When a planet is at its slowest orbital speed, its radius vector sweeps an area, A, in 45 days. What area will the radius vector for this planet sweep during a 40-day time period while at its fastest orbital speed

Answer:

B to C

Explanation:

The object height decreases

Potential energy= mass x height x gravitational force

Which means that potential energy is directly proportional to height

Thus, a decrease in height will cause a decrease in potential energy.

ENERGY cannot be wasted, it is transformed to another form, and here this form is kinetic energy as according to the gravitational force the speed increases as the object falls downward.

And kinetic energy = 1/2 mv2

Which again means that speed is directly proportional to kinetic energy

And thus an increase in speed will cause an increase in kinetic energy.

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

The five examples of pseudoscience found on the Internet include the following:

Pseudosciences is defined as the science that is regarded as false science because it deals with something that has no connection to proper scientific methodology and cannot be proven realistically.

The different types of Pseudosciences include the following:

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Based on the information given, it can be posited that Kyle has a general anxiety disorder.

Generalized Anxiety Disorder is a disorder that is characterized by persistent and excessive worry about different things. People with the disorder may anticipate disaster and are concerned about money, health, family, or other issues.

Some of the effective ways of treatment are spending more time with family and friends, doing regular exercises , enough sleeping, etc.

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Answer: 16 Pounds.

To figure out how much YOU would weigh on the moon, take your weight and divide it by 6. So, if you weighed 100 pounds on Earth, you would weigh only about 16 pounds on the moon.

The total Resistance is 14 ohm, Current is V/14 and Power is V²/14.

R total= R1+R2+R3+R4 = 2+2+6+4= 14ohm

The 4 resistances are connected in series.

Current across R total = I = V/R total = V/14

Power= I. V= V/14 × V= V²/14

Ohm's law is one of the physics that is quite close to everyday life, because in everyday life, of course, we cannot be separated from electronic devices. As is known, almost all electronic devices require electricity to be turned on or operated. Every electrical device has different voltages, depending on their needs.

When the electricity supplied exceeds the required limit of the device, it is likely that the device will be damaged. Electricity itself appears because basically every object contains two types of charge, namely positive (protons) and negative (electrons). And when the negative charge or electrons move, an electric current will appear.

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Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Answer:

047.1

Explanation:

frequency equals velocity over lambda

Answer:

22 m/s

Explanation:

v(t) = Vo + at

v(3) = 4 + 6*3

v = 4 + 18

v = 22 m/s (almost 50 miles/hour)

The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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The resolution of an instrument is the smallest increment of measurement that can be reliably distinguished. It is a measure of the precision of the instrument.

What is resolution?
Resolution is the process of making a decision or reaching an agreement about a problem or dispute. It is the act of solving a problem or coming to an agreement. It is a process of defining the problem, gathering relevant information, analyzing the data, generating possible solutions, evaluating the solutions, and selecting the most appropriate option.

Accuracy is the degree to which a measured value corresponds to the true value of the quantity being measured. In the example given, the resolution of the instrument would be the smallest increment of the measurement of the stiffness constant of the spring that could be reliably distinguished. The accuracy of the measurement would be determined by comparing the theoretical equation to that of a straight line y=mx+c to find the string constant.

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Answer:

false

Explanation:

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Answer: The density is greater at point C

Explanation: At that point

The convention current slowly cools off

Hello!

For this, first let's calculate time of stop:

t = (V - Vi) / a

Replacing:

t = (0 m/s - 18 m/s) / -5,4 m/s^2

Resolving:

t = -18 m/s / -5,4 m/s^2

t = 3,33 s + 0,25 s = 3,58 s

Now lets calculate distance traveled, with formula:

d = Vi*t + (a*t^2)/2

Replacing:

d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2

Resolving:

d = 64,44 m + (-34,604 m)

d = 29,83 m

Then, the vehicle will CRASH

Answer:

Total distance = 700 m

Displacement = 500 m

Explanation:

Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is:  300 + 400 = 700 m.

