When a circular runout tolerance is applied to a surface of revolution:A. The tolerance zone applies to all circular elements of the surface simultaneously.B. The tolerance zone applies to one circular element of the surface.C. The tolerance zone applies only once anywhere on the indicated surface.D. The tolerance zone applies to each circular element of the surface independently.

Answer:

20% of the critical value. Determine (a) the damping factor, (b) the

Explanation:

Answer:

Ribosomes 1

Explanation

Ribosomes are small structures where proteins are made. Although they are not enclosed within a membrane, they are frequently considered organelles. Each ribosome is formed of two subunits, like the one pictured at the top of this section. Both subunits consist of proteins and RNA

Answer:

i hope it's correct

Explanation:

A thermal boundary layer will not develop in flow over a surface if both the fluid and the surface are at the same temperature since there will be no heat transfer in that case.

Answer:

4th generation computers

Silicon chips are used primarily in relays. The correct option is B.

The brain of the device is made up of silicon chips, which control all of its internal mechanisms. Tablets, smartphones, and laptops are a few examples.

The invention of silicon chips led to the revolutionization and miniaturization of technology, as well as the creation of the contemporary computer.

Instead of the slow computers that used to take up entire rooms, it made it possible to create fast computers that fit in people's homes and eventually portable computers.

Relays are electrically powered switches that operate by receiving electrical signals from other sources to open and close circuits.

Therefore, the correct option is B. relays.

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The question is incomplete. Your most probably complete question is given below:

A. integrated circuits

B. relays

C. motors

D. transformers

The spreadsheet can be set up to allow for additional density and percent crystallinity values to be inputted, and the formulas will update automatically. With this spreadsheet, the user can easily determine the density and percent crystallinity of the polymer for various values.

To develop a spreadsheet for the given polymer, we can use the following formulas:

(a) Density of totally crystalline polymer = Highest density value given
(b) Density of totally amorphous polymer = Lowest density value given
(c) Percent crystallinity of a specified density = (Density of the specified value - Density of totally amorphous polymer) / (Density of totally crystalline polymer - Density of totally amorphous polymer) x 100
(d) Density for a specified percent crystallinity = Density of totally amorphous polymer + (Specified percent crystallinity / 100) x (Density of totally crystalline polymer - Density of totally amorphous polymer)

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Answer:

B!

Explanation:

Answer:

B. Flying solo across the atlantic

Explanation:

history class

The number of character comparisons that are used by the Naive String Matcher to search for the pattern of the text "love" in the text is defined as  The naive approach is an elementary algorithm for solving string matching problems.

When looking for a substring in a string, the naive method examines each character in the substring for a match against the text starting at every possible position.
To check whether the pattern occurs in the text or not, the naive algorithm compares each character of the pattern to the corresponding character of the text.

Since there are four characters in the pattern "love," the total number of character comparisons required by the naive string matcher to search for the pattern of "love" in the text would be equal to the length of the text multiplied by the length of the pattern, or more precisely, 4n character comparisons are needed for a text of length n.

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The major types of interior walls and partitions in a larger building are:

It is different because it is more durable than the rest and it is also:

Conclusively, the coats of plaster that are used over expanded metal lath are:

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A saturated soil with a mass of 43.2g. When dried in the oven its mass was 30g, the limit of contraction is 0.4.

For the limit of contraction, we know that:

Limit of contraction (Lc) = (Vw - Vd) / Vw

Lc = (20 - 12) / 20

Lc = 8 / 20

Lc = 0.4

Therefore, the limit of contraction is 0.4.

Now for the dry weight,

Dry unit weight (γd) = γw / (1 + e)

e = (Gs - 1) / Gs

n = e / (1 + e)

w = (wet weight - dry weight) / dry weight

In this case,

γw = 9.81 kN/\(m^3\)

Gs = 2.74.

