What's the theoretical yield of oxygen from the oxides present in 1. 00 kg sample of lunar soil?

The concentration of chlorine in the well-mixed water storage tank will be 0.639 mg/L one day later, assuming no water flows out of the tank.

The decay of chlorine in a distribution system follows first-order decay with a rate constant of 0.360 d-1. The concentration of chlorine in a well-mixed water storage tank is 1.00 mg/L at time zero.

Assuming no water flows out of the tank.

The concentration of chlorine in the well-mixed water storage tank after a time t can be calculated using the following equation:

\(C = Coe^{(-kt)}\),

where C is the concentration of chlorine at time t, Co is the initial concentration of chlorine at time zero, k is the first-order rate constant, and t is the time elapsed.

The rate constant k = 0.360 d-1, and the initial concentration of chlorine Co = 1.00 mg/L.

Therefore, after one day (t = 1 day), the concentration of chlorine C can be calculated as follows:

\(C = Coe^{(-kt)}\)

\(C = 1.00 mg/L * e^{(-0.360 d-1 * 1 day)}\)

C = 0.639 mg/L

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In comparison to the greater hydrogen bonding in ethanol, diethyl ether molecules are bound together by weak dispersion forces. As a result, one mole of diethyl ether takes less heat to vapourize than one mole of ethanol.

The vapour pressure of diethyl ether at these temperatures is more than 20 times that of water, indicating its volatility.

Diethyl Ether, CH3CH2OCH2CH3, is a highly flammable organic solvent that was also revealed to be one of the earliest anaesthetics. Because it boils at 34.6°C, just below the typical human body temperature, ether evaporates quickly. Since its vapour is denser than air, ether fumes tend to sink into the atmosphere.

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Action potentials are generated at the axon hillock and are conducted along the axon.

The axon hillock is the region of the neuron where the axon originates from the cell body. It is responsible for integrating the incoming signals from the dendrites and initiating the action potential. Once the action potential is initiated, it travels down the axon, which is a long, slender projection of the neuron. The axon is insulated by the myelin sheath, which helps to increase the speed of conduction.

At the end of the axon, the action potential reaches the terminal buttons, which are small knobs that release neurotransmitters into the synapse, a gap between neurons. From there, the neurotransmitters can bind to receptors on the dendrites of the next neuron, initiating a new round of electrical activity. The glial membrane surrounds both the axon and dendrite, providing support and insulation for the neuron.

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If 2 moles of oxygen are consumed during cellular respiration, 36.03 grams of water are produced.

Using the cellular respiration reaction  C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O. For every 6 moles water produced, 6 mole of oxygen is consumed as well. Therefore, for 2 moles of oxygen consumed,

2/6 x 6 mol of H₂O = 2 mol of H₂O

To convert moles of water to grams, we need to use the molar mass of water,

2 mol of H₂O x 18.015 g/mol = 36.03 g of H₂O

Therefore, if 2 moles of oxygen are consumed during cellular respiration, 36.03 grams of water are produced.

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Complete question - If you have 2 moles of oxygen (O₂), how many grams of water are produced during cellular respiration? Solve and record your answer

C₆H₁₂O₆ + 602 → 6CO₂ + 6H₂O

The mass of carbon dioxide that would be produced will be 22 kg

The combustion of carbon in air can be represented by the equation:

C + O2 ---> CO2

The mole ratio of C to O2 to CO2 is 1:1:1.

Mole of 6kg of carbon = mass/molar mass

                                      = 6000/12

                                      = 500 moles

Equivalent mole of CO2 produced = 500 moles

Mass of 500 moles CO2 = mole x molar mass

                                          = 500 x 44.01

                                           = 22,005 g or 22 kg approximately

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Answer:hey man hey man

Explanation:

ooo she fine  

Answer:

balance the equation

Explanation:

\(C_{3}H_{8} + 5O_{2} ->3CO_{2} + 4H_2O\)

This new ratio of 1:1.5 does not match the stoichiometric ratio of 2:3 in the balanced equation. Therefore, we cannot halve the amounts of reactants and expect the reaction to occur completely.

In the given chemical reaction, solid aluminum reacts with chlorine gas to form solid aluminum chloride. Let's break down the question step by step.

