When 21.44 moles of si react with 17.62 moles of n2 how many moles of si3n4 are formed

Answer:

Explanation:

A. The charge on an element is determined by the differences between the number of protons and electrons in an atom.

An atom will have no charges if the number of protons and electrons are the same.

Charge  = number of protons  - number of electrons

B. Electrons form the charges they do because with the charge, they become stable like the noble gases.

The desire of every atom is  to have stable electronic configuration like those of the noble gases.

A potassium atom with a configuration 2 8 8 1 will prefer to lose an electron to become an Argon atom making the ion stable.

Answer:

An atom of a group 17 element such as chlorine has seven valence electrons. It is “eager” to gain an extra electron to fill its outer energy level and gain stability. Group 16 elements with six valence electrons are almost as reactive for the same reason

Explanation:

Answer:

b. Environmental regulatory law

Explanation:

Environmental regulatory laws are specific legal regulations and frameworks that govern the actions and practices of individuals, organizations, or industries in relation to environmental protection and conservation. These laws are designed to regulate and prevent harmful activities that can have detrimental effects on the environment, including the disposal of hazardous substances such as PCBs.

It is important to note that specific legal jurisdictions may have variations in their environmental laws and regulations, so the categorization may vary depending on the specific legal context in which the offense occurred.

Answer:

The significance of being able to "grow" organs is the potential to create new organs to replace the old and worn out ones or any that are missing. This can potentially save lives.

Explanation:

Answer: Chris Brown has launched a charity organization called the Symphonic Love Foundation.

Explanation:

1. The concentration of the hydronium ion, [H₃O⁺] is 3.02×10⁻¹⁰ M

2. The concentration of the hydroxide ion, [OH⁻] is 3.31×10⁻⁵ M

The concentration of the hydronium ion, [H₃O⁺], can be obtained as follow:

pH of a solution is given by the following formula:

pH = -Log [H₃O⁺]

Inputting the various parameters, we have

9.52 = -Log [H₃O⁺]

Multiply through by -1

-9.52 = Log [H₃O⁺]

Take the anti-log of -9.52

[H₃O⁺] = Anti-log -9.52

[H₃O⁺] = 3.02×10⁻¹⁰ M

The value of the the hydroxide ion, [OH⁻], can be obtained as follow:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

3.02×10⁻¹⁰ × [OH⁻] = 10¯¹⁴

Divide both side by 3.02×10⁻¹⁰

[OH⁻] = 10¯¹⁴ / 3.02×10⁻¹⁰

[OH⁻] = 3.31×10⁻⁵ M

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A piggyback is a secondary infusion that can be provided in conjunction with a primary infusion. Piggyback infusions are usually provided for shorter periods of time than primary infusions. They are given through an intravenous (IV) tube that is connected to a port above the primary infusion. Piggybacks are used when a patient needs intermittent drug administration or when their treatment regimen requires more than one drug.The volume of solution or diluent that is administered through piggybacks varies depending on the drug being administered and the patient's needs. The volume ranges from 25 to 250 milliliters.

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2.20 g (to 3 sig. figs.) the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.

hexane is C6H14 or put another way, as in the question CH3(CH2)4CH3. Actually, it is incorrect as depicted in the question.Nonetheless..

2C6H14 + 19O2 ===> 12CO2 + 14H2O ... balanced equation

moled hexane present = 2.6 g x 1 mole/130 g = 0.02 moles

moles O2 present = 5.29 g x 1 mole/32 g = 0.165 moles

Which reactant is limiting? Hexane = 0.02/2 = 0.01; O2 = 0.165/19 = 0.0087

Thus O2 is limiting...

moles of H2O that can be produced =0.165 moles O2 x 14 H2O/19 CO2 = 0.122 moles H2O

Mass of water( H2O) = 0.122 moles x 18 gm/mole = 2.20 g (to 3 sig. figs.)

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when the inter molecular force between solute-solvent are weaker than solvent-solvent imf.

In order to create a solution, a solute must dissolve in a solvent, which causes the solute particles to break their previous bond with the solvent and form a new one.

Solvent-solvent intermolecular forces are stronger than solvent-solute intermolecular interactions in the given situation. In order to create new solute-solvent interactions, the solute particle cannot simply overcome the solvent-solvent intermolecular forces.

As a result, we must first apply heat to displace the solvent-solvent intermolecular forces. Because heat is used to create the solution.

The process is hence exothermic.