So,

γd = 2010 / (1 + ((2.74 - 1) / 2.74))

γd = 2010 / (1 + 0.727)

γd = 2010 / 1.727

γd = 1163.54 kg/m^3

e = (2.74 - 1) / 2.74

e = 1.74 / 2.74

e ≈ 0.635

n = 0.635 / (1 + 0.635)

n = 0.635 / 1.635

n ≈ 0.388

w = (43.2 - 30) / 30

w = 13.2 / 30

w ≈ 0.44

Therefore, the dry unit weight (γd) is approximately 1163.54 kg/m^3, the void ratio (e) is approximately 0.635, the porosity (n) is approximately 0.388, and the moisture content (w) is approximately 0.44.

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the radius using a 3-inch diameter cylinder to get a surface area of 7.065 square inches (1.5 x 1.5 x 3.14).

It is true that size matters when it comes to hydraulic cylinders. The size of the cylinder is determined by a number of crucial factors, including its mass, bore diameter, rod diameter, and even how it will move within the hydraulic system.

The standard recommendation for a typical reservoir used in open circuits is a tank oil capacity of three to five times the flow of the pump(s) per minute plus a ten percent air cushion. The general recommendation is 5 to 8 times pump flow per minute for HFC and HFD fire-resistant fluids.

When calculated as the transverse section to the wet perimeter, the equivalent diameter is determined to be two times the hydraulic radius.

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The semi-major axis is approximately 5,311.6 km, the radius of apoapsis is approximately 22,316.5 km, the velocity at apoapsis is approximately 0.712 km/sec, the radius of periapsis is approximately 1,306.7 km, the eccentricity is approximately 0.917, and the semi-latus rectum is approximately 844.7 km.

To determine the required parameters, we can use the vis-viva equation and the formulas for the semi-major axis, eccentricity, and semi-latus rectum of an elliptical orbit:

Semi-major axis (a):

a = (2π/ T)² (μₘ/a)⁻¹/³

where T is the orbital period and μₘ is the gravitational parameter of Mars.

Substituting the given values, we get:

a = (2π/18.6 hr)² (4.269 x 10⁴ km³/sec² / 3397.2 km)⁻¹/³

a ≈ 5,311.6 km

Radius of apoapsis (ra):

ra = a(1 + e)

where e is the eccentricity of the orbit.

Velocity at apoapsis (va):

va = (μₘ/ra)⁰⁵ (2/rp - 1/a)⁰⁵

where rp is the radius of periapsis.

Radius of periapsis (rp):

rp = a(1 - e)

Eccentricity (e):

e = (ra - rp)/(ra + rp)

Semi-latus rectum (p):

p = a(1 - e²)

Now, let's calculate each parameter:

Radius of apoapsis (ra):

We can use the fact that the spacecraft's orbit is highly elliptical to assume that the orbit is nearly a straight line from the periapsis to the apoapsis. Therefore, the spacecraft's position at apoapsis is approximately at the maximum distance from Mars. At this point, the spacecraft's speed is at a minimum, and it is moving only due to the gravitational attraction of Mars. Hence, we can assume that va ≈ 0.

From the given information, we know that the orbital period T = 18 hr 36 m. Therefore, the time taken for one complete orbit from periapsis to apoapsis is half of the period, or T/2 = 9 hr 18 m.

Using the vis-viva equation, we can find the radius of apoapsis:

va² = μₘ(2/rp - 1/a)

0 = μₘ(2/rp - 1/ra)

2ra = rp + ra

ra = 2a - rp

Substituting this expression for ra in terms of a and rp into the equation above, we get:

Up² = μₘ(2/rp - 2/(2a-rp))

Up² = μₘ(2/rp - 1/a + 2/rp - 2/a)

Up² = μₘ(4/rp - 3/a)

ra = (Up²/μₘ)⁻¹ (4/rp - 3/a)⁻¹

ra = (4.269 x 10⁴ km³/sec²)(3600 s/hr)²/(Up)² (4/rp - 3/a)⁻¹

ra ≈ 22,316.5 km

Velocity at apoapsis (va):

We can use the equation derived above:

va = (μₘ/ra)⁰⁵ (2/rp - 1/a)⁰⁵

va ≈ (4.269 x 10⁴ km³/sec² / 22,316.5 km)⁰⁵ (2/3,827.6 km - 1/5,311.6 km)⁰⁵

va ≈ 0.712 km/sec

Radius of periapsis (rp):

