its resonance frequency by a 100 VmS AC power supply. Rank these circuits on the basis of their maximum current. Rank from largest to smallest. To rank items as equivalent, overlap them
Answers
Part A:
The resonance frequency is the frequency at which the circuits oscillate naturally. The frequency of the resonance is directly proportional to the values of L and C, as given by the relation ω0 = (1/LC)^0.5. Given circuits have different inductances and hence they will have different resonance frequencies as well. The given circuits can be ranked in the order of the largest to smallest resonance frequency as given below:1.
L-1.0 H2. L-0.5 H3. L1.0H4. L 1.5 H5. L 2.0H
Part B:
The maximum current through the circuit is directly proportional to the Q-factor, which is given by
Q = R (1/LC)^0.5.
Thus, the higher the Q-factor of the circuit, the larger the maximum current through the circuit. The given circuits can be ranked in the order of the largest to smallest maximum current as given below:1.
L 1.0H2. L-0.5 H (same as L1.0H)3. L-1.0 H4. L 1.5 H5. L 2.0H.
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a balloon has a volume of 4.0 liters at 24.0°c. the balloon is heated to 48.0°c. calculate the new volume of the balloon (in liters).
Answers
The new volume of the balloon at 48.0°C is approximately 4.83 liters.
To calculate the new volume of the balloon, we can use the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
Since the amount of gas and the pressure are constant in this problem, we can use the simplified version of the ideal gas law: V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume (what we're trying to find), and T2 is the final temperature.
Converting the temperatures to Kelvin by adding 273.15, we get: V1/T1 = V2/T2, 4.0 L / (24.0 + 273.15) K = V2 / (48.0 + 273.15) K. Solving for V2, we get: V2 = (4.0 L * (48.0 + 273.15) K) / (24.0 + 273.15) K, V2 ≈ 4.83 L
Therefore, the new volume of the balloon at 48.0°C is approximately 4.83 liters.
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is time a scaler or a vector? explain.
Answers
Answer:
scalar Besause it has magnitude but no direction
i swimmers swims 180m in 20 seconds how much meters does she swim in a second
Answers
Answer:
20
Explanation:
20m= 1 seconds
40m= 2 seconds
180÷9=20
3. A baseball has a mass of 0.5 kg and a velocity of 30 m/s to the right collides with a bat that has a mass of 1.5 kg with a velocity of 20m/s to the left. If after the collision the baseball has a new velocity of 20 m/s to the left.
а. What is the bat's momentum after the collision?
b. What is the bat's new velocity?
Answers
(a) The momentum of the bat after collision is 5 kgm/s to the left
(b) The new velocity of the bat is 3.33 m/s to the left
What is momentum?
Momentum is the product of mass and velocity.
(a) To calculate the momentum of the bat after collision, we use the formula below
Formula:
M' = mu+m'u'-mv.................... Equation 1Where:
m = Mass of the basebalu = Initial velocity of the baseballm' = Mass of the batu' = Initial velocity of the batv = Final velocity of the baseballM' = Final momentum of the batFrom the question,
Note: Taking right direction as positive
Given:
m = 0.5 kgu = 30 m/su' = -20 m/sm' = 1.5 kgv = -20 m/sSubstitute these values into equation 1
M' = (0.5×30)+(-20×1.5)-(-20×0.5)M' = 15-30+10M' = -5 kgm/s(b) To calculate the new velocity of the bat, we use the formula below
Formul:
v' = M'/m'................ Equation 2Where:
v' = New velocity of the batSubstitute into equation 2
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An arrow can only be shot by pulling it backward. When life is dragging you back with difficulties, it means it's going to launch you into something great. So just focus, and keep aiming.
Answers
That's a great analogy!
The quote you mentioned highlights the idea that challenges and difficulties in life can sometimes serve as a precursor to achieving something remarkable or experiencing personal growth. Just like an arrow, which needs to be pulled back before it can be launched forward with speed and precision, setbacks and obstacles can provide the momentum and direction needed for progress.
During tough times, it's important to stay focused on your goals and maintain a positive mindset. Instead of allowing difficulties to discourage you, view them as opportunities for learning and development. By staying determined and persevering through adversity, you increase your chances of reaching new heights and accomplishing great things.