We are given that we have a certain amount of solid aluminum (which is not specified) and a certain amount of chlorine gas (also not specified) in a reactor.

The question asks if we can halve (reduce by half) the amount of reactants and still have the reaction occur.

To determine this, we need to consider the stoichiometry of the reaction, which refers to the balanced equation that shows the ratio of reactants and products.

The balanced equation for the reaction between solid aluminum and chlorine gas is:

2Al + 3Cl₂ → 2AlCl₃

From the balanced equation, we can see that the ratio of aluminum to chlorine is 2:3. This means that for every 2 moles of aluminum, we need 3 moles of chlorine to react completely and form 2 moles of aluminum chloride.

If we want to reduce the amount of reactants by half, we need to adjust the quantities accordingly.

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ANSWER:

4 a) Specific elements have more than one oxidation state, demonstrating variable valency.

For example, the following transition metals demonstrate varied valence states: \(Fe^{2+}\), \(Fe^{3+}\), \(Cr^{2+}, Cr^{3+}\), etc.

Normal metals such as \(Pb^{2+} and Pb^{4+}\) also show variable valencies. Certain non-metals are also found to show more than one valence state \(Pb^{3+} and Pb^{5+}.\)

4 b) Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons.

For example, Carbon-14 is a naturally occurring radioactive isotope of carbon, having six protons and eight neutrons in the nucleus. However, C-14 does not last forever and there will come a time when it loses its extra neutrons and becomes Carbon-12.

5 a) \(2Fe + 3Cl_2\) → \(2FeCl_3\)    

5 b) \(3Pb + 8HNO_3\) → \(3Pb (NO_3)_2 + 4H_2O + 2NO_2\)

5 c) \(Zn + H_2SO_4\) → \(ZnSO_4 + H_2\)   (already balanced so don't need to change)

5 d) \(2H_2 + O_2\) → \(2H_2O\)

5 e) \(2Mg + 2HCl\) → \(2MgCl + H_2\)

EXPLANATION (IF NEEDED):

1. Write out how many atoms of each element is on the left (reactant side) and right (product side) of the arrow.

2. Start multiplying each side accordingly to try to get atoms of the elements on both sides equal.

EXAMPLE OF BALANCING:

The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.

Case 1: HD​:pSun ​=rhoMan ​=pTue ​=pWed ​=pThu ​=pFri ​=pSat ​=71​
Ha​ : Not all proportions are equal.

Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\)  where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.  
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)

We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)

Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)

Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)

The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)

From the above percentages, we can see that Friday has the highest percentage of traffic accidents.

Case 2:
HD​: Not all proportions are equal.

Ha​:pSun ​=pMon ​=pTue ​=rhoWed ​=pThu ​=rhoFri ​=rhoSat ​=71

Test Statistic

\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)

We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic can be computed as:

\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

Case 3:

All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic is,

\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)

The p-value is 0.1664.

Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

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Answer:

Filament

Explanation:

The style, ovary and the stigma is present in the pistil thus the gilament is not a part of the pistil

Answer:

Released I think

Answer:

to figure out how to sustain large populations in this environment.

Answer:

The maya needed to create innovative ways to manage water because they lived in a dry climate.

They needed to find ways to collect water and store it for later use.

Explanation:

There were downpours during the unpredictable wet season and there was a long dry season

Not many rivers

If we talk about the balanced chemical equation of photosynthesis  the reactants, six carbon dioxide molecules and six water molecules, convert into a glucose (sugar molecule) and six oxygen molecules, the products d by the light energy captured by chlorophyll.

which means, one mole of glucose can be produced by six mole of carbon dioxide.

or can say that, six moles of carbon dioxide molecules will be needed to produce one mole of glucose.

6(number of moles of carbon dioxide) = 1(number of moles of glucose)

number of moles of carbon dioxide = (number of moles of glucose)/6

We are given with,

Number of moles of glucose produced = 2.4 moles

number of moles of carbon dioxide = 2.4/6

number of moles of carbon dioxide = 0.4 moles

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Answer:

Styrene has the empirical formula CH, and there is 92.25% carbon and 7.75% hydrogen. The percentage of these parts can be used to determine the molar mass and use the molecular formula.

Explanation:

The following statements correctly describes chemical equation : Bonds between atoms break and reform.

