The mass of an object is a measure of the amount of matter in the object, while weight is the force exerted on an object due to gravity: the mass of an object will remain the same regardless of its location in the universe, while its weight will vary depending on the gravitational force at that location. 
Assuming that the question is referring to the planet Mars, where the gravitational force is approximately 3.8 N/kg, we can calculate the weight of each object based on their mass. For example, if we have an object with a mass of 1 kg, its weight on Mars would be:
Weight = Mass x Gravity
Weight = 1 kg x 3.8 N/kg
Weight = 3.8 N
Therefore, the weight of a 1 kg object on Mars would be 3.8 N. Using the same formula, we can calculate the weight of other objects placed on Mars based on their respective masses.
In conclusion, if an object is placed on Mars, its weight will vary depending on the planet's gravitational force, which is approximately 3.8 N/kg. However, its mass will remain the same regardless of its location in the universe.
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A football player has a mass of 65 kg and is moving with a velocity of 5 m/s. What is the player’s momentum? 13 kg • m/s 70 kg • m/s 305 kg • m/s 325 kg • m/s
Answer:
d. 325 kg • m/s
Explanation:
Angela and Blake are running toward each other from
15 m away. At time t = 0 s, Angela runs to the right at 5
m/s and Blake runs to the left at 3 m/s
Write an equation for Angela?
Answer:
Kindly check explanation
Explanation:
Given the following information :
Distance between Angela and Blake = 15m
Angela's speed = 5m/s at t = 0
Angela's direction = Right = positive
Blake's speed = 3m/s at t = 0
Blake's direction = left = negative
Position or distance = speed × time
Hence,
Combined speed = (3 + 5) = 8m/s
Distance = 15m
Time = distance / speed
Time = 15 / 8
Time they meet = 1.875 seconds
Distance covered by Angela :
Speed × time
= 5 × 1.875 = 9.375 meters
The equation for the distance traveled by Angela is 5t and the distance covered by Angela is 9.375 m.
The given parameter:
the distance between Angela and Blake = 15 mspeed of Angela, \(V_A\) = 5 m/sspeed of Blake, \(V_B\) = 3 m/slet the time at which Angela and Blake meet = t
The equation for the distance traveled by Angela = 5t
The time (t) at which Angela and Blake meet will be calculated using relative velocity concept:
since they are closing the distance together, we will add their velocities
(i.e they are working together and not against each other)
\((V_A +V_B) t = 15\\\\(5 + 3) t = 15\\\\8t = 15\\\\t = \frac{15}{8} \\\\t = 1.875 \ s\)
The distance covered by Angela = 1.875 s x 5 m/s = 9.375 m
The distance covered by Blake = 1.875 x 3 m/s = 5.625 m
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__________ refers to the distinctive character of a sound, or the quality that allows one to distinguish it from other sounds of similar pitch and loudness.
A ball is rolled twice across the same level laboratory table and allowed to roll off
the table and strike the floor. In each trial, the time it takes the ball to travel from the
edge of the table to the floor is accurately measured. [Neglect friction.]
a) In trial A, the ball is traveling at 2.50 meters per second when it reaches
the edge of the table. The ball strikes the floor 0.391 second after rolling
off the edge of the table. Calculate the height of the table. (Organize your
given variables. Do not mix x-variables with the y-variables)
Answer:
Explanation:
To calculate the height of the table in this scenario, we can use the equations of motion. Let's define the variables first:
Initial velocity (u) = 2.50 m/s (given)
Time taken to reach the floor (t) = 0.391 s (given)
Acceleration due to gravity (g) = 9.8 m/s² (assuming the ball falls freely near the surface of the Earth)
Now, we can use the kinematic equation:
h = u * t + (1/2) * g * t²
Plugging in the given values, we have:
h = (2.50 m/s) * (0.391 s) + (1/2) * (9.8 m/s²) * (0.391 s)²
Simplifying the equation:
h = 0.97875 m + 0.07511 m
h = 1.05386 m
Therefore, the height of the table is approximately 1.05386 meters.
an old-fashioned (vinyl) record rotates at a constant rate of 45 rpm. if it plays music for 21 min, how far does a point on the edge travel in meters? (assume the radius of the record is 9 cm.)
The speed of a vintage turntable is 33 1/3 mph (rotational speed). b) Calculate the duration of a 45 mph record.
What does spinning mean?a circular motion, particularly one centred on a fixed point, or the induction of a circular motion: To open the door, turn the handle 180 degrees. Axle-driven wheels revolve around them. The spacecraft circles the planet slowly as it rotates.
What is an example of rotation?Geometry can be used to explain rotation's meaning in mathematics. As a result, it is described as an object moving around with a centre or axis. Any rotation is regarded as the movement of a certain space which freezes as least one point. We are aware of the earth's rotation.
