when a 45.0 g sample of an alloy at i 00.0 oc is dropped into i 00.0 g of water at 25.0 °c, the final temperature is 37.0 oc. what is the specific heat of the alloy?

Answers

Answer 1

The specific heat of the alloy is 0.655 J/g°C.  Amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius is known as specific heat.

First, we need to calculate the heat lost by the alloy as it cools down from 100.0 °C to the final temperature of 37.0 °C. We can use the formula:

Q = m * c * ΔT

where Q is the heat lost, m is the mass of the alloy, c is the specific heat of the alloy, and ΔT is the change in temperature.

Using the values given in the question, we can write:

Q = (45.0 g) * c * (100.0 °C - 37.0 °C)

Simplifying this expression, we get:

Q = 1530 g°C * c

Next, we need to calculate the heat gained by the water as it warms up from 25.0 °C to the final temperature of 37.0 °C. We can use the same formula as before, but with the mass of water and the specific heat of water:

Q = (100.0 g) * (4.184 J/g°C) * (37.0 °C - 25.0 °C)

Simplifying this expression, we get:

Q = 1002.4 J

Since energy is conserved, the heat lost by the alloy must be equal to the heat gained by the water:

1530 g°C * c = 1002.4 J

Solving for c, we get:

c = 0.655 J/g°C

Therefore, the specific heat of the alloy is 0.655 J/g°C.

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Related Questions

kinds of solar power stations

Answers

There are Three main types of concentrating solar thermal power systems: linear concentrating systems, which include public Troughs and linear fresnel reflectors. solar power towers.

what is chemical energy help I'm really dumb

Answers

Answer: Chemical energy is the energy stored in bonds that is released when chemical reactions occur.

A bus is moving at a speed of 45 km/h. What is the speed of
the bus in m/s?
a) 1.25×101 m/s
b) 1.5×103 m/s
c) 2.5 m/s
d) 1.5×102 m/s

Answers

.

We want to convert the speed of the bus from kilometers per hour to meters per second.

To do this, multiply the speed in km/hr by 1,000 and divide by 3,600.

The formula to do this is: 1 km/hr = 1,000/3,600 m/s

Therefore, we have that 45 km/hr is:

45 x 1000/ 3,600 ➡️ 12.5 m/s = 1.25 x 10 to the 1st power m/s

The answer is option A.

Find the current flowing across the 20 ohm resistor.​

Find the current flowing across the 20 ohm resistor.

Answers

Answer:

15 is it

Explanation:

Answer:

The answer would be 0.23

Explanation:

Put in 0.23

A race boat, starting from rest, uniformly accelerates for 4 seconds. If the boat moves
70 meters during the acceleration period, what is its rate of acceleration?

A race boat, starting from rest, uniformly accelerates for 4 seconds. If the boat moves 70 meters during

Answers

Answer:

uui 2+6=8m calculator hunny work's

According to x-ray observations, the space between galaxies in a galaxy cluster is?

Answers

According to x-ray observations, the space between galaxies in a galaxy cluster is very hot. It is because the matter between galaxies (often called the intergalactic medium) is mostly hot, ionized hydrogen with bits of heavier elements such as carbon, oxygen and silicon thrown in.

Massive structures are collapsing than at earlier times. Large collapsing structures lead to higher velocity intergalactic shocks and, as a result, significant intergalactic shock heating, with some gas heated well above the \(10^{4}\) K temperatures.

Heating also occurs as galaxies expel out most of the gas that fell into them. The final product is a warm/hot phase, with temperatures of > \(10^{5}\) K.

Now, Let's know how do you use X-rays to make space observations?

X-radiation is absorbed by the Earth's atmosphere, so instruments to detect X-rays must be taken to high altitude by balloons, sounding rockets, and satellites.

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A jogger takes 3.5 min to run once around a square block that is 220 m on each side. What is the jogger’s average velocity?

Answers

Answer:4.2 miles/hour

Explanation:

220 each side = 880 meters total

880/3.5 = 251 is how many meters per minute

multiply by 60 to get per hour

a ball is shot off a cliff from 100m above the ground at angle 20 degrees, and lands on the ground 12 seconds later. a) What is the initial speed of the projectile? b) what is the initial x-component of the projectiles velocity c) determine the horizontal position of the projectile after landing (hint: not a range)

Answers

A ball is shot off a cliff from 100m above the ground at angle 20 degrees, and lands on the ground 12 seconds later.