We can use the equation ra = 2a - rp to find rp in terms of ra and a:

rp = 2a - ra

rp = 2(5,311.6 km) - 22,316.5 km

rp ≈ 1,306.7 km

Eccentricity (e):

We can use the formula for eccentricity:

e = (ra - rp)/(ra + rp)

e = (22,316.5 km - 1,306.7 km)/(22,316.5 km + 1,306.7 km)

e ≈ 0.917

Semi-latus rectum (p):

We can use the formula for semi-latus rectum:

p = a(1 - e²)

p = 5,311.6 km(1 - (0.917)²)

p ≈ 844.7 km

Therefore, the semi-major axis is approximately 5,311.6 km, the radius of apoapsis is approximately 22,316.5 km, the velocity at apoapsis is approximately 0.712 km/sec, the radius of periapsis is approximately 1,306.7 km, the eccentricity is approximately 0.917, and the semi-latus rectum is approximately 844.7 km.

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The text format of the question in the picture:

The Mars Odyssey spacecraft successfully entered a highly elliptical Mars polar orbit on October 24, 2001 (UTC). Here is the information we have concerning the orbit (note that μₘ = 4.269 x 10⁴ km³/sec² and rₘ = 3397.2 km):

Orbital period = 18 hr 36 m

Up = 4.582 km/sec

a) Determine the semi-major axis (a), radius of apoapsis (ra), velocity at apoapsis (va), radius of periapsis (rp), eccentricity (e), and semi-latus rectum (p) of the orbit.

Drone refers to an unmanned aircraft that can fly autonomously or be remotely operated by a human pilot. Drones are used for a variety of applications, including military and commercial purposes.

A drone, also known as an unmanned aerial vehicle (UAV), is an aircraft without a human pilot on board. It is controlled remotely or can fly autonomously. Drones are commonly used in military applications, as well as for commercial, scientific, and recreational purposes. Drones range in size from small handheld models to larger aircraft that can carry heavy payloads.

Drones are used for a variety of applications, including:Surveillance and reconnaissance

Search and rescue

Aerial photography and videography

Delivery of goods and packages

Inspection of infrastructure such as power lines and bridges

Mapping and surveying

Weather monitoring and research

Drones can help communities in a variety of ways, including:

Disaster response and relief

Efficient delivery of medical supplies and equipment

Search and rescue operations

Wildlife conservation and monitoring

Agriculture monitoring and management

Traffic monitoring and control

Drones can create new job opportunities in a variety of fields, including:

Drone pilots and operators

Aerial photographers and videographers

Data analysts and surveyors

Drone manufacturers and retailers

Consultants and trainers in drone-related fields

Entrepreneurs who develop drone-related businesses and services

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b. false Meter loading refers to inaccurate readings due to the meter's resistance being in series with the component being tested, not in parallel.

When a meter is connected in series with a component, the meter's internal resistance creates a voltage drop that affects the measurement of the component's voltage or current.

The internal resistance of a meter forms a voltage divider with the component's resistance, causing a voltage drop across the meter itself. This voltage drop reduces the voltage or current being measured, leading to inaccurate readings. The extent of the error depends on the relative magnitudes of the meter's internal resistance and the component's resistance.

To minimize meter loading and obtain more accurate readings, meters with high input impedance (low internal resistance) are used. These high-impedance meters minimize the voltage drop across the meter and have minimal impact on the circuit being measured.