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a child kicks a soccer ball across the grounds the ball travels 10.0 meters in 0.56 seconds. what is the speed of the ball
a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s, what is their acceleration?
If a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s, then the acceleration of the rock would be 8 meters/second².
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s,
initial velocity of rock = 0 m/s
displacement = 100 meters
time = 5 seconds
s = ut + 0.5at²
100 = 0 + 12.5a
a = 100/12.5
= 8 meters/second²
Thus, the acceleration of the rock would be 8 meters/second².
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if the mass of object is 135 kg then its weight on earth will be?
Answer:
1323
Explanation:
we know ,
weight = m*g
= 135 * 9.8 ( acceleration due to gravity in earth is 9.8 m/S2)
= 1323 N
William drew a diagram of a box containing a gas for his science project. His drawing is shown.
as you walk to the grocery store you walk 800m north, 600m east and 200m south at a speed of 1m/s. what is your velocity?
According to the question as you walk to the grocery store you walk 800m north, 600m east, and 200m south at a speed of 1m/s. Then your velocity will be ( V = 0.5m/sec )
Velocity is the directional pace of an object in movement as an indication of its price of alternate in function as located from a specific body of reference and as measured by a particular widespread of time.
To find the velocity follow the following steps:
Displacement of 800m north, 600m east, and 200m south from the Cartesian coordination is given as 600\(\sqrt{2}\)
Velocity = displacement / time
Therefore time = distance / speed
Time = 800 + 600 + 200 / 1
Time = 1600s
Therefore velocity = 600\(\sqrt{2}\) / 1600
Velocity = 0.5m/sec
A Cartesian coordinate gadget in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates, which are the signed distances to the factor from constant perpendicular oriented strains, measured in the equal unit of duration.
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5. What is the velocity of a Nolan Catholic football player if he runs 200.0 m in 24.0 s?
Answer:
\( \boxed{ \bold{ \huge{ \boxed {\sf{8.33 \: m \:/s \: }}}}} \)
Explanation:
Distance travelled = 200 metre
Time taken = 24 second
Velocity = ?
Finding the velocity
\( \boxed{ \sf{velocity = \frac{distance \: travelled \: }{time \: taken}}} \)
\( \dashrightarrow{ \sf{velocity = \frac{200 \: m}{24 \: s} }}\)
\( \dashrightarrow{ \sf{velocity = 8.33 \: m/s}}\)
Hope I helped!
Best regards!
How is the 3rd law different from the 1st and 2nd laws?
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Explanation:
a circular loop of wire is placed in a magnetic field so that the field points in a direction perpendicular to the plane of the loop. if the magnitude of the field is 0.621 t, and the radius of the loop is 4.37 cm, find the magnetic flux through the loop.
The magnetic flux through the loop is 0.00371 Wb.
To find the magnetic flux through the circular loop of wire, we can use the formula:
Φ = BAcosθ
where Φ is the magnetic flux, B is the magnitude of the magnetic field, A is the area of the loop, and θ is the angle between the magnetic field and the normal plane of the loop.
In this case, the field is perpendicular to the plane of the loop, so θ = 90° and cosθ = 0. Therefore, the formula simplifies to:
Φ = BA
We are given that the magnitude of the field is 0.621 T and the radius of the loop is 4.37 cm. To find the area of the loop, we can use the formula for the area of a circle:
A = πr²
where r is the radius of the circle. Substituting the values, we get:
A = π(0.0437 m)² = 0.00599 m²
Note that we converted the radius from cm to m to be consistent with the units of B (T = N/(m·s)).
Now we can calculate the magnetic flux:
Φ = BA = (0.621 T)(0.00599 m²) = 0.00371 Wb
Therefore, the magnetic flux through the loop is 0.00371 Wb.
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A roller coaster car has a mass of 400kg and a speed of 15m/s What will be the P.E of this roller coaster car at its highest point ,where KE =0 at that point
Answer:
3000J
Explanation:
Given parameters:
mass = 400kg
speed = 15m/s
Unknown:
P.E at the highest point of the roller coaster = ?
Solution:
Due to the law of conservation of energy, the potential energy at the highest point can be solved using the formula of the kinetic energy
Potential energy = \(\frac{1}{2}\) mv²
m is the mass
v is the velocity
Potential energy = \(\frac{1}{2}\) x 400 x 15 = 3000J
How much is the unit price for an order of 80 t-shirts that cost $300? 
help me plisssssssss!!!!!!!! 
 
                                                Unit price = (total cost) / (number of units) . . . The unit is 'dollars per shirt'.
Unit price = ($ 300) / (80 shirts)
Unit price = $3.75 / shirt
What are two factors that must be kept the same (constant) between both groups?