The given values are as follows:

Initial height (y) = 100 mAngle (θ) = 20 degreesTime taken (t) = 12 s

Now, we need to find the following values:Initial velocity (u)Initial x-component velocity (ux)Horizontal position (x)Let’s solve these one by one:

a) Initial velocity (u)The initial velocity of the projectile can be found using the following formula:

v = u + at

Here, a is the acceleration due to gravity, which is equal to -9.8 m/s² (since it is acting downwards).

Also, the final velocity (v) is equal to zero (since the projectile lands on the ground and stops).

Substituting these values, we get:0 = u + (-9.8 × 12)u = 117.6 m/s

Therefore, the initial speed of the projectile is 117.6 m/s.

b) Initial x-component velocity (ux)The initial x-component velocity can be found using the following formula:ux = u × cosθSubstituting the values, we get:

ux = 117.6 × cos20°ux = 111.6 m/sc) Horizontal position (x)The horizontal position of the projectile after landing can be found using the following formula:

x = ut + ½at²

Here, a is the acceleration due to gravity, which is equal to -9.8 m/s² (since it is acting downwards).

Substituting the values, we get:

x = (117.6 × cos20°) × 12 + ½ × (-9.8) × 144x = 1345.1 m

Therefore, the horizontal position of the projectile after landing is 1345.1 m.

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"An airline is considering operating a new service. The aircraft has a maximum capacity of 200 passengers. Each flight has fixed costs of £25,000 plus an additional cost of £75 per passenger (to cover things like catering, booking, baggage handling)." "The company is considering charging £225 per ticket, how many passengers will the airline need on each flight to break even?""An airline is considering operating a new service. The aircraft has a maximum capacity of 200 passengers. Each flight has fixed costs of £25,000 plus an additional cost of £75 per passenger (to cover things like catering, booking, baggage handling)." "The company is considering charging £225 per ticket, how many passengers will the airline need on each flight to break even?"

Answers

The airline will need to have at least 167 passengers on each flight to break even.

To calculate the number of passengers needed to break even, we need to consider the total costs and the revenue generated per flight.

The total cost per flight consists of the fixed costs (£25,000) and the variable costs (£75 per passenger). The revenue per flight is determined by the ticket price (£225) multiplied by the number of passengers.

Let's denote the number of passengers as 'P'. The total cost per flight is given by:

Total Cost = Fixed Costs + (Variable Cost per Passenger * Number of Passengers)

Total Cost = £25,000 + (£75 * P)

The revenue per flight is given by:

Revenue = Ticket Price * Number of Passengers

Revenue = £225 * P

To break even, the total cost should equal the revenue:

£25,000 + (£75 * P) = £225 * P

Now, we can solve this equation for P to find the number of passengers needed to break even:

£25,000 + (£75 * P) = £225 * P

£25,000 = £225 * P - £75 * P

£25,000 = £150 * P

P = £25,000 / £150

P ≈ 166.67

Since the number of passengers must be a whole number, we round up to the nearest whole number:

P = 167

The airline will need at least 167 passengers on each flight to break even. However, since the maximum capacity of the aircraft is 200 passengers, the airline will need to fill the aircraft to its maximum capacity to break even on each flight.

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What is final velocity

Answers

Answer:

Final velocity is the velocity which the body has at the end of the given time period.

A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.
After being pulled 3.07 meters the crate has a velocity of 5.61 m/s. What is the angle (degrees) made by the rope with the horizontal?

Answers

Hi there!

We can use the work-energy theorem to solve.

Recall that:

\(\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}\)

The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:

\(W = \frac{1}{2}(50)(5.61^2) = 786.8025 J\)

Now, we can define work:

\(\large\boxed{W = Fdcos\theta}}\)

Now, plug in the values:

\(786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta\)

Solve for theta:

\(cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}\)

Calculate the wave speed for a wave with a wavelength of 2 m and a frequency of 0.3 Hz.
v=lf
a.
0.6 m/s
b. 1.67 m/s
C. 0.15 m/s
d. 2.3 m/s

Answers

Answer:

wave velocity is 0.6 so answer would be A.