Chemical reaction refers to the rearrangement of atoms and their bonds in reactants to yield new substances which are known as products.

Reactants go into reaction and products are yielded from reaction. Reaction require energy which is called endothermic reaction or it may release energy which is known as exothermic reaction.

Chemical equation tells us about the substances involved in reaction and chemical equation informs us about the symbols and formulae of substances involved in reaction. Chemical equation tells us about the atoms or molecules of reactants and products in reaction.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Which statement correctly describes a chemical reaction?

Reactants come out of a reaction.

Energy is always released.

Bonds between atoms break and reform.

Products go into a reaction.

Explanation:

i hope i have been useful buddy.

good luck ♥️♥️.

Answer:

[Au] = 0.171 M

Explanation:

For this question, we assume the rock is 100 % gold.

First of all, we determine the moles of gold

67.3 g . 1mol/ 196.97g = 0.342 moles

Molar concentration is defined as the moles of solute, contained in 1L of solution.

Our solution volume is 2L.

M = 0.342 mol / 2L = 0.171

Molar concentration, also called molarity of solution is the most typical unit of concentration.

The given statement -"Microcrystalline tests are more specific than color tests in identifying a particular drug."is false.

Color tests can indicate the presence of a drug, but cannot provide specific information about the type or quantity of the drug. Microcrystalline tests involve the formation of specific crystals in the presence of a particular drug, allowing for more specific identification.

Color testing is a presumptive identification technique indicating the presence or absence of a particular drug class using rapid and uncomplicated chemical methods.

Color tests for drugs are commonly used in forensic and drug analysis to provide preliminary identification of substances. These tests involve adding specific reagents or chemical solutions to a sample, which can produce a color change or reaction indicative of the presence of certain drugs.

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What are the choices? I'll answer once you tell me those

Answer:

sunlight is an abiotic factor

Explanation:

In the reaction: Fe²⁺(aq) + Cr₂O₇²⁻(aq) → Fe³⁺(aq) + Cr³⁺(aq), the coefficient of water in the balanced reaction is 7.

To find the coefficient of water in the balanced reaction Fe²⁺(aq) + Cr₂O₇²⁻(aq) → Fe³⁺(aq) + Cr³⁺(aq) in an acidic solution, follow these steps:

1. Determine the oxidation states of each species:
Fe²⁺ has an oxidation state of +2
Cr₂O₇²⁻: Cr has an oxidation state of +6, and O has an oxidation state of -2
Fe³⁺ has an oxidation state of +3
Cr³⁺ has an oxidation state of +3

2. Identify the species being oxidized and reduced:
Fe²⁺ is being oxidized to Fe³⁺ (oxidation state increases from +2 to +3)
Cr₂O₇²⁻ is being reduced to Cr³⁺ (oxidation state decreases from +6 to +3)

3. Balance the atoms and charges through half-reactions:
Oxidation half-reaction: Fe²⁺ → Fe³⁺ + e⁻
Reduction half-reaction: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O

4. Balance the number of electrons transferred in both half-reactions:
Oxidation:  6Fe²⁺ → 6Fe³⁺ + 6e⁻
Reduction: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O

5. Add the balanced half-reactions to obtain the balanced overall reaction:
6Fe²⁺ + Cr₂O₇²⁻ + 14H⁺ → 6Fe³⁺ + 2Cr³⁺ + 7H₂O

Therefore, the coefficient of water in the balanced reaction is 7.

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Answer:

So if you want to raise the temperature of that one gram from 19 to 35 degrees, that same gram will need 35 −19 = 16 times as much heat. And if you want to raise the temperature of 193 grams in stead of just 1 gram, you will need 193 times as much heat.

Explanation:

Sugar is a simple carbohydrate consisting of carbon, oxygen, and hydrogen molecules which are linked by covalent bonds.

The chemical covalent bonds are a type of chemical bond in which atoms that differ in their electronegativity share electrons to maintain cohesion i.e., intramolecular cohesion, while sugar molecules may interact by glycosidic bonds.

Therefore, with this data, we can see covalent bonds bind atoms in the sugar molecule while glycosidic bonds are those required to connect different sugar and thus form a complex macromolecule or polysaccharide.

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