Must be given 30 mL of water for 7 days. 
c. What is the independent variable? 
d. What is the dependent variable? 
e. Which is the experimental group? 
f. Which is the control group? 
g. What must be done to make this experiment valid?
Answer:
Which is the control group?
g. What must be done to make this experiment valid?
Explanation:
If the surface of a moon is impacted by meteorites at a constant rate, the density, or quantity per unit of area, of impact craters on the moon’s surface will increase over time. How can this information be used to determine the relative age of a moon’s surface?.
The number of impact craters on a moon's surface can be used to determine the relative age of that surface. This is because the rate at which impact craters are formed is roughly constant over time. Therefore, the more impact craters a surface has, the older it is.
To determine the relative age of a moon's surface, scientists can compare the number of impact craters on that surface to the number of impact craters on other surfaces of known age. For example, the Moon's surface is covered in impact craters, and the oldest parts of the Moon's surface have the most impact craters. The youngest parts of the Moon's surface have the fewest impact craters.
Scientists can also use the size of impact craters to determine the relative age of a moon's surface. Larger impact craters are formed by more energetic impacts, and these impacts are less frequent than smaller impacts. Therefore, older surfaces are more likely to have larger impact craters.
The relative age of a moon's surface can also be determined by studying the composition of the surface material. Older surfaces are more likely to be covered in material that has been modified by the impacts of meteorites. This material is often more heavily cratered and has a different composition than the material on younger surfaces.
By combining all of these methods, scientists can get a good estimate of the relative age of a moon's surface. This information can be used to study the history of the moon and to understand the processes that have shaped its surface.
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Meteoric material dates the formation of the solar system at about_____ billion years.
According to meteoric material, the solar system was formed around 4.6 billion years ago.
What substance makes up a meteorite?With just trace levels of sulphide and carbide minerals, they are primarily composed of iron-nickel metal. Many asteroids melted during the radioactive element decay in the early solar system, and the iron they carried, being dense, sank to the centre to create a metallic core.What is the term for meteorite metal?Meteoric iron, also known as meteoritic iron, is a native metal and a protoplanetary-disk remnant from the early universe that is found in meteorites. It is mostly composed of the metals iron and nickel, primarily in the crystalline phases kamacite and taenite.learn more about meteorite here
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Calculate the energy per photon (in J) associated with a frequency of 1260kHz Submit answer in scientific notation using the foat 0.00×10∧ 0(e.g.0.000123=1.23×10 ∧
−4). Omit units and spaces.
The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.
To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:
Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz
Now, we can substitute the values into the equation:
E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)
E = 8.33929859 × 10^-28 J
The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:
E = (8.33929859 × 10^-28 J) × (10^3)
E = 8.33929859 × 10^-25 J
Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.
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need help please and thank you
 
                                                Answer:
0.13m/s
Explanation:
jhghffhjffhjfhjfhjf
A 66 kg student traveling in a car with a constant velocity has a kinetic energy of 1. 1 104 J. What is the speedometer reading of the car in km/h?
Answer:
65.74 km/hr
Explanation:
KE = 1/2mv²
I'm assuming the KE is 1.1x10⁴ J ? It's hard to tell from what you wrote.
1.1x10⁴ J = 1/2(66 kg)v²
v² = 2(1.1x10⁴ J) / (66 kg) = 333.3 m²/s²
v = √333.3 m²/s² = 18.26 m/s
convert m/s to km/hr:
18.26 m/s x 1 km/1000 m x 3600 s/hr = 65.74 km/hr
Calculate the orbital period of a satellite circling the Earth at an altitude of 3500 km. Answer to the nearest minute. Show your work.
The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes
How do i determine the orbital period?The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:
Altitude = 3500 kmRadius of earth = 6400 KmSemi-major axis (a) = Radius + Altitude = 6400 + 3500 = 9900 Km = 9900 × 1000 = 9900000 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Mass of earth (M) = 5.987×10²⁴ KgOrbital period (T) = ?T² = (4π² / GM) × a³
T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³
Take the square root of both sides
T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]
T = 9789.15 s
Divide by 60 to express in minutes
T = 9789.15 / 60
T = 163 minutes
Thus, we can conclude that the orbital period of the satellite is 163 minutes
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Completing a turn requires that you Select one: a. use more than one lane as you turn the corner. b. accelerate gently about halfway through the turn. c. accelerate throughout the turn. d. press the brake pedal throughout the turn. Previous page
The correct option is b. accelerate gently about halfway through the turn.
Completing a turn requires that you steer the vehicle smoothly and gradually, maintaining a safe and appropriate speed throughout the turn, and then straightening the wheels as you exit the turn. It is important to use signals to indicate your intentions to other drivers and to check for any pedestrians, cyclists, or other potential hazards before turning. You should not use more than one lane as you turn the corner, accelerate too quickly, or press the brake pedal throughout the turn.