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A) The amount of space must be left between adjacent rails if they are just to touch on a summer day when their temperature is 31.0 °C is; 0.6048 cm

B) The stress in the rails on a summer day when their temperature is 31.0 °C is; 86.4 × 10⁶ Pa

We are given;

Length; L = 14 m

Initial Temperature; T_i = −5 °C

Final Temperature; T_f = 31 °C

The formula for Linear Thermal Expansion is;

ΔL = L_i * α * ΔT

where;

L_i is initial length

α is thermal expansion

ΔL is change in length

ΔT is change in temperature

Now, the thermal expansion of steel from online tables is α = 1.2 × 10⁻⁵ C⁻¹

Thus;

ΔL = 14 * 1.2 × 10⁻⁵  * (31 - (-5))

ΔL = 6.048 × 10⁻³ m = 0.6048 cm

The formula to get the stress is;

σ = Y * α  * ΔT

where;

Y is young's modulus of steel = 20 × 10¹⁰ Pa

α is thermal expansion

ΔT is change in temperature

Thus;

σ = 20 × 10¹⁰ × 1.2 × 10⁻⁵ × (31 - (-5))

σ = 86.4 × 10⁶ Pa

The complete question is;

Steel train rails are laid in 14.0-m long segments placed end to end. The rails are laid on a winter day when their temperature is −5 °C.

(a) How much space must be left between adjacent rails if they are just to touch on a summer day when their temperature is 31.0 °C?

(b) If the rails are originally laid in contact, what is the stress in them on a summer day when their temperature is 31.0 °C?

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Answer:

The distributions of solid wastes produced daily at a commercial facility are normally distributed with a mean of 10 yd3 and a standard deviation of 7 yd3. If you were to make a container size recommendation for this facility, what size would you propose? What important tradeoffs should be considered when selecting the size of the container?

It's quite perplexing to determine the perfect size of container for a facility whose waste quantity varies and is subject to changes frequently. A certain degree of burstiness is present in the distribution of solid waste generated on a daily basis in a commercial facility. However, using the available mean and standard deviation values, we can infer that a container size of 24 yd3 should be sufficient to hold the daily waste generated, considering that it's two standard deviations above the mean.

When selecting a container size, various tradeoffs must be considered. A large container is more efficient, as it would not require to be emptied as frequently, but it might be expensive and may take up more space. A smaller container may be less expensive and take up less space, but it would need to be emptied more frequently, which can result in higher transportation costs and more time spent on waste management. It is therefore essential to strike a balance between the frequency of emptying and the container size to ensure that the waste is managed effectively and efficiently.

The experimental probability of Brandy rolling a strike in the first frame of the next game is 1/5.

Given that Brandy rolls a strike in 2 out of 10 frames in a game, we can calculate the experimental probability of her rolling a strike in the first frame of the next game. Since there are 10 frames in a game, the probability of Brandy rolling a strike in any given frame is 2/10 or 1/5. Therefore, the experimental probability of her rolling a strike in the first frame of the next game is also 1/5. This is based on the assumption that her performance in each frame is independent of the others, and the probability remains constant from frame to frame.

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ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.

ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.

In the case above about manual transmission, the gears are engaged manually.

The Definition of the term manual transmission is regarded as a kind of a system where there is the changing gears in a manual way.

Hence, In the case above about manual transmission, the gears are engaged manually is correct.

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Answer:

1) This is because too much fuel is needed to get a payload from the surface to orbital altitude an accelerated to orbital speed.

2) This is because space travel present extreme environment that affect machines operations and survival.

Explanation:

Hope it helps

sen yapsana mk halla halla yaw

If we consider the first element to be the next of the last element, we have a circular array. Queues are implemented using circular arrays.

What is Array?

An array is a collection of numbers, pictures, or objects that are organized in to the rows and columns based on their type. An array is a set of items, or data, stashed in contiguous memory locations, also recognized as database systems, in coding and programming.

An array's purpose is to keep multiple pieces of data of the same type around each other. An array can be used to illustrate a mathematical property known as the commutative property of multiplication, that also shows that the order of the factors or elements could be changed into, while the product of these elements remains as constant.

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Answer:

\( \therefore \) The power output of the draw-works motor is 4.36 hp

Explanation:

Given that,

As the problem given, the cable is tied of the top on the oil rig and it wraps around the lower pulley and the top pulley. So, we will be using the formula below:

Differentiate it but with respect to the time. Therefore,

Thus,

Thus, the power output should be

\( P = Fv = \bigg(\frac{600}{2}\bigg) \cdot 8 = 2400 \ lb \cdot ft/s = \frac{2400}{550} = 4.36 \ hp \)

\( \therefore \) The power output of the draw-works motor is 4.36 hp

A "While" Loop is used to repeatedly execute a particular block of code until a condition is met.

The responses to the questions are listed below. The operation that determines whether the condition x 10 is true is assessed first because the operator is used first. The reason for this is that we use the post increment operator for x. As a result, x is first used for the operation we are performing before being raised by 1. According to semantics, the variable's value is increased by 1 by both prefix and postfix ++. The result of the operator is the NEW/CURRENT value stored in the variable if the ++ is placed before the variable (a prefix operator); the result of the operator is the value stored in the variable if the ++ is written after the variable (a postfix operator).

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The correct option that describes 17mA is option D, 17,000µA.What is an ampere?An ampere is a basic International System unit (SI).

The amount of current that passes through a conductor in one second with a charge of one coulomb is referred to as an ampere. An ampere is also known as an amp.What is milliampere?A milliampere is a one-thousandth (1/1000) of an ampere. This unit is used to measure low current values, typically in electronic circuits and low-power devices.So, 17mA may be represented as 17 x 1000 µA= 17000 µA.How is the conversion of milliampere to microampere done?We know that 1mA= 1000µA; 17mA will be equal to 17*1000 µA= 17,000µA.This answer is the correct one that describes 17mA. It's crucial to know the correct unit when you're measuring current since it can have significant implications for the circuit's overall performance.

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The boundary work for the heating of air in a rigid tank from a pressure of 100 kPa to 500 kPa can be calculated as follows:First, we need to assume that there is no change in the volume of the air in the tank, which implies that there is no expansion or contraction of the air.

Therefore, the work done on the air is equal to the change in pressure, which is given as ΔP = P₂ - P₁ = 500 kPa - 100 kPa = 400 kPa, since the volume remains constant. The boundary work done is then given asW = ΔP * Vwhere V is the volume of air in the tank.We know that the volume of the air in the tank remains constant, therefore V can be taken as a constant and we can say thatW = ΔP * V = 400 kPa * VSince we don't have any information about the volume of air in the tank, we cannot calculate the boundary work for this process.

However, we can say that the boundary work done is positive, since the pressure increases. The boundary work is the work done by the gas on its surroundings during an isobaric process, that is, when the pressure remains constant.

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Answer: the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s

Explanation:

from the T-S diagram, we get the overall pressure ratio of the cycle is 9

Calculate the pressure ratio in each stage of compression and expansion. P1/P2 = P4/P3  = √9 = 3

P5/P6 = P7/P8  = √9 =3  

get the properties of air from, "TABLE A-17 Ideal-gas properties of air", in the text book.

At temperature T1 =300K

Specific enthalpy of air h1 = 300.19 kJ/kg

Relative pressure pr1 = 1.3860  

At temperature T5 = 1200 K

Specific enthalpy h5 = 1277.79 kJ/kg

Relative pressure pr5 = 238  

Calculate the relative pressure at state 2

Pr2 = (P2/P1) Pr5

Pr2 =3 x 1.3860 = 4.158  

get the two values of relative pressure between which the relative pressure at state 2 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.  

Relative pressure pr = 4.153

The corresponding specific enthalpy h = 411.12 kJ/kg  

Relative pressure pr = 4.522

The corresponding specific enthalpy h = 421.26 kJ/kg  

Find the specific enthalpy of state 2 by the method of interpolation

(h2 - 411.12) / ( 421.26 - 411.12) =  

(4.158 - 4.153) / (4.522 - 4.153 )

h2 - 411.12 = (421.26 - 411.12) ((4.158 - 4.153) / (4.522 - 4.153))  

h2 - 411.12 = 0.137

h2 = 411.257kJ/kg  

Calculate the relative pressure at state 6.

Pr6 = (P6/P5) Pr5

Pr6 = 1/3 x 238 = 79.33  

Obtain the two values of relative pressure between which the relative pressure at state 6 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.  

Relative pressure Pr = 75.29

The corresponding specific enthalpy h = 932.93 kJ/kg  

Relative pressure pr = 82.05

The corresponding specific enthalpy h = 955.38 kJ/kg  

Find the specific enthalpy of state 6 by the method of interpolation.

(h6 - 932.93) / ( 955.38 - 932.93) =  

(79.33 - 75.29) / ( 82.05 - 75.29 )

(h6 - 932.93) = ( 955.38 - 932.93) ((79.33 - 75.29) / ( 82.05 - 75.29 )

h6 - 932.93 = 13.427

h6 = 946.357 kJ/kg

Calculate the total work input of the first and second stage compressors

(Wcomp)in = 2(h2 - h1 ) = 2( 411.257 - 300.19 )

= 222.134 kJ/kg  

Calculate the total work output of the first and second stage turbines.

(Wturb)out = 2(h5 - h6) = 2( 1277.79 - 946.357 )

= 662.866 kJ/kg  

Calculate the net work done

Wnet = (Wturb)out  - (Wcomp)in

= 662.866 - 222.134

= 440.732 kJ/kg  

Calculate the minimum mass flow rate of air required to generate a power output of 105 MW

W = m × Wnet

(105 x 10³) kW = m(440.732 kJ/kg)

m = (105 x 10³) / 440.732

m = 238.2 kg/s

therefore the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s

To meet the demand for component A without increasing lot sizes, 192.86 machines are required, exceeding the available 3 machines.

a. Calculation of machines required for minimum (Pessimistic) demand:

For component A, Processing (hr/unit) = 0.04

Lot Size (units/lot) = 60

Total demand required for pessimistic forecast = 15,000 machines

For pessimistic forecast, the processing time required will be: 15,000 × 0.04 = 600 hours

Setup (hr/lot) = 1.0

For 30% capacity cushion, the total operating hours will be: (600 / (1 - 0.3)) = 857.1428571428571

For expected forecast, the processing time required will be: 16,000 × 0.04 = 640 hours

For 30% capacity cushion, the total operating hours will be: (640 / (1 - 0.3)) = 914.2857142857142

For optimistic forecast, the processing time required will be: 27,000 × 0.04 = 1080 hours

For 30% capacity cushion, the total operating hours will be: (1080 / (1 - 0.3)) = 1542.857142857143

Therefore, the machines required will be:

107.14 machines for pessimistic forecast

114.29 machines for expected forecast

192.86 machines for optimistic forecast

b. Calculation of machines required if the operations manager decides to double lot sizes:

Pessimistic forecast: 120 units/lot

Expected forecast: 150 units/lot

Optimistic forecast: 200 units/lot

The calculation of the total operating hours and machines required will be the same as in part a, with the respective lot sizes.

c. Calculation of the number of machines required with 20% reduced setup time:

New setup time for component A: 0.8 hours/lot

The calculation of the new processing hours and machines required will be the same as in part a, with the reduced setup time.

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Answer:

The following are some advantages of a Top-down design approach:

1. Separating a problem into more smaller parts causes it to be far more simpler and easier to tackle and manage.

2. Top down design permits programmers or groups to work on a similar projects without getting in one another's way.

3. Every module of code to be tested independently.

4. Top-down plan permits the systems analyst to analyze the general organizational objectives first.

5. The top-down design likewise gives attractive accentuation on collaboration or the interfaces that systems and their subsystems require.

6. Top-down design allows system analyst to work in parallel on different sub-systems which can save a lot of time.

Explanation:

Most systems comprise of progressively more modest and more modest sub-systems.

Top down design is the name given to separating an issue into progressively smaller and more smaller sensible parts (otherwise called decomposition).

Answer:

look online

Explanation:

Incorrect result: (C) ?- bachelor(Who). Who = henry; Who = joe; false. The Option C.

The query bachelor(Who) is expected to find all individuals who are male and not married, providing their names as solutions. However, the incorrect result is obtained in this case.

The correct part of the result, Who = henry, is consistent with the knowledge base, as Henry is declared as a male and is not married. However, the incorrect part of the result, Who = joe, is unexpected. There is no mention of Joe in the knowledge base, so the query should not yield him as a solution.

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