Explanation:

Used omni wavelength calculator

Determine the value of F
l will give BRAINLIEST.....​

Determine the value of F l will give BRAINLIEST.....

Answers

Answer:

10 N

Explanation:

From the diagram,

Applying the principle of moment,

Sum of clockwise moment = sum of anti clockwise moment.

Assuming: the 10 N is placed on the 5 cm mark, F is placed on the 40 cm mark, The 25 N is placed on the 10 cm mark, the 30 N is placed on the 75 cm mark, and the 40 N is placed on the 80 cm mark.

Therefore,

10(50-5)+F(50-40)+40(80-50) = 30(75-50)+25(50-10)

450+10F+1200 = 750+1000

10F+1650 = 1750

10F = 1750-1650

10F = 100

F = 100/10

F = 10 N

Calculate the potential energy of a rock with a mass of 55 kg as it sits on a cliff that is 27 m high

Answers

Answer:

The potential energy is zero since the rock isn't moving.

In Fig.30.11 in the textbook, suppose that E = 60.0V, R = 240 ?, and L = 0.160H. Initially there is no current in the circuit. Switch S2 is left open, and switch S1 is closed.
a)Just after S1 is closed, what is the potential differences Vab?
b)Just after S1 is closed, what is the potential differences Vbc?
c)A long time (many time constants) after S1 is closed, what is Vab?
d)A long time (many time constants) after S1 is closed, what is Vbc?
e)What is Vab at an intermediate time when i = 0.150A?
f)What is Vbc at an intermediate time when i = 0.150A?

Answers

In the circuit described in Fig. 30.11 of the textbook, when switch S1 is closed, a current will begin to flow in the circuit and an induced emf will be generated due to the self-inductance of the coil. The potential differences Vab and Vbc can be determined using Kirchhoff's voltage law (KVL).

(a) Just after S1 is closed, the current in the circuit is initially zero. Therefore, the potential difference across the resistor R is also zero. The potential difference across the inductor L is given by:

V_L = -L(di/dt)

Since the current i is initially zero, the potential difference across the inductor is also zero. Therefore, the potential difference between points a and b (Vab) is equal to the applied voltage E:

Vab = E = 60.0 V

(b) Just after S1 is closed, the potential difference across the inductor L is equal to the applied voltage E, and the potential difference across the resistor R is zero. Therefore, the potential difference between points b and c (Vbc) is given by:

Vbc = -E = -60.0 V

(c) A long time (many time constants) after S1 is closed, the current in the circuit will reach a steady state and the induced emf due to the self-inductance of the coil will be zero. At steady state, the potential difference across the resistor R is given by:

V_R = iR

where i is the steady-state current in the circuit. The potential difference across the inductor L is zero since there is no induced emf. Therefore, the potential difference between points a and b (Vab) is given by:

Vab = V_R = iR

Using Ohm's law, we can express the steady-state current in terms of the resistance R and the applied voltage E:

i = E/R

Substituting the given values, we get:

i = 60.0 V / 240 Ω = 0.25 A

Therefore, the potential difference between points a and b at steady state is:

Vab = iR = (0.25 A)(240 Ω) = 60.0 V

(d) A long time (many time constants) after S1 is closed, the potential difference across the inductor L is zero, since there is no induced emf. Therefore, the potential difference between points b and c (Vbc) is given by:

Vbc = iR

where i is the steady-state current in the circuit. Using the value of i calculated above, we get:

Vbc = iR = (0.25 A)(240 Ω) = 60.0 V

Therefore, the potential difference between points b and c at steady state is also 60.0 V.