Completing a turn requires that you gradually slow down before entering the turn, maintain a steady speed throughout the turn, and accelerate gently after completing the turn. Additionally, you should stay within your lane while turning and avoid using more than one lane.
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9. in 1959, pound and rebka did an experiment to test the prediction of einstein's theory of general relativity about the relationship between the pace of time and the strength of gravity. when two identical atomic clocks, one on the ground floor and one on the top floor, were compared, a. the clocks ran at exactly the same pace in both locations b. the clock on the top floor ran a tiny bit slower c. the clock on the ground floor ran a tiny bit slower d. the clock on the ground floor became a little bit lighter (weighed less) e. the clock on the top floor became a little bit lighter
Pound and Rebka did an experiment of general relativity to test Einstein’s theory. When two identical atomic clocks (one on the ground floor, one on the top floor) were compared, then: B. The clock on the top floor ran a tiny bit slower.
What is Einstein’s theory of general relativity of how gravity affects the pace of time?General relativity is a theory of gravity capable of curving and warping space. Albert Einstein claimed that time is relative. It depends on how strong gravity affects it. The further an object is to the ground, the weaker the gravity and the slower the pace of time it experiences. That is why the clock on the top of a building runs a tiny bit slower than on the ground floor.
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What value of resistor R gives the circuit in the figure a time constant of 22 μs ?
The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.
The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:
RC = τ, where R is the resistance and C is the capacitance of the circuit.
Rearranging the above formula, we get:R = τ / C
Where τ is the time constant and C is the capacitance of the circuit.
From the figure, the capacitance is given as 0.1 μF
.Substituting the values of τ and C in the above formula, we get:
R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)
R = 220 Ω
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what happens to the magnitude of the magnetic field inside a long solenoid if the current is doubled?
If the current is doubled, the size of the magnetic field inside a long solenoid increases by a factor of two.
I enc = nh x I because I enc = (number of turns inside the area) x (current through each turn)The magnetic field strength in a long solenoid is calculated using the equation above.
A wire coil that can generate a powerful magnetic field inside itself is called a solenoid. When the current is permitted to flow via a wire that is wrapped around a cylindrical object, the magnetic field produced is stronger.
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Find the density of a 2 cm x 2 cm x 2 cm cube with a mass of 64 g.
Answer:
8 g/cm³
Explanation:
density=mass/volume
volume=2*2*2=8 cm³
mass=64 g
density=64/8=8 g/cm³
The density of a 2 cm x 2 cm x 2 cm cube with a mass of 64 g is equal to 8 g/cm³.
What is the density?Density can be defined as the material mass per unit of volume. The symbol commonly used to represent density ρ and the letter 'D' can also be used.
The mathematical equation of the density can be represented as written below:
Density = Mass /Volume
or, ρ = m/V
The density of a material varies with pressure and temperature. There is a small variation for solids and liquids of any material but much larger for gases. Increasing the pressure of material decreases the volume and thus increases its density.
Given the volume of the cube = 2 cm x 2 cm x 2 cm
V = 8 cm³
The mass of the cube, m = 64 g
The density of the cube can be calculated from the above-mentioned formula:
Density = Mass of cube/volume
D = 64/8
D = 8 g/cm³
Therefore, the density of the cube is 8 g/cm³.
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If a sound travels 343m/s through air and has a frequency of 800Hz, what would the wavelength be of the same sound traveling through water 500m/s with the same frequency?
Answer:
0.625m
Explanation:
Now Velocity of a wave ,V = frequency × wavelength
Wavelength =velocity /frequency
=500/800 =0.625m
Why is it important to describe the reference frame you are using when sharing information about position?
It is important to describe the reference frame you are using when sharing information about position because it helps to determine the relative distance or position of an object.
What is frame of reference?
A frame of reference is a particular position or point on which you base your judgment of a moving object.
Also, reference frames are used to specify the relationship between a moving observer and the phenomenon under observation.
A frame reference helps to measure the accurate position or distance traveled by an object.
Thus, it is important to describe the reference frame you are using when sharing information about position because it helps to determine the relative distance or position of an object.
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Spring tides occurs at two of the time shown which two? how do u know ?
Spring tides are extremely wide ranges of tidal highs and lows that occur during full moon or new moon phases when the gravitational forces of the Sun and Moon are at their strongest.
Neap tides are characterized by lower high tides and higher low tides, while spring tides feature higher high tides and lower low tides. Because of this, a spring tide has a significantly wider range than a low tide (the difference in water level between high and low tide).Spring tides are the tides that occur right after a new or full moon when the difference between high and low water is the biggest. The earth, moon, and sun are in a straight line at this time, causing the gravitational pull to be at its strongest. There are more high tides than usual and fewer low tides than usual.To know more about spring tides
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