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Answer:B

Explanation:

Answer:This chapter begins the first where we will look at matter on a microscopic scale.  Matter is made of small particles of atoms or molecules.  There are three common states of matter, solid, liquid and gas.  A gas and a liquid will change shape to fit the shape of their container.  A gas will change volume to fit the volume of the container.

Explanation:

In general, solids are denser than liquids, which are denser than gases. . The particles in the solid are touching with very little space between them. The particles in a liquid usually are still touching but there are some spaces between them. The gas particles have big distances between them.

Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other.   Their vibration is related to their kinetic energy.  In the solid the particles vibrate in place.

Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container. The attractive forces between particles are strong enough to hold a specific volume but not strong enough to keep the molecules sliding over each other.

Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other.  In most cases, there are essentially no attractive forces between particles.  This means that a gas has nothing to hold a specific shape or volume.

(A fourth state of matter, called plasma, exists when a gas becomes ionized. Plasma exists inside stars and in interstellar gases.)

Yes, it is possible to distinguish between two points that have the same Rf value but represent different compounds. This can be done by: using gas chromatography.

Repeat the experiment with another solvent system. Different compounds with the same Rf value may behave differently in different solvents. Different compounds have different Rf values ​​in different solvents. Rf values ​​can be used to identify compounds in a mixture. The Rf value for a given compound is always the same when using the same solvent and stationary phase. The Rf value varies from 0 (substance not attracted to mobile phase) to 1 (substance not attracted to stationary phase). Yes, it is possible to distinguish between two points that have the same Rf value but represent different compounds. This can be done by: using gas chromatography.  

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Answer: The standard cell potential (E°cell) of the silver electrode is +0.93 V

Explanation:

To determine the potential of the silver electrode in the cell, we need to use the standard reduction potentials of the half-reactions involved and apply the Nernst equation.

The half-reactions involved in this cell are:

Ag⁺(aq) + e⁻ → Ag(s) (Silver half-reaction)

Pb²⁺(aq) + 2e⁻ → Pb(s) (Lead half-reaction)

The standard reduction potentials for these half-reactions are as follows:

E°(Ag⁺/Ag) = +0.80 V

E°(Pb²⁺/Pb) = -0.13 V

To find the potential of the silver electrode (E°cell), we need to subtract the reduction potential of the anode (Pb) from the reduction potential of the cathode (Ag):

E°cell = E°(cathode) - E°(anode)

E°cell = +0.80 V - (-0.13 V)

E°cell = +0.93 V

The standard cell potential (E°cell) is +0.93 V. This value represents the potential of the silver electrode in the cell.

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To determine the potential of the silver electrode in the cell, we need to use the standard reduction potentials of the half-reactions involved and apply the Nernst equation.

The half-reactions involved in this cell are:

Ag⁺(aq) + e⁻ → Ag(s) (Silver half-reaction)

Pb²⁺(aq) + 2e⁻ → Pb(s) (Lead half-reaction)

The standard reduction potentials for these half-reactions are as follows:

E°(Ag⁺/Ag) = +0.80 V

E°(Pb²⁺/Pb) = -0.13 V

To find the potential of the silver electrode (E°cell), we need to subtract the reduction potential of the anode (Pb) from the reduction potential of the cathode (Ag):

E°cell = E°(cathode) - E°(anode)

E°cell = +0.80 V - (-0.13 V)

E°cell = +0.93 V

The standard cell potential (E°cell) is +0.93 V. This value represents the potential of the silver electrode in the cell.

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The aluminum hydroxide is dissolved, as well as any other acids or bases present that can affect the pH. Without this information, it is not possible to provide a specific pH value for the solution.

To determine the pH of a solution containing aluminum hydroxide (Al(OH)3), we need additional information. Aluminum hydroxide is a weak base, and its pH will depend on its dissociation in water.

First, we can calculate the number of moles of aluminum hydroxide using its molar mass. The molar mass of Al(OH)3 is 78 grams/mol (27 g/mol for aluminum and 3 × 17 g/mol for three hydroxide groups). Therefore, we have 78 g / 78 g/mol = 1 mol of Al(OH)3.

Since aluminum hydroxide is a weak base, it will undergo partial dissociation in water, releasing hydroxide ions (OH-) and aluminum ions (Al3+). The hydroxide ions will increase the pH of the solution.

However, to determine the pH accurately, we need to know the initial volume of water.

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Answer:

Number of energy levels that the element has.

Explanation:

The period number (n) is the outer energy level that is occupied by electrons. The period number that an element is in, is the number of energy levels that the element has.

To furnish 1.5 mol of carbon atoms from sucrose, you would need approximately 294.3 mL of aqueous 40% sucrose solution.