(e) At an intermediate time when the current in the circuit is 0.150 A, the potential difference across the resistor R is given by:

V_R = iR = (0.150 A)(240 Ω) = 36.0 V

The potential difference across the inductor L is given by:

V_L = -L(di/dt)

To determine di/dt, we can use the equation for the current in an RL circuit:

i = (E/R)(1 - e^(-Rt/L))

Differentiating both sides with respect to time, we get:

di/dt = (E/R)(e^(-Rt/L))

Substituting the given values, we get:

di/dt = (60.0 V / 240 Ω)(e^(-240t/0.160))

At the intermediate time when i = 0.150

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You are pushing a book across a desk with a constant velocity. What are the forces acting on the book and in what direction? Are the y-forces equal in magnitude, why or why not? Are the x-forces equal in magnitude, why or why not? Explain using Newton’s Second Law. If you push on the book, according to Newton’s Third Law of Motion, what is the equal and reactive force?

Answers

When you are pushing a book across a desk with a constant velocity, there are two forces acting on the book: friction and the force of your push.

The force of friction acts in the opposite direction to the motion of the book and opposes the motion of the book. The force of friction is caused by the interaction between the bottom surface of the book and the surface of the desk.

The force of your push acts in the same direction as the motion of the book and causes the book to move.

The y-forces on the book are not equal in magnitude, as there is only one force acting in the y-direction, which is the force of friction. The x-forces are also not equal in magnitude, as there is one force acting in the x-direction, which is the force of your push.

According to Newton's Second Law, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the book is moving with a constant velocity, the forces acting on the book are balanced, and the net force on the book is zero.

According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. So, when you push on the book, the equal and opposite force is the force exerted by the book on your hand.

Answer:

The book is being pushed from the side meaning there are horizontal forces at work. The first is an applied force, the second is a force of friction against the motion. Since the book is moving at a constant velocity, the book is not accelerating. This means that the forces must be balanced.

Have a Nice Day :  ) .

Course Task

As I sat under an Oak tree I recognized some similar comparisons to what Isaac Newton saw under his apple tree.
I saw three different objects fall to the ground…an acorn, a leaf, and a small stick. I wondered how and why they fell the way they did. The stick fell from the very top of the tree and seemed to almost “slow down” about half way down. The acorn got faster all the way to the ground. Yet the leaf would just float back and forth in a calm rhythm like motion.
Furthermore, I could see the moon sitting up in the sky just waiting to peak over the trees at dark.
How is it that all objects are apparently affected by the earth’s gravity but they seem to respond differently? If gravity is a force that affects all objects…shouldn’t all objects respond the same? Interesting Phenomenon huh….

Can you explain what is happening with each of these four objects (including the moon)?

Answers

Answer:

gravity effects only the mass of an object

Explanation:

an acorn is heavier that a stick and it's round shape gives it less wind resistance so gravity pulls it down faster. A stick vertical has little wind resistance but when rotated to when it is horizontal it has more resistance so it slows down but the the force of gravity is still as strong. A leaf has very little mass and it's shape provideds lots of wind resistance so it falls slower. The moon is not only effected by the earth's gravity it is also effected by the suns. It has its own gravity as well. with all these factors it stays in place and moves with the earth.

An earthquake erupted outside of Colorado and was detected 123,600 meters away after 48 seconds, the frequency of the waves was 0.25Hz what was the wavelength of the earthquake waves?

Answers

The wavelength of the earthquake waves is 12,000 meters.

To calculate

the wavelength of the earthquake waves, we can use the formula:

Wavelength = Velocity / Frequency

First, let's convert the distance of 123,600 meters to kilometers by dividing it by 1000, which gives us 123.6 km. Next, we need to calculate the velocity of the earthquake waves. The velocity of seismic waves depends on the medium through which they travel. In general, for most types of seismic waves, the velocity ranges between 2 and 8 km/s.

Assuming a conservative value of 5 km/s for the velocity, we can substitute the values into the formula:

Wavelength = (123.6 km) / (0.25 Hz)

Dividing 123.6 by 0.25 gives us a wavelength of 494.4 km.

Therefore, the wavelength of the earthquake waves is approximately 494.4 kilometers.

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pestel analysis of capei soaps?

Answers

They must follow specific regulations concerning their products and the industry they operate in, they should also follow health and safety regulations to ensure that their products are safe for consumers to use.

Pestel analysis of Capei Soaps:

Political: The manufacturing company, Capei Soaps, must follow specific policies to make sure that they can conduct business in an ethical and efficient manner.

They must adhere to labor laws, environmental laws, and anti-corruption laws.

Economic: Capei Soaps operates in an industry that is heavily dependent on the economy.

As a result, any economic changes, including a recession, can impact their production and sales.

Capei Soaps should try to find ways to operate more cost-effectively, so that they can maintain their competitive advantage.

Social: Capei Soaps has to be mindful of the current social trends and consumer preferences.

They should produce environmentally-friendly soaps, as this is what consumers are looking for.

Technological: As technology is improving, it is critical for Capei Soaps to maintain technological advancements.

This is because they have to stay ahead of their competition and use the latest technology to produce more efficient soaps.

Environmental: Capei Soaps must be environmentally conscious and try to find ways to make their soaps more eco-friendly.

This could include utilizing renewable energy, using biodegradable packaging, and reducing their carbon footprint.

Legal: Capei Soaps has to make sure they are following all legal requirements.

They must follow specific regulations concerning their products and the industry they operate in.

They should also follow health and safety regulations to ensure that their products are safe for consumers to use.

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A baseball with a mass of 0. 15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8. 0 x 103 seconds. The

ball moves off with a speed of 50 meters/second in the opposite direction. What is the value of the force?

Answers

The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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How do different elements of the
human body work together?

Answers

Answer:

There are several ways to consider the composition of the human body, including the elements, type of molecule, or type of cells. Most of the human body is made up of water and H2O, with bone cells being comprised of 31% water and the lungs 83%.1  Therefore, it isn't surprising that most of the human body's mass is oxygen. Carbon, the basic unit for organic molecules, comes in second. 96.2% of the mass of the human body is made up of just four elements: oxygen, carbon, hydrogen, and nitrogen.

Explanation:

Elements are essential units that are the basic constituents of all living and non-living beings. They are the core of the universe. Every tiny or huge particle comprises elements. Our body is built up of five major elements: Carbon, Hydrogen, Oxygen, Nitrogen and calcium.

A student is studying the Periodic Table. The student has been asked to place all of the nonmetals on the same side of
the chart. The student notices that the arrangement of the Periodic Table already has the nonmetals grouped together,
except one. In order to put all of the nonmetals on the same side, the student should relocate one element on the Periodic
Table. Which element should be relocated and in which direction?
4x A Helium should be moved to the left on the Periodic Table,
4x B
4x
Hydrogen should be moved to the right on the Periodic Table,
C Hydrogen should be moved down its family on the Periodic Table,
D
Helium should be moved down its family on the Periodic Table.
Next

Answers

Answer:

A is the right answer

Explanation:

mark me as a

Answer: B) Hydrogen should be moved to the right on the Periodic Table.

A force acts on an object. Which option describes an action that could prevent the object from moving

Answers

Answer:

Friction or tension

Explanation:

Friction stops an object from moving in the presence of force

Why does air move from solid land towards water during the night?

A-Solid ground cools faster at night while water remains heat longer, warming the air above the water.

B- The ground retains the heat from the sun longer than the water.

C- The dry air over the land is heavier than the air over the water the contains more water vapor

D- gravity moves the air towards the water because water is lower than the land

Answers

Answer:

A

Explanation:

This is to do with convection currents :)

Hope this helps!

Supposing the half-life of element x to be 1 year, if you have a 100 gram sample of x, how much of element x would be left after 4 years? (do not use significant digits in answering this question.)
75 g
50 g
25 g
6.25 g

Answers

6.25 gram of element x would be left after 4 years.

What's half life of an element?Half - life is the time period of decay of an element to half of its initial number of nuclei.After n no. of half lives, no. of nuclei left in the sample is initial number of nuclei / 2^n

What's the amount of 100 gm of element x left after 4 half lives ?

Leftover amount of the element x = 100/2^4

= 100/16 = 6.25 gram

Thus, we can conclude that 6.25 gram of element x would be left after 4 years.

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A walkway suspended across a hotel lobby is supported at numerous points along its edges by a vertical cable above each point and a vertical column underneath. The steel cable is 1.27cm in diameter and is 5.75m long before loading. The aluminum column is a hollow cylinder with an inside diameter of 16.14cm, and an unloaded length of 3.25m. When the walkway exerts a loa force of 8500N on one of the support points, through what distance does the point move down?