Remember, success often comes after overcoming obstacles, and setbacks can provide valuable lessons and insights that contribute to personal and professional growth. So, keep your aim steady, embrace challenges as stepping stones, and maintain your focus on the target you're striving to achieve.
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17)
A positively charged ion will bond with
A)
a negatively charged ion.
Elin
B)
a neutral atom.
C)
another positively charged ion.
D)
nothing else.
Answers
Answer:
Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... the complete transfer of valence electron(s) between atoms. It is ... The compound is neutral overall, but consists of positively charged ions called cations and negatively ... an ion with net negative charge, having more electrons than protons.
Explanation:
suppose a parachutist is falling toward the ground, and the downward force of gravity is exactly equal to the upward force of air resistance. which statement is true?
Answers
Suppose a parachutist is falling toward the ground, and the downward force of gravity is exactly equal to the upward force of air resistance. In this scenario, the true statement is that the parachutist has reached terminal velocity.
Terminal velocity is the constant speed attained by a freely falling object when the opposing forces of gravity and air resistance become equal. At this point, there is no net force acting on the parachutist, and the acceleration becomes zero. As a result, the parachutist maintains a constant speed during the descent.
When a parachutist initially jumps out of the aircraft, the downward force of gravity exceeds air resistance, and they accelerate towards the ground. As their speed increases, so does the air resistance acting against them. Eventually, these two forces balance each other out, and the parachutist reaches terminal velocity, allowing them to fall at a constant speed until they deploy their parachute to slow down and land safely. The true statement is that the parachutist has reached terminal velocity.
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The coefficient of static and kinetic friction between a 3. 9 kg box and a horizontal desktop are0. 6 and 0. 3 respectively. What is the force of friction on the box when a 9. 8 N horizontal push is applied to the box
Answers
38.2 is the force of friction on the box when a 9. 8 N horizontal push is applied to the box
What does friction force mean?
The force that opposes the relative motion of two surfaces of an object when they come into contact is known as friction. Always acting in the opposite direction from the direction of applied force is frictional force.
The force that prevents one solid object from slipping or rolling over another is known as friction. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion. The angle of friction is the resultant of normal reaction and limiting friction with the normal reaction.
The force of friction will be given by : 9.8*3.9 i.e. 38.2
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Plz help!
A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?
Answers
The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:
Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.
Indicate in the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.
Vector A.
Aₓ = 100.0 m
Vector B.
B_y = -300.0 m
The negative sign indicates that it goes in the negative direction of the y-axis
Vector C.
We use trigonometry.
The angle measured from the positive side of the x-axis counterclockwise is
θ = 180 + 30 = 210
sin 210 = \(\frac{C_y}{C}\)
cos 210 = \(\frac{C_x}{C}\)
C_y = C sin 210
Cₓ = C cos 210
C_y = 150.0 sin 210 = -75.0 m
Cₓ = 150.0 cos 210 = -129.9 m
Vector D.
The angle from the positive side of the x-axis counterclockwise.
θ = 180-60 = 120º
sin 120 = \(\frac{D_y}{D}\)
cos 120 = \(\frac{D_x}{D}\)
D_y = D sin 120
Dₓ = D cos 120
D_y = 200.0 sin 120 = 173.2 m
Dₓ = 200.0 cos 120 = -100.0 m
we add the component with algebraic sum.
x = Aₓ + Cₓ + Dₓ
y = B_y + C_y + D_y
x = 100 - 129.9 -100 = -129.9 m
y = -300 - 75.0 + 173.2 = -201.8 m
We construct the resulting vector.
We use the Pythagorean theorem for the Modulus.
\(R+ \sqrt{x^2 +y^2}\)
R = \(\sqrt{129.9^2 + 201.8^2 }\)
R = 239.99 m
We use trigonometry for the angle.
tan θ = \(\frac{y}{x}\)
θ = \(tan^{-1} \frac{y}{x}\)
θ = \(tan^{-1} \frac{201.8}{129.9}\)tan-1 (201.8 / 129.9)
θ = 57.2º
Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.
θ = 270 - θ'
θ = 270 - 57.2
θ = 212.8º
In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
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The net force on an object is 200 N. The object accelerates at 10 m/s? What is the mass of the object ?