But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:

displacement = \(\sqrt{300^2+400^2} =\sqrt{250000} =500\,m\)

Answer:

The answer is false

Explanation:

Though the mostly used SI unit of measurement or the most popular units are the

Length,

Time and

Mass

i.e meter (m), seconds (s), kilogram (kg)

Aside all the above stated units for measurements there are other four basic units which are itemized  bellow.

they are

1. Amount of substance - mole (mole)

2. Electric current - ampere (A)

3. Temperature - kelvin (K)

4. Luminous intensity - candela (cd)

The charge on the segment ds is  \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

As Q is uniformly distributed over semicircel so,charge density

\(\lambda=\frac{Q}{s}=\frac{Q}{\pi r}\)

so in ds region charge: \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

In physics, a uniformly distributed charge refers to a charge distribution where the charge density is constant throughout the given volume or surface. In other words, the amount of charge per unit volume or unit area is the same everywhere within the region.

Uniformly distributed charge is an important concept in electrostatics, which is the study of the behavior of electric charges at rest. The electric field produced by a uniformly charged object has a particularly simple form, and this makes it easier to calculate the electric field at any point outside the charged object using Gauss's Law.

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the complete question is:

What is the charge on a segment ds?

Express your answer in terms of some, all, or none of the variables Q, a, θ, dθ, and the constant π.

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

The formulas are down below

Explanation:

\(w = \frac{o}{t} \)

From V=rw

\(w = \frac{v}{r} \)

In order get the block up to a speed of 3.58 m/s in 1.77 s, it must undergo an acceleration a of

a = (3.58 m/s) / (1.77 s) ≈ 2.02 m/s²

When the spring is getting pulled, Newton's second law tells us

• the net vertical force is

∑ F = n - mg = 0

where ∑ F is the net force, n is the magnitude of the normal force, and mg is the weight of the block - it follows that n = mg ; and

• the net horizontal force is

∑ F = F - f = ma

where F is the applied force, f is kinetic friction, m is the block's mass, and a is the acceleration found earlier. F stretches the spring by x = 0.250 m, so we have

F - f = kx - µn = kx - µmg = ma

where k is the spring constant and µ is the coefficient of kinetic friction.

When the block is being pulled at a constant speed, Newton's second law says

• the net vertical force is still

∑ F = n - mg = 0

so that n = mg again; and

• the net horizontal force is

∑ F = F - f = 0

This time, F stretches the spring by y = 0.0544 m, so we have

F - f = ky - µmg = 0

Solve the equations in boldface for k and µ :

kx - µmg = ma

ky - µmg = 0

==>   k (x - y) = ma

==>   k = ma / (x - y)

==>   k = (17.6 kg) (2.02 m/s²) / (0.250 m - 0.0544 m) ≈ 182 N/m

Then

ky - µmg = 0

==>   µ = ky / (mg)

==>   µ = (182 N/m) (0.0544 m) / ((17.6 kg) g) ≈ 0.0574

Answer:

Valsalva device

Explanation: Valsalva device allows astronauts to equalize the pressure in their ears by performing the Valsalva maneuver inside the suit without using their hands to block their nose.

Answer:

Astronauts wear communication devices called intercoms on the ear.

Explanation:

We know that the outer space is a vacuum environment and hence sound waves cannot travel through space. Hence an alternative means of communication is necessary for proper communication between two astronauts. This alternative is the use of intercom. Its functioning is similar to a walkie-talkie, it transmits and recieves radio waves for communication

Answer:

the piano.

Explanation:

Answer:

Why does it take sometimes to be brighter again after eclipse? The moon looks dimmer before lunar eclipse because the moon enters into shadow of penumbra region of earth. As a result, the brightness of moon decreases and looks dimmer.

Explanation:

Answer: The moon looks dimmer before lunar eclipse because the moon enters into shadow of penumbra region of earth. As a result, the brightness of moon decreases and looks dimmer.

Explanation: