When a hydrochloric acid solution is combined with a potassium hydroxide solution, an acid-base reaction occurs. write a balanced molecular equation for this reaction. Write a net ionic equation for this reaction.

Answer:

A

Explanation:

Na2SO4 +BaCl2 ____BaSO4+2NaCl

There are vacant orbitals on the phosphorus atom that allows it to expand its octet.

There is a concept that we would need to consider as we are answering the question that we here and that is the idea of the octet rule. The octet rule states that it is only about eight electrons that can be found on the outermost shell of an atom and as such all of the compounds can be formed in obedience to this rule.

Now we should know that there are no vacant d orbitals that are present on the nitrogen atom and this stems from the fact that it does not have a 3d level as such there are no orbitals that can be able to help the Nitrogen atom so as to be able to expand its octet. This is the reason why its pentafluoride can be easily formed.

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The concentration of AB, in mol/dm³, after 6 minutes : 0.125

For first-order reaction :

\(\tt [A]=[A]oe^{-kt}\rightarrow t1/2=\dfrac{ln~2}{k}\)

The half-life of the reaction is 2 minutes⇒t1/2=2 minutes

The concentration of AB, in mol dm, after 6 minutes ⇒ t=6 minutes

The rate constant (k) :

\(\tt k=\dfrac{ln~2}{t1/2}=\dfrac{0.693}{2}=0.3465\)

The concentration after 6 minutes :

\(\tt [A]o=0.1~mol/100~cm^3=1~~mol/dm^3\\\\(A]=1\times e^{-0.3465\times 6}\\\\(A]=0.125\)

Answer:

C)a mass number of 38

Explanation:

yes

Answer:

5.12 L

Explanation:

P1V1/T1 = P2V2/T2

1.71 atm *10.0L /100 K = 9.70 atm *x/290.29 K

x = 1.71 atm *10.0L*290.29K /(100 K * 9.70 atm)= 5.12 L

The chemical formula for the ionic compound barium iodide is \(BaI_2\) .

Barium iodide is composed of one barium ion (Ba2+) and two iodide ions (I-), which together form a neutral compound. Barium iodide is a white crystalline solid with a high melting point and is soluble in water. It is commonly used in the manufacture of photographic paper and in the production of cathode ray tubes for televisions and computer monitors.

Barium iodide has a variety of other uses, including in medicine as a contrast agent for X-ray imaging and in the synthesis of organic compounds.

The compound has several different crystal structures, including hexagonal and cubic, and can be prepared by reacting barium carbonate with hydroiodic acid. Overall, barium iodide is an important and versatile compound with a range of practical applications.

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Option D, W3+ (g) → W4+ (g) + e-, requires the most energy for the ionization process.

The ionization interaction that requires the most energy is choice D, where W3+ (g) is ionized to W4+ (g) by the deficiency of one electron. This is on the grounds that the energy expected to eliminate an electron from a particle increments as the particle turns out to be all the more decidedly charged. Hence, it takes more energy to eliminate an electron from W3+ (g) than it does from W+(g), W2+ (g), or W3+ (g).

Choice An includes the expulsion of one electron from an impartial tungsten iota, and choice B includes eliminating an electron from W+. Choice C includes eliminating an electron from W2+. These ionization processes require less energy than choice D in light of the fact that the ionization energy increments as the particle turns out to be all the more emphatically charged. Hence, the ionization energy expected to eliminate an electron from W3+ is more prominent than that expected to eliminate an electron from any of the past particles.

Subsequently, choice D, W3+ (g) → W4+ (g) + e-, requires the most energy for the ionization interaction.

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A. The incandescent light bulb does not create as much as much light energy as the fluorescent light bulb.

Incandescent light bulbs have the drawback of wasting a lot of electricity due to heat. All the energy used to create heat is a waste because heat does not produce light, and the light bulb's intended function is to produce light. Thus, incandescent lamps are quite ineffective.

Mercury vapor is excited by an electric current in the gas to produce short-wave ultraviolet light, which illuminates a phosphor coating inside the lamp. Compared to an incandescent lamp, a fluorescent lamp is far more efficient at converting electrical energy into usable light.

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We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Mass of Cu = 63.5

Mass of S = 32

Mass of O = 4

Total molecular mass = 63.5 + 32 + 16 × 4 = 159.5 amu

To synthesize the given compound from an alkyl bromide and a nucleophile in an SN2 reaction, you need to draw the reactants using the wedge/hash bond tools to indicate stereochemistry.

If there is more than one possible combination of alkyl bromide and nucleophile , draw only one combination. Do not include counter-ions, e. g. Na+, I-, in your answer. For example, one possible combination could be:

R-Br + Nu: → R-Nu + Br-

An alkyl bromide is a type of organic compound that contains a carbon atom bonded to a bromine atom. Alkyl bromides are classified as alkyl halides, which are compounds that contain a carbon atom bonded to a halogen atom. Alkyl bromides are commonly used in a variety of organic reactions, such as in substitution reactions, in which the carbon-bromine bond is replaced by a different group. Alkyl bromides can also be used to make alkyl sulfonates, alkyl esters, and other compounds. Alkyl bromides are generally colorless liquids or solids, and have a low boiling point.

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Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

Firstly, we need to balance the reaction.

The hydrogen appear in two products, so let's start with it. We need to have the same number of H in both sides, but we have 2 on the left side and 3 on the right side.

If we add a coefficient of 2 in H₂O we will have 4 H on the left side, which is now more than the 3 we have on the right side.

However, if then we add a coefficient of 2 in NaOH too, we will have 4 H in both sides.

The O will also be balanced because we will have 2 in each side.

The Na, on the other hand, we will have 1 on the left side and 2 on the irght sicde because of the coefficient 2 in NaOH, so to finish the balancing we need to add a coefficient of 2 in Na.

So, the balanced reaction is:

(a) Firslty, we need transform the masses into number of moles. For this, we will need the molar masses of Na and H₂O:

So, in number of moles, we have:

Since both Na and H₂O have the same coefficients, for each Na that reacts, 1 H₂O will react, which means that we can see which one is in excess and which one is the limiting one by simple comparison.

Since we have more number of moles of Na than H₂O, we have Na in excess and H₂O is the limiting one.

So, assuming all the limiting reactant is consumed, we can calculate how much H₂ will be produced using the relation set by their coefficients:

H₂ --- H₂O

1 --- 2

Since the options are in grams, we need to convert this to mass, which we do as the opposite as we done with the initial masses. So we start by the molar mass of H₂:

Now, we covert to mass:

So, the mass produced of H₂ is approximately 0.839 g.

(b) Assuming LR stands for limiting reactant and ER stands for excess reactant, we already saw which is which in item (a):

LR: H₂O

ER: Na

(c) Since both Na and H₂O have the same coefficient, the number of moles of H₂O that reacted is the same as the number of moles of Na that reacted, so:

Since we had a total of 1.0874... mol of Na, we can calculate the number of moles left by substracting the amount that reacted:

And now we use the molar amss of Na to convert it to mass:

We can see that we don't have the exact option, but we have the option 5.87g. The difference comes from different rounding used.

So, the excess left is approximately 5.87 g.

Answer:

Explanation:

balance

2 C2H6 + 7  O2  --> 4 CO2 + 6 H2O

given 360 g H20 (g)

required =586.67 g CO2

360 g H20 x (1mole/18 g H20) X (4 mole CO2/6 moles H20) X (44g CO2/1mole) =586.67 g CO2

Answer:

Largest: Mg

Smallest: Cl

Explanation:

Hail is most commonly formed within the cumulonimbus clouds of thunderstorms. Large updrafts of air can throw rain droplets high up into the tops of the cloud.

What is a thunderstorm?

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Answer:

Explanation:

Hope this helps good day

Answer:

I'm going to call the length of the bracelet the number of times you have to add to get back to the first bead. This is the same as the number of beads, except in one case:

The shortest bracelet has length 1 and starts with (0,0). If you add one time, you get back to the first 0. But the bracelet has two beads. (Every bracelet has to have at least two beads to start.) The next shortest bracelet starts with (0,5), and has length 3: 0 5 5.

There is a bracelet of length 4 that starts with (2,6) (the first example on the main page):

2 6 8 4

There is a bracelet of length 12 that starts with (1,3) (the second example on the main page):

1 3 4 7 1 8 9 7 6 3 9 2

There is a bracelet of length 20 that starts with (0,4)

0 4 4 8 2 0 2 2 4 6 0 6 6 2 8 0 8 8 6 4

There is a bracelet of length 60 that starts with (0,1)

Answer:Electrical Conductivity,soluble

Explanation:

Salt is a non-magnetic solid and is soluble in water. Sand is a non-magnetic solid and is insoluble in water.

Electrical Conductivity: Salt is an electrolyte and conducts electricity when dissolved in water or in a molten state. This is because salt dissociates into ions (Na+ and Cl-) that can carry electric current. In contrast, sand is a covalent compound and does not conduct electricity, as it does not dissociate into ions in the same way as salt. Sand is considered an insulator in terms of electrical conductivity.

Answer: The concentration of solution is, 62.5 g/100 mL

Explanation:

Mass of solute = 25 g

Volume of solvent (water) = 40 mL

Now we have to calculate the concentration of solution.

Now put all the given values in this expression, we get:

Thus, the concentration of solution is, 62.5 g/100 mL

Answer:

\(m_{solute}=100g\)

Explanation:

Hello,

In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:

\(\%m/m=\frac{m_{solute}}{m_{solution}}*100\%\)

We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:

\(m_{solute}=\frac{m_{solution}*\%m/m}{100\%} =\frac{500g*20\%}{100\%}\\ \\m_{solute}=100g\)

Best regards.

Answer:

(CH3)CI

Explanation:

As we move down the group, the halogen atoms become more easily polarizable and the C-X bond is more easily broken.

Recall that E2 mechanism has to do with synchronous proton abstraction and loss of the halogen.

These occur faster with (CH3)CI than when the C-X bond involves other halogens.

The final temperature of the granite and the water in the calorimeter is 8.4°.

We know that in accordance to the first law of thermodynamics, energy is neither created nor destroyed but it can be converted from one form to another. This implies that the heat that is lost by the granite has to be equal to the heat that is gained by the water in this case.

Knowing that;

H = mcdT

H = heat lost or gained

c = specific heat capacity of the substance

dT = temperature change

Heat lost by the granite = Heat gained by water

52.6 * 0.79 * (θ - 125) = 100 * 4.18 * (θ - 20)

41.6θ - 5200 = 418θ - 8360

Collecting the like terms

41.6θ  - 418θ =  - 8360 + 5200

-376.4θ =  -3160

θ = -3160/-376.4

θ = 8.4°

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There are 6 sigma bonds in 1-chloro-1,3-pentadiene.

In 1-chloro-1,3-pentadiene, let's break down the structure to count the number of sigma bonds

The compound 1-chloro-1,3-pentadiene has the following structure:

Cl

H2C=C=CH-CH2-CH3

To count the sigma bonds, we examine each carbon atom and its attached atoms or groups.

Starting from the left side:

The first carbon (C1) is bonded to one hydrogen (H) atom and two other carbon atoms (C2 and C3) by sigma bonds.

The second carbon (C2) forms a double bond with the third carbon (C3), so they share one sigma bond and one pi bond.

The third carbon (C3) is also bonded to the second carbon (C2) and the fourth carbon (C4) by sigma bonds.

The fourth carbon (C4) is bonded to the third carbon (C3) and the fifth carbon (C5) by sigma bonds.

The fifth carbon (C5) is bonded to one hydrogen (H) atom and one methyl (CH3) group by sigma bonds.

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Electrons first occupy the position in lowest possible energy.

orbital diagrams:-

The higher the energy level, the Third energy the electrons in that level have. On the orbital diagram, fill in the boxes to label the representations of an orbital and a sublevel.   2   electrons can occupy a single orbital, and these electrons have Opposite spin. Within a sublevel, all the orbitals fill with one electron, each of which has the Positive spin before a second electron fills any of the orbitals.

what is Orbital?

Each energy position is made up of areas known as an orbital. An orbital is an area of probability in which electrons can be set up. Each energy position, except for the first, has further than one orbital. Each orbital has a specific shape.

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Answer:

232.4 grams of KI solution

Explanation:

Well, we first start off by using like units. The concentration (M) of KI can be rewritten as Moles/ Liter, which makes the solution rewritten as 2.80 Moles/ 1 L.

We also know that 1000 Milliliters are equal to 1 Liter, therefore we can rewrite the 500 Milliliters as 0.500 Liters from doing a conversion (500 mL x  (1 L/1000 mL)= 0.500 L).

From here we multiply the concentration by the number of liters to leave us with moles ((2.80 Moles/ 1 L)  x  0.500 L= 1.4 Moles).

Now, we must find the molar mass of the KI solution, this can be done either by googleing it or adding the molar mass of each element in the compound via the periodic table. In this case, the molar mass for the Potassium in the compound is 39 g/mol while the Iodine is 127 g/mol. Those add to 166 g/mol, and now we can convert to grams from moles.

Now, we multiply the moles by the molar mass to cancel out the moles and leave us with grams. (1.4 mol x (166 g/mol)= 232.4 grams).

I hoped this helps and good luck with your semester in Chemistry!

Answer:

c is the

Explanation:

Answer:

I dont no ma men

Explanation:

Sorry cause a dont no

Answer:

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