Answers
Answer:
F=200 N
a=10m/s2
F=ma
m=F/a=200/10=20m
Explanation:
What is the name for a burst of activity on an EEG in the early stages of sleep?
gamma waves
sleep spindles
REM
lingering activation
Answers
The name for a burst of activity on an EEG in the early stages of sleep is "sleep spindle".
What is sleep spindle?A burst of brain activity during non-rapid eye movement (NREM) sleep is known as a sleep spindle and can be seen on an electroencephalogram (EEG). Although it can occur in other NREM sleep stages as well, it is a hallmark of Stage 2 sleep.
Sleep spindles are characterized by a burst of rhythmic brain activity that spans from 11 to 16 Hz and are short (often lasting only a few seconds). The thalamus, a region of the brain that is essential for transmitting sensory data to the cerebral cortex, is the source of this activity. The thalamus absorbs sensory input during sleep and modifies the information flow to the cortex, enabling the brain to filter out unimportant inputs and concentrate on significant ones.
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How can you tell if a crown is made of solid gold?
Answers
Answer: bite it and if it bend its fake
Explanation:
Answer
if it........ shines bright like a diamond
Fuel crises will occur in future because of a. over use of petroleum
b. use of solar energy
c. over use of bio-gas
d. use of hydro-energy
Answers
What is natural and artificial sound?
Answers
Answer:
The Natural sounds contained sounds of living objects. The Musical sounds contained notes of different musical instruments, whereas the Artificial sounds were daily object-like sounds.
Explanation:
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A transparent material has a refractive index of 1.03. What is the speed of light in that material? Express your answer in km/s and keep three significant digits.
Answers
The speed of light in a transparent material with a refractive index of 1.03 is 299,236 km/s.
Refractive index is a dimensionless value that represents the ratio of the speed of light in a vacuum to its speed in a particular medium. The formula for calculating the speed of light in a transparent material is given by:
Speed of light in material = (Speed of light in vacuum) / Refractive index of the material
We know that the speed of light in vacuum is 299,792 km/s. Therefore, we can substitute the values in the above formula to get:
Speed of light in material = 299,792 km/s / 1.03
Solving this equation, we get the speed of light in the transparent material to be 299,236 km/s. It is important to note that the speed of light in any transparent material is always less than its speed in a vacuum because the refractive index of any material is always greater than 1.
In conclusion, the speed of light in a transparent material with a refractive index of 1.03 is 299,236 km/s. The refractive index is a dimensionless value that represents the ratio of the speed of light in a vacuum to its speed in a particular medium.
The formula for calculating the speed of light in a transparent material is given by the equation: Speed of light in material = (Speed of light in vacuum) / Refractive index of the material.
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An artist makes necklaces. she packs each necklace in a small jewelry box that is1 3 4 inches by inches by inch.2 1 4 3 4 a department store ordered 270 necklaces. the artist plans to ship the necklaces to the department store using flat-rate shipping boxes from the post office. which of the flat-rate boxes should she use to minimize her shipping cost?
1. read the problem statement. what additional information will you need to solve this problem?
2. discuss this information with your group. make a plan for using this information to find the most inexpensive way to ship the jewelry boxes. once you have agreed on a plan, write down the main steps.
i need help now
Answers
To determine the most inexpensive way to ship the jewelry boxes, we need to know the dimensions and cost of the available flat-rate shipping boxes from the post office. Once we have this information, we can compare the cost of shipping 270 jewelry boxes using each of the available flat-rate shipping boxes and choose the one with the lowest cost.
Assuming we have this information, here is a plan for finding the most inexpensive way to ship the jewelry boxes:
1. List the available flat-rate shipping boxes from the post office along with their dimensions and cost.
2. Calculate the volume of each jewelry box by multiplying its dimensions (1 3/4 inches by 2 1/4 inches by 3/4 inch) to get 2.53125 cubic inches.
3. Calculate the total volume of the 270 jewelry boxes by multiplying the volume of one jewelry box by the number of boxes (2.53125 x 270 = 683.4375 cubic inches).
4. For each flat-rate shipping box, calculate the number of jewelry boxes that can fit inside by dividing the volume of the shipping box by the volume of one jewelry box.
5. Calculate the cost of shipping 270 jewelry boxes using each of the available flat-rate shipping boxes.
6. Choose the flat-rate shipping box with the lowest cost.
To know more about cost of shipping, refer
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What type of energy is energy in the form of motion.
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Answer:
the answer is kinetic energy