Answers

Answer:

\(\triangle I=8.60*10^{-4}m\)

Explanation:

From the question we are told that:

Diameter \(d=1.27cm\)

Length \(l=5.75m\)

Diameter of aluminum column \(d_a=16.14cm\)

Length of aluminum column \(l_a=3.25m\)

Load Force \(F=8500N\)

Generally the equation for Young modulus is mathematically given by

\(\gamma=\frac{FL}{A \triangle L}\)

Given the The load force

\(F=\frac{Y_aA_a\triangle I}{L_a}+\frac{YA \triangle I}{L}\)

\(\triangle I=\frac{F}{\frac{Y_aA_a}{L_a}}+\frac{YA}{L}\)

\(\triangle I=\frac{8500N}{ \frac{7*10^{10} \pi (0.1624^2-0.1614^2)}{4*3.15}+ \frac{20*10^10 \pi (0.0127^2)}{4(5.75)}}\)

\(\triangle I=8.60*10^{-4}m\)

the block of mass m in the following figure slides on a frictionless surface

Answers

For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.

The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.

When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.

\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)

Substituting the known values:

\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)

Solving for m₂:

\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)

The mass of the right block must be 7.9 kg for the two blocks to remain stationary.

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The question is -

Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg

the block of mass m in the following figure slides on a frictionless surface

A rope is used to pull a box 15.0 m across a floor. The rope is held at an angle of 46.0˚ and a force of 628 N is used along the rope. What is the work done? Your answer should be rounded to the tenths place, and include the correct units. View question

Answers

Answer:

6544.07 J

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 15 m

Force (F) = 628 N

Angle (θ) = 46°

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 628 × 15 × Cos 46

Wd = 9420 × 0.6947

Wd = 6544.07 J

Therefore, the workdone is 6544.07 J

An apple in a tree has a GPE of 175 J and a mass of 0.36 KG how high from the ground is the apple Solve for  height

Answers

Answer:

The height of the apple from the ground is at 49552.61071 m or is approximately at 5.0 × 10 m

Explanation:

The rotor on a helicopter turns at an angular speed of 3.20 × 102 revolutions per minute. (In this book, we sometimes use the abbreviation rpm, but in most cases we use rev/min.)(a) Express this angular speed In radlans per second.(b) If the rotor has a radlus of 2.00 m, what arc length does the tip of the blade trace out in 3.00 x 10 ?(c) The pilot opens the throttle, and the angular speed of the blade increases while rotating twenty-six times in 3.60 s. Calculate the average angular speed during that time

Answers

The rotor on a helicopter turns at an angular speed of 3.20 × 102 revolutions per minute.

(a) The angular speed in radians per second is 33.6 radians/second.
(b) If the rotor has a radius of 2.00 m, the arc length at which the blade traces out in 3.00 x 10² seconds is 2.016 x 10⁴ meters

(c) If the pilot opens the throttle, and the angular speed of the blade increases while rotating twenty-six times in 3.60 s, the average angular speed is 45.3 radians/second


(a) To express the angular speed in radians per second, first convert the given speed from revolutions per minute to radians per second.
1 revolution = 2π radians
1 minute = 60 seconds

 Angular speed = 3.20 × 102 rev/min × (2π radians/1 rev) × (1 min/60 sec)

                           = 33.6 radians/second

(b) To find the arc length traced by the tip of the blade in 3.00 x 10² seconds, first calculate the total angle in radians that the rotor turns in that time.

             Total angle = angular speed × time

                                 = 33.6 radians/sec × 3.00 x 10² sec

                                 = 1.008 x 10⁴radians

             Arc length (s) = radius (r) × angle (θ)

                                    = 2.00 m × 1.008 x 10⁴radians

                                    = 2.016 x 10⁴ meters

(c) To calculate the average angular speed during the 3.60 seconds when the rotor rotates twenty-six times, first convert the number of rotations to radians.

           Total angle = 26 rev × (2π radians/1 rev)

                               = 52π radians

           Average angular speed = total angle/time

                                                    = (52π radians)/(3.60 sec)

                                                    ≈ 45.3 radians/second

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