The molar mass of sucrose (C12H22O11) can be calculated as follows:

Molar mass of C12H22O11 = (12 * 12.01 g/mol) + (22 * 1.01 g/mol) + (11 * 16.00 g/mol)

                      = 144.12 g/mol + 22.22 g/mol + 176.00 g/mol

                      = 342.34 g/mol

Since each mole of sucrose contains 12 moles of carbon atoms, the molar mass of carbon is:

Molar mass of carbon = (12 * 12.01 g/mol)

                   = 144.12 g/mol

To calculate the mass of carbon atoms needed to furnish 1.5 moles, we can use the following formula:

Mass of carbon = (1.5 mol) * (144.12 g/mol)

             = 216.18 g

Now, we can calculate the volume of the aqueous 40% sucrose solution using its density:

Volume = Mass / Density

      = 216.18 g / 0.911 g/mL

      ≈ 237.34 mL

However, the 40% sucrose solution is not pure sucrose. We need to consider the actual amount of sucrose in the solution. A 40% sucrose solution means it contains 40 g of sucrose per 100 mL of solution.

Therefore, the volume of the aqueous 40% sucrose solution required would be:

Volume = (237.34 mL * 100 mL) / 40 g

      ≈ 593.35 mL

To furnish 1.5 mol of carbon atoms from sucrose, you would need approximately 593.35 mL of aqueous 40% sucrose solution.

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Answer:

Cl-35 isotope is more abundant.

Explanation:

How to calculate the abundance of isotopes in a mixture from the mass of isotopes and the average atomic mass of the element?

Solution :

Say the % abundance of Cl - 35 is x, i.e, 100 units of Cl contains x units of Cl-35.

Therefore, the % abundance of Cl - 37 is (100 - x).

∴ [35 x + 37 (100-x)] = 35.45 x 100

Simplifying the above equation, we get

-2x + 3700 = 3545

Subtracting 3700 from both sides of the equation, we get

-2x = -155

or, 2x = 155

Dividing both sides of the equation by 2, we get

x = 155 ÷ 2 = 77.5

∴ 100 -x = 22.5

Thus, Cl-35 is more abundant (77.5%) than Cl-37 (22.5%).

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Answer:

216 g of NO

Explanation:

We begin from the reaction:

4NH₃ + 5O₂ →  4NO  + 6H₂O

We determine the limiting reactant with the moles of each reactant:

4 moles of ammonia react to 5 moles of oxygen

Our 7.2 moles of ammonia may react to (7.2 . 5) /4 = 9 moles

It's ok because we have 9.6 moles of oxygen. 0.6 moles still remain.

5 moles of oxygen react to 4 moles of NH₃

Our 9.6 moles of oxygen may react to (9.6 . 4) /5 = 7.68 moles

We only have 7.2 moles of NH₃ and we need 7.68; so there is no enough ammonia and that's our limiting reagent.

Now we determine the moles of product.

4 moles of ammonia can produce 4 moles of NO

Definetely our 7.2 moles, will produce 7.2 moles of oxide.

We convert to mass: 7.2 mol . 30 g/mol = 216 g

Answer:

\({ \sf{Pb(NO_{3})_{2(aq)} + 2NaCl _{(aq)} → 2NaNO_{3(aq)} + PbCl _{2(s)} }} \\ \)

50 grams of NaCl, m.w. 58.5 daltons are required to make 1 liter of 5% saline.

Saline water (generally known as salt water) is water that contains a high concentration of dissolved salts or NaCl. The saline is used in the management and treatment of dehydration, e.g., hypovolemia, shock), metabolic alkalosis in the presence of fluid loss, and mild sodium depletion.

Therefore it is stated that saline is the solution which is composed of salt and water. And in order to make 1 liter of 5% saline, 50 grams of sodium chloride or NaCl is required.

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Before 1937, scientists had not yet discovered element 43, which we now know as technetium. However, chemists were still able to predict its properties based on its position in the periodic table and its relationship to other elements.

Elements in the same group of the periodic table tend to have similar properties, so chemists could make educated guesses about what properties element 43 might have based on its position in the table.

Additionally, chemists could study the behavior and properties of neighboring elements, such as manganese and rhenium, to gain further insight into what element 43 might be like.

While they couldn't know for sure until the element was actually discovered and studied, chemists were able to make predictions about element 43 based on their understanding of the periodic table and chemical behavior.

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Answer:

a. energy levels

Explanation:

Electrons are organized in energy levels or electron shells, which correspond to the periods on the periodic table.

The number of grams of NaCl necessary to make up 100 mL of a 0.10 M solution is 0.58 g.

Option (a) is correct

To calculate the number of grams of NaCl, we need to use the formula: Mass = Molarity x Volume x Molar mass.

Given that the volume is 100 mL (which is equivalent to 0.1 L) and the molarity is 0.10 M, we can substitute these values into the formula.

The molar mass of NaCl is approximately 58.5 g/mol.

Mass = 0.10 M x 0.1 L x 58.5 g/mol = 0.58 g.

Therefore, the number of grams of NaCl necessary to make up 100 mL of a 0.10 M solution is 0.58 g.

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Determine the number of grams of NaCl necessary to make up 100 mL of a 0. 10 M solution.

a) 0. 58 g

b) 1. 7 g

c) 58 g

d) 0. 017 g.

By using the ideal gas law to get volume we have"

Where v is volume, T is temperatute, n is number of moles, R is the molar gas constant and P is pressure. At STP P= 101,325 Pa, T= 273.15 K and R= 8.314 J/mol K

We must first convert mass to moles:

By substituting this value into the ideal gas law we have:

1.9502e-6L of H2 gas reacted at STP

Answer:

53.7kPa

Explanation:

Given parameters:

Total pressure of the mixture  = 96.4kPa

partial pressure of hydrogen  = 13.4kPa

partial pressure of oxygen  = 29.3kPa

Unknown:

partial pressure of methane  = ?

Solution:

The total pressure of mixture is equal to the sum of their particles pressures;

   Partial pressure of methane  = 96.4kPa - (13.4kPa + 29.3kPa)

  Partial pressure of methane = 53.7kPa

Answer: 53.6

Explanation: I just took the test and got it right.

The amount that will be left after 115.2 years, given that you started with 10 grams sample of strontium-90 is 0.625 g

To obtain the amount that will be left after 115.2 years, we shall begin our calculation by obtaining the number of half lives that has passed.

The number of half lives that has passed can be obtained as followed:

n = t / t½

n = 115.2 / 28.8

n = 4

Thus, 4 half lives has passed.

Finally, we shall determine the amount that will be left after 115.2 years. This is illustrated below:

N = N₀ / 2ⁿ

N = 10 / 2⁴

N = 10 / 16

N = 0.625 g

Thus, we can conclude that the amount that will be left after 115.2 years is 0.625 g

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Therefore, the volume occupied by the amount of ethyl alcohol containing 48.0 moles of hydrogen atoms is approximately 61.41 mL.

To calculate the volume occupied by the given amount of ethyl alcohol, we need to use the density of ethyl alcohol and convert moles of hydrogen atoms to grams.

First, we need to find the molar mass of ethyl alcohol (C2H5OH).

The molar mass of carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol.

Adding these up gives a molar mass of 46.08 g/mol for ethyl alcohol.

Next, we can calculate the mass of 48.0 moles of hydrogen atoms using the molar mass of hydrogen (1.01 g/mol).

The mass is given by:

mass = moles × molar mass

mass = 48.0 mol × 1.01 g/mol

mass = 48.48 g.

Now, we can use the density of ethyl alcohol (0.789 g/mL) to find the volume.

Density is defined as mass divided by volume, so we can rearrange the equation to solve for volume:

volume = mass/density

volume = 48.48 g / 0.789 g/mL

volume = 61.41 mL.

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Melting occurs when a solid changes state into a liquid.

Fusion occurs when a liquid changes state into a solid.

(So, basically, they are opposite of each other)

Hope this helps!

Have an awesome day!

1. Valency of oxygen is 2.

=> This statement is true.

As, atomic number of oxygen is 8. So, it have 2 electrons in its first shell and 6 electrons in second or valence shell. To complete its valence shell, oxygen needs 2 more electrons to complete shell of 8 electrons. So, valency of oxygen is 2.

2. The number of atoms of each element should be same on each side of Balanced equation.

=> This statement is true.

In a balanced reaction, the number of atoms in the reactant side must be equal to number of atoms in product side. If number of atoms are equal on both sides, then we can say that the reaction is balanced.

Answer:

\([C_6H_{12}O_6]\)

Explanation:

Hello there!

In this case, since the concept of solution concentration is majorly used in terms of moles per liters of solution or molarity (M), it is also possible to represent this chemical unit by using squared brackets, [ ].

In such a way, when focused on the concentration of glucose, C6H12O6, we can use:

\([C_6H_{12}O_6]\)